🔗 Problem

Problem: A songwriter creates a long ballad with many verses. Each verse has 162 words and he divides these into 18 lines per verse. This gives a certain number of words per line. To each line, he adds 34 more words as a refrain. What is the total number of words present in each line now?

Gemma 2B:

     Reasoning: Each verse has 162/18 = <<162/18=9>>9 words per line.
    After adding the refrain, each line has 9+34 = <<9+34=43>>43 words.
    ### Answer: 43

Expected answer: 43

Correct? Yes

🔗 Follow-up

Problem: Following from the previous problem, the songwriter then decides to add an extra refrain to the end of each verse. If the refrain has 39 words, determine how many words are in each line after this final addition.

Gemma 2B:

     Reasoning: After adding the extra refrain, each line has 43+39 = <<43+39=82>>82 words.
    ### Answer: 82

Expected answer: 82

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, the songwriter added 34 words as the refrain to each line in his song. However, what if he had decided to keep the refrain a bit shorter and added only 28 words to each line instead? How many words would each line of the song contain in that case?

Gemma 2B:

     Reasoning: Each verse has 162/18 = <<162/18=9>>9 words per line.
    After adding the shorter refrain, each line has 9+28 = <<9+28=37>>37 words.
    ### Answer: 37

Expected answer: 37

Correct? Yes

🔗 Problem

Problem: A penguin biologist counted 35 penguins on a small ice floe. In another part of the Antarctic, she counted a different group of penguins and found there were approximately 598 divided evenly among 26 ice floes. After returning to the first place, she found that the penguin population had increased by 49. Wishing to conduct another survey, she decided to take 33 more penguins into account. However, when she counted them again, she realized she had overestimated and had to subtract 10 from her calculations. Her final step was to add in the penguins she’d left at her base camp, which were 20 adults and 14 chicks. How many penguins did she count in total?

Gemma 2B:

     Reasoning: The biologist counted 35 penguins on the first ice floe.
    She counted 598/26 = <<598/26=23>>23 penguins on the second ice floe.
    After returning to the first place, she found that the penguin population had increased by 49, so there were 35+49 = <<35+49=84>>84 penguins on the first ice floe.
    She decided to take 33 more penguins into account, so there were 84+33 = <<84+33=117>>117 penguins on the first ice floe.
    However, she realized she had overestimated and had to subtract 10 from her calculations, so there were 117-10 = <<117-10=107>>107 penguins on the first ice floe.
    Finally, she added in the penguins she’d left at her base camp, which were 20 adults and 14 chicks, so there were 107+20+14 = <<107+20+14=141>>141 penguins in total.
    ### Answer: 141

Expected answer: 164

Correct? No

🔗 Problem

Problem: In a local park, a jungle gym has a total of 27 steps. If the top 19 steps are blue and rest along with another 19 steps are red, we get a certain number of colored steps. On another jungle gym, there are 34 green steps. What is the total number of colored steps on the two jungle gyms?

Gemma 2B:

     Reasoning: The number of colored steps on the first jungle gym is 19+19 = <<19+19=38>>38.
    The total number of colored steps on the two jungle gyms is 38+34 = <<38+34=72>>72.
    ### Answer: 72

Expected answer: 61

Correct? No

🔗 Problem

Problem: If a cloud releases 47 millimeters of rainfall per hour over a one hour period, and the average cloud typically releases 775 millimeters of rainfall over the course of 31 hours, find the amount of rainfall from the following condition. Subtract 22 from the average rainfall of the typical cloud per hour then multiply this by 23. Add this result to a constant cloud factor of 42. Add this new result to the hourly rainfall of the initial cloud and subtract 2 from it. What is the resultant millimeters of rainfall?

Gemma 2B:

     Reasoning: The average rainfall of the typical cloud per hour is 775/31 = <<775/31=25>>25 millimeters.
    Subtract 22 from this to get 25-22 = <<25-22=3>>3 millimeters.
    Multiply this by 23 to get 3*23 = <<3*23=69>>69 millimeters.
    Add this to the constant cloud factor of 42 to get 69+42 = <<69+42=111>>111 millimeters.
    Add this to the hourly rainfall of the initial cloud to get 111+47 = <<111+47=158>>158 millimeters.
    Subtract 2 from this to get 158-2 = <<158-2=156>>156 millimeters.
    ### Answer: 156

Expected answer: 156

Correct? Yes

🔗 Follow-up

Problem: Now consider a different scenario where the initial cloud releases less rainfall, specifically 15 millimeters per hour over a one hour period. Keeping the other conditions from the previous problem the same (the average cloud releases 775 millimeters of rainfall over the course of 31 hours, subtract 22 from the average rainfall of the typical cloud per hour then multiply this by 23, add this result to a constant cloud factor of 42, and subtract 2 from the last result), how much rainfall would be produced in this scenario?

Gemma 2B:

     Reasoning: The average rainfall of the typical cloud per hour is still 775/31 = <<775/31=25>>25 millimeters.
    Subtract 22 from this to get 25-22 = <<25-22=3>>3 millimeters.
    Multiply this by 23 to get 3*23 = <<3*23=69>>69 millimeters.
    Add this to the constant cloud factor of 42 to get 69+42 = <<69+42=111>>111 millimeters.
    Add this to the hourly rainfall of the initial cloud to get 111+15 = <<111+15=126>>126 millimeters.
    Subtract 2 from this to get 126-2 = <<126-2=124>>124 millimeters.
    ### Answer: 124

Expected answer: 124

Correct? Yes

🔗 Problem

Problem: Nadia likes to practice playing the piano. The other day she practiced for 45 minutes in the morning. In the same day, she also practiced for another 35 minutes in the afternoon and then another 35 minutes in the evening. How long did Nadia practice the piano in total that day?

Gemma 2B:

     Reasoning: Nadia practiced for 35+35 = <<35+35=70>>70 minutes in the afternoon and evening.
    Nadia practiced for 45+70 = <<45+70=115>>115 minutes in total that day.
    ### Answer: 115

Expected answer: 115

Correct? Yes

🔗 Follow-up

Problem: Reflecting upon her previous practice sessions, Nadia thought she could do more. She decided to adjust her morning practice time from 45 minutes to 26 minutes. Still maintaining her afternoon and evening sessions at 35 minutes each, how many minutes in total would Nadia be practicing for the day with this adjustment?

Gemma 2B:

     Reasoning: Nadia practiced for 26+35+35 = <<26+35+35=96>>96 minutes in total that day.
    ### Answer: 96

Expected answer: 96

Correct? Yes

🔗 Problem

Problem: A popular clothing store sells dresses for $44 each. During a flash sale, they further reduce prices by a factor of 465 divided by 31. How much does a dress cost during the flash sale?

Gemma 2B:

     Reasoning: The price of the dress during the flash sale is $44 * (465/31) = <<44*(465/31)=68>>$68.
    ### Answer: $68

Expected answer: 660

Correct? No

🔗 Problem

Problem: A rope maker made 46 meters of rope on Monday. On Tuesday, he made as many meters of rope as he did on Monday, plus an additional 19 meters. However, by Wednesday, 9 meters of this rope had been damaged and was unusable. How many meters of usable rope does he have after Wednesday?

Gemma 2B:

     Reasoning: The rope maker made 46+19 = <<46+19=65>>65 meters of rope on Tuesday.
    The rope maker made 46+65 = <<46+65=111>>111 meters of rope in total.
    After Wednesday, the rope maker has 111-9 = <<111-9=102>>102 meters of usable rope.
    ### Answer: 102

Expected answer: 56

Correct? No

🔗 Problem

Problem: Juliana bought 16 pairs of vintage earrings for a gift. Each pair costs $2. She also chose a special jewelry box that costs $25. In addition, she paid $48 for the gift wrapping service. How much did she spend in total for her gift?

Gemma 2B:

     Reasoning: Juliana spent 16*$2 = <<16*2=32>>$32 on earrings.
    Juliana spent $32+$25+$48 = <<32+25+48=105>>$105 in total for her gift.
    ### Answer: 105

Expected answer: 105

Correct? Yes

🔗 Problem

Problem: If Emma takes 60 beads and divides them equally among 3 of her friends, each friend will get a certain number of beads. She then adds 4 more beads to each friend's pile to start making necklaces. How many beads does each friend have now?

Gemma 2B:

     Reasoning: Emma divides 60 beads equally among 3 friends, so each friend gets 60/3 = <<60/3=20>>20 beads.
    Emma then adds 4 more beads to each friend's pile, so each friend now has 20+4 = <<20+4=24>>24 beads.
    ### Answer: 24

Expected answer: 24

Correct? Yes

🔗 Follow-up

Problem: After distributing the beads among her friends, Emma realizes that she actually wanted to divide her 60 beads evenly among 28 friends instead of 3. She recalculates and then adds 4 more beads to each friend's stack after the initial division. How many beads does each friend have now?

Gemma 2B:

     Reasoning: Emma divides 60 beads equally among 28 friends, so each friend gets 60/28 = <<60/28=2.1428571428571427>>2.1428571428571427 beads.
    Emma then adds 4 more beads to each friend's pile, so each friend now has 2.1428571428571427+4 = <<2.1428571428571427+4=6.142857142857143>>6.142857142857143 beads.
    ### Answer: 6.142857142857143

Expected answer: 43/7

Correct? Yes

🔗 Problem

Problem: A young boy with a creative mind decided to build a kite. He started with 37 paper straws but decided that 4 were unnecessary and removed them. Later, he realized his kite was still too bulky and removed another 23 straws. He multiplied the remaining number of straws by 45, subtracted 49 from that total, and then took out 7 more straws. How many straws did the boy have left?

Gemma 2B:

     Reasoning: The boy started with 37 straws and removed 4, leaving him with 37-4 = <<37-4=33>>33 straws.
    He then removed another 23 straws, leaving him with 33-23 = <<33-23=10>>10 straws.
    He multiplied the remaining number of straws by 45, resulting in 10*45 = <<10*45=450>>450 straws.
    He subtracted 49 from that total, leaving him with 450-49 = <<450-49=401>>401 straws.
    Finally, he removed 7 more straws, leaving him with 401-7 = <<401-7=394>>394 straws.
    ### Answer: 394

Expected answer: 394

Correct? Yes

🔗 Follow-up

Problem: After reflecting on his kite design, the young boy realized he made a mistake. When he multiplied the number of remaining paper straws by 45, he should have subtracted 25, not 49. If he corrects this calculation error and takes out 7 final straws as before, how many straws does he have now for his kite?

Gemma 2B:

     Reasoning: The boy started with 37 straws and removed 4, leaving him with 37-4 = <<37-4=33>>33 straws.
    He then removed another 23 straws, leaving him with 33-23 = <<33-23=10>>10 straws.
    He multiplied the remaining number of straws by 45, resulting in 10*45 = <<10*45=450>>450 straws.
    He subtracted 25 from that total, leaving him with 450-25 = <<450-25=425>>425 straws.
    Finally, he removed 7 more straws, leaving him with 425-7 = <<425-7=418>>418 straws.
    ### Answer: 418

Expected answer: 418

Correct? Yes

🔗 Problem

Problem: At the zoo, there were 2 trips being hosted. Each trip was allowed to see 2 animals. However, each animal had 3 baby animals with them, making the number of animals seen per trip multiplied by 3. If each baby animal could be photographed 21 times, how many photos could be taken in total? Also, if 34 photos were spoiled and unusable out of the entire batch, but guests were given the opportunity to take an additional 30 photos later, how many usable photos would there be in total?

Gemma 2B:

     Reasoning: Each trip saw 2*3 = <<2*3=6>>6 animals.
    So, 2 trips saw 2*6 = <<2*6=12>>12 animals.
    Each animal could be photographed 21 times, so 12 animals could be photographed 12*21 = <<12*21=252>>252 times.
    If 34 photos were spoiled, then there were 252-34 = <<252-34=218>>218 usable photos.
    If guests were given the opportunity to take an additional 30 photos later, then there would be 218+30 = <<218+30=248>>248 usable photos in total.
    ### Answer: 248

Expected answer: 248

Correct? Yes

🔗 Follow-up

Problem: In the previous case at the zoo, imagine if each baby animal could only be photographed 16 times, instead of 21. Given the same spoiling rate of 34 photos and the additional opportunity to take 30 more photos later, how many usable photos would be available now?

Gemma 2B:

     Reasoning: Each trip saw 2*3 = <<2*3=6>>6 animals.
    So, 2 trips saw 2*6 = <<2*6=12>>12 animals.
    Each animal could be photographed 16 times, so 12 animals could be photographed 12*16 = <<12*16=192>>192 times.
    If 34 photos were spoiled, then there were 192-34 = <<192-34=158>>158 usable photos.
    If guests were given the opportunity to take an additional 30 photos later, then there would be 158+30 = <<158+30=188>>188 usable photos in total.
    ### Answer: 188

Expected answer: 188

Correct? Yes

🔗 Problem

Problem: In a literacy event, a group of learners were asked to write a word from letters. In the first round, they could form a word with 47 letters, but due to a mistake, they had to remove 30 letters. Then, they figured out they could still add 10 more letters to this word. In the next round, they removed 3 of these letters from the updated word. How many letters were there in the word after this last deletion?

Gemma 2B:

     Reasoning: After removing 30 letters, they had 47-30 = <<47-30=17>>17 letters left.
    After adding 10 more letters, they had 17+10 = <<17+10=27>>27 letters.
    After removing 3 letters, they had 27-3 = <<27-3=24>>24 letters left.
    ### Answer: 24

Expected answer: 24

Correct? Yes

🔗 Follow-up

Problem: In the continuation of the literacy event, the learners had the opportunity to add more letters to the word after the last deletion. They decided to add 39 more letters. How many letters were in the word after this final addition?

Gemma 2B:

     Reasoning: After the last deletion, they had 24 letters left.
    After adding 39 more letters, they had 24+39 = <<24+39=63>>63 letters.
    ### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Follow-up

Problem: In revisiting the literacy event, let's consider a different scenario. When the learners formed the word with 47 letters and due to a mistake had to remove 30, instead of adding 10 letters, what if they added only 10 - 16 = -6 letters? What would the total number of letters be in the word after this change?

Gemma 2B:

     Reasoning: After removing 30 letters, they had 47-30 = <<47-30=17>>17 letters left.
    After adding -6 letters, they had 17+(-6) = <<17+(-6)=11>>11 letters.
    ### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Problem

Problem: A turtle named Tommy moves at 74/37 miles per hour. If Tommy maintains his current speed for a while then slows down by 3 mph, then speeds up to his initial speed again, what would be his average speed?

Gemma 2B:

     Reasoning: Tommy's initial speed is 74/37 = <<74/37=2>>2 mph.
    Tommy's speed after slowing down is 2-3 = <<2-3=-1>>-1 mph.
    Tommy's speed after speeding up is 2 mph.
    Tommy's average speed is (2-1+2)/3 = <<(2-1+2)/3=1>>1 mph.
    ### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Problem

Problem: Liam has 40 sets of building blocks. Each set contains 16 blocks. How many building blocks does Liam have in total?

Gemma 2B:

     Reasoning: Liam has 40*16 = <<40*16=640>>640 building blocks in total.
    ### Answer: 640

Expected answer: 640

Correct? Yes

🔗 Follow-up

Problem: After counting all the building blocks, Liam decides to give away 25 to his friend. How many building blocks does Liam have left after giving some to his friend?

Gemma 2B:

     Reasoning: Liam has 640-25 = <<640-25=615>>615 building blocks left after giving some to his friend.
    ### Answer: 615

Expected answer: 615

Correct? Yes

🔗 Follow-up

Problem: What if Liam only had 38 sets of building blocks instead of 40? How many building blocks would he have in that case?

Gemma 2B:

     Reasoning: Liam would have 38*16 = <<38*16=608>>608 building blocks in total.
    ### Answer: 608

Expected answer: 608

Correct? Yes

🔗 Problem

Problem: John has 24 pencils. Then he bought more such that the number of pencils he has now is equal to the number of what he had plus 7. How many pencils does John have now?

Gemma 2B:

     Reasoning: John has 24+7 = <<24+7=31>>31 pencils now.
    ### Answer: 31

Expected answer: 31

Correct? Yes

🔗 Follow-up

Problem: After having a total of 31 pencils, John received a gift box with an additional 26 pencils. How many pencils does he have now?

Gemma 2B:

     Reasoning: John has 31+26 = <<31+26=57>>57 pencils now.
    ### Answer: 57

Expected answer: 57

Correct? Yes

🔗 Follow-up

Problem: Suppose originally, John only had 2 pencils instead of 24 and then he bought more such that the number of pencils he has now is equal to the number of pencils he had plus 7. How many pencils does John have now?

Gemma 2B:

     Reasoning: John has 2+7 = <<2+7=9>>9 pencils now.
    ### Answer: 9

Expected answer: 9

Correct? Yes

🔗 Problem

Problem: The snowfall in City A, which lasts for 50 days, is currently 36 days in. In City B, there is a unique snow pattern where for every 14 days, it snows 98 inches. The total snowfall in inches in City A is expected to be the product of the remaining snowfall days in City A and the average daily snowfall in inches in City B. However, the snow removal has been keeping up and has managed to remove an amount of snow equal to the average daily snowfall in City B. How much snow in inches is left in City A after the snow removal?

Gemma 2B:

     Reasoning: The remaining snowfall days in City A are 50-36 = <<50-36=14>>14 days.
    The average daily snowfall in inches in City B is 98/14 = <<98/14=7>>7 inches.
    The total snowfall in inches in City A is 14*7 = <<14*7=98>>98 inches.
    The amount of snow removed is equal to the average daily snowfall in City B, which is 7 inches.
    The amount of snow left in City A after the snow removal is 98-7 = <<98-7=91>>91 inches.
    ### Answer: 91

Expected answer: 91

Correct? Yes

🔗 Problem

Problem: A pirate finds 28 rubies on the first day of his treasure hunt. On the second day, he finds another haul of rubies equal to the first day's find plus an additional 21 rubies. How many rubies does the pirate have in total after the second day?

Gemma 2B:

     Reasoning: The pirate finds 28+21 = <<28+21=49>>49 rubies on the second day.
    The pirate has 28+49 = <<28+49=77>>77 rubies in total after the second day.
    ### Answer: 77

Expected answer: 77

Correct? Yes

🔗 Follow-up

Problem: After the second day, the pirate continues his adventure and stumbles upon a third treasure chest containing 29 additional rubies. Unfortunately, he drops and loses 36 rubies while escaping a group of rival pirates. How many rubies does he have in total now?

Gemma 2B:

     Reasoning: The pirate has 77+29 = <<77+29=106>>106 rubies after finding the third treasure chest.
    The pirate has 106-36 = <<106-36=70>>70 rubies left after losing some to the rival pirates.
    ### Answer: 70

Expected answer: 70

Correct? Yes

🔗 Follow-up

Problem: After reflecting on his loss, the pirate remembers that, on the first day, he actually only found 6 rubies, not 28. On the second day, he still found a number of rubies equal to what he found on the first day plus an additional 21 rubies. How many rubies did the pirate have in total after the second day, taking this into account?

Gemma 2B:

     Reasoning: The pirate finds 6+21 = <<6+21=27>>27 rubies on the second day.
    The pirate has 6+27 = <<6+27=33>>33 rubies in total after the second day.
    ### Answer: 33

Expected answer: 33

Correct? Yes

🔗 Problem

Problem: There were 47 inches of snowfall in January and an additional 7 inches in early February. On February 15th, there was an additional 17 inches of snowfall. Then, 48 inches of snow fell in March. In April, we had an additional 31 inches of snowfall early on, but then 27 inches melted by the end of the month. How many inches of snow does this sum up to at the end of April?

Gemma 2B:

     Reasoning: The total snowfall in January and early February is 47+7 = <<47+7=54>>54 inches.
    The total snowfall in February is 54+17 = <<54+17=71>>71 inches.
    The total snowfall in March is 71+48 = <<71+48=119>>119 inches.
    The total snowfall in April is 119+31 = <<119+31=150>>150 inches.
    The total snowfall at the end of April is 150-27 = <<150-27=123>>123 inches.
    ### Answer: 123

Expected answer: 123

Correct? Yes

🔗 Follow-up

Problem: Following the same snowfall pattern, but this time if April were to receive a slightly higher snowfall, with an additional 44 inches of snowfall early on, but then 27 inches melted by the end of the month, how many inches of snow would this sum up to at the end of April now?

Gemma 2B:

     Reasoning: The total snowfall in April is now 119+44 = <<119+44=163>>163 inches.
    The total snowfall at the end of April is now 163-27 = <<163-27=136>>136 inches.
    ### Answer: 136

Expected answer: 136

Correct? Yes

🔗 Problem

Problem: At a fair, a vendor sold balloons. On a particularly busy day, he sold 46 balloons every hour for 11 hours straight. After the fair had closed, he ended up selling an additional 31 balloons to some stragglers. How many balloons did he sell in total that day?

Gemma 2B:

     Reasoning: The vendor sold 46 balloons every hour for 11 hours, so he sold 46*11 = <<46*11=506>>506 balloons during the fair.
    After the fair had closed, he sold an additional 31 balloons, so he sold 506+31 = <<506+31=537>>537 balloons in total that day.
    ### Answer: 537

Expected answer: 537

Correct? Yes

🔗 Problem

Problem: Mary and John decided to play a game of cards. In the first game, Mary scored 31 points and John scored 39 points. In the second game, their combined score was increased by 35 more points. During a special round, they could multiply their score by the difference between 27 and the number of cards left in the deck, which was 23. What was their final score in the special round?

Gemma 2B:

     Reasoning: The combined score of Mary and John in the first game was 31+39 = <<31+39=70>>70 points.
    In the second game, their combined score was increased by 35 points, so their new combined score was 70+35 = <<70+35=105>>105 points.
    The difference between 27 and the number of cards left in the deck was 27-23 = <<27-23=4>>4.
    In the special round, they could multiply their score by the difference between 27 and the number of cards left in the deck, which was 4.
    So, their final score in the special round was 105*4 = <<105*4=420>>420 points.
    ### Answer: 420

Expected answer: 420

Correct? Yes

🔗 Follow-up

Problem: After the special round in their card game, Mary and John discovered two extra points they hadn't accounted for earlier. After adding these extra points to their score, what was their final combined score?

Gemma 2B:

     Reasoning: Mary and John's final score in the special round was 420 points.
    After adding the two extra points, their final combined score was 420+2 = <<420+2=422>>422 points.
    ### Answer: 422

Expected answer: 422

Correct? Yes

🔗 Follow-up

Problem: Given the same card game situation, suppose that in the second game, Mary and John’s combined score increased by 50 points instead of 35. Following the same rule in their special round, where they multiplied their score by the difference between 27 and the number of cards left in the deck (which was 23), what would their final score be in this case?

Gemma 2B:

     Reasoning: The combined score of Mary and John in the first game was 31+39 = <<31+39=70>>70 points.
    In the second game, their combined score was increased by 50 points, so their new combined score was 70+50 = <<70+50=120>>120 points.
    The difference between 27 and the number of cards left in the deck was 27-23 = <<27-23=4>>4.
    In the special round, they could multiply their score by the difference between 27 and the number of cards left in the deck, which was 4.
    So, their final score in the special round would be 120*4 = <<120*4=480>>480 points.
    ### Answer: 480

Expected answer: 480

Correct? Yes

🔗 Problem

Problem: A furniture company manufactured 17 upholstered seats and 18 wooden seats in the morning, and then produced another 29 in the afternoon. They repeated this production in the evening. Later on, they gave away 48 chairs to charity and used 7 chairs for quality testing. How many chairs are left after these operations?

Gemma 2B:

     Reasoning: The company produced 17+18+29 = <<17+18+29=64>>64 chairs in the morning and afternoon.
    They repeated this production in the evening, so they produced 64*2 = <<64*2=128>>128 chairs in total.
    They gave away 48 chairs to charity and used 7 chairs for quality testing, so they have 128-48-7 = <<128-48-7=73>>73 chairs left.
    ### Answer: 73

Expected answer: 73

Correct? Yes

🔗 Follow-up

Problem: Continuing from the last example, suppose the furniture company only crafted 15 wooden seats in the morning instead of 18 but kept the rest of operations unchanged. After repeating the same production, donating 48 chairs to charity, and using 7 for quality testing, how many chairs will be the company left with?

Gemma 2B:

     Reasoning: The company produced 17+15+29 = <<17+15+29=61>>61 chairs in the morning and afternoon.
    They repeated this production in the evening, so they produced 61*2 = <<61*2=122>>122 chairs in total.
    They gave away 48 chairs to charity and used 7 chairs for quality testing, so they have 122-48-7 = <<122-48-7=67>>67 chairs left.
    ### Answer: 67

Expected answer: 67

Correct? Yes

🔗 Problem

Problem: On a popular jungle gym, there are 46 monkey bars and 18 swinging ropes for the kids to play on. Nearby, a larger jungle gym was recently built to accommodate more kids. The new jungle gym contains 2 extra long zip lines and 20 regular zip lines, each requiring 31 special hooks to install. How many more hooks were used in the new jungle gym compared to the number of play components on the popular jungle gym?

Gemma 2B:

     Reasoning: The popular jungle gym has 46+18 = <<46+18=64>>64 play components.
    The new jungle gym has 20*31 = <<20*31=620>>620 hooks for regular zip lines.
    The new jungle gym has 2*31 = <<2*31=62>>62 hooks for extra long zip lines.
    The new jungle gym has 620+62 = <<620+62=682>>682 hooks in total.
    The new jungle gym has 682-64 = <<682-64=618>>618 more hooks than the popular jungle gym.
    ### Answer: 618

Expected answer: 618

Correct? Yes

🔗 Problem

Problem: John has saved $168 and he decides to divide it evenly between 21 days. After doing so, he then gets an additional $47 from his job. He then receives another amount of money which is the sum of $12 and $45. How much money does John have now?

Gemma 2B:

     Reasoning: John divides his money evenly between 21 days, so he gets $168/21 = <<168/21=8>>8 dollars per day.
    After getting an additional $47 from his job, John has $8+$47 = <<8+47=55>>55 dollars.
    John then receives another amount of money which is the sum of $12 and $45, so he gets $12+$45 = <<12+45=57>>57 dollars.
    John now has $55+$57 = <<55+57=112>>112 dollars.
    ### Answer: 112

Expected answer: 112

Correct? Yes

🔗 Follow-up

Problem: In the original problem, John was saving $168 and divided it evenly between 21 days. Then he got an additional $47. But what if instead of $47, John only gets an additional $10? Following the same pattern as before, he then receives another amount of money which is the sum of $12 and $45. How much money does John have now?

Gemma 2B:

     Reasoning: John divides his money evenly between 21 days, so he gets $168/21 = <<168/21=8>>8 dollars per day.
    After getting an additional $10 from his job, John has $8+$10 = <<8+10=18>>18 dollars.
    John then receives another amount of money which is the sum of $12 and $45, so he gets $12+$45 = <<12+45=57>>57 dollars.
    John now has $18+$57 = <<18+57=75>>75 dollars.
    ### Answer: 75

Expected answer: 75

Correct? Yes

🔗 Problem

Problem: A robot can stack 32 boxes in 1 minute. If it works non-stop for 4 minutes and then picks up 1 extra box, how many boxes will this robot have stacked in total?

Gemma 2B:

     Reasoning: The robot can stack 32*4 = <<32*4=128>>128 boxes in 4 minutes.
    The robot can stack 128+1 = <<128+1=129>>129 boxes in total.
    ### Answer: 129

Expected answer: 129

Correct? Yes

🔗 Follow-up

Problem: After stacking boxes for 4 minutes, the robot takes a break. When it comes back, it accidentally knocks over 21 of the boxes. How many boxes remain stacked after the robot knocks some over?

Gemma 2B:

     Reasoning: The robot stacked 129 boxes in total.
    The robot knocks over 21 boxes.
    The robot has 129-21 = <<129-21=108>>108 boxes remaining stacked.
    ### Answer: 108

Expected answer: 108

Correct? Yes

🔗 Follow-up

Problem: Let's consider a different scenario: If, instead of picking up an extra single box after 4 minutes, the robot picked up an extra 11 boxes, how many boxes would this robot have stacked in total?

Gemma 2B:

     Reasoning: The robot can stack 32*4 = <<32*4=128>>128 boxes in 4 minutes.
    The robot can stack 128+11 = <<128+11=139>>139 boxes in total.
    ### Answer: 139

Expected answer: 139

Correct? Yes

🔗 Problem

Problem: A female tiger gave birth to 26 cubs in all her lifetime. Unfortunately, 17 of them did not survive the harsh conditions of the wild. However, after growing up, 6 of the surviving tigers moved to other territories. How many tigers remained in the female tiger's territory?

Gemma 2B:

     Reasoning: The female tiger had 26 cubs in total.
    17 of them did not survive, so 26 - 17 = <<26-17=9>>9 cubs survived.
    After growing up, 6 of the surviving tigers moved to other territories, so 9 - 6 = <<9-6=3>>3 tigers remained in the female tiger's territory.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Suppose that originally the female tiger had given birth to 24 cubs instead of 26 in her lifetime, and the same number of 17 cubs had not survived the harsh conditions of the wild. If the same number of surviving tigers, 6, moved to other territories, how many tigers would have remained in the female tiger's territory?

Gemma 2B:

     Reasoning: The female tiger had 24 cubs in total.
    17 of them did not survive, so 24 - 17 = <<24-17=7>>7 cubs survived.
    After growing up, 6 of the surviving tigers moved to other territories, so 7 - 6 = <<7-6=1>>1 tiger remained in the female tiger's territory.
    ### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Problem

Problem: A colony of penguins originally started with 44 members. After a while, 39 new penguins join the colony. Later, from that group, 16 penguins leave to start a new colony elsewhere. To supplant the loss, another group of 35 penguins join the colony. How many penguins are in the colony now?

Gemma 2B:

     Reasoning: The colony started with 44 members.
    After 39 new penguins join, the colony has 44+39 = <<44+39=83>>83 members.
    After 16 penguins leave, the colony has 83-16 = <<83-16=67>>67 members.
    After 35 more penguins join, the colony has 67+35 = <<67+35=102>>102 members.
    ### Answer: 102

Expected answer: 102

Correct? Yes

🔗 Follow-up

Problem: In the same penguin colony, they started off with 44 members. After a while, 39 new penguins join the colony. Later, from that group, 16 penguins leave to start a new colony elsewhere. This time, to supplant the loss, another group of 12 penguins join the colony, instead of 35. How many penguins are in the colony now?

Gemma 2B:

      Reasoning: The colony started with 44 members.
    After 39 new penguins join, the colony has 44+39 = <<44+39=83>>83 members.
    After 16 penguins leave, the colony has 83-16 = <<83-16=67>>67 members.
    After 12 more penguins join, the colony has 67+12 = <<67+12=79>>79 members.
    ### Answer: 79

Expected answer: 79

Correct? Yes

🔗 Problem

Problem: A helicopter travels 10 miles in one minute. If the helicopter increases its speed by 40 miles, plus another 20 miles, how far will the helicopter travel in 12 minutes at this increased speed?

Gemma 2B:

     Reasoning: The helicopter's increased speed is 10+40+20 = <<10+40+20=70>>70 miles per minute.
    The helicopter will travel 70*12 = <<70*12=840>>840 miles in 12 minutes at this increased speed.
    ### Answer: 840

Expected answer: 840

Correct? Yes

🔗 Follow-up

Problem: After re-evaluating its performance, the helicopter realized that its actual speed increase was lesser than initially thought. Instead of the initial 40 miles speed increase, the increase was just 2 miles. Given that the original speed of 10 miles and an additional bonus speed of 20 miles remained the same, how far will the helicopter be able to travel in 12 minutes at this revised speed?

Gemma 2B:

     Reasoning: The helicopter's revised speed is 10+2+20 = <<10+2+20=32>>32 miles per minute.
    The helicopter will travel 32*12 = <<32*12=384>>384 miles in 12 minutes at this revised speed.
    ### Answer: 384

Expected answer: 384

Correct? Yes

🔗 Problem

Problem: A new telescope has a magnification power of 26. To further explore the universe, another telescope is required that needs to be exactly 41 in magnification strength. How much more magnification is required for the new telescope compared to the existing one?

Gemma 2B:

     Reasoning: The required magnification is 41 - 26 = <<41-26=15>>15.
    ### Answer: 15

Expected answer: 15

Correct? Yes

🔗 Follow-up

Problem: The Space Institute realized that the initial magnification power of the existing telescope was actually 16, not 26 as previously thought. If they still want to reach a magnification strength of 41, how much more magnification is now needed compared to the existing telescope?

Gemma 2B:

     Reasoning: The required magnification is now 41 - 16 = <<41-16=25>>25.
    ### Answer: 25

Expected answer: 25

Correct? Yes

🔗 Problem

Problem: Sophie's parents give her $18 for every hour she works at the family business. On Monday, she worked 2 of those hours. Then she bought a $4 ice cream and another $4 coffee afterwards. She then added Monday's leftover amount to her pay for her next single hour of work. After that, she got an additional $45 as a bonus from her grandmother. How much money does Sophie have in total now?

Gemma 2B:

     Reasoning: Sophie earned 2*18 = <<2*18=36>>36 dollars on Monday.
    Sophie spent 4+4 = <<4+4=8>>8 dollars on ice cream and coffee.
    Sophie had 36-8 = <<36-8=28>>28 dollars left after buying ice cream and coffee.
    Sophie earned 18 dollars for her next hour of work.
    Sophie had 28+18 = <<28+18=46>>46 dollars after her next hour of work.
    Sophie had 46+45 = <<46+45=91>>91 dollars after receiving the bonus.
    ### Answer: 91

Expected answer: 91

Correct? Yes

🔗 Follow-up

Problem: In the same scenario, imagine if Sophie's parents now give her $5 for every hour she works at the family business instead of $18. She still works for two hours on Monday, spends the same amount on ice cream and coffee, works an additional hour, and receives the same $45 bonus from her grandmother. How much money does Sophie have in total now?

Gemma 2B:

     Reasoning: Sophie earned 2*5 = <<2*5=10>>10 dollars on Monday.
    Sophie spent 4+4 = <<4+4=8>>8 dollars on ice cream and coffee.
    Sophie had 10-8 = <<10-8=2>>2 dollars left after buying ice cream and coffee.
    Sophie earned 5 dollars for her next hour of work.
    Sophie had 2+5 = <<2+5=7>>7 dollars after her next hour of work.
    Sophie had 7+45 = <<7+45=52>>52 dollars after receiving the bonus.
    ### Answer: 52

Expected answer: 52

Correct? Yes

🔗 Problem

Problem: A towel company initially produced 30 beach towels and 6 hand towels. They then gave away 7 towels for charity, which leaves a certain amount of towels. They then decided to produce 14 more towels to add to their current stock. On the other hand, they made a special batch of 13 towels for every towel left after their charity activity and deducted 19 towels from this special batch, calling it their premium collection. They then noted 20 towels were damaged and removed it from this premium collection. After this, they deducted 3 more towels from the remaining premium collection and combined it with the total they had after their second batch of production. How many towels does the company have now?

Gemma 2B:

     Reasoning: The company initially had 30+6 = <<30+6=36>>36 towels.
    After giving away 7 towels for charity, they had 36-7 = <<36-7=29>>29 towels left.
    After producing 14 more towels, they had 29+14 = <<29+14=43>>43 towels.
    They made a special batch of 13 towels for every towel left after their charity activity, which is 13*29 = <<13*29=377>>377 towels.
    They deducted 19 towels from this special batch, which is 377-19 = <<377-19=358>>358 towels.
    They then noted 20 towels were damaged and removed it from this premium collection, which is 358-20 = <<358-20=338>>338 towels.
    They deducted 3 more towels from the remaining premium collection, which is 338-3 = <<338-3=335>>335 towels.
    They combined it with the total they had after their second batch of production, which is 43+335 = <<43+335=378>>378 towels.
    ### Answer: 378

Expected answer: 378

Correct? Yes

🔗 Problem

Problem: An extraterrestrial being from the planet Zorkon communicates that they have 50 special energy crystals. Then they explain that they'll get 20 more energy crystals in a few earth days. Additionally, their zorbcraft has a hidden compartment that contains 50 energy crystals and 6 extra lumino-gems, and they plan to add the upcoming energy crystals to this compartment as well. How many items (including both energy crystals and lumino-gems) would be in the zorbcraft's compartment at that time?

Gemma 2B:

     Reasoning: The zorbcraft will have 50+20 = <<50+20=70>>70 energy crystals after they get the new ones.
    The zorbcraft will have 70+50 = <<70+50=120>>120 energy crystals in total.
    The zorbcraft will have 120+6 = <<120+6=126>>126 items in total.
    ### Answer: 126

Expected answer: 126

Correct? Yes

🔗 Problem

Problem: A park contains 43 Velociraptors. Then, the park added another set of dinosaurs which numbered 972, but as it so happens, each of these sections contained 27 dinosaurs. This meant the actual number of new dinosaur types added was less. After calculating the new dinosaur types, they found out that the number of Velociraptors was more. They found the difference and multiplied this difference by 7, as each of the Velociraptors laid 7 new eggs that week. How many total eggs were laid by the Velociraptors that week?

Gemma 2B:

     Reasoning: The park added 972/27 = <<972/27=36>>36 new dinosaur types.
    The difference between the number of Velociraptors and the number of new dinosaur types is 43-36 = <<43-36=7>>7.
    The number of eggs laid by the Velociraptors that week is 7*7 = <<7*7=49>>49.
    ### Answer: 49

Expected answer: 49

Correct? Yes

🔗 Follow-up

Problem: Following up from the previous scenario, the park's wardens discovered that 46 of the eggs laid by the Velociraptors were not fertilized and not going to hatch. What is the number of Velociraptor eggs that are expected to successfully hatch?

Gemma 2B:

     Reasoning: The number of Velociraptor eggs that are expected to successfully hatch is 49-46 = <<49-46=3>>3.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Continuing off the previous scenario, the wardens realized that they had made a mistake in their calculations. Each box actually contained 46 dinosaurs, not 27. If this was the case, how many total eggs are expected to be laid by the Velociraptors this week?

Gemma 2B:

     Reasoning: The park added 972/46 = <<972/46=21>>21 new dinosaur types.
    The difference between the number of Velociraptors and the number of new dinosaur types is 43-21 = <<43-21=22>>22.
    The number of eggs laid by the Velociraptors that week is 22*7 = <<22*7=154>>154.
    ### Answer: 154

Expected answer: 3521/23

Correct? No

🔗 Problem

Problem: There is a bowl containing 46 oranges. After Maria took 16 oranges from that bowl, how many oranges are left?

Gemma 2B:

     Reasoning: There are 46-16 = <<46-16=30>>30 oranges left.
    ### Answer: 30

Expected answer: 30

Correct? Yes

🔗 Follow-up

Problem: Initially, Maria believed the bowl contained 46 oranges, but soon she realized her mistake and found out there were actually 49 in total. With this new information, after taking out 16 oranges, how many are left now in the bowl?

Gemma 2B:

     Reasoning: There are 49-16 = <<49-16=33>>33 oranges left.
    ### Answer: 33

Expected answer: 33

Correct? Yes

🔗 Problem

Problem: A toothbrush factory produces 37 toothbrushes per minute at the start of its morning shift. A little later, it increases its production to rate to 308 toothbrushes every 7 minutes. If this increased rate of production continued for 16 minutes, how many toothbrushes were produced in total?

Gemma 2B:

     Reasoning: The factory produces 308/7 = <<308/7=44>>44 toothbrushes per minute after the increase in production.
    In 16 minutes, the factory produces 44*16 = <<44*16=704>>704 toothbrushes.
    The total number of toothbrushes produced is 37*16 + 704 = <<37*16+704=1232>>1232.
    ### Answer: 1232

Expected answer: 741

Correct? No

🔗 Problem

Problem: A research laboratory has 39 telescopes initially. They added 7 more telescopes in the first month and then 17 more in the second month. Twelve more telescopes arrived in the third month, followed by further add up of 18 in the fourth month. In fifth month, they got exactly the same number of telescopes as they had initially i.e. 39 telescopes and in the sixth month, they received extra 19 telescopes. How many telescopes does the research laboratory have at the end of the sixth month.

Gemma 2B:

     Reasoning: The research laboratory has 39+7 = <<39+7=46>>46 telescopes after the first month.
    The research laboratory has 46+17 = <<46+17=63>>63 telescopes after the second month.
    The research laboratory has 63+12 = <<63+12=75>>75 telescopes after the third month.
    The research laboratory has 75+18 = <<75+18=93>>93 telescopes after the fourth month.
    The research laboratory has 93+39 = <<93+39=132>>132 telescopes after the fifth month.
    The research laboratory has 132+19 = <<132+19=151>>151 telescopes after the sixth month.
    ### Answer: 151

Expected answer: 151

Correct? Yes

🔗 Follow-up

Problem: After reviewing the inventory, the management of the research laboratory discovered that instead of adding 12 new telescopes in the third month, they had actually added 29 telescopes. How would this affect the total count of telescopes at the end of the sixth month, before any old models were decommissioned?

Gemma 2B:

     Reasoning: The research laboratory has 39+7 = <<39+7=46>>46 telescopes after the first month.
    The research laboratory has 46+17 = <<46+17=63>>63 telescopes after the second month.
    The research laboratory has 63+29 = <<63+29=92>>92 telescopes after the third month.
    The research laboratory has 92+18 = <<92+18=110>>110 telescopes after the fourth month.
    The research laboratory has 110+39 = <<110+39=149>>149 telescopes after the fifth month.
    The research laboratory has 149+19 = <<149+19=168>>168 telescopes after the sixth month.
    ### Answer: 168

Expected answer: 168

Correct? Yes

🔗 Problem

Problem: A table was initially set with 20 forks and 23 knives. Later in the day, 28 more sets of cutlery were added, each set containing 26 utensils. After counting, they found 7 more utensils than expected. However, there were 46 missing utensils, and they had to remove the original set of 20 forks and 23 knives. How many utensils were left on the table?

Gemma 2B:

     Reasoning: Initially, there were 20 forks + 23 knives = <<20+23=43>>43 utensils.
    After adding 28 sets of cutlery, there were 28 * 26 = <<28*26=728>>728 additional utensils.
    So, the total number of utensils became 43 + 728 = <<43+728=771>>771 utensils.
    After finding 7 more utensils, the total became 771 + 7 = <<771+7=778>>778 utensils.
    After removing 46 missing utensils, the total became 778 - 46 = <<778-46=732>>732 utensils.
    Finally, after removing the original set of 20 forks and 23 knives, the total became 732 - 43 = <<732-43=689>>689 utensils.
    ### Answer: 689

Expected answer: 646

Correct? No

🔗 Problem

Problem: A magical unicorn has 50 red roses and 36 blue roses in her mystical garden. But then, a storm comes and 25 blue roses are destroyed. How many roses does the unicorn have left in her garden after the storm?

Gemma 2B:

     Reasoning: The unicorn has 50 red roses and 36 blue roses, so she has 50+36 = <<50+36=86>>86 roses in total.
    After the storm, the unicorn has 36-25 = <<36-25=11>>11 blue roses left.
    So, the unicorn has 50+11 = <<50+11=61>>61 roses left in her garden after the storm.
    ### Answer: 61

Expected answer: 61

Correct? Yes

🔗 Follow-up

Problem: After the storm, the magical unicorn plants 41 more pink roses in her mystical garden. How many roses does the unicorn have in her garden now?

Gemma 2B:

     Reasoning: The unicorn had 61 roses left in her garden after the storm.
    After planting 41 more pink roses, the unicorn has 61+41 = <<61+41=102>>102 roses in her garden now.
    ### Answer: 102

Expected answer: 102

Correct? Yes

🔗 Follow-up

Problem: Originally, the magical unicorn had 50 red roses and 36 blue roses in her mystical garden. But if she had initially had 50 red roses and 38 blue roses instead, and still lost 25 roses in the storm, how many roses would she have left in her garden after the storm?

Gemma 2B:

     Reasoning: If the unicorn had 50 red roses and 38 blue roses, she would have 50+38 = <<50+38=88>>88 roses in total.
    After the storm, the unicorn would have 38-25 = <<38-25=13>>13 blue roses left.
    So, the unicorn would have 50+13 = <<50+13=63>>63 roses left in her garden after the storm.
    ### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Problem

Problem: A factory produces 100 bottles every hour. Half of the hourly production is sent to one warehouse. At another location, triple the amount sent to the first warehouse was marked for shipping, as well as an additional 29 bottles. By the end of the day, 28 more bottles were added to this shipment. How many bottles were marked for shipping in total?

Gemma 2B:

     Reasoning: Half of the hourly production is sent to one warehouse, which is 100/2 = <<100/2=50>>50 bottles.
    Triple the amount sent to the first warehouse was marked for shipping, which is 50*3 = <<50*3=150>>150 bottles.
    An additional 29 bottles were added to this shipment, making it 150+29 = <<150+29=179>>179 bottles.
    By the end of the day, 28 more bottles were added to this shipment, making it 179+28 = <<179+28=207>>207 bottles.
    ### Answer: 207

Expected answer: 207

Correct? Yes

🔗 Follow-up

Problem: From the same factory scenario as before, reconsider the situation such that instead of adding 28 more bottles for shipment by the end of the day, they actually added 50 more bottles. How many bottles were marked for shipping in total now?

Gemma 2B:

     Reasoning: Half of the hourly production is sent to one warehouse, which is 100/2 = <<100/2=50>>50 bottles.
    Triple the amount sent to the first warehouse was marked for shipping, which is 50*3 = <<50*3=150>>150 bottles.
    An additional 29 bottles were added to this shipment, making it 150+29 = <<150+29=179>>179 bottles.
    By the end of the day, 50 more bottles were added to this shipment, making it 179+50 = <<179+50=229>>229 bottles.
    ### Answer: 229

Expected answer: 229

Correct? Yes

🔗 Problem

Problem: The height of a window frame is calculated as the sum of 925 divided by 37 and 26 inches. The width of the window is 11 inches greater than the height. The circumference of the window is calculated as the sum of twice the width and the height. Finally the size of the glass for the window is calculated by subtracting 32 from the circumference. Find the size of the glass required for the window?

Gemma 2B:

     Reasoning: The height of the window frame is 925/37+26 = <<925/37+26=51>>51 inches.
    The width of the window is 51+11 = <<51+11=62>>62 inches.
    The circumference of the window is 2*62+51 = <<2*62+51=175>>175 inches.
    The size of the glass required for the window is 175-32 = <<175-32=143>>143 inches.
    ### Answer: 143

Expected answer: 143

Correct? Yes

🔗 Follow-up

Problem: Suppose that there was an error in the original measurements. The height of the window frame is instead calculated as the sum of 925 divided by 37 and 16 inches, not 26 inches. Recalculating with these new measurements, what would be the size of the glass required for the window now?

Gemma 2B:

     Reasoning: The height of the window frame is 925/37+16 = <<925/37+16=41>>41 inches.
    The width of the window is 41+11 = <<41+11=52>>52 inches.
    The circumference of the window is 2*52+41 = <<2*52+41=145>>145 inches.
    The size of the glass required for the window is 145-32 = <<145-32=113>>113 inches.
    ### Answer: 113

Expected answer: 113

Correct? Yes

🔗 Problem

Problem: A pirate finds treasure with 135 gold coins. He divides these amongst his crew of 9. On another island, they find 323 emeralds which he divides amongst his crew of 19. He then multiplies these two shares to find out the total share per crew member. However, due to a miscount, he later realizes he has overcounted the share by 14. What is the corrected total share per crew member?

Gemma 2B:

     Reasoning: The pirate divides the 135 gold coins amongst his crew of 9, so each crew member gets 135/9 = <<135/9=15>>15 gold coins.
    The pirate divides the 323 emeralds amongst his crew of 19, so each crew member gets 323/19 = <<323/19=17>>17 emeralds.
    The pirate multiplies these two shares to find out the total share per crew member, which is 15*17 = <<15*17=255>>255.
    However, due to a miscount, he later realizes he has overcounted the share by 14. So the corrected total share per crew member is 255-14 = <<255-14=241>>241.
    ### Answer: 241

Expected answer: 241

Correct? Yes

🔗 Problem

Problem: A chocolatier has decided to make small chocolate bars that weigh 176 grams each. To get the right size, he divides each bar into 8 pieces, which means each piece weighs a certain number of grams. He then decides to make a new batch of chocolate using a special recipe. This recipe calls for a total of 38 grams of cocoa, but subtraction the weight of one piece from the 176g bars, plus an additional 26 grams of sugar. Simultaneously, the chocolatier decides to create another batch of chocolates that needs a total of 38 grams of cocoa and 18 grams of milk. What is the difference in the total weight of ingredients between the second and third batch of chocolates?

Gemma 2B:

     Reasoning: First, let's find the weight of one piece of chocolate from the 176g bars. Since each bar is divided into 8 pieces, each piece weighs:

    $$
    \text{Weight of one piece} = \frac{176 \text{ grams}}{8} = 22 \text{ grams}
    $$

    Next, let's calculate the total weight of ingredients for the second batch of chocolates. This batch requires 38 grams of cocoa and 26 grams of sugar. However, we need to subtract the weight of one piece from the 176g bars:

    $$
    \text{Total weight for second batch} = 38 \text{ grams (cocoa)} + 26 \text{ grams (sugar)} - 22 \text{ grams (one piece)} = 42 \text{ grams}
    $$

    Now, let's calculate the total weight of ingredients for the third batch of chocolates. This batch requires 38 grams of cocoa and 18 grams of milk:

    $$
    \text{Total weight for third batch} = 38 \text{ grams (cocoa)} + 18 \text{ grams (milk)} = 56 \text{ grams}
    $$

    Finally, to find the difference in the total weight of ingredients between the second and third batch of chocolates, we subtract the total weight of the second batch from the total weight of the third batch:

    $$
    \text{Difference} = 56 \text{ grams} - 42 \text{ grams} = 14 \text{ grams}
    $$

    ### Answer: 14 grams

Expected answer: 14

Correct? Yes

🔗 Follow-up

Problem: Continuing from the original problem, the chocolatier decides to reduce the amount of sugar in his special recipe. Initially, he was adding 26 grams of sugar but now, he's decided to only add 6 grams. How does this change in sugar affect the difference in the total weight of ingredients between the second (now modified) and third batch of chocolates?

Gemma 2B:

     Reasoning: First, let's recalculate the total weight of ingredients for the modified second batch of chocolates. This batch now requires 38 grams of cocoa and 6 grams of sugar, but we still need to subtract the weight of one piece from the 176g bars:

    $$
    \text{Total weight for modified second batch} = 38 \text{ grams (cocoa)} + 6 \text{ grams (sugar)} - 22 \text{ grams (one piece)} = 22 \text{ grams}
    $$

    Now, let's compare this to the total weight of ingredients for the third batch of chocolates, which remains at 56 grams.

    To find the new difference in the total weight of ingredients between the modified second and third batch of chocolates, we subtract the total weight of the modified second batch from the total weight of the third batch:

    $$
    \text{New difference} = 56 \text{ grams} - 22 \text{ grams} = 34 \text{ grams}
    $$

    ### Answer: The difference in the total weight of ingredients between the modified second and third batch of chocolates is now 34 grams.

Expected answer: 34

Correct? Yes

🔗 Problem

Problem: Jenny has 9 red colored pencils in her art box. She also has some green colored pencils which amounts to 38 minus the number of red colored pencils she has. The total number of times she used all the pencils is the product of the number of green and red pencils she has. How many times did she use all her pencils?

Gemma 2B:

     Reasoning: Jenny has 38-9 = <<38-9=29>>29 green colored pencils.
    The total number of times she used all the pencils is 29*9 = <<29*9=261>>261.
    ### Answer: 261

Expected answer: 261

Correct? Yes

🔗 Follow-up

Problem: Following from the previous scenario, Jenny also used her blue colored pencils an equivalent number of times to the sum of 31 and 16. Now, the total number of times she used all her pencils is equivalent to the times she used her blue pencils added to the times she used her green and red pencils. How many times in total did she use all her pencils?

Gemma 2B:

     Reasoning: Jenny used her blue colored pencils 31+16 = <<31+16=47>>47 times.
    The total number of times she used all her pencils is 261+47 = <<261+47=308>>308.
    ### Answer: 308

Expected answer: 308

Correct? Yes

🔗 Follow-up

Problem: Now, instead of having only 9 red colored pencils, Jenny actually had 12 of them. She again has green colored pencils which, as before, total 38 minus the number of red colored pencils. The total number of times she used all the pencils is the product of the number of green and red pencils she has, just as in the previous case. Now, with this change, how many times did she use all her pencils?

Gemma 2B:

     Reasoning: Jenny has 38-12 = <<38-12=26>>26 green colored pencils.
    The total number of times she used all the pencils is 26*12 = <<26*12=312>>312.
    ### Answer: 312

Expected answer: 312

Correct? Yes

🔗 Problem

Problem: A factory has just released a new robot model, where each model has 17 transistors and each transistor may have 16 separate connections. One of the newly manufactured robots by accident was made with one less connection than standard. However, to compensate for the mistake, an extra 41 connections were added elsewhere. What is the total number of connections in the strangely built robot?

Gemma 2B:

     Reasoning: The standard robot has 17*16 = <<17*16=272>>272 connections.
    The strangely built robot has 272-1 = <<272-1=271>>271 connections from the standard model.
    The strangely built robot has 271+41 = <<271+41=312>>312 connections in total.
    ### Answer: 312

Expected answer: 312

Correct? Yes

🔗 Follow-up

Problem: In the assembly line, another robot was produced similar to the first. However, this time instead of adding an additional 41 connections to compensate for the one lost, the production team decided to add only 13 additional connections. How many connections does this robot have now?

Gemma 2B:

     Reasoning: The strangely built robot has 312 connections.
    The second robot has 312-1 = <<312-1=311>>311 connections from the first robot.
    The second robot has 311+13 = <<311+13=324>>324 connections in total.
    ### Answer: 324

Expected answer: 284

Correct? No

🔗 Problem

Problem: At the local jungle gym, during busy hours, there are usually 24 kids climbing on each of the 31 different attractions. One rainy day, however, there were only 6 kids in total! If you subtract the number of kids on the rainy day from the usual busy day, and then further subtract 12 (the number of squirrels scampering around), how many kids will you have counted in total?

Gemma 2B:

     Reasoning: On a busy day, there are 24 kids on each of the 31 attractions, so there are 24*31 = <<24*31=744>>744 kids in total.
    On the rainy day, there were only 6 kids in total.
    Subtracting the number of kids on the rainy day from the usual busy day, we get 744-6 = <<744-6=738>>738 kids.
    Further subtracting 12 (the number of squirrels scampering around), we get 738-12 = <<738-12=726>>726 kids in total.
    ### Answer: 726

Expected answer: 726

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, instead of 31 attractions at the jungle gym, let's say there were only 6 attractions. So now, on a busy day, you have 24 kids at each of these 6 attractions. If that rainy day still only had 6 kids at the jungle gym in total, and there were 12 squirrels, how many kids will you have counted in total now?

Gemma 2B:

     Reasoning: On a busy day, there are 24 kids on each of the 6 attractions, so there are 24*6 = <<24*6=144>>144 kids in total.
    On the rainy day, there were only 6 kids in total.
    Subtracting the number of kids on the rainy day from the usual busy day, we get 144-6 = <<144-6=138>>138 kids.
    Further subtracting 12 (the number of squirrels scampering around), we get 138-12 = <<138-12=126>>126 kids in total.
    ### Answer: 126

Expected answer: 126

Correct? Yes

🔗 Problem

Problem: There's this mystical ring that, after you perform a special chant, it will grant you powers based on a complex magic formula. If the first step of the magical formula is subtracting 5 from 23 and then multiplying by the number of magical chants you perform, which in this case is 6. After that, the result is multiplied by 7 and again by 1. However, for the final step, you subtract 48 from the result. If you follow these steps, how powerful will the ring's magic be?

Gemma 2B:

     Reasoning: The first step of the magical formula is subtracting 5 from 23, which gives us 23-5 = <<23-5=18>>18.
    Then, we multiply this result by the number of magical chants you perform, which is 6. So, 18*6 = <<18*6=108>>108.
    Next, we multiply this result by 7 and again by 1. So, 108*7*1 = <<108*7*1=756>>756.
    Finally, we subtract 48 from this result. So, 756-48 = <<756-48=708>>708.
    ### Answer: 708

Expected answer: 708

Correct? Yes

🔗 Follow-up

Problem: Imagine in the initial mystical chant, instead of subtracting 5 from 23, you subtracted 5 from just 8, then continued with the rest of the magic formula exactly the same - multiplying by the number of chants and so forth. How would this adjustment impact the final power of the ring?

Gemma 2B:

     Reasoning: If we subtract 5 from 8 instead of 23, we get 8-5 = <<8-5=3>>3.
    Then, we multiply this result by the number of magical chants you perform, which is 6. So, 3*6 = <<3*6=18>>18.
    Next, we multiply this result by 7 and again by 1. So, 18*7*1 = <<18*7*1=126>>126.
    Finally, we subtract 48 from this result. So, 126-48 = <<126-48=78>>78.
    ### Answer: 78

Expected answer: 78

Correct? Yes

🔗 Problem

Problem: A child can make 15 cookies in one hour. If the child spends 24 hours making the cookies, how many cookies are made in total?

Gemma 2B:

     Reasoning: The child can make 15*24 = <<15*24=360>>360 cookies in total.
    ### Answer: 360

Expected answer: 360

Correct? Yes

🔗 Follow-up

Problem: If the same child decides to increase their cookie production rate and can now make 40 cookies in one hour, how many cookies are made when they spend the same amount of time (24 hours) baking?

Gemma 2B:

     Reasoning: The child can make 40*24 = <<40*24=960>>960 cookies in total.
    ### Answer: 960

Expected answer: 960

Correct? Yes

🔗 Problem

Problem: A silversmith has 16 silver rings in stock. He decided to create more rings and ended up with 28 silver and 24 gold rings. Then he subtracted from them the number of his original stock of silver rings. He traded some rings and ended up with 21 rings less than what he had after the creation stage. After that, for a special order, he created 26 times the number of rings he had left. In addition, he had made 7 platinum and 47 bronze rings for another order. How many rings does the silversmith have in total now?

Gemma 2B:

     Reasoning: The silversmith created 28+24 = <<28+24=52>>52 rings.
    He had 52-16 = <<52-16=36>>36 rings after subtracting his original stock.
    He traded some rings and ended up with 36-21 = <<36-21=15>>15 rings.
    For the special order, he created 26*15 = <<26*15=390>>390 rings.
    In addition, he made 7+47 = <<7+47=54>>54 rings for another order.
    The silversmith has 390+54 = <<390+54=444>>444 rings in total now.
    ### Answer: 444

Expected answer: 444

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, let's consider the silversmith initially had made not 28 silver rings, but only 18. He still had the 24 gold rings and subtracted from them his original stock of 16 silver rings. He continues through the same steps of trading, creating the rings for the special order, and the other rings as before. How many rings does the silversmith have now if he started with 18 silver rings instead of 28?

Gemma 2B:

     Reasoning: The silversmith created 18+24 = <<18+24=42>>42 rings.
    He had 42-16 = <<42-16=26>>26 rings after subtracting his original stock.
    He traded some rings and ended up with 26-21 = <<26-21=5>>5 rings.
    For the special order, he created 26*5 = <<26*5=130>>130 rings.
    In addition, he made 7+47 = <<7+47=54>>54 rings for another order.
    The silversmith has 130+54 = <<130+54=184>>184 rings in total now.
    ### Answer: 184

Expected answer: 184

Correct? Yes

🔗 Problem

Problem: A gardener plants flowers in several rows. Each row contains 40 flowers, but due to the rough soil conditions only half of them grow properly. In total, 19 rows are planted this way. Additionally, the gardener plants another small batch of 18 bulbs in one corner and 48 in another corner of the garden. What is the difference between the total number of flowers in the rows and the small corners?

Gemma 2B:

     Reasoning: The gardener plants 19 rows of flowers, each row containing 40 flowers. However, only half of them grow properly. So, the total number of flowers in the rows is 19*40/2 = <<19*40/2=380>>380.
    The gardener plants another small batch of 18 bulbs in one corner and 48 in another corner of the garden. So, the total number of flowers in the small corners is 18+48 = <<18+48=66>>66.
    The difference between the total number of flowers in the rows and the small corners is 380-66 = <<380-66=314>>314.
    ### Answer: 314

Expected answer: 314

Correct? Yes

🔗 Problem

Problem: In the forest, a certain bird lays an average of 11 eggs per month. This month, the bird laid 4 times the average. Due to extreme weather conditions, the forest welcoming committee distributed an additional 40 eggs to various nests to support the bird population. How many eggs are there in the forest this month?

Gemma 2B:

     Reasoning: The bird laid 11*4 = <<11*4=44>>44 eggs this month.
    There are 44+40 = <<44+40=84>>84 eggs in the forest this month.
    ### Answer: 84

Expected answer: 84

Correct? Yes

🔗 Follow-up

Problem: After examining the ground for fallen eggs, the forest rangers found more eggs which they distributed to the nests. They found 216 eggs in total, and divided them between 18 nests, before adding them to the initial number of eggs in the forest. How many eggs are there in the forest now?

Gemma 2B:

     Reasoning: The rangers added 216/18 = <<216/18=12>>12 eggs to each nest.
    There are now 84+12 = <<84+12=96>>96 eggs in the forest.
    ### Answer: 96

Expected answer: 96

Correct? Yes

🔗 Problem

Problem: You are mixing paints to create different shades. In one mixture, you have 41 drops of red paint. You then add 13 drops of white paint and the same amount of red paint as before. You take a sample of this mixture, which is 34 drops, and add that to a new mixture. Then take away the same amount of the 34 drop sample that you took originally. How many drops of paint are there in the new mixture?

Gemma 2B:

     Reasoning: You have 41 drops of red paint.
    You add 13 drops of white paint and the same amount of red paint as before, so you have 41+13+41 = <<41+13+41=95>>95 drops of paint in the first mixture.
    You take a sample of this mixture, which is 34 drops, and add that to a new mixture, so you have 34 drops of paint in the new mixture.
    Then take away the same amount of the 34 drop sample that you took originally, so you have 34-34 = <<34-34=0>>0 drops of paint in the new mixture.
    ### Answer: 0

Expected answer: 95

Correct? No

🔗 Problem

Problem: A small toy car factory made 32 toy cars on Monday, but only 27 on Tuesday. They multiply the difference by 49 to determine their weekly goal. The staff number in the factory is 12, and every staff member makes 9 toy cars a day. They add 45 to the total number of toy cars prepared by staff members. On Friday, they prepare 31 additional toy cars and add this to the weekly goal and staff prepared cars. How many toy cars in total were made in this process?

Gemma 2B:

     Reasoning: The difference between the number of toy cars made on Monday and Tuesday is 32-27 = <<32-27=5>>5.
    The weekly goal is 5*49 = <<5*49=245>>245 toy cars.
    The staff members make 12*9 = <<12*9=108>>108 toy cars a day.
    The total number of toy cars prepared by staff members is 108+45 = <<108+45=153>>153 toy cars.
    On Friday, they prepare 31 additional toy cars, so the total number of toy cars made is 245+153+31 = <<245+153+31=429>>429 toy cars.
    ### Answer: 429

Expected answer: 429

Correct? Yes

🔗 Follow-up

Problem: After their first week, the small toy car factory decided to change their production strategy. The staff now produce only 6 toy cars each day instead of 9. They still add 45 to the total number of toy cars prepared by the staff members. Keeping their weekly goal constant and their Friday production same as last week, how many toy cars in total were made this week?

Gemma 2B:

     Reasoning: The staff members now make 12*6 = <<12*6=72>>72 toy cars a day.
    The total number of toy cars prepared by staff members is 72+45 = <<72+45=117>>117 toy cars.
    The total number of toy cars made this week is 245+117+31 = <<245+117+31=393>>393 toy cars.
    ### Answer: 393

Expected answer: 393

Correct? Yes

🔗 Problem

Problem: A farmer harvested 45 carrots in one day from his farm. He noticed that for every carrot over 44 per day, he can earn 29 dollars. How much would the farmer have earned if this continued?

Gemma 2B:

     Reasoning: The farmer harvested 45 carrots in one day, which is 45 - 44 = <<45-44=1>>1 carrot over the base amount.
    For every carrot over 44, he earns 29 dollars, so for 1 carrot, he earns 1 * 29 = <<1*29=29>>29 dollars.
    ### Answer: 29

Expected answer: 29

Correct? Yes

🔗 Follow-up

Problem: Continuing from our previous scenario, let's suppose that the market rate for extra carrots has now changed. Now, for every carrot that the farmer harvests over 44 per day, he can earn 41 dollars instead of 29. How much would his new earnings be if he still harvested 45 carrots in one day?

Gemma 2B:

     Reasoning: The farmer still harvested 45 carrots in one day, which is 45 - 44 = <<45-44=1>>1 carrot over the base amount.
    For every carrot over 44, he now earns 41 dollars, so for 1 carrot, he earns 1 * 41 = <<1*41=41>>41 dollars.
    ### Answer: 41

Expected answer: 41

Correct? Yes

🔗 Problem

Problem: In a sock factory, a worker started with 26 pairs of socks. Unfortunately, 50 pairs got torn and had to be discarded. The worker was able to produce 36 more pairs to replace them. Each pair of socks is sold for $37. After earning from the sock sales, the worker found a $13 bill on the floor. How much money does the worker have in total?

Gemma 2B:

     Reasoning: The worker initially had 26 pairs of socks, but 50 pairs got torn, leaving 26-50 = <<26-50=-24>>-24 pairs. However, this calculation is incorrect because the worker cannot have a negative number of pairs. The correct calculation should be 26-50 = <<26-50=-24>>-24 pairs, but since the worker cannot have a negative number of pairs, we should consider the worker had 0 pairs after the tearing. The worker then produced 36 more pairs, so the total number of pairs is 0+36 = <<0+36=36>>36 pairs. Each pair is sold for $37, so the worker earned 36*37 = <<36*37=1332>>$1332 from the sock sales. The worker also found a $13 bill on the floor, so the total amount of money the worker has is $1332+$13 = <<1332+13=1345>>$1345.
    ### Answer: $1345

Expected answer: 457

Correct? No

🔗 Problem

Problem: A jewelry maker starts with 38 beads to make a bracelet. However, the number of beads was not right, so she removed a number of beads equal to dividing 560 by 40. However, she thinks her initial count may have been wrong and she may have actually started with 15 more beads than she initially thought. After adjusting the count and removing some beads, she adds one more bead, and then 39 more. How many beads does the jewelry maker have now?

Gemma 2B:

     Reasoning: The jewelry maker removed 560/40 = <<560/40=14>>14 beads.
    The jewelry maker may have actually started with 38+15 = <<38+15=53>>53 beads.
    After removing 14 beads, the jewelry maker has 53-14 = <<53-14=39>>39 beads.
    After adding one more bead, the jewelry maker has 39+1 = <<39+1=40>>40 beads.
    After adding 39 more beads, the jewelry maker has 40+39 = <<40+39=79>>79 beads.
    ### Answer: 79

Expected answer: 79

Correct? Yes

🔗 Follow-up

Problem: In the continuation of the previous story, the jewelry maker decided to make another adjustment after adding beads to her bracelet. She then removed again the same number of beads she removed earlier, equal to dividing 560 by 40. After that, she finds a small box with an additional 20 beads in it that she decides to add to the bracelet. How many beads does the jewelry maker have now on her bracelet?

Gemma 2B:

     Reasoning: The jewelry maker removed 560/40 = <<560/40=14>>14 beads.
    After removing 14 beads, the jewelry maker has 79-14 = <<79-14=65>>65 beads.
    After adding 20 beads, the jewelry maker has 65+20 = <<65+20=85>>85 beads.
    ### Answer: 85

Expected answer: 85

Correct? Yes

🔗 Follow-up

Problem: In a different scenario, suppose the jewelry maker initially had 50 beads instead of 38. She still removed a number of beads equal to 560 divided by 40. Afterwards, she realized she might have actually started with 15 more beads than she originally thought. After correcting her count and removing some beads, she added one more bead, and then 39 more beads. How many beads does the jewelry maker have now in this case?

Gemma 2B:

     Reasoning: The jewelry maker removed 560/40 = <<560/40=14>>14 beads.
    The jewelry maker may have actually started with 50+15 = <<50+15=65>>65 beads.
    After removing 14 beads, the jewelry maker has 65-14 = <<65-14=51>>51 beads.
    After adding one more bead, the jewelry maker has 51+1 = <<51+1=52>>52 beads.
    After adding 39 more beads, the jewelry maker has 52+39 = <<52+39=91>>91 beads.
    ### Answer: 91

Expected answer: 91

Correct? Yes

🔗 Problem

Problem: In an aquarium, there are initially 30 sharks. But then, 23 of them are moved to a different area of the aquarium. A few days later, an additional 14 sharks are brought in, followed by 3 more being moved to the other area. The number of sharks is then multiplied by 43 for a research study. What is the final figure for the research?

Gemma 2B:

     Reasoning: Initially, there are 30 sharks in the aquarium.
    After 23 sharks are moved, there are 30-23 = <<30-23=7>>7 sharks left.
    After 14 sharks are brought in, there are 7+14 = <<7+14=21>>21 sharks.
    After 3 sharks are moved, there are 21-3 = <<21-3=18>>18 sharks left.
    The final figure for the research is 18*43 = <<18*43=774>>774 sharks.
    ### Answer: 774

Expected answer: 774

Correct? Yes

🔗 Follow-up

Problem: We are back at the aquarium again! Previously, we mentioned the number of sharks being multiplied by 43 for a research study. But this time, instead of multiplying by 43, the scientists made a mistake and only multiplied it by 4. What would the new figure for the experiment be?

Gemma 2B:

     Reasoning: The number of sharks is 18.
    The new figure for the experiment is 18*4 = <<18*4=72>>72 sharks.
    ### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Problem

Problem: In a puzzle game, each round you collect 150 points which are then divided by 10 to determine the number of gold coins you earn. After two rounds, you earned some gold coins. In the third round, you collected 28 emeralds and 14 sapphires but you had to sacrifice the same amount of gold coins as you earned in the first two rounds. How many emeralds and sapphires did you have left after the third round?

Gemma 2B:

     Reasoning: In the first two rounds, you earned 150/10 = <<150/10=15>>15 gold coins each round, so you earned a total of 15*2 = <<15*2=30>>30 gold coins in the first two rounds.
    In the third round, you had to sacrifice 30 gold coins, so you had 28+14-30 = <<28+14-30=12>>12 emeralds and sapphires left after the third round.
    ### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: After the third round of the puzzle game, you decided to combine all of your remaining emeralds and sapphires into powerful jewels. Each jewel requires the exact same amount of emeralds and sapphires that you had left. However, the process of creation multiplies the total number of your existing jewels with itself. How many powerful jewels did you end up having after this process?

Gemma 2B:

     Reasoning: You had 12 emeralds and sapphires left after the third round, so you could create 12 jewels.
    The process of creation multiplies the total number of your existing jewels with itself, so you ended up having 12*12 = <<12*12=144>>144 powerful jewels.
    ### Answer: 144

Expected answer: 144

Correct? Yes

🔗 Follow-up

Problem: In the initial phase of the puzzle game, instead of collecting 150 points in each of the first two rounds, let's say you managed to collect fewer points such that each round you earned only 15 gold coins as the points were divided by 10. Therefore, after the second round, you had a different amount of gold coins. In the third round, you collected 28 emeralds and 14 sapphires but had to sacrifice the same newly calculated amount of gold coins (as per the points collected in the first two rounds). How many emeralds and sapphires did you have left after adjusting for the gold coin sacrifice in the third round?

Gemma 2B:

     Reasoning: In the first two rounds, you earned 15 gold coins each round, so you earned a total of 15*2 = <<15*2=30>>30 gold coins in the first two rounds.
    In the third round, you had to sacrifice 30 gold coins, so you had 28+14-30 = <<28+14-30=12>>12 emeralds and sapphires left after the third round.
    ### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: A train gets to carry 15 containers every day. On Fridays, the train gets to carry an extra 12 containers than usual. The following Monday, the train carries an additional 26 containers. However, on Wednesday, the load decreases by 32 containers. For a particular trip, the train is coupled with 2 more containers, and after it makes one stop, an additional 48 containers are loaded onto the train. How many containers is the train carrying at this point?

Gemma 2B:

     Reasoning: The train carries 15 containers every day.
    On Fridays, the train carries an extra 12 containers than usual, so it carries 15+12 = <<15+12=27>>27 containers on Fridays.
    On the following Monday, the train carries an additional 26 containers, so it carries 27+26 = <<27+26=53>>53 containers on Monday.
    On Wednesday, the load decreases by 32 containers, so the train carries 53-32 = <<53-32=21>>21 containers on Wednesday.
    For a particular trip, the train is coupled with 2 more containers, so it carries 21+2 = <<21+2=23>>23 containers for the trip.
    After it makes one stop, an additional 48 containers are loaded onto the train, so the train is carrying 23+48 = <<23+48=71>>71 containers at this point.
    ### Answer: 71

Expected answer: 71

Correct? Yes

🔗 Problem

Problem: A lemon farmer had harvested 39 lemons in the morning and 33 in the afternoon. Unfortunately, 12 lemons got spoiled by the end of the day. The next day, the farmer used 23 lemons to make lemonade. How many lemons did he have left after making the lemonade?

Gemma 2B:

     Reasoning: The farmer had 39+33 = <<39+33=72>>72 lemons in total.
    After 12 lemons got spoiled, he had 72-12 = <<72-12=60>>60 lemons left.
    After making lemonade, he had 60-23 = <<60-23=37>>37 lemons left.
    ### Answer: 37

Expected answer: 37

Correct? Yes

🔗 Follow-up

Problem: In our previous calculations, we found out how many lemons the farmer had left after some got spoiled and some were used to make lemonade. However, what if the farmer actually had 24 lemons get spoiled on the first day instead of 12? How many lemons would the farmer have left after making the lemonade?

Gemma 2B:

     Reasoning: The farmer had 39+33 = <<39+33=72>>72 lemons in total.
    After 24 lemons got spoiled, he had 72-24 = <<72-24=48>>48 lemons left.
    After making lemonade, he had 48-23 = <<48-23=25>>25 lemons left.
    ### Answer: 25

Expected answer: 25

Correct? Yes

🔗 Problem

Problem: A bee lands on 33 flowers in an hour. If the bee is collecting 15 nectar droplets from each flower, how many nectar droplets does it have after an hour if it started with 26 nectar droplets?

Gemma 2B:

     Reasoning: The bee collects 33*15 = <<33*15=495>>495 nectar droplets in an hour.
    The bee has 495+26 = <<495+26=521>>521 nectar droplets after an hour.
    ### Answer: 521

Expected answer: 521

Correct? Yes

🔗 Follow-up

Problem: If instead of starting with 26 nectar droplets, the bee had initially found 49 nectar droplets before it started its hour of flower visits, how many nectar droplets would the bee have after an hour of collecting nectar from 33 flowers with 15 nectar droplets each?

Gemma 2B:

     Reasoning: The bee collects 33*15 = <<33*15=495>>495 nectar droplets in an hour.
    The bee has 495+49 = <<495+49=544>>544 nectar droplets after an hour.
    ### Answer: 544

Expected answer: 544

Correct? Yes

🔗 Problem

Problem: A company produces 36 marshmallow packs in an hour. To meet a sudden increase in demand, they decide to increase their production. They add an extra 350 marshmallows to their daily production, which is distributed evenly over 7 hours of their working day. Additionally, they add another 6 marshmallow packs to their hourly production. But, due to some limitations, they end up producing 43 less packs per hour than their goal. How many marshmallow packs per hour are they now producing?

Gemma 2B:

     Reasoning: The company adds 350 marshmallows to their daily production, which is distributed evenly over 7 hours of their working day. So, they add 350/7 = <<350/7=50>>50 marshmallows per hour.
    They add another 6 marshmallow packs to their hourly production. So, they add 6*36 = <<6*36=216>>216 marshmallows per hour.
    So, they add 50+216 = <<50+216=266>>266 marshmallows per hour.
    They end up producing 43 less packs per hour than their goal. So, they produce 36+6-43 = <<36+6-43=-1>>-1 marshmallow packs per hour.
    But, they can't produce negative packs. So, they produce 0 marshmallow packs per hour.
    ### Answer: 0

Expected answer: 49

Correct? No

🔗 Problem

Problem: A wizard casts a spell that produces 882 glimmering lights over a span of 21 days. That's an average of how many lights a day? In comparison, another wizard casts a spell that produces 460 glowing orbs in 20 days. What is the daily average here? Now, let's assume that the difference in their daily averages times the second wizard's daily average is a magical constant represented by 'n'. Can you find out what 'n' is?

Gemma 2B:

     Reasoning: The first wizard produces 882/21 = <<882/21=42>>42 glimmering lights per day.
    The second wizard produces 460/20 = <<460/20=23>>23 glowing orbs per day.
    The difference in their daily averages is 42-23 = <<42-23=19>>19.
    The magical constant 'n' is the difference in their daily averages times the second wizard's daily average, which is 19*23 = <<19*23=437>>437.
    ### Answer: 437

Expected answer: 437

Correct? Yes

🔗 Problem

Problem: A candy factory has 20 different flavors of candy. Their bestselling flavors are the Sugar Rush, which has 14 different base ingredients, the Candy Twirl, which has 25 base ingredients, and the Jawbreaker, which has 16 base ingredients. They create a Special Mix which combines all of these bestsellers and adds 43 extra goodies, including sprinkles and marshmallows. To create a limited edition candy, they take a piece of the Special Mix, add 7 uniquely crafted sweets, then combine this with one of each flavor from their 20 different flavored candies (excluding 19 of them so it's not too overwhelming). They then top it all off by removing 3 experimental sweets that didn't taste quite right. What is the count of various components used in creating this limited edition candy?

Gemma 2B:

     Reasoning: The Special Mix has 14+25+16+43 = <<14+25+16+43=98>>98 components.
    The limited edition candy has 98+7+20-19-3 = <<98+7+20-19-3=103>>103 components.
    ### Answer: 103

Expected answer: 103

Correct? Yes

🔗 Follow-up

Problem: Further consider the candy factory's process. If instead of the Jawbreaker having 16 base ingredients, it had 23 base ingredients instead, then how many different components would be used in creating the same limited edition candy as before?

Gemma 2B:

     Reasoning: The Special Mix would then have 14+25+23+43 = <<14+25+23+43=105>>105 components.
    The limited edition candy would then have 105+7+20-19-3 = <<105+7+20-19-3=109>>109 components.
    ### Answer: 109

Expected answer: 110

Correct? No

🔗 Problem

Problem: In a special operation, 32 police officers were assigned to the north district, 33 were sent to the south district, and 29 officers were held for the downtown district. After the operation, 21 officers from the downtown district were transferred elsewhere. A week later, on a different assignment, 39 officers were added to the remaining duty force. Later that day, another 14 officers joined the force. How many officers were on duty by the end of the day?

Gemma 2B:

     Reasoning: There were 32+33+29 = <<32+33+29=94>>94 officers in total at the beginning.
    After 21 officers were transferred, there were 94-21 = <<94-21=73>>73 officers left.
    After 39 officers were added, there were 73+39 = <<73+39=112>>112 officers.
    After 14 officers joined, there were 112+14 = <<112+14=126>>126 officers.
    ### Answer: 126

Expected answer: 126

Correct? Yes

🔗 Follow-up

Problem: The previous problem had us determine the total number of police officers on duty under certain conditions. Now, let's imagine a slightly different scenario. Like the previous situation, there were still 32 officers assigned to the north district and 33 sent to the south. The number for the downtown district was also the same, at 29. However, this time around, only 21 officers from the total force were transferred elsewhere instead of the original scenario's subtraction. A week later, an additional 22 officers, fewer than the 39 from the original scenario, were brought in for a different assignment. That same day, another addition of 14 officers was made, just like with the initial series of events. New question: How many officers total were on duty by the end of the day in this amended scenario?

Gemma 2B:

     Reasoning: There were 32+33+29 = <<32+33+29=94>>94 officers in total at the beginning.
    After 21 officers were transferred, there were 94-21 = <<94-21=73>>73 officers left.
    After 22 officers were added, there were 73+22 = <<73+22=95>>95 officers.
    After 14 officers joined, there were 95+14 = <<95+14=109>>109 officers.
    ### Answer: 109

Expected answer: 109

Correct? Yes

🔗 Problem

Problem: The distance between the Moon and the Earth changes throughout the month. On one particular day, the distance was 36 million kilometers but decreased by 19 million kilometers later in the month. Then it increased again by 11 million kilometers. If that distance, in millions of kilometers, times 19 minus 27 equals to a certain value, what is the value?

Gemma 2B:

     Reasoning: The distance between the Moon and the Earth changed by 36-19 = <<36-19=17>>17 million kilometers.
    The distance between the Moon and the Earth changed by 17+11 = <<17+11=28>>28 million kilometers.
    The value is 28*19-27 = <<28*19-27=505>>505.
    ### Answer: 505

Expected answer: 505

Correct? Yes

🔗 Follow-up

Problem: In the scenario mentioned earlier about the distance between the Moon and the Earth: on one particular day, the distance was 36 million kilometers but decreased by 19 million kilometers later in the month. It further increased by 11 million kilometers. Previously we calculated that distance, in millions of kilometers, times 19 and subtracted 27. But what if, instead of subtracting 27, we were to subtract 45? What would be the new value of the total distance?

Gemma 2B:

     Reasoning: The distance between the Moon and the Earth changed by 36-19 = <<36-19=17>>17 million kilometers.
    The distance between the Moon and the Earth changed by 17+11 = <<17+11=28>>28 million kilometers.
    The new value of the total distance is 28*19-45 = <<28*19-45=487>>487.
    ### Answer: 487

Expected answer: 487

Correct? Yes

🔗 Problem

Problem: A tiger has an average step length of 9 meters. If a tiger took two steps and then leaped 44 meters, it would have covered a certain distance. Another tiger covered a distance combining 23 meters with a leap and a 46-meter run but then retraces the distance equal to the first tiger's steps and the leap. How much distance did the second tiger cover finally?

Gemma 2B:

     Reasoning: The first tiger covered a distance of 9*2+44 = <<9*2+44=62>>62 meters.
    The second tiger covered a distance of 23+46 = <<23+46=69>>69 meters.
    The second tiger retraced the distance equal to the first tiger's steps and the leap, which is 62 meters.
    The second tiger covered a final distance of 69-62 = <<69-62=7>>7 meters.
    ### Answer: 7

Expected answer: 7

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous situation, after retracing the distance equal to the first tiger's steps and the leap, the second tiger then decides to run an additional 30 meters before making a 44-meter leap. How much total distance did the second tiger cover after all these movements?

Gemma 2B:

     Reasoning: The second tiger covered a distance of 7+30 = <<7+30=37>>37 meters after retracing the distance equal to the first tiger's steps and the leap.
    The second tiger then made a 44-meter leap.
    The second tiger covered a total distance of 37+44 = <<37+44=81>>81 meters after all these movements.
    ### Answer: 81

Expected answer: 81

Correct? Yes

🔗 Problem

Problem: A toothpaste factory produces 26 tubes of toothpaste every hour. On Sundays, they work for 7 hours and produce additional 8 tubes of toothpaste. So, in one Sunday, they produce ((26 * 7) + 8) tubes. The following Monday, they continue their production by adding another 31 tubes to their Sunday's total. In parallel, in the packaging department, they have 50 empty boxes. They use 19 of them for another department, leaving them with (50 - 19) boxes. The total number of toothpaste tubes ready is calculated by adding the packaged boxes number with Monday's production. On Tuesday, they produced an additional 48 tubes of toothpaste. What is the total number of produced toothpaste tubes until Tuesday, inclusive?

Gemma 2B:

     Reasoning: The factory produces 26 tubes of toothpaste every hour. On Sundays, they work for 7 hours and produce additional 8 tubes of toothpaste. So, in one Sunday, they produce ((26 * 7) + 8) = <<(26 * 7) + 8=182+8=190>>190 tubes.

    The following Monday, they continue their production by adding another 31 tubes to their Sunday's total. So, the total number of toothpaste tubes produced until Monday is (190 + 31) = <<190 + 31=221>>221 tubes.

    In the packaging department, they have 50 empty boxes. They use 19 of them for another department, leaving them with (50 - 19) = <<50 - 19=31>>31 boxes.

    The total number of toothpaste tubes ready is calculated by adding the packaged boxes number with Monday's production. So, the total number of toothpaste tubes ready is (221 + 31) = <<221 + 31=252>>252 tubes.

    On Tuesday, they produced an additional 48 tubes of toothpaste. So, the total number of produced toothpaste tubes until Tuesday, inclusive, is (252 + 48) = <<252 + 48=300>>300 tubes.

    ### Answer: 300

Expected answer: 300

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, the toothpaste factory was producing 26 tubes of toothpaste every hour on Sundays. Now, consider a different Sunday where they changed their production to 22 tubes every hour instead, while still working for 7 hours and producing 8 additional tubes. They continue their production on Monday by adding an additional 31 tubes. With the same scenario in the packaging department, where they started with 50 boxes and used 19 of them leaving (50 - 19) boxes. The total number of toothpaste tubes ready for packaging is calculated by adding the packaged box number with Monday's production. If they produced an additional 48 tubes on Tuesday, how many tubes of toothpaste have they produced up till Tuesday now?

Gemma 2B:

     Reasoning: On Sundays, they now produce 22 tubes of toothpaste every hour. So, in one Sunday, they produce ((22 * 7) + 8) = <<(22 * 7) + 8=154+8=162>>162 tubes.

    The following Monday, they continue their production by adding another 31 tubes to their Sunday's total. So, the total number of toothpaste tubes produced until Monday is (162 + 31) = <<162 + 31=193>>193 tubes.

    In the packaging department, they have 50 empty boxes. They use 19 of them for another department, leaving them with (50 - 19) = <<50 - 19=31>>31 boxes.

    The total number of toothpaste tubes ready is calculated by adding the packaged boxes number with Monday's production. So, the total number of toothpaste tubes ready is (193 + 31) = <<193 + 31=224>>224 tubes.

    On Tuesday, they produced an additional 48 tubes of toothpaste. So, the total number of produced toothpaste tubes until Tuesday, inclusive, is (224 + 48) = <<224 + 48=272>>272 tubes.

    ### Answer: 272

Expected answer: 272

Correct? Yes

🔗 Problem

Problem: In a magical forest, a unicorn has 42 rainbow pebbles. A day later, it finds 26 more. It also has a stash of 44 dreamberries. Later on, the unicorn gathers 33 more rainbow pebbles and adds them with its stash of dreamberries. Finally, the unicorn finds 40 magical dandelions and adds them to his stash, but oh no, he loses 14! How many items does the unicorn have altogether after these events?

Gemma 2B:

     Reasoning: The unicorn has 42+26 = <<42+26=68>>68 rainbow pebbles after finding more.
    The unicorn has 68+44 = <<68+44=112>>112 items after adding its dreamberries.
    The unicorn has 112+33 = <<112+33=145>>145 items after gathering more rainbow pebbles.
    The unicorn has 145+40 = <<145+40=185>>185 items after finding magical dandelions.
    The unicorn has 185-14 = <<185-14=171>>171 items after losing some.
    ### Answer: 171

Expected answer: 171

Correct? Yes

🔗 Follow-up

Problem: In the previous magical scenario, consider that instead of initially having 42 rainbow pebbles, the unicorn started with just 40. It still finds 26 more the following day. Maintaining his stash of 44 dreamberries, the unicorn still accumulates 33 more rainbow pebbles and adds them to the dreamberries. Once again, the unicorn ventures to obtain an additional 40 magical dandelions, but unfortunately, he loses 14. After these events, how many items does the unicorn have?

Gemma 2B:

     Reasoning: The unicorn has 40+26 = <<40+26=66>>66 rainbow pebbles after finding more.
    The unicorn has 66+44 = <<66+44=110>>110 items after adding its dreamberries.
    The unicorn has 110+33 = <<110+33=143>>143 items after gathering more rainbow pebbles.
    The unicorn has 143+40 = <<143+40=183>>183 items after finding magical dandelions.
    The unicorn has 183-14 = <<183-14=169>>169 items after losing some.
    ### Answer: 169

Expected answer: 169

Correct? Yes

🔗 Problem

Problem: A pirate captain has a treasure chest containing 23 types of jewels. Each type has 28 jewels. Tired from his adventure, he mistakenly lost 40 jewels on his way back to his ship. The next day, he luckily found 16 jewels from a deserted island. How many jewels does he have now in his treasure chest?

Gemma 2B:

     Reasoning: The pirate captain has 23*28 = <<23*28=644>>644 jewels in his treasure chest.
    After losing 40 jewels, he has 644-40 = <<644-40=604>>604 jewels left.
    After finding 16 jewels, he has 604+16 = <<604+16=620>>620 jewels now.
    ### Answer: 620

Expected answer: 620

Correct? Yes

🔗 Follow-up

Problem: Following the discovery of additional jewels, the pirate captain realized he had miscalculated the number of types of jewels in his original stash. Instead of 23 types of jewels, he remembered that he actually only had 17 types originally, with each type still containing 28 jewels. After recalculating his treasure and still taking into account the loss of 40 jewels and the 16 he found on a deserted island, how many jewels does he have now?

Gemma 2B:

     Reasoning: The pirate captain has 17*28 = <<17*28=476>>476 jewels in his treasure chest.
    After losing 40 jewels, he has 476-40 = <<476-40=436>>436 jewels left.
    After finding 16 jewels, he has 436+16 = <<436+16=452>>452 jewels now.
    ### Answer: 452

Expected answer: 452

Correct? Yes

🔗 Problem

Problem: In a distant galaxy, a star shines brightly with 38 neutrons. It then gains 4 more. This total number gets multiplied by 18 to create a sensational energy output. During an explosion, it additionally releases the energy equivalent to 6 plus 25. How much total energy does the star emit?

Gemma 2B:

     Reasoning: The star has 38+4 = <<38+4=42>>42 neutrons.
    The energy output is 42*18 = <<42*18=756>>756.
    The energy released during the explosion is 6+25 = <<6+25=31>>31.
    The total energy emitted by the star is 756+31 = <<756+31=787>>787.
    ### Answer: 787

Expected answer: 787

Correct? Yes

🔗 Follow-up

Problem: Now consider instead that the star had only 38 neutrons initially, and then it gains only 4 more. This total number is then multiplied by 10, for a lower energy output. During an explosion, it still releases additional energy equivalent to 6 plus 25. Now, how much total energy does the star emit?

Gemma 2B:

     Reasoning: The star has 38+4 = <<38+4=42>>42 neutrons.
    The energy output is 42*10 = <<42*10=420>>420.
    The energy released during the explosion is 6+25 = <<6+25=31>>31.
    The total energy emitted by the star is 420+31 = <<420+31=451>>451.
    ### Answer: 451

Expected answer: 451

Correct? Yes

🔗 Problem

Problem: A gardener planted 13 Sunflowers in his garden. The next day, he worked out that he needed to plant more, with the number being calculated as 37 times the number of petals on one sunflower, which is 5, minus 18. On the following day, he subtracted 10 flowers from that number, then added his initial sunflowers back, creating a new total. Meanwhile, he figured out that in a special part of his garden, ideal for 92 orchids he had, each spot can hold 23, so he calculated how many spots needed. By the end of the week, he summed up the total number of plants he worked on and the spots needed, then he doubled that total for no particular reason. How many did he end up with?

Gemma 2B:

     Reasoning: The gardener needed to plant 37*5-18 = <<37*5-18=167>>167 Sunflowers the next day.
    After subtracting 10 flowers, he had 167-10 = <<167-10=157>>157 Sunflowers.
    Adding back his initial sunflowers, he had 157+13 = <<157+13=170>>170 Sunflowers in total.
    The gardener needed 92/23 = <<92/23=4>>4 spots for his orchids.
    By the end of the week, he worked on 170+4 = <<170+4=174>>174 plants and spots needed.
    Doubling that total, he ended up with 174*2 = <<174*2=348>>348 plants and spots needed.
    ### Answer: 348

Expected answer: 348

Correct? Yes

🔗 Follow-up

Problem: After all of his calculations and planting, the gardener discovered an error in his original calculations: instead of 37 times the number of petals on one sunflower, which is 5, it should have been 47 times the number of petals on one sunflower, minus 18. He corrected this mistake in his calculations, following the same steps as before, then doubled that total for no particular reason. How many did he end up with by using this new calculation?

Gemma 2B:

     Reasoning: The gardener needed to plant 47*5-18 = <<47*5-18=217>>217 Sunflowers the next day.
    After subtracting 10 flowers, he had 217-10 = <<217-10=207>>207 Sunflowers.
    Adding back his initial sunflowers, he had 207+13 = <<207+13=220>>220 Sunflowers in total.
    The gardener needed 92/23 = <<92/23=4>>4 spots for his orchids.
    By the end of the week, he worked on 220+4 = <<220+4=224>>224 plants and spots needed.
    Doubling that total, he ended up with 224*2 = <<224*2=448>>448 plants and spots needed.
    ### Answer: 448

Expected answer: 448

Correct? Yes

🔗 Problem

Problem: In a particular pond, there are 18 frogs. Each frog can catch 21 flies in a day. How many flies do all the frogs catch in a day?

Gemma 2B:

     Reasoning: There are 18 frogs, and each frog can catch 21 flies in a day.
    Therefore, the total number of flies caught by all the frogs in a day is 18 * 21 = <<18*21=378>>378 flies.
    ### Answer: 378

Expected answer: 378

Correct? Yes

🔗 Follow-up

Problem: Using the initial information from the previous problem where 18 frogs catch 21 flies each in a day (resulting in a total of 'j' flies), imagine the scenario where a particularly voracious toad comes by the next day and catches an additional 39 flies. How many flies have been caught in total over the two days then?

Gemma 2B:

     Reasoning: From the previous problem, we know that 18 frogs catch 21 flies each in a day, resulting in a total of 'j' flies. The toad catches an additional 39 flies. Therefore, the total number of flies caught over the two days is 'j' + 39 flies.
    ### Answer: j + 39

Expected answer: 417

Correct? No

🔗 Follow-up

Problem: Using the information from the previous problem, now consider if the number of frogs in the pond increased to 46. If each frog can still catch 21 flies in a day, how many flies do all the frogs catch in a day now?

Gemma 2B:

     Reasoning: There are now 46 frogs, and each frog can still catch 21 flies in a day.
    Therefore, the total number of flies caught by all the frogs in a day is 46 * 21 = <<46*21=966>>966 flies.
    ### Answer: 966

Expected answer: 966

Correct? Yes

🔗 Problem

Problem: A community center has 21 chairs in their main meeting room. They are supplemented with an additional 22 chairs from the storage room for a large event. How many chairs are in the meeting room now for the event?

Gemma 2B:

     Reasoning: The community center has 21+22 = <<21+22=43>>43 chairs in the meeting room now for the event.
    ### Answer: 43

Expected answer: 43

Correct? Yes

🔗 Follow-up

Problem: Now, instead of starting with 21 chairs in the main meeting room at the community center, suppose they had only 12 chairs. They still supplement with an additional 22 chairs from the storage room for the event. How many chairs are in the meeting room now for the event?

Gemma 2B:

     Reasoning: The community center has 12+22 = <<12+22=34>>34 chairs in the meeting room now for the event.
    ### Answer: 34

Expected answer: 34

Correct? Yes

🔗 Problem

Problem: There are 14 elephants in a conservation park. This year, 11 new baby elephants were born, and the park received 25 more elephants from various rescues. How many elephants are there in the park now?

Gemma 2B:

     Reasoning: There are 14+11 = <<14+11=25>>25 elephants in the park after the birth of the baby elephants.
    There are 25+25 = <<25+25=50>>50 elephants in the park after receiving more elephants from rescues.
    ### Answer: 50

Expected answer: 50

Correct? Yes

🔗 Follow-up

Problem: Unfortunately, due to unfortunate circumstances, 27 elephants had to be relocated to different parks over the course of the year. How many elephants are left in the park now?

Gemma 2B:

     Reasoning: There are 50-27 = <<50-27=23>>23 elephants left in the park after the relocation.
    ### Answer: 23

Expected answer: 23

Correct? Yes

🔗 Follow-up

Problem: Suppose initially, there were 38 elephants in the conservation park instead of 14. If the park still received 11 new baby elephants and 25 more elephants from various rescues this year, how many elephants would there be in the park now?

Gemma 2B:

     Reasoning: There are 38+11 = <<38+11=49>>49 elephants in the park after the birth of the baby elephants.
    There are 49+25 = <<49+25=74>>74 elephants in the park after receiving more elephants from rescues.
    ### Answer: 74

Expected answer: 74

Correct? Yes

🔗 Problem

Problem: A treasure chest contains 23 emeralds and 30 diamonds. Unfortunately, 39 of the stones are fake and had to be removed. The number of real stones left (y) is multiplied by itself and then 37 is subtracted to get a number (g) that represents the value of the chest. In another chest, there were 540 rubies which have been equally shared amongst 45 pirates, and then 3 are lost in the division. The remaining number (x) is subtracted from the value of the first chest (g) to get a new value. In the same chest as the rubies, there were also 23 pearls and 11 zirconias, but 9 pieces had to be discarded due to damage. The count (s) is subtracted from the new value to determine the value (m) of the remaining treasure. What is the value (m) of the remaining treasure?

Gemma 2B:

     Reasoning: The number of real stones left in the first chest is 23+30-39 = <<23+30-39=14>>14.
    The value of the first chest is 14*14-37 = <<14*14-37=157>>157.
    The number of rubies each pirate gets is 540/45 = <<540/45=12>>12.
    The remaining number of rubies is 12-3 = <<12-3=9>>9.
    The new value is 157-9 = <<157-9=148>>148.
    The count of the remaining pieces is 23+11-9 = <<23+11-9=25>>25.
    The value of the remaining treasure is 148-25 = <<148-25=123>>123.
    ### Answer: 123

Expected answer: 125

Correct? No

🔗 Problem

Problem: There are 6 confirmed UFO sightings in a small city. After a viral event, sightings increase by a daily average obtained by dividing an additional 504 sightings over the next 14 days. Subtract the initial confirmed sightings from this new daily average. Then, multiply it by the result of taking the maximum number of sightings recorded in one day (9) and subtracting the number you would typically dismiss as random (3). How many sightings are there according to this calculation?

Gemma 2B:

     Reasoning: The daily average increase in sightings is 504/14 = <<504/14=36>>36.
    Subtracting the initial sightings, we get 36-6 = <<36-6=30>>30.
    The maximum number of sightings recorded in one day is 9, and we subtract the number typically dismissed as random, which is 3, giving us 9-3 = <<9-3=6>>6.
    Multiplying these results, we have 30*6 = <<30*6=180>>180.
    ### Answer: 180

Expected answer: 180

Correct? Yes

🔗 Follow-up

Problem: After reconsideration, the investigator noticed a mistake in the calculations. They remembered that the maximum number of sightings recorded in one day was actually 35, not 9. If they corrected their mistake and subtracted 3 from 35 instead, and then multiplied by the previously calculated daily increase, what would be the corrected calculated number of sightings?

Gemma 2B:

     Reasoning: The corrected maximum number of sightings recorded in one day is 35, and we subtract the number typically dismissed as random, which is 3, giving us 35-3 = <<35-3=32>>32.
    The previously calculated daily increase in sightings is 30.
    Multiplying these results, we have 30*32 = <<30*32=960>>960.
    ### Answer: 960

Expected answer: 960

Correct? Yes

🔗 Problem

Problem: A blanket maker has 5 square patches of blue material. She wants to make an intricate design that requires her to subtract this from 26*25 square patches of red material. Then, she wants to compare this number to her stock of green material, which is 48*21 square patches, by subtracting the number of red patches from the green patches. How many patches is the difference between her stock of green patches and the red patches needed for the design?

Gemma 2B:

     Reasoning: The blanket maker has 26*25 = <<26*25=650>>650 square patches of red material.
    She needs to subtract the 5 square patches of blue material from the red material, so she has 650-5 = <<650-5=645>>645 square patches of red material left for the design.
    She wants to compare this number to her stock of green material, which is 48*21 = <<48*21=1008>>1008 square patches.
    The difference between her stock of green patches and the red patches needed for the design is 1008-645 = <<1008-645=363>>363 square patches.
    ### Answer: 363

Expected answer: 363

Correct? Yes

🔗 Follow-up

Problem: The blanket maker realized that she made a mistake in her initial calculations. Instead of having 5 patches of blue material, she actually had 27 patches. After correcting her calculations, she subtracted this from 26*25 square patches of red material. Then, she compared this number to her stock of green material, which is 48*21 square patches, by subtracting the number of red patches from the green patches. After making this correction, how many patches is the difference between her stock of green patches and the red patches now required for the design?

Gemma 2B:

     Reasoning: The blanket maker has 26*25 = <<26*25=650>>650 square patches of red material.
    She needs to subtract the 27 square patches of blue material from the red material, so she has 650-27 = <<650-27=623>>623 square patches of red material left for the design.
    She wants to compare this number to her stock of green material, which is 48*21 = <<48*21=1008>>1008 square patches.
    The difference between her stock of green patches and the red patches needed for the design is 1008-623 = <<1008-623=385>>385 square patches.
    ### Answer: 385

Expected answer: 385

Correct? Yes

🔗 Problem

Problem: Lemonville is a small village known for its lemon trees. One year, the villagers picked 38 baskets of lemons from the trees near the river and 24 baskets from the ones near an old well. From the trees near the school, they picked 16 more baskets and from the trees near the mayor's house, they picked 13 more baskets. They realized that their lemons were heavier and they could extract more juice so they decided to get 35 baskets to make lemonade. If each basket of lemons could produce 14 bottles of lemonade, how many bottles of lemonade would they get from the remaining baskets?

Gemma 2B:

     Reasoning: The villagers picked 38+24 = <<38+24=62>>62 baskets from the trees near the river and the old well.
    They picked 16+13 = <<16+13=29>>29 baskets from the trees near the school and the mayor's house.
    They picked a total of 62+29 = <<62+29=91>>91 baskets of lemons.
    They decided to get 35 baskets to make lemonade, so they had 91-35 = <<91-35=56>>56 baskets remaining.
    Each basket of lemons could produce 14 bottles of lemonade, so they would get 56*14 = <<56*14=784>>784 bottles of lemonade from the remaining baskets.
    ### Answer: 784

Expected answer: 784

Correct? Yes

🔗 Follow-up

Problem: The villagers in Lemonville reconsidered their previous decision and determined that they would only need 23 baskets of lemons, instead of their initial estimation of 35 baskets, to make their village famous lemonade. If each basket of lemons could still produce 14 bottles of lemonade, how many bottles of lemonade would they get from the remaining baskets now?

Gemma 2B:

     Reasoning: The villagers picked 38+24 = <<38+24=62>>62 baskets from the trees near the river and the old well.
    They picked 16+13 = <<16+13=29>>29 baskets from the trees near the school and the mayor's house.
    They picked a total of 62+29 = <<62+29=91>>91 baskets of lemons.
    They decided to get 23 baskets to make lemonade, so they had 91-23 = <<91-23=68>>68 baskets remaining.
    Each basket of lemons could produce 14 bottles of lemonade, so they would get 68*14 = <<68*14=952>>952 bottles of lemonade from the remaining baskets.
    ### Answer: 952

Expected answer: 952

Correct? Yes

🔗 Problem

Problem: Amy found 21 seashells in the sandbox, but gave 15 of them to her sister. The next day, she found another group of seashells that was 13 more than the amount she had remaining from the previous day. She also found an additional 49. Being a generous sister, she gave 23 to her brother and 27 to her cousin. How many seashells does Amy have left now?

Gemma 2B:

     Reasoning: Amy had 21-15 = <<21-15=6>>6 seashells left after giving some to her sister.
    The next day, she found 6+13 = <<6+13=19>>19 seashells.
    She also found an additional 49 seashells, so she had 19+49 = <<19+49=68>>68 seashells in total.
    After giving some to her brother and cousin, she had 68-23-27 = <<68-23-27=18>>18 seashells left.
    ### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Follow-up

Problem: In the initial story, Amy found 21 seashells in the sandbox and gave 15 of them away. She then found another 13 seashells, more than what she had kept for herself from the prior day. Additionally, she found 49 more seashells. However, let's reconsider the story and change the part where Amy gave away 23 seashells to her brother. Instead, imagine that she gave away 32 seashells to her brother. If she still gave 27 seashells to her cousin after this, how many seashells does Amy have left now?

Gemma 2B:

     Reasoning: Amy had 21-15 = <<21-15=6>>6 seashells left after giving some to her sister.
    The next day, she found 6+13 = <<6+13=19>>19 seashells.
    She also found an additional 49 seashells, so she had 19+49 = <<19+49=68>>68 seashells in total.
    After giving some to her brother and cousin, she had 68-32-27 = <<68-32-27=9>>9 seashells left.
    ### Answer: 9

Expected answer: 9

Correct? Yes

🔗 Problem

Problem: Princess Anna was playing a numbers game in the kingdom. In the first round of the game, she thought of two numbers: 7 and 10. She added them together. In the second round, she thought of a number 29. She subtracted the result from the first round and then subtracted 8 more from that result. In the final round, Princess Anna added the results from the first and second round and then multiplied the sum by the result from the second round. What was the final result of the Princess's game?

Gemma 2B:

     Reasoning: In the first round, Princess Anna added 7 and 10 together to get 7+10 = <<7+10=17>>17.

    In the second round, she subtracted the result from the first round from 29 and then subtracted 8 more from that result. So, she did 29-17-8 = <<29-17-8=4>>4.

    In the final round, Princess Anna added the results from the first and second round and then multiplied the sum by the result from the second round. So, she did (17+4)*4 = <<(17+4)*4=84>>84.

    ### Answer: 84

Expected answer: 84

Correct? Yes

🔗 Follow-up

Problem: Following the princess' first game, her little sister, Princess Bella, wanted to join in with her own twist. Bella did as follows: In the first round, Bella copied Anna and added the same two numbers: 7 and 10 together. For the second round, sister Bella thought of the number 33. Just like Anna, She subtracted the result from the first round and then decreased it by 8. In the final round, Princess Bella, like Anna, added the results from the first and second round. Then, she multiplied the sum by the result from her modified second round. What was the final result of Princess Bella's game?

Gemma 2B:

     Reasoning: Bella added 7 and 10 together to get 7+10 = <<7+10=17>>17.

    In the second round, Bella subtracted the result from the first round from 33 and then decreased it by 8. So, she did 33-17-8 = <<33-17-8=8>>8.

    In the final round, Bella added the results from the first and second round and then multiplied the sum by the result from her modified second round. So, she did (17+8)*8 = <<(17+8)*8=192>>192.

    ### Answer: 192

Expected answer: 200

Correct? No

🔗 Problem

Problem: Ellen had 15 dollars. Meanwhile, Sam had 48 dollars but then he gave some money to Ellen. After Sam gave his money to Ellen, he had as much money as Ellen originally had. Then, Sam got 24 dollars from his brother. How much money does Sam have now?

Gemma 2B:

     Reasoning: Sam gave Ellen 48-15 = <<48-15=33>>33 dollars.
    After Sam gave Ellen 33 dollars, he had 15 dollars left.
    After Sam got 24 dollars from his brother, he had 15+24 = <<15+24=39>>39 dollars.
    ### Answer: 39

Expected answer: 57

Correct? No

🔗 Problem

Problem: A group of scientists began studying a river and found that it was 33 kilometers long. To be thorough, they decided to also study a connected tributary, which added 19 kilometers to the total length of waterway they needed to investigate. However, they later realized that a 30-kilometer portion of the river was inaccessible and couldn't be studied. How many kilometers of the river were they able to study?

Gemma 2B:

     Reasoning: The total length of the river and tributary is 33+19 = <<33+19=52>>52 kilometers.
    The scientists were able to study 52-30 = <<52-30=22>>22 kilometers of the river.
    ### Answer: 22

Expected answer: 22

Correct? Yes

🔗 Follow-up

Problem: After finishing the initial survey, the team of scientists received a special permit to investigate an additional stretch of the river 32 kilometers long that was previously off limits. In total, how many kilometers of the river were the scientists able to study?

Gemma 2B:

     Reasoning: The scientists were able to study 22+32 = <<22+32=54>>54 kilometers of the river.
    ### Answer: 54

Expected answer: 54

Correct? Yes

🔗 Follow-up

Problem: Suppose instead that the inaccessible portion of the river that the scientists were unable to study was 26 kilometers, not 30. How many kilometers of the river would they have been able to study under these conditions?

Gemma 2B:

     Reasoning: The total length of the river and tributary is still 52 kilometers.
    The scientists would have been able to study 52-26 = <<52-26=26>>26 kilometers of the river.
    ### Answer: 26

Expected answer: 26

Correct? Yes

🔗 Problem

Problem: A photographer took 34 shots at a wedding but decided to remove 19 of them because they were out of focus. The next day he took an additional 21 shots at a different event. Then, he decided to add to this collection, 23 more shots he took on a third event. Similarly, another photographer took 880 shots at a large event and decided to select every 40th shot for his collection. What is the total number of shots in their collections combined?

Gemma 2B:

     Reasoning: The first photographer took 34 shots and removed 19 of them, so he has 34-19 = <<34-19=15>>15 shots left.
    The next day he took 21 shots and added 23 more shots, so he has 15+21+23 = <<15+21+23=59>>59 shots in total.
    The second photographer took 880 shots and selected every 40th shot, so he has 880/40 = <<880/40=22>>22 shots in his collection.
    The total number of shots in their collections combined is 59+22 = <<59+22=81>>81.
    ### Answer: 81

Expected answer: 81

Correct? Yes

🔗 Follow-up

Problem: Recalling the photographers from the previous problems. Suppose the second photographer decided to select every 28th shot instead of every 40th shot for his collection from the large event where he took 880 shots. Now, what is the total number of shots in their collections combined after this modification?

Gemma 2B:

     Reasoning: The first photographer has 59 shots in his collection, as calculated in the previous problem.
    The second photographer now selects every 28th shot from the 880 shots, so he has 880/28 = <<880/28=31.42857142857143>>31 shots in his collection.
    The total number of shots in their collections combined is 59+31 = <<59+31=90>>90.
    ### Answer: 90

Expected answer: 633/7

Correct? No

🔗 Problem

Problem: A pirate found a treasure chest containing 3 times the amount of his previous loot of 13 gold coins. After spending 22 of these coins for the crew's rum, he discovered another loot of 47 gold coins. How many gold coins does the pirate have now?

Gemma 2B:

     Reasoning: The pirate found a treasure chest containing 3*13 = <<3*13=39>>39 gold coins.
    After spending 22 coins for the crew's rum, he had 39-22 = <<39-22=17>>17 gold coins left.
    After discovering another loot of 47 gold coins, he had 17+47 = <<17+47=64>>64 gold coins.
    ### Answer: 64

Expected answer: 64

Correct? Yes

🔗 Follow-up

Problem: Recall the pirate's adventure. But let's say, originally the treasure chest he found had 42 times the amount of his previous loot of 13 gold coins instead of 3 times. After spending 22 of these coins for the crew's rum, and discovering another loot of 47 gold coins, how many gold coins does the pirate have now?

Gemma 2B:

     Reasoning: The pirate found a treasure chest containing 42*13 = <<42*13=546>>546 gold coins.
    After spending 22 coins for the crew's rum, he had 546-22 = <<546-22=524>>524 gold coins left.
    After discovering another loot of 47 gold coins, he had 524+47 = <<524+47=571>>571 gold coins.
    ### Answer: 571

Expected answer: 571

Correct? Yes

🔗 Problem

Problem: A hiker traveled an average of 900 miles in 36 days. One day, he increases his daily average to 16 miles. This reduces his remaining journey by a certain number of days. After that, he finds a shortcut which saves him an additional 4 days, and a friendly traveller advised him of another path that will save him 40 days. If he also saves 21 days due to good weather, how many days in total did he save on his journey?

Gemma 2B:

     Reasoning: The hiker's original daily average was 900/36 = <<900/36=25>>25 miles.
    Increasing his daily average to 16 miles reduces his remaining journey by (25-16) * 36 = <<(25-16)*36=324>>324 miles.
    This reduces his remaining journey by 324/16 = <<324/16=20.25>>20.25 days.
    Adding the 4 days saved by the shortcut and the 40 days saved by the other path, the hiker saved a total of 20.25 + 4 + 40 = <<20.25+4+40=64.25>>64.25 days.
    Adding the 21 days saved due to good weather, the hiker saved a total of 64.25 + 21 = <<64.25+21=85.25>>85.25 days.
    ### Answer: 85.25

Expected answer: 74

Correct? No

🔗 Problem

Problem: A pillow manufacturing company produces 33 pillows every hour in round the clock operations. In a day, they realized they had incurred a loss of 43 pillows due to machine errors. What is the total number of pillows the company manufactured in a day after accounting for the losses?

Gemma 2B:

     Reasoning: The company produces 33 pillows every hour.
    In a day, they produce 33*24 = <<33*24=792>>792 pillows.
    After accounting for the loss of 43 pillows, the total number of pillows manufactured in a day is 792-43 = <<792-43=749>>749 pillows.
    ### Answer: 749

Expected answer: 749

Correct? Yes

🔗 Follow-up

Problem: The pillow manufacturing company decides to adjust their production rate to be consistent with worker shifts, producing 24 pillows every hour instead. However, they still incur a loss of 43 pillows due to machine errors. What is the total number of pillows the company manufactured in a day after accounting for the losses?

Gemma 2B:

     Reasoning: The company now produces 24 pillows every hour.
    In a day, they produce 24*24 = <<24*24=576>>576 pillows.
    After accounting for the loss of 43 pillows, the total number of pillows manufactured in a day is 576-43 = <<576-43=533>>533 pillows.
    ### Answer: 533

Expected answer: 533

Correct? Yes

🔗 Problem

Problem: In a Castle, there are 5 rooms in one wing. The other wing has 216 bricks. Nowadays, there's a strange rule: one room is equivalent to 36 bricks. Following this, if we have to calculate the sum of total rooms from both wings by converting the number of bricks to the number of rooms. How many rooms would be considered in total according to this rule?

Gemma 2B:

     Reasoning: The other wing has 216/36 = <<216/36=6>>6 rooms.
    The total number of rooms is 5+6 = <<5+6=11>>11 rooms.
    ### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: In the same castle, there is a hidden underground passage which has 9 rooms. After discovering these, if you count all the rooms: the original five, the ones found in the second wing when converting the number of bricks to rooms, and these new rooms from the underground passage together. How many rooms are there in the castle in total?

Gemma 2B:

     Reasoning: The total number of rooms is 5+6+9 = <<5+6+9=20>>20 rooms.
    ### Answer: 20

Expected answer: 20

Correct? Yes

🔗 Follow-up

Problem: Suppose when we originally counted, we made a mistake and there were actually 35 rooms in the first wing of the castle, not 5. If we still convert the bricks in the second wing into the equivalent number of rooms and add them to this new total, how many rooms are now in the castle excluding the underground passage rooms?

Gemma 2B:

     Reasoning: The other wing has 216/36 = <<216/36=6>>6 rooms.
    The total number of rooms is 35+6 = <<35+6=41>>41 rooms.
    ### Answer: 41

Expected answer: 41

Correct? Yes

🔗 Problem

Problem: A player scored 15 goals each over 31 matches. However, due to an error, 43 of the goals were discounted. Later, the error was rectified and 40 goals were awarded back to the player. Unfortunately, after a reevaluation of the matches, 26 of those goals were deducted from the player again. How many goals does the player end up with?

Gemma 2B:

     Reasoning: The player initially scored 15 goals each over 31 matches, which is 15*31 = <<15*31=465>>465 goals.
    After the error, 43 goals were discounted, leaving the player with 465-43 = <<465-43=422>>422 goals.
    After the error was rectified, 40 goals were awarded back, making the total 422+40 = <<422+40=462>>462 goals.
    Unfortunately, after a reevaluation, 26 goals were deducted, leaving the player with 462-26 = <<462-26=436>>436 goals.
    ### Answer: 436

Expected answer: 436

Correct? Yes

🔗 Follow-up

Problem: The player from the previous question, with his total number of goals determined, got involved in a contest where the goal tally he had counted as points with a multiplier attached. If that multiplier was 1, how many points did he get in the contest?

Gemma 2B:

     Reasoning: The player had 436 goals, and since the multiplier is 1, the number of points he got in the contest is 436*1 = <<436*1=436>>436 points.
    ### Answer: 436

Expected answer: 436

Correct? Yes

🔗 Problem

Problem: An aquarium has 9 tanks, each with 49 fish. However, 5 of the fish in one tank are relocated. What is the new total number of fish in the aquarium?

Gemma 2B:

     Reasoning: The aquarium has 9*49 = <<9*49=441>>441 fish in total.
    After relocating 5 fish, the aquarium has 441-5 = <<441-5=436>>436 fish in total.
    ### Answer: 436

Expected answer: 436

Correct? Yes

🔗 Follow-up

Problem: Let's consider another situation. Suppose each of the 9 tanks in the aquarium originally contained 47 fish, instead of 49, and the same number of fish (5) were relocated from one tank as in the previous situation. Now, what would be the total number of fish in the aquarium?

Gemma 2B:

     Reasoning: The aquarium has 9*47 = <<9*47=423>>423 fish in total.
    After relocating 5 fish, the aquarium has 423-5 = <<423-5=418>>418 fish in total.
    ### Answer: 418

Expected answer: 418

Correct? Yes

🔗 Problem

Problem: In a card game, Jeremy has 14 cards. He then discards 19 of his cards, and then gains 32 more cards from the deck. How many cards does Jeremy have now?

Gemma 2B:

     Reasoning: Jeremy has 14-19 = <<14-19=-5>>-5 cards after discarding 19 of his cards.
    Jeremy has -5+32 = <<-5+32=27>>27 cards now.
    ### Answer: 27

Expected answer: 27

Correct? Yes

🔗 Follow-up

Problem: In a card game, Jeremy has 14 cards. He then discards 19 of his cards, and then gains 32 more cards from the deck. In the next moved, Jeremy was fortunate enough to be given 7 more cards and found 12 more discarded cards on the table, which he added to his deck. How many cards does Jeremy have now?

Gemma 2B:

     Reasoning: Jeremy has 14-19 = <<14-19=-5>>-5 cards after discarding 19 of his cards.
    Jeremy has -5+32 = <<-5+32=27>>27 cards after gaining 32 more cards from the deck.
    Jeremy has 27+7 = <<27+7=34>>34 cards after being given 7 more cards.
    Jeremy has 34+12 = <<34+12=46>>46 cards after finding 12 more discarded cards on the table.
    ### Answer: 46

Expected answer: 46

Correct? Yes

🔗 Follow-up

Problem: In the card game, let's imagine that Jeremy initially had 14 cards, but this time he only discards 19 cards before gaining 13 more cards from the deck. How many cards does Jeremy have now?

Gemma 2B:

     Reasoning: Jeremy has 14-19 = <<-5>>-5 cards after discarding 19 of his cards.
    Jeremy has -5+13 = <<8>>8 cards now.
    ### Answer: 8

Expected answer: 8

Correct? Yes

🔗 Problem

Problem: A clock ticks 504 times in 42 minutes. Similarly, another clock ticks 279 times in 31 minutes. Add 34 to the rate of the second clock's ticks per minute. Multiply the first clock's ticks per minute by 35 and then subtract 41 from it. Finally, subtract the rate of the second clock (after adding 34) from the manipulated rate of the first clock. What is the final value?

Gemma 2B:

     Reasoning: The first clock ticks 504/42 = <<504/42=12>>12 times per minute.
    The second clock ticks 279/31 = <<279/31=9>>9 times per minute.
    Adding 34 to the second clock's ticks per minute: 9+34 = <<9+34=43>>43.
    Multiplying the first clock's ticks per minute by 35: 12*35 = <<12*35=420>>420.
    Subtracting 41 from the result: 420-41 = <<420-41=379>>379.
    Finally, subtracting the rate of the second clock (after adding 34) from the manipulated rate of the first clock: 379-43 = <<379-43=336>>336.
    ### Answer: 336

Expected answer: 336

Correct? Yes

🔗 Follow-up

Problem: In the previous question about clocks, the second clock actually ticks 279 times in just 2 minutes, not 31 minutes. Re-calculate the rate of ticks per minute for this clock and add 34 to it. As before, calculate the tick rate for the first clock, then multiply it by 35 and subtract 41. Finally, subtract this modified rate of the second clock from the manipulated rate of the first clock. What is the new result?

Gemma 2B:

     Reasoning: The first clock ticks 504/42 = <<504/42=12>>12 times per minute.
    The second clock ticks 279/2 = <<279/2=139.5>>139.5 times per minute.
    Adding 34 to the second clock's ticks per minute: 139.5+34 = <<139.5+34=173.5>>173.5.
    Multiplying the first clock's ticks per minute by 35: 12*35 = <<12*35=420>>420.
    Subtracting 41 from the result: 420-41 = <<420-41=379>>379.
    Finally, subtracting the rate of the second clock (after adding 34) from the manipulated rate of the first clock: 379-173.5 = <<379-173.5=205.5>>205.5.
    ### Answer: 205.5

Expected answer: 411/2

Correct? Yes

🔗 Problem

Problem: Nina has noted down the rainfall of her town in centimeters over the last few days. On Tuesday, there was a rainfall of 39 cm. The rainfall decreased by 6 cm on Wednesday and further decreased by 31 cm on Thursday. How much rainfall did Nina note on Thursday?

Gemma 2B:

     Reasoning: The rainfall on Wednesday was 39-6 = <<39-6=33>>33 cm.
    The rainfall on Thursday was 33-31 = <<33-31=2>>2 cm.
    ### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: A UFO-watching enthusiast reported seeing 50 UFOs in a month. However, a later investigation revealed that 36 of these were actually meteors. In the next month, the enthusiast reported seeing 41 UFOs, plus an amount equal to the revised (i.e., actual) number of UFO sightings from the previous month, with an additional 5. How many UFO sightings were reported by the enthusiast in the second month?

Gemma 2B:

     Reasoning: The actual number of UFOs seen in the first month is 50-36 = <<50-36=14>>14.
    The number of UFOs seen in the second month is 41+14+5 = <<41+14+5=60>>60.
    ### Answer: 60

Expected answer: 60

Correct? Yes

🔗 Problem

Problem: A cat started playing with yarn balls. In her first game, she managed to accumulate 5 yarn balls. In her second game, she got as many balls as the square of what she obtained in the first game plus 8 more. Finally, she lost some of her balls in her third game due to a playful dog. She ended the game with a number of balls which is 25 times the difference between 45 and what she accumulated from the second game. How many yarn balls does the cat have now?

Gemma 2B:

     Reasoning: In the second game, the cat got 5^2+8 = <<5^2+8=33>>33 balls.
    In the third game, the cat ended with 25*(45-33) = <<25*(45-33)=300>>300 balls.
    ### Answer: 300

Expected answer: 300

Correct? Yes

🔗 Follow-up

Problem: Let's rethink the second game the cat played. Suppose that instead of intensifying her third game by multiplying the difference of the balls by 25, the cat only multiplied by 6. After playing her second game, where she got as many balls as the square of what she obtained in the first game (5 yarn balls) plus 8 more, she played her third game. This time around, she ended the game with a number of balls which is 6 times the difference between 45 and what she accumulated from the second game. How many yarn balls does the cat have now?

Gemma 2B:

     Reasoning: In the second game, the cat got 5^2+8 = <<5^2+8=33>>33 balls.
    In the third game, the cat ended with 6*(45-33) = <<6*(45-33)=72>>72 balls.
    ### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Problem

Problem: A basket contains 41 balls. The balls are split into two types - tennis balls and cricket balls. If we remove 16 balls from the basket, we get cricket balls. When 9 ping pong balls and 21 basketballs are added to the basket, what is the total number of balls in the basket?

Gemma 2B:

     Reasoning: The number of cricket balls in the basket is 16.
    The number of tennis balls in the basket is 41-16 = <<41-16=25>>25.
    The total number of balls in the basket after adding ping pong balls and basketballs is 41+9+21 = <<41+9+21=71>>71.
    ### Answer: 71

Expected answer: 55

Correct? No

🔗 Problem

Problem: The design of a classic wall clock dictates that there should be 1 number represented for every 12 around the clock face. However, your quirky modernist clockmaker friend wants to do things differently. They want to represent 37 hours on the clock's face, each hour has an equivalent of 1 square. Your friend has already completed 32 squares. They left their project for a while, and when they came back, they forgot how many squares they needed to fulfill their quirk. So they did some math to figure it out: they subtracted 32 from 37, added 42 to the result, and then subtracted 37 from that total. Suddenly, an idea occurred to them. What if they add 25 more squares for representing minutes on their quirky clock? Plus, they also wanted to add another 28 squares for seconds. Since your friend is a bit forgetful, they forgot how many squares they need again to finish their project. So, they did a little more math - added 41 to 25, followed by another 28, and then added 17 to the result. Because your friend didn't have enough material, they decided that they could reduce the total number of squares by 23. Finally, they added the number they figured out at the beginning (for hours) to this reduced number. Can you help your friend figure out how many squares they would need in total to complete their quirky clock?

Gemma 2B:

     Reasoning: First, your friend subtracted 32 from 37, which is 37-32 = <<37-32=5>>5.
    Then, they added 42 to the result, which is 5+42 = <<5+42=47>>47.
    Next, they subtracted 37 from that total, which is 47-37 = <<47-37=10>>10.
    Then, they added 25 to 10, which is 10+25 = <<10+25=35>>35.
    Next, they added 28 to 35, which is 35+28 = <<35+28=63>>63.
    Then, they added 17 to 63, which is 63+17 = <<63+17=80>>80.
    Next, they subtracted 23 from 80, which is 80-23 = <<80-23=57>>57.
    Finally, they added the number they figured out at the beginning (for hours) to this reduced number, which is 57+10 = <<57+10=67>>67.
    ### Answer: 67

Expected answer: 98

Correct? No

🔗 Problem

Problem: An orange farm produced 2 times the 28 pounds of oranges they typically produce in a single day due to a new method. This production also multiplied by the 15 days of the harvest period. If the farm then added 16 pounds of a rare orange variant to this harvest, how much did the farm produce in total?

Gemma 2B:

     Reasoning: The farm produced 28*2 = <<28*2=56>>56 pounds of oranges in a single day.
    The farm produced 56*15 = <<56*15=840>>840 pounds of oranges in the harvest period.
    The farm produced 840+16 = <<840+16=856>>856 pounds of oranges in total.
    ### Answer: 856

Expected answer: 856

Correct? Yes

🔗 Follow-up

Problem: Previously, the orange farm had been able to double its typical daily output of 28 pounds to increase its harvest yield. However, imagine what would have happened had the farm originally been producing a lesser daily output, such as 7 pounds. If they were still able to double this amount each day of the 15-day harvest period and added the same 16 pounds of the rare orange variant to their yield, how much would the farm have produced in that case?

Gemma 2B:

     Reasoning: The farm would have produced 7*2 = <<7*2=14>>14 pounds of oranges in a single day.
    The farm would have produced 14*15 = <<14*15=210>>210 pounds of oranges in the harvest period.
    The farm would have produced 210+16 = <<210+16=226>>226 pounds of oranges in total.
    ### Answer: 226

Expected answer: 226

Correct? Yes

🔗 Problem

Problem: A bus has 37 passengers. At the next stop, 20 more passengers get on. Before the bus reaches to the next stop, 44 passengers get off. Now, suppose this remaining number of passengers each pays an $11 fare, but the bus company also deducts a $14 service fee from the total fare. How much revenue does the bus company get?

Gemma 2B:

     Reasoning: The bus has 37+20 = <<37+20=57>>57 passengers after the first stop.
    The bus has 57-44 = <<57-44=13>>13 passengers after the second stop.
    The bus company gets 13*11 = <<13*11=143>>143 dollars from the passengers.
    The bus company gets 143-14 = <<143-14=129>>129 dollars after deducting the service fee.
    ### Answer: 129

Expected answer: 129

Correct? Yes

🔗 Follow-up

Problem: Following the previously described bus ride, where, after passengers got on and off, the company collected fare from each remaining passenger and deducted a $14 service fee, the company then had to pay a $23 parking fee for the bus at the end of the day. After all these expenses, how much revenue does the bus company have now?

Gemma 2B:

     Reasoning: The bus company had 129 dollars after the fare and service fee.
    The bus company has 129-23 = <<129-23=106>>106 dollars after paying the parking fee.
    ### Answer: 106

Expected answer: 106

Correct? Yes

🔗 Follow-up

Problem: Suppose we revisit the scenario of the bus ride. This time, imagine that instead of 37 passengers initially on the bus, there were only 28 passengers. Then, the bus picked up 20 more passengers at the next stop, but 44 passengers get off before the next stop. The remaining passengers each pay a bus fare of $11, but the company also deducts a $14 service fee from the total fares. How much revenue does the bus company get in this situation?

Gemma 2B:

     Reasoning: The bus has 28+20 = <<28+20=48>>48 passengers after the first stop.
    The bus has 48-44 = <<48-44=4>>4 passengers after the second stop.
    The bus company gets 4*11 = <<4*11=44>>44 dollars from the passengers.
    The bus company gets 44-14 = <<44-14=30>>30 dollars after deducting the service fee.
    ### Answer: 30

Expected answer: 30

Correct? Yes

🔗 Problem

Problem: A pirate found a treasure chest with 13 emeralds, 42 rubies, and 19 sapphires. He gave away 43 of these precious gems to his crewmates. How many gems did the pirate have left?

Gemma 2B:

     Reasoning: The pirate found 13+42+19 = <<13+42+19=74>>74 gems in total.
    The pirate gave away 43 gems to his crewmates.
    The pirate had 74-43 = <<74-43=31>>31 gems left.
    ### Answer: 31

Expected answer: 31

Correct? Yes

🔗 Problem

Problem: A certain reserve has 16 ginger giraffes. They then bring in the same number of golden giraffes as they had of the ginger ones. Later, they decide to add another group of 46 greyish giraffes. What is the total number of giraffes in the reserve now?

Gemma 2B:

     Reasoning: The reserve brings in 16 golden giraffes.
    The reserve now has 16+16 = <<16+16=32>>32 giraffes.
    The reserve now has 32+46 = <<32+46=78>>78 giraffes.
    ### Answer: 78

Expected answer: 78

Correct? Yes

🔗 Follow-up

Problem: After successfully populating the reserve with various giraffes, unfortunately, 2 of the greyish giraffes suddenly moved out of the reserve. How many giraffes are there now in the reserve after the 2 greyish giraffes left?

Gemma 2B:

     Reasoning: The reserve now has 78-2 = <<78-2=76>>76 giraffes.
    ### Answer: 76

Expected answer: 76

Correct? Yes

🔗 Follow-up

Problem: Let's reconsider the original scenario where the reserve started with ginger giraffes. But this time assume that the reserve initially had 42 ginger giraffes instead of 16. They again brought in the same number of golden giraffes as the ginger ones. Later, they decided to add another group of 46 greyish giraffes. What would be the total number of giraffes in the reserve now under this new scenario?

Gemma 2B:

     Reasoning: The reserve brings in 42 golden giraffes.
    The reserve now has 42+42 = <<42+42=84>>84 giraffes.
    The reserve now has 84+46 = <<84+46=130>>130 giraffes.
    ### Answer: 130

Expected answer: 130

Correct? Yes

🔗 Problem

Problem: A turtle decides to swim. One day, it travels as many leagues as 11 plus 10, then multiplies that by 16 to get the total distance it swam that week. Later, it realized it had over calculated the distance by 41 leagues. What is the real distance it swam that week?

Gemma 2B:

     Reasoning: The turtle traveled 11+10 = <<11+10=21>>21 leagues on the first day.
    The turtle traveled 21*16 = <<21*16=336>>336 leagues that week.
    The turtle over calculated the distance by 41 leagues, so the real distance it swam that week is 336-41 = <<336-41=295>>295 leagues.
    ### Answer: 295

Expected answer: 295

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous scenario, consider that the turtle realizes that it originally miscalculated the daily travel distance. Instead of swimming 11 leagues plus 10 a day, it actually swam 11 leagues plus 17 leagues a day. After multiplying that daily total by 16 for the week, and subtracting the over-calculated 41 leagues, how much did the turtle actually swim in the originally estimated week?

Gemma 2B:

     Reasoning: The turtle actually swam 11+17 = <<11+17=28>>28 leagues a day.
    The turtle actually swam 28*16 = <<28*16=448>>448 leagues that week.
    After subtracting the over-calculated 41 leagues, the turtle actually swam 448-41 = <<448-41=407>>407 leagues in the originally estimated week.
    ### Answer: 407

Expected answer: 407

Correct? Yes