🔗 Problem

Problem: There are 535 fish in a large tank and a shark eats 461 of them in one sitting. If the shark continues this pattern and only eats when there are 461 or more fish to consume, how many fish will be leftover after its dinner?

Gemma 2B:

     Reasoning: The shark eats 461 fish, leaving 535-461 = <<535-461=74>>74 fish in the tank.
    ### Answer: 74

Expected answer: 74

Correct? Yes

🔗 Problem

Problem: A baker baked a total of 928 cookies. He decided to distribute equal amounts of cookies to 186 orphanages. After giving out as many entire sets of cookies as possible to each orphanage, how many cookies does the baker have left?

Gemma 2B:

     Reasoning: The baker distributed 928/186 = <<928/186=4.989247311827957>>4.989247311827957 cookies to each orphanage.
    Since the baker can only distribute whole cookies, he distributed 4 cookies to each orphanage.
    The baker distributed a total of 4*186 = <<4*186=744>>744 cookies.
    The baker has 928-744 = <<928-744=184>>184 cookies left.
    ### Answer: 184

Expected answer: 184

Correct? Yes

🔗 Follow-up

Problem: In the previously mentioned scenario, consider that the baker only baked 173 cookies instead of 928. He still plans on distributing equal amounts of cookies to the 186 orphanages. After giving out as many full sets as possible to each orphanage, how many cookies will the baker have left over this time?

Gemma 2B:

     Reasoning: The baker distributed 173/186 = <<173/186=0.9295698924731183>>0.9295698924731183 cookies to each orphanage.
    Since the baker can only distribute whole cookies, he distributed 0 cookies to each orphanage.
    The baker distributed a total of 0*186 = <<0*186=0>>0 cookies.
    The baker has 173-0 = <<173-0=173>>173 cookies left.
    ### Answer: 173

Expected answer: 173

Correct? Yes

🔗 Problem

Problem: A pizza store has 975 slices of pizza ready to serve. If each pizza box can contain 196 slices, how many left over slices will there be after all the pizza boxes are full?

Gemma 2B:

     Reasoning: The number of full boxes is 975/196 = <<975/196=4.974489795918367>>4.974489795918367, which rounds down to 4 full boxes.
    The number of slices in the full boxes is 4*196 = <<4*196=784>>784 slices.
    The number of leftover slices is 975-784 = <<975-784=191>>191 slices.
    ### Answer: 191

Expected answer: 191

Correct? Yes

🔗 Problem

Problem: A wizard casts a spell to summon 932 magical stones. Each powerful creature he summons requires 193 stones. After summoning several creatures, how many stones will the wizard have left?

Gemma 2B:

     Reasoning: The wizard will have 932-193 = <<932-193=739>>739 stones left.
    ### Answer: 739

Expected answer: 160

Correct? No

🔗 Problem

Problem: A builder has a job to install 660 square foot tiles in a house. Each tile can cover 335 square feet. After installing tiles evenly across the available space, how many square feet will the last tile need to cover?

Gemma 2B:

     Reasoning: The total area that can be covered by the tiles is 660 * 335 = <<660*335=221100>>221,100 square feet.
    The last tile will need to cover 221,100 - (659 * 335) = <<221100-(659*335)=165>>165 square feet.
    ### Answer: 165

Expected answer: 325

Correct? No

🔗 Problem

Problem: A juice company produced 473 gallons of juice. If the company bottles the juice in 22-gallon containers, how many gallons of juice will be left after filling up all the containers?

Gemma 2B:

     Reasoning: The company can fill 473/22 = <<473/22=21.5>>21 containers with juice.
    The company will have 473-21*22 = <<473-21*22=11>>11 gallons of juice left.
    ### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: A juice company initially thought they produced 473 gallons of juice, but they realized they actually produced 599 gallons. They used the same 22-gallon containers as before. After filling up all the containers, how many gallons of juice do they now have left over?

Gemma 2B:

     Reasoning: The company can fill 599/22 = <<599/22=27.227272727272727>>27 containers with juice.
    The company will have 599-27*22 = <<599-27*22=11>>11 gallons of juice left.
    ### Answer: 11

Expected answer: 5

Correct? No

🔗 Problem

Problem: A toy factory produced 979 toy cars in a day. If they packed these cars into boxes, each containing 108 cars, how many toy cars will be left unpacked at the end of the day?

Gemma 2B:

     Reasoning: The factory can pack 979/108 = <<979/108=9.064814814814815>>9 full boxes of toy cars.
    The factory will have 979 - (9*108) = <<979-(9*108)=79>>79 toy cars left unpacked at the end of the day.
    ### Answer: 79

Expected answer: 7

Correct? No

🔗 Problem

Problem: A crayon factory has the capacity to make 994 crayons in one operation. However, each box only holds 425 crayons. If they operate at full capacity, how many crayons will be left out of the boxes after the operation?

Gemma 2B:

     Reasoning: The crayon factory makes 994 crayons in one operation.
    Each box holds 425 crayons.
    To find out how many crayons will be left out of the boxes, we need to subtract the number of crayons that can fit in the boxes from the total number of crayons made.
    994 - 425 = <<994-425=569>>569 crayons will be left out of the boxes after the operation.
    ### Answer: 569

Expected answer: 144

Correct? No

🔗 Problem

Problem: A wildlife reserve has 740 tigers. The reserve is divided into different zones, and each zone can only hold up to 696 tigers. If tigers are distributed evenly among the zones, how many tigers will be left in the last zone?

Gemma 2B:

     Reasoning: To find out how many tigers will be left in the last zone, we need to divide the total number of tigers by the maximum number of tigers each zone can hold and then find the remainder.
    740 ÷ 696 = 1 remainder 44
    So, 44 tigers will be left in the last zone.
    ### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Follow-up

Problem: Consider the wildlife reserve again. This time, however, the zones have been expanded and each can now accommodate up to 908 tigers. If the 740 tigers are distributed evenly among the expanded zones, how many tigers will be left in the last zone?

Gemma 2B:

     Reasoning: To find out how many tigers will be left in the last zone, we need to divide the total number of tigers by the maximum number of tigers each zone can hold and then find the remainder.
    740 ÷ 908 = 0 remainder 740
    So, 740 tigers will be left in the last zone.
    ### Answer: 740

Expected answer: 740

Correct? Yes

🔗 Problem

Problem: A hat shop makes 830 hats every week. In order to make special edition boxes, the shop plans to put 421 hats in each box. If all the hats are evenly distributed among the boxes, how many hats will be left over?

Gemma 2B:

     Reasoning: To find the number of hats left over, we need to find the remainder when 830 is divided by 421.
    830 ÷ 421 = 1 remainder 409
    Therefore, there will be 409 hats left over.
    ### Answer: 409

Expected answer: 409

Correct? Yes

🔗 Problem

Problem: There are 871 fish in a lake. A fisherman catches 575 fish every month. If the fish repopulate at the same rate that the fisherman is depleting them, how many fish will be left after a month?

Gemma 2B:

     Reasoning: The fisherman catches 575 fish every month, and the fish repopulate at the same rate. Therefore, the number of fish left after a month will be 871-575 = <<871-575=296>>296.
    ### Answer: 296

Expected answer: 296

Correct? Yes

🔗 Problem

Problem: There are 891 beach balls, and every beach bag can fit 119 beach balls. If all the beach balls are evenly placed into the bags, how many beach balls will not fit and left over?

Gemma 2B:

     Reasoning: 891/119 = <<891/119=7.487394957983193>>7.487394957983193
    7*119 = <<7*119=833>>833
    891-833 = <<891-833=58>>58
    ### Answer: 58

Expected answer: 58

Correct? Yes

🔗 Follow-up

Problem: If instead there were 901 beach balls and every beach bag can fit 119 beach balls. After evenly placing the balls into bags, how many beach balls would be left over now?

Gemma 2B:

     Reasoning: 901/119 = <<901/119=7.571428571428571>>7.571428571428571
    7*119 = <<7*119=833>>833
    901-833 = <<901-833=68>>68
    ### Answer: 68

Expected answer: 68

Correct? Yes

🔗 Problem

Problem: There are 544 stars in a particular constellation. These stars are grouped into smaller clusters of 446 stars each. If these clusters are evenly split, how many stars will remain ungrouped?

Gemma 2B:

     Reasoning: To find the number of stars that will remain ungrouped, we need to divide the total number of stars by the number of stars in each cluster and find the remainder.
    544 ÷ 446 = 1 remainder 98
    Therefore, 98 stars will remain ungrouped.
    ### Answer: 98

Expected answer: 98

Correct? Yes

🔗 Follow-up

Problem: Considering the previous scenario with the constellation, suppose there were only 278 stars in the constellation instead of 544, and they were still to be grouped into smaller clusters of 446 stars each. If the clusters are evenly distributed, how many stars will now remain ungrouped?

Gemma 2B:

     Reasoning: To find the number of stars that will remain ungrouped, we need to divide the total number of stars by the number of stars in each cluster and find the remainder.
    278 ÷ 446 = 0 remainder 278
    Therefore, 278 stars will remain ungrouped.
    ### Answer: 278

Expected answer: 278

Correct? Yes

🔗 Problem

Problem: A manufacturer produces 805 socks in one shift. They are packaged into sets of 132 each. After the packaging, how many socks will remain unpackaged?

Gemma 2B:

     Reasoning: The manufacturer packages 132 socks per set, so they can package 805/132 = <<805/132=6.098484848484849>>6 sets of socks.
    Since they can only package whole sets, they will have 805 - (132 * 6) = <<805-(132*6)=13>>13 socks remaining unpackaged.
    ### Answer: 13

Expected answer: 13

Correct? Yes

🔗 Follow-up

Problem: If instead of producing 805 socks, the manufacturer produced 634 socks in one shift, how many socks would remain unpackaged after being bundled into sets of 132 each?

Gemma 2B:

     Reasoning: The manufacturer packages 132 socks per set, so they can package 634/132 = <<634/132=4.803030303030303>>4 sets of socks.
    Since they can only package whole sets, they will have 634 - (132 * 4) = <<634-(132*4)=106>>106 socks remaining unpackaged.
    ### Answer: 106

Expected answer: 106

Correct? Yes

🔗 Problem

Problem: An astronomy club has 759 members that want to view a rare celestial event through their club's telescope. However, the telescope can only handle 228 people viewing the event each night. If they distribute the viewing evenings evenly amongst all members, how many people will view the event on the final night?

Gemma 2B:

     Reasoning: The astronomy club has 759/228 = <<759/228=3.3289473684210525>>3.3289473684210525 viewing evenings.
    Since they can't have a fraction of a viewing evening, they will have 4 viewing evenings.
    On the final night, there will be 759 - (228*3) = <<759-(228*3)=75>>75 people viewing the event.
    ### Answer: 75

Expected answer: 75

Correct? Yes

🔗 Follow-up

Problem: A similar astronomy club from a neighboring town also wants to take part in viewing this rare celestial event. They have 593 members interested in participating. If they follow the same pattern of distributing the viewing nights evenly amongst all members, with only 228 people viewing the event each night, how many people from this club will view the event on the final night?

Gemma 2B:

     Reasoning: The astronomy club from the neighboring town has 593/228 = <<593/228=2.5964912280701754>>2.5964912280701754 viewing evenings.
    Since they can't have a fraction of a viewing evening, they will have 3 viewing evenings.
    On the final night, there will be 593 - (228*2) = <<593-(228*2)=137>>137 people viewing the event.
    ### Answer: 137

Expected answer: 137

Correct? Yes

🔗 Problem

Problem: A postman has to deliver 891 letters. Each mailbox can only hold 616 letters. If he puts equal numbers of letters in each mailbox, how many letters will remain in the last mailbox?

Gemma 2B:

     Reasoning: The postman can deliver 891/616 = <<891/616=1.447>>1.447 letters per mailbox.
    Since each mailbox can only hold 616 letters, the postman can deliver 616 letters to each mailbox.
    The postman can deliver 1 mailbox full of letters, which is 616 letters.
    The postman will have 891-616 = <<891-616=275>>275 letters remaining.
    ### Answer: 275

Expected answer: 275

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, assuming the postman had to originally deliver 524 letters instead of 891, and each mailbox can still only accommodate 616 letters. How many letters will remain in the last mailbox now?

Gemma 2B:

     Reasoning: The postman can deliver 524/616 = <<524/616=0.850>>0.850 letters per mailbox.
    Since each mailbox can only hold 616 letters, the postman can deliver 616 letters to each mailbox.
    The postman can deliver 0 mailbox full of letters, which is 0 letters.
    The postman will have 524-0 = <<524-0=524>>524 letters remaining.
    ### Answer: 524

Expected answer: 524

Correct? Yes

🔗 Problem

Problem: A total of 941 flies are jumping around the pond. Every time a frog jumps, it eats exactly 258 flies. After a series of jumps where each jump the frog eats the same number of flies, how many flies are left?

Gemma 2B:

     Reasoning: The number of flies eaten by the frog is a multiple of 258. The closest multiple of 258 to 941 is 774 (258*3). Therefore, the frog ate 774 flies and there are 941-774 = <<941-774=167>>167 flies left.
    ### Answer: 167

Expected answer: 167

Correct? Yes

🔗 Follow-up

Problem: Previously, a frog ate flies from a total of 941 flies with 258 flies eaten in each jump. Now, consider that instead of 941 flies there initially were 146 flies hopping around the pond. Given that the frog still eats 258 flies in each jump, how many flies would be left after a series of jumps?

Gemma 2B:

     Reasoning: Since the frog eats 258 flies in each jump, and there are only 146 flies, the frog will eat all the flies in one jump. Therefore, there will be 146-258 = <<146-258=-112>>-112 flies left. However, since the number of flies cannot be negative, the answer is 0.
    ### Answer: 0

Expected answer: 146

Correct? No

🔗 Problem

Problem: A large park has a capacity of 991 spaces for cars to park. If all the spaces are evenly distributed between 66 rows, how many spare spaces will be there in the last row after max spaces are filled?

Gemma 2B:

     Reasoning: The number of spaces in each row is 991/66 = <<991/66=15>>15.
    The number of spaces filled in the last row is 991 - (15 * 65) = <<991-(15*65)=16>>16.
    The number of spare spaces in the last row is 16 - 15 = <<16-15=1>>1.
    ### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: In the same large park, suppose they restructure the parking with larger spaces to accommodate bigger vehicles. Now, the adjusted parking lot configurations can hold 471 cars in each row. After filling up the rows, how many spare spaces would be there in the last row now?

Gemma 2B:

     Reasoning: The number of rows filled is 991/471 = <<991/471=2>>2.
    The number of spaces filled in the last row is 991 - (471 * 2) = <<991-(471*2)=50>>50.
    The number of spare spaces in the last row is 50 - 471 = <<50-471=-421>>-421.
    ### Answer: -421

Expected answer: 49

Correct? No

🔗 Problem

Problem: There are 193 liters of water that need to be divided evenly among 167 water bottles. If each bottle holds the same amount of water, how many liters overflows and can't be distributed to the bottles?

Gemma 2B:

     Reasoning: Each bottle holds 193/167 = <<193/167=1.155688622754491>>1.155688622754491 liters of water.
    The total amount of water that can be distributed to the bottles is 167 * 1.155688622754491 = <<167*1.155688622754491=193.00000000000003>>193.00000000000003 liters.
    The amount of water that overflows is 193 - 193.00000000000003 = <<193-193.00000000000003=-3.552713678800501e-15>>-3.552713678800501e-15 liters.
    ### Answer: -3.552713678800501e-15

Expected answer: 26

Correct? No

🔗 Problem

Problem: A dragon lays 996 jewel eggs in rows. Each row can hold 319 eggs. If the dragon distributes the eggs evenly among the rows, how many eggs would be left over to be put in the last row?

Gemma 2B:

     Reasoning: To find the number of eggs left over, we need to divide the total number of eggs by the number of eggs that can fit in each row and find the remainder.
    996 ÷ 319 = 3 with a remainder of 39.
    Therefore, there would be 39 eggs left over to be put in the last row.
    ### Answer: 39

Expected answer: 39

Correct? Yes

🔗 Follow-up

Problem: Now, consider if the dragon had only laid 8 jewel eggs and continued to distribute them among rows that could hold 319 eggs. How many eggs would be left over to be put in the last row?

Gemma 2B:

     Reasoning: To find the number of eggs left over, we need to divide the total number of eggs by the number of eggs that can fit in each row and find the remainder.
    8 ÷ 319 = 0 with a remainder of 8.
    Therefore, there would be 8 eggs left over to be put in the last row.
    ### Answer: 8

Expected answer: 8

Correct? Yes

🔗 Problem

Problem: A lamp manufacturer produces 691 bulb units. If a pack includes 205 bulbs, how many bulbs would be left unpacked after filling as many packs as possible?

Gemma 2B:

     Reasoning: The number of packs that can be filled is 691/205 = <<691/205=3.370731707317073>>3.370731707317073.
    Since we can't have a fraction of a pack, we can only fill 3 packs.
    The number of bulbs left unpacked is 691 - 3*205 = <<691-3*205=76>>76 bulbs.
    ### Answer: 76

Expected answer: 76

Correct? Yes

🔗 Follow-up

Problem: If the lamp manufacturer produced 739 bulb units instead of 691, how many bulbs would be left unpacked after filling as many packs as possible with 205 bulbs each?

Gemma 2B:

     Reasoning: The number of packs that can be filled is 739/205 = <<739/205=3.604878048780488>>3.604878048780488.
    Since we can't have a fraction of a pack, we can only fill 3 packs.
    The number of bulbs left unpacked is 739 - 3*205 = <<739-3*205=124>>124 bulbs.
    ### Answer: 124

Expected answer: 124

Correct? Yes

🔗 Problem

Problem: On a farm, there are 330 bales of hay to be stored evenly in barns. Each barn can store up to 259 bales. After filling up the barns as evenly as possible, how many bales of hay will be left for the last barn?

Gemma 2B:

     Reasoning: To find out how many bales of hay will be left for the last barn, we need to divide the total number of bales by the number of bales each barn can store and find the remainder.
    330 ÷ 259 = 1 remainder 71
    So, there will be 71 bales of hay left for the last barn.
    ### Answer: 71

Expected answer: 71

Correct? Yes

🔗 Problem

Problem: A construction company is installing 166 windows on a building. They have determined that one installation team can install 137 windows per day. If all windows are equally distributed amongst teams each day, how many windows will remain for the team to install on the next day?

Gemma 2B:

     Reasoning: The company has 166 windows to install and one team can install 137 windows per day. If all windows are equally distributed amongst teams each day, then the number of windows that will remain for the team to install on the next day is 166 - 137 = <<166-137=29>>29 windows.
    ### Answer: 29

Expected answer: 29

Correct? Yes

🔗 Problem

Problem: There are 533 campers coming for a camping event at a park. Each tent can host 445 people. If the campers are evenly distributed among the tents, how many campers will be left over after all the tents are filled?

Gemma 2B:

     Reasoning: To find out how many campers will be left over, we need to divide the total number of campers by the number of people each tent can host and find the remainder.
    533 divided by 445 is 1 with a remainder of 88.
    Therefore, 88 campers will be left over after all the tents are filled.
    ### Answer: 88

Expected answer: 88

Correct? Yes

🔗 Follow-up

Problem: Now suppose that the park upgraded their tents and each tent can now host 886 people. With the same group of 533 campers, how many campers will be left over after all the tents are filled?

Gemma 2B:

     Reasoning: To find out how many campers will be left over, we need to divide the total number of campers by the number of people each tent can host and find the remainder.
    533 divided by 886 is 0 with a remainder of 533.
    Therefore, 533 campers will be left over after all the tents are filled.
    ### Answer: 533

Expected answer: 533

Correct? Yes

🔗 Problem

Problem: There are 999 seashells collected from a beach. They are grouped in beach-themed souvenir sets, each containing 474 shells. After grouping, how many seashells will be left without a set?

Gemma 2B:

     Reasoning: 999 seashells can be grouped into 999/474 = <<999/474=2.1076>>2 sets with a remainder of 999-2*474 = <<999-2*474=51>>51 seashells.
    ### Answer: 51

Expected answer: 51

Correct? Yes

🔗 Follow-up

Problem: In continuation of the previous scenario with seashells, imagine instead that there were initially only 234 seashells collected from the beach, but the souvenir sets are still made up of 474 shells each. How many shells would be left after attempting to form these sets?

Gemma 2B:

     Reasoning: Since there are only 234 seashells and each set requires 474 shells, no complete sets can be formed. Therefore, all 234 seashells will be left without a set.
    ### Answer: 234

Expected answer: 234

Correct? Yes

🔗 Problem

Problem: A tailor has 366 meters of fabric. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?

Gemma 2B:

     Reasoning: The tailor can make 366/160 = <<366/160=2.2875>>2 skirts from the fabric.
    The tailor will use 160*2 = <<160*2=320>>320 meters of fabric to make 2 skirts.
    The tailor will have 366-320 = <<366-320=46>>46 meters of fabric left.
    ### Answer: 46

Expected answer: 46

Correct? Yes

🔗 Follow-up

Problem: A tailor realized that she has made a mistake. Actually, she has only 21 meters of fabric at her disposal, not 366. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?

Gemma 2B:

     Reasoning: The tailor can make 21/160 = <<21/160=0.13125>>0 skirts from the fabric.
    The tailor will use 160*0 = <<160*0=0>>0 meters of fabric to make 0 skirts.
    The tailor will have 21-0 = <<21-0=21>>21 meters of fabric left.
    ### Answer: 21

Expected answer: 21

Correct? Yes

🔗 Problem

Problem: A toymaker made 993 dolls to be packed in boxes for shipment. Each box can hold 327 dolls. How many dolls will she have left once all the boxes are packed to their capacities?

Gemma 2B:

     Reasoning: The toymaker can pack 993/327 = <<993/327=3>>3 boxes.
    The toymaker can pack 3*327 = <<3*327=981>>981 dolls in total.
    The toymaker will have 993-981 = <<993-981=12>>12 dolls left once all the boxes are packed to their capacities.
    ### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous problem, what if, instead of each box holding 327 dolls, each box can now hold 115 dolls? After packing each box to capacity, how many dolls will the toymaker have left?

Gemma 2B:

     Reasoning: The toymaker can pack 993/115 = <<993/115=8.634782608695652>>8.634782608695652 boxes.
    Since the toymaker can't pack a fraction of a box, she can pack 8 boxes.
    The toymaker can pack 8*115 = <<8*115=920>>920 dolls in total.
    The toymaker will have 993-920 = <<993-920=73>>73 dolls left once all the boxes are packed to their capacities.
    ### Answer: 73

Expected answer: 73

Correct? Yes

🔗 Problem

Problem: A child has 964 stuffed animals that they want to divide equally among their 839 friends. If they distribute the stuffed animals evenly, how many will the child have left over?

Gemma 2B:

     Reasoning: To find out how many stuffed animals the child will have left over, we need to divide the total number of stuffed animals by the number of friends and find the remainder.
    964 ÷ 839 = 1 with a remainder of 125.
    ### Answer: 125

Expected answer: 125

Correct? Yes

🔗 Follow-up

Problem: The child from the previous problem has gotten even more stuffed animals and now has a total of 964 stuffed animals. If they still want to divide them equally among their 892 friends, how many stuffed animals will be left over after distributing them?

Gemma 2B:

     Reasoning: To find out how many stuffed animals will be left over, we need to divide the total number of stuffed animals by the number of friends and find the remainder.
    964 ÷ 892 = 1 with a remainder of 72.
    ### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Problem

Problem: A toy factory produces 369 teddy bears in a day. The bears are packaged in boxes and each box can hold 270 teddy bears. How many teddy bears will be left if all the teddy bears are evenly packed in the boxes?

Gemma 2B:

     Reasoning: The number of boxes needed to pack all the teddy bears is 369/270 = <<369/270=1.3666666666666667>>1.3666666666666667.
    Since we can't have a fraction of a box, we round up to the nearest whole number, which is 2.
    The number of teddy bears that can be packed in 2 boxes is 2*270 = <<2*270=540>>540.
    The number of teddy bears that will be left is 540-369 = <<540-369=171>>171.
    ### Answer: 171

Expected answer: 99

Correct? No

🔗 Problem

Problem: A village has a yearly tradition of building snowmen. This year, the villagers make 804 snowballs to build their snowmen. Each snowman needs exactly 184 snowballs. After all snowmen are built, how many snowballs are left leftover?

Gemma 2B:

     Reasoning: The villagers can build 804/184 = <<804/184=4.37>>4.37 snowmen. Since they can't build a fraction of a snowman, they can only build 4 snowmen.
    After building 4 snowmen, they will have used 4*184 = <<4*184=736>>736 snowballs.
    Therefore, they will have 804-736 = <<804-736=68>>68 snowballs left over.
    ### Answer: 68

Expected answer: 68

Correct? Yes

🔗 Follow-up

Problem: In the same village, another year, there were only 444 snowballs made to build the snowmen. If each snowman still requires exactly 184 snowballs, how many snowballs would be left over after as many complete snowmen as possible are built?

Gemma 2B:

     Reasoning: The villagers can build 444/184 = <<444/184=2.41>>2.41 snowmen. Since they can't build a fraction of a snowman, they can only build 2 snowmen.
    After building 2 snowmen, they will have used 2*184 = <<2*184=368>>368 snowballs.
    Therefore, they will have 444-368 = <<444-368=76>>76 snowballs left over.
    ### Answer: 76

Expected answer: 76

Correct? Yes

🔗 Problem

Problem: A jewelry store has 843 rings to be placed equally into 839 boxes. If each box is filled, how many rings will be left over?

Gemma 2B:

     Reasoning: To find the number of rings left over, we need to divide the total number of rings by the number of boxes and find the remainder.
    843 ÷ 839 = 1 remainder 4
    Therefore, there will be 4 rings left over.
    ### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: The jewelry store just received an additional shipment and now has a total of 843 rings. However, this time they must be equally placed into 804 boxes. If every box is filled, how many rings will be left over now?

Gemma 2B:

     Reasoning: To find the number of rings left over, we need to divide the total number of rings by the number of boxes and find the remainder.
    843 ÷ 804 = 1 remainder 39
    Therefore, there will be 39 rings left over.
    ### Answer: 39

Expected answer: 39

Correct? Yes

🔗 Problem

Problem: A fireplace manufacturing company has 819 bricks to build fireplaces, and each fireplace requires 583 bricks. If they build as many fireplaces as possible, how many bricks will they have left over?

Gemma 2B:

     Reasoning: The company can build 819/583 = <<819/583=1.404802744425386>>1.404802744425386 fireplaces, which is approximately 1 fireplace.
    The company will have 819-583 = <<819-583=236>>236 bricks left over.
    ### Answer: 236

Expected answer: 236

Correct? Yes

🔗 Follow-up

Problem: The company received a new delivery of bricks, now they have 486 bricks in total. If they continue making fireplaces, each requiring 583 bricks as before, how many bricks will they have left after building as many full fireplaces as they can?

Gemma 2B:

     Reasoning: The company can build 486/583 = <<486/583=0.8336192109777015>>0.8336192109777015 fireplaces, which is approximately 0 fireplaces.
    The company will have 486-0 = <<486-0=486>>486 bricks left over.
    ### Answer: 486

Expected answer: 486

Correct? Yes

🔗 Problem

Problem: A marshmallow factory produces 998 marshmallows per minute. However, the packaging machine can only hold 957 marshmallows at a time. What will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled?

Gemma 2B:

     Reasoning: The number of marshmallows left un-packaged in a minute will be 998-957 = <<998-957=41>>41.
    ### Answer: 41

Expected answer: 41

Correct? Yes

🔗 Follow-up

Problem: The marshmallow factory upgraded its packaging machine and now it can hold 804 marshmallows at a time instead of 957. If the factory continues to produce 998 marshmallows per minute, what will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity?

Gemma 2B:

     Reasoning: The number of marshmallows left un-packaged in a minute will be 998-804 = <<998-804=194>>194.
    ### Answer: 194

Expected answer: 194

Correct? Yes

🔗 Problem

Problem: There are 984 roses in the castle's garden. Princess likes to place 426 roses in every tribute for her loyal subjects. If she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?

Gemma 2B:

     Reasoning: Princess can distribute 984/426 = <<984/426=2.309859154929577>>2 tributes with 426 roses each.
    The number of roses left undistributed is 984 - (2 * 426) = <<984-(2*426)=132>>132 roses.
    ### Answer: 132

Expected answer: 132

Correct? Yes

🔗 Follow-up

Problem: In the same castle's garden, there were originally 984 roses, but the princess has decided to use only 730 roses for each tribute to her loyal subjects instead of the previous 426. Now, if she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?

Gemma 2B:

     Reasoning: Princess can distribute 984/730 = <<984/730=1.347945205479452>>1 tribute with 730 roses.
    The number of roses left undistributed is 984 - (1 * 730) = <<984-(1*730)=254>>254 roses.
    ### Answer: 254

Expected answer: 254

Correct? Yes

🔗 Problem

Problem: A song has 334 words in it. If each line in the song has 23 words, how many words would be in the incomplete line at the end of the song?

Gemma 2B:

     Reasoning: The total number of words in the song is 334.
    The number of complete lines in the song is 334/23 = <<334/23=14.521739130434783>>14.521739130434783.
    Since we can't have a fraction of a line, we round down to 14 complete lines.
    The number of words in the incomplete line is 334 - (14*23) = <<334-(14*23)=10>>10.
    ### Answer: 10

Expected answer: 12

Correct? No

🔗 Problem

Problem: A teacher has 928 pages of study materials that he wants to print for his students. His printer can only print 336 pages in one go. After filling the printer a number of times, how many pages will he have left over to print?

Gemma 2B:

     Reasoning: The teacher will have 928-336 = <<928-336=592>>592 pages left to print after the first run.
    The teacher will have 592-336 = <<592-336=256>>256 pages left to print after the second run.
    The teacher will have 256-336 = <<256-336=-80>>-80 pages left to print after the third run.
    Since the number of pages left to print cannot be negative, the teacher will have 0 pages left to print after the third run.
    ### Answer: 0

Expected answer: 256

Correct? No

🔗 Problem

Problem: Scientists have spotted 972 sharks in an area. The scientists tag groups of 667 sharks each. How many sharks are left untagged after the scientists finish tagging as many complete groups as possible?

Gemma 2B:

     Reasoning: The scientists can tag 972/667 = <<972/667=1.457>>1 complete group of sharks.
    After tagging 1 group, there are 972-667 = <<972-667=305>>305 sharks left untagged.
    ### Answer: 305

Expected answer: 305

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous question, the scientists later spotted a new group of 758 sharks in a different area. Again, they were trying to tag the sharks in groups of 667. How many sharks were left untagged after all complete groups have been tagged in this new area?

Gemma 2B:

     Reasoning: The scientists can tag 758/667 = <<758/667=1.136>>1 complete group of sharks in the new area.
    After tagging 1 group, there are 758-667 = <<758-667=91>>91 sharks left untagged.
    ### Answer: 91

Expected answer: 91

Correct? Yes

🔗 Problem

Problem: There are 686 blocks of cheese in the dairy shop. Each box can contain 349 blocks of cheese. If all the blocks of cheese are evenly distributed in the boxes, how many blocks of cheese would be left over after all the boxes are filled?

Gemma 2B:

     Reasoning: To find the number of blocks of cheese left over, we need to find the remainder when 686 is divided by 349.
    686 divided by 349 is 1 with a remainder of 337.
    ### Answer: 337

Expected answer: 337

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, say the dairy shop initially had 239 blocks of cheese instead of 686. Using the same boxes which can contain 349 blocks of cheese, how many blocks of cheese would be left over after all the boxes are filled?

Gemma 2B:

     Reasoning: To find the number of blocks of cheese left over, we need to find the remainder when 239 is divided by 349.
    239 divided by 349 is 0 with a remainder of 239.
    ### Answer: 239

Expected answer: 239

Correct? Yes

🔗 Problem

Problem: There were 513 centimeters of snowfall recorded this winter. A snowplow can clear up to 170 centimeters of snow at a time. If the snowplow runs continuously, how many centimeters of snow will be left over after the final pass?

Gemma 2B:

     Reasoning: The snowplow can clear up to 170 centimeters of snow at a time, so it will need to make 513/170 = <<513/170=3>>3 passes to clear all the snow.
    After the first pass, there will be 513-170 = <<513-170=343>>343 centimeters of snow left.
    After the second pass, there will be 343-170 = <<343-170=173>>173 centimeters of snow left.
    After the third pass, there will be 173-170 = <<173-170=3>>3 centimeters of snow left.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Suppose that instead of 513 centimeters, there were 460 centimeters of snowfall this winter. If the same snowplow, which can clear up to 170 centimeters of snow at a time, runs continuously, how many centimeters of snow would then be left over after the final pass?

Gemma 2B:

     Reasoning: The snowplow can clear up to 170 centimeters of snow at a time, so it will need to make 460/170 = <<460/170=2.7058823529411765>>2.7058823529411765 passes to clear all the snow. Since the snowplow can't make a fraction of a pass, it will need to make 3 passes.
    After the first pass, there will be 460-170 = <<460-170=290>>290 centimeters of snow left.
    After the second pass, there will be 290-170 = <<290-170=120>>120 centimeters of snow left.
    After the third pass, there will be 120-170 = <<120-170=-50>>-50 centimeters of snow left. Since the snowplow can't clear a negative amount of snow, it will have cleared all the snow.
    ### Answer: 0

Expected answer: 120

Correct? No

🔗 Problem

Problem: A compass maker has 661 needles to install in compasses. Each compass uses 510 needles. After installing as many full compasses as he can, how many needles will the compass maker have left?

Gemma 2B:

     Reasoning: The compass maker can install 661/510 = <<661/510=1.296078431372549>>1 full compasses.
    The compass maker will have 661-510*1 = <<661-510*1=151>>151 needles left.
    ### Answer: 151

Expected answer: 151

Correct? Yes

🔗 Problem

Problem: A furniture factory has manufactured 380 chairs to distribute to its retail shops. Each shop can only hold 310 chairs in its storage. If the factory evenly distributes all the chairs to the shops, how many chairs will be left at the factory?

Gemma 2B:

     Reasoning: The factory has 380 chairs and each shop can hold 310 chairs. So, the number of chairs left at the factory is 380 - 310 = <<380-310=70>>70 chairs.
    ### Answer: 70

Expected answer: 70

Correct? Yes

🔗 Follow-up

Problem: Now suppose the factory decides to distribute these chairs amongst its smaller distributors, each of which can only hold 143 chairs. Now, how many chairs will be left at the factory after distributing them evenly?

Gemma 2B:

     Reasoning: The factory has 380 chairs and each distributor can hold 143 chairs. So, the number of distributors needed is 380/143 = <<380/143=2.6573426573426575>>2.6573426573426575 distributors. Since we can't have a fraction of a distributor, we round up to 3 distributors. So, the number of chairs left at the factory is 380 - (143*3) = <<380-(143*3)=51>>51 chairs.
    ### Answer: 51

Expected answer: 94

Correct? No

🔗 Problem

Problem: A farmer has gathered 929 tomatoes from his field. He plans to sell them in boxes, with 154 tomatoes in each box. After packing them evenly in boxes, how many tomatoes will be left over?

Gemma 2B:

     Reasoning: The farmer can pack 929/154 = <<929/154=6.032467532467532>>6 boxes of tomatoes, with 929-6*154 = <<929-6*154=11>>11 tomatoes left over.
    ### Answer: 11

Expected answer: 5

Correct? No

🔗 Problem

Problem: A sporting goods store has 454 pairs of ice skates in total. The store distributes the skates evenly among 128 boxes. How many pairs of ice skates will be left over after all the boxes are filled up equally?

Gemma 2B:

     Reasoning: The store can fill up 128 boxes with 454 pairs of ice skates evenly, with each box containing 454/128 = <<454/128=3.546875>>3 pairs of ice skates.
    The store will have 454 - 128*3 = <<454-128*3=454-384=70>>70 pairs of ice skates left over after all the boxes are filled up equally.
    ### Answer: 70

Expected answer: 70

Correct? Yes

🔗 Follow-up

Problem: If the sporting goods store originally had 976 pairs of ice skates instead of 454, and they still distribute the skates evenly among 128 boxes as before, how many pairs of ice skates will be left over after all the boxes are filled equally?

Gemma 2B:

     Reasoning: The store can fill up 128 boxes with 976 pairs of ice skates evenly, with each box containing 976/128 = <<976/128=7.625>>7 pairs of ice skates.
    The store will have 976 - 128*7 = <<976-128*7=976-896=80>>80 pairs of ice skates left over after all the boxes are filled up equally.
    ### Answer: 80

Expected answer: 80

Correct? Yes

🔗 Problem

Problem: A windmill generates 506 units of power per day. Every day, a small village consumes power in increments of 385 units. At the end of the day, after the village has consumed as much power as it can in full increments, how much power is left over?

Gemma 2B:

     Reasoning: The village consumes power in increments of 385 units, so the leftover power is the remainder when 506 is divided by 385.
    506 divided by 385 is 1 with a remainder of 121.
    ### Answer: 121

Expected answer: 121

Correct? Yes

🔗 Follow-up

Problem: Following the scenario of the windmill and the small village, let's now consider that the windmill had a great day and managed to generate 506 units of power. However, due to development demands, the daily consumption of the village has increased to 920 units. At the end of the day, with the power being consumed in complete units, how much power is left over?

Gemma 2B:

     Reasoning: The village consumes power in increments of 920 units, so the leftover power is the remainder when 506 is divided by 920.
    506 divided by 920 is 0 with a remainder of 506.
    ### Answer: 506

Expected answer: 506

Correct? Yes

🔗 Problem

Problem: Superhero Blast Man has 338 energy units in his power cells. Each energy blast he fires uses 16 energy units. After using equal units of energy firing blasts, how many energy units will Blast Man have left in his power cells?

Gemma 2B:

     Reasoning: Blast Man has 338 energy units in his power cells.
    Each energy blast he fires uses 16 energy units.
    After using equal units of energy firing blasts, Blast Man will have 338 - 16 = <<338-16=322>>322 energy units left in his power cells.
    ### Answer: 322

Expected answer: 2

Correct? No

🔗 Problem

Problem: A school district has 530 students who need to be transported and each school bus can carry 144 students. If all students are equally spread across the buses, how many students will be on the last school bus?

Gemma 2B:

     Reasoning: The number of buses needed is 530/144 = <<530/144=3.6805555555555554>>3.6805555555555554, which rounds up to 4 buses.
    The number of students on the first 3 buses is 3*144 = <<3*144=432>>432.
    The number of students on the last bus is 530-432 = <<530-432=98>>98.
    ### Answer: 98

Expected answer: 98

Correct? Yes

🔗 Problem

Problem: A wizard has 999 spells in his book. He tries to distribute them equally among 951 apprentice wizards but they don't divide evenly. How many spells will the wizard have left after giving out as many as he can to his apprentices?

Gemma 2B:

     Reasoning: The wizard can give out 999/951 = <<999/951=1.0504732807560463>>1 spell to each apprentice.
    The wizard will have 999-951*1 = <<999-951*1=48>>48 spells left.
    ### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: If the wizard had instead 999 spells and he tries to distribute them equally among 801 apprentice wizards, how many spells will the wizard have left after giving out as many as he can to his apprentices?

Gemma 2B:

     Reasoning: The wizard can give out 999/801 = <<999/801=1.247191011235955>>1 spell to each apprentice.
    The wizard will have 999-801*1 = <<999-801*1=198>>198 spells left.
    ### Answer: 198

Expected answer: 198

Correct? Yes

🔗 Problem

Problem: A scooter manufacturing company has produced 767 scooters. Each delivery truck they use can carry 369 scooters. If they distribute the scooters evenly among the trucks, how many scooters will be left after all the trucks are loaded?

Gemma 2B:

     Reasoning: To find out how many scooters will be left after all the trucks are loaded, we need to divide the total number of scooters by the number of scooters each truck can carry and then find the remainder.
    767 ÷ 369 = 2 with a remainder of 29.
    ### Answer: 29

Expected answer: 29

Correct? Yes

🔗 Problem

Problem: There are 846 water droplets in a cloud. Each raindrop needs 722 droplets to form. If all droplets are used to form raindrops, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Gemma 2B:

     Reasoning: The number of raindrops that can be formed is 846/722 = <<846/722=1.1717732989029086>>1.1717732989029086. Since we can't have a fraction of a raindrop, we can only form 1 raindrop. The number of droplets used to form this raindrop is 722. Therefore, the number of droplets left unconverted is 846-722 = <<846-722=124>>124.
    ### Answer: 124

Expected answer: 124

Correct? Yes

🔗 Follow-up

Problem: There was a slight miscalculation in the cloud's droplet count. There are actually 846 water droplets in the cloud, but each raindrop needs 442 droplets to form instead of 722. With this updated droplet count per raindrop, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Gemma 2B:

     Reasoning: The number of raindrops that can be formed is 846/442 = <<846/442=1.9140271493212669>>1.9140271493212669. Since we can't have a fraction of a raindrop, we can only form 1 raindrop. The number of droplets used to form this raindrop is 442. Therefore, the number of droplets left unconverted is 846-442 = <<846-442=404>>404.
    ### Answer: 404

Expected answer: 404

Correct? Yes

🔗 Problem

Problem: Unicorn Village, a magical place where 265 unicorns live, is divided into 146 equal sections where these magical creatures reside. If each section is occupied by an equal number of unicorns, how many unicorns will live in the last incomplete section?

Gemma 2B:

     Reasoning: There are 265 unicorns in total and 146 sections. If each section is occupied by an equal number of unicorns, then the number of unicorns in each section is 265/146 = <<265/146=1.8150684931506849>>1.8150684931506849. Since the number of unicorns must be a whole number, we round down to 1 unicorn per section. Therefore, there are 146 unicorns in the complete sections and 265-146 = <<265-146=119>>119 unicorns in the last incomplete section.
    ### Answer: 119

Expected answer: 119

Correct? Yes

🔗 Follow-up

Problem: Considering the same scenario from the previous problem, let's say instead of 146 sections, Unicorn Village is divided into 781 equal sections. How many unicorns will live in the last incomplete section now?

Gemma 2B:

     Reasoning: There are 265 unicorns in total and 781 sections. If each section is occupied by an equal number of unicorns, then the number of unicorns in each section is 265/781 = <<265/781=0.3392957746478873>>0.3392957746478873. Since the number of unicorns must be a whole number, we round down to 0 unicorns per section. Therefore, there are 0 unicorns in the complete sections and 265-0 = <<265-0=265>>265 unicorns in the last incomplete section.
    ### Answer: 265

Expected answer: 265

Correct? Yes

🔗 Problem

Problem: In a game, there are 923 players waiting to enter a match. Only 383 players can enter a match at a time. If players enter matches evenly, how many players will be left waiting after filling all the matches?

Gemma 2B:

     Reasoning: The number of players left waiting after filling all the matches is 923-383 = <<923-383=540>>540 players.
    ### Answer: 540

Expected answer: 157

Correct? No

🔗 Problem

Problem: A pirate ship has 923 cannonballs on board. They want to equally disperse them between 499 different crates. After evenly distributing them as much as possible, how many cannonballs will be left uncrated?

Gemma 2B:

     Reasoning: To find out how many cannonballs will be left uncrated, we need to divide the total number of cannonballs by the number of crates and find the remainder.
    923 ÷ 499 = 1 remainder 424
    Therefore, 424 cannonballs will be left uncrated.
    ### Answer: 424

Expected answer: 424

Correct? Yes

🔗 Follow-up

Problem: Keeping in line with the previous pirate ship themed problem, let's consider the following scenario: The same pirate ship initially started with 462 cannonballs instead of 923. After the pirates evenly distribute these cannonballs into the same 499 crates, can any be leftover? If so, how many cannonballs will be left uncrated?

Gemma 2B:

     Reasoning: To find out how many cannonballs will be left uncrated, we need to divide the total number of cannonballs by the number of crates and find the remainder.
    462 ÷ 499 = 0 remainder 462
    Therefore, 462 cannonballs will be left uncrated.
    ### Answer: 462

Expected answer: 462

Correct? Yes

🔗 Problem

Problem: A kite store has 530 string spools to attach to their kites. They distribute them to 518 kites, each getting one string spool. After each kite gets a spool, how many spools are left in the store?

Gemma 2B:

     Reasoning: The store has 530-518 = <<530-518=12>>12 spools left.
    ### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: A dairy farm produces 913 gallons of milk in a day. If every milk jug holds 39 gallons, how many gallons will be left over after all the jugs are filled?

Gemma 2B:

     Reasoning: The dairy farm produces 913 gallons of milk in a day.
    The dairy farm can fill 913/39 = <<913/39=23.41025641025641>>23 full jugs of milk.
    The dairy farm will have 913 - 23*39 = <<913-23*39=16>>16 gallons of milk left over.
    ### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Follow-up

Problem: The dairy farm has adjusted its production and now produces 913 gallons of milk in a day. If they started using larger milk jugs that hold 230 gallons each, how many gallons will be left over after all the jugs are filled?

Gemma 2B:

     Reasoning: The dairy farm produces 913 gallons of milk in a day.
    The dairy farm can fill 913/230 = <<913/230=3.969565217391304>>3 full jugs of milk.
    The dairy farm will have 913 - 3*230 = <<913-3*230=223>>223 gallons of milk left over.
    ### Answer: 223

Expected answer: 223

Correct? Yes

🔗 Problem

Problem: A doll seller received a shipment of 603 new dolls to put on the shelves. She arranged all the dolls in rows, with 369 dolls in each row. After filling up the rows as much as possible, how many dolls were left unarranged?

Gemma 2B:

     Reasoning: The doll seller arranged 369 dolls in each row. To find out how many rows she could fill, we divide the total number of dolls by the number of dolls in each row: 603 / 369 = <<603/369=1.6341463414634147>>1.6341463414634147. Since she can only fill complete rows, she fills 1 row with 369 dolls. The number of dolls left unarranged is the remainder when 603 is divided by 369: 603 % 369 = <<603%369=234>>234.
    ### Answer: 234

Expected answer: 234

Correct? Yes

🔗 Follow-up

Problem: In the previous doll problem, if the doll seller initially received a shipment of 44 new dolls instead of 603, and still arranged them in rows of 369 dolls, how many dolls would be left unarranged after filling up the rows as much as possible?

Gemma 2B:

     Reasoning: The doll seller arranged 369 dolls in each row. To find out how many rows she could fill, we divide the total number of dolls by the number of dolls in each row: 44 / 369 = <<44/369=0.11924119241192412>>0.11924119241192412. Since she can only fill complete rows, she fills 0 rows with 369 dolls. The number of dolls left unarranged is the remainder when 44 is divided by 369: 44 % 369 = <<44%369=44>>44.
    ### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Problem

Problem: A jewelry maker has 850 beads to make necklaces. They use 631 beads for each necklace. After using as many beads as possible, how many beads will the jewelry maker have left over?

Gemma 2B:

     Reasoning: The jewelry maker uses 631 beads for each necklace, so they can make 850/631 = <<850/631=1.346>>1 necklace with 850-631 = <<850-631=219>>219 beads left over.
    ### Answer: 219

Expected answer: 219

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker decides to change the design and now each necklace uses only 150 beads instead of 631 beads. After they distribute the 850 beads as equally as possible among the new necklaces, how many beads will the jewelry maker have left over?

Gemma 2B:

     Reasoning: The jewelry maker can make 850/150 = <<850/150=5.666>>5 necklaces with 850-150*5 = <<850-150*5=100>>100 beads left over.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Problem

Problem: A gardener has 952 grapes that he wants to package into boxes. If each box can hold 380 grapes, how many grapes will be left after the gardener has filled as many boxes as possible?

Gemma 2B:

     Reasoning: The gardener can fill 952/380 = <<952/380=2.5052631578947367>>2.5052631578947367 boxes with grapes. Since the gardener can only fill whole boxes, he can fill 2 boxes with grapes.
    The gardener will have 952 - 2*380 = <<952-2*380=192>>192 grapes left after filling the boxes.
    ### Answer: 192

Expected answer: 192

Correct? Yes

🔗 Follow-up

Problem: The gardener's friend gave him an additional 183 grapes from his own garden. If the gardener decides to package these grapes as well into boxes with each box holding 380 grapes, how many grapes will remain after packaging the new grapes into as many boxes as possible?

Gemma 2B:

     Reasoning: The gardener can fill 183/380 = <<183/380=0.48157894736842105>>0.48157894736842105 boxes with grapes. Since the gardener can only fill whole boxes, he can fill 0 boxes with grapes.
    The gardener will have 183 - 0*380 = <<183-0*380=183>>183 grapes left after filling the boxes.
    ### Answer: 183

Expected answer: 183

Correct? Yes

🔗 Problem

Problem: On a treasure map, there are 236 steps mentioned on the guide. If every 44 steps I make leads me to a significant place or clue, how many steps will be left after I reach the last significant place or clue?

Gemma 2B:

     Reasoning: There are 236/44 = <<236/44=5.36>>5.36 significant places or clues.
    Since I can't make a fraction of a step, I will make 5 significant places or clues.
    After reaching the last significant place or clue, I will have made 5*44 = <<5*44=220>>220 steps.
    There will be 236-220 = <<236-220=16>>16 steps left.
    ### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Problem

Problem: Sarah blew 932 bubbles using her new bubble machine. The machine is designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Gemma 2B:

     Reasoning: The machine can form 932/507 = <<932/507=1.8382642997633136>>1.8382642997633136 groups of bubbles.
    Since the machine can only form complete groups, it forms 1 complete group of 507 bubbles.
    The remaining bubbles are 932 - 507 = <<932-507=425>>425 bubbles.
    ### Answer: 425

Expected answer: 425

Correct? Yes

🔗 Follow-up

Problem: Suppose Sarah uses her bubble machine again, this time to blow 904 bubbles. The machine is still designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Gemma 2B:

     Reasoning: The machine can form 904/507 = <<904/507=1.7829976331360947>>1.7829976331360947 groups of bubbles.
    Since the machine can only form complete groups, it forms 1 complete group of 507 bubbles.
    The remaining bubbles are 904 - 507 = <<904-507=397>>397 bubbles.
    ### Answer: 397

Expected answer: 397

Correct? Yes

🔗 Problem

Problem: At the park, there are 931 kids who want to use the swings. Each swing set can accommodate 34 kids at a time. If all the swing sets are filled continuously, how many kids will be waiting for their turn after all the swing sets are occupied?

Gemma 2B:

     Reasoning: To find out how many kids will be waiting, we need to determine the remainder when 931 is divided by 34.
    931 divided by 34 is 27 with a remainder of 13.
    Therefore, 13 kids will be waiting for their turn after all the swing sets are occupied.
    ### Answer: 13

Expected answer: 13

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, let's say that some of the kids finished their swinging and left the park. Now, there are only 708 kids waiting to use the swings. Each swing set can still accommodate 34 kids at a time. Given this new number, how many children will be waiting for their turn after all the swing sets are occupied?

Gemma 2B:

     Reasoning: To find out how many kids will be waiting, we need to determine the remainder when 708 is divided by 34.
    708 divided by 34 is 20 with a remainder of 28.
    Therefore, 28 kids will be waiting for their turn after all the swing sets are occupied.
    ### Answer: 28

Expected answer: 28

Correct? Yes

🔗 Problem

Problem: John has 943 dollar bills in his possession. He tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left?

Gemma 2B:

     Reasoning: John can stuff 943/433 = <<943/433=2.17782909930716>>2 wallets with 433 dollar bills each.
    John has 943 - 2*433 = <<943-2*433=77>>77 dollar bills left.
    ### Answer: 77

Expected answer: 77

Correct? Yes

🔗 Follow-up

Problem: Suppose John originally had 586 dollar bills instead of 943. He still tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left now?

Gemma 2B:

     Reasoning: John can stuff 586/433 = <<586/433=1.35334872979215>>1 wallet with 433 dollar bills.
    John has 586 - 1*433 = <<586-1*433=153>>153 dollar bills left.
    ### Answer: 153

Expected answer: 153

Correct? Yes

🔗 Problem

Problem: A helicopter pilot plans to transport 240 passengers over several trips. He can carry 177 passengers in one trip. How many passengers will be left behind after the helicopter makes the first full trip?

Gemma 2B:

     Reasoning: The helicopter pilot can transport 177 passengers in one trip. Therefore, after the first full trip, the number of passengers left behind will be 240 - 177 = <<240-177=63>>63 passengers.
    ### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Problem

Problem: A gardener has 982 flowers to plant in flowerbeds. Each flowerbed can fit 555 flowers. After filling up as many flowerbeds as possible, how many flowers will the gardener have left to plant?

Gemma 2B:

     Reasoning: The gardener can fill up 982/555 = <<982/555=1.7693693693693694>>1.7693693693693694 flowerbeds.
    Since the gardener can only fill up whole flowerbeds, they can fill up 1 flowerbed.
    The gardener will have 982-555 = <<982-555=427>>427 flowers left to plant.
    ### Answer: 427

Expected answer: 427

Correct? Yes

🔗 Follow-up

Problem: The gardener received an additional shipment, bringing the total number of flowers up to 867. If he continues to plant the flowers in flowerbeds of 555 each, how many flowers will he have left to plant after filling up as many flowerbeds as possible?

Gemma 2B:

     Reasoning: The gardener can fill up 867/555 = <<867/555=1.5621621621621622>>1.5621621621621622 flowerbeds.
    Since the gardener can only fill up whole flowerbeds, they can fill up 1 flowerbed.
    The gardener will have 867-555 = <<867-555=312>>312 flowers left to plant.
    ### Answer: 312

Expected answer: 312

Correct? Yes

🔗 Problem

Problem: A farmer grows 203 strawberry plants. She wants to divide her plants into groups of 5 to sell. How many plants will be remaining if she divides them equally?

Gemma 2B:

     Reasoning: The farmer can divide 203 by 5 to find out how many groups of 5 she can make. 203 divided by 5 is 40 with a remainder of 3. Therefore, there will be 3 plants remaining.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: The farmer harvested another field and got an additional 76 strawberry plants. Again, she wants to divide the new plants into groups of 5 to sell. How many plants will be remaining if she divides these new strawberries equally?

Gemma 2B:

     Reasoning: The farmer can divide 76 by 5 to find out how many groups of 5 she can make. 76 divided by 5 is 15 with a remainder of 1. Therefore, there will be 1 plant remaining.
    ### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Problem

Problem: A gardener has 355 carrots. He wants to create bundles of 16. After creating as many bundles as he can, how many carrots will he have left?

Gemma 2B:

     Reasoning: The gardener can create 355/16 = <<355/16=22.1875>>22 bundles of 16 carrots, with 355-22*16 = <<355-22*16=3>>3 carrots left over.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Problem

Problem: A total rainfall of 612 inches fell over a certain city in 29 consecutive days. If the rain fell in the same amount every day, how many inches of rain would be left to make the days evenly rainy?

Gemma 2B:

     Reasoning: The total rainfall is 612 inches, and it fell over 29 days. To find out how many inches of rain fell each day, we divide the total rainfall by the number of days: 612 / 29 = <<612/29=21>>21 inches per day.
    Since the rain fell in the same amount every day, there would be no inches of rain left to make the days evenly rainy.
    ### Answer: 0

Expected answer: 3

Correct? No

🔗 Problem

Problem: A truck company has got 514 boxes for delivery. Each truck can hold up to 371 boxes. If each truck is loaded to its full capacity, how many boxes will be left over?

Gemma 2B:

     Reasoning: The truck company can load 371 boxes per truck, and they have 514 boxes in total. To find out how many boxes will be left over, we need to divide the total number of boxes by the number of boxes each truck can hold and then find the remainder.
    514 ÷ 371 = 1 remainder 143
    ### Answer: 143

Expected answer: 143

Correct? Yes

🔗 Problem

Problem: In a large sandbox, children create 684 sandcastles over the summer. The sandcastles were grouped into sets of 230 for a photography contest. After all the sets were completed, how many sandcastles were left that didn't form a complete set?

Gemma 2B:

     Reasoning: The number of complete sets of sandcastles is 684/230 = <<684/230=2.973913043478261>>2.973913043478261.
    Since we can't have a fraction of a set, we round down to the nearest whole number, which is 2.
    The number of sandcastles in the complete sets is 2*230 = <<2*230=460>>460.
    The number of sandcastles left that didn't form a complete set is 684-460 = <<684-460=224>>224.
    ### Answer: 224

Expected answer: 224

Correct? Yes

🔗 Follow-up

Problem: Continuing from the prior problem, suppose that in another large sandbox, children now create 533 sandcastles over the summer instead of 684. If they still group the sandcastles in sets of 230 for a photography contest, how many sandcastles will be left now that don't form a complete set?

Gemma 2B:

     Reasoning: The number of complete sets of sandcastles is 533/230 = <<533/230=2.317391304347826>>2.317391304347826.
    Since we can't have a fraction of a set, we round down to the nearest whole number, which is 2.
    The number of sandcastles in the complete sets is 2*230 = <<2*230=460>>460.
    The number of sandcastles left that didn't form a complete set is 533-460 = <<533-460=73>>73.
    ### Answer: 73

Expected answer: 73

Correct? Yes

🔗 Problem

Problem: A toy manufacturer has a production run of 735 toy cars. They package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among packs, how many toy cars will be left over after all full packs have been filled?

Gemma 2B:

     Reasoning: The number of full packs that can be filled is 735/348 = <<735/348=2.1120689655172413>>2.1120689655172413. Since we can't have a fraction of a pack, we round down to 2 full packs.
    The number of toy cars left over is 735 - 2*348 = <<735-2*348=43>>43.
    ### Answer: 43

Expected answer: 39

Correct? No

🔗 Problem

Problem: In a forest, there are 386 animals. Each woodlands territory can support 95 animals. If the existing animals are evenly distributed among the territories, how many animals will be left in the last not fully occupied territory?

Gemma 2B:

     Reasoning: There are 386/95 = <<386/95=4.063157894736842>>4.063157894736842 territories. Since we can't have a fraction of a territory, we round down to 4 territories.
    Each territory can support 95 animals, so 4 territories can support 4*95 = <<4*95=380>>380 animals.
    There are 386-380 = <<386-380=6>>6 animals left in the last not fully occupied territory.
    ### Answer: 6

Expected answer: 6

Correct? Yes

🔗 Follow-up

Problem: In the same forest, a new report finds that there were actually 497 animals instead of the initially thought 386. If these animals were evenly distributed among the territories, each still supporting 95 animals, how many animals would be in the last not fully occupied territory now?

Gemma 2B:

     Reasoning: There are 497/95 = <<497/95=5.231578947368421>>5.231578947368421 territories. Since we can't have a fraction of a territory, we round down to 5 territories.
    Each territory can support 95 animals, so 5 territories can support 5*95 = <<5*95=475>>475 animals.
    There are 497-475 = <<497-475=22>>22 animals left in the last not fully occupied territory.
    ### Answer: 22

Expected answer: 22

Correct? Yes

🔗 Problem

Problem: A forest has 801 trees. A tree disease starts to spread and is expected to affect 646 trees. If all the diseased trees have to be cut down evenly, how many trees are likely to stay healthy after the disease has affected all possible trees?

Gemma 2B:

     Reasoning: The number of trees that are likely to stay healthy is 801-646 = <<801-646=155>>155 trees.
    ### Answer: 155

Expected answer: 155

Correct? Yes

🔗 Problem

Problem: A rope manufacturer has made a rope of 934 meters in length. This rope is supposed to be cut into smaller pieces, each piece being 902 meters in length. After cutting into the maximum possible number of equal pieces, how many meters will the last piece of the rope be?

Gemma 2B:

     Reasoning: The maximum number of equal pieces that can be cut from the rope is 934/902 = <<934/902=1.0354789915966387>>1.0354789915966387.
    Since we can't cut a fraction of a piece, we can only cut 1 piece from the rope.
    The length of the last piece will be 934 - 902 = <<934-902=32>>32 meters.
    ### Answer: 32

Expected answer: 32

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous scenario, suppose that the manufacturer only made a rope of 202 meters in length initially. Applying the same method of cutting rope into pieces that are each 902 meters long, how many meters would the piece of the rope be now?

Gemma 2B:

     Reasoning: The maximum number of equal pieces that can be cut from the rope is 202/902 = <<202/902=0.2239467872283823>>0.2239467872283823.
    Since we can't cut a fraction of a piece, we can only cut 0 pieces from the rope.
    The length of the last piece will be 202 meters.
    ### Answer: 202

Expected answer: 202

Correct? Yes

🔗 Problem

Problem: A dairy farm produces 561 liters of milk each day. The milk is packaged into 550-liter containers. How many liters of milk are left over each day after filling the containers?

Gemma 2B:

     Reasoning: The dairy farm produces 561 liters of milk each day.
    The milk is packaged into 550-liter containers.
    The number of liters of milk left over each day after filling the containers is 561-550 = <<561-550=11>>11 liters.
    ### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: If the dairy farm increased its production and started producing 729 liters of milk each day instead of 561 liters, how many liters of milk would be left over each day after filling the 550-liter containers?

Gemma 2B:

     Reasoning: The dairy farm now produces 729 liters of milk each day.
    The milk is still packaged into 550-liter containers.
    The number of liters of milk left over each day after filling the containers is 729-550 = <<729-550=179>>179 liters.
    ### Answer: 179

Expected answer: 179

Correct? Yes

🔗 Problem

Problem: Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?

Gemma 2B:

     Reasoning: Jon can complete 259/258 = <<259/258=1.003875968992248>>1 full puzzle.
    The number of pieces left over is 259 - 258 = <<259-258=1>>1 piece.
    ### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, Jon had 259 puzzle pieces and each puzzle requires 258 pieces. Suppose instead each puzzle needs 542 pieces. How many pieces would Jon have left over after finishing as many full puzzles as possible with his 259 pieces?

Gemma 2B:

     Reasoning: Jon can complete 259/542 = <<259/542=0.47785977859778597>>0 full puzzles.
    The number of pieces left over is 259 - 0*542 = <<259-0*542=259>>259 pieces.
    ### Answer: 259

Expected answer: 259

Correct? Yes

🔗 Problem

Problem: A jewelry maker has 673 beads. She plans to use exactly 49 beads for each bracelet. How many beads will she have left after creating as many bracelets as possible with the exact number of beads?

Gemma 2B:

     Reasoning: The jewelry maker can create 673/49 = <<673/49=13.73469387755102>>13 bracelets with 49 beads each.
    The jewelry maker will have 673 - (13*49) = <<673-(13*49)=46>>46 beads left.
    ### Answer: 46

Expected answer: 36

Correct? No

🔗 Problem

Problem: A police station received 927 calls within a week. They have 311 operators who can handle the same number of calls each week. However, when the calls are divided equally, how many calls will the last operator handle?

Gemma 2B:

     Reasoning: To find out how many calls each operator handles, we divide the total number of calls by the number of operators: 927 / 311 = <<927/311=3>>3 calls per operator.
    Since the calls are divided equally, the last operator will also handle 3 calls.
    ### Answer: 3

Expected answer: 305

Correct? No

🔗 Problem

Problem: John has 764 pieces for his jigsaw puzzle, and every package should contain 589 pieces. If he separates these pieces into full packages, how many pieces will be left outside without a package?

Gemma 2B:

     Reasoning: John can separate 764/589 = <<764/589=1.3>>1 full package from his pieces.
    John will have 764-589 = <<764-589=175>>175 pieces left outside without a package.
    ### Answer: 175

Expected answer: 175

Correct? Yes

🔗 Follow-up

Problem: If John had originally only 404 puzzle pieces, and each package can still only contain 589, how many pieces will be left outside the package now?

Gemma 2B:

     Reasoning: John can separate 404/589 = <<404/589=0.68>>0 full packages from his pieces.
    John will have 404-0 = <<404-0=404>>404 pieces left outside without a package.
    ### Answer: 404

Expected answer: 404

Correct? Yes

🔗 Problem

Problem: A dressmaker has 984 meters of fabric. She uses 217 meters of fabric to make each dress. After using all the fabric she can to make as many dresses as possible, how many meters of fabric will she have left?

Gemma 2B:

     Reasoning: The dressmaker can make 984/217 = <<984/217=4.534562211981566>>4 dresses with the fabric she has.
    After making 4 dresses, she will have used 4*217 = <<4*217=868>>868 meters of fabric.
    Therefore, she will have 984-868 = <<984-868=116>>116 meters of fabric left.
    ### Answer: 116

Expected answer: 116

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, let's now suppose that the dressmaker has 984 meters of fabric, but this time she uses 585 meters of fabric to make each dress. Again, she uses all the fabric she can to make as many dresses as possible. With this change, how many meters of fabric will she have left after all the dresses are made?

Gemma 2B:

     Reasoning: The dressmaker can make 984/585 = <<984/585=1.682051282051282>>1 dress with the fabric she has.
    After making 1 dress, she will have used 1*585 = <<1*585=585>>585 meters of fabric.
    Therefore, she will have 984-585 = <<984-585=399>>399 meters of fabric left.
    ### Answer: 399

Expected answer: 399

Correct? Yes

🔗 Problem

Problem: A company donates 639 sleeping bags for a camping event. Each campsite is supplied with 374 sleeping bags. If all the sleeping bags are divided equally among the campsites, how many sleeping bags will there be left?

Gemma 2B:

     Reasoning: The company donates 639 sleeping bags.
    Each campsite is supplied with 374 sleeping bags.
    If all the sleeping bags are divided equally among the campsites, there will be 639-374 = <<639-374=265>>265 sleeping bags left.
    ### Answer: 265

Expected answer: 265

Correct? Yes

🔗 Follow-up

Problem: The same company from our previous question receives an updated request for sleeping bags. Now instead of 639, they only need to donate 613. If each campsite is still supplied with 374 sleeping bags, how many sleeping bags will be left after all the campsites are filled?

Gemma 2B:

     Reasoning: The company donates 613 sleeping bags.
    Each campsite is supplied with 374 sleeping bags.
    If all the sleeping bags are divided equally among the campsites, there will be 613-374 = <<613-374=239>>239 sleeping bags left.
    ### Answer: 239

Expected answer: 239

Correct? Yes

🔗 Problem

Problem: A pizza restaurant made 620 pizzas today. They package up the pizzas in boxes that hold 578 each for delivery. If the pizzas are evenly distributed into these boxes, how many pizzas will be left over that don't fit into a box?

Gemma 2B:

     Reasoning: The number of pizzas that will be left over is the remainder when 620 is divided by 578.
    620 divided by 578 is 1 with a remainder of 42.
    ### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Follow-up

Problem: The owner of the pizza restaurant decides to make 74 more pizzas tomorrow, bringing the total to 694 pizzas. If they are again distributed into boxes that hold 578 pizzas each, how many pizzas will be left out without a box this time?

Gemma 2B:

     Reasoning: The number of pizzas that will be left over is the remainder when 694 is divided by 578.
    694 divided by 578 is 1 with a remainder of 116.
    ### Answer: 116

Expected answer: 116

Correct? Yes

🔗 Problem

Problem: A factory made a total of 820 robots. It can store 684 robots in one storage unit. If the robots are evenly stored, how many robots will not fit and remain outside of the storage units?

Gemma 2B:

     Reasoning: The factory can store 684 robots in one storage unit. To find out how many robots will not fit, we need to subtract the number of robots that can be stored from the total number of robots made.
    820 - 684 = <<820-684=136>>136 robots will not fit and remain outside of the storage units.
    ### Answer: 136

Expected answer: 136

Correct? Yes

🔗 Follow-up

Problem: In the same factory, another production run is completed, this time manufacturing a total of 820 upgraded robots. However, the storage units for these new models can only hold 625 robots each. If the robots are evenly stored, how many upgraded robots will not fit and remain outside the storage units now?

Gemma 2B:

     Reasoning: The factory can store 625 robots in one storage unit. To find out how many robots will not fit, we need to subtract the number of robots that can be stored from the total number of robots made.
    820 - 625 = <<820-625=195>>195 robots will not fit and remain outside of the storage units.
    ### Answer: 195

Expected answer: 195

Correct? Yes

🔗 Problem

Problem: A cloud changes its shape by reducing its water droplets. Initially, there were 516 droplets in the cloud. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?

Gemma 2B:

     Reasoning: The cloud loses water droplets in cycles of 289. To find out how many droplets are left after the final cycle, we need to determine how many complete cycles of 289 droplets can be subtracted from the initial 516 droplets.
    516 - 289 = <<516-289=227>>227 droplets left after the first cycle.
    Since 227 is less than 289, the cloud will be dry after the first cycle, and no droplets will be left.
    ### Answer: 0

Expected answer: 227

Correct? No

🔗 Problem

Problem: A transport company needs to load 330 boxes into trucks. Each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded?

Gemma 2B:

     Reasoning: The company can fill 330/4 = <<330/4=82.5>>82 trucks completely.
    Since each truck can only hold 4 boxes, the company can only load 82*4 = <<82*4=328>>328 boxes.
    Therefore, 330-328 = <<330-328=2>>2 boxes will be left unloaded.
    ### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: The transport company now needs to load a new batch of 274 boxes into trucks. Again, each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded this time?

Gemma 2B:

     Reasoning: The company can fill 274/4 = <<274/4=68.5>>68 trucks completely.
    Since each truck can only hold 4 boxes, the company can only load 68*4 = <<68*4=272>>272 boxes.
    Therefore, 274-272 = <<274-272=2>>2 boxes will be left unloaded.
    ### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: A farmer harvested 649 potatoes this season. He decides to pack them into crates each containing 183 potatoes. How many potatoes will be left after all crates are filled to their maximum capacity?

Gemma 2B:

     Reasoning: The farmer can fill 649/183 = <<649/183=3.546448087431694>>3 crates to their maximum capacity.
    The farmer will have 649 - 3*183 = <<649-3*183=100>>100 potatoes left.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Follow-up

Problem: The farmer realized that he actually only harvested 238 potatoes this season instead of 649. If he still packs them into crates each holding 183 potatoes, how many potatoes will be left after all crates are filled to their maximum capacity?

Gemma 2B:

     Reasoning: The farmer can fill 238/183 = <<238/183=1.3005464480874316>>1 crate to its maximum capacity.
    The farmer will have 238 - 1*183 = <<238-1*183=55>>55 potatoes left.
    ### Answer: 55

Expected answer: 55

Correct? Yes

🔗 Problem

Problem: A t-shirt company has a batch of 258 shirts in production. Each box can pack 67 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?

Gemma 2B:

     Reasoning: The number of boxes needed to pack all the shirts is 258/67 = <<258/67=3.8507462686567164>>3.8507462686567164.
    Since we can't have a fraction of a box, we round up to the nearest whole number, which is 4.
    The total number of shirts that can be packed in 4 boxes is 4*67 = <<4*67=268>>268.
    Therefore, the number of shirts left outside the boxes is 268-258 = <<268-258=10>>10.
    ### Answer: 10

Expected answer: 57

Correct? No

🔗 Problem

Problem: On a pirate ship, there are 995 gold coins that need to be evenly divided among the 267 pirates. If they split the gold up as evenly as possible, how many gold coins will be left over?

Gemma 2B:

     Reasoning: 995 divided by 267 is 3 with a remainder of 194.
    ### Answer: 194

Expected answer: 194

Correct? Yes

🔗 Problem

Problem: There are 776 snails all lined up in a row. If you group them in bunches of 375 snails, how many snails will be left in the final group?

Gemma 2B:

     Reasoning: 776 divided by 375 is 2 with a remainder of 26.
    ### Answer: 26

Expected answer: 26

Correct? Yes

🔗 Follow-up

Problem: Originally, you had grouped the snails in bunches of 375 snails each. Now, think about what would happen if each bunch had 18 snails instead. How many snails would be left in the final group then?

Gemma 2B:

     Reasoning: 776 divided by 18 is 43 with a remainder of 2.
    ### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: A pillow factory produces 589 pillows per day. They package these pillows in boxes, and each box holds 198 pillows. If they pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?

Gemma 2B:

     Reasoning: The factory can pack 589/198 = <<589/198=2.9747474747474747>>2.9747474747474747 boxes, which is approximately 2 full boxes.
    The number of pillows in the full boxes is 2*198 = <<2*198=396>>396 pillows.
    The number of pillows left outside the boxes is 589-396 = <<589-396=193>>193 pillows.
    ### Answer: 193

Expected answer: 193

Correct? Yes

🔗 Follow-up

Problem: The pillow factory has made an adjustment to the packaging process and recently upgraded their boxes so that each can now hold 810 pillows. If they still produce 589 pillows per day and pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?

Gemma 2B:

     Reasoning: The factory can pack 589/810 = <<589/810=0.7271604938271605>>0.7271604938271605 boxes, which is approximately 0 full boxes.
    The number of pillows in the full boxes is 0*810 = <<0*810=0>>0 pillows.
    The number of pillows left outside the boxes is 589-0 = <<589-0=589>>589 pillows.
    ### Answer: 589

Expected answer: 589

Correct? Yes

🔗 Problem

Problem: A jewelry maker has 633 beads. If she uses beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Gemma 2B:

     Reasoning: The jewelry maker can make 633/30 = <<633/30=21.1>>21 necklaces with 3 beads left over.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker found an additional box of beads in her storage, increasing her total number of beads to 588. Now, if she uses these beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Gemma 2B:

     Reasoning: The jewelry maker can make 588/30 = <<588/30=19.6>>19 necklaces with 18 beads left over.
    ### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Problem

Problem: John has collected 365 coins. He decided to put equal numbers of them in his 140 wallets. However, he found out he would still have some coins left after evenly distributing them into these wallets. How many coins will John have left?

Gemma 2B:

     Reasoning: John can evenly distribute 365 coins into 140 wallets if he puts 2 coins in each wallet, because 140 * 2 = <<140*2=280>>280 coins can be evenly distributed.
    John will have 365 - 280 = <<365-280=85>>85 coins left.
    ### Answer: 85

Expected answer: 85

Correct? Yes

🔗 Follow-up

Problem: Now, suppose John comes across additional coins and his collection increases to 739 coins. He again tries to evenly distribute these coins among his 140 wallets. How many coins will John have left after this distribution?

Gemma 2B:

     Reasoning: John can evenly distribute 739 coins into 140 wallets if he puts 5 coins in each wallet, because 140 * 5 = <<140*5=700>>700 coins can be evenly distributed.
    John will have 739 - 700 = <<739-700=39>>39 coins left.
    ### Answer: 39

Expected answer: 39

Correct? Yes

🔗 Problem

Problem: A sock manufacturer produces 743 socks in a single production run. The socks are packed into cartons, each containing 451 socks. After filling up as many cartons as possible, how many socks are left unpacked?

Gemma 2B:

     Reasoning: The number of full cartons that can be packed is 743/451 = <<743/451=1.647450110864745>>1.647450110864745, which rounds down to 1 full carton.
    The number of socks left unpacked is 743 - 451 = <<743-451=292>>292 socks.
    ### Answer: 292

Expected answer: 292

Correct? Yes

🔗 Follow-up

Problem: Now suppose the sock manufacturer changes their packaging method and each carton contains 179 socks instead of 451 socks. After filling up as many cartons as possible with 743 socks, how many socks are left unpacked?

Gemma 2B:

     Reasoning: The number of full cartons that can be packed is 743/179 = <<743/179=4.150837988826816>>4.150837988826816, which rounds down to 4 full cartons.
    The number of socks left unpacked is 743 - 4*179 = <<743-4*179=139>>139 socks.
    ### Answer: 139

Expected answer: 27

Correct? No

🔗 Problem

Problem: A total of 923 children want to slide down a slide at an amusement park. If 771 children can go down the slide without rest, how many children will be left waiting for their turn?

Gemma 2B:

     Reasoning: 923-771 = <<923-771=152>>152 children will be left waiting for their turn.
    ### Answer: 152

Expected answer: 152

Correct? Yes

🔗 Follow-up

Problem: After the first 771 children go down the slide, another wave of children arrives and now there are 923 children in total waiting again. If 881 children can go down the slide without any break this time, how many children will be left waiting for their turn?

Gemma 2B:

     Reasoning: 923-881 = <<923-881=42>>42 children will be left waiting for their turn.
    ### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Problem

Problem: Superhero Iron Punch has to save 442 people from a collapsing building. He can teleport a maximum of 104 people at a time to safety. After teleporting as many full groups as he can, how many people will be left in the building for his last round of rescue?

Gemma 2B:

     Reasoning: Superhero Iron Punch can teleport 442/104 = <<442/104=4.25>>4 full groups of people to safety.
    There will be 442-4*104 = <<442-4*104=26>>26 people left in the building for his last round of rescue.
    ### Answer: 26

Expected answer: 26

Correct? Yes

🔗 Follow-up

Problem: What if there were actually 512 people in the collapsing building instead of 442? After Superhero Iron Punch teleports as many full groups of 104 people as he can to safety, how many people will be left in the building for his last round of rescue now?

Gemma 2B:

     Reasoning: Superhero Iron Punch can teleport 512/104 = <<512/104=4.923076923076923>>4 full groups of people to safety.
    There will be 512-4*104 = <<512-4*104=96>>96 people left in the building for his last round of rescue.
    ### Answer: 96

Expected answer: 96

Correct? Yes

🔗 Problem

Problem: A card game manufacturer creates a deck of cards with 569 cards. Each card pack has 68 cards. After creating as many packs as possible, how many cards will the manufacturer have left over?

Gemma 2B:

     Reasoning: The manufacturer can create 569/68 = <<569/68=8.367647058823529>>8.367647058823529 packs of cards.
    Since the manufacturer can't create a fraction of a pack, they can only create 8 packs.
    The manufacturer will have 569 - 8*68 = <<569-8*68=57>>57 cards left over.
    ### Answer: 57

Expected answer: 25

Correct? No

🔗 Problem

Problem: A stationery store received a shipment of 842 erasers. The store owner wants to display them in boxes, with each box containing 719 erasers. After filling as many boxes as possible, how many erasers will be left over?

Gemma 2B:

     Reasoning: To find the number of erasers left over, we need to divide the total number of erasers by the number of erasers in each box and find the remainder.
    842 ÷ 719 = 1 remainder 123
    Therefore, there will be 123 erasers left over after filling as many boxes as possible.
    ### Answer: 123

Expected answer: 123

Correct? Yes

🔗 Follow-up

Problem: Suppose the stationery store owner later decided to display the erasers in smaller boxes, with each box containing 420 erasers instead. After filling as many boxes as possible, how many erasers will be left over now?

Gemma 2B:

     Reasoning: To find the number of erasers left over, we need to divide the total number of erasers by the number of erasers in each box and find the remainder.
    842 ÷ 420 = 2 remainder 2
    Therefore, there will be 2 erasers left over after filling as many boxes as possible.
    ### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: A farmer harvested 461 carrots from his garden. He packs them into boxes, each box can hold up to 244 carrots. After packing as many full boxes as possible, how many carrots will be left unpacked?

Gemma 2B:

     Reasoning: The farmer can pack 461/244 = <<461/244=1.889344262295082>>1.889344262295082 boxes, which is approximately 1 full box.
    The farmer can pack 1*244 = <<1*244=244>>244 carrots into the full box.
    The farmer will have 461-244 = <<461-244=217>>217 carrots left unpacked.
    ### Answer: 217

Expected answer: 217

Correct? Yes

🔗 Follow-up

Problem: The farmer found out that he had initially miscounted and he actually only harvested 11 carrots. After he tries to pack these into the boxes which each can hold up to 244 carrots, how many carrots will be left unpacked now?

Gemma 2B:

     Reasoning: The farmer can pack 11/244 = <<11/244=0.045081967213114755>>0.045081967213114755 boxes, which is approximately 0 full boxes.
    The farmer can pack 0*244 = <<0*244=0>>0 carrots into the full box.
    The farmer will have 11-0 = <<11-0=11>>11 carrots left unpacked.
    ### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Problem

Problem: A penguin scientist counts 309 penguins in a colony. She decides to tag them in groups of 293 for easier tracking. How many penguins will be in the final, possibly incomplete, group?

Gemma 2B:

     Reasoning: The scientist can tag 309/293 = <<309/293=1.0545999999999999>>1.0545999999999999 groups of penguins. Since she can't tag a fraction of a group, she can only tag 1 complete group of 293 penguins. Therefore, the final, possibly incomplete, group will have 309-293 = <<309-293=16>>16 penguins.
    ### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Follow-up

Problem: The penguin scientist realizes she made a mistake and there were actually only 262 penguins in each group. How many penguins will be in the final, possibly incomplete, group now?

Gemma 2B:

     Reasoning: The scientist can now tag 309/262 = <<309/262=1.1793893129770992>>1.1793893129770992 groups of penguins. Since she can't tag a fraction of a group, she can only tag 1 complete group of 262 penguins. Therefore, the final, possibly incomplete, group will have 309-262 = <<309-262=47>>47 penguins.
    ### Answer: 47

Expected answer: 47

Correct? Yes

🔗 Problem

Problem: A sandwich shop has 580 slices of bread. They use 18 slices of bread for each sandwich-making batch. After using up the bread in these batches, how many slices will they have left?

Gemma 2B:

     Reasoning: The shop can make 580/18 = <<580/18=32.22222222222222>>32.22222222222222 batches of sandwiches.
    Since they can't make a fraction of a batch, they can only make 32 batches of sandwiches.
    They will have 580 - (32*18) = <<580-(32*18)=16>>16 slices of bread left.
    ### Answer: 16

Expected answer: 4

Correct? No

🔗 Problem

Problem: A tailor has 925 meters of fabric. The tailor uses 529 meters of fabric to make each dress. If the tailor uses the fabric evenly for each dress, how many meters of fabric will be left over after completing the dresses?

Gemma 2B:

     Reasoning: The tailor uses 529 meters of fabric for each dress, so the number of dresses that can be made is 925/529 = <<925/529=1.7485822306238186>>1.7485822306238186 dresses.
    Since the tailor cannot make a fraction of a dress, the tailor can make 1 dress.
    The amount of fabric left over is 925 - 529 = <<925-529=396>>396 meters.
    ### Answer: 396

Expected answer: 396

Correct? Yes

🔗 Follow-up

Problem: After making some dresses, the tailor now only has 62 meters of fabric left. If the tailor continues to use 529 meters of fabric to make each dress, how many meters of fabric will be left over after making the dresses?

Gemma 2B:

     Reasoning: The tailor can make 62/529 = <<62/529=0.1171644612476373>>0.1171644612476373 dresses.
    Since the tailor cannot make a fraction of a dress, the tailor can make 0 dresses.
    The amount of fabric left over is 62 meters.
    ### Answer: 62

Expected answer: 62

Correct? Yes

🔗 Problem

Problem: There are 976 tourists wanting to explore a castle. Each tour group throughout the day accommodates up to 530 people. After all the groups have taken off, how many tourists will be left for the last group of the day?

Gemma 2B:

     Reasoning: The number of tourists left for the last group is 976-530 = <<976-530=446>>446.
    ### Answer: 446

Expected answer: 446

Correct? Yes

🔗 Follow-up

Problem: What would happen if the number of tourists wanting to explore the castle was still 976, but this time each group could accommodate up to 726 people? How many tourists would be left for the last group of the day now?

Gemma 2B:

     Reasoning: The number of tourists left for the last group is 976-726 = <<976-726=250>>250.
    ### Answer: 250

Expected answer: 250

Correct? Yes