🔗 Problem

Problem: A full-grown giraffe has an average height of 40.4 feet. If a baby giraffe is 7.34 feet shorter than the full-grown giraffe, then how tall is the baby giraffe?

InternLM-Math Base 7B:

     Reasoning: 40.4-7.34= <<40.4-7.34=33.06>>33.06
    ### Answer: 33.06

Expected answer: 33.0600000000000

Correct? Yes

🔗 Follow-up

Problem: Given the previous scenario but this time, let's say that the full-grown giraffe has a different height of 78 feet. If a baby giraffe is still 7.34 feet shorter than this full-grown giraffe, then how tall is the baby giraffe now?

InternLM-Math Base 7B:

      Reasoning: 78-7.34= <<78-7.34=70.66>>70.66
    ### Answer: 70.66

Expected answer: 70.6600000000000

Correct? Yes

🔗 Problem

Problem: A scooter was initially priced at $59.9 but is now on sale for $39.3. How much is the discount on the scooter?

InternLM-Math Base 7B:

     Reasoning: The discount is 59.9-39.3=<<59.9-39.3=20.6>>20.6.
    ### Answer: 20.6

Expected answer: 20.6000000000000

Correct? Yes

🔗 Follow-up

Problem: The scooter store decided to multiply the discount you received, $j, by 15.1 to determine how much they'd donate to a local charity based on your purchase. How much money would be donated to the charity as a result of your scooter purchase?

InternLM-Math Base 7B:

      Reasoning: The amount donated to the charity is 15.1 ⋅ j=<<15.1⋅j=20.6>>20.6.
    ### Answer: 20.6

Expected answer: 311.060000000000

Correct? No

🔗 Follow-up

Problem: If instead the scooter was initially priced at $66 before being discounted to $39.3, how much would be the discount on the scooter?

InternLM-Math Base 7B:

      Reasoning: The discount is 66-39.3=<<66-39.3=26.7>>26.7.
    ### Answer: 26.7

Expected answer: 26.7000000000000

Correct? Yes

🔗 Problem

Problem: The length of a slide was initially 71.36 meters. However, due to safety concerns, officials reduced the length by 50.0 meters. What's the new length of the slide?

InternLM-Math Base 7B:

     Reasoning: 71.36-50.0 = <<71.36-50.0=21.36>>21.36
    ### Answer: 21.36

Expected answer: 21.3600000000000

Correct? Yes

🔗 Follow-up

Problem: In a different playground, there was also a slide that was initially 71.36 meters long. However, safety concerns caused the officials to reduce the length by 24 meters instead of the original 50.0 meters. What is the new length of this slide?

InternLM-Math Base 7B:

      Reasoning: 71.36-24 = <<71.36-24=47.36>>47.36
    ### Answer: 47.36

Expected answer: 47.3600000000000

Correct? Yes

🔗 Problem

Problem: A farmer collects a certain weight of tomatoes from his farm. The first day he collects 86.7 kg and the second day he collects 57.19 kg. What is the total weight of the tomatoes he collected over the two days?

InternLM-Math Base 7B:

     86.7+57.19 = <<86.7+57.19=144.89>>144.89
    ### Answer: 144.89

Expected answer: 143.890000000000

Correct? No

🔗 Problem

Problem: A farmer sold a total of 111.94 kilograms of tomatoes. If each batch he sold weighs roughly 2.9 kilograms, how many batches of tomatoes did he sell?

InternLM-Math Base 7B:

     Reasoning: 111.94/2.9 = <<111.94/2.9=38.5>>38.5
    The farmer sold 38.5 batches of tomatoes.
    ### Answer: 38.5

Expected answer: 38.6000000000000

Correct? Yes

🔗 Follow-up

Problem: Following his earlier sales, the farmer sold an additional 4.8 batches of tomatoes. Including the new sales, how many total batches of tomatoes has the farmer sold now?

InternLM-Math Base 7B:

     38.5+4.8 = <<38.5+4.8=43.3>>43.3
    The farmer has sold 43.3 total batches of tomatoes.

Expected answer: 43.4000000000000

Correct? Yes

🔗 Follow-up

Problem: After recalculating, it turns out the farmer had actually sold 83 kilograms of tomatoes, not 111.94 kilograms, still in batches of 2.9 kilograms each. How many batches of tomatoes did he actually sell?

InternLM-Math Base 7B:

      Reasoning: 83/2.9 = <<83/2.9=28.6206897>>28.6
    The farmer sold 28.6 batches of tomatoes.
    ### Answer: 28.6

Expected answer: 28.6206896551724

Correct? Yes

🔗 Problem

Problem: A skirt was originally priced at $75.0 but it is now on sale and its new price is $37.5 less than the original price. What is the sale price of the skirt?

InternLM-Math Base 7B:

     Reasoning: The sale price of the skirt is 75.0-37.5 = <<75.0-37.5=37.5>>$37.5.
    ### Answer: 37.5

Expected answer: 37.5000000000000

Correct? Yes

🔗 Follow-up

Problem: Instead of the original price being $75.0, assume that the original price of the skirt was $49. How much would the skirt cost after the first discount of $37.5?

InternLM-Math Base 7B:

      Reasoning: The new price of the skirt is 49.0-37.5 = <<49.0-37.5=11.5>>$11.5.
    ### Answer: 11.5

Expected answer: 11.5000000000000

Correct? Yes

🔗 Problem

Problem: On a farm, there are 35.9 acres of wheat fields and 11.5 acres of corn fields. What is the total acreage of wheat and corn fields on the farm?

InternLM-Math Base 7B:

     Reasoning: 35.9+11.5 = <<35.9+11.5=47.4>>47.4
    ### Answer: 47.4

Expected answer: 47.4000000000000

Correct? Yes

🔗 Follow-up

Problem: In addition to the existing wheat and corn fields, the farm has a newly acquired barley field that spans 7.16 acres. What is the total acreage of wheat, corn, and barley fields altogether on the farm now?

InternLM-Math Base 7B:

      Reasoning: 7.16+47.4 = <<7.16+47.4=54.6>>54.6
    ### Answer: 54.6

Expected answer: 54.5600000000000

Correct? Yes

🔗 Follow-up

Problem: Suppose instead of the 35.9 acres of wheat in the original calculation, the farm actually has 93 acres of wheat fields. Taking the updated acreage of wheat fields into account and keeping the 11.5 acres of corn fields the same, what would then be the total acreage of wheat and corn fields on the farm?

InternLM-Math Base 7B:

      Reasoning: 93+11.5 = <<93+11.5=104.5>>104.5
    ### Answer: 104.5

Expected answer: 104.500000000000

Correct? Yes

🔗 Problem

Problem: A tank contains 540.38 liters of water, which is divided between 65.9 buckets. Find out how many liters of water is in each bucket?

InternLM-Math Base 7B:

     Reasoning: 540.38/65.9 = <<540.38/65.9=8.16>>8.16 liters of water is in each bucket.
    ### Answer: 8.16

Expected answer: 8.20000000000000

Correct? No

🔗 Problem

Problem: A TV is sold for $48.21 per month for 35.5 months. What is the total cost of the TV?

InternLM-Math Base 7B:

     Reasoning: The cost of the TV is 35.5 × 48.21 = <<35.5 × 48.21=1720.255>>\$1720.255.
    ### Answer: 1720.255

Expected answer: 1711.45500000000

Correct? No

🔗 Problem

Problem: A UFO was spotted moving at a speed of 94.83 miles per hour, and then it increased its speed by an additional 2.63 miles per hour. What was the new speed of the UFO?

InternLM-Math Base 7B:

     Reasoning: The new speed of the UFO was 94.83+2.63 = <<94.83+2.63=97.46>>97.46 miles per hour.
    ### Answer: 97.46

Expected answer: 97.4600000000000

Correct? Yes

🔗 Follow-up

Problem: After increasing its speed, the UFO maintained its new speed for 52.9 hours. How many miles did the UFO travel at its new speed?

InternLM-Math Base 7B:

     Reasoning: The UFO traveled 97.46*52.9 = <<97.46*52.9=5,149.434>>5,149.434 miles at its new speed.
    ### Answer: 5,149.434

Expected answer: 5155.63400000000

Correct? No

🔗 Follow-up

Problem: Suppose that the UFO was originally moving at a speed of 94.83 mph, but then it increased its speed by 72 mph instead of 2.63 mph. What would its new speed be now?

InternLM-Math Base 7B:

      Reasoning: The new speed of the UFO would be 94.83+72 = <<94.83+72=166.83>>166.83 miles per hour.
    ### Answer: 166.83

Expected answer: 166.830000000000

Correct? Yes

🔗 Problem

Problem: If a monkey can swing 80.48 meters in one second and it continues to swing at this speed for 73.9 seconds, how far will the monkey have swung in total?

InternLM-Math Base 7B:

     Reasoning: 80.48m/1s*73.9s = <<80.48m/1s*73.9s=5950m>>5950m
    ### Answer: 5950m

Expected answer: 5947.47200000000

Correct? No

🔗 Problem

Problem: A strong wind travels a total of 2250.3 km over a period of 57.7 hours. How many kilometers does the wind cover in each hour?

InternLM-Math Base 7B:

     Reasoning: The wind covers 2250.3/57.7 = <<2250.3/57.7=39.1>>39.1 kilometers in each hour.
    ### Answer: 39.1

Expected answer: 39.0000000000000

Correct? No

🔗 Problem

Problem: A Penguin swam 95.34 kilometers to the east and then swam another 41.6 kilometers in the same direction. What is the total distance that the Penguin swam?

InternLM-Math Base 7B:

     Reasoning: The Penguin swam 95.34+41.6 = <<95.34+41.6=136.94>>136.94 kilometers.
    ### Answer: 136.94

Expected answer: 136.940000000000

Correct? Yes

🔗 Follow-up

Problem: After swimming 95.34 kilometers to the east and another 41.6 kilometers in the same direction, the Penguin continued its journey and swam an additional 97.85 kilometers. What is the total distance that the Penguin swam?

InternLM-Math Base 7B:

      Reasoning: The Penguin swam 95.34+41.6+97.85 = <<95.34+41.6+97.85=234.79>>234.79 kilometers.
    ### Answer: 234.79

Expected answer: 234.790000000000

Correct? Yes

🔗 Follow-up

Problem: Suppose instead of swimming 95.34 kilometers to the east initially, the penguin only swam 12 kilometers before continuing for another 41.6 kilometers in the same direction. How much distance would the penguin have covered in this scenario?

InternLM-Math Base 7B:

      Reasoning: The Penguin swam 12+41.6 = <<12+41.6=53.6>>53.6 kilometers.
    ### Answer: 53.6

Expected answer: 53.6000000000000

Correct? Yes

🔗 Problem

Problem: A park installs a new slide that is 86.42 feet long. After it is extended by another 9.86 feet, how long is the slide then?

InternLM-Math Base 7B:

Expected answer: 96.2800000000000

Correct? No

🔗 Problem

Problem: Throughout the month, an ice cream shop sold 1878.8 gallons of ice cream in 44.0 equally profitable days. How many gallons of ice cream did they sell each day?

InternLM-Math Base 7B:

     Reasoning: 1878.8/44.0 = <<1878.8/44.0=42.5>>42.5
    The ice cream shop sold 42.5 gallons of ice cream each day.

Expected answer: 42.7000000000000

Correct? Yes

🔗 Follow-up

Problem: Considering the ice cream shop you previously calculated about. If the total amount of ice cream sold (1878.8 gallons) was actually spread over 87 days instead of 44.0 days, how many gallons of ice cream would have been sold each day?

InternLM-Math Base 7B:

      Reasoning: 1878.8/87.0 = <<1878.8/87.0=21.5>>21.5
    The ice cream shop would have sold 21.5 gallons of ice cream each day.

Expected answer: 21.5954022988506

Correct? Yes

🔗 Problem

Problem: A book has a total character count of 1540.93 characters and each word takes up about 22.3 characters. How many words should there be in the book?

InternLM-Math Base 7B:

     Reasoning: 1540.93/22.3 = <<1540.93/22.3=68.8>>68.8. The book should have 68.8 words.

Expected answer: 69.1000000000000

Correct? No

🔗 Problem

Problem: A pair of ice skates costs $81.66, and you decide to buy a set of skate guards for an additional $54.6. What is the total cost of the ice skates combined with the skate guards?

InternLM-Math Base 7B:

     Reasoning: The cost of the skates is $<<81.66>>81.66, and the cost of the skate guards is $<<54.6>>54.6. The total cost of the skates and the skate guards is $<<81.66+54.6=136.26>>81.66+54.6=136.26.
    ### Answer: 136.26

Expected answer: 136.260000000000

Correct? Yes

🔗 Follow-up

Problem: After buying the ice skates and skate guards, you decide to take advantage of a special offer that gives you a discount of $46.83. What would be your new total cost after this discount is applied?

InternLM-Math Base 7B:

      Reasoning: The discount is $<<46.83>>46.83. The new total cost is $<<136.26-46.83=89.43>>136.26-46.83=89.43.
    ### Answer: 89.43

Expected answer: 89.4300000000000

Correct? Yes

🔗 Follow-up

Problem: Suppose instead of the original pair of ice skates costing $81.66, you found a different pair on sale for only $25. If you still buy the skate guards for an additional $54.6, what would be the total cost of these discounted ice skates combined with the skate guards?

InternLM-Math Base 7B:

      Reasoning: The cost of the skates is $<<25>>25, and the cost of the skate guards is $<<54.6>>54.6. The total cost of the skates and the skate guards is $<<25+54.6=79.6>>25+54.6=79.6.
    ### Answer: 79.6

Expected answer: 79.6000000000000

Correct? Yes

🔗 Problem

Problem: A farmer harvests 36.0 kilograms of strawberries from his strawberry farm. After selling some, he has 22.6 kilograms left. How many kilograms of strawberries did he sell?

InternLM-Math Base 7B:

     Reasoning: The farmer sold 36.0-22.6 = <<36.0-22.6=13.4>>13.4 kilograms of strawberries.
    ### Answer: 13.4

Expected answer: 13.4000000000000

Correct? Yes

🔗 Follow-up

Problem: If originally, the farmer had harvested 36.0 kilograms of strawberries and now instead, he sold 12 kilograms of strawberries. How many kilograms of strawberries does he have left now?

InternLM-Math Base 7B:

     Reasoning: The farmer has 36.0-12 = <<36.0-12=24.0>>24.0 kilograms of strawberries left.
    ### Answer: 24.0

Expected answer: 24.0000000000000

Correct? Yes

🔗 Problem

Problem: A pillow originally costs $22.88 but is on sale. After the discount, the price is reduced to $14.2. What is the amount of the discount?

InternLM-Math Base 7B:

     Reasoning: The amount of the discount is $14.2 - $22.88 = $<<14.2-22.88=8.68>>8.68.
    ### Answer: 8.68

Expected answer: 8.68000000000000

Correct? Yes

🔗 Follow-up

Problem: Consider the same scenario but with a different original cost. If the pillow originally cost $72 instead of $22.88 and its price is reduced to $14.2 after a sale, what would be the amount of the discount now?

InternLM-Math Base 7B:

      Reasoning: The amount of the discount is $14.2 - $72 = $<<14.2-72=-57.8>>-57.8.
    ### Answer: -57.8

Expected answer: 57.8000000000000

Correct? Yes

🔗 Problem

Problem: A bunch of bananas originally weighed 77.8 grams. After removing the peel, which weighed 7.0 grams, what is the new weight of the bananas?

InternLM-Math Base 7B:

     Reasoning: The new weight of the bananas is 77.8-7.0=<<77.8-7.0=70.8>>70.8 grams.
    ### Answer: 70.8

Expected answer: 70.8000000000000

Correct? Yes

🔗 Follow-up

Problem: In the initial situation, the bunch of bananas weighed 79 grams instead of 77.8 grams. After removing the peel, which weighed 7.0 grams as before, what would be the new weight of the bananas this time?

InternLM-Math Base 7B:

      Reasoning: The new weight of the bananas is 79-7.0=<<79-7.0=72>>72 grams.
    ### Answer: 72

Expected answer: 72.0000000000000

Correct? Yes

🔗 Problem

Problem: Each page in a book has 15.18 words and the book has a total of 24.0 pages. How many words does the book contain in total?

InternLM-Math Base 7B:

     Reasoning: 15.18 × 24.0 = <<15.18 × 24.0= 360.3>>360.3
    ### Answer: 360.3

Expected answer: 364.320000000000

Correct? No

🔗 Problem

Problem: A camera company spent $530.12 to produce 5.8 identical cameras. How much does the company spend to manufacture each camera?

InternLM-Math Base 7B:

     Reasoning: 5.8/5.8 = 1. 530.12/1 = 530.12. 530.12/5.8 = <<530.12/5.8=90.8>>90.8. 90.8/5.8 = 15.8. 15.8/5.8 = 2.7. 2.7/5.8 = 0.5. 0.5/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 = 0.0. 0.0/5.8 =

Expected answer: 91.4000000000000

Correct? No

🔗 Problem

Problem: A toy car model is 22.64 cm long. If one centimeter represents an actual length of 86.4 cm on the real car, what is the length of the actual car in centimeters?

InternLM-Math Base 7B:

     Reasoning: 1/86.4 = 0.0115
    22.64 ⋅ 0.0115 = <<22.64⋅0.0115=0.2599>>0.2599
    ### Answer: 0.2599

Expected answer: 1956.09600000000

Correct? No

🔗 Problem

Problem: Two kids are playing in a sandbox. The first kid pours 43.21 pounds of sand on their sandcastle, and the second kid adds 19.57 pounds of sand. How much does the sand on the sandcastle weigh in total?

InternLM-Math Base 7B:

     Reasoning: The first kid pours 43.21+19.57 = <<43.21+19.57=62.78>>62.78 pounds of sand on the sandcastle.
    The sand on the sandcastle weighs 62.78 pounds in total.

Expected answer: 62.7800000000000

Correct? Yes

🔗 Follow-up

Problem: After the kids added sand to their sandcastle, they decided to make it even bigger. They multiplied the original weight of the sand by 46.6. What is the total weight of the sand in the sandcastle after their addition?

InternLM-Math Base 7B:

      Reasoning: The total weight of the sand in the sandcastle is 62.78*46.6 = <<62.78*46.6=2.91>2.91>9.1>91>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91.0>91

Expected answer: 2925.54800000000

Correct? No

🔗 Problem

Problem: An online sock retailer has just checked their inventory and found that they have a total of 5600.48 meters of materials left. If it takes 98.6 meters of material to make one pair of socks, how many pairs of socks can they make with the amount of material they have left?

InternLM-Math Base 7B:

     Reasoning: 5600.48/98.6 = <<5600.48/98.6=57.02018>>57.02018
    The retailer can make 57.02018 = <<57.02018=57>>57 pairs of socks with the amount of material they have left.
    ### Answer: 57

Expected answer: 56.8000000000000

Correct? No

🔗 Problem

Problem: The distance from the Earth to the Sun changes over the course of the year. On a particular day, an observatory measures the distance to be 56.14 million kilometers. They notice an increase in the following day by 15.25 million kilometers. How far is the Earth from the Sun on the second day in millions of kilometers?

InternLM-Math Base 7B:

Expected answer: 71.3900000000000

Correct? No

🔗 Problem

Problem: The temperature in the cloud layer dropped from 92.5 degrees Fahrenheit to 57.07 degrees Fahrenheit. How much did the temperature change?

InternLM-Math Base 7B:

     Reasoning: 57.07-92.5 = <<57.07-92.5=-35.43>>-35.43
    ### Answer: -35.43

Expected answer: 35.4300000000000

Correct? Yes

🔗 Follow-up

Problem: Suppose that for each degree drop in temperature, the cloud loses 97.29 liters of water vapor. How much water vapor would the cloud lose given the temperature change from the previous question?

InternLM-Math Base 7B:

      Reasoning: 57.07-92.5 = <<57.07-92.5=-35.43>>-35.43
    -35.43*97.29 = <<-35.43*97.29=-3432.8477>>-3432.8477
    ### Answer: -3432.8477

Expected answer: 3446.98470000000

Correct? No

🔗 Follow-up

Problem: Suppose that instead of dropping from 92.5 degrees Fahrenheit, the temperature in the cloud layer had dropped from 87 degrees Fahrenheit. How much would the temperature change be in this situation?

InternLM-Math Base 7B:

      Reasoning: 57.07-87 = <<57.07-87=-30.93>>-30.93
    ### Answer: -30.93

Expected answer: 29.9300000000000

Correct? No

🔗 Problem

Problem: A Giraffe walks 42.53 miles to the north in the morning then it walks another 28.9 miles to the east in the afternoon. What is the total distance the Giraffe walked in miles?

InternLM-Math Base 7B:

     Reasoning: The Giraffe walked 42.53+28.9=<<42.53+28.9=71.43>>71.43 miles in total.
    ### Answer: 71.43

Expected answer: 71.4300000000000

Correct? Yes

🔗 Follow-up

Problem: After the giraffe walks 42.53 miles to the north in the morning and 28.9 miles to the east in the afternoon, it then retraces 60.5 miles back towards its starting point. How many miles is the giraffe from its starting point now?

InternLM-Math Base 7B:

     Reasoning: The giraffe is 60.5-60.5=<<60.5-60.5=0>>0 miles from its starting point.
    ### Answer: 0

Expected answer: 10.9300000000000

Correct? No

🔗 Follow-up

Problem: If the giraffe had walked 42.53 miles to the north in the morning and then 57 miles to the east in the afternoon instead of 28.9, how many miles in total would the giraffe have walked?

InternLM-Math Base 7B:

      Reasoning: The giraffe would have walked 42.53+57=<<42.53+57=99.53>>99.53 miles in total.
    ### Answer: 99.53

Expected answer: 99.5300000000000

Correct? Yes

🔗 Problem

Problem: In a children's sandbox, there are 90.74 kilograms of sand on one side and 95.27 kilograms of sand on the other side. What is the total weight of sand in the sandbox?

InternLM-Math Base 7B:

     Reasoning: The total weight of sand in the sandbox is 90.74+95.27 = <<90.74+95.27=185.01>>185.01 kilograms.
    ### Answer: 185.01

Expected answer: 186.010000000000

Correct? No

🔗 Problem

Problem: A train ticket costs $14.15 and the cost of a meal on the train is $95.07. How much does it cost in total to buy the ticket and eat the meal?

InternLM-Math Base 7B:

     Reasoning: 14.15+95.07 = <<14.15+95.07=109.22>>109.22
    ### Answer: 109.22

Expected answer: 109.220000000000

Correct? Yes

🔗 Follow-up

Problem: A train ticket costs $14.15 and the cost of a meal on the train is $95.07. After your meal, you decide to buy a cool souvenir train mug for $4.02. How much would it cost in total for the train ticket, meal, and souvenir mug?

InternLM-Math Base 7B:

      Reasoning: 14.15+95.07+4.02 = <<14.15+95.07+4.02=113.24>>113.24
    ### Answer: 113.24

Expected answer: 113.240000000000

Correct? Yes

🔗 Follow-up

Problem: The train ticket originally costs $14.15, and in this follow-up question, we're considering what happens if the meal cost is changed to $59. Now, how much is the total cost for the ticket and the meal?

InternLM-Math Base 7B:

      Reasoning: 14.15+59.00 = <<14.15+59.00=73.15>>73.15
    ### Answer: 73.15

Expected answer: 73.1500000000000

Correct? Yes

🔗 Problem

Problem: One of your friends spends 56.1 dollars every day. In 91.13 days, how much total will your friend have spent?

InternLM-Math Base 7B:

     Reasoning: 56.1*91.13 = <<56.1*91.13=5100.933>>5100.933
    ### Answer: 5100.933

Expected answer: 5112.39300000000

Correct? No

🔗 Problem

Problem: Tom wrote 86.7 letters to his friends in one year, and he wrote 17.1 letters to his family throughout the same year. In total, how many letters did Tom write in that year?

InternLM-Math Base 7B:

     Reasoning: Tom wrote 86.7+17.1 = <<86.7+17.1=104>>104 letters in the year.
    ### Answer: 104

Expected answer: 103.800000000000

Correct? No

🔗 Problem

Problem: The average distance from the Earth to the Moon is 44.7 million kilometers. If another celestial body is 16.09 million kilometers closer to Earth than the Moon, what is the average distance from Earth to this celestial body in million kilometers?

InternLM-Math Base 7B:

     Reasoning: The average distance from the Earth to the Moon is 44.7 million kilometers. The other celestial body is 16.09 million kilometers closer to Earth than the Moon. 44.7-16.09 = <<44.7-16.09=28.6>>28.6. The average distance from Earth to the other celestial body is 28.6+16.09 = <<28.6+16.09=44.6>>44.6 million kilometers.
    ### Answer: 44.6

Expected answer: 28.6100000000000

Correct? No

🔗 Problem

Problem: A scientist views a galaxy far away through her binoculars. The distance measured is 4299.12 light years and she views it over 85.3 different scopes. What is the approximate distance in light years that she sees through each scope?

InternLM-Math Base 7B:

Expected answer: 50.4000000000000

Correct? No

🔗 Problem

Problem: A water company has 1774.46 cubic meters of water, which needs to be divided equally into 28.9 storage tanks. How many cubic meters of water will each tank contain?

InternLM-Math Base 7B:

     Reasoning: 1774.46/28.9 = <<1774.46/28.9=61.5>>61.5
    Each tank will contain 61.5 cubic meters of water.

Expected answer: 61.4000000000000

Correct? Yes

🔗 Follow-up

Problem: Originally, the water company decided to divide the 1774.46 cubic meters of water between 28.9 storage tanks. However, it later decides to evenly distribute the water among 46 tanks instead. How many cubic meters of water will each tank contain under this new distribution plan?

InternLM-Math Base 7B:

      Reasoning: 1774.46/46 = <<1774.46/46=38.5>>38.5
    Each tank will contain 38.5 cubic meters of water.

Expected answer: 38.5752173913043

Correct? Yes

🔗 Problem

Problem: A star's observed magnitude brightness is modified by 4.7 units when its intrinsic brightness is 96.46 units. What is the total magnitude brightness of the star when the modifications are added?

InternLM-Math Base 7B:

    Reasoning: 96.46+4.7 = <<96.46+4.7=101.16>>101.16
    ### Answer: 101.16

Expected answer: 101.160000000000

Correct? Yes

🔗 Follow-up

Problem: After the modifications, the star's magnitude brightness is multiplied by a factor of 96.1 due to interference from the earth's atmosphere. What is the value of the star's final observed brightness after being adjusted for atmospheric interference?

InternLM-Math Base 7B:

     Reasoning: 96.1*101.16 = <<96.1*101.16=97.0376>>97.0376
    ### Answer: 97.0376

Expected answer: 9721.47600000000

Correct? No

🔗 Follow-up

Problem: Suppose the star's observed magnitude brightness was modified by 54 units instead of 4.7 units, keeping its intrinsic brightness the same at 96.46 units. What would be the total magnitude brightness of the star then when these modifications are added?

InternLM-Math Base 7B:

     Reasoning: 96.46+54 = <<96.46+54=150.46>>150.46
    ### Answer: 150.46

Expected answer: 150.460000000000

Correct? Yes

🔗 Problem

Problem: A large blanket has a total area of 175.56 square feet and is rectangular. If the length of the blanket is 46.2 feet, what is the width in feet?

InternLM-Math Base 7B:

     Reasoning: 175.56/46.2 = <<175.56/46.2=3.8>>3.8
    The width of the blanket is 3.8 feet.
    ### Answer: 3.8

Expected answer: 3.80000000000000

Correct? Yes

🔗 Follow-up

Problem: If a smaller blanket has a width of 94.35 feet, what would be the total width in feet if you laid the large and small blankets side by side?

InternLM-Math Base 7B:

      Reasoning: 3.8+94.35 = <<3.8+94.35=98.15>>98.15
    The total width in feet is 98.15.

Expected answer: 98.1500000000000

Correct? Yes

🔗 Follow-up

Problem: If the large blanket actually had a total area of 86 square feet instead of 175.56 while keeping the length identical at 46.2 feet, what would be the new width in feet?

InternLM-Math Base 7B:

      Reasoning: 86/46.2 = <<86/46.2=1.8>>1.8
    The width of the blanket is 1.8 feet.
    ### Answer: 1.8

Expected answer: 1.86147186147186

Correct? Yes

🔗 Problem

Problem: A candy store has 23.4 kilos of strawberry flavored candy and decides to add 98.1 kilos of the same flavor. How many kilos of strawberry flavored candy does the store have now?

InternLM-Math Base 7B:

     Reasoning: 23.4+98.1=<<23.4+98.1=121.5>>121.5
    ### Answer: 121.5

Expected answer: 121.500000000000

Correct? Yes

🔗 Problem

Problem: A window maker is creating a custom rectangular glass pane. If the length is 71.4 cm and the width is 54.58 cm, what is the total area of the window pane in cm²?

InternLM-Math Base 7B:

     Reasoning: The total area of the window pane is 71.4 × 54.58 = <<71.4*54.58=3899.172>>3899.172 cm².
    ### Answer: 3899.172

Expected answer: 3897.01200000000

Correct? No

🔗 Problem

Problem: A firefighter uses 37.7 liters of water to extinguish a small fire, then uses additional 85.93 liters to cool down the area, thereby preventing another potential fire. How many liters of water has the firefighter used in total?

InternLM-Math Base 7B:

     Reasoning: The firefighter used 37.7+85.93 = <<37.7+85.93=123.63>>123.63 liters of water in total.
    ### Answer: 123.63

Expected answer: 123.630000000000

Correct? Yes

🔗 Follow-up

Problem: After successfully handling the small fire, the firefighter then moves on to control a medium fire, using an additional 46.61 liters of water. How many liters of water has the firefighter used in total?

InternLM-Math Base 7B:

     Reasoning: The firefighter has used 37.7+46.61 = <<37.7+46.61=84.31>>84.31 liters of water in total.
    ### Answer: 84.31

Expected answer: 170.240000000000

Correct? No

🔗 Follow-up

Problem: Suppose the firefighter initially used 92 liters of water to extinguish the small fire instead of 37.7 liters, but still uses an additional 85.93 liters to cool down the area. How many liters of water has the firefighter used in total now?

InternLM-Math Base 7B:

      Reasoning: The firefighter used 92+85.93 = <<92+85.93=177.93>>177.93 liters of water in total.
    ### Answer: 177.93

Expected answer: 177.930000000000

Correct? Yes

🔗 Problem

Problem: A chocolate factory makes 98.3 pounds of a special kind of chocolate in an hour. In 44.2 hours, how many pounds of chocolate does the factory produce?

InternLM-Math Base 7B:

     Reasoning: 98.3*44.2 = <<98.3*44.2=4343.26>>4343.26
    ### Answer: 4343.26

Expected answer: 4344.86000000000

Correct? No

🔗 Problem

Problem: Over the course of a winter season, a total of 509.39 inches of snowfall was measured. If each snowfall measured 38.3 inches, how many snowfalls were there during the season?

InternLM-Math Base 7B:

     Reasoning: 509.39/38.3 = <<509.39/38.3=13.3>>13.3
    The number of snowfalls is 13.3 rounded to the nearest whole number, 13.
    ### Answer: 13

Expected answer: 13.3000000000000

Correct? Yes

🔗 Follow-up

Problem: Following the last snow season, the weather department is predicting that the upcoming season will have double the number of snowfalls as the previous season. If the previous season had a certain number of snowfalls, each measuring 38.3 inches for a total of 509.39 inches, how many snowfalls are expected in the upcoming winter season?

InternLM-Math Base 7B:

      Reasoning: 2*13.3 = <<2*13.3=26.6>>26.6
    The number of snowfalls is 26.6 rounded to the nearest whole number, 27.
    ### Answer: 27

Expected answer: 26.6000000000000

Correct? No

🔗 Follow-up

Problem: In retrospect, the Met Office revised their measurements for the previous winter season. Instead of a total of 509.39 inches of snowfall, there were only 83 inches, still with each snowfall measuring 38.3 inches. With that in mind, how many snowfalls were there truly last winter season?

InternLM-Math Base 7B:

      Reasoning: 83/38.3 = <<83/38.3=2.1>>2.1
    The number of snowfalls is 2.1 rounded to the nearest whole number, 2.
    ### Answer: 2

Expected answer: 2.16710182767624

Correct? Yes

🔗 Problem

Problem: A clock measures 85.44 cm in overall height. The base of the clock takes up 1.58 cm of this height. How tall is the main body of the clock without the base?

InternLM-Math Base 7B:

     Reasoning: The main body of the clock is 85.44 - 1.58 = <<85.44-1.58=83.86>>83.86 cm tall.
    ### Answer: 83.86

Expected answer: 83.8600000000000

Correct? Yes

🔗 Follow-up

Problem: Following from the previous question, let's consider a smaller clock that initially measures 6 cm in height. If it also has a base of 1.58 cm that is removed, what would be the height of the main body of this smaller clock without the base?

InternLM-Math Base 7B:

      Reasoning: The main body of the clock is 6 - 1.58 = <<6-1.58=4.42>>4.42 cm tall.
    ### Answer: 4.42

Expected answer: 4.42000000000000

Correct? Yes

🔗 Problem

Problem: To make a large batch of hot chocolate, you use 3.91 ounces of cocoa powder per cup. If you are making 12.7 cups of hot chocolate, how much cocoa powder will you need?

InternLM-Math Base 7B:

     Reasoning: 3.91 × 12.7 = <<3.91 × 12.7=49.957>>49.957.

Expected answer: 49.6570000000000

Correct? No

🔗 Problem

Problem: A toy car started with a speed of 98.9 cm/s. After 1 second, its speed reduced to 28.0 cm/s. What was the change in the toy car's speed?

InternLM-Math Base 7B:

     Reasoning: The car's final speed is 28.0 cm/s. The car's initial speed is 98.9 cm/s. The car's change in speed is 98.9 – 28.0 = <<98.9 – 28.0=70.9>>70.9 cm/s.
    ### Answer: 70.9

Expected answer: 70.9000000000000

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous problem, the toy car runs on a battery that drains power proportional to the change in its speed per second. The rate is 24.8 mAh for each cm/s change in speed. How much power would the battery have drained in 1 second due to the speed change?

InternLM-Math Base 7B:

     Reasoning: The battery drained 24.8 ⋅ 70.9 = <<24.8⋅70.9=1750.12>>1750.12 mAh of power in 1 second.
    ### Answer: 1750.12

Expected answer: 1758.32000000000

Correct? No

🔗 Follow-up

Problem: In the previous scenario, if the toy car's speed after 1 second was modified to 29 cm/s instead of 28.0 cm/s, what would be the new change in the toy car's speed?

InternLM-Math Base 7B:

      Reasoning: The car's final speed is 29 cm/s. The car's initial speed is 98.9 cm/s. The car's change in speed is 98.9 – 29 = <<98.9 – 29=69.9>>69.9 cm/s.
    ### Answer: 69.9

Expected answer: 69.9000000000000

Correct? Yes

🔗 Problem

Problem: A turtle travels at a speed of 23.0 km/h. How far will the turtle go in 46.7 hours?

InternLM-Math Base 7B:

    Reasoning: The turtle will go 23.0*46.7 = <<23.0*46.7=1070.1>>1070.1 km in 46.7 hours.
    ### Answer: 1070.1

Expected answer: 1074.10000000000

Correct? No

🔗 Problem

Problem: A lion hunter observes two prides in the savannah. He counts 25.5 lions in one pride and 29.9 lions in the other pride (counting half a lion if the lion is a cub). How many lions (including cubs as half) did the lion hunter count in total?

InternLM-Math Base 7B:

     Reasoning: 25.5+29.9 = <<25.5+29.9=55.4>>55.4
    ### Answer: 55.4

Expected answer: 55.4000000000000

Correct? Yes

🔗 Follow-up

Problem: Following the previous question, the lion hunter then sees a third pride that has a total of 3.72 lions (including cubs as half). How many lions (taking cubs as half each) did the lion hunter count across all three prides?

InternLM-Math Base 7B:

      Reasoning: 3.72+55.4 = <<3.72+55.4=59.12>>59.12
    ### Answer: 59.12

Expected answer: 59.1200000000000

Correct? Yes

🔗 Follow-up

Problem: Following the previous story, what if the lion hunter actually saw 76 lions in the first pride instead of 25.5 that he initially counted? When he then counted the second pride with 29.9 lions (including cubs as half), how many lions (considering cubs as half each) did the lion hunter count in total?

InternLM-Math Base 7B:

      Reasoning: 76+29.9 = <<76+29.9=105.9>>105.9
    ### Answer: 105.9

Expected answer: 105.900000000000

Correct? Yes

🔗 Problem

Problem: A brown bear ate 50.1 pounds of fish in the morning. Then, it ate another 65.7 pounds in the afternoon. How many total pounds of fish did the brown bear consume in one day?

InternLM-Math Base 7B:

     Reasoning: The bear ate 50.1+65.7 = <<50.1+65.7=115.8>>115.8 pounds of fish in one day.
    ### Answer: 115.8

Expected answer: 115.800000000000

Correct? Yes

🔗 Follow-up

Problem: A brown bear ate 50.1 pounds of fish in the morning. Then, it ate another 21 pounds in the afternoon instead of 65.7 pounds. How many total pounds of fish did the brown bear consume in one day now?

InternLM-Math Base 7B:

      Reasoning: The bear ate 50.1+21 = <<50.1+21=71.1>>71.1 pounds of fish in one day.
    ### Answer: 71.1

Expected answer: 71.1000000000000

Correct? Yes

🔗 Problem

Problem: A bakery initially has 62.06 kilograms of flour. After making a batch of cakes, they are left with 51.59 kilograms of flour. How many kilograms of flour were used to make the cakes?

InternLM-Math Base 7B:

     Reasoning: The bakery used 62.06-51.59 = <<62.06-51.59=10.47>>10.47 kilograms of flour to make the cakes.
    ### Answer: 10.47

Expected answer: 10.4700000000000

Correct? Yes

🔗 Follow-up

Problem: After calculating the flour used to make the cakes, suppose this amount is then mixed with 74.2 grams of sugar per kilogram of the flour. How many grams of sugar would be needed in total?

InternLM-Math Base 7B:

      Reasoning: 10.47x74.2 = <<10.47x74.2=777.17>>777.17 grams of sugar would be needed in total.
    ### Answer: 777.17

Expected answer: 776.874000000000

Correct? No

🔗 Follow-up

Problem: Suppose the bakery initially started with 68 kilograms of flour instead of 62.06 kilograms. How many kilograms of flour would have been used to make the cakes then?

InternLM-Math Base 7B:

      Reasoning: The bakery would have used 68-51.59 = <<68-51.59=16.41>>16.41 kilograms of flour to make the cakes.
    ### Answer: 16.41

Expected answer: 16.4100000000000

Correct? Yes

🔗 Problem

Problem: A mermaid has found a sunken treasure chest containing some gold pieces and a pearl. The gold is worth $86.7 and the pearl is worth $11.99. How much is the total worth of the treasure found by the mermaid?

InternLM-Math Base 7B:

     Reasoning: The value of the total treasure is 11.99+86.7 = <<11.99+86.7=98.69>>98.69.

Expected answer: 98.6900000000000

Correct? Yes

🔗 Follow-up

Problem: After adding the value of the gold and the pearl, the mermaid decides to give $28.05 worth of her treasure to her best sea creature friend. How much is the value of the remaining treasures after giving away part of it?

InternLM-Math Base 7B:

      Reasoning: The value of the remaining treasure is 98.69-28.05 = <<98.69-28.05=70.64>>70.64.

Expected answer: 70.6400000000000

Correct? Yes

🔗 Follow-up

Problem: Suppose instead of the gold being worth $86.7, it was actually worth $71. Now how much is the total value of the treasure the mermaid found?

InternLM-Math Base 7B:

      Reasoning: The new value of the total treasure is 11.99+71 = <<11.99+71=82.99>>82.99.

Expected answer: 82.9900000000000

Correct? Yes

🔗 Problem

Problem: An astronaut moves a distance of 85.3 meters from the spaceship and then moves another 85.98 meters further out into space. What is the total distance the astronaut moved away from the spaceship?

InternLM-Math Base 7B:

     Reasoning: The first distance the astronaut moved was 85.3 meters. The next distance the astronaut moved was 85.98 meters. The sum of 85.3+85.98 = <<85.3+85.98=170.28>>170.28.
    ### Answer: 170.28

Expected answer: 171.280000000000

Correct? No

🔗 Problem

Problem: A tent has a rectangular floor with a length of 44.68 feet and a width of 49.75 feet. What is the area of the tent's floor in square feet?

InternLM-Math Base 7B:

     Reasoning: The area of a rectangle is the product of its length and its width. The area of the tent is 44.68*49.75 = <<44.68*49.75=2210.19>>2210.19 square feet.
    ### Answer: 2210.19

Expected answer: 2222.83000000000

Correct? No

🔗 Problem

Problem: A craftsman is making a bracelet which requires 10.7 grams of silver for each charm. If the bracelet needs 4.54 charms, how many grams of silver are needed in total for the charms on the bracelet?

InternLM-Math Base 7B:

     Reasoning: 4.54*10.7 = <<4.54*10.7=48.378>>48.378
    ### Answer: 48.378

Expected answer: 48.5780000000000

Correct? No

🔗 Problem

Problem: A city bus has a capacity of 68.0 passengers. If 10.66 seats are reserved for specific riders, how many seats are available for general riders?

InternLM-Math Base 7B:

     Reasoning: 68.0 - 10.66 = <<68.0-10.66=57.34>>57.34
    ### Answer: 57.34

Expected answer: 57.3400000000000

Correct? Yes

🔗 Follow-up

Problem: From the previous problem, we knew a city bus has a capacity of 68.0 passengers with 10.66 seats reserved for specific riders. Now, suppose there are an additional 73.24 available seats added to the bus after an upgrade. How many total seats are now available for general riders after the upgrade?

InternLM-Math Base 7B:

      Reasoning: 68.0 - 10.66 = <<68.0-10.66=57.34>>57.34
    10.66 + 57.34 = <<10.66+57.34=68.0>>68.0
    10.66 + 57.34 + 73.24 = <<10.66+57.34+73.24=144.24>>144.24
    ### Answer: 144.24

Expected answer: 130.580000000000

Correct? No

🔗 Follow-up

Problem: From the previous problem, a city bus was upgraded to have more seats for general riders. However, now consider that originally, the bus only had a capacity of 28 passengers instead of 68.0, with the same 10.66 seats reserved for specific riders. How many seats would then have been available for general riders before the upgrade?

InternLM-Math Base 7B:

      Reasoning: 28.0 - 10.66 = <<28.0-10.66=17.34>>17.34
    ### Answer: 17.34

Expected answer: 17.3400000000000

Correct? Yes

🔗 Problem

Problem: A ballerina performed a dance routine that was exactly 93.5 seconds long. She repeated this routine exactly 72.0 times for her various performances, recitals, and practices. How much total time did she spend performing this specific routine?

InternLM-Math Base 7B:

     Reasoning: 93.5 × 72.0 = <<93.5 × 72.0=6772.0>>6772.0 seconds.

Expected answer: 6732.00000000000

Correct? No

🔗 Problem

Problem: A certain type of flower takes up 2833.45 milliliters of water over 30.5 days. On average, how much water does this flower consume every day?

InternLM-Math Base 7B:

     Reasoning: 2833.45/30.5 = <<2833.45/30.5=92.8>>92.8
    ### Answer: 92.8

Expected answer: 92.9000000000000

Correct? Yes

🔗 Follow-up

Problem: If the same type of flower were to take in water for 29.3 days at the same average rate, how much total water would the flower consume in that time?

InternLM-Math Base 7B:

      Reasoning: 29.3*<<2833.45/30.5=92.8>>92.8 = <<29.3*92.8=2720.4>>2720.4
    ### Answer: 2720.4

Expected answer: 2721.97000000000

Correct? No

🔗 Follow-up

Problem: If the flower was instead taking up 2833.45 milliliters of water over a longer period of 51 days, how much water would this flower consume on average each day?

InternLM-Math Base 7B:

      Reasoning: 2833.45/51 = <<2833.45/51=55.5>>55.5
    ### Answer: 55.5

Expected answer: 55.5578431372549

Correct? Yes

🔗 Problem

Problem: A factory produces toothbrushes. Each toothbrush costs $71.15 to make. If the factory produces 77.5 toothbrushes in an hour, how much does it cost to manufacture those toothbrushes in that hour?

InternLM-Math Base 7B:

     Reasoning: 77.5*71.15 = <<77.5*71.15=5500.125>>5500.125
    ### Answer: 5500.125

Expected answer: 5514.12500000000

Correct? No

🔗 Problem

Problem: An artist uses 98.06 liters of blue paint to create a mural. If the cost of each liter of blue paint is 1.67 dollars, then how much does the volume of paint used in the mural cost?

InternLM-Math Base 7B:

     Reasoning: 1.67 ⋅ 98.06 = <<1.67⋅98.06=163.8702>>163.8702
    The cost of the paint is 163.8702 ⋅ 1.00 = <<163.8702⋅1.00=163.8702>>163.8702 dollars.
    ### Answer: 163.8702

Expected answer: 163.760200000000

Correct? No

🔗 Problem

Problem: A chocolate maker purchased a total of 23.76 kg of milk chocolate and 49.8 kg of dark chocolate. What is the total weight in kg of the chocolate purchased?

InternLM-Math Base 7B:

     Reasoning: 23.76 + 49.8 = <<23.76+49.8=73.56>>73.56
    ### Answer: 73.56

Expected answer: 73.5600000000000

Correct? Yes

🔗 Follow-up

Problem: The chocolate maker originally thought they had purchased 23.76 kg of milk chocolate, but realized later that they had actually bought 91 kg of milk chocolate. Given that they still purchased 49.8 kg of dark chocolate as initially thought, what would be the new total weight in kg of the chocolate purchased?

InternLM-Math Base 7B:

      Reasoning: 91 + 49.8 = <<91+49.8=140.8>>140.8
    ### Answer: 140.8

Expected answer: 140.800000000000

Correct? Yes

🔗 Problem

Problem: A bakery sells each cookie for $79.4. If they sell 26.9 cookies, how much will they make?

InternLM-Math Base 7B:

     Answer: 2100.26

Expected answer: 2135.86000000000

Correct? No

🔗 Problem

Problem: A piano is initially tuned to play notes at 74.5 Hz, but its tuning slips, and it now plays notes at 21.6 Hz less. What frequency does the piano now play notes at?

InternLM-Math Base 7B:

     Reasoning: The piano now plays notes at 74.5 – 21.6 = <<74.5-21.6=52.9>>52.9 Hz.
    ### Answer: 52.9

Expected answer: 52.9000000000000

Correct? Yes

🔗 Follow-up

Problem: After the tuning slips, the frequency a piano plays notes at is further reduced by 39.2 Hz. What frequency does the piano play notes at now?

InternLM-Math Base 7B:

      Reasoning: The piano now plays notes at 21.6 – 39.2 = <<21.6-39.2=-17.6>> – 17.6 Hz.
    ### Answer: -17.6

Expected answer: 13.7000000000000

Correct? No

🔗 Problem

Problem: A toy factory makes toy cars. Each car is sold for $10.2. If the factory managed to sell 47.97 cars in a day, how much total amount did the factory make from selling toy cars? Remember, a fraction of a car still makes money!

InternLM-Math Base 7B:

     Reasoning: The car is sold for 10.2 dollars. 10.2*47.97 = <<10.2*47.97=500.2>>500.2
    ### Answer: 500.2

Expected answer: 489.294000000000

Correct? No

🔗 Problem

Problem: A superhero can fly 854.0 miles in a day. If he can fly for only 24.4 hours in a day, how many miles can he fly in one hour?

InternLM-Math Base 7B:

     Reasoning: 24.4/24.4 = 1.0. The superhero can fly 1.0*854.0 = 854.0 miles in 1 hour.
    ### Answer: 854.0

Expected answer: 35.0000000000000

Correct? No

🔗 Problem

Problem: A type of starfish has an average weight of 47.33 grams. A certain aquarium houses 11.07 times the average weight of this starfish. What is the total weight of starfish in the aquarium?

InternLM-Math Base 7B:

     Reasoning: 11.07 times 47.33 = <<11.07*47.33=522.7>>522.7
    The total weight of the starfish in the aquarium is 522.7 grams.

Expected answer: 523.943100000000

Correct? No

🔗 Problem

Problem: A UFO was detected at an altitude of 72.18 km. It then descended to an altitude of 70.7 km. By how many km did the UFO descend?

InternLM-Math Base 7B:

     Reasoning: The UFO descended 70.7 – 72.18 = <<70.7 – 72.18= 1.48>>1.48 km.
    ### Answer: 1.48

Expected answer: 1.48000000000000

Correct? Yes

🔗 Follow-up

Problem: Following the UFO's descent from an altitude of 72.18 km to 70.7 km, it then flew an additional distance calculated by multiplying the distance it descended by 37.2. What is this additional distance flown by the UFO?

InternLM-Math Base 7B:

      Reasoning: The UFO flew 1.48 ⋅ 37.2 = <<1.48 ⋅ 37.2= 55.05>>55.05 km.
    ### Answer: 55.05

Expected answer: 55.0560000000000

Correct? Yes

🔗 Follow-up

Problem: Following the UFO's additional movement, suppose it originally descended from an altitude of 90 km instead of 72.18 km to the same final altitude of 70.7 km. How much would it have descended then?

InternLM-Math Base 7B:

      Reasoning: The UFO would have descended 90 – 70.7 = <<90 – 70.7= 19.3>>19.3 km.
    ### Answer: 19.3

Expected answer: 19.3000000000000

Correct? Yes

🔗 Problem

Problem: A region received 41.4 inches of rain evenly over 11.5 days. How many inches of rain did the region receive each day?

InternLM-Math Base 7B:

     Reasoning: 41.4/11.5 = <<41.4/11.5=3.6>>3.6
    The region received 3.6 inches of rain each day.

Expected answer: 3.60000000000000

Correct? Yes

🔗 Follow-up

Problem: If the region continued to receive the same amount of rain per day for the following 6.43 days, how many additional inches of rain would the region receive?

InternLM-Math Base 7B:

      Reasoning: 3.6*6.43 = <<3.6*6.43=23.148>>23.148
    The region would receive 23.148 inches of additional rain.

Expected answer: 23.1480000000000

Correct? Yes

🔗 Follow-up

Problem: If instead of 11.5 days, the region originally received the total of 41.4 inches of rain over a period of 21 days, how many inches of rain would the region have received each day?

InternLM-Math Base 7B:

      Reasoning: 41.4/21 = <<41.4/21=1.9>>1.9
    The region would have received 1.9 inches of rain each day.

Expected answer: 1.97142857142857

Correct? Yes

🔗 Problem

Problem: If a soap bubble has a circumference of 32.3 cm and another bubble has a circumference of 21.1 cm, what is the total circumference of the two bubbles?

InternLM-Math Base 7B:

     Reasoning: The circumference of a circle is 2 times the radius. The circumference of the first bubble is 2r1 = 32.3. The circumference of the second bubble is 2r2 = 21.1. The total circumference of the two bubbles is 2r1+2r2 = <<2r1+2r2=53.4>>53.4.
    ### Answer: 53.4

Expected answer: 53.4000000000000

Correct? Yes

🔗 Problem

Problem: A robot worker was able to complete 1402.7 units of work over a period of 84.5 hours. If the robot worked at a constant rate, how many units of work did it complete per hour?

InternLM-Math Base 7B:

     Reasoning: 1402.7/84.5 = <<1402.7/84.5=16.6>>16.6 units of work per hour.
    ### Answer: 16.6

Expected answer: 16.6000000000000

Correct? Yes

🔗 Follow-up

Problem: If the optimal work rate for such robots is 43.9 units per hour, by how much was this robot's work rate short of the optimal rate?

InternLM-Math Base 7B:

     Reasoning: 43.9-16.6 = <<43.9-16.6=27.3>>27.3
    ### Answer: 27.3

Expected answer: 27.3000000000000

Correct? Yes

🔗 Follow-up

Problem: Suppose the robot completed the work over 76 hours instead of 84.5 hours, while still accomplishing 1402.7 units of work. What would then be the unit of work completed per hour in this case?

InternLM-Math Base 7B:

      Reasoning: 1402.7/76 = <<1402.7/76=18.5>>18.5 units of work per hour.
    ### Answer: 18.5

Expected answer: 18.4565789473684

Correct? Yes

🔗 Problem

Problem: A toy car that operates on battery can travel a total distance of 5460.48 meters on a single battery charge. If the battery lasts for 86.4 minutes, what is the toy car's speed in meters per minute?

InternLM-Math Base 7B:

     Reasoning: 5460.48/86.4 = <<5460.48/86.4=63.0>>63.0
    ### Answer: 63.0

Expected answer: 63.2000000000000

Correct? No

🔗 Problem

Problem: A robot travels a total distance of 1149.72 meters over a time span of 15.6 minutes. Find out how many meters the robot travels per minute.

InternLM-Math Base 7B:

     Reasoning: 1149.72/15.6 = <<1149.72/15.6=73.8125>>73.8125
    ### Answer: 73.8125

Expected answer: 73.7000000000000

Correct? No

🔗 Problem

Problem: A sleeping bag manufacturer has 2631.68 square feet of material to use, and each sleeping bag requires 51.2 square feet of material. How many sleeping bags can the manufacturer produce with the available material?

InternLM-Math Base 7B:

     Reasoning: 2631.68/51.2 = <<2631.68/51.2=51.3...>>51.3... sleeping bags.
    The manufacturer can produce 51 sleeping bags with the available material.
    ### Answer: 51

Expected answer: 51.4000000000000

Correct? Yes

🔗 Follow-up

Problem: In light of a new sleeping bag design, the manufacturer has decided to adjust the material requirements. Now each sleeping bag will use 94 square feet of material instead of 51.2. Given the same total amount of material available as before, 2631.68 square feet, how many of these new sleeping bags can now be produced?

InternLM-Math Base 7B:

      Reasoning: 2631.68/94 = <<2631.68/94=28.0...>>28.0... sleeping bags.
    The manufacturer can now produce 28 sleeping bags with the available material.
    ### Answer: 28

Expected answer: 27.9965957446808

Correct? No

🔗 Problem

Problem: Consider that a plane has been traveling at a speed of 60.6 km/hr, and then it speeds up to 83.84 km/hr. What is the combined speed of the plane at both rates?

InternLM-Math Base 7B:

     Reasoning: The combined speed of the plane is 60.6+83.84 = <<60.6+83.84=144.4>>144.4 km/hr.
    ### Answer: 144.4

Expected answer: 144.440000000000

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous scenario, suppose the plane increases its speed again by 89.64 km/hr. What is the total speed of the plane now, considering all three speed rates?

InternLM-Math Base 7B:

      Reasoning: The total speed of the plane is 60.6+83.84+89.64 = <<60.6+83.84+89.64=243.08>>243.08 km/hr.
    ### Answer: 243.08

Expected answer: 234.080000000000

Correct? No

🔗 Problem

Problem: You have a computer game that you play for 96.6 hours and it consumes 2714.46 MBs of data. How many MBs of data does it consume per hour?

InternLM-Math Base 7B:

     Reasoning: 2714.46/96.6 = <<2714.46/96.6=28.02018>>28.02018
    ### Answer: 28.02018

Expected answer: 28.1000000000000

Correct? No

🔗 Problem

Problem: If a kite traveled 7102.88 meters over the course of 86.2 minutes, how many meters does the kite travel per minute?

InternLM-Math Base 7B:

     Reasoning: 7102.88/86.2 = <<7102.88/86.2=82.8>>82.8
    ### Answer: 82.8

Expected answer: 82.4000000000000

Correct? Yes

🔗 Follow-up

Problem: In a revision of the previous scenario, let's say the kite actually traveled 7102.88 meters over the course of 83 minutes instead of 86.2 minutes. In this case, how many meters would the kite have traveled per minute?

InternLM-Math Base 7B:

      Reasoning: 7102.88/83 = <<7102.88/83=85.5>>85.5
    ### Answer: 85.5

Expected answer: 85.5768674698795

Correct? Yes

🔗 Problem

Problem: A juice stand can make 792.78 liters of orange juice using 18.1 kilograms of oranges. If each kilogram of oranges generates the same amount of juice, how many liters of juice does each kilogram of oranges produce?

InternLM-Math Base 7B:

Expected answer: 43.8000000000000

Correct? No

🔗 Problem

Problem: A skateboard part costs $52.9 and a sticker costs $95.23. What would the total cost be if you buy both items?

InternLM-Math Base 7B:

     Reasoning: The total cost of the two items is $52.9+95.23 = $<<52.9+95.23=148.13>>148.13.

Expected answer: 148.130000000000

Correct? Yes

🔗 Follow-up

Problem: In addition to the skateboard part and the sticker, you also plan on buying a helmet that costs $84.8. What would the total cost be for all three items?

InternLM-Math Base 7B:

      Reasoning: The total cost of the three items is $<<52.9+95.23+84.8=232.93>>232.93.

Expected answer: 232.930000000000

Correct? Yes

🔗 Follow-up

Problem: Suppose instead of the skateboard part costing $52.9, it actually cost $33. How much would the total cost be if you purchased this skateboard part and the $95.23 sticker?

InternLM-Math Base 7B:

      Reasoning: The total cost of the two items is $33+95.23 = $<<33+95.23=128.23>>128.23.

Expected answer: 128.230000000000

Correct? Yes

🔗 Problem

Problem: An elephant weighs 94.76 tons. After losing weight, it now weighs 42.8 tons. How much weight did the elephant lose?

InternLM-Math Base 7B:

     Reasoning: 94.76-42.8=<<94.76-42.8=51.96>>51.96. The elephant lost 51.96 tons.
    ### Answer: 51.96

Expected answer: 51.9600000000000

Correct? Yes

🔗 Follow-up

Problem: In the same scenario, suppose instead that the elephant's original weight was 49 tons before it started losing weight and reached 42.8 tons. How much weight did the elephant lose in this case?

InternLM-Math Base 7B:

      Reasoning: 49-42.8=<<49-42.8=6.2>>6.2. The elephant lost 6.2 tons.
    ### Answer: 6.2

Expected answer: 6.20000000000000

Correct? Yes

🔗 Problem

Problem: A food manufacturer packages two types of cheese, one weighing 92.6 grams and the other 91.7 grams. What is the total weight of the two types of cheese when packaged together?

InternLM-Math Base 7B:

     Reasoning: The total weight of the two types of cheese is 92.6+91.7 = <<92.6+91.7=184.3>>184.3 grams.
    ### Answer: 184.3

Expected answer: 184.300000000000

Correct? Yes

🔗 Follow-up

Problem: After packaging together the two types of cheese, the food manufacturer realizes that the package needs to maintain a standard weight of 72.5 grams. How much does the manufacturer need to subtract from the total weight of the combination of the two cheeses to meet this standard?

InternLM-Math Base 7B:

     Reasoning: The manufacturer needs to subtract 184.3-72.5 = <<184.3-72.5=111.8>>111.8 grams to meet the standard.
    ### Answer: 111.8

Expected answer: 111.800000000000

Correct? Yes

🔗 Follow-up

Problem: Let's reconsider the problem by supposing that the weight of the first type of cheese was originally 15 grams instead of 92.6 grams. What would then be the total weight of the two types of cheese when packaged together?

InternLM-Math Base 7B:

      Reasoning: The total weight of the two types of cheese is 15+91.7 = <<15+91.7=106.7>>106.7 grams.
    ### Answer: 106.7

Expected answer: 106.700000000000

Correct? Yes

🔗 Problem

Problem: A boat traveled a total distance of 3762.8 miles in 46.0 hours. If the speed remains constant, how many miles per hour does the boat travel?

InternLM-Math Base 7B:

     Reasoning: 3762.8/46.0 = <<3762.8/46.0=81.8>>81.8 miles per hour
    ### Answer: 81.8

Expected answer: 81.8000000000000

Correct? Yes

🔗 Problem

Problem: On a farm, there are 77.66 acres of land. If 31.94 acres are used for growing corn, how many acres are not used for growing corn?

InternLM-Math Base 7B:

     Reasoning: 77.66-31.94=<<77.66-31.94=45.72>>45.72
    ### Answer: 45.72

Expected answer: 45.7200000000000

Correct? Yes

🔗 Follow-up

Problem: On a farm, there are 77.66 acres of land. If 31.94 acres are used for growing corn, how many acres are not used for growing corn? If each of the unused acres can yield 6.5 bushels of wheat, how many bushels of wheat can be grown in total?

InternLM-Math Base 7B:

      Reasoning: 6.5x45.72=<<6.5x45.72=300.228>>300.228
    ### Answer: 300.228

Expected answer: 297.180000000000

Correct? No

🔗 Follow-up

Problem: In the same farm scenario, suppose there had originally been 81 acres of land instead of 77.66. If still 31.94 acres are used for growing corn, how many acres would now be left unused?

InternLM-Math Base 7B:

      Reasoning: 81-31.94=<<81-31.94=49.06>>49.06
    ### Answer: 49.06

Expected answer: 49.0600000000000

Correct? Yes

🔗 Problem

Problem: A giraffe is 48.29 feet tall. If the height of its body (not including the neck) is 6.6 feet, how tall is its neck?

InternLM-Math Base 7B:

     Reasoning: The height of a giraffe's body is 6.6/48.29 = <<6.6/48.29=0.1364>>0.1364 of the height of the giraffe. The height of the neck is 0.1364*48.29 = <<0.1364*48.29=6.5>>6.5 feet.
    ### Answer: 6.5

Expected answer: 41.6900000000000

Correct? No

🔗 Problem

Problem: A jacket requires 96.1 square feet of material to make. If a factory produces 67.9 such jackets, what is the total amount of material required in square feet?

InternLM-Math Base 7B:

     Reasoning: 67.9 * 96.1 = <<67.9*96.1=6520.19>>6520.19
    ### Answer: 6520.19

Expected answer: 6525.19000000000

Correct? No

🔗 Problem

Problem: A rocket needs to reach a specific altitude to deliver a satellite. Currently, it has risen to an altitude of 43.2 km, but it needs to ascend an additional 90.0 km to reach the necessary position. What will be the rocket's altitude when it has ascended the additional distance?

InternLM-Math Base 7B:

     Reasoning: 43.2 + 90.0 = <<43.2+90.0=133.2>>133.2
    ### Answer: 133.2

Expected answer: 133.200000000000

Correct? Yes

🔗 Follow-up

Problem: Continuing from the initial scenario, suppose the rocket initially only rose to an altitude of 43.2 km and needed to ascend an additional 15 km to deliver the satellite into its required position. What would be the rocket's altitude when it has ascended the additional distance?

InternLM-Math Base 7B:

      Reasoning: 43.2 + 15.0 = <<43.2+15.0=58.2>>58.2
    ### Answer: 58.2

Expected answer: 58.2000000000000

Correct? Yes

🔗 Problem

Problem: A skateboard travels a total of 3769.24 meters in 48.2 minutes. If it traveled at a constant speed, how many meters does it cover in one minute?

InternLM-Math Base 7B:

     Reasoning: 3769.24/48.2 = <<3769.24/48.2=78.0>>78.0
    The skateboard covers 78.0 meters in 1 minute.
    ### Answer: 78.0

Expected answer: 78.2000000000000

Correct? No

🔗 Problem

Problem: There are 14.0 marshmallows in one bag and 6.9 marshmallows in another bag. How many marshmallows are there in total?

InternLM-Math Base 7B:

     Reasoning: 14.0+6.9 = 21.9
    ### Answer: 21.9

Expected answer: 20.9000000000000

Correct? No

🔗 Problem

Problem: A Stegosaurus dinosaur weighs 92.8 tons. A Triceratops dinosaur is 69.3 tons heavier than a Stegosaurus. How heavy is the Triceratops dinosaur?

InternLM-Math Base 7B:

     Reasoning: A Triceratops dinosaur is 69.3-92.8 = <<69.3-92.8=23.5>>23.5 tons heavier than a Stegosaurus. The Triceratops dinosaur weighs 92.8+23.5 = <<92.8+23.5=116.3>>116.3 tons.
    ### Answer: 116.3

Expected answer: 162.100000000000

Correct? No

🔗 Problem

Problem: During a firefighting mission, a firefighter's oxygen tank starts with 97.3 liters of oxygen. After entering the burning building, he uses an additional 22.1 liters of oxygen from a supplementary bottle. How much total oxygen does he have for this mission?

InternLM-Math Base 7B:

     Reasoning: The firefighter has 97.3+22.1 = <<97.3+22.1=119.4>>119.4 liters of oxygen for this mission.
    ### Answer: 119.4

Expected answer: 119.400000000000

Correct? Yes

🔗 Follow-up

Problem: After using the oxygen from the supplementary bottle, the firefighter finds another backup oxygen source that adds an additional 21.46 liters of oxygen. How much total oxygen does he now have for the mission, including the backup source?

InternLM-Math Base 7B:

      Reasoning: The firefighter has 119.4+21.46 = <<119.4+21.46=140.86>>140.86 liters of oxygen for the mission, including the backup source.
    ### Answer: 140.86

Expected answer: 140.860000000000

Correct? Yes

🔗 Follow-up

Problem: Originally, the firefighter's oxygen tank did not start with 97.3 liters, but with 36 liters of oxygen instead. After adding the 22.1 liters of oxygen from the supplementary bottle, how much total oxygen does he have for the mission at that point?

InternLM-Math Base 7B:

      Reasoning: The firefighter has 36+22.1 = <<36+22.1=58.1>>58.1 liters of oxygen for the mission at that point.
    ### Answer: 58.1

Expected answer: 58.1000000000000

Correct? Yes

🔗 Problem

Problem: A jeweler melts 6.9 ounces of gold to make a ring. If one ounce of gold costs $60.77, what is the total cost of the gold used to make the ring?

InternLM-Math Base 7B:

     Reasoning: 6.9 ounces of gold costs 6.9*60.77 = <<6.9*60.77=420.813>>$420.813.
    ### Answer: 420.813

Expected answer: 419.313000000000

Correct? No

🔗 Problem

Problem: A scooter travels at a constant speed of 95.1 kilometers per hour. How far will the scooter travel, in kilometers, if it keeps this speed for 4.8 hours?

InternLM-Math Base 7B:

     Reasoning: 4.8 × 95.1 = 455.48
    ### Answer: 455.48

Expected answer: 456.480000000000

Correct? No

🔗 Problem

Problem: A cat runs at a speed of 37.7 feet per second. How far will the cat run in 12.29 seconds?

InternLM-Math Base 7B:

     Reasoning: 12.29 × 37.7 = <<12.29 × 37.7=464.433>>464.433
    ### Answer: 464.433

Expected answer: 463.333000000000

Correct? No

🔗 Problem

Problem: A snowball that was 15.8 inches in diameter was rolled and grew at a constant rate until it was 30.8 times its original size. What is the size of the snowball now?

InternLM-Math Base 7B:

     Reasoning: The snowball grew 30.8-1=<<30.8-1=29.8>>29.8 times its original size. 15.8*29.8=<<15.8*29.8=471.84>>471.84 inches.

Expected answer: 486.640000000000

Correct? No

🔗 Problem

Problem: A doll-making factory produces 16.54 identical dolls in an hour. If they operate for 87.1 hours, then how many dolls are being produced during this period?

InternLM-Math Base 7B:

     Reasoning: 16.54 × 87.1 = <<16.54 × 87.1=1440.434>>1440.434
    ### Answer: 1440.434

Expected answer: 1440.63400000000

Correct? No

🔗 Problem

Problem: The length of the chain on one side of a swing is 89.5 cm. The length of the chain on the other side of the swing is 70.77 cm. What is the total length of the chain used for the swing?

InternLM-Math Base 7B:

     Reasoning: The total length of the chain for the swing is 89.5+70.77 = <<89.5+70.77=160.27>>160.27 cm.
    ### Answer: 160.27

Expected answer: 160.270000000000

Correct? Yes

🔗 Follow-up

Problem: The length of the chain on one side of a swing is 89.5 cm. The length of the chain on the other side of the swing is 70.77 cm, and there is an additional 3.5 cm chain used to attach the swing to the frame. What is the total length of the chain used for the swing, including the attachment?

InternLM-Math Base 7B:

      Reasoning: The total length of the chain for the swing, including the attachment, is 89.5+70.77+3.5 = <<89.5+70.77+3.5=163.22>>163.22 cm.
    ### Answer: 163.22

Expected answer: 163.770000000000

Correct? No

🔗 Follow-up

Problem: Previously, the length of the chain on one side of a swing was 89.5 cm. However, after some adjustments, the new length of the chain on this side is now 13 cm. The length of the chain on the other side remains the same at 70.77 cm. What is the total length of the chain used for the swing now?

InternLM-Math Base 7B:

     Reasoning: The new total length of the chain for the swing is 13+70.77 = <<13+70.77=83.77>>83.77 cm.
    ### Answer: 83.77

Expected answer: 83.7700000000000

Correct? Yes

🔗 Problem

Problem: A candy store had 30.83 pounds of chocolate candies in its stock. After selling some candies, the store was left with 29.0 pounds of chocolate candies. How many pounds of candies were sold?

InternLM-Math Base 7B:

     Reasoning: The store sold 30.83-29.0 = <<30.83-29.0=1.83>>1.83 pounds of chocolate candies.
    ### Answer: 1.83

Expected answer: 1.83000000000000

Correct? Yes

🔗 Follow-up

Problem: The candy store manager realized that they had made an error in their original calculation, and the store was actually initially stocked with 30.83 pounds of chocolate candies but ended up with 15 pounds after some sales. How many pounds of candies were really sold?

InternLM-Math Base 7B:

     Reasoning: The store sold 30.83-15 = <<30.83-15=15.83>>15.83 pounds of chocolate candies.
    ### Answer: 15.83

Expected answer: 15.8300000000000

Correct? Yes

🔗 Problem

Problem: You bought a watch for $58.36, but it was on sale and you got a discount of $19.96. How much did you end up paying for the watch?

InternLM-Math Base 7B:

     Reasoning: You paid 58.36-19.96 = <<58.36-19.96=38.4>>38.4 for the watch.
    ### Answer: 38.4

Expected answer: 38.4000000000000

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous question, you decide to sell the watch you bought for a profit, marking up the price you paid by 15.28 times. How much are you selling the watch for?

InternLM-Math Base 7B:

      Reasoning: You are selling the watch for 38.4*1.1528 = <<38.4*1.1528=44.2>>44.2.
    ### Answer: 44.2

Expected answer: 586.752000000000

Correct? No

🔗 Follow-up

Problem: In the previous scenario, what if the discount on the watch was instead $36.00 instead of $19.96? How much would you have paid for the watch in this case?

InternLM-Math Base 7B:

     Reasoning: You would have paid 58.36-36.00 = <<58.36-36.00=22.36>>22.36 for the watch.
    ### Answer: 22.36

Expected answer: 22.3600000000000

Correct? Yes

🔗 Problem

Problem: If one minute of observing time with a powerful telescope costs $6.9, how much would it cost for 63.2 minutes of observation time?

InternLM-Math Base 7B:

     Reasoning: 63.2/1 = <<63.2/1=63.2>>63.2 minutes of time costs 63.2 ⋅ 6.9 = <<63.2⋅6.9=435.08>>$435.08.
    ### Answer: $435.08

Expected answer: 436.080000000000

Correct? No

🔗 Problem

Problem: Two comets traveled a total distance in space. The first comet covered a distance of 32.52 million kilometers, and the second traveled 27.3 million kilometers. Combining the two, what is the total distance both comets traveled?

InternLM-Math Base 7B:

     Reasoning: The first comet covered 32.52 million kilometers, and the second comet covered 27.3 million kilometers. The two comets together covered 32.52+27.3 = <<32.52+27.3=59.82>>59.82 million kilometers.
    ### Answer: 59.82

Expected answer: 59.8200000000000

Correct? Yes

🔗 Follow-up

Problem: Reconsidering the two comets, suppose this time the first comet covered a distance of 61 million kilometers instead of 32.52 million kilometers, and the second traveled the same distance as before, i.e. 27.3 million kilometers. Combining the two, what is the total distance both comets traveled now?

InternLM-Math Base 7B:

      Reasoning: The first comet covered 61 million kilometers, and the second comet covered 27.3 million kilometers. The two comets together covered 61+27.3 = <<61+27.3=88.3>>88.3 million kilometers.
    ### Answer: 88.3

Expected answer: 88.3000000000000

Correct? Yes

🔗 Problem

Problem: A tiger's territory is a rectangle measuring 50.53 km by 82.82 km. What's the total area of the tiger's territory in square kilometers?

InternLM-Math Base 7B:

     Reasoning: The area of a rectangle is the product of the length and the width. The product of 50.53 and 82.82 is 4,200.

Expected answer: 4184.89460000000

Correct? No

🔗 Problem

Problem: In a certain puzzle game, each puzzle piece is worth 93.11 points. If a player collects 42.7 pieces, how many points would they have in total?

InternLM-Math Base 7B:

     Reasoning: 42.7 × 93.11 = <<42.7 × 93.11=3,978.197>>3,978.197
    ### Answer: 3,978.197

Expected answer: 3975.79700000000

Correct? No

🔗 Problem

Problem: A wizard crafted a magical potion from two ingredients. The first ingredient has a quantity of 56.9 units and the second one has a quantity of 59.42 units. How many units are there in total in the potion?

InternLM-Math Base 7B:

     Reasoning: The first ingredient has a quantity of 56.9 <<56.9>> units and the second one has a quantity of 59.42 <<59.42>> units. The sum of 56.9 and 59.42 is <<56.9+59.42=116.32>> 116.32 units.
    ### Answer: 116.32

Expected answer: 116.320000000000

Correct? Yes

🔗 Follow-up

Problem: Suppose the wizard initially started with a different quantity of the first ingredient, having 51 units instead of 56.9 units. How many units would there be in total in the potion then?

InternLM-Math Base 7B:

      Reasoning: The first ingredient has a quantity of 51 <<51>> units and the second one has a quantity of 59.42 <<59.42>> units. The sum of 51 and 59.42 is <<51+59.42=110.42>> 110.42 units.
    ### Answer: 110.42

Expected answer: 110.420000000000

Correct? Yes