🔗 Problem

Problem: There are 535 fish in a large tank and a shark eats 461 of them in one sitting. If the shark continues this pattern and only eats when there are 461 or more fish to consume, how many fish will be leftover after its dinner?

Mixtral 8x22B:

     Reasoning: The shark eats 461 fish in one sitting, so there will be 535-461 = <<535-461=74>>74 fish leftover after its first dinner.
    Since the shark only eats when there are 461 or more fish to consume, it will not eat any more fish after its first dinner.
    ### Answer: 74

Expected answer: 74

Correct? Yes

🔗 Problem

Problem: A baker baked a total of 928 cookies. He decided to distribute equal amounts of cookies to 186 orphanages. After giving out as many entire sets of cookies as possible to each orphanage, how many cookies does the baker have left?

Mixtral 8x22B:

     Reasoning: The baker can give out 928/186 = <<928/186=5>>5 cookies to each orphanage.
    The baker has 928 - (186*5) = <<928-(186*5)=28>>28 cookies left.
    ### Answer: 28

Expected answer: 184

Correct? No

🔗 Problem

Problem: A pizza store has 975 slices of pizza ready to serve. If each pizza box can contain 196 slices, how many left over slices will there be after all the pizza boxes are full?

Mixtral 8x22B:

     Reasoning: The pizza store can fill 975/196 = <<975/196=4.974489795918367>>4 full pizza boxes with 196 slices each.
    The pizza store will have 975 - (4 \* 196) = <<975-(4\*196)=111>>111 left over slices.
    ### Answer: 111

Expected answer: 191

Correct? No

🔗 Problem

Problem: A wizard casts a spell to summon 932 magical stones. Each powerful creature he summons requires 193 stones. After summoning several creatures, how many stones will the wizard have left?

Mixtral 8x22B:

     Reasoning: The wizard can summon 932/193 = <<932/193=4>>4 creatures with the stones he has.
    After summoning 4 creatures, the wizard will have 932 - (4 \* 193) = <<932-(4\*193)=108>>108 stones left.
    ### Answer: 108

Expected answer: 160

Correct? No

🔗 Problem

Problem: A builder has a job to install 660 square foot tiles in a house. Each tile can cover 335 square feet. After installing tiles evenly across the available space, how many square feet will the last tile need to cover?

Mixtral 8x22B:

     Reasoning: The builder can install 660/335 = <<660/335=1.96989698969897>>1.96989698969897 tiles completely.
    Since the builder can't install a fraction of a tile, they will install 1 tile completely and the last tile will need to cover the remaining area.
    The remaining area is 660 - (1 \* 335) = <<660-(1\*335)=325>>325 square feet.
    ### Answer: 325

Expected answer: 325

Correct? Yes

🔗 Follow-up

Problem: A builder realizes that he made a mistake and the tiles can actually cover 337 square feet instead of 335 square feet. Given the same total area of 660 square feet, how many square feet will the last tile now need to cover?

Mixtral 8x22B:

     Reasoning: The builder can install 660/337 = <<660/337=1.95845697329377>>1.95845697329377 tiles completely.
    Since the builder can't install a fraction of a tile, they will install 1 tile completely and the last tile will need to cover the remaining area.
    The remaining area is 660 - (1 \* 337) = <<660-(1\*337)=323>>323 square feet.
    ### Answer: 323

Expected answer: 323

Correct? Yes

🔗 Problem

Problem: A juice company produced 473 gallons of juice. If the company bottles the juice in 22-gallon containers, how many gallons of juice will be left after filling up all the containers?

Mixtral 8x22B:

     Reasoning: The company can fill up 473/22 = <<473/22=21.5>>21 containers with 22 gallons each.
    The company will have 473 - (21\*22) = <<473-(21\*22)=11>>11 gallons of juice left over.
    ### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: A juice company initially thought they produced 473 gallons of juice, but they realized they actually produced 599 gallons. They used the same 22-gallon containers as before. After filling up all the containers, how many gallons of juice do they now have left over?

Mixtral 8x22B:

     Reasoning: The company can fill up 599/22 = <<599/22=27.227272727272725>>27 containers with 22 gallons each.
    The company will have 599 - (27\*22) = <<599-(27\*22)=13>>13 gallons of juice left over.
    ### Answer: 13

Expected answer: 5

Correct? No

🔗 Problem

Problem: A toy factory produced 979 toy cars in a day. If they packed these cars into boxes, each containing 108 cars, how many toy cars will be left unpacked at the end of the day?

Mixtral 8x22B:

     Reasoning: The factory produced 979 toy cars and packed them into boxes containing 108 cars each.
    To find out how many boxes they can fill, we divide the total number of cars by the number of cars per box: 979/108 = <<979/108=9>>9 boxes with 108 cars each.
    To find out how many cars will be left unpacked, we multiply the number of boxes by the number of cars per box and subtract that from the total number of cars: 9*108 = <<9*108=972>>972 cars packed, 979-972 = <<979-972=7>>7 cars left unpacked.
    ### Answer: 7

Expected answer: 7

Correct? Yes

🔗 Follow-up

Problem: The toy factory now produced 979 toy cars in a day and decided to package these cars into larger boxes, each containing 684 cars. After all the cars have been packed into the larger boxes, how many toy cars would be left unpacked at the end of the day?

Mixtral 8x22B:

     Reasoning: The factory produced 979 toy cars and packed them into larger boxes containing 684 cars each.
    To find out how many boxes they can fill, we divide the total number of cars by the number of cars per box: 979/684 = <<979/684=1.4312865497076023>>1 box with 684 cars and 295 cars left unpacked.
    Since they can only fill one box, they will have 979-684 = <<979-684=295>>295 cars left unpacked.
    ### Answer: 295

Expected answer: 295

Correct? Yes

🔗 Problem

Problem: A crayon factory has the capacity to make 994 crayons in one operation. However, each box only holds 425 crayons. If they operate at full capacity, how many crayons will be left out of the boxes after the operation?

Mixtral 8x22B:

     Reasoning: The factory can make 994 crayons in one operation.
    Each box holds 425 crayons, so they can fill 994/425 = <<994/425=2>>2 boxes with crayons.
    The remaining crayons will be 994 - (2 \* 425) = <<994-(2\*425)=144>>144 crayons.
    ### Answer: 144

Expected answer: 144

Correct? Yes

🔗 Follow-up

Problem: Let's now consider that the crayon factory only made 223 crayons in one operation, while each box still holds 425 crayons. Again, how many crayons are left over and fail to make it into a box?

Mixtral 8x22B:

     Reasoning: The factory made 223 crayons in one operation.
    Each box holds 425 crayons, so they can't fill any boxes with crayons.
    The remaining crayons will be 223 - (0 \* 425) = <<223-(0\*425)=223>>223 crayons.
    ### Answer: 223

Expected answer: 223

Correct? Yes

🔗 Problem

Problem: A wildlife reserve has 740 tigers. The reserve is divided into different zones, and each zone can only hold up to 696 tigers. If tigers are distributed evenly among the zones, how many tigers will be left in the last zone?

Mixtral 8x22B:

     Reasoning: The reserve can hold 740/696 = <<740/696=1.063218452381>>1.063218452381 zones of tigers. Since we can't have a fraction of a zone, we'll round down to 1 full zone.
    Each zone can hold 696 tigers, so 1 full zone will hold 696 tigers.
    The remaining tigers will be in the last zone, which is 740 - 696 = <<740-696=44>>44 tigers.
    ### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Follow-up

Problem: Consider the wildlife reserve again. This time, however, the zones have been expanded and each can now accommodate up to 908 tigers. If the 740 tigers are distributed evenly among the expanded zones, how many tigers will be left in the last zone?

Mixtral 8x22B:

     Reasoning: The reserve can hold 740/908 = <<740/908=0.814980077098>>0.814980077098 zones of tigers. Since we can't have a fraction of a zone, we'll round down to 0 full zones.
    Each zone can hold 908 tigers, so 0 full zones will hold 0 tigers.
    The remaining tigers will be in the last zone, which is 740 - 0 = <<740-0=740>>740 tigers.
    ### Answer: 740

Expected answer: 740

Correct? Yes

🔗 Problem

Problem: A hat shop makes 830 hats every week. In order to make special edition boxes, the shop plans to put 421 hats in each box. If all the hats are evenly distributed among the boxes, how many hats will be left over?

Mixtral 8x22B:

     Reasoning: The hat shop can make 830/421 = <<830/421=2>>2 boxes of hats.
    The hat shop will have 830 - (2 \* 421) = <<830-(2\*421)=-1>>830 - 842 = -11 hats left over. However, since it is not possible to have a negative number of hats, this means that the hat shop will not have enough hats to make a third box.
    Therefore, the hat shop will have 830 - (2 \* 421) = <<830-(2\*421)=89>>89 hats left over.
    ### Answer: 89

Expected answer: 409

Correct? No

🔗 Problem

Problem: There are 871 fish in a lake. A fisherman catches 575 fish every month. If the fish repopulate at the same rate that the fisherman is depleting them, how many fish will be left after a month?

Mixtral 8x22B:

     Reasoning: The fisherman catches 575 fish every month, and the fish repopulate at the same rate. Therefore, the number of fish in the lake will remain the same after a month.
    871 - 575 = <<871-575=296>>296 fish will be left after a month.
    ### Answer: 296

Expected answer: 296

Correct? Yes

🔗 Problem

Problem: There are 891 beach balls, and every beach bag can fit 119 beach balls. If all the beach balls are evenly placed into the bags, how many beach balls will not fit and left over?

Mixtral 8x22B:

     Reasoning: 891/119 = <<891/119=7>>7 full bags with 119 beach balls each.
    891 - (7*119) = <<891-(7*119)=66>>66 beach balls left over.
    ### Answer: 66

Expected answer: 58

Correct? No

🔗 Problem

Problem: There are 544 stars in a particular constellation. These stars are grouped into smaller clusters of 446 stars each. If these clusters are evenly split, how many stars will remain ungrouped?

Mixtral 8x22B:

     Reasoning: The number of clusters is 544/446 = <<544/446=1>>1 with a remainder of 98.
    There will be 98 stars remaining ungrouped.
    ### Answer: 98

Expected answer: 98

Correct? Yes

🔗 Follow-up

Problem: Considering the previous scenario with the constellation, suppose there were only 278 stars in the constellation instead of 544, and they were still to be grouped into smaller clusters of 446 stars each. If the clusters are evenly distributed, how many stars will now remain ungrouped?

Mixtral 8x22B:

     Reasoning: Since there are only 278 stars, and each cluster requires 446 stars, there will be no clusters formed.
    All 278 stars will remain ungrouped.
    ### Answer: 278

Expected answer: 278

Correct? Yes

🔗 Problem

Problem: A manufacturer produces 805 socks in one shift. They are packaged into sets of 132 each. After the packaging, how many socks will remain unpackaged?

Mixtral 8x22B:

     Reasoning: The manufacturer can package 805/132 = <<805/132=6>>6 sets of socks.
    The remaining socks will be 805 - (6*132) = <<805-(6*132)=17>>17.
    ### Answer: 17

Expected answer: 13

Correct? No

🔗 Problem

Problem: An astronomy club has 759 members that want to view a rare celestial event through their club's telescope. However, the telescope can only handle 228 people viewing the event each night. If they distribute the viewing evenings evenly amongst all members, how many people will view the event on the final night?

Mixtral 8x22B:

     Reasoning: The total number of members is 759, and the telescope can handle 228 people each night.
    To find out how many nights are needed, we divide the total number of members by the number of people that can view each night: 759/228 = <<759/228=3.328069767441767>>3.328069767441767.
    Since we can't have a fraction of a night, we round up to the nearest whole number, which is 4 nights.
    To find out how many people will view the event on the final night, we subtract the number of people that can view each night from the total number of members: 759 - (228*3) = <<759-(228*3)=87>>87.
    ### Answer: 87

Expected answer: 75

Correct? No

🔗 Problem

Problem: A postman has to deliver 891 letters. Each mailbox can only hold 616 letters. If he puts equal numbers of letters in each mailbox, how many letters will remain in the last mailbox?

Mixtral 8x22B:

     Reasoning: The postman can put 891/616 = <<891/616=1>>1 full mailbox of letters.
    The remaining letters are 891 - 616 = <<891-616=275>>275.
    Since each mailbox can only hold 616 letters, the last mailbox will hold 275 letters.
    ### Answer: 275

Expected answer: 275

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, assuming the postman had to originally deliver 524 letters instead of 891, and each mailbox can still only accommodate 616 letters. How many letters will remain in the last mailbox now?

Mixtral 8x22B:

     Reasoning: The postman can put 524/616 = <<524/616=0>>0 full mailboxes of letters.
    The remaining letters are 524 - 0*616 = <<524-0*616=524>>524.
    Since each mailbox can only hold 616 letters, the last mailbox will hold 524 letters.
    ### Answer: 524

Expected answer: 524

Correct? Yes

🔗 Problem

Problem: A total of 941 flies are jumping around the pond. Every time a frog jumps, it eats exactly 258 flies. After a series of jumps where each jump the frog eats the same number of flies, how many flies are left?

Mixtral 8x22B:

     Reasoning: To find out how many flies are left, we need to know how many jumps the frog made. Since the number of flies eaten by the frog in each jump is a multiple of 258, we can divide the total number of flies by 258 to find out how many jumps the frog made.

    941 / 258 = <<941/258=3.647286516396123>>3 with a remainder of 197.

    This means that the frog made 3 jumps and ate 3 \* 258 = <<3\*258=774>>774 flies.

    Therefore, there are 941 - 774 = <<941-774=167>>167 flies left.

    ### Answer: 167

Expected answer: 167

Correct? Yes

🔗 Follow-up

Problem: Previously, a frog ate flies from a total of 941 flies with 258 flies eaten in each jump. Now, consider that instead of 941 flies there initially were 146 flies hopping around the pond. Given that the frog still eats 258 flies in each jump, how many flies would be left after a series of jumps?

Mixtral 8x22B:

     Reasoning: Since the frog eats 258 flies in each jump, and there are only 146 flies initially, the frog will not be able to make any jumps and eat any flies. Therefore, all 146 flies will be left.

    ### Answer: 146

Expected answer: 146

Correct? Yes

🔗 Problem

Problem: A large park has a capacity of 991 spaces for cars to park. If all the spaces are evenly distributed between 66 rows, how many spare spaces will be there in the last row after max spaces are filled?

Mixtral 8x22B:

     Reasoning: The total number of spaces is 991, and there are 66 rows. To find out how many spaces are in each row, we divide the total number of spaces by the number of rows: 991/66 = <<991/66=15.015151515151515>>15.015151515151515. Since we can't have a fraction of a space, we round down to the nearest whole number, which is 15.

    Now, to find out how many spare spaces there will be in the last row, we multiply the number of rows by the number of spaces per row and subtract that from the total number of spaces: 66*15 = <<66\*15=990>>990.

    So, there will be 991 - 990 = <<991-990=1>>1 spare space in the last row.
    ### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: In the same large park, suppose they restructure the parking with larger spaces to accommodate bigger vehicles. Now, the adjusted parking lot configurations can hold 471 cars in each row. After filling up the rows, how many spare spaces would be there in the last row now?

Mixtral 8x22B:

     Reasoning: The total number of spaces is still 991, but now there are 471 spaces in each row. To find out how many rows there are, we divide the total number of spaces by the number of spaces per row: 991/471 = <<991/471=2.104033970275966>>2.104033970275966. Since we can't have a fraction of a row, we round down to the nearest whole number, which is 2.

    Now, to find out how many spare spaces there will be in the last row, we multiply the number of rows by the number of spaces per row and subtract that from the total number of spaces: 2*471 = <<2\*471=942>>942.

    So, there will be 991 - 942 = <<991-942=49>>49 spare spaces in the last row.
    ### Answer: 49

Expected answer: 49

Correct? Yes

🔗 Problem

Problem: There are 193 liters of water that need to be divided evenly among 167 water bottles. If each bottle holds the same amount of water, how many liters overflows and can't be distributed to the bottles?

Mixtral 8x22B:

     Reasoning: 193 liters / 167 bottles = <<193/167=1.155688502994012>>1.155688502994012 liters per bottle.
    Since the amount of water per bottle is not a whole number, there will be some water that can't be distributed evenly.
    To find out how much water overflows, we can multiply the number of bottles by the whole number part of the amount of water per bottle, and then subtract that from the total amount of water.
    167 bottles \* 1 liter = <<167\*1=167>>167 liters.
    193 liters - 167 liters = <<193-167=26>>26 liters overflows.
    ### Answer: 26 liters

Expected answer: 26

Correct? Yes

🔗 Follow-up

Problem: If, instead of 193 liters of water, there were 857 liters of water that needed to be divided evenly among the 167 water bottles, how many liters would overflow and can't be distributed to the bottles now?

Mixtral 8x22B:

     Reasoning: 857 liters / 167 bottles = <<857/167=5.131736526946108>>5.131736526946108 liters per bottle.
    Since the amount of water per bottle is not a whole number, there will be some water that can't be distributed evenly.
    To find out how much water overflows, we can multiply the number of bottles by the whole number part of the amount of water per bottle, and then subtract that from the total amount of water.
    167 bottles \* 5 liters = <<167\*5=835>>835 liters.
    857 liters - 835 liters = <<857-835=22>>22 liters overflows.
    ### Answer: 22 liters

Expected answer: 22

Correct? Yes

🔗 Problem

Problem: A dragon lays 996 jewel eggs in rows. Each row can hold 319 eggs. If the dragon distributes the eggs evenly among the rows, how many eggs would be left over to be put in the last row?

Mixtral 8x22B:

     Reasoning: The dragon can fill 996/319 = <<996/319=3>>3 rows completely with 319 eggs each.
    The dragon would have 996 - (3 \* 319) = <<996-(3\*319)=39>>39 eggs left over to be put in the last row.
    ### Answer: 39

Expected answer: 39

Correct? Yes

🔗 Follow-up

Problem: Now, consider if the dragon had only laid 8 jewel eggs and continued to distribute them among rows that could hold 319 eggs. How many eggs would be left over to be put in the last row?

Mixtral 8x22B:

     Reasoning: The dragon can fill 0 rows completely with 319 eggs each.
    The dragon would have 8 - (0 \* 319) = <<8-(0\*319)=8>>8 eggs left over to be put in the last row.
    ### Answer: 8

Expected answer: 8

Correct? Yes

🔗 Problem

Problem: A lamp manufacturer produces 691 bulb units. If a pack includes 205 bulbs, how many bulbs would be left unpacked after filling as many packs as possible?

Mixtral 8x22B:

     Reasoning: The manufacturer can fill 691/205 = <<691/205=3.370731707317073>>3 packs with 205 bulbs each.
    Since the manufacturer cannot fill a partial pack, they will only fill 3 packs, leaving 691 - (3*205) = <<691-(3*205)=91>>91 bulbs unpacked.
    ### Answer: 91

Expected answer: 76

Correct? No

🔗 Problem

Problem: On a farm, there are 330 bales of hay to be stored evenly in barns. Each barn can store up to 259 bales. After filling up the barns as evenly as possible, how many bales of hay will be left for the last barn?

Mixtral 8x22B:

     Reasoning: To find out how many bales of hay will be left for the last barn, we need to divide the total number of bales by the capacity of each barn and find the remainder.

    330 ÷ 259 = <<330÷259=1>>1 with a remainder of <<330-259=71>>71 bales.

    So, there will be 71 bales of hay left for the last barn.

    ### Answer: 71

Expected answer: 71

Correct? Yes

🔗 Problem

Problem: A construction company is installing 166 windows on a building. They have determined that one installation team can install 137 windows per day. If all windows are equally distributed amongst teams each day, how many windows will remain for the team to install on the next day?

Mixtral 8x22B:

     Reasoning: The construction company can install 166/137 = <<166/137=1.2116788461315>>1.2116788461315 teams worth of windows per day.
    Since they can't have a fraction of a team, they will have 1 team installing windows for 1 day and then have 166 - 137 = <<166-137=29>>29 windows remaining for the next day.
    ### Answer: 29

Expected answer: 29

Correct? Yes

🔗 Problem

Problem: There are 533 campers coming for a camping event at a park. Each tent can host 445 people. If the campers are evenly distributed among the tents, how many campers will be left over after all the tents are filled?

Mixtral 8x22B:

     Reasoning: The number of tents needed to accommodate all the campers is 533/445 = <<533/445=1.197752808988764>>1.197752808988764. Since we can't have a fraction of a tent, we need to round up to the nearest whole number, which is 2 tents.
    The number of campers that can be accommodated in 2 tents is 2*445 = <<2\*445=890>>890.
    The number of campers left over after all the tents are filled is 533-890 = <<533-890=-357>>-357. However, since we can't have a negative number of campers, this means that there are not enough tents to accommodate all the campers.
    Therefore, the number of campers left over after all the tents are filled is 533-445 = <<533-445=88>>88.
    ### Answer: 88

Expected answer: 88

Correct? Yes

🔗 Follow-up

Problem: Now suppose that the park upgraded their tents and each tent can now host 886 people. With the same group of 533 campers, how many campers will be left over after all the tents are filled?

Mixtral 8x22B:

     Reasoning: The number of tents needed to accommodate all the campers is 533/886 = <<533/886=0.6014634146341463>>0.6014634146341463. Since we can't have a fraction of a tent, we need to round up to the nearest whole number, which is 1 tent.
    The number of campers that can be accommodated in 1 tent is 886.
    The number of campers left over after all the tents are filled is 533-886 = <<533-886=-353>>-353. However, since we can't have a negative number of campers, this means that there are not enough campers to fill the tent.
    Therefore, the number of campers left over after all the tents are filled is 0.
    ### Answer: 0

Expected answer: 533

Correct? No

🔗 Problem

Problem: There are 999 seashells collected from a beach. They are grouped in beach-themed souvenir sets, each containing 474 shells. After grouping, how many seashells will be left without a set?

Mixtral 8x22B:

     Reasoning: 999/474 = <<999/474=2>>2 sets can be made with 474 shells each.
    2*474 = <<2*474=948>>948 shells will be used in the sets.
    999-948 = <<999-948=51>>51 shells will be left without a set.
    ### Answer: 51

Expected answer: 51

Correct? Yes

🔗 Follow-up

Problem: In continuation of the previous scenario with seashells, imagine instead that there were initially only 234 seashells collected from the beach, but the souvenir sets are still made up of 474 shells each. How many shells would be left after attempting to form these sets?

Mixtral 8x22B:

     Reasoning: Since there are only 234 shells, it is not possible to make any sets of 474 shells.
    Therefore, all 234 shells will be left without a set.
    ### Answer: 234

Expected answer: 234

Correct? Yes

🔗 Problem

Problem: A tailor has 366 meters of fabric. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?

Mixtral 8x22B:

     Reasoning: The tailor can make 366/160 = <<366/160=2>>2 skirts.
    After making 2 skirts, the tailor will have 366 - (2*160) = <<366-(2*160)=46>>46 meters of fabric left.
    ### Answer: 46

Expected answer: 46

Correct? Yes

🔗 Follow-up

Problem: A tailor realized that she has made a mistake. Actually, she has only 21 meters of fabric at her disposal, not 366. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?

Mixtral 8x22B:

      Reasoning: The tailor cannot make any skirts with only 21 meters of fabric, as each skirt requires 160 meters.
    Therefore, the tailor will have 21 meters of fabric left.
    ### Answer: 21

Expected answer: 21

Correct? Yes

🔗 Problem

Problem: A toymaker made 993 dolls to be packed in boxes for shipment. Each box can hold 327 dolls. How many dolls will she have left once all the boxes are packed to their capacities?

Mixtral 8x22B:

     Reasoning: The toymaker can pack 993/327 = <<993/327=3>>3 boxes to their full capacity.
    The toymaker will have 993 - (327\*3) = <<993-(327\*3)=32>>32 dolls left.
    ### Answer: 32

Expected answer: 12

Correct? No

🔗 Problem

Problem: A child has 964 stuffed animals that they want to divide equally among their 839 friends. If they distribute the stuffed animals evenly, how many will the child have left over?

Mixtral 8x22B:

     Reasoning: The child can give 964/839 = <<964/839=1.149>>1 stuffed animal to each friend with a remainder of 964 - (839 \* 1) = <<964-(839\*1)=125>>125 stuffed animals left over.
    ### Answer: 125

Expected answer: 125

Correct? Yes

🔗 Follow-up

Problem: The child from the previous problem has gotten even more stuffed animals and now has a total of 964 stuffed animals. If they still want to divide them equally among their 892 friends, how many stuffed animals will be left over after distributing them?

Mixtral 8x22B:

     Reasoning: The child can give 964/892 = <<964/892=1.080>>1 stuffed animal to each friend with a remainder of 964 - (892 \* 1) = <<964-(892\*1)=72>>72 stuffed animals left over.
    ### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Problem

Problem: A toy factory produces 369 teddy bears in a day. The bears are packaged in boxes and each box can hold 270 teddy bears. How many teddy bears will be left if all the teddy bears are evenly packed in the boxes?

Mixtral 8x22B:

     Reasoning: The factory can pack 369/270 = <<369/270=1>>1 full box of teddy bears.
    The remaining teddy bears will be 369 - (270*1) = <<369-(270*1)=99>>99.
    ### Answer: 99

Expected answer: 99

Correct? Yes

🔗 Follow-up

Problem: Earlier, the toy factory produced 369 teddy bears in a day and they were packaged in boxes with each box holding 270 teddy bears. Now, suppose that the toy factory increased its production and now makes 813 teddy bears in a day while still packing them in boxes that can hold 270 teddy bears. How many teddy bears will be left now if all the teddy bears are evenly packed in the boxes?

Mixtral 8x22B:

     Reasoning: The factory can pack 813/270 = <<813/270=3>>3 full boxes of teddy bears.
    The remaining teddy bears will be 813 - (270*3) = <<813-(270*3)=63>>63.
    ### Answer: 63

Expected answer: 3

Correct? No

🔗 Problem

Problem: A village has a yearly tradition of building snowmen. This year, the villagers make 804 snowballs to build their snowmen. Each snowman needs exactly 184 snowballs. After all snowmen are built, how many snowballs are left leftover?

Mixtral 8x22B:

     Reasoning: The number of snowmen that can be built is 804/184 = <<804/184=4.37>>4.37. Since we can't build a fraction of a snowman, we can only build 4 snowmen.
    The number of snowballs used to build 4 snowmen is 4*184 = <<4\*184=736>>736.
    The number of snowballs left leftover is 804-736 = <<804-736=68>>68.
    ### Answer: 68

Expected answer: 68

Correct? Yes

🔗 Follow-up

Problem: In the same village, another year, there were only 444 snowballs made to build the snowmen. If each snowman still requires exactly 184 snowballs, how many snowballs would be left over after as many complete snowmen as possible are built?

Mixtral 8x22B:

     Reasoning: The number of snowmen that can be built is 444/184 = <<444/184=2.41>>2.41. Since we can't build a fraction of a snowman, we can only build 2 snowmen.
    The number of snowballs used to build 2 snowmen is 2*184 = <<2\*184=368>>368.
    The number of snowballs left leftover is 444-368 = <<444-368=76>>76.
    ### Answer: 76

Expected answer: 76

Correct? Yes

🔗 Problem

Problem: A jewelry store has 843 rings to be placed equally into 839 boxes. If each box is filled, how many rings will be left over?

Mixtral 8x22B:

     Reasoning: The number of rings that can be placed in each box is 843/839 = <<843/839=1>>1 ring per box.
    The number of rings that will be left over is 843 - (839*1) = <<843-(839*1)=4>>4 rings.
    ### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: The jewelry store just received an additional shipment and now has a total of 843 rings. However, this time they must be equally placed into 804 boxes. If every box is filled, how many rings will be left over now?

Mixtral 8x22B:

     Reasoning: The number of rings that can be placed in each box is 843/804 = <<843/804=1>>1 ring per box.
    The number of rings that will be left over is 843 - (804*1) = <<843-(804*1)=39>>39 rings.
    ### Answer: 39

Expected answer: 39

Correct? Yes

🔗 Problem

Problem: A fireplace manufacturing company has 819 bricks to build fireplaces, and each fireplace requires 583 bricks. If they build as many fireplaces as possible, how many bricks will they have left over?

Mixtral 8x22B:

     Reasoning: The company can build 819/583 = <<819/583=1>>1 fireplace with no bricks left over.
    The company will have 819 - 583 = <<819-583=236>>236 bricks left over.
    ### Answer: 236

Expected answer: 236

Correct? Yes

🔗 Follow-up

Problem: The company received a new delivery of bricks, now they have 486 bricks in total. If they continue making fireplaces, each requiring 583 bricks as before, how many bricks will they have left after building as many full fireplaces as they can?

Mixtral 8x22B:

     Reasoning: The company can build 486/583 = <<486/583=0>>0 fireplaces with no bricks left over.
    The company will have 486 - 0*583 = <<486-0*583=486>>486 bricks left over.
    ### Answer: 486

Expected answer: 486

Correct? Yes

🔗 Problem

Problem: A marshmallow factory produces 998 marshmallows per minute. However, the packaging machine can only hold 957 marshmallows at a time. What will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled?

Mixtral 8x22B:

     Reasoning: The factory produces 998 marshmallows per minute, and the packaging machine can hold 957 marshmallows at a time.
    The number of marshmallows left un-packaged in a minute will be 998 - 957 = <<998-957=41>>41 marshmallows.
    ### Answer: 41

Expected answer: 41

Correct? Yes

🔗 Follow-up

Problem: The marshmallow factory upgraded its packaging machine and now it can hold 804 marshmallows at a time instead of 957. If the factory continues to produce 998 marshmallows per minute, what will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity?

Mixtral 8x22B:

     Reasoning: The factory produces 998 marshmallows per minute, and the upgraded packaging machine can hold 804 marshmallows at a time.
    The number of marshmallows left un-packaged in a minute will be 998 - 804 = <<998-804=194>>194 marshmallows.
    ### Answer: 194

Expected answer: 194

Correct? Yes

🔗 Problem

Problem: There are 984 roses in the castle's garden. Princess likes to place 426 roses in every tribute for her loyal subjects. If she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?

Mixtral 8x22B:

     Reasoning: Princess can create 984/426 = <<984/426=2>>2 full tributes.
    Princess will have 984 - 2*426 = <<984-2*426=132>>132 roses left undistributed.
    ### Answer: 132

Expected answer: 132

Correct? Yes

🔗 Follow-up

Problem: In the same castle's garden, there were originally 984 roses, but the princess has decided to use only 730 roses for each tribute to her loyal subjects instead of the previous 426. Now, if she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?

Mixtral 8x22B:

     Reasoning: Princess can create 984/730 = <<984/730=1>>1 full tribute.
    Princess will have 984 - 1*730 = <<984-1*730=254>>254 roses left undistributed.
    ### Answer: 254

Expected answer: 254

Correct? Yes

🔗 Problem

Problem: A song has 334 words in it. If each line in the song has 23 words, how many words would be in the incomplete line at the end of the song?

Mixtral 8x22B:

     Reasoning: The song has 334/23 = <<334/23=14>>14 complete lines.
    The incomplete line at the end of the song would have 334 - (14 \* 23) = <<334-(14\*23)=12>>12 words.
    ### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: Suppose the song writer decided to change the structure of the song and made each line contain 314 words instead. Now with the same total of 334 words, how many words would be left in the incomplete line at the end of the song?

Mixtral 8x22B:

     Reasoning: The song would have 334/314 = <<334/314=1>>1 complete line.
    The incomplete line at the end of the song would have 334 - 314 = <<334-314=20>>20 words.
    ### Answer: 20

Expected answer: 20

Correct? Yes

🔗 Problem

Problem: A teacher has 928 pages of study materials that he wants to print for his students. His printer can only print 336 pages in one go. After filling the printer a number of times, how many pages will he have left over to print?

Mixtral 8x22B:

     Reasoning: The teacher can print 928/336 = <<928/336=2>>2 full batches of pages.
    The teacher will have 928 - (2 \* 336) = <<928-(2\*336)=256>>256 pages left over to print.
    ### Answer: 256

Expected answer: 256

Correct? Yes

🔗 Follow-up

Problem: In the same scenario, suppose the teacher decides to use a different printer that can print 409 pages in one go. After filling this printer a number of times, how many pages will he have left over to print?

Mixtral 8x22B:

     Reasoning: The teacher can print 928/409 = <<928/409=2>>2 full batches of pages.
    The teacher will have 928 - (2 \* 409) = <<928-(2\*409)=109>>109 pages left over to print.
    ### Answer: 109

Expected answer: 110

Correct? No

🔗 Problem

Problem: Scientists have spotted 972 sharks in an area. The scientists tag groups of 667 sharks each. How many sharks are left untagged after the scientists finish tagging as many complete groups as possible?

Mixtral 8x22B:

     Reasoning: The scientists can tag 972/667 = <<972/667=1>>1 complete group of 667 sharks.
    The number of sharks left untagged is 972 - 667 = <<972-667=305>>305.
    ### Answer: 305

Expected answer: 305

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous question, the scientists later spotted a new group of 758 sharks in a different area. Again, they were trying to tag the sharks in groups of 667. How many sharks were left untagged after all complete groups have been tagged in this new area?

Mixtral 8x22B:

     Reasoning: The scientists can tag 758/667 = <<758/667=1>>1 complete group of 667 sharks.
    The number of sharks left untagged is 758 - 667 = <<758-667=91>>91.
    ### Answer: 91

Expected answer: 91

Correct? Yes

🔗 Problem

Problem: There are 686 blocks of cheese in the dairy shop. Each box can contain 349 blocks of cheese. If all the blocks of cheese are evenly distributed in the boxes, how many blocks of cheese would be left over after all the boxes are filled?

Mixtral 8x22B:

     Reasoning: 686/349 = <<686/349=2>>2 boxes can be filled completely with 349 blocks of cheese each.
    686 - (2 \* 349) = <<686-(2\*349)=686-698=-12>>-12 blocks of cheese would be left over.
    Since it is not possible to have a negative number of blocks of cheese, there must be an error in the calculation.
    686 - (2 \* 349) = <<686-(2\*349)=686-698=0>>0 blocks of cheese would be left over.
    ### Answer: 0

Expected answer: 337

Correct? No

🔗 Problem

Problem: There were 513 centimeters of snowfall recorded this winter. A snowplow can clear up to 170 centimeters of snow at a time. If the snowplow runs continuously, how many centimeters of snow will be left over after the final pass?

Mixtral 8x22B:

     Reasoning: The snowplow can clear 513/170 = <<513/170=3>>3 full passes of snow.
    After 3 full passes, the snowplow will have cleared 3*170 = <<3*170=510>>510 centimeters of snow.
    There will be 513-510 = <<513-510=3>>3 centimeters of snow left over after the final pass.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Suppose that instead of 513 centimeters, there were 460 centimeters of snowfall this winter. If the same snowplow, which can clear up to 170 centimeters of snow at a time, runs continuously, how many centimeters of snow would then be left over after the final pass?

Mixtral 8x22B:

     Reasoning: The snowplow can clear 460/170 = <<460/170=2>>2 full passes of snow.
    After 2 full passes, the snowplow will have cleared 2*170 = <<2*170=340>>340 centimeters of snow.
    There will be 460-340 = <<460-340=120>>120 centimeters of snow left over after the final pass.
    ### Answer: 120

Expected answer: 120

Correct? Yes

🔗 Problem

Problem: A compass maker has 661 needles to install in compasses. Each compass uses 510 needles. After installing as many full compasses as he can, how many needles will the compass maker have left?

Mixtral 8x22B:

     Reasoning: The compass maker can make 661/510 = <<661/510=1>>1 full compass.
    The compass maker will have 661 - 510 = <<661-510=151>>151 needles left.
    ### Answer: 151

Expected answer: 151

Correct? Yes

🔗 Problem

Problem: A furniture factory has manufactured 380 chairs to distribute to its retail shops. Each shop can only hold 310 chairs in its storage. If the factory evenly distributes all the chairs to the shops, how many chairs will be left at the factory?

Mixtral 8x22B:

     Reasoning: The factory can distribute 380/310 = <<380/310=1>>1 full load of chairs to the shops.
    The factory will have 380 - 310 = <<380-310=70>>70 chairs left at the factory.
    ### Answer: 70

Expected answer: 70

Correct? Yes

🔗 Follow-up

Problem: Now suppose the factory decides to distribute these chairs amongst its smaller distributors, each of which can only hold 143 chairs. Now, how many chairs will be left at the factory after distributing them evenly?

Mixtral 8x22B:

     Reasoning: The factory can distribute 380/143 = <<380/143=2>>2 full loads of chairs to the smaller distributors.
    The factory will have 380 - 2*143 = <<380-286=94>>94 chairs left at the factory.
    ### Answer: 94

Expected answer: 94

Correct? Yes

🔗 Problem

Problem: A farmer has gathered 929 tomatoes from his field. He plans to sell them in boxes, with 154 tomatoes in each box. After packing them evenly in boxes, how many tomatoes will be left over?

Mixtral 8x22B:

     Reasoning: The farmer can pack 929/154 = <<929/154=6>>6 boxes of tomatoes.
    The remaining tomatoes will be 929 - (6*154) = <<929-(6*154)=11>>11 tomatoes.
    ### Answer: 11

Expected answer: 5

Correct? No

🔗 Problem

Problem: A sporting goods store has 454 pairs of ice skates in total. The store distributes the skates evenly among 128 boxes. How many pairs of ice skates will be left over after all the boxes are filled up equally?

Mixtral 8x22B:

     Reasoning: The store can fill up 454/128 = <<454/128=3.546875>>3 boxes with 128 skates each.
    The store will have 454 - (3*128) = <<454-(3*128)=62>>62 skates left over.
    ### Answer: 62

Expected answer: 70

Correct? No

🔗 Problem

Problem: A windmill generates 506 units of power per day. Every day, a small village consumes power in increments of 385 units. At the end of the day, after the village has consumed as much power as it can in full increments, how much power is left over?

Mixtral 8x22B:

     Reasoning: The village consumes power in increments of 385 units. To find out how many increments the village can consume, we divide the total power generated by the windmill by the increment size: 506/385 = <<506/385=1>>1 full increment and <<506-385=121>>121 units left over.
    ### Answer: 121 units

Expected answer: 121

Correct? Yes

🔗 Follow-up

Problem: Following the scenario of the windmill and the small village, let's now consider that the windmill had a great day and managed to generate 506 units of power. However, due to development demands, the daily consumption of the village has increased to 920 units. At the end of the day, with the power being consumed in complete units, how much power is left over?

Mixtral 8x22B:

     Reasoning: The village now consumes power in increments of 920 units. Since the windmill only generated 506 units of power, the village cannot consume any power in full increments. Therefore, all 506 units of power generated by the windmill are left over.
    ### Answer: 506 units

Expected answer: 506

Correct? Yes

🔗 Problem

Problem: Superhero Blast Man has 338 energy units in his power cells. Each energy blast he fires uses 16 energy units. After using equal units of energy firing blasts, how many energy units will Blast Man have left in his power cells?

Mixtral 8x22B:

     Reasoning: Blast Man can fire 338/16 = <<338/16=21.125>>21 blasts with 4 energy units left over.
    Blast Man will have 4 energy units left in his power cells.
    ### Answer: 4

Expected answer: 2

Correct? No

🔗 Problem

Problem: A school district has 530 students who need to be transported and each school bus can carry 144 students. If all students are equally spread across the buses, how many students will be on the last school bus?

Mixtral 8x22B:

     Reasoning: The school district can fill 530/144 = <<530/144=3.6805555555555554>>3.68 buses with students.
    Since the school district cannot have a fraction of a bus, they will need to use 4 buses.
    The last bus will have 144 - (530 - (144*3)) = <<144 - (530 - (144*3))=102>>102 students.
    ### Answer: 102

Expected answer: 98

Correct? No

🔗 Problem

Problem: A wizard has 999 spells in his book. He tries to distribute them equally among 951 apprentice wizards but they don't divide evenly. How many spells will the wizard have left after giving out as many as he can to his apprentices?

Mixtral 8x22B:

     Reasoning: The wizard can give out 999/951 = <<999/951=1>>1 spell to each apprentice.
    The wizard will have 999 - 951 = <<999-951=48>>48 spells left after giving out as many as he can to his apprentices.
    ### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: If the wizard had instead 999 spells and he tries to distribute them equally among 801 apprentice wizards, how many spells will the wizard have left after giving out as many as he can to his apprentices?

Mixtral 8x22B:

     Reasoning: The wizard can give out 999/801 = <<999/801=1>>1 spell to each apprentice.
    The wizard will have 999 - 801 = <<999-801=198>>198 spells left after giving out as many as he can to his apprentices.
    ### Answer: 198

Expected answer: 198

Correct? Yes

🔗 Problem

Problem: A scooter manufacturing company has produced 767 scooters. Each delivery truck they use can carry 369 scooters. If they distribute the scooters evenly among the trucks, how many scooters will be left after all the trucks are loaded?

Mixtral 8x22B:

     Reasoning: The company can load 767/369 = <<767/369=2>>2 trucks fully.
    The remaining scooters will be 767 - (2*369) = <<767-(2*369)=29>>29 scooters.
    ### Answer: 29

Expected answer: 29

Correct? Yes

🔗 Problem

Problem: There are 846 water droplets in a cloud. Each raindrop needs 722 droplets to form. If all droplets are used to form raindrops, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Mixtral 8x22B:

     Reasoning: The cloud can form 846/722 = <<846/722=1>>1 complete raindrop.
    The remaining droplets would be 846 - (722*1) = <<846-(722*1)=124>>124.
    ### Answer: 124

Expected answer: 124

Correct? Yes

🔗 Follow-up

Problem: There was a slight miscalculation in the cloud's droplet count. There are actually 846 water droplets in the cloud, but each raindrop needs 442 droplets to form instead of 722. With this updated droplet count per raindrop, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Mixtral 8x22B:

     Reasoning: The cloud can form 846/442 = <<846/442=1>>1 complete raindrop.
    The remaining droplets would be 846 - (442*1) = <<846-(442*1)=404>>404.
    ### Answer: 404

Expected answer: 404

Correct? Yes

🔗 Problem

Problem: Unicorn Village, a magical place where 265 unicorns live, is divided into 146 equal sections where these magical creatures reside. If each section is occupied by an equal number of unicorns, how many unicorns will live in the last incomplete section?

Mixtral 8x22B:

     Reasoning: Since the total number of unicorns (265) is not a multiple of the number of sections (146), there will be an incomplete section.

    First, we need to find out how many unicorns live in each complete section. To do this, we divide the total number of unicorns by the number of sections: 265 / 146 = <<265/146=1.8150684931506848>>1.8150684931506848 (approximately).

    Since we can't have a fraction of a unicorn, we round down to the nearest whole number, which is 1 unicorn per complete section.

    Now, we need to find out how many unicorns will be in the incomplete section. To do this, we multiply the number of complete sections by the number of unicorns per complete section: 145 * 1 = <<145*1=145>>145 unicorns.

    Finally, we subtract the number of unicorns in the complete sections from the total number of unicorns to find out how many unicorns will be in the incomplete section: 265 - 145 = <<265-145=120>>120 unicorns.

    ### Answer: 120

Expected answer: 119

Correct? No

🔗 Problem

Problem: In a game, there are 923 players waiting to enter a match. Only 383 players can enter a match at a time. If players enter matches evenly, how many players will be left waiting after filling all the matches?

Mixtral 8x22B:

     Reasoning: The number of matches that can be filled is 923/383 = <<923/383=2>>2 matches with 383 players each.
    The number of players left waiting is 923 - (2 \* 383) = <<923-(2\*383)=157>>157 players.
    ### Answer: 157

Expected answer: 157

Correct? Yes

🔗 Follow-up

Problem: In the same game, a new day dawns with 456 players waiting to join a match. The match capacity remains the same, permitting 383 players at a time. If players are allocated evenly across the matches, how many players will be left waiting after all available matches are filled?

Mixtral 8x22B:

     Reasoning: The number of matches that can be filled is 456/383 = <<456/383=1>>1 match with 383 players.
    The number of players left waiting is 456 - 383 = <<456-383=73>>73 players.
    ### Answer: 73

Expected answer: 73

Correct? Yes

🔗 Problem

Problem: A pirate ship has 923 cannonballs on board. They want to equally disperse them between 499 different crates. After evenly distributing them as much as possible, how many cannonballs will be left uncrated?

Mixtral 8x22B:

     Reasoning: To find out how many cannonballs will be in each crate, we divide the total number of cannonballs by the number of crates: 923/499 = <<923/499=1.85>>1.85 (rounded to two decimal places). Since we can't have a fraction of a cannonball, we'll round down to the nearest whole number, which is 1 cannonball per crate.

    Now, we multiply the number of crates by the number of cannonballs per crate to find out how many cannonballs will be distributed: 499 * 1 = <<499*1=499>>499 cannonballs.

    Finally, we subtract the number of distributed cannonballs from the total number of cannonballs to find out how many will be left uncrated: 923 - 499 = <<923-499=424>>424 cannonballs.

    ### Answer: 424

Expected answer: 424

Correct? Yes

🔗 Follow-up

Problem: Keeping in line with the previous pirate ship themed problem, let's consider the following scenario: The same pirate ship initially started with 462 cannonballs instead of 923. After the pirates evenly distribute these cannonballs into the same 499 crates, can any be leftover? If so, how many cannonballs will be left uncrated?

Mixtral 8x22B:

     Reasoning: To find out how many cannonballs will be in each crate, we divide the total number of cannonballs by the number of crates: 462/499 = <<462/499=0.926>>0.926 (rounded to three decimal places). Since we can't have a fraction of a cannonball, we'll round down to the nearest whole number, which is 0 cannonballs per crate.

    Since we can't distribute any cannonballs into the crates, all 462 cannonballs will be left uncrated.

    ### Answer: 462

Expected answer: 462

Correct? Yes

🔗 Problem

Problem: A kite store has 530 string spools to attach to their kites. They distribute them to 518 kites, each getting one string spool. After each kite gets a spool, how many spools are left in the store?

Mixtral 8x22B:

     Reasoning: The store distributes 518 spools to the kites.
    The store has 530 - 518 = <<530-518=12>>12 spools left.
    ### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: A dairy farm produces 913 gallons of milk in a day. If every milk jug holds 39 gallons, how many gallons will be left over after all the jugs are filled?

Mixtral 8x22B:

     Reasoning: The dairy farm can fill 913/39 = <<913/39=23.41025641025641>>23 jugs completely.
    The remaining milk will be 913 - (23 \* 39) = <<913-(23\*39)=16>>16 gallons.
    ### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Follow-up

Problem: The dairy farm has adjusted its production and now produces 913 gallons of milk in a day. If they started using larger milk jugs that hold 230 gallons each, how many gallons will be left over after all the jugs are filled?

Mixtral 8x22B:

     Reasoning: The dairy farm can fill 913/230 = <<913/230=3.969565217391304>>3 jugs completely.
    The remaining milk will be 913 - (3 \* 230) = <<913-(3\*230)=143>>143 gallons.
    ### Answer: 143

Expected answer: 223

Correct? No

🔗 Problem

Problem: A doll seller received a shipment of 603 new dolls to put on the shelves. She arranged all the dolls in rows, with 369 dolls in each row. After filling up the rows as much as possible, how many dolls were left unarranged?

Mixtral 8x22B:

     Reasoning: The doll seller can arrange 603/369 = <<603/369=1>>1 full row of dolls.
    The remaining dolls are 603 - 369 = <<603-369=234>>234 dolls.
    ### Answer: 234

Expected answer: 234

Correct? Yes

🔗 Follow-up

Problem: In the previous doll problem, if the doll seller initially received a shipment of 44 new dolls instead of 603, and still arranged them in rows of 369 dolls, how many dolls would be left unarranged after filling up the rows as much as possible?

Mixtral 8x22B:

     Reasoning: The doll seller cannot arrange any full rows of dolls with 44 dolls.
    The remaining dolls are 44 - 0 = <<44-0=44>>44 dolls.
    ### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Problem

Problem: A jewelry maker has 850 beads to make necklaces. They use 631 beads for each necklace. After using as many beads as possible, how many beads will the jewelry maker have left over?

Mixtral 8x22B:

     Reasoning: The jewelry maker can make 850/631 = <<850/631=1>>1 complete necklace.
    The jewelry maker will have 850 - (631*1) = <<850-(631*1)=219>>219 beads left over.
    ### Answer: 219

Expected answer: 219

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker decides to change the design and now each necklace uses only 150 beads instead of 631 beads. After they distribute the 850 beads as equally as possible among the new necklaces, how many beads will the jewelry maker have left over?

Mixtral 8x22B:

     Reasoning: The jewelry maker can make 850/150 = <<850/150=5>>5 complete necklaces.
    The jewelry maker will have 850 - (150*5) = <<850-(150*5)=100>>100 beads left over.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Problem

Problem: A gardener has 952 grapes that he wants to package into boxes. If each box can hold 380 grapes, how many grapes will be left after the gardener has filled as many boxes as possible?

Mixtral 8x22B:

     Reasoning: The gardener can fill 952/380 = <<952/380=2>>2 boxes with grapes.
    The gardener will have 952 - (2*380) = <<952-(2*380)=192>>192 grapes left over.
    ### Answer: 192

Expected answer: 192

Correct? Yes

🔗 Follow-up

Problem: The gardener's friend gave him an additional 183 grapes from his own garden. If the gardener decides to package these grapes as well into boxes with each box holding 380 grapes, how many grapes will remain after packaging the new grapes into as many boxes as possible?

Mixtral 8x22B:

     Reasoning: The gardener now has 192 + 183 = <<192+183=375>>375 grapes.
    The gardener can fill 375/380 = <<375/380=0>>0 boxes with grapes.
    The gardener will have 375 - (0*380) = <<375-(0*380)=375>>375 grapes left over.
    ### Answer: 375

Expected answer: 183

Correct? No

🔗 Problem

Problem: On a treasure map, there are 236 steps mentioned on the guide. If every 44 steps I make leads me to a significant place or clue, how many steps will be left after I reach the last significant place or clue?

Mixtral 8x22B:

     Reasoning: To find out how many significant places or clues there are, we divide the total number of steps by the number of steps between each significant place or clue.

    236 steps / 44 steps per significant place = <<236/44=5.36>>5 significant places (since we can't have a fraction of a significant place, we round down to the nearest whole number).

    Now, to find out how many steps will be left after reaching the last significant place, we multiply the number of significant places by the number of steps between each significant place and subtract that from the total number of steps.

    5 significant places * 44 steps per significant place = <<5*44=220>>220 steps.

    236 steps - 220 steps = <<236-220=16>>16 steps will be left after reaching the last significant place.

    ### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Problem

Problem: Sarah blew 932 bubbles using her new bubble machine. The machine is designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Mixtral 8x22B:

     Reasoning: Sarah blew 932 bubbles, and the machine forms groups of 507 bubbles each.
    The machine formed 932/507 = <<932/507=1>>1 complete group of 507 bubbles.
    The remaining bubbles in the final, incomplete group are 932 - 507 = <<932-507=425>>425 bubbles.
    ### Answer: 425

Expected answer: 425

Correct? Yes

🔗 Follow-up

Problem: Suppose Sarah uses her bubble machine again, this time to blow 904 bubbles. The machine is still designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Mixtral 8x22B:

     Reasoning: Sarah blew 904 bubbles, and the machine forms groups of 507 bubbles each.
    The machine formed 904/507 = <<904/507=1>>1 complete group of 507 bubbles.
    The remaining bubbles in the final, incomplete group are 904 - 507 = <<904-507=397>>397 bubbles.
    ### Answer: 397

Expected answer: 397

Correct? Yes

🔗 Problem

Problem: At the park, there are 931 kids who want to use the swings. Each swing set can accommodate 34 kids at a time. If all the swing sets are filled continuously, how many kids will be waiting for their turn after all the swing sets are occupied?

Mixtral 8x22B:

     Reasoning: The number of kids that can be accommodated at a time is 931/34 = <<931/34=27.38235294117647>>27.38235294117647. Since we can't have a fraction of a kid, we'll round down to 27 kids per swing set.
    The number of swing sets needed to accommodate all the kids is 931/27 = <<931/27=34.48148148148148>>34.48148148148148. Since we can't have a fraction of a swing set, we'll round up to 35 swing sets.
    The number of kids that can be accommodated with 35 swing sets is 35*27 = <<35\*27=945>>945.
    The number of kids waiting for their turn is 931-945 = <<931-945=-14>>-14. Since we can't have a negative number of kids waiting, this means that all the kids will be able to use the swings without waiting.
    ### Answer: 0

Expected answer: 13

Correct? No

🔗 Problem

Problem: John has 943 dollar bills in his possession. He tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left?

Mixtral 8x22B:

     Reasoning: John can fully load 943/433 = <<943/433=2>>2 wallets.
    John has 943 - 2*433 = <<943-2*433=67>>67 dollar bills left.
    ### Answer: 67

Expected answer: 77

Correct? No

🔗 Problem

Problem: A helicopter pilot plans to transport 240 passengers over several trips. He can carry 177 passengers in one trip. How many passengers will be left behind after the helicopter makes the first full trip?

Mixtral 8x22B:

     Reasoning: The helicopter can carry 177 passengers in one trip.
    After the first full trip, there will be 240 - 177 = <<240-177=63>>63 passengers left behind.
    ### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Problem

Problem: A gardener has 982 flowers to plant in flowerbeds. Each flowerbed can fit 555 flowers. After filling up as many flowerbeds as possible, how many flowers will the gardener have left to plant?

Mixtral 8x22B:

     Reasoning: The gardener can fill up 982/555 = <<982/555=1>>1 flowerbed completely.
    The gardener will have 982 - 555 = <<982-555=427>>427 flowers left to plant.
    ### Answer: 427

Expected answer: 427

Correct? Yes

🔗 Follow-up

Problem: The gardener received an additional shipment, bringing the total number of flowers up to 867. If he continues to plant the flowers in flowerbeds of 555 each, how many flowers will he have left to plant after filling up as many flowerbeds as possible?

Mixtral 8x22B:

     Reasoning: The gardener can fill up 867/555 = <<867/555=1>>1 flowerbed completely.
    The gardener will have 867 - 555 = <<867-555=312>>312 flowers left to plant.
    ### Answer: 312

Expected answer: 312

Correct? Yes

🔗 Problem

Problem: A farmer grows 203 strawberry plants. She wants to divide her plants into groups of 5 to sell. How many plants will be remaining if she divides them equally?

Mixtral 8x22B:

     Reasoning: The farmer can divide 203/5 = <<203/5=40>>40 groups of 5 plants each.
    The remaining plants will be 203 - (40\*5) = <<203-(40\*5)=3>>3 plants.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: The farmer harvested another field and got an additional 76 strawberry plants. Again, she wants to divide the new plants into groups of 5 to sell. How many plants will be remaining if she divides these new strawberries equally?

Mixtral 8x22B:

     Reasoning: The farmer can divide 76/5 = <<76/5=15>>15 groups of 5 plants each.
    The remaining plants will be 76 - (15\*5) = <<76-(15\*5)=1>>1 plant.
    ### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Problem

Problem: A gardener has 355 carrots. He wants to create bundles of 16. After creating as many bundles as he can, how many carrots will he have left?

Mixtral 8x22B:

     Reasoning: The gardener can create 355/16 = <<355/16=22>>22 full bundles of carrots.
    He will have 355 - (22 \* 16) = <<355-(22\*16)=11>>11 carrots left over.
    ### Answer: 11

Expected answer: 3

Correct? No

🔗 Problem

Problem: A total rainfall of 612 inches fell over a certain city in 29 consecutive days. If the rain fell in the same amount every day, how many inches of rain would be left to make the days evenly rainy?

Mixtral 8x22B:

     Reasoning: The total rainfall of 612 inches divided by 29 days equals 612/29 = <<612/29=21.103448275862068>>21.103448275862068 inches per day.
    Since the rain cannot fall in a fraction of an inch, the rainfall must be rounded to the nearest whole number.
    Rounding 21.103448275862068 inches to the nearest whole number gives 21 inches per day.
    Therefore, the total rainfall of 612 inches divided by 21 inches per day equals 612/21 = <<612/21=29>>29 days.
    Since the rain fell for 29 consecutive days, there would be no rain left to make the days evenly rainy.
    ### Answer: 0

Expected answer: 3

Correct? No

🔗 Problem

Problem: A truck company has got 514 boxes for delivery. Each truck can hold up to 371 boxes. If each truck is loaded to its full capacity, how many boxes will be left over?

Mixtral 8x22B:

     Reasoning: The number of trucks needed to hold all the boxes is 514/371 = <<514/371=1>>1 truck with a remainder of 143 boxes.
    The number of boxes left over is 143.
    ### Answer: 143

Expected answer: 143

Correct? Yes

🔗 Problem

Problem: In a large sandbox, children create 684 sandcastles over the summer. The sandcastles were grouped into sets of 230 for a photography contest. After all the sets were completed, how many sandcastles were left that didn't form a complete set?

Mixtral 8x22B:

     Reasoning: 684/230 = <<684/230=3>>3 sets of sandcastles were completed for the photography contest.
    684 - (3*230) = <<684-(3*230)=64>>64 sandcastles were left that didn't form a complete set.
    ### Answer: 64

Expected answer: 224

Correct? No

🔗 Problem

Problem: A toy manufacturer has a production run of 735 toy cars. They package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among packs, how many toy cars will be left over after all full packs have been filled?

Mixtral 8x22B:

     Reasoning: The toy manufacturer can fill 735/348 = <<735/348=2>>2 full packs of toy cars.
    The remaining toy cars will be 735 - (2*348) = <<735-(2*348)=39>>39.
    ### Answer: 39

Expected answer: 39

Correct? Yes

🔗 Follow-up

Problem: The toy manufacturer decides in the next production run to make only 77 toy cars instead of 735. Again, they package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among these packs, how many toy cars will be left over after all full packs have been filled?

Mixtral 8x22B:

     Reasoning: The toy manufacturer can fill 77/348 = <<77/348=0>>0 full packs of toy cars.
    The remaining toy cars will be 77 - (0*348) = <<77-(0*348)=77>>77.
    ### Answer: 77

Expected answer: 77

Correct? Yes

🔗 Problem

Problem: In a forest, there are 386 animals. Each woodlands territory can support 95 animals. If the existing animals are evenly distributed among the territories, how many animals will be left in the last not fully occupied territory?

Mixtral 8x22B:

     Reasoning: The number of fully occupied territories is 386/95 = <<386/95=4>>4.
    The number of animals in the fully occupied territories is 4*95 = <<4*95=380>>380.
    The number of animals left in the last not fully occupied territory is 386-380 = <<386-380=6>>6.
    ### Answer: 6

Expected answer: 6

Correct? Yes

🔗 Follow-up

Problem: In the same forest, a new report finds that there were actually 497 animals instead of the initially thought 386. If these animals were evenly distributed among the territories, each still supporting 95 animals, how many animals would be in the last not fully occupied territory now?

Mixtral 8x22B:

     Reasoning: The number of fully occupied territories is 497/95 = <<497/95=5>>5.
    The number of animals in the fully occupied territories is 5*95 = <<5*95=475>>475.
    The number of animals left in the last not fully occupied territory is 497-475 = <<497-475=22>>22.
    ### Answer: 22

Expected answer: 22

Correct? Yes

🔗 Problem

Problem: A forest has 801 trees. A tree disease starts to spread and is expected to affect 646 trees. If all the diseased trees have to be cut down evenly, how many trees are likely to stay healthy after the disease has affected all possible trees?

Mixtral 8x22B:

     Reasoning: The number of trees that will stay healthy is the total number of trees minus the number of trees that will be affected by the disease.
    801 - 646 = <<801-646=155>>155 trees are likely to stay healthy after the disease has affected all possible trees.
    ### Answer: 155

Expected answer: 155

Correct? Yes

🔗 Problem

Problem: A rope manufacturer has made a rope of 934 meters in length. This rope is supposed to be cut into smaller pieces, each piece being 902 meters in length. After cutting into the maximum possible number of equal pieces, how many meters will the last piece of the rope be?

Mixtral 8x22B:

     Reasoning: The rope manufacturer can cut 934/902 = <<934/902=1.0354545454545455>>1.0354545454545455 pieces of 902 meters each. Since the manufacturer can only cut whole pieces, they can cut 1 piece of 902 meters.
    The remaining length of the rope will be 934 - 902 = <<934-902=32>>32 meters.
    ### Answer: 32 meters

Expected answer: 32

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous scenario, suppose that the manufacturer only made a rope of 202 meters in length initially. Applying the same method of cutting rope into pieces that are each 902 meters long, how many meters would the piece of the rope be now?

Mixtral 8x22B:

     Reasoning: The manufacturer can cut 202/902 = <<202/902=0.2239469387755102>>0.2239469387755102 pieces of 902 meters each. Since the manufacturer can only cut whole pieces, they cannot cut any pieces of 902 meters.
    The remaining length of the rope will be 202 meters.
    ### Answer: 202 meters

Expected answer: 202

Correct? Yes

🔗 Problem

Problem: A dairy farm produces 561 liters of milk each day. The milk is packaged into 550-liter containers. How many liters of milk are left over each day after filling the containers?

Mixtral 8x22B:

     Reasoning: The dairy farm can fill 561/550 = <<561/550=1>>1 container completely.
    The remaining milk is 561 - (550*1) = <<561-(550*1)=11>>11 liters.
    ### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: If the dairy farm increased its production and started producing 729 liters of milk each day instead of 561 liters, how many liters of milk would be left over each day after filling the 550-liter containers?

Mixtral 8x22B:

     Reasoning: The dairy farm can fill 729/550 = <<729/550=1>>1 container completely.
    The remaining milk is 729 - (550*1) = <<729-(550*1)=179>>179 liters.
    ### Answer: 179

Expected answer: 179

Correct? Yes

🔗 Problem

Problem: Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?

Mixtral 8x22B:

     Reasoning: Jon will use 258 pieces to complete a full puzzle.
    He will have 259-258 = <<259-258=1>>1 piece left over.
    ### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, Jon had 259 puzzle pieces and each puzzle requires 258 pieces. Suppose instead each puzzle needs 542 pieces. How many pieces would Jon have left over after finishing as many full puzzles as possible with his 259 pieces?

Mixtral 8x22B:

     Reasoning: Jon can complete 259/542 = <<259/542=0>>0 full puzzles with his 259 pieces.
    He will have 259-0*542 = <<259-0*542=259>>259 pieces left over.
    ### Answer: 259

Expected answer: 259

Correct? Yes

🔗 Problem

Problem: A jewelry maker has 673 beads. She plans to use exactly 49 beads for each bracelet. How many beads will she have left after creating as many bracelets as possible with the exact number of beads?

Mixtral 8x22B:

     Reasoning: The jewelry maker can create 673/49 = <<673/49=13.73469387755102>>13 bracelets with the exact number of beads.
    Since she can't create a partial bracelet, she will have 673 - (13 \* 49) = <<673-(13\*49)=36>>36 beads left.
    ### Answer: 36

Expected answer: 36

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker received an additional shipment, and now she has a total of 673 beads. This time, she wants to make larger bracelets which use exactly 545 beads each. After creating as many large bracelets as possible, how many beads will she have left over?

Mixtral 8x22B:

     Reasoning: The jewelry maker can create 673/545 = <<673/545=1.234862385321101>>1 large bracelet with the exact number of beads.
    Since she can't create a partial bracelet, she will have 673 - 545 = <<673-545=128>>128 beads left.
    ### Answer: 128

Expected answer: 128

Correct? Yes

🔗 Problem

Problem: A police station received 927 calls within a week. They have 311 operators who can handle the same number of calls each week. However, when the calls are divided equally, how many calls will the last operator handle?

Mixtral 8x22B:

     Reasoning: The total number of calls is 927.
    The number of operators is 311.
    When the calls are divided equally, each operator will handle 927/311 = <<927/311=3>>3 calls.
    However, since 927 is not a multiple of 311, there will be some calls left over.
    The last operator will handle the remaining calls, which is 927 - (311 \* 3) = <<927-(311\*3)=1>>1 call.
    ### Answer: 1

Expected answer: 305

Correct? No

🔗 Problem

Problem: John has 764 pieces for his jigsaw puzzle, and every package should contain 589 pieces. If he separates these pieces into full packages, how many pieces will be left outside without a package?

Mixtral 8x22B:

     Reasoning: John can make 764/589 = <<764/589=1>>1 full package.
    John will have 764 - 589 = <<764-589=175>>175 pieces left outside without a package.
    ### Answer: 175

Expected answer: 175

Correct? Yes

🔗 Follow-up

Problem: If John had originally only 404 puzzle pieces, and each package can still only contain 589, how many pieces will be left outside the package now?

Mixtral 8x22B:

     Reasoning: John cannot make any full package with 404 pieces since 404 < 589.
    John will have 404 pieces left outside without a package.
    ### Answer: 404

Expected answer: 404

Correct? Yes

🔗 Problem

Problem: A dressmaker has 984 meters of fabric. She uses 217 meters of fabric to make each dress. After using all the fabric she can to make as many dresses as possible, how many meters of fabric will she have left?

Mixtral 8x22B:

     Reasoning: The dressmaker can make 984/217 = <<984/217=4>>4 dresses with the fabric she has.
    After making 4 dresses, she will have used 4*217 = <<4*217=868>>868 meters of fabric.
    The dressmaker will have 984-868 = <<984-868=116>>116 meters of fabric left.
    ### Answer: 116

Expected answer: 116

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, let's now suppose that the dressmaker has 984 meters of fabric, but this time she uses 585 meters of fabric to make each dress. Again, she uses all the fabric she can to make as many dresses as possible. With this change, how many meters of fabric will she have left after all the dresses are made?

Mixtral 8x22B:

     Reasoning: The dressmaker can make 984/585 = <<984/585=1>>1 dress with the fabric she has.
    After making 1 dress, she will have used 1*585 = <<1*585=585>>585 meters of fabric.
    The dressmaker will have 984-585 = <<984-585=399>>399 meters of fabric left.
    ### Answer: 399

Expected answer: 399

Correct? Yes

🔗 Problem

Problem: A company donates 639 sleeping bags for a camping event. Each campsite is supplied with 374 sleeping bags. If all the sleeping bags are divided equally among the campsites, how many sleeping bags will there be left?

Mixtral 8x22B:

     Reasoning: The company donates 639 sleeping bags, and each campsite is supplied with 374 sleeping bags. To find out how many sleeping bags will be left after dividing them equally among the campsites, we need to find out how many campsites can be fully supplied with 374 sleeping bags each.

    639 / 374 = <<639/374=1.70855614973262>>1.70855614973262 (approximately)

    Since we can't have a fraction of a campsite, we can only fully supply 1 campsite with 374 sleeping bags.

    Therefore, the remaining sleeping bags will be:

    639 - 374 = <<639-374=265>>265

    ### Answer: 265

Expected answer: 265

Correct? Yes

🔗 Follow-up

Problem: The same company from our previous question receives an updated request for sleeping bags. Now instead of 639, they only need to donate 613. If each campsite is still supplied with 374 sleeping bags, how many sleeping bags will be left after all the campsites are filled?

Mixtral 8x22B:

     Reasoning: The company now needs to donate 613 sleeping bags, and each campsite is still supplied with 374 sleeping bags. To find out how many sleeping bags will be left after dividing them equally among the campsites, we need to find out how many campsites can be fully supplied with 374 sleeping bags each.

    613 / 374 = <<613/374=1.63903743315481>>1.63903743315481 (approximately)

    Since we can't have a fraction of a campsite, we can only fully supply 1 campsite with 374 sleeping bags.

    Therefore, the remaining sleeping bags will be:

    613 - 374 = <<613-374=239>>239

    ### Answer: 239

Expected answer: 239

Correct? Yes

🔗 Problem

Problem: A pizza restaurant made 620 pizzas today. They package up the pizzas in boxes that hold 578 each for delivery. If the pizzas are evenly distributed into these boxes, how many pizzas will be left over that don't fit into a box?

Mixtral 8x22B:

     Reasoning: The pizza restaurant can fit 620/578 = <<620/578=1>>1 box of pizzas.
    The remaining pizzas that don't fit into a box are 620 - (578*1) = <<620-(578*1)=42>>42 pizzas.
    ### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Follow-up

Problem: The owner of the pizza restaurant decides to make 74 more pizzas tomorrow, bringing the total to 694 pizzas. If they are again distributed into boxes that hold 578 pizzas each, how many pizzas will be left out without a box this time?

Mixtral 8x22B:

     Reasoning: The pizza restaurant can fit 694/578 = <<694/578=1>>1 box of pizzas.
    The remaining pizzas that don't fit into a box are 694 - (578*1) = <<694-(578*1)=116>>116 pizzas.
    ### Answer: 116

Expected answer: 116

Correct? Yes

🔗 Problem

Problem: A factory made a total of 820 robots. It can store 684 robots in one storage unit. If the robots are evenly stored, how many robots will not fit and remain outside of the storage units?

Mixtral 8x22B:

     Reasoning: The factory can store 820/684 = <<820/684=1.2>>1.2 storage units worth of robots.
    Since the robots must be stored in whole units, the factory can only store 1 storage unit worth of robots.
    The remaining robots that will not fit in the storage unit are 820 - 684 = <<820-684=136>>136 robots.
    ### Answer: 136

Expected answer: 136

Correct? Yes

🔗 Follow-up

Problem: In the same factory, another production run is completed, this time manufacturing a total of 820 upgraded robots. However, the storage units for these new models can only hold 625 robots each. If the robots are evenly stored, how many upgraded robots will not fit and remain outside the storage units now?

Mixtral 8x22B:

     Reasoning: The factory can store 820/625 = <<820/625=1.312>>1.312 storage units worth of upgraded robots.
    Since the robots must be stored in whole units, the factory can only store 1 storage unit worth of upgraded robots.
    The remaining upgraded robots that will not fit in the storage unit are 820 - 625 = <<820-625=195>>195 robots.
    ### Answer: 195

Expected answer: 195

Correct? Yes

🔗 Problem

Problem: A cloud changes its shape by reducing its water droplets. Initially, there were 516 droplets in the cloud. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?

Mixtral 8x22B:

     Reasoning: The cloud loses water droplets at an equal rate of 289 droplets per cycle.
    The cloud initially had 516 droplets.
    After the first cycle, the cloud will have 516 - 289 = <<516-289=227>>227 droplets left.
    After the second cycle, the cloud will have 227 - 289 = <<227-289=-62>>0 droplets left (since the cloud cannot have a negative number of droplets).
    Therefore, the cloud will be entirely dry after the second cycle, and there will be 0 droplets left.
    ### Answer: 0

Expected answer: 227

Correct? No

🔗 Problem

Problem: A transport company needs to load 330 boxes into trucks. Each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded?

Mixtral 8x22B:

     Reasoning: The number of trucks needed to hold all the boxes is 330/4 = <<330/4=82.5>>82.5. Since a truck cannot hold a fraction of a box, the company will need 83 trucks to hold all the boxes.
    The number of boxes that can be loaded into 82 trucks is 82*4 = <<82*4=328>>328.
    The number of boxes left unloaded is 330-328 = <<330-328=2>>2.
    ### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: The transport company now needs to load a new batch of 274 boxes into trucks. Again, each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded this time?

Mixtral 8x22B:

     Reasoning: The number of trucks needed to hold all the boxes is 274/4 = <<274/4=68.5>>68.5. Since a truck cannot hold a fraction of a box, the company will need 69 trucks to hold all the boxes.
    The number of boxes that can be loaded into 68 trucks is 68*4 = <<68*4=272>>272.
    The number of boxes left unloaded is 274-272 = <<274-272=2>>2.
    ### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: A farmer harvested 649 potatoes this season. He decides to pack them into crates each containing 183 potatoes. How many potatoes will be left after all crates are filled to their maximum capacity?

Mixtral 8x22B:

     Reasoning: The farmer can fill 649/183 = <<649/183=3>>3 crates with 183 potatoes each.
    The remaining potatoes will be 649 - (3*183) = <<649-(3*183)=100>>100 potatoes.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Follow-up

Problem: The farmer realized that he actually only harvested 238 potatoes this season instead of 649. If he still packs them into crates each holding 183 potatoes, how many potatoes will be left after all crates are filled to their maximum capacity?

Mixtral 8x22B:

     Reasoning: The farmer can fill 238/183 = <<238/183=1>>1 crate with 183 potatoes.
    The remaining potatoes will be 238 - 183 = <<238-183=55>>55 potatoes.
    ### Answer: 55

Expected answer: 55

Correct? Yes

🔗 Problem

Problem: A t-shirt company has a batch of 258 shirts in production. Each box can pack 67 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?

Mixtral 8x22B:

     Reasoning: The company can pack 258/67 = <<258/67=3.8507462686567164>>3 full boxes of shirts.
    Since the company can't pack a partial box, they would pack 3 boxes and have 258 - (3 \* 67) = <<258-(3\*67)=63>>63 shirts left outside the boxes.
    ### Answer: 63

Expected answer: 57

Correct? No

🔗 Problem

Problem: On a pirate ship, there are 995 gold coins that need to be evenly divided among the 267 pirates. If they split the gold up as evenly as possible, how many gold coins will be left over?

Mixtral 8x22B:

     Reasoning: To find out how many gold coins each pirate will get, we divide the total number of gold coins by the number of pirates: 995/267 = <<995/267=3.726591759550562>>3.726591759550562. Since we can't have a fraction of a gold coin, we round down to the nearest whole number, which is 3.

    To find out how many gold coins will be left over, we multiply the number of pirates by the number of gold coins each pirate gets and subtract that from the total number of gold coins: 267*3 = <<267\*3=801>>801.

    995 - 801 = <<995-801=194>>194 gold coins will be left over.

    ### Answer: 194

Expected answer: 194

Correct? Yes

🔗 Problem

Problem: There are 776 snails all lined up in a row. If you group them in bunches of 375 snails, how many snails will be left in the final group?

Mixtral 8x22B:

     Reasoning: 776 divided by 375 is 2 with a remainder of 26.
    So, there will be 2 full groups of 375 snails and a final group of 26 snails.
    ### Answer: 26

Expected answer: 26

Correct? Yes

🔗 Follow-up

Problem: Originally, you had grouped the snails in bunches of 375 snails each. Now, think about what would happen if each bunch had 18 snails instead. How many snails would be left in the final group then?

Mixtral 8x22B:

     Reasoning: 776 divided by 18 is 43 with a remainder of 4.
    So, there will be 43 full groups of 18 snails and a final group of 4 snails.
    ### Answer: 4

Expected answer: 2

Correct? No

🔗 Problem

Problem: A pillow factory produces 589 pillows per day. They package these pillows in boxes, and each box holds 198 pillows. If they pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?

Mixtral 8x22B:

     Reasoning: The factory produces 589 pillows per day and each box holds 198 pillows.
    To find out how many full boxes they can pack, we divide the total number of pillows by the number of pillows per box: 589/198 = <<589/198=2.9747474747474746>>2.9747474747474746
    Since they can only pack full boxes, they can pack 2 full boxes.
    To find out how many pillows will be left outside the boxes, we multiply the number of full boxes by the number of pillows per box and subtract that from the total number of pillows: 589 - (2 \* 198) = <<589 - (2 \* 198)=589 - 396=193>>193
    ### Answer: 193

Expected answer: 193

Correct? Yes

🔗 Follow-up

Problem: The pillow factory has made an adjustment to the packaging process and recently upgraded their boxes so that each can now hold 810 pillows. If they still produce 589 pillows per day and pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?

Mixtral 8x22B:

     Reasoning: The factory produces 589 pillows per day and each box now holds 810 pillows.
    To find out how many full boxes they can pack, we divide the total number of pillows by the number of pillows per box: 589/810 = <<589/810=0.7271604938271605>>0.7271604938271605
    Since they can only pack full boxes, they can pack 0 full boxes.
    To find out how many pillows will be left outside the boxes, we subtract the number of full boxes from the total number of pillows: 589 - (0 \* 810) = <<589 - (0 \* 810)=589>>589
    ### Answer: 589

Expected answer: 589

Correct? Yes

🔗 Problem

Problem: A jewelry maker has 633 beads. If she uses beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Mixtral 8x22B:

     Reasoning: The jewelry maker can make 633/30 = <<633/30=21>>21 necklaces.
    She will have 633 - (21 \* 30) = <<633-(21\*30)=3>>3 beads left.
    ### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker found an additional box of beads in her storage, increasing her total number of beads to 588. Now, if she uses these beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Mixtral 8x22B:

     Reasoning: The jewelry maker can now make 588/30 = <<588/30=19>>19 necklaces.
    She will have 588 - (19 \* 30) = <<588-(19\*30)=18>>18 beads left.
    ### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Problem

Problem: John has collected 365 coins. He decided to put equal numbers of them in his 140 wallets. However, he found out he would still have some coins left after evenly distributing them into these wallets. How many coins will John have left?

Mixtral 8x22B:

     Reasoning: John can put 365/140 = <<365/140=2.607142857142857>>2 coins in each wallet with a remainder of 365 - (140*2) = <<365-(140*2)=85>>85 coins left.
    ### Answer: 85

Expected answer: 85

Correct? Yes

🔗 Follow-up

Problem: Now, suppose John comes across additional coins and his collection increases to 739 coins. He again tries to evenly distribute these coins among his 140 wallets. How many coins will John have left after this distribution?

Mixtral 8x22B:

     Reasoning: John can put 739/140 = <<739/140=5.278571428571429>>5 coins in each wallet with a remainder of 739 - (140*5) = <<739-(140*5)=39>>39 coins left.
    ### Answer: 39

Expected answer: 39

Correct? Yes

🔗 Problem

Problem: A sock manufacturer produces 743 socks in a single production run. The socks are packed into cartons, each containing 451 socks. After filling up as many cartons as possible, how many socks are left unpacked?

Mixtral 8x22B:

     Reasoning: The manufacturer can fill up 743/451 = <<743/451=1>>1 carton completely.
    The remaining socks are 743 - 451 = <<743-451=292>>292.
    ### Answer: 292

Expected answer: 292

Correct? Yes

🔗 Follow-up

Problem: Now suppose the sock manufacturer changes their packaging method and each carton contains 179 socks instead of 451 socks. After filling up as many cartons as possible with 743 socks, how many socks are left unpacked?

Mixtral 8x22B:

     Reasoning: The manufacturer can fill up 743/179 = <<743/179=4>>4 cartons completely.
    The remaining socks are 743 - (4*179) = <<743-(4*179)=107>>107.
    ### Answer: 107

Expected answer: 27

Correct? No

🔗 Problem

Problem: A total of 923 children want to slide down a slide at an amusement park. If 771 children can go down the slide without rest, how many children will be left waiting for their turn?

Mixtral 8x22B:

     Reasoning: The total number of children is 923, and 771 children can go down the slide without rest.
    The number of children left waiting for their turn is 923 - 771 = <<923-771=152>>152.
    ### Answer: 152

Expected answer: 152

Correct? Yes

🔗 Follow-up

Problem: After the first 771 children go down the slide, another wave of children arrives and now there are 923 children in total waiting again. If 881 children can go down the slide without any break this time, how many children will be left waiting for their turn?

Mixtral 8x22B:

     Reasoning: After the first wave of children, there are 923 children waiting again.
    881 children can go down the slide without any break this time.
    The number of children left waiting for their turn is 923 - 881 = <<923-881=42>>42.
    ### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Problem

Problem: Superhero Iron Punch has to save 442 people from a collapsing building. He can teleport a maximum of 104 people at a time to safety. After teleporting as many full groups as he can, how many people will be left in the building for his last round of rescue?

Mixtral 8x22B:

     Reasoning: Iron Punch can teleport 442/104 = <<442/104=4>>4 full groups of people to safety.
    4 * 104 = <<4*104=416>>416 people will be teleported in the full groups.
    442 - 416 = <<442-416=26>>26 people will be left in the building for the last round of rescue.
    ### Answer: 26

Expected answer: 26

Correct? Yes

🔗 Follow-up

Problem: What if there were actually 512 people in the collapsing building instead of 442? After Superhero Iron Punch teleports as many full groups of 104 people as he can to safety, how many people will be left in the building for his last round of rescue now?

Mixtral 8x22B:

     Reasoning: Iron Punch can teleport 512/104 = <<512/104=5>>5 full groups of people to safety.
    5 * 104 = <<5*104=520>>520 people will be teleported in the full groups.
    512 - 520 = <<512-520=-8>>512 - 520 is not possible, as there cannot be a negative number of people left in the building.
    Therefore, Iron Punch can teleport all 512 people to safety in 5 full groups.
    ### Answer: 0

Expected answer: 96

Correct? No

🔗 Problem

Problem: A card game manufacturer creates a deck of cards with 569 cards. Each card pack has 68 cards. After creating as many packs as possible, how many cards will the manufacturer have left over?

Mixtral 8x22B:

     Reasoning: The manufacturer can create 569/68 = <<569/68=8>>8 packs of cards.
    The manufacturer will have 569 - (8\*68) = <<569-(8\*68)=53>>53 cards left over.
    ### Answer: 53

Expected answer: 25

Correct? No

🔗 Problem

Problem: A stationery store received a shipment of 842 erasers. The store owner wants to display them in boxes, with each box containing 719 erasers. After filling as many boxes as possible, how many erasers will be left over?

Mixtral 8x22B:

     Reasoning: The store owner can fill 842/719 = <<842/719=1>>1 box completely.
    The remaining erasers will be 842 - 719 = <<842-719=123>>123.
    ### Answer: 123

Expected answer: 123

Correct? Yes

🔗 Follow-up

Problem: Suppose the stationery store owner later decided to display the erasers in smaller boxes, with each box containing 420 erasers instead. After filling as many boxes as possible, how many erasers will be left over now?

Mixtral 8x22B:

     Reasoning: The store owner can fill 842/420 = <<842/420=2>>2 boxes completely.
    The remaining erasers will be 842 - 2*420 = <<842-2*420=1>>1.
    ### Answer: 1

Expected answer: 2

Correct? No

🔗 Problem

Problem: A farmer harvested 461 carrots from his garden. He packs them into boxes, each box can hold up to 244 carrots. After packing as many full boxes as possible, how many carrots will be left unpacked?

Mixtral 8x22B:

     Reasoning: The farmer can pack 461/244 = <<461/244=1>>1 full box of carrots.
    The remaining carrots will be 461 - (244*1) = <<461-(244*1)=227>>227 carrots.
    ### Answer: 227

Expected answer: 217

Correct? No

🔗 Problem

Problem: A penguin scientist counts 309 penguins in a colony. She decides to tag them in groups of 293 for easier tracking. How many penguins will be in the final, possibly incomplete, group?

Mixtral 8x22B:

     Reasoning: The scientist can tag 309/293 = <<309/293=1>>1 full group of 293 penguins.
    The remaining penguins will be in the final group, which will have 309 - (293*1) = <<309-(293*1)=16>>16 penguins.
    ### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Follow-up

Problem: The penguin scientist realizes she made a mistake and there were actually only 262 penguins in each group. How many penguins will be in the final, possibly incomplete, group now?

Mixtral 8x22B:

     Reasoning: The scientist can tag 309/262 = <<309/262=1>>1 full group of 262 penguins.
    The remaining penguins will be in the final group, which will have 309 - (262*1) = <<309-(262*1)=47>>47 penguins.
    ### Answer: 47

Expected answer: 47

Correct? Yes

🔗 Problem

Problem: A sandwich shop has 580 slices of bread. They use 18 slices of bread for each sandwich-making batch. After using up the bread in these batches, how many slices will they have left?

Mixtral 8x22B:

     Reasoning: The sandwich shop can make 580/18 = <<580/18=32.22222222222222>>32 batches with 580 slices of bread.
    Since they can't make a fraction of a batch, they will use up 32 batches * 18 slices/batch = <<32*18=576>>576 slices of bread.
    They will have 580 - 576 = <<580-576=4>>4 slices of bread left.
    ### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: The sandwich shop's supplier delivered an additional batch of bread, bringing their total to 580 slices. If the shop still makes sandwiches using 477 slices of bread per batch, how many slices will they have left after the latest batch of sandwiches is made?

Mixtral 8x22B:

     Reasoning: The sandwich shop now has 580 + 477 = <<580+477=1057>>1057 slices of bread.
    They can make 1057/477 = <<1057/477=2.216352201257861>>2 batches with 1057 slices of bread.
    Since they can't make a fraction of a batch, they will use up 2 batches * 477 slices/batch = <<2*477=954>>954 slices of bread.
    They will have 1057 - 954 = <<1057-954=103>>103 slices of bread left.
    ### Answer: 103

Expected answer: 103

Correct? Yes

🔗 Problem

Problem: A tailor has 925 meters of fabric. The tailor uses 529 meters of fabric to make each dress. If the tailor uses the fabric evenly for each dress, how many meters of fabric will be left over after completing the dresses?

Mixtral 8x22B:

     Reasoning: The tailor can make 925/529 = <<925/529=1>>1 dress with the fabric.
    The tailor will use 529 meters of fabric for the dress, leaving 925-529 = <<925-529=396>>396 meters of fabric left over.
    ### Answer: 396

Expected answer: 396

Correct? Yes

🔗 Follow-up

Problem: After making some dresses, the tailor now only has 62 meters of fabric left. If the tailor continues to use 529 meters of fabric to make each dress, how many meters of fabric will be left over after making the dresses?

Mixtral 8x22B:

     Reasoning: The tailor cannot make any more dresses with the remaining fabric, as 62 < 529.
    Therefore, the tailor will have 62 meters of fabric left over.
    ### Answer: 62

Expected answer: 62

Correct? Yes

🔗 Problem

Problem: There are 976 tourists wanting to explore a castle. Each tour group throughout the day accommodates up to 530 people. After all the groups have taken off, how many tourists will be left for the last group of the day?

Mixtral 8x22B:

     Reasoning: The first group can accommodate 530 tourists, so 976-530 = <<976-530=446>>446 tourists will be left for the second group.
    The second group can accommodate 530 tourists, so 446-530 = <<446-530=-84>>-84 tourists will be left for the last group.
    Since there cannot be a negative number of tourists, this means that all the remaining tourists will be in the second group, and there will be no tourists left for the last group.
    ### Answer: 0

Expected answer: 446

Correct? No