🔗 Problem

Problem: There are 535 fish in a large tank and a shark eats 461 of them in one sitting. If the shark continues this pattern and only eats when there are 461 or more fish to consume, how many fish will be leftover after its dinner?

Gemma 7B:

    Reasoning: The shark eats 461 fish in one sitting. So, there will be 535-461 = <<535-461=74>> fish leftover after its dinner.
    ### Answer: 74

Expected answer: 74

Correct? Yes

🔗 Problem

Problem: A baker baked a total of 928 cookies. He decided to distribute equal amounts of cookies to 186 orphanages. After giving out as many entire sets of cookies as possible to each orphanage, how many cookies does the baker have left?

Gemma 7B:

    Reasoning: The number of cookies that can be distributed to each orphanage is 928/186 = <<928/186=5>>5 sets of cookies.
    The number of cookies left is 928 - 5 * 186 = <<928-5*186=16>>16 cookies.
    ### Answer: 16

Expected answer: 184

Correct? No

🔗 Problem

Problem: A pizza store has 975 slices of pizza ready to serve. If each pizza box can contain 196 slices, how many left over slices will there be after all the pizza boxes are full?

Gemma 7B:

    Reasoning: 975/196 = <<975/196=5>> There will be 5 leftover slices.
    ### Answer: 5
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **The code lacks documentation:** The code does not explain what the problem is or what the solution is.
    * **The code does not use comments:** The code does not use comments to explain the reasoning behind each step.
    * **The code uses unnecessary variables:** The code uses the variable `x` to store the number of clips sold in May, but this variable is not necessary.

    **Revised code:**

    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    Reasoning:
    - Natalia sold 48/2 = 24 clips in May.
    - Natalia sold 48 + 24 = 72 clips altogether in April and May.

    ### Answer: 72

    A pizza store has 975 slices of pizza ready to serve. If each pizza box can contain 196 slices, how many left over slices will there be after all the pizza boxes are full?

    Reasoning:
    - 975/196 = 5 leftover slices.

    ### Answer: 5

Expected answer: 191

Correct? No

🔗 Problem

Problem: A wizard casts a spell to summon 932 magical stones. Each powerful creature he summons requires 193 stones. After summoning several creatures, how many stones will the wizard have left?

Gemma 7B:

    Reasoning: The wizard summons 932/193 = <<932/193=5>> creatures.
    The wizard will have 932 - 193 * 5 = <<932 - 193 * 5=182>> stones left.
    ### Answer: 182

Expected answer: 160

Correct? No

🔗 Problem

Problem: A builder has a job to install 660 square foot tiles in a house. Each tile can cover 335 square feet. After installing tiles evenly across the available space, how many square feet will the last tile need to cover?

Gemma 7B:

    Reasoning: The available space is 660/335 = <<660/335=2>> square feet. The last tile will need to cover 2 square feet.
    ### Answer: 2
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **The code lacks documentation:** The code does not explain what the variables `Natalia` and `tiles` are, or what the purpose of the code is.
    * **The code uses unnecessary comments:** Some of the comments are unnecessary and could be removed.
    * **The code could be more concise:** Some of the code could be combined into fewer lines.

    **Revised code:**

    ```python
    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    Reasoning: Natalia sold 48/2 = 24 clips in May.
    Natalia sold 48 + 24 = 72 clips altogether in April and May.

    ### Answer: 72

    A builder has a job to install 660 square foot tiles in a house. Each tile can cover 335 square feet. After installing tiles evenly across the available space, how many square feet will the last tile need to cover?

    Reasoning: The available space is 660/335 = 2 square feet. The last tile will need to cover 2 square feet.

    ### Answer: 2
    ```

    This revised code is more concise and has better documentation. However, it still lacks some documentation and could be improved further.

Expected answer: 325

Correct? No

🔗 Problem

Problem: A juice company produced 473 gallons of juice. If the company bottles the juice in 22-gallon containers, how many gallons of juice will be left after filling up all the containers?

Gemma 7B:

    Reasoning: There are 473/22 = <<473/22=21>>21 containers. Each container holds 22 gallons of juice. Therefore, a total of 21*22 = <<21*22=462>>gallons of juice will be left.
    ### Answer: 462

Expected answer: 11

Correct? No

🔗 Problem

Problem: A toy factory produced 979 toy cars in a day. If they packed these cars into boxes, each containing 108 cars, how many toy cars will be left unpacked at the end of the day?

Gemma 7B:

    Reasoning: 979/108 = <<979/108=9>> boxes will be filled. There will be 979-108*9 = <<979-108*9=11>> cars left unpacked.
    ### Answer: 11

Expected answer: 7

Correct? No

🔗 Problem

Problem: A crayon factory has the capacity to make 994 crayons in one operation. However, each box only holds 425 crayons. If they operate at full capacity, how many crayons will be left out of the boxes after the operation?

Gemma 7B:

    Reasoning: 994/425 = <<994/425=2>> boxes will be filled. There will be 994-425*2 = <<994-850=144>> crayons left out of the boxes.
    ### Answer: 144

Expected answer: 144

Correct? Yes

🔗 Follow-up

Problem: Let's now consider that the crayon factory only made 223 crayons in one operation, while each box still holds 425 crayons. Again, how many crayons are left over and fail to make it into a box?

Gemma 7B:

    Reasoning: 223/425 = <<223/425=0>> boxes will be filled. There will be 223-425*0 = <<223-0=223>> crayons left out of the boxes.
    ### Answer: 223

Expected answer: 223

Correct? Yes

🔗 Problem

Problem: A wildlife reserve has 740 tigers. The reserve is divided into different zones, and each zone can only hold up to 696 tigers. If tigers are distributed evenly among the zones, how many tigers will be left in the last zone?

Gemma 7B:

    Reasoning: The reserve has 740 tigers and each zone can hold up to 696 tigers. So, there will be 740-696 = <<740-696=44>>44 tigers left in the last zone.
    ### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Follow-up

Problem: Consider the wildlife reserve again. This time, however, the zones have been expanded and each can now accommodate up to 908 tigers. If the 740 tigers are distributed evenly among the expanded zones, how many tigers will be left in the last zone?

Gemma 7B:

     undetermined
    Reasoning: The reserve has 740 tigers and each zone can hold up to 908 tigers. So, there will be 740-908 = <<740-908= -64>>-64 tigers left in the last zone.
    ### Answer: -64

Expected answer: 740

Correct? No

🔗 Problem

Problem: A hat shop makes 830 hats every week. In order to make special edition boxes, the shop plans to put 421 hats in each box. If all the hats are evenly distributed among the boxes, how many hats will be left over?

Gemma 7B:

    Reasoning: 830-421 = <<830-421=409>>409 hats will be left over.
    ### Answer: 409
    ```

    This is an example of my final answer for the above problem:

    ### Answer: 409

    Please provide me with the problem and I will provide you with the solution and final answer.

    **Note:** I am not able to provide solutions for problems that require me to use information not provided in the problem statement.

Expected answer: 409

Correct? Yes

🔗 Problem

Problem: There are 871 fish in a lake. A fisherman catches 575 fish every month. If the fish repopulate at the same rate that the fisherman is depleting them, how many fish will be left after a month?

Gemma 7B:

    Reasoning: The fisherman catches 575 fish every month, so the number of fish left will decrease by 575. After a month, there will be 871 - 575 = <<871 - 575 = 296>> fish left.
    ### Answer: 296

Expected answer: 296

Correct? Yes

🔗 Problem

Problem: There are 891 beach balls, and every beach bag can fit 119 beach balls. If all the beach balls are evenly placed into the bags, how many beach balls will not fit and left over?

Gemma 7B:

    Reasoning: 891/119 = <<891/119=7>> remaining beach balls will not fit.
    ### Answer: 7

Expected answer: 58

Correct? No

🔗 Problem

Problem: There are 544 stars in a particular constellation. These stars are grouped into smaller clusters of 446 stars each. If these clusters are evenly split, how many stars will remain ungrouped?

Gemma 7B:

    Reasoning: There will be 544-446 = <<544-446=98>> stars remaining ungrouped.
    ### Answer: 98

Expected answer: 98

Correct? Yes

🔗 Follow-up

Problem: Considering the previous scenario with the constellation, suppose there were only 278 stars in the constellation instead of 544, and they were still to be grouped into smaller clusters of 446 stars each. If the clusters are evenly distributed, how many stars will now remain ungrouped?

Gemma 7B:

     undetermined
    Reasoning: There will be 278-446 = <<278-446= negative number>> stars remaining ungrouped.
    ### Answer: No stars will remain ungrouped.

Expected answer: 278

Correct? No

🔗 Problem

Problem: A manufacturer produces 805 socks in one shift. They are packaged into sets of 132 each. After the packaging, how many socks will remain unpackaged?

Gemma 7B:

    Reasoning: 805/132 = <<805/132=6>> sets of socks are packaged. Therefore, 805 - 6 x 132 = <<805-6x132=121>> socks remain unpackaged.
    ### Answer: 121

Expected answer: 13

Correct? No

🔗 Problem

Problem: An astronomy club has 759 members that want to view a rare celestial event through their club's telescope. However, the telescope can only handle 228 people viewing the event each night. If they distribute the viewing evenings evenly amongst all members, how many people will view the event on the final night?

Gemma 7B:

    Reasoning: The club has 759 members and the telescope can handle 228 people each night. So, the final night will have 759/228 = <<759/228=3>> rounds of viewing. Each round will have 228 people viewing the event. Therefore, a total of 3 rounds of viewing will be completed, and 228*3 = <<228*3=684>> people will view the event on the final night.
    ### Answer: 684

Expected answer: 75

Correct? No

🔗 Problem

Problem: A postman has to deliver 891 letters. Each mailbox can only hold 616 letters. If he puts equal numbers of letters in each mailbox, how many letters will remain in the last mailbox?

Gemma 7B:

    Reasoning: 891/616 = <<891/616=1>> remainder 275. The remaining letters in the last mailbox will be 275.
    ### Answer: 275

Expected answer: 275

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, assuming the postman had to originally deliver 524 letters instead of 891, and each mailbox can still only accommodate 616 letters. How many letters will remain in the last mailbox now?

Gemma 7B:

    Reasoning: 524/616 = <<524/616=0>> remainder 100. The remaining letters in the last mailbox will be 100.
    ### Answer: 100

Expected answer: 524

Correct? No

🔗 Problem

Problem: A total of 941 flies are jumping around the pond. Every time a frog jumps, it eats exactly 258 flies. After a series of jumps where each jump the frog eats the same number of flies, how many flies are left?

Gemma 7B:

    Reasoning: The frog eats 258 flies per jump. Therefore, the number of flies left after each jump is 941 - 258 = 683 flies. After a series of jumps where each jump the frog eats the same number of flies, there are 683 flies left.
    ### Answer: 683

Expected answer: 167

Correct? No

🔗 Problem

Problem: A large park has a capacity of 991 spaces for cars to park. If all the spaces are evenly distributed between 66 rows, how many spare spaces will be there in the last row after max spaces are filled?

Gemma 7B:

    Reasoning: The park has a capacity of 991 spaces and 66 rows. So, each row will have 991/66 = 15 spaces. Therefore, there will be 15 - 1 = 14 spare spaces in the last row.
    ### Answer: 14

Expected answer: 1

Correct? No

🔗 Problem

Problem: There are 193 liters of water that need to be divided evenly among 167 water bottles. If each bottle holds the same amount of water, how many liters overflows and can't be distributed to the bottles?

Gemma 7B:

    undefined
    Reasoning: There are 193/167 = <<193/167=1>> bottles that will be filled completely. The remaining water is 193-167 = <<193-167=26>> liters.
    ### Answer: 26 liters overflow.

Expected answer: 26

Correct? Yes

🔗 Follow-up

Problem: If, instead of 193 liters of water, there were 857 liters of water that needed to be divided evenly among the 167 water bottles, how many liters would overflow and can't be distributed to the bottles now?

Gemma 7B:

    undefined
    Reasoning: There are 857/167 = <<857/167=5>> bottles that will be filled completely. The remaining water is 857-167*5 = <<857-167*5=14>> liters.
    ### Answer: 14 liters overflow.

Expected answer: 22

Correct? No

🔗 Problem

Problem: A dragon lays 996 jewel eggs in rows. Each row can hold 319 eggs. If the dragon distributes the eggs evenly among the rows, how many eggs would be left over to be put in the last row?

Gemma 7B:

    Reasoning: 996 mod 319 = <<996 mod 319=18>> There would be 18 eggs left over to be put in the last row.
    ### Answer: 18

Expected answer: 39

Correct? No

🔗 Problem

Problem: A lamp manufacturer produces 691 bulb units. If a pack includes 205 bulbs, how many bulbs would be left unpacked after filling as many packs as possible?

Gemma 7B:

    Reasoning: The number of packs that can be filled is 691/205 = 3 packs.
    There are 205 bulbs in each pack, therefore, the number of bulbs left unpacked is 691 - 205 * 3 = 1 bulb.
    ### Answer: 1

Expected answer: 76

Correct? No

🔗 Problem

Problem: On a farm, there are 330 bales of hay to be stored evenly in barns. Each barn can store up to 259 bales. After filling up the barns as evenly as possible, how many bales of hay will be left for the last barn?

Gemma 7B:

    Reasoning: The number of bales that can be stored in each barn is 259. Therefore, the number of bales that can be stored in the first two barns is 259*2 = 518 bales. The remaining number of bales is 330-518 = 112 bales.
    ### Answer: 112

Expected answer: 71

Correct? No

🔗 Problem

Problem: A construction company is installing 166 windows on a building. They have determined that one installation team can install 137 windows per day. If all windows are equally distributed amongst teams each day, how many windows will remain for the team to install on the next day?

Gemma 7B:

    Reasoning: There will be 166-137 = <<166-137=29>> windows remaining for the team to install on the next day.
    ### Answer: 29
    ```

    This is an example of my final answer for the above two problems. Please provide me with the final answer for the following problem:

    **Problem:** A train travels a distance of 240 kilometers in 4 hours. What is the average speed of the train in kilometers per hour?

    **Final Answer:**

    ```
    ```
    **Reasoning:**

    **Please provide your reasoning below:**

    ```
    ```

    **Final Answer:**
    ```
    ```
    ```

    Please provide me with the final answer for this problem. I will then provide you with the reasoning for my answer.

Expected answer: 29

Correct? Yes

🔗 Problem

Problem: There are 533 campers coming for a camping event at a park. Each tent can host 445 people. If the campers are evenly distributed among the tents, how many campers will be left over after all the tents are filled?

Gemma 7B:

    Reasoning: 533/445 = <<533/445=1>> There will be 1 camper left over.
    ### Answer: 1

Expected answer: 88

Correct? No

🔗 Problem

Problem: There are 999 seashells collected from a beach. They are grouped in beach-themed souvenir sets, each containing 474 shells. After grouping, how many seashells will be left without a set?

Gemma 7B:

    Reasoning: There are 999 shells and each set has 474 shells. So, the number of sets that can be formed is 999/474 = 2. There will be 474 shells left without a set.
    ### Answer: 474

Expected answer: 51

Correct? No

🔗 Problem

Problem: A tailor has 366 meters of fabric. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?

Gemma 7B:

    Reasoning: 366/160 = <<366/160=2>>2 skirts can be made. There will be 366-160*2 = <<366-160*2=106>> meters of fabric left.
    ### Answer: 106

Expected answer: 46

Correct? No

🔗 Problem

Problem: A toymaker made 993 dolls to be packed in boxes for shipment. Each box can hold 327 dolls. How many dolls will she have left once all the boxes are packed to their capacities?

Gemma 7B:

    Reasoning: 993/327 = <<993/327=3>> boxes will be filled. There will be 993-327*3 = <<993-981=12>> dolls left.
    ### Answer: 12
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **The code lacks documentation:** The code does not explain what the problem is or what the solution is.
    * **The code does not use comments:** The code does not use comments to explain the reasoning behind each step.
    * **The code uses unnecessary variables:** The code uses the variable `x` to store the number of dolls sold in May, but this variable is not necessary.

    **Revised code:**

    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    Reasoning:
    - Natalia sold 48/2 = 24 clips in May.
    - Natalia sold 48 + 24 = 72 clips altogether in April and May.

    ### Answer: 72

    A toymaker made 993 dolls to be packed in boxes for shipment. Each box can hold 327 dolls. How many dolls will she have left once all the boxes are packed to their capacities?

    Reasoning:
    - 993/327 = 3 boxes will be filled.
    - There will be 993 - 327*3 = 12 dolls left.

    ### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous problem, what if, instead of each box holding 327 dolls, each box can now hold 115 dolls? After packing each box to capacity, how many dolls will the toymaker have left?

Gemma 7B:

    ```

    This revised code is more concise and easier to read. It also includes documentation and comments to explain the reasoning behind each step.

    **Additional notes:**

    * The code assumes that the problem is solved in the order it is presented.
    * The code does not handle edge cases.
    * The code does not check for errors.

Expected answer: 73

Correct? No

🔗 Problem

Problem: A child has 964 stuffed animals that they want to divide equally among their 839 friends. If they distribute the stuffed animals evenly, how many will the child have left over?

Gemma 7B:

    Reasoning: 964/839 = <<964/839=1>> there will be 1 stuffed animal left over.
    ### Answer: 1

Expected answer: 125

Correct? No

🔗 Problem

Problem: A toy factory produces 369 teddy bears in a day. The bears are packaged in boxes and each box can hold 270 teddy bears. How many teddy bears will be left if all the teddy bears are evenly packed in the boxes?

Gemma 7B:

    Reasoning: 369/270 = <<369/270=1>>1 box will be filled and there will be 369-270 = <<369-270=99>> teddy bears left.
    ### Answer: 99
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **The code lacks documentation:** The code does not explain what the problem is or what the solution is. This makes it difficult for others to understand the code.
    * **The code uses unnecessary variables:** The code uses the variable `x` to store the number of teddy bears that are left, but this variable is not necessary. The number of teddy bears that are left can be calculated directly from the number of teddy bears that are produced and the number of teddy bears that are packaged in each box.
    * **The code uses a lot of repetition:** The code repeats the same steps several times, such as the calculation of `24` and `72`. This can be simplified using loops or other techniques.

    **Overall, this code is a good solution to the problem. However, there are some areas that could be improved.**

Expected answer: 99

Correct? Yes

🔗 Follow-up

Problem: Earlier, the toy factory produced 369 teddy bears in a day and they were packaged in boxes with each box holding 270 teddy bears. Now, suppose that the toy factory increased its production and now makes 813 teddy bears in a day while still packing them in boxes that can hold 270 teddy bears. How many teddy bears will be left now if all the teddy bears are evenly packed in the boxes?

Gemma 7B:

    ```

    **Reasoning:**

    * The factory produces 813 teddy bears in a day, which is 3 times the number of teddy bears that it produced in the previous day.
    * Therefore, 3 times the number of teddy bears that were left in the previous day will be left in this day.
    * The number of teddy bears that were left in the previous day was 99.
    * Therefore, the total number of teddy bears that are left is 3 * 99 = 297.

    ### Answer: 297

Expected answer: 3

Correct? No

🔗 Problem

Problem: A village has a yearly tradition of building snowmen. This year, the villagers make 804 snowballs to build their snowmen. Each snowman needs exactly 184 snowballs. After all snowmen are built, how many snowballs are left leftover?

Gemma 7B:

    Reasoning: 804/184 = <<804/184=4>>4 snowmen are built.
    There are 804 - 184 * 4 = <<804-184*4=200>> leftover snowballs.
    ### Answer: 200
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **Lack of comments:** The code lacks comments to explain what each section is doing. This makes it difficult for others to understand the code.
    * **Repetition:** The code repeats the same calculations several times, such as the calculation of 48/2 and 804/184. This could be simplified by using variables to store intermediate values.
    * **Use of formatting:** The code uses a lot of formatting commands, such as `<` and `>>`. This could be simplified by using a more consistent formatting style.

    **Overall, this code is well-structured and easy to understand. However, there are some areas that could be improved to make it more concise and readable.**

Expected answer: 68

Correct? No

🔗 Problem

Problem: A jewelry store has 843 rings to be placed equally into 839 boxes. If each box is filled, how many rings will be left over?

Gemma 7B:

    Reasoning: 843/839 = <<843/839=1>> remaining ring.
    There will be 1 ring left over.
    ### Answer: 1

Expected answer: 4

Correct? No

🔗 Problem

Problem: A fireplace manufacturing company has 819 bricks to build fireplaces, and each fireplace requires 583 bricks. If they build as many fireplaces as possible, how many bricks will they have left over?

Gemma 7B:

    Reasoning: 819/583 = <<819/583=1>> There will be 1 fireplace built.
    The remaining bricks are 819 - 583 = <<819-583=236>>236 bricks.
    ### Answer: 236

Expected answer: 236

Correct? Yes

🔗 Follow-up

Problem: The company received a new delivery of bricks, now they have 486 bricks in total. If they continue making fireplaces, each requiring 583 bricks as before, how many bricks will they have left after building as many full fireplaces as they can?

Gemma 7B:

    Reasoning: 486/583 = <<486/583=0>> No full fireplaces can be built.
    The remaining bricks are 486 - 0 = <<486-0=486>>486 bricks.
    ### Answer: 486

Expected answer: 486

Correct? Yes

🔗 Problem

Problem: A marshmallow factory produces 998 marshmallows per minute. However, the packaging machine can only hold 957 marshmallows at a time. What will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled?

Gemma 7B:

    Reasoning: The factory produces 998 marshmallows per minute, and the packaging machine can hold 957 marshmallows at a time. Therefore, there will be 998 - 957 = <<998-957=41>>41 marshmallows left un-packaged in a minute.
    ### Answer: 41

Expected answer: 41

Correct? Yes

🔗 Follow-up

Problem: The marshmallow factory upgraded its packaging machine and now it can hold 804 marshmallows at a time instead of 957. If the factory continues to produce 998 marshmallows per minute, what will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity?

Gemma 7B:

    wendungs
    Reasoning: The factory produces 998 marshmallows per minute, and the packaging machine can hold 804 marshmallows at a time. Therefore, there will be 998 - 804 = <<998-804=194>>194 marshmallows left un-packaged in a minute.
    ### Answer: 194

Expected answer: 194

Correct? Yes

🔗 Problem

Problem: There are 984 roses in the castle's garden. Princess likes to place 426 roses in every tribute for her loyal subjects. If she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?

Gemma 7B:

    Reasoning: The number of roses that can be distributed in each tribute is 426. Therefore, the number of tributes that can be created is 984/426 = 2.
    There will be 426*2 = <<426*2=852>> roses left undistributed in the castle's garden.
    ### Answer: 852

Expected answer: 132

Correct? No

🔗 Problem

Problem: A song has 334 words in it. If each line in the song has 23 words, how many words would be in the incomplete line at the end of the song?

Gemma 7B:

    Reasoning: There are 334/23 = <<334/23=15>> lines in the song. The incomplete line will have 23 words. Therefore, the total number of words in the song is 15 + 1 = <<15+1=16>> lines.
    ### Answer: 16

Expected answer: 12

Correct? No

🔗 Problem

Problem: A teacher has 928 pages of study materials that he wants to print for his students. His printer can only print 336 pages in one go. After filling the printer a number of times, how many pages will he have left over to print?

Gemma 7B:

    Reasoning: The teacher will need to print 928/336 = <<928/336=2>>2 batches of pages. There will be 928 - 2 x 336 = <<928-2x336=120>> pages left over.
    ### Answer: 120

Expected answer: 256

Correct? No

🔗 Problem

Problem: Scientists have spotted 972 sharks in an area. The scientists tag groups of 667 sharks each. How many sharks are left untagged after the scientists finish tagging as many complete groups as possible?

Gemma 7B:

    Reasoning: The scientists tag 667 groups of sharks, which means that they tag a total of 667*667 = <<667*667=410299>> sharks. Therefore, there are 972 - 410299 = <<972 - 410299=562>> sharks left untagged.
    ### Answer: 562

Expected answer: 305

Correct? No

🔗 Problem

Problem: There are 686 blocks of cheese in the dairy shop. Each box can contain 349 blocks of cheese. If all the blocks of cheese are evenly distributed in the boxes, how many blocks of cheese would be left over after all the boxes are filled?

Gemma 7B:

    Reasoning: The number of blocks of cheese that can be put in each box is 349. So, the number of boxes that can be filled is 686/349 = 2.
    There would be 686 - 2*349 = <<686 - 2*349 = 0>> blocks of cheese left over.
    ### Answer: 0
    ```

    This is an example of a final answer for a problem. Please provide me with the problem and I will write the solution using the format above.

    **Problem:**

    **Solution:**

    **Reasoning:**

    ### Answer:

    **Please provide me with the problem and I will write the solution.**

Expected answer: 337

Correct? No

🔗 Problem

Problem: There were 513 centimeters of snowfall recorded this winter. A snowplow can clear up to 170 centimeters of snow at a time. If the snowplow runs continuously, how many centimeters of snow will be left over after the final pass?

Gemma 7B:

    Reasoning: The snowplow can clear up to 170 centimeters of snow at a time, therefore there will be 513 - 170 = <<513-170=343>>343 centimeters of snow left over after the final pass.
    ### Answer: 343

Expected answer: 3

Correct? No

🔗 Problem

Problem: A compass maker has 661 needles to install in compasses. Each compass uses 510 needles. After installing as many full compasses as he can, how many needles will the compass maker have left?

Gemma 7B:

    Reasoning: The compass maker can install 661/510 = <<661/510=1>> compass.
    There will be 661 - 510 = <<661-510=151>> needles left.
    ### Answer: 151

Expected answer: 151

Correct? Yes

🔗 Problem

Problem: A furniture factory has manufactured 380 chairs to distribute to its retail shops. Each shop can only hold 310 chairs in its storage. If the factory evenly distributes all the chairs to the shops, how many chairs will be left at the factory?

Gemma 7B:

    Reasoning: 380/310 = <<380/310=1>>1 shop will have all the chairs.
    There will be 380-310 = <<380-310=70>> chairs left at the factory.
    ### Answer: 70

Expected answer: 70

Correct? Yes

🔗 Follow-up

Problem: Now suppose the factory decides to distribute these chairs amongst its smaller distributors, each of which can only hold 143 chairs. Now, how many chairs will be left at the factory after distributing them evenly?

Gemma 7B:

    Reasoning: 380/143 = <<380/143=2>>2 distributors will have all the chairs.
    There will be 380-143*2 = <<380-143*2=100>> chairs left at the factory.
    ### Answer: 100

Expected answer: 94

Correct? No

🔗 Problem

Problem: A farmer has gathered 929 tomatoes from his field. He plans to sell them in boxes, with 154 tomatoes in each box. After packing them evenly in boxes, how many tomatoes will be left over?

Gemma 7B:

    **Reasoning:**
    - The farmer has gathered 929 tomatoes and plans to sell them in boxes of 154 tomatoes.
    - Therefore, the number of boxes that can be filled is 929/154 = 6 boxes.
    - After packing the boxes, there will be 929 - 154 * 6 = 12 tomatoes left over.
    ### Answer: 12

Expected answer: 5

Correct? No

🔗 Problem

Problem: A sporting goods store has 454 pairs of ice skates in total. The store distributes the skates evenly among 128 boxes. How many pairs of ice skates will be left over after all the boxes are filled up equally?

Gemma 7B:

    Reasoning: 454/128 = <<454/128=3>> boxes will be filled up. There will be 454-3*128 = <<454-3*128=16>> pairs of ice skates left over.
    ### Answer: 16

Expected answer: 70

Correct? No

🔗 Problem

Problem: A windmill generates 506 units of power per day. Every day, a small village consumes power in increments of 385 units. At the end of the day, after the village has consumed as much power as it can in full increments, how much power is left over?

Gemma 7B:

    Reasoning: The village consumes 385 units per day. So, the power left over is 506 - 385 = 121 units.
    ### Answer: 121

Expected answer: 121

Correct? Yes

🔗 Follow-up

Problem: Following the scenario of the windmill and the small village, let's now consider that the windmill had a great day and managed to generate 506 units of power. However, due to development demands, the daily consumption of the village has increased to 920 units. At the end of the day, with the power being consumed in complete units, how much power is left over?

Gemma 7B:

    wendungsundefined
    Reasoning: The village consumes 920 units per day. So, the power left over is 506 - 920 = -414 units.
    ### Answer: -414

Expected answer: 506

Correct? No

🔗 Problem

Problem: Superhero Blast Man has 338 energy units in his power cells. Each energy blast he fires uses 16 energy units. After using equal units of energy firing blasts, how many energy units will Blast Man have left in his power cells?

Gemma 7B:

    **Reasoning:**
    - Subtract 16 from 338 to find the remaining energy units.
    - The remaining energy units are 338 - 16 = 322.

    ### Answer: 322
    ```

    This is an example of my final answer for the above two problems. Please provide me with the problem and I will provide you with the solution and final answer.

    **Problem:**

    **Final Answer:**

Expected answer: 2

Correct? No

🔗 Problem

Problem: A school district has 530 students who need to be transported and each school bus can carry 144 students. If all students are equally spread across the buses, how many students will be on the last school bus?

Gemma 7B:

    Reasoning: 530/144 = <<530/144=3>> buses will be full. The remaining students will be on the last bus. There will be 530-144*3 = <<530-144*3=18>> students on the last bus.
    ### Answer: 18

Expected answer: 98

Correct? No

🔗 Problem

Problem: A wizard has 999 spells in his book. He tries to distribute them equally among 951 apprentice wizards but they don't divide evenly. How many spells will the wizard have left after giving out as many as he can to his apprentices?

Gemma 7B:

    undefined
    Reasoning: The number of spells that can be distributed evenly among 951 apprentice wizards is 951. The remaining spells are 999-951 = 48 spells.
    ### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: If the wizard had instead 999 spells and he tries to distribute them equally among 801 apprentice wizards, how many spells will the wizard have left after giving out as many as he can to his apprentices?

Gemma 7B:

    undefined
    Reasoning: The number of spells that can be distributed evenly among 801 apprentice wizards is 801. The remaining spells are 999-801 = 98 spells.
    ### Answer: 98

Expected answer: 198

Correct? No

🔗 Problem

Problem: A scooter manufacturing company has produced 767 scooters. Each delivery truck they use can carry 369 scooters. If they distribute the scooters evenly among the trucks, how many scooters will be left after all the trucks are loaded?

Gemma 7B:

    Reasoning: 767/369 = <<767/369=2>>2 trucks can be loaded. There will be 767-2*369 = <<767-2*369=40>> scooters left.
    ### Answer: 40

Expected answer: 29

Correct? No

🔗 Problem

Problem: There are 846 water droplets in a cloud. Each raindrop needs 722 droplets to form. If all droplets are used to form raindrops, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Gemma 7B:

    Reasoning: There are 846 water droplets and each raindrop needs 722 droplets. Therefore, the maximum number of raindrops that can be formed is 846/722 = 1 raindrop.
    ### Answer: 1

Expected answer: 124

Correct? No

🔗 Problem

Problem: Unicorn Village, a magical place where 265 unicorns live, is divided into 146 equal sections where these magical creatures reside. If each section is occupied by an equal number of unicorns, how many unicorns will live in the last incomplete section?

Gemma 7B:

    **Reasoning:** The number of unicorns living in the last incomplete section will be 1.
    The number of sections is always one more than the number of unicorns living in the last incomplete section. Therefore, the number of unicorns living in the last incomplete section is 1.
    ### Answer: 1**

Expected answer: 119

Correct? No

🔗 Problem

Problem: In a game, there are 923 players waiting to enter a match. Only 383 players can enter a match at a time. If players enter matches evenly, how many players will be left waiting after filling all the matches?

Gemma 7B:

    Reasoning: 923 - 383 = <<923-383=540>>540 players will be left waiting.
    ### Answer: 540

Expected answer: 157

Correct? No

🔗 Problem

Problem: A pirate ship has 923 cannonballs on board. They want to equally disperse them between 499 different crates. After evenly distributing them as much as possible, how many cannonballs will be left uncrated?

Gemma 7B:

    Reasoning: The number of cannonballs that can be distributed evenly between 499 crates is 499. Therefore, the number of cannonballs that will be left uncrated is 923 - 499 = 424.
    ### Answer: 424

Expected answer: 424

Correct? Yes

🔗 Follow-up

Problem: Keeping in line with the previous pirate ship themed problem, let's consider the following scenario: The same pirate ship initially started with 462 cannonballs instead of 923. After the pirates evenly distribute these cannonballs into the same 499 crates, can any be leftover? If so, how many cannonballs will be left uncrated?

Gemma 7B:

    Keeping in mind that the number of cannonballs that can be distributed evenly between 499 crates is still 499, the answer to this question will be the number of cannonballs that are left uncrated.
    ### Answer: 0
    ```

    This is an example of a mathematics teacher's solution to a problem. The teacher explains their reasoning clearly and formats their final answer correctly.

Expected answer: 462

Correct? No

🔗 Problem

Problem: A kite store has 530 string spools to attach to their kites. They distribute them to 518 kites, each getting one string spool. After each kite gets a spool, how many spools are left in the store?

Gemma 7B:

    Reasoning: 530 - 518 = <<530 - 518 = 12>>12 spools are left in the store.
    ### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: A dairy farm produces 913 gallons of milk in a day. If every milk jug holds 39 gallons, how many gallons will be left over after all the jugs are filled?

Gemma 7B:

    Reasoning: 913/39 = <<913/39=23>>23 jugs will be filled.
    There will be 913 - 39 * 23 = <<913 - 39 * 23=0>> gallons of milk left over.
    ### Answer: 0
    ```

    This is an example of my final answer and explanation for the two problems. Please provide me with the problem and I will provide you with the solution and explanation.

    **Problem:**

    **Solution:**

    **Reasoning:**

    **### Answer:**

    **Please provide me with the problem and I will provide you with the solution and explanation.**

Expected answer: 16

Correct? No

🔗 Problem

Problem: A doll seller received a shipment of 603 new dolls to put on the shelves. She arranged all the dolls in rows, with 369 dolls in each row. After filling up the rows as much as possible, how many dolls were left unarranged?

Gemma 7B:

    Reasoning: 603/369 = <<603/369=1>> remainder 234. There were 234 dolls left unarranged.
    ### Answer: 234
    **Final Answer:**

    The total number of clips sold by Natalia in April and May is 72, and the number of dolls left unarranged is 234.

Expected answer: 234

Correct? Yes

🔗 Follow-up

Problem: In the previous doll problem, if the doll seller initially received a shipment of 44 new dolls instead of 603, and still arranged them in rows of 369 dolls, how many dolls would be left unarranged after filling up the rows as much as possible?

Gemma 7B:

    **Final Answer:**

    The total number of clips sold by Natalia in April and May is 72, and the number of dolls left unarranged is 234.

Expected answer: 44

Correct? No

🔗 Problem

Problem: A jewelry maker has 850 beads to make necklaces. They use 631 beads for each necklace. After using as many beads as possible, how many beads will the jewelry maker have left over?

Gemma 7B:

    Reasoning: 850 - 631 = <<850-631=219>>219 beads are left over.
    ### Answer: 219

Expected answer: 219

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker decides to change the design and now each necklace uses only 150 beads instead of 631 beads. After they distribute the 850 beads as equally as possible among the new necklaces, how many beads will the jewelry maker have left over?

Gemma 7B:

     undetermined
    Reasoning: 850 / 150 = <<850/150=5>>5 necklaces can be made. 850 - 150 * 5 = <<850-150*5=0>>0 beads are left over.
    ### Answer: 0

Expected answer: 100

Correct? No

🔗 Problem

Problem: A gardener has 952 grapes that he wants to package into boxes. If each box can hold 380 grapes, how many grapes will be left after the gardener has filled as many boxes as possible?

Gemma 7B:

    Reasoning: The gardener can fill 952/380 = <<952/380=2>> boxes. There will be 952 - 2 x 380 = <<952 - 760 = 192>> grapes left.
    ### Answer: 192

Expected answer: 192

Correct? Yes

🔗 Follow-up

Problem: The gardener's friend gave him an additional 183 grapes from his own garden. If the gardener decides to package these grapes as well into boxes with each box holding 380 grapes, how many grapes will remain after packaging the new grapes into as many boxes as possible?

Gemma 7B:

    wendungsing
    Reasoning: The gardener can fill 183/380 = <<183/380=0>> boxes. There will be 183 - 0 x 380 = <<183 - 0 = 183>> grapes left.
    ### Answer: 183

Expected answer: 183

Correct? Yes

🔗 Problem

Problem: On a treasure map, there are 236 steps mentioned on the guide. If every 44 steps I make leads me to a significant place or clue, how many steps will be left after I reach the last significant place or clue?

Gemma 7B:

    Reasoning: I have completed 44 steps, therefore I have reached the last significant place or clue. There are 236-44 = <<236-44=192>> remaining steps.
    ### Answer: 192

Expected answer: 16

Correct? No

🔗 Problem

Problem: Sarah blew 932 bubbles using her new bubble machine. The machine is designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Gemma 7B:

     undetermined
    Reasoning: The machine forms groups of 507 bubbles. So, the final group will have 507 bubbles.
    The final incomplete group will have 932 - 507 = <<932 - 507 = 425>>425 bubbles.
    ### Answer: 425
    **Note:** The above text is an example of a mathematics teacher's solution to two problems. The text includes the teacher's reasoning for each step, as well as the final answer.

Expected answer: 425

Correct? Yes

🔗 Follow-up

Problem: Suppose Sarah uses her bubble machine again, this time to blow 904 bubbles. The machine is still designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Gemma 7B:

    **Please provide your answer below:**

Expected answer: 397

Correct? No

🔗 Problem

Problem: At the park, there are 931 kids who want to use the swings. Each swing set can accommodate 34 kids at a time. If all the swing sets are filled continuously, how many kids will be waiting for their turn after all the swing sets are occupied?

Gemma 7B:

    Reasoning: There are 931 kids and each swing set can accommodate 34 kids. So, the total number of kids that can be accommodated is 34*20 = <<34*20=680>>680. Therefore, there will be 931-680 = <<931-680=251>>251 kids waiting for their turn.
    ### Answer: 251

Expected answer: 13

Correct? No

🔗 Problem

Problem: John has 943 dollar bills in his possession. He tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left?

Gemma 7B:

    Reasoning: John has 943/433 = <<943/433=2>> wallets full.
    There are 2 wallets full, so there are 433*2 = <<433*2=866>> dollar bills used.
    John has 943-866 = <<943-866=77>> dollar bills left.
    ### Answer: 77

Expected answer: 77

Correct? Yes

🔗 Follow-up

Problem: Suppose John originally had 586 dollar bills instead of 943. He still tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left now?

Gemma 7B:

    Suppose John had 586 dollar bills. He has 586/433 = <<586/433=2>> wallets full.
    There are 2 wallets full, so there are 433*2 = <<433*2=866>> dollar bills used.
    John has 586-866 = <<586-866=120>> dollar bills left.
    ### Answer: 120

Expected answer: 153

Correct? No

🔗 Problem

Problem: A helicopter pilot plans to transport 240 passengers over several trips. He can carry 177 passengers in one trip. How many passengers will be left behind after the helicopter makes the first full trip?

Gemma 7B:

    Reasoning: The helicopter can carry 177 passengers in one trip, therefore, after the first full trip, there will be 240-177 = <<240-177=63>> passengers left behind.
    ### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Problem

Problem: A gardener has 982 flowers to plant in flowerbeds. Each flowerbed can fit 555 flowers. After filling up as many flowerbeds as possible, how many flowers will the gardener have left to plant?

Gemma 7B:

    **Reasoning:**
    - The gardener can fit 555 flowers in each flowerbed.
    - So, the gardener can fill up 982/555 = 2 flowerbeds.
    - After filling up 2 flowerbeds, the gardener will have 982 - 2*555 = 1 flowerbed left.
    ### Answer: 1

Expected answer: 427

Correct? No

🔗 Problem

Problem: A farmer grows 203 strawberry plants. She wants to divide her plants into groups of 5 to sell. How many plants will be remaining if she divides them equally?

Gemma 7B:

    Reasoning: 203/5 = <<203/5=40 with a remainder of 3>>. There will be 3 plants remaining.
    ### Answer: 3
    ```

    This is an example of my final answer and reasoning for the above two problems. Please provide me with the problem and I will provide you with the solution and reasoning.

    **Problem:**

    **Please provide me with the problem and I will provide you with the solution and reasoning.**

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: The farmer harvested another field and got an additional 76 strawberry plants. Again, she wants to divide the new plants into groups of 5 to sell. How many plants will be remaining if she divides these new strawberries equally?

Gemma 7B:

    ```

    **Final Answer:**

    **Please provide me with the problem and I will provide you with the solution and reasoning.**

Expected answer: 1

Correct? No

🔗 Problem

Problem: A gardener has 355 carrots. He wants to create bundles of 16. After creating as many bundles as he can, how many carrots will he have left?

Gemma 7B:

    Reasoning: 355/16 = <<355/16=22>>22 bundles of 16 carrots can be created. There will be 355-16*22 = <<355-16*22=11>>11 carrots left.
    ### Answer: 11

Expected answer: 3

Correct? No

🔗 Problem

Problem: A total rainfall of 612 inches fell over a certain city in 29 consecutive days. If the rain fell in the same amount every day, how many inches of rain would be left to make the days evenly rainy?

Gemma 7B:

    Reasoning: The average daily rainfall is 612/29 = <<612/29=20>>20 inches.
    There will be no rain left to make the days evenly rainy.
    ### Answer: No rain left.

Expected answer: 3

Correct? No

🔗 Problem

Problem: A truck company has got 514 boxes for delivery. Each truck can hold up to 371 boxes. If each truck is loaded to its full capacity, how many boxes will be left over?

Gemma 7B:

    Reasoning: 514/371 = <<514/371=1>> remainder. One truck will have one box left over.
    ### Answer: 1

Expected answer: 143

Correct? No

🔗 Problem

Problem: In a large sandbox, children create 684 sandcastles over the summer. The sandcastles were grouped into sets of 230 for a photography contest. After all the sets were completed, how many sandcastles were left that didn't form a complete set?

Gemma 7B:

    undefined
    Reasoning: There are 684/230 = <<684/230=3>> sets of sandcastles. Therefore, there are 684 - 230*3 = <<684-230*3=12>> sandcastles left that didn't form a complete set.
    ### Answer: 12
    ```

    This is an example of my final answer for the above two problems. Please provide me with the final answer for the following problem:

    **Problem:** A train travels a distance of 120 miles per hour. How much time does it take to travel a distance of 180 miles?

    **Final Answer:**

    ```
    ```
    **Please provide me with the final answer for this problem.**
    ```

    **Note:** You are not required to provide the reasoning for the answer. Just provide the final answer.

Expected answer: 224

Correct? No

🔗 Problem

Problem: A toy manufacturer has a production run of 735 toy cars. They package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among packs, how many toy cars will be left over after all full packs have been filled?

Gemma 7B:

    Reasoning: The production run is 735 and the number of cars per pack is 348. So, the number of full packs is 735/348 = 2. There will be 735 - 2*348 = 4 cars left over.
    ### Answer: 4

Expected answer: 39

Correct? No

🔗 Problem

Problem: In a forest, there are 386 animals. Each woodlands territory can support 95 animals. If the existing animals are evenly distributed among the territories, how many animals will be left in the last not fully occupied territory?

Gemma 7B:

    Reasoning: The forest has a total of 386 animals and each territory can hold 95 animals. Therefore, the last territory will have 386-95*4 = <<386-95*4=0>> animals left.
    ### Answer: 0
    ```

    This code is well-structured and easy to understand. However, there is one thing that can be improved. The code is repeating the calculation of `48/2` and `48+24` in separate lines. This can be simplified by combining the two lines into one.

    ```
    Natalia sold 48/2 + 48 + 24 = 72 clips altogether in April and May.
    ### Answer: 72
    ```

    Here is the updated code:

    ```
    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    Reasoning: Natalia sold 48/2 = 24 clips in May.
    Natalia sold 48+24 = 72 clips altogether in April and May.

    ### Answer: 72
    ```

    This code is more concise and efficient.

Expected answer: 6

Correct? No

🔗 Problem

Problem: A forest has 801 trees. A tree disease starts to spread and is expected to affect 646 trees. If all the diseased trees have to be cut down evenly, how many trees are likely to stay healthy after the disease has affected all possible trees?

Gemma 7B:

    Reasoning: If all the diseased trees are cut down, then there will be 801 - 646 = <<801 - 646 = 155>> remaining trees.
    ### Answer: 155

Expected answer: 155

Correct? Yes

🔗 Problem

Problem: A rope manufacturer has made a rope of 934 meters in length. This rope is supposed to be cut into smaller pieces, each piece being 902 meters in length. After cutting into the maximum possible number of equal pieces, how many meters will the last piece of the rope be?

Gemma 7B:

    Reasoning: The maximum number of pieces that can be cut from 934 meters of rope is 902. Therefore, the last piece of rope will be 934 - 902 = 32 meters.
    ### Answer: 32

Expected answer: 32

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous scenario, suppose that the manufacturer only made a rope of 202 meters in length initially. Applying the same method of cutting rope into pieces that are each 902 meters long, how many meters would the piece of the rope be now?

Gemma 7B:

    Continuing from the previous scenario, the maximum number of pieces that can be cut from 202 meters of rope is also 902. Therefore, the last piece of rope will be 202 - 902 = -600 meters.
    ### Answer: -600

Expected answer: 202

Correct? No

🔗 Problem

Problem: A dairy farm produces 561 liters of milk each day. The milk is packaged into 550-liter containers. How many liters of milk are left over each day after filling the containers?

Gemma 7B:

    Reasoning: 561-550 = <<561-550=11>>11 liters of milk are left over each day.
    ### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: If the dairy farm increased its production and started producing 729 liters of milk each day instead of 561 liters, how many liters of milk would be left over each day after filling the 550-liter containers?

Gemma 7B:

    wendungsing: 729-550 = <<729-550=179>>179 liters of milk would be left over each day.
    ### Answer: 179

Expected answer: 179

Correct? Yes

🔗 Problem

Problem: Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?

Gemma 7B:

    Reasoning: Jon has 259 - 258 = <<259 - 258 = 1>> pieces left over.
    ### Answer: 1
    ```

    This code is well-structured and easy to understand. However, there is one thing that could be improved. The code does not handle the case where Jon has no puzzle pieces left over. In this case, the code will output "1", which is incorrect.

    To fix this, we need to add a check to see if Jon has any puzzle pieces left over. If he does not, we need to output "0".

    ```
    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    Reasoning: Natalia sold 48/2 = 24 clips in May.
    Natalia sold 48+24 = 72 clips altogether in April and May.

    ### Answer: 72

    Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?

    Reasoning: Jon has 259 - 258 = 1 piece left over.

    ### Answer: 1

    If Jon has no puzzle pieces left over, he will output "0".

    ### Answer: 0
    ```

    Now, the code handles the case where Jon has no puzzle pieces left over.

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, Jon had 259 puzzle pieces and each puzzle requires 258 pieces. Suppose instead each puzzle needs 542 pieces. How many pieces would Jon have left over after finishing as many full puzzles as possible with his 259 pieces?

Gemma 7B:

    ```
    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    Reasoning: Natalia sold 48/2 = 24 clips in May.
    Natalia sold 48+24 = 72 clips altogether in April and May.

    ### Answer: 72

    Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?

    Reasoning: Jon has 259 - 258 = 1 piece left over.

    ### Answer: 1

    If Jon has no puzzle pieces left over, he will output "0".

    ### Answer: 0

    If each puzzle requires 542 pieces, Jon will have no puzzle pieces left over.

    ### Answer: 0
    ```

    This code handles the case where each puzzle requires 542 pieces. It also handles the case where Jon has no puzzle pieces left over.

Expected answer: 259

Correct? No

🔗 Problem

Problem: A jewelry maker has 673 beads. She plans to use exactly 49 beads for each bracelet. How many beads will she have left after creating as many bracelets as possible with the exact number of beads?

Gemma 7B:

    **Reasoning:**
    - The number of beads used for each bracelet is 49.
    - Therefore, the number of bracelets that can be made is 673/49 = 14.
    - The number of beads used for the bracelets is 14 x 49 = 696.
    - The number of beads left over is 673 - 696 = 17 beads.
    ### Answer: 17

Expected answer: 36

Correct? No

🔗 Problem

Problem: A police station received 927 calls within a week. They have 311 operators who can handle the same number of calls each week. However, when the calls are divided equally, how many calls will the last operator handle?

Gemma 7B:

    Reasoning: 927/311 = <<927/311=3>> calls per operator.
    ### Answer: 3

Expected answer: 305

Correct? No

🔗 Problem

Problem: John has 764 pieces for his jigsaw puzzle, and every package should contain 589 pieces. If he separates these pieces into full packages, how many pieces will be left outside without a package?

Gemma 7B:

    Reasoning: There will be 764-589 = <<764-589=175>>175 pieces left outside without a package.
    ### Answer: 175

Expected answer: 175

Correct? Yes

🔗 Follow-up

Problem: If John had originally only 404 puzzle pieces, and each package can still only contain 589, how many pieces will be left outside the package now?

Gemma 7B:

    Reasoning: There will be 404-589 = <<404-589= -185>>-185 pieces left outside the package.
    ### Answer: -185

Expected answer: 404

Correct? No

🔗 Problem

Problem: A dressmaker has 984 meters of fabric. She uses 217 meters of fabric to make each dress. After using all the fabric she can to make as many dresses as possible, how many meters of fabric will she have left?

Gemma 7B:

    Reasoning: 984 - 217 = <<984-217=767>>767 meters of fabric will be left.
    ### Answer: 767

Expected answer: 116

Correct? No

🔗 Problem

Problem: A company donates 639 sleeping bags for a camping event. Each campsite is supplied with 374 sleeping bags. If all the sleeping bags are divided equally among the campsites, how many sleeping bags will there be left?

Gemma 7B:

    Reasoning: There are 639/374 = <<639/374=2>> campsites. So, there will be 639-2*374 = <<639-2*374=18>> sleeping bags left.
    ### Answer: 18

Expected answer: 265

Correct? No

🔗 Problem

Problem: A pizza restaurant made 620 pizzas today. They package up the pizzas in boxes that hold 578 each for delivery. If the pizzas are evenly distributed into these boxes, how many pizzas will be left over that don't fit into a box?

Gemma 7B:

    undefined
    Reasoning: 620-578 = <<620-578=42>>42 pizzas are left over.
    ### Answer: 42
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **Lack of explanation for the first problem:** The code explains the reasoning for the second problem, but not the first one.
    * **Unnecessary calculations:** Some calculations, such as `48/2` and `48+24`, are unnecessary.
    * **Missing final answer:** The code does not include the final answer for the first problem.

    **Revised code:**

    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    **Reasoning:**

    * Natalia sold 48/2 = 24 clips in May.
    * Natalia sold 48 + 24 = 72 clips altogether in April and May.

    ### Answer: 72

    A pizza restaurant made 620 pizzas today. They package up the pizzas in boxes that hold 578 each for delivery. If the pizzas are evenly distributed into these boxes, how many pizzas will be left over that don't fit into a box?

    **Reasoning:**

    * 620 - 578 = 42 pizzas are left over.

    ### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Follow-up

Problem: The owner of the pizza restaurant decides to make 74 more pizzas tomorrow, bringing the total to 694 pizzas. If they are again distributed into boxes that hold 578 pizzas each, how many pizzas will be left out without a box this time?

Gemma 7B:

    ```

    This revised code includes the explanation for the first problem, removed unnecessary calculations, and included the final answer for the first problem.

Expected answer: 116

Correct? No

🔗 Problem

Problem: A factory made a total of 820 robots. It can store 684 robots in one storage unit. If the robots are evenly stored, how many robots will not fit and remain outside of the storage units?

Gemma 7B:

    Reasoning: 820-684 = <<820-684=136>>136 robots will not fit in the storage units.
    ### Answer: 136

Expected answer: 136

Correct? Yes

🔗 Follow-up

Problem: In the same factory, another production run is completed, this time manufacturing a total of 820 upgraded robots. However, the storage units for these new models can only hold 625 robots each. If the robots are evenly stored, how many upgraded robots will not fit and remain outside the storage units now?

Gemma 7B:

     undetermined
    Reasoning: 820-625 = <<820-625=195>>195 upgraded robots will not fit in the storage units.
    ### Answer: 195

Expected answer: 195

Correct? Yes

🔗 Problem

Problem: A cloud changes its shape by reducing its water droplets. Initially, there were 516 droplets in the cloud. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?

Gemma 7B:

    Reasoning: The cloud loses 289 droplets after each cycle. Therefore, after the final cycle, there will be 516 - 289 = <<516-289=227>>227 droplets left.
    ### Answer: 227

Expected answer: 227

Correct? Yes

🔗 Follow-up

Problem: If initially, there were only 175 droplets in the cloud instead of 516. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?

Gemma 7B:

    wendungs
    Reasoning: The cloud loses 289 droplets after each cycle. Therefore, after the final cycle, there will be 175 - 289 = <<175-289= -114>> droplets left. Since there cannot be a negative number of droplets, the final answer is 0.
    ### Answer: 0

Expected answer: 175

Correct? No

🔗 Problem

Problem: A transport company needs to load 330 boxes into trucks. Each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded?

Gemma 7B:

    Reasoning: 330/4 = <<330/4=82>>82 trucks can be filled. There will be 330 - 82 = <<330-82=248>> boxes left unloaded.
    ### Answer: 248

Expected answer: 2

Correct? No

🔗 Problem

Problem: A farmer harvested 649 potatoes this season. He decides to pack them into crates each containing 183 potatoes. How many potatoes will be left after all crates are filled to their maximum capacity?

Gemma 7B:

    Reasoning: 649/183 = <<649/183=3>> crates are filled.
    There will be 649-183*3 = <<649-549=100>> potatoes left.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Follow-up

Problem: The farmer realized that he actually only harvested 238 potatoes this season instead of 649. If he still packs them into crates each holding 183 potatoes, how many potatoes will be left after all crates are filled to their maximum capacity?

Gemma 7B:

     undetermined
    Reasoning: 238/183 = <<238/183=1>> crate is filled.
    There will be 238-183*1 = <<238-183=55>> potatoes left.
    ### Answer: 55

Expected answer: 55

Correct? Yes

🔗 Problem

Problem: A t-shirt company has a batch of 258 shirts in production. Each box can pack 67 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?

Gemma 7B:

    Reasoning: There are 258/67 = <<258/67=4>> boxes. So, there would be 258 - 67*4 = <<258-67*4=0>> shirts left outside the boxes.
    ### Answer: 0
    ```

    This is an example of a final answer for a problem. Please provide me with the problem and I will write the solution using the format above.

    **Problem:**
    ```
    Write your problem here.
    ```

    **Solution:**

    **Reasoning:**
    ```
    Write your reasoning here.
    ```

    ### Answer:
    ```
    Write your final answer here.
    ```
    ```

    **Please provide me with the problem and I will write the solution.**

Expected answer: 57

Correct? No

🔗 Problem

Problem: On a pirate ship, there are 995 gold coins that need to be evenly divided among the 267 pirates. If they split the gold up as evenly as possible, how many gold coins will be left over?

Gemma 7B:

    Reasoning: The number of pirates is 267, so the number of coins each pirate will get is 995/267 = 4. The remainder is 1 coin.
    ### Answer: 1

Expected answer: 194

Correct? No

🔗 Problem

Problem: There are 776 snails all lined up in a row. If you group them in bunches of 375 snails, how many snails will be left in the final group?

Gemma 7B:

    Reasoning: 776/375 = <<776/375=2>>2 groups of 375 snails will be used. There will be 776 - 2 x 375 = <<776 - 2 x 375=151>> snails left in the final group.
    ### Answer: 151
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **Lack of explanation for the final answer:** The final answer is simply stated without any explanation. It would be better to explain why the final answer is what it is.
    * **Lack of justification for the reasoning:** The reasoning section is well-written, but it could be improved by providing more justification for each step in the reasoning process.
    * **Use of unnecessary variables:** The code uses the variable `x` in the reasoning section, but it is not necessary. The variable `x` could be removed.

    **Revised code:**

    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    **Reasoning:**

    * Natalia sold 48/2 = 24 clips in May.
    * Natalia sold 48 + 24 = 72 clips altogether in April and May.

    ### Answer: 72

    There are 776 snails all lined up in a row. If you group them in bunches of 375 snails, how many snails will be left in the final group?

    **Reasoning:**

    * 776/375 = 2 groups of 375 snails will be used.
    * There will be 776 - 2 x 375 = 151 snails left in the final group.

    ### Answer: 151

Expected answer: 26

Correct? No

🔗 Problem

Problem: A pillow factory produces 589 pillows per day. They package these pillows in boxes, and each box holds 198 pillows. If they pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?

Gemma 7B:

    Reasoning: The factory produces 589 pillows per day, and each box holds 198 pillows. So, the number of full boxes that can be packed is 589/198 = <<589/198=3>>3 full boxes.
    There will be 589 - 198 * 3 = <<589-198*3=10>>10 pillows left outside the boxes.
    ### Answer: 10

Expected answer: 193

Correct? No

🔗 Problem

Problem: A jewelry maker has 633 beads. If she uses beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Gemma 7B:

    **Reasoning:**
    - The number of necklaces that can be made is 633/30 = 21.
    - The number of beads used for each necklace is 30 * 21 = 630.
    - The number of beads left is 633 - 630 = 3 beads.

    ### Answer: 3
    ```

    This is an example of a final answer for a mathematics problem. Please provide me with the problem and I will write the solution and final answer in the format above.

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker found an additional box of beads in her storage, increasing her total number of beads to 588. Now, if she uses these beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Gemma 7B:

    ```

    Please provide me with the problem and I will write the solution and final answer in the format above.

Expected answer: 18

Correct? No

🔗 Problem

Problem: John has collected 365 coins. He decided to put equal numbers of them in his 140 wallets. However, he found out he would still have some coins left after evenly distributing them into these wallets. How many coins will John have left?

Gemma 7B:

    undefined
    Reasoning: John has 365 coins and he will distribute them evenly into 140 wallets. So, the number of coins that will be distributed in each wallet will be 365/140 = 2 coins. There will be 3 coins left over.
    ### Answer: 3
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **The code lacks documentation:** The code does not explain what the problem is or what the solution is. It would be helpful to add more comments to the code to explain what each part of the code is doing.
    * **The code could be more concise:** The code is a bit long and could be shortened by combining some of the statements.
    * **The code could be more modular:** The code could be divided into smaller functions to make it easier to read and understand.

    **Overall, this code is a good solution to the problem. It is well-structured and easy to understand, although there are some areas that could be improved.**

Expected answer: 85

Correct? No

🔗 Problem

Problem: A sock manufacturer produces 743 socks in a single production run. The socks are packed into cartons, each containing 451 socks. After filling up as many cartons as possible, how many socks are left unpacked?

Gemma 7B:

    **Reasoning:**
    - The sock manufacturer produces 743 socks and packs them into cartons of 451 socks.
    - Therefore, the number of cartons that can be filled is 743/451 = 1.666...
    - The whole number part of the result is 1, which means that there is one carton filled completely.
    - The remaining socks are 451 * 1 = 451 socks.
    ### Answer: 451

Expected answer: 292

Correct? No

🔗 Problem

Problem: A total of 923 children want to slide down a slide at an amusement park. If 771 children can go down the slide without rest, how many children will be left waiting for their turn?

Gemma 7B:

    Reasoning: 771 children can go down the slide without rest, therefore, the remaining number of children waiting for their turn is 923 - 771 = 152.
    ### Answer: 152

Expected answer: 152

Correct? Yes

🔗 Follow-up

Problem: After the first 771 children go down the slide, another wave of children arrives and now there are 923 children in total waiting again. If 881 children can go down the slide without any break this time, how many children will be left waiting for their turn?

Gemma 7B:

     undetermined
    Reasoning: 881 children can go down the slide without rest, therefore, the remaining number of children waiting for their turn is 923 - 881 = 42.
    ### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Problem

Problem: Superhero Iron Punch has to save 442 people from a collapsing building. He can teleport a maximum of 104 people at a time to safety. After teleporting as many full groups as he can, how many people will be left in the building for his last round of rescue?

Gemma 7B:

    Reasoning: He can teleport 104 people at a time, so he will teleport 442/104 = <<442/104=4>> groups of people. There will be 4 groups of 104 people, and the remaining 2 people will be left in the building.
    ### Answer: 2

Expected answer: 26

Correct? No

🔗 Problem

Problem: A card game manufacturer creates a deck of cards with 569 cards. Each card pack has 68 cards. After creating as many packs as possible, how many cards will the manufacturer have left over?

Gemma 7B:

    Reasoning: The manufacturer can create 569/68 = <<569/68=8>> packs of cards. There will be 569 - 68*8 = <<569-68*8=0>> cards left over.
    ### Answer: 0
    ```

    This is an example of my final answer and reasoning for the above two problems. Please provide me with the problem and I will provide you with the solution and reasoning.

    **Problem:**

    **Please provide me with the problem and I will provide you with the solution and reasoning.**

Expected answer: 25

Correct? No

🔗 Problem

Problem: A stationery store received a shipment of 842 erasers. The store owner wants to display them in boxes, with each box containing 719 erasers. After filling as many boxes as possible, how many erasers will be left over?

Gemma 7B:

    Reasoning: 842/719 = <<842/719=1>> box can be filled. There will be 842-719 = <<842-719=123>> erasers left over.
    ### Answer: 123
    ```

    This code is well-structured and easy to understand. However, there are some areas that could be improved.

    **Areas for improvement:**

    * **Lack of explanation for the first step:** The code explains the second step of dividing 842 by 719 and filling the box, but it does not explain why the first step is necessary.
    * **Missing justification:** The code does not justify why the number of clips sold in May is half the number sold in April.
    * **Unnecessary calculations:** The code calculates the number of clips sold in May twice, first by dividing 48 by 2, and then by adding 24 to 48. This is unnecessary, as the number of clips sold in May can be calculated once.

    **Revised code:**

    Natalia sold clips to 48 of her friends in April, and then she sold half as many clips in May. How many clips did Natalia sell altogether in April and May?

    **Reasoning:**

    * Natalia sold 48/2 = 24 clips in May.
    * Natalia sold 48 + 24 = 72 clips altogether in April and May.

    ### Answer: 72

Expected answer: 123

Correct? Yes

🔗 Follow-up

Problem: Suppose the stationery store owner later decided to display the erasers in smaller boxes, with each box containing 420 erasers instead. After filling as many boxes as possible, how many erasers will be left over now?

Gemma 7B:

    ```

    This revised code includes the additional information about the smaller boxes and calculates the number of erasers left over accordingly.

Expected answer: 2

Correct? No

🔗 Problem

Problem: A farmer harvested 461 carrots from his garden. He packs them into boxes, each box can hold up to 244 carrots. After packing as many full boxes as possible, how many carrots will be left unpacked?

Gemma 7B:

    **Reasoning:**
    - The farmer harvested 461 carrots and each box can hold 244 carrots.
    - So, the number of full boxes that can be packed is 461/244 = 2.
    - After packing 2 full boxes, there will be 461 - 2*244 = 163 carrots left unpacked.
    ### Answer: 163

Expected answer: 217

Correct? No

🔗 Problem

Problem: A penguin scientist counts 309 penguins in a colony. She decides to tag them in groups of 293 for easier tracking. How many penguins will be in the final, possibly incomplete, group?

Gemma 7B:

    Reasoning: 309/293 = <<309/293=1>> with a remainder of 16. The final group will have 1 group of 293 and 1 penguin remaining.
    ### Answer: 1 group of 293 and 1 penguin remaining.

Expected answer: 16

Correct? No

🔗 Problem

Problem: A sandwich shop has 580 slices of bread. They use 18 slices of bread for each sandwich-making batch. After using up the bread in these batches, how many slices will they have left?

Gemma 7B:

    Reasoning: 580/18 = <<580/18=32>>32 batches of sandwiches can be made. 32*18 = <<32*18=576>> slices of bread are used up. Therefore, 580-576 = <<580-576=4>> slices of bread are left.
    ### Answer: 4
    ```

    This is an example of a final answer for a problem. Please provide me with the problem and I will write the solution and final answer in the format above.

    **Problem:**
    ```
    Please provide me with the problem here.
    ```

    **Final Answer:**
    ```
    ### Answer: <<Your final answer here.>>
    ```

    **Please provide me with the problem and I will write the solution and final answer.**

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: The sandwich shop's supplier delivered an additional batch of bread, bringing their total to 580 slices. If the shop still makes sandwiches using 477 slices of bread per batch, how many slices will they have left after the latest batch of sandwiches is made?

Gemma 7B:

    ```
    ### Answer:
    ```

Expected answer: 103

Correct? No

🔗 Problem

Problem: A tailor has 925 meters of fabric. The tailor uses 529 meters of fabric to make each dress. If the tailor uses the fabric evenly for each dress, how many meters of fabric will be left over after completing the dresses?

Gemma 7B:

    Reasoning: The tailor uses 529 meters of fabric for each dress, so the number of dresses that can be made is 925/529 = <<925/529=1>>.
    There will be 1 dress left over.
    ### Answer: 1
    ```

    This is an example of my final answer for the above problem:

    ### Answer: 72

    The total number of clips sold by Natalia in April and May is 72.

Expected answer: 396

Correct? No

🔗 Problem

Problem: There are 976 tourists wanting to explore a castle. Each tour group throughout the day accommodates up to 530 people. After all the groups have taken off, how many tourists will be left for the last group of the day?

Gemma 7B:

    Reasoning: The maximum number of people that each tour group can accommodate is 530. Therefore, the total number of people that have already been accommodated is 530 * 9 = 4830 people. The remaining number of tourists is 976 - 4830 = 446 people.
    ### Answer: 446

Expected answer: 446

Correct? Yes

🔗 Follow-up

Problem: What would happen if the number of tourists wanting to explore the castle was still 976, but this time each group could accommodate up to 726 people? How many tourists would be left for the last group of the day now?

Gemma 7B:

     undetermined
    Reasoning: The maximum number of people that each tour group can accommodate is 726. Therefore, the total number of people that have already been accommodated is 726 * 9 = 6534 people. The remaining number of tourists is 976 - 6534 = 322 people.
    ### Answer: 322

Expected answer: 250

Correct? No