🔗 Problem

Problem: At a party, 66 teenagers and 6 adults attend at first. Later on, the number of guests increases by 62. Near the end, an additional group of 52 people join the party. How many people attended the party in total?

InternLM-Math Base 20B:

     Reasoning: The number of teenagers at the party increased by 66+62+52 = <<66+62+52=180>>180.
    The number of adults at the party increased by 6+0+0 = <<6+0+0=6>>6.
    The total number of people at the party increased by 66+6+180+6 = <<66+6+180+6=268>>268.
    ### Answer: 268

Expected answer: 186

Correct? No

🔗 Problem

Problem: Tom has 11 hats. He then buys a box of hats that contains 42 more. How many hats does Tom have now?

InternLM-Math Base 20B:

     Reasoning: Tom has 11+42 = <<11+42=53>>53 hats now.
    ### Answer: 53

Expected answer: 53

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous problem, what if Tom originally had 8 hats instead of 11? How many hats would Tom have after buying the box of 42 hats?

InternLM-Math Base 20B:

      Reasoning: Tom has 8+42 = <<8+42=50>>50 hats now.
    ### Answer: 50

Expected answer: 50

Correct? Yes

🔗 Problem

Problem: Penny has 9 pens in her backpack. Later in the day, she finds 56 gum wrappers in her backpack. How many items does Penny have in her backpack in total?

InternLM-Math Base 20B:

     Reasoning: Penny has 9+56 = <<9+56=65>>65 items in her backpack in total.
    ### Answer: 65

Expected answer: 65

Correct? Yes

🔗 Follow-up

Problem: Penny realizes she drastically underestimated the number of pens in her backpack. There are actually 90 pens, not 9. With the 56 gum wrappers, how many items does Penny have in her backpack now?

InternLM-Math Base 20B:

      Reasoning: Penny has 90+56 = <<90+56=146>>146 items in her backpack in total.
    ### Answer: 146

Expected answer: 146

Correct? Yes

🔗 Problem

Problem: At a beach party, one participant inflated 75 beach balls. Shortly after, another participant added 78 more beach balls. How many beach balls are there in total at the beach party?

InternLM-Math Base 20B:

     Reasoning: 75+78 = <<75+78=153>>153
    ### Answer: 153

Expected answer: 153

Correct? Yes

🔗 Follow-up

Problem: After all the beach balls were inflated at the party, a group of latecomers showed up with 96 more beach balls of their own to add to the mix. How many beach balls are there now in total at the beach party?

InternLM-Math Base 20B:

      Reasoning: 153+96 = <<153+96=249>>249
    ### Answer: 249

Expected answer: 249

Correct? Yes

🔗 Problem

Problem: At a party, 74 adults and 58 children were enjoying the games and food. Later, an additional 20 adults arrived. How many total people were at the party then?

InternLM-Math Base 20B:

     Reasoning: 74+20 = <<74+20=94>>94 adults were at the party.
    94+58 = <<94+58=152>>152 people were at the party.
    ### Answer: 152

Expected answer: 152

Correct? Yes

🔗 Follow-up

Problem: At the party where 74 adults and 58 children were enjoying the games and food, 20 more adults arrived later. After a while, a bus with 65 more people, both adults, and children, came to join the party. How many total people were at the party after the bus arrived?

InternLM-Math Base 20B:

      Reasoning: 74+20 = <<74+20=94>>94 adults were at the party.
    94+65 = <<94+65=159>>159 people were at the party.
    ### Answer: 159

Expected answer: 217

Correct? No

🔗 Follow-up

Problem: Originally at the party there were 74 adults and 58 children. However, what if there were only 11 children to start with instead of 58? 20 more adults still arrive later. How many total people would be at the party then?

InternLM-Math Base 20B:

      Reasoning: 74+20 = <<74+20=94>>94 adults were at the party.
    94+11 = <<94+11=105>>105 people were at the party.
    ### Answer: 105

Expected answer: 105

Correct? Yes

🔗 Problem

Problem: A boat starts on the east coast and travels 43 squids (a joke nickname for miles) west. It then takes a detour for an additional 25 squids. After this, it travels another 33 squids. How far in total, in squids, has the boat traveled from the starting point of east coast?

InternLM-Math Base 20B:

     Reasoning: The boat traveled 43+25+33 = <<43+25+33=101>>101 squids in total.
    ### Answer: 101

Expected answer: 101

Correct? Yes

🔗 Follow-up

Problem: Continuing from the last problem, the boat decides to continue its journey, traveling for another 83 squids. How far in total, in squids, has the boat traveled from the starting point of the East Coast now?

InternLM-Math Base 20B:

      Reasoning: The boat traveled 43+25+33+83 = <<43+25+33+83=184>>184 squids in total.
    ### Answer: 184

Expected answer: 184

Correct? Yes

🔗 Follow-up

Problem: Let's revisit the previous scenario. Suppose that the boat started on the East Coast and initially traveled 43 squids west, then took a detour that was only 25 squids long. But instead of moving an additional 33 squids as before, this time, it only travels another 30 squids. Now, how far, in squids, has the boat traveled from the starting point of the East Coast?

InternLM-Math Base 20B:

      Reasoning: The boat traveled 43+25+30 = <<43+25+30=98>>98 squids in total.
    ### Answer: 98

Expected answer: 98

Correct? Yes

🔗 Problem

Problem: Mary has 89 guitar picks in her collection. She goes to a music festival and indicates that she will have the amount she currently has plus 60 more after the event. How many guitar picks will Mary have after the festival?

InternLM-Math Base 20B:

     Reasoning: Mary will have 89+60 = <<89+60=149>>149 guitar picks after the festival.
    ### Answer: 149

Expected answer: 149

Correct? Yes

🔗 Follow-up

Problem: After the music festival, Mary's friend James gives her an additional 31 guitar picks for her collection. Now, with the ones she got from the festival and the ones James gave her, how many guitar picks does Mary have in her collection?

InternLM-Math Base 20B:

      Reasoning: Mary has 149+31 = <<149+31=180>>180 guitar picks in her collection.
    ### Answer: 180

Expected answer: 180

Correct? Yes

🔗 Follow-up

Problem: Instead of obtaining 60 guitar picks at the music festival, what if Mary had only managed to gather 27 more picks? How many guitar picks would Mary have had after the music festival in that case?

InternLM-Math Base 20B:

      Reasoning: Mary would have had 89+27 = <<89+27=116>>116 guitar picks after the music festival.
    ### Answer: 116

Expected answer: 116

Correct? Yes

🔗 Problem

Problem: A fisherman was in his boat out on the lake. The total length, in inches, of all the fish he caught today was 90 inches. On the way back to shore, he caught 14 more inches of fish. He also caught a total of 56 inches of fish yesterday. Before he went home he caught an additional 46 inches of fish from the dock. If he added all the inches of fish he caught together, how many total inches of fish did he catch?

InternLM-Math Base 20B:

     Reasoning: The total length of all the fish he caught today was 90+14 = <<90+14=104>>104 inches. The total length of all the fish he caught yesterday was 56 inches. The total length of all the fish he caught from the dock was 46 inches. The total length of all the fish he caught altogether was 104+56+46 = <<104+56+46=206>>206 inches.
    ### Answer: 206

Expected answer: 206

Correct? Yes

🔗 Problem

Problem: Jackie has 49 contacts on her phone. She meets new people at a conference and adds 80 more contacts. Then, her co-worker gives her a list with 27 additional contacts. How many contacts does Jackie have on her phone now?

InternLM-Math Base 20B:

     Reasoning: Jackie has 49+80+27 = <<49+80+27=156>>156 contacts on her phone.
    ### Answer: 156

Expected answer: 156

Correct? Yes

🔗 Follow-up

Problem: What if, instead of initially having 49 contacts, Jackie only had 32 contacts on her phone before the conference? How many contacts would she have on her phone after adding the 80 from the conference and the additional 27 from her co-worker?

InternLM-Math Base 20B:

      Reasoning: Jackie has 32+80+27 = <<32+80+27=139>>139 contacts on her phone.
    ### Answer: 139

Expected answer: 139

Correct? Yes

🔗 Problem

Problem: Elizabeth has 70 beads and buys another 55 beads for making her necklace. She also gets another 52 beads as a gift from her friend. How many beads does she have altogether now?

InternLM-Math Base 20B:

     Reasoning: Elizabeth has 70+55+52 = <<70+55+52=177>>177 beads altogether now.
    ### Answer: 177

Expected answer: 177

Correct? Yes

🔗 Follow-up

Problem: Following the previous question, let's consider a different scenario. Suppose initially, Elizabeth had 70 beads and still bought another 55. However, her friend, instead of giving her 52 beads, gave her 75 beads. How many beads does she have in this case?

InternLM-Math Base 20B:

      Reasoning: Elizabeth has 70+55+75 = <<70+55+75=200>>200 beads altogether now.
    ### Answer: 200

Expected answer: 200

Correct? Yes

🔗 Problem

Problem: In a mythical land, a unicorn, named Oscar, discovered 66 golden apples. To his surprise, after a magical event, the number of apples increased by 67. On his way back home, he found an extra 13 golden apples. How many golden apples does Oscar have now?

InternLM-Math Base 20B:

     Reasoning: Oscar has 66+67+13 = <<66+67+13=146>>146 golden apples now.
    ### Answer: 146

Expected answer: 146

Correct? Yes

🔗 Problem

Problem: Jenny starts her day with 96 beads. She then gets an additional bracelet that has 73 more beads than she started with. How many beads are on the new bracelet?

InternLM-Math Base 20B:

     Reasoning: Jenny starts with 96 beads. She then gets a bracelet with 96+73 = <<96+73=169>>169 beads.

Expected answer: 169

Correct? Yes

🔗 Follow-up

Problem: After receiving the new bracelet, Jenny decides to add 2 beads that she found in her room to her collection. How many beads does Jenny have now in total?

InternLM-Math Base 20B:

      Reasoning: Jenny has 96+73+2 = <<96+73+2=171>>171 beads in total.

Expected answer: 171

Correct? Yes

🔗 Follow-up

Problem: Instead of starting the day with 96 beads, imagine that Jenny had only 29 beads to begin with. She still adds a new bracelet to her collection, which has 73 more beads than she started the day with. How many beads are on this new bracelet?

InternLM-Math Base 20B:

      Reasoning: Jenny starts with 29 beads. She then gets a bracelet with 29+73 = <<29+73=102>>102 beads.

Expected answer: 102

Correct? Yes

🔗 Problem

Problem: A cat named Whiskers catches 50 mice in a year. In the same year, another cat named Velvet catches 89. How many mice combined did Whiskers and Velvet catch in that year?

InternLM-Math Base 20B:

     Reasoning: Whiskers and Velvet caught 50+89 = <<50+89=139>>139 mice in that year.
    ### Answer: 139

Expected answer: 139

Correct? Yes

🔗 Follow-up

Problem: Following the previous problem, suppose Whiskers had a surge in hunting activity and caught an additional amount of mice equal to the combined total previously calculated. How many mice would Whiskers have caught in total by the end of the year?

InternLM-Math Base 20B:

      Reasoning: Whiskers caught 139+139 = <<139+139=278>>278 mice in total by the end of the year.
    ### Answer: 278

Expected answer: 189

Correct? No

🔗 Follow-up

Problem: Referring back to the first problem, suppose Whiskers only caught 4 mice in the year instead of 50. Considering Velvet still caught 89 mice, how many mice combined did Whiskers and Velvet catch in that year?

InternLM-Math Base 20B:

      Reasoning: Whiskers and Velvet caught 4+89 = <<4+89=93>>93 mice in that year.
    ### Answer: 93

Expected answer: 93

Correct? Yes

🔗 Problem

Problem: Oliver has 80 maps in his collection. Then, he acquires an additional 77 maps. How many maps does Oliver have in his collection now?

InternLM-Math Base 20B:

     Reasoning: Oliver has 80+77 = <<80+77=157>>157 maps in his collection now.
    ### Answer: 157

Expected answer: 157

Correct? Yes

🔗 Follow-up

Problem: Following the previous question, Oliver decided to visit a flea market and found additional 61 old maps to add to his collection. Now, how many maps does Oliver have in his collection?

InternLM-Math Base 20B:

      Reasoning: Oliver has 157+61 = <<157+61=218>>218 maps in his collection now.
    ### Answer: 218

Expected answer: 218

Correct? Yes

🔗 Follow-up

Problem: Consider the map collection problem again. What if Oliver originally had 72 maps instead of 80, but still added the same number of maps (77) to his collection. Now, how many maps does Oliver have in his collection?

InternLM-Math Base 20B:

      Reasoning: Oliver has 72+77 = <<72+77=149>>149 maps in his collection now.
    ### Answer: 149

Expected answer: 149

Correct? Yes

🔗 Problem

Problem: Joseph was weaving a blanket and the first day, he made 17 pieces. On the second day, he added an additional 33 pieces to his work. After seeing his work, his grandmother made 19 more pieces and added them to Joseph's work. How many pieces were made in total?

InternLM-Math Base 20B:

     Reasoning: Joseph made 17+33 = <<17+33=50>>50 pieces in the first two days.
    Joseph's grandmother made 19 more pieces, so Joseph made 50+19 = <<50+19=69>>69 pieces altogether.
    ### Answer: 69

Expected answer: 69

Correct? Yes

🔗 Problem

Problem: Mark has 79 apples from his apple picking trip. His friend gifts him more apples such that the total count is now 92 more than his initial count. A week later, his neighbor gifts him another 24 apples. How many apples does Mark have now?

InternLM-Math Base 20B:

     Reasoning: Mark has 79+92 = <<79+92=171>>171 apples after his friend gifts him.
    Mark has 171+24 = <<171+24=195>>195 apples after his neighbor gifts him.
    ### Answer: 195

Expected answer: 195

Correct? Yes

🔗 Follow-up

Problem: Following the previous scenario, Mark's cousin visits him and, being aware of his enthusiasm for apples, gifts him another 40 apples. Now, how many apples does Mark have in total?

InternLM-Math Base 20B:

      Reasoning: Mark has 195+40 = <<195+40=235>>235 apples after his cousin gifts him.
    ### Answer: 235

Expected answer: 235

Correct? Yes

🔗 Follow-up

Problem: Going back to Mark's initial apple count, let's say he originally had 79 apples from his apple picking trip. His friend gifts him more apples such that the total count is now 92 more than his initial count. This time, however, his neighbour gifts him another 64 apples instead of 24. How many apples does Mark have in this scenario?

InternLM-Math Base 20B:

      Reasoning: Mark has 79+92 = <<79+92=171>>171 apples after his friend gifts him.
    Mark has 171+64 = <<171+64=235>>235 apples after his neighbor gifts him.
    ### Answer: 235

Expected answer: 235

Correct? Yes

🔗 Problem

Problem: In a fairy realm, Twinkle, a star fairy finds 35 magical clovers. Lumina, a light fairy finds 69 more. How many magical clovers did they both find in total?

InternLM-Math Base 20B:

     Reasoning: Twinkle and Lumina found 35+69 = <<35+69=104>>104 magical clovers in total.
    ### Answer: 104

Expected answer: 104

Correct? Yes

🔗 Follow-up

Problem: After gathering their magical clovers, Twinkle and Lumina decide to pool their findings together. How many magical clovers do Twinkle and Lumina have together now?

InternLM-Math Base 20B:

      Reasoning: Twinkle and Lumina have 35+69 = <<35+69=104>>104 magical clovers together now.
    ### Answer: 104

Expected answer: 104

Correct? Yes

🔗 Follow-up

Problem: After re-counting their magical clovers, Twinkle realizes that she actually found 24, not 35. If Lumina still found 69, how many magical clovers do they have now when pooled together?

InternLM-Math Base 20B:

      Reasoning: Twinkle and Lumina now have 24+69 = <<24+69=93>>93 magical clovers in total.
    ### Answer: 93

Expected answer: 93

Correct? Yes

🔗 Problem

Problem: A weather instrument measured the wind speed at 93 miles per hour at one location. At another location, the wind speed was exactly the same. What was the combined wind speed recorded at the two locations?

InternLM-Math Base 20B:

     Reasoning: The wind speed at the two locations was 93+93 = <<93+93=186>>186 miles per hour.
    ### Answer: 186

Expected answer: 186

Correct? Yes

🔗 Follow-up

Problem: Continuing from the last problem, an additional location was checked, and its wind speed was also 93 miles per hour. What is the total wind speed recorded across all three locations?

InternLM-Math Base 20B:

      Reasoning: The total wind speed across all three locations was 186+93 = <<186+93=279>>279 miles per hour.
    ### Answer: 279

Expected answer: 279

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous problem, suppose that the wind speed at each of the initial two locations was 99 miles per hour instead of 93. What would the combined wind speed from these two locations be then?

InternLM-Math Base 20B:

      Reasoning: The wind speed at the two locations was 99+99 = <<99+99=198>>198 miles per hour.
    ### Answer: 198

Expected answer: 198

Correct? Yes

🔗 Problem

Problem: A robot is programmed to drive around a circuit. Initially, it travels 10 meters. Then, it runs an updated programming command that allows it to travel 26 meters more than it originally did. How far in total does the robot travel after running the updated programming command?

InternLM-Math Base 20B:

     Reasoning: The robot travels 10+26 = <<10+26=36>>36 meters after running the updated programming command.
    ### Answer: 36

Expected answer: 36

Correct? Yes

🔗 Follow-up

Problem: After the robot ran the updated programming command, it was given another update that allowed it to travel an additional 89 meters beyond the distance it covered with the first update. How far in total did the robot travel after this second update?

InternLM-Math Base 20B:

      Reasoning: The robot travels 36+89 = <<36+89=125>>125 meters after the second update.
    ### Answer: 125

Expected answer: 125

Correct? Yes

🔗 Follow-up

Problem: Consider if the robot initially traveled 43 meters instead of 10 meters before running the updated programming command. How far in total would the robot travel after running the updated programming command then?

InternLM-Math Base 20B:

      Reasoning: The robot travels 43+26 = <<43+26=69>>69 meters after running the updated programming command.
    ### Answer: 69

Expected answer: 69

Correct? Yes

🔗 Problem

Problem: Ella owns 5 pens, while Zach owns 30 pens. They both decide to donate all their pens to a local school. How many pens are they donating to the school?

InternLM-Math Base 20B:

     Reasoning: Ella and Zach are donating 5+30 = <<5+30=35>>35 pens to the school.
    ### Answer: 35

Expected answer: 35

Correct? Yes

🔗 Follow-up

Problem: After Ella and Zach donate their pens to the local school, the school received another donation of 80 pens from a stationery company. How many total pens does the school now have after receiving all of the donation?

InternLM-Math Base 20B:

      Reasoning: The school now has 35+80 = <<35+80=115>>115 pens.
    ### Answer: 115

Expected answer: 115

Correct? Yes

🔗 Follow-up

Problem: Ella realized that she actually had 50 pens instead of 5. Adding to Zach's 30 pens they had earlier, how many pens are they donating to the local school now?

InternLM-Math Base 20B:

      Reasoning: Ella and Zach are donating 50+30 = <<50+30=80>>80 pens to the school.
    ### Answer: 80

Expected answer: 80

Correct? Yes

🔗 Problem

Problem: A dog shelter has 62 indoor kennels and 52 outdoor kennels for the dogs. How many kennels do they have altogether?

InternLM-Math Base 20B:

     Reasoning: 62+52 = <<62+52=114>>114
    ### Answer: 114

Expected answer: 114

Correct? Yes

🔗 Follow-up

Problem: What if at the start, the shelter originally had 89 indoor kennels instead of 62. How many kennels would they have combined with the 52 outdoor kennels in this scenario?

InternLM-Math Base 20B:

      Reasoning: 89+52 = <<89+52=141>>141
    ### Answer: 141

Expected answer: 141

Correct? Yes

🔗 Problem

Problem: In a math class, students have to draw shapes based on certain numeric conditions. One student starts by rotating an angle to form 92 degrees. Then, he rotates the same angle by an additional 84 degrees. This gives him shape 't'. He modifies shape 't' by rotating another 90 degrees and labels this as shape 'l'. Finally, he rotates it by another 66 degrees to form shape 'n'. What is the total degree measure of the rotations made to get shape 'n'?

InternLM-Math Base 20B:

     Reasoning: The total degree measure of the rotations made to get shape 'n' is 92+84+90+66 = <<92+84+90+66=332>>332 degrees.
    ### Answer: 332

Expected answer: 332

Correct? Yes

🔗 Follow-up

Problem: After the student creates shape 'n', he isn't quite satisfied. He rotates his most recent shape by another 22 degrees in order to make shape 'z'. What is the total degree measure of the rotations made to end up with shape 'z'?

InternLM-Math Base 20B:

      Reasoning: The total degree measure of the rotations made to end up with shape 'z' is 92+84+90+66+22 = <<92+84+90+66+22=350>>350 degrees.
    ### Answer: 350

Expected answer: 354

Correct? No

🔗 Follow-up

Problem: Let's change the scenario a bit. Suppose the student does everything as before, rotating an angle to form 92 degrees, and again by an additional of 84 degrees to form shape 't'. Then they modify shape 't' by adding another 90 degrees to form shape 'l'. But this time, instead of rotating an additional 66 degrees for shape 'n', he rotates by 30 degrees. What would be the total degree measure of the rotations made to get to shape 'n' in this case?

InternLM-Math Base 20B:

      Reasoning: The total degree measure of the rotations made to get to shape 'n' in this case is 92+84+90+30 = <<92+84+90+30=296>>296 degrees.
    ### Answer: 296

Expected answer: 296

Correct? Yes

🔗 Problem

Problem: Jeremy bought 28 pieces of cheese from the cheese shop. Later that day, he buys 4 more pieces from the market. How many pieces of cheese does Jeremy now have?

InternLM-Math Base 20B:

     Reasoning: Jeremy bought 28+4 = <<28+4=32>>32 pieces of cheese altogether.
    ### Answer: 32

Expected answer: 32

Correct? Yes

🔗 Follow-up

Problem: Let's imagine that when Jeremy first went shopping, he actually only bought 26 pieces of cheese from the cheese shop, but he still bought 4 more pieces from the market later that day. How many pieces of cheese would Jeremy have then?

InternLM-Math Base 20B:

      Reasoning: Jeremy bought 26+4 = <<26+4=30>>30 pieces of cheese altogether.
    ### Answer: 30

Expected answer: 30

Correct? Yes

🔗 Problem

Problem: Once upon a time, there were 84 magic jewels in the secret treasure chest of the kingdom. Young princess Mia found the treasure chest and a magical charm that whenever she puts it on 83 more magic jewels appear in the chest. How many magic jewels are there in the treasure chest now?

InternLM-Math Base 20B:

     Reasoning: The princess put the magical charm on the treasure chest and 83 more magic jewels appeared in the chest. 84+83 = <<84+83=167>>167 magic jewels are in the treasure chest now.
    ### Answer: 167

Expected answer: 167

Correct? Yes

🔗 Follow-up

Problem: After Princess Mia discovered the magic of the charm, she was very excited and couldn't resist using the charm one more time. This time, instead of 83 magic jewels, 72 extra magic jewels appeared in the treasure chest. How many magic jewels are there in the treasure chest now?

InternLM-Math Base 20B:

      Reasoning: The princess put the magical charm on the treasure chest and 72 more magic jewels appeared in the chest. 167+72 = <<167+72=239>>239 magic jewels are in the treasure chest now.
    ### Answer: 239

Expected answer: 239

Correct? Yes

🔗 Problem

Problem: In a jewelry store, there are 98 rings on display. In another display case, there are an additional number of rings that is equal to 59 plus the number of rings in the first display case. How many rings are in the second display case?

InternLM-Math Base 20B:

     Reasoning: The number of rings in the second display case is 98+59 = <<98+59=157>>157.
    ### Answer: 157

Expected answer: 157

Correct? Yes

🔗 Follow-up

Problem: Following the previous scenario, the jewelry store receives a new batch of 84 rings that are added to the second display case. What is the new total number of rings in the second display case after adding the new batch?

InternLM-Math Base 20B:

      Reasoning: The new total number of rings in the second display case is 157+84 = <<157+84=241>>241.
    ### Answer: 241

Expected answer: 241

Correct? Yes

🔗 Follow-up

Problem: Let's rethink our original scenario at the jewelry store. Suppose instead that the second display contained a number of rings equal to 43 plus the number of rings in the first display case, which was 98. In that case, how many rings would the second display case have held?

InternLM-Math Base 20B:

      Reasoning: The number of rings in the second display case is 98+43 = <<98+43=141>>141.
    ### Answer: 141

Expected answer: 141

Correct? Yes

🔗 Problem

Problem: In a school stationery shop, there are 74 erasers available. If the shopkeeper adds 32 more erasers to the inventory, how many erasers are there in total?

InternLM-Math Base 20B:

     Reasoning: 74+32 = <<74+32=106>>106
    ### Answer: 106

Expected answer: 106

Correct? Yes

🔗 Follow-up

Problem: In a school stationery shop, there are 74 erasers available. A shopkeeper adds 32 more erasers to the inventory. Later in the day, a student donates another 24 erasers to the school shop. How many erasers are there in total now?

InternLM-Math Base 20B:

      Reasoning: 74+32+24 = <<74+32+24=130>>130
    ### Answer: 130

Expected answer: 130

Correct? Yes

🔗 Problem

Problem: Sally was on a swing and she swung back and forth 57 times. Jack also started swinging and he swung back and forth 57 more times than Sally. Xavier, feeling competitive, starts swinging too and he further manages to swing back forth 92 times more than Jack. How many times did Xavier swing back and forth?

InternLM-Math Base 20B:

     Reasoning: Xavier swung back and forth 57+57+92 = <<57+57+92=206>>206 times.
    ### Answer: 206

Expected answer: 206

Correct? Yes

🔗 Follow-up

Problem: After Xavier finishes his turn on the swing, Faye decides to take a ride. She swings back and forth 95 times. If we add the number of times Faye swung to the number of times Xavier swung, how many total swings is that?

InternLM-Math Base 20B:

      Reasoning: Faye swung 95 times and Xavier swung 206 times. 95+206 = <<95+206=301>>301.
    ### Answer: 301

Expected answer: 301

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, we learned that Jack swung 57 times more than Sally. But what if Jack had only swung 46 times more than Sally? Sally still swung 57 times. If Jack then swung 46 more times than Sally, and Xavier again swung 92 times more than Jack, how many swings would Xavier have taken in this case?

InternLM-Math Base 20B:

      Reasoning: Xavier swung back and forth 57+46+92 = <<57+46+92=195>>195 times.
    ### Answer: 195

Expected answer: 195

Correct? Yes

🔗 Problem

Problem: Tommy absolutely loves ice cream. One day he ate 15 ice creams. The next day, he ate twice that amount. On the third day, he couldn't resist and ate 31 more than he did on the second day. How many ice creams did Tommy eat on the third day?

InternLM-Math Base 20B:

     Reasoning: Tommy ate 15 ice creams on the first day.
    He ate 15*2 = <<15*2=30>>30 ice creams on the second day.
    He ate 30+31 = <<30+31=61>>61 ice creams on the third day.
    ### Answer: 61

Expected answer: 61

Correct? Yes

🔗 Follow-up

Problem: In the initial scenario, Tommy ate 15 ice creams on the first day and twice that amount on the second. Given this, suppose on the third day, Tommy ate 32 more than the number of ice creams he had on the second day, instead of 31. How many ice creams would Tommy have eaten on the third day, then?

InternLM-Math Base 20B:

      Reasoning: Tommy ate 15 ice creams on the first day.
    He ate 15*2 = <<15*2=30>>30 ice creams on the second day.
    He ate 30+32 = <<30+32=62>>62 ice creams on the third day.
    ### Answer: 62

Expected answer: 62

Correct? Yes

🔗 Problem

Problem: Michael has a camera collection. He starts off with 97 cameras. He wins a major auction and adds another 65 cameras. How many cameras does he have in his collection now?

InternLM-Math Base 20B:

     Reasoning: Michael has 97+65 = <<97+65=162>>162 cameras in his collection now.
    ### Answer: 162

Expected answer: 162

Correct? Yes

🔗 Follow-up

Problem: After winning the auction, Michael receives a gift of 82 more cameras from a close friend who is retiring from photography. How many cameras does he have in his collection now?

InternLM-Math Base 20B:

      Reasoning: Michael has 97+65+82 = <<97+65+82=244>>244 cameras in his collection now.
    ### Answer: 244

Expected answer: 244

Correct? Yes

🔗 Follow-up

Problem: What would have been the total number of cameras if Michael originally started off with 35 cameras instead of 97 before he won the auction and received additional cameras?

InternLM-Math Base 20B:

      Reasoning: Michael would have had 35+65 = <<35+65=100>>100 cameras in his collection.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Problem

Problem: Sam has 75 skateboard stickers. His friend Zack gives him another 68 stickers. Later, his other friend Ethan gives him 46 more stickers. How many skateboard stickers does Sam have now?

InternLM-Math Base 20B:

     Reasoning: Sam has 75+68+46 = <<75+68+46=189>>189 stickers now.
    ### Answer: 189

Expected answer: 189

Correct? Yes

🔗 Follow-up

Problem: Let's imagine that this time, Sam originally had 75 skateboard stickers, but his friend Zack gave him fewer stickers than before, just 68 stickers. However, his other friend Ethan only contributes 16 stickers this time. How many skateboard stickers does Sam have now?

InternLM-Math Base 20B:

      Reasoning: Sam has 75+68+16 = <<75+68+16=159>>159 stickers now.
    ### Answer: 159

Expected answer: 159

Correct? Yes

🔗 Problem

Problem: Samantha has 54 yellow crayons in her art box. Then, her friend Christina gave her 20 more crayons. How many crayons does Samantha have in total?

InternLM-Math Base 20B:

     Reasoning: Samantha has 54+20 = <<54+20=74>>74 crayons in total.
    ### Answer: 74

Expected answer: 74

Correct? Yes

🔗 Follow-up

Problem: Samantha counts all the crayons in her art box. She realizes that she now has a new total number of crayons due to the 54 yellow ones and the 20 her friend Christina gave her. How many crayons does Samantha have now?

InternLM-Math Base 20B:

      Reasoning: Samantha has 54+20 = <<54+20=74>>74 crayons in total.
    ### Answer: 74

Expected answer: 74

Correct? Yes

🔗 Follow-up

Problem: Suppose Samantha originally had only 3 yellow crayons in her art box instead of 54 before her friend Christina gave her 20 more crayons. How many crayons would Samantha have in that case?

InternLM-Math Base 20B:

      Reasoning: Samantha has 3+20 = <<3+20=23>>23 crayons in total.
    ### Answer: 23

Expected answer: 23

Correct? Yes

🔗 Problem

Problem: In an amusement park, there are 75 people waiting in line to slide down one slide, while 73 people are lined up for another slide. How many total people are waiting to slide down the slides?

InternLM-Math Base 20B:

     Reasoning: 75+73 = <<75+73=148>>148 people are waiting to slide down the slides.
    ### Answer: 148

Expected answer: 148

Correct? Yes

🔗 Follow-up

Problem: After recounting, it turns out that there were actually 27 people waiting in line for one slide, not 75, while 73 people are still lined up for the other slide. Now, how many total people are waiting to slide down the slides?

InternLM-Math Base 20B:

      Reasoning: 27+73 = <<27+73=100>>100 people are waiting to slide down the slides.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Problem

Problem: A teacher has a classroom of 10 students in the morning and 13 students in the afternoon. The other teacher has 36 students in the morning and 80 in the afternoon. How many students do these teachers teach in total in a day?

InternLM-Math Base 20B:

     Reasoning: The first teacher has 10+13 = <<10+13=23>>23 students in a day.
    The second teacher has 36+80 = <<36+80=116>>116 students in a day.
    The teachers teach 23+116 = <<23+116=139>>139 students in total in a day.
    ### Answer: 139

Expected answer: 139

Correct? Yes

🔗 Follow-up

Problem: A teacher has a classroom of 10 students in the morning and 13 students in the afternoon. The other teacher has 36 students in the morning and 80 in the afternoon. The school just received a transfer of 85 more students. How many students do these teachers teach in total in a day after the new students arrive?

InternLM-Math Base 20B:

      Reasoning: The first teacher has 10+13 = <<10+13=23>>23 students in a day.
    The second teacher has 36+80 = <<36+80=116>>116 students in a day.
    The teachers teach 23+116 = <<23+116=139>>139 students in total in a day.
    ### Answer: 139

Expected answer: 224

Correct? No

🔗 Follow-up

Problem: In the original scenario, one teacher had a classroom of 10 students in the morning and 13 students in the afternoon. But what if there were actually 30 students in the morning instead of 10? The other teacher has 36 students in the morning and 80 in the afternoon, as before. How many students do these teachers teach in total in a day in this new scenario?

InternLM-Math Base 20B:

      Reasoning: The first teacher has 30+13 = <<30+13=43>>43 students in a day.
    The second teacher has 36+80 = <<36+80=116>>116 students in a day.
    The teachers teach 43+116 = <<43+116=159>>159 students in total in a day.
    ### Answer: 159

Expected answer: 159

Correct? Yes

🔗 Problem

Problem: A wizard named Albus needs to perform an enchantment. The enchantment requires 43 units of sage. To make the spell stronger, he also adds a mixture that contains 78 units of elderberry and 85 units of thistle. What is the total amount of ingredients used in the enchantment?

InternLM-Math Base 20B:

     Reasoning: Albus uses 43+78+85 = <<43+78+85=206>>206 units of ingredients in the enchantment.
    ### Answer: 206

Expected answer: 206

Correct? Yes

🔗 Follow-up

Problem: Albus, the wizard, realizes he needs to amplify the enchantment even further. He decides to add 67 units of phoenix feather in addition to the sage, elderberry and thistle. Now, what is the total amount of ingredients used in the enchantment?

InternLM-Math Base 20B:

      Reasoning: Albus uses 43+78+85+67 = <<43+78+85+67=273>>273 units of ingredients in the enchantment.
    ### Answer: 273

Expected answer: 273

Correct? Yes

🔗 Problem

Problem: John bought 59 jackets for the winter season. Later, he bought another 22 jackets. Driven by the sale, he also bought 58 jackets with different colors and patterns. How many jackets did John buy in total?

InternLM-Math Base 20B:

     Reasoning: John bought 59+22+58 = <<59+22+58=139>>139 jackets in total.
    ### Answer: 139

Expected answer: 139

Correct? Yes

🔗 Follow-up

Problem: In the previous question, John had bought a total of 139 jackets. However, his family members also wanted some jackets for themselves. So, he bought an additional 35 jackets for his family. How many jackets did John buy in total now?

InternLM-Math Base 20B:

      Reasoning: John bought 139+35 = <<139+35=174>>174 jackets in total.
    ### Answer: 174

Expected answer: 174

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, John initially bought 59 jackets. However, let's reconsider that scenario with a slight modification. This time, after buying the initial 59 jackets, John went to another store and bought 83 more jackets. Then, as he was leaving, he noticed a stand with discount jackets and purchased 58 more of them there. How many jackets did John buy in total under these new conditions?

InternLM-Math Base 20B:

      Reasoning: John bought 59+83+58 = <<59+83+58=200>>200 jackets in total.
    ### Answer: 200

Expected answer: 200

Correct? Yes

🔗 Problem

Problem: On Thursday, the city experienced rainfall of about 69mm. On Friday, it rained more with an increase of 31mm compared to the previous day. On Saturday, it poured heavily throughout the day and the city saw 82mm of rain. How much total rainfall did the city experience on Friday and Saturday?

InternLM-Math Base 20B:

     Reasoning: On Friday, the city experienced rainfall of 69+31 = <<69+31=100>>100mm.
    On Saturday, the city experienced rainfall of 82mm.
    The total rainfall on Friday and Saturday was 100+82 = <<100+82=182>>182mm.
    ### Answer: 182

Expected answer: 182

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, we considered an increase in rainfall of 31mm from Thursday to Friday. But what if the increase was less, let's say only 19mm more than Thursday's rainfall of 69mm? Then how much total rainfall did the city experience on Friday and Saturday?

InternLM-Math Base 20B:

      Reasoning: On Friday, the city experienced rainfall of 69+19 = <<69+19=88>>88mm.
    On Saturday, the city experienced rainfall of 82mm.
    The total rainfall on Friday and Saturday was 88+82 = <<88+82=170>>170mm.
    ### Answer: 170

Expected answer: 170

Correct? Yes

🔗 Problem

Problem: A penguin named Zazu finds 66 shiny stones. Zazu sees that his friend Umi has found 70 more shiny stones than him. Another friend named Yara tucked away 36 shiny stones in addition to what Umi found. How many shiny stones did Yara find in total?

InternLM-Math Base 20B:

     Reasoning: Umi found 66+70 = <<66+70=136>>136 stones.
    Yara found 136+36 = <<136+36=172>>172 stones.
    ### Answer: 172

Expected answer: 172

Correct? Yes

🔗 Follow-up

Problem: After all the shiny stones have been counted, a penguin named Dina dives and finds an additional 34 shiny stones. How many shiny stones are there in total now considering Yara's stones and the ones that Dina found?

InternLM-Math Base 20B:

      Reasoning: Yara found 172 stones.
    Dina found 34 stones.
    Yara and Dina found 172+34 = <<172+34=206>>206 stones.
    ### Answer: 206

Expected answer: 206

Correct? Yes

🔗 Follow-up

Problem: Recall from the last time, Zazu found 66 shiny stones initially. Umi found 70 more shiny stones than Zazu. However, now consider that Yara only found 45 shiny stones more than what Umi found, instead of the 36 as previously stated. How many shiny stones did Yara find in this new scenario?

InternLM-Math Base 20B:

      Reasoning: Umi found 66+70 = <<66+70=136>>136 stones.
    Yara found 136+45 = <<136+45=181>>181 stones.
    ### Answer: 181

Expected answer: 181

Correct? Yes

🔗 Problem

Problem: A river is composed of 77 miles of calm water. A new tributary recently merged and extended the river by an additional 26 miles. Later, a 99-mile rapid water stretch is discovered and added to the river's length. How long is the river in total?

InternLM-Math Base 20B:

     Reasoning: The river is 77+26+99 = <<77+26+99=202>>202 miles long.
    ### Answer: 202

Expected answer: 202

Correct? Yes

🔗 Problem

Problem: An optical shop manages to sell 44 eyeglasses in the month of May and 84 in the month of June. The total number of glasses sold before May was 77. How many eyeglasses has the shop sold in total?

InternLM-Math Base 20B:

     Reasoning: The number of glasses sold in May is 44, and the number of glasses sold in June is 84. The total number of glasses sold before May is 77. Therefore, the total number of glasses sold in May and June is 44+84 = <<44+84=128>>128. The total number of glasses sold is 77+128 = <<77+128=205>>205.
    ### Answer: 205

Expected answer: 205

Correct? Yes

🔗 Follow-up

Problem: What if instead of selling 77 eyeglasses before May, they only sold 44 eyeglasses? How many eyeglasses has the shop sold in total then (including sales in May, June, and the first week of July)?

InternLM-Math Base 20B:

      Reasoning: The number of glasses sold in May is 44, and the number of glasses sold in June is 84. The total number of glasses sold before May is 44. Therefore, the total number of glasses sold in May and June is 44+84 = <<44+84=128>>128. The total number of glasses sold is 44+128 = <<44+128=172>>172.
    ### Answer: 172

Expected answer: 172

Correct? Yes

🔗 Problem

Problem: In preparing for a camping trip, a group of friends collected 8 small tents and 88 large tents. They then added 17 medium tents to their collection. Separately, they also managed to gather 77 ground mats for the tents. How many total items including both tents and ground mats did they gather for the camping trip?

InternLM-Math Base 20B:

     Reasoning: The group of friends gathered 8+88+17 = <<8+88+17=113>>113 tents and 77 ground mats. So, they gathered 113+77 = <<113+77=190>>190 items altogether.
    ### Answer: 190

Expected answer: 190

Correct? Yes

🔗 Follow-up

Problem: Now consider this - instead of initially collecting 8 small tents, the group collected 9. They still maintained the same number of large tents at 88 and added 17 medium tents just as before. If they also collected 77 ground mats, how many total items including both tents and ground mats did they gather for the camping trip now?

InternLM-Math Base 20B:

      Reasoning: The group of friends gathered 9+88+17 = <<9+88+17=114>>114 tents and 77 ground mats. So, they gathered 114+77 = <<114+77=191>>191 items altogether.
    ### Answer: 191

Expected answer: 191

Correct? Yes

🔗 Problem

Problem: In Lila's vineyard, one grapevine produced 61 grapes while another produced 49 grapes. What is the total number of grapes produced by these two grapevines?

InternLM-Math Base 20B:

     Reasoning: 61+49 = <<61+49=110>>110 grapes were produced by the two grapevines.
    ### Answer: 110

Expected answer: 110

Correct? Yes

🔗 Follow-up

Problem: In addition to Lila's vineyard, her neighbor also runs a vineyard. This year, the neighbor's vineyard produced 94 grapes. What is the total number of grapes produced by Lila and her neighbor's vineyards combined?

InternLM-Math Base 20B:

      Reasoning: 110+94 = <<110+94=204>>204 grapes were produced by the two vineyards.
    ### Answer: 204

Expected answer: 204

Correct? Yes

🔗 Follow-up

Problem: Let's reconsider Lila's vineyard. Suppose one of the grapevines originally produced 50 grapes instead of 61. With the other grapevine still producing 49 grapes, what would then be the total number of grapes produced by these two grapevines?

InternLM-Math Base 20B:

      Reasoning: 50+49 = <<50+49=99>>99 grapes were produced by the two grapevines.
    ### Answer: 99

Expected answer: 99

Correct? Yes

🔗 Problem

Problem: Sally is a fashion designer who loves knitting socks. One day, she made 63 colourful pairs of socks. The next day, she decided to add 6 more pairs to her collection. How many pairs of socks does Sally have now?

InternLM-Math Base 20B:

     Reasoning: Sally made 63+6 = <<63+6=69>>69 pairs of socks.
    ### Answer: 69

Expected answer: 69

Correct? Yes

🔗 Follow-up

Problem: After knitting her socks, Sally decided to try knitting mittens as well. She found that she really liked it, and she was able to knit 16 pairs of mittens. How many pairs of socks and mittens does Sally have now?

InternLM-Math Base 20B:

      Reasoning: Sally has 69+16 = <<69+16=85>>85 pairs of socks and mittens.
    ### Answer: 85

Expected answer: 85

Correct? Yes

🔗 Follow-up

Problem: Suppose Sally didn't make 63 pairs of socks, but she actually only made 9 pairs of socks initially. She still added 6 more pairs of socks the next day as she did previously. How many pairs of socks does Sally have now?

InternLM-Math Base 20B:

      Reasoning: Sally made 9+6 = <<9+6=15>>15 pairs of socks.
    ### Answer: 15

Expected answer: 15

Correct? Yes

🔗 Problem

Problem: Mike is the owner of an aquarium. He added 13 gallons of water to one of his tanks in the morning. Later in the afternoon, he added another 55 gallons to the same tank. Meanwhile, in another tank, he added 57 gallons in the morning and an additional 33 gallons in the afternoon. What is the total quantity of water (in gallons) that Mike added to both of his tanks throughout the day?

InternLM-Math Base 20B:

     Reasoning: Mike added 13+55 = <<13+55=68>>68 gallons to the first tank and 57+33 = <<57+33=90>>90 gallons to the second tank. Therefore, he added 68+90 = <<68+90=158>>158 gallons to both tanks.
    ### Answer: 158

Expected answer: 158

Correct? Yes

🔗 Follow-up

Problem: Now, imagine that Mike also has a large pond outside his house. In the evening, he decides to refill it and adds 56 gallons of water. Considering all three locations (the two tanks and the pond), how much total water did Mike add throughout the day?

InternLM-Math Base 20B:

      Reasoning: Mike added 68+90+56 = <<68+90+56=214>>214 gallons of water throughout the day.
    ### Answer: 214

Expected answer: 214

Correct? Yes

🔗 Follow-up

Problem: Let's reconsider the scenario. Instead of adding 55 gallons of water to his first tank, suppose Mike instead adds 96 gallons of water in the afternoon. Given that all other quantities remain the same with 13 gallons added in the morning to the first tank, and the second tank receiving 57 gallons in the morning and an additional 33 gallons in the afternoon, how much total water did Mike add to both tanks throughout the day?

InternLM-Math Base 20B:

      Reasoning: Mike added 13+96 = <<13+96=109>>109 gallons to the first tank and 57+33 = <<57+33=90>>90 gallons to the second tank. Therefore, he added 109+90 = <<109+90=199>>199 gallons to both tanks.
    ### Answer: 199

Expected answer: 199

Correct? Yes

🔗 Problem

Problem: Teddy has a favorite toy which is a tiny teddy bear. One day, Teddy's dad gave him 64 more teddy bears. Teddy's mom, feeling envious, gave Teddy 60 more teddy bears plus the exact number of teddy bears Teddy's dad gave him. At the end of the day, Teddy's grandma surprised him with twice the number of teddy bears his mom gave him. How many teddy bears did Teddy receive from his grandma?

InternLM-Math Base 20B:

     Reasoning: Teddy's mom gave him 60+64 = <<60+64=124>>124 teddy bears.
    Teddy's grandma gave him 2*124 = <<2*124=248>>248 teddy bears.
    ### Answer: 248

Expected answer: 248

Correct? Yes

🔗 Follow-up

Problem: Let's imagine that instead of 64 teddy bears, Teddy's dad initially gave him only 30 teddy bears. Teddy's mom, feeling envious as before, gave Teddy 60 more bears plus the exact number of bears Teddy's dad gave him. At the end of the day, Teddy's grandma, wanting to double the joy, surprised him with twice the number of teddy bears his mom gave him. How many teddy bears did Teddy receive from his grandma under this new scenario?

InternLM-Math Base 20B:

      Reasoning: Teddy's mom gave him 60+30 = <<60+30=90>>90 teddy bears.
    Teddy's grandma gave him 2*90 = <<2*90=180>>180 teddy bears.
    ### Answer: 180

Expected answer: 180

Correct? Yes

🔗 Problem

Problem: In a forest, there are 84 oak trees. If the number of pine trees adds 75 more to the total number of trees, how many trees are there in the forest?

InternLM-Math Base 20B:

     Reasoning: The number of pine trees is 84+75 = <<84+75=159>>159.
    The total number of trees is 84+159 = <<84+159=243>>243.
    ### Answer: 243

Expected answer: 159

Correct? No

🔗 Problem

Problem: In a newly discovered dinosaur park, scientists found 71 Neovenator dinosaurs and 56 Ferrotholus dinosaurs. How many total dinosaurs did they find in all?

InternLM-Math Base 20B:

     Reasoning: 71+56 = <<71+56=127>>127
    ### Answer: 127

Expected answer: 127

Correct? Yes

🔗 Follow-up

Problem: After their initial discovery at the dinosaur park, scientists found another group of dinosaurs which was equal to the total number of Neovenator and Ferrotholus dinosaurs combined. How many dinosaurs did the scientists find in this second group?

InternLM-Math Base 20B:

      Reasoning: 71+56 = <<71+56=127>>127
    ### Answer: 127

Expected answer: 127

Correct? Yes

🔗 Follow-up

Problem: In their initial findings, the scientists had made a miscount and actually found 54 Neovenator dinosaurs instead of 71. With the same number of Ferrotholus dinosaurs being 56, what is the corrected total number of dinosaurs they found?

InternLM-Math Base 20B:

      Reasoning: 54+56 = <<54+56=110>>110
    ### Answer: 110

Expected answer: 110

Correct? Yes

🔗 Problem

Problem: A boat has traveled 88 miles today. The next day, it travels 92 more miles plus the miles it traveled today. The third day, it travels an additional 61 miles plus the miles it traveled the previous days. How many miles has the boat traveled in these three days?

InternLM-Math Base 20B:

     Reasoning: The boat traveled 88+92 = <<88+92=180>>180 miles the next day.
    The boat traveled 180+61 = <<180+61=241>>241 miles the third day.
    The boat traveled 88+180+241 = <<88+180+241=509>>509 miles in these three days.
    ### Answer: 509

Expected answer: 241

Correct? No

🔗 Problem

Problem: Sarah has 7 liters of apple juice. She went to the store and bought 69 more liters. How many liters of apple juice does Sarah have now?

InternLM-Math Base 20B:

     Reasoning: Sarah has 7+69 = <<7+69=76>>76 liters of apple juice now.
    ### Answer: 76

Expected answer: 76

Correct? Yes

🔗 Follow-up

Problem: Initially, Sarah thought she had bought only 7 liters of juice, but she realized she had actually bought 55 liters of apple juice. If she still bought an additional 69 liters from the store, how much apple juice does Sarah have in total now?

InternLM-Math Base 20B:

      Reasoning: Sarah has 7+55+69 = <<7+55+69=131>>131 liters of apple juice now.
    ### Answer: 131

Expected answer: 124

Correct? No

🔗 Problem

Problem: Sally is on a mission to build the biggest marshmallow tower. She starts with 83 marshmallows, but then her friend brings an additional 33 marshmallows. How many marshmallows does Sally have now for her tower?

InternLM-Math Base 20B:

     Reasoning: Sally has 83+33 = <<83+33=116>>116 marshmallows.
    ### Answer: 116

Expected answer: 116

Correct? Yes

🔗 Follow-up

Problem: After Sally counts all her marshmallows, her other friend decides to contribute as well and brings 22 more marshmallows. How many marshmallows does Sally have in total now for her tower?

InternLM-Math Base 20B:

      Reasoning: Sally has 116+22 = <<116+22=138>>138 marshmallows.
    ### Answer: 138

Expected answer: 138

Correct? Yes

🔗 Follow-up

Problem: Suppose Sally started with only 13 marshmallows instead of 83 and then her friend brought the same amount of 33 additional marshmallows. How many marshmallows would Sally have had then for her tower?

InternLM-Math Base 20B:

      Reasoning: Sally has 13+33 = <<13+33=46>>46 marshmallows.
    ### Answer: 46

Expected answer: 46

Correct? Yes

🔗 Problem

Problem: Jenna is a jewelry maker. She currently has 48 earrings in stock. She makes an additional 34 earrings for a special event. After the event, Jenna makes 24 more earrings to replenish her stock. How many earrings does she have in total?

InternLM-Math Base 20B:

     Reasoning: Jenna has 48+34+24 = <<48+34+24=106>>106 earrings in total.
    ### Answer: 106

Expected answer: 106

Correct? Yes

🔗 Follow-up

Problem: After the special event, Jenna decides to replenish her stock by making 94 more earrings instead of the 24 she initially planned. Now, how many earrings does she have on her shelf?

InternLM-Math Base 20B:

      Reasoning: Jenna has 48+34+94 = <<48+34+94=176>>176 earrings in total.
    ### Answer: 176

Expected answer: 176

Correct? Yes

🔗 Problem

Problem: In a city, 48 babies were born in March, and in April, another 25 were born. How many babies were born in these two months in total?

InternLM-Math Base 20B:

     Reasoning: 48+25 = <<48+25=73>>73 babies were born in these two months in total.
    ### Answer: 73

Expected answer: 73

Correct? Yes

🔗 Follow-up

Problem: In May, the number of babies born matches the total of both March and April. How many babies were born in May?

InternLM-Math Base 20B:

      Reasoning: 48+25 = <<48+25=73>>73 babies were born in these two months in total.
    ### Answer: 73

Expected answer: 73

Correct? Yes

🔗 Follow-up

Problem: In a rethink, the hospital realized that there were actually 55 babies born in March, not 48. With the 25 born in April, how many babies were born in total over the two months?

InternLM-Math Base 20B:

      Reasoning: 55+25 = <<55+25=80>>80 babies were born in these two months in total.
    ### Answer: 80

Expected answer: 80

Correct? Yes

🔗 Problem

Problem: At a drum store, there are 52 drum sets on display and 1 more drum set in the store room. In a different section of the same store, there are also 46 single drums. How many total drums and drum sets are in the store?

InternLM-Math Base 20B:

     Reasoning: There are 52+1 = <<52+1=53>>53 drum sets in the store.
    There are 46 single drums in the store.
    There are 53+46 = <<53+46=99>>99 total drums and drum sets in the store.
    ### Answer: 99

Expected answer: 99

Correct? Yes

🔗 Follow-up

Problem: Suppose in the store, instead of having 52 drum sets, there were only 52 single drums, in addition to the 1 drum set in the store room. Given that there are still 46 single drums in a different section, how many drums and drum sets are then in the store?

InternLM-Math Base 20B:

      Reasoning: There are 52+1 = <<52+1=53>>53 single drums in the store.
    There are 46 single drums in the store.
    There are 53+46 = <<53+46=99>>99 total drums and drum sets in the store.
    ### Answer: 99

Expected answer: 99

Correct? Yes

🔗 Problem

Problem: A store sells 9 boxes of oranges each day. The following day, the seller added 22 more boxes to the total from the previous day. The next day, he added another 26 boxes to that day's total. How many boxes of oranges does the store have on the last day?

InternLM-Math Base 20B:

     Reasoning: The store has 9+22+26 = <<9+22+26=57>>57 boxes of oranges on the last day.
    ### Answer: 57

Expected answer: 57

Correct? Yes

🔗 Follow-up

Problem: Following on from the problem with the orange seller: after the seller added 26 boxes to the previous day's total, he decided to get a major shipment of oranges. So, he added an impressive shipment of 96 more boxes to the pile. Now, how many boxes of oranges does the store have?

InternLM-Math Base 20B:

      Reasoning: The store has 9+22+26+96 = <<9+22+26+96=143>>143 boxes of oranges.
    ### Answer: 143

Expected answer: 153

Correct? No

🔗 Follow-up

Problem: Following on from the previous scenario with the orange seller: suppose that the seller initially had only 9 boxes of orange but on the subsequent day, he added 22 new boxes as before. However, instead of adding 26 boxes to total on the third day this time, he adds 66 boxes. How many boxes of oranges does the store have now?

InternLM-Math Base 20B:

      Reasoning: The store has 9+22+66 = <<9+22+66=97>>97 boxes of oranges now.
    ### Answer: 97

Expected answer: 97

Correct? Yes

🔗 Problem

Problem: Yvonne has 27 balls in her collection. She went to a fair and won 19 more. How many balls does Yvonne have in her collection now?

InternLM-Math Base 20B:

     Reasoning: Yvonne has 27+19 = <<27+19=46>>46 balls in her collection now.
    ### Answer: 46

Expected answer: 46

Correct? Yes

🔗 Follow-up

Problem: After donating some of her balls, Yvonne now has 97 balls left in her collection. She goes to another fair and wins 19 more. How many balls does Yvonne have in her collection now?

InternLM-Math Base 20B:

      Reasoning: Yvonne has 97+19 = <<97+19=116>>116 balls in her collection now.
    ### Answer: 116

Expected answer: 116

Correct? Yes

🔗 Problem

Problem: In the sky, a cloud split into 8 small clouds and 13 larger ones. Another cloud split the same way. How many total clouds were formed?

InternLM-Math Base 20B:

     Reasoning: 8+13 = <<8+13=21>>21 clouds were formed from the first cloud.
    8+13 = <<8+13=21>>21 clouds were formed from the second cloud.
    21+21 = <<21+21=42>>42 clouds were formed altogether.
    ### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Follow-up

Problem: After splitting, the original clouds came back together and formed 91 additional smaller clouds. How many total clouds are there now including the additional smaller clouds formed?

InternLM-Math Base 20B:

      Reasoning: 42+91 = <<42+91=133>>133 clouds are there now.
    ### Answer: 133

Expected answer: 133

Correct? Yes

🔗 Follow-up

Problem: What if initially, instead of splitting into 8 small clouds, each of the two clouds split into 43 small clouds and kept the 13 larger ones the same? How many total clouds would have formed in that case?

InternLM-Math Base 20B:

      Reasoning: 43+13 = <<43+13=56>>56 clouds were formed from the first cloud.
    43+13 = <<43+13=56>>56 clouds were formed from the second cloud.
    56+56 = <<56+56=112>>112 clouds were formed altogether.
    ### Answer: 112

Expected answer: 112

Correct? Yes

🔗 Problem

Problem: Oliver recently took up skateboard stunting. He can perform 77 stunts with his skateboard. Now, if he learns to perform each stunt in reverse as well, how many stunts will he be able to perform in total?

InternLM-Math Base 20B:

     Reasoning: Oliver can perform 77/2 = <<77/2=38.5>>38.5 stunts in reverse.
    Oliver can perform 77+38.5 = <<77+38.5=115.5>>115.5 stunts in total.
    ### Answer: 115.5

Expected answer: 154

Correct? No

🔗 Problem

Problem: A pair of binoculars increases visibility by 22 degrees in one direction and 26 degrees in another direction. What is the total increase in the angle of visibility when both directions are considered?

InternLM-Math Base 20B:

     Reasoning: 22+26 = <<22+26=48>>48 degrees.
    ### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous problem, after the binoculars increase visibility by 22 degrees in one direction and 26 degrees in another direction, an additional lens is added that further increases the visibility by 76 degrees. What is the total increase in the angle of visibility considering all enhancements?

InternLM-Math Base 20B:

      Reasoning: 22+26+76 = <<22+26+76=124>>124 degrees.
    ### Answer: 124

Expected answer: 124

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous problem, consider that the binoculars initially increased visibility by 14 degrees in one direction instead of 22 degrees, while the increase in the other direction remains 26 degrees. What is the total increase in the angle of visibility now when both directions are considered?

InternLM-Math Base 20B:

      Reasoning: 14+26 = <<14+26=40>>40 degrees.
    ### Answer: 40

Expected answer: 40

Correct? Yes

🔗 Problem

Problem: In a galaxy, there are 83 stars in the Great Nebula. Fifty more are spotted in the South Nebula. In the Eastern Nebula, there are 45 stars. How many stars are there in total in the Great Nebula, South Nebula, and Eastern Nebula?

InternLM-Math Base 20B:

     Reasoning: There are 83+50+45 = <<83+50+45=178>>178 stars in total in the Great Nebula, South Nebula, and Eastern Nebula.
    ### Answer: 178

Expected answer: 178

Correct? Yes

🔗 Follow-up

Problem: Following from the previous problem, a recalculation by astronomers reveals that there are actually 32 stars, not 83, in the Great Nebula. Considering this recalculation, with 50 stars still in the South Nebula, and 45 in the Eastern Nebula, how many stars are there now across these three nebulas?

InternLM-Math Base 20B:

      Reasoning: There are 32+50+45 = <<32+50+45=127>>127 stars in total in the Great Nebula, South Nebula, and Eastern Nebula.
    ### Answer: 127

Expected answer: 127

Correct? Yes

🔗 Problem

Problem: A boy has 15 balls. He goes to the store and buys another 22 balls. How many balls does he have now?

InternLM-Math Base 20B:

     Reasoning: The boy has 15+22 = <<15+22=37>>37 balls now.
    ### Answer: 37

Expected answer: 37

Correct? Yes

🔗 Follow-up

Problem: In addition to the balls he already has, his friends give him 64 more balls for his upcoming birthday. Now, how many balls does the boy have in total?

InternLM-Math Base 20B:

      Reasoning: The boy has 37+64 = <<37+64=101>>101 balls in total.
    ### Answer: 101

Expected answer: 101

Correct? Yes

🔗 Follow-up

Problem: Consider instead that the boy originally had 48 balls instead of 15. After buying another 22 balls from the store, how many balls does he have now?

InternLM-Math Base 20B:

      Reasoning: The boy has 48+22 = <<48+22=70>>70 balls now.
    ### Answer: 70

Expected answer: 70

Correct? Yes

🔗 Problem

Problem: Mira has 82 beautiful roses in her garden, and she decides to plant 12 additional daisies to add more variety. How many flowers does Mira have in her garden after planting the daisies?

InternLM-Math Base 20B:

     Reasoning: Mira has 82+12 = <<82+12=94>>94 flowers in her garden after planting the daisies.
    ### Answer: 94

Expected answer: 94

Correct? Yes

🔗 Follow-up

Problem: Suppose instead Mira originally had 88 roses in her garden before planting the 12 daisies. How many flowers would there be in Mira's garden then?

InternLM-Math Base 20B:

      Reasoning: Mira has 88+12 = <<88+12=100>>100 flowers in her garden after planting the daisies.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Problem

Problem: A jeweler strings together 82 gems to begin making a bracelet. He then adds 79 more gems to it. He finishes off the bracelet by adding 58 more gems. How many gems are there in total on the bracelet?

InternLM-Math Base 20B:

     Reasoning: The jeweler added 79+58 = <<79+58=137>>137 gems to the bracelet.
    The jeweler added 82+137 = <<82+137=219>>219 gems to the bracelet.
    ### Answer: 219

Expected answer: 219

Correct? Yes

🔗 Follow-up

Problem: Following the previous problem: after the jeweler has strung together the number of gems on the bracelet, he decides to make a matching necklace. He adds another 60 gems to the total number of gems he has already used. How many gems in total did the jeweler use for both the bracelet and the necklace?

InternLM-Math Base 20B:

      Reasoning: The jeweler added 60 to the bracelet.
    The jeweler added 219+60 = <<219+60=279>>279 gems to the bracelet and necklace.
    ### Answer: 279

Expected answer: 279

Correct? Yes

🔗 Follow-up

Problem: The jeweler has a change of mind and decides to start recreating the bracelet, but this time he starts with 77 gems instead of 82. He once again adds 79 more gems and completes it by adding 58 more gems. How many gems are now on this new bracelet in total?

InternLM-Math Base 20B:

      Reasoning: The jeweler added 79+58 = <<79+58=137>>137 gems to the bracelet.
    The jeweler added 77+137 = <<77+137=214>>214 gems to the bracelet.
    ### Answer: 214

Expected answer: 214

Correct? Yes

🔗 Problem

Problem: Dalia has a stock of 65 tomatoes. She decides to buy the same quantity again. How many tomatoes does she have now?

InternLM-Math Base 20B:

     Reasoning: Dalia has 65+65 = <<65+65=130>>130 tomatoes now.
    ### Answer: 130

Expected answer: 130

Correct? Yes

🔗 Follow-up

Problem: After buying the same quantity of tomatoes again, Dalia decides to buy 50 more from her friend's farm. How many tomatoes does she have in total now?

InternLM-Math Base 20B:

      Reasoning: Dalia has 130+50 = <<130+50=180>>180 tomatoes now.
    ### Answer: 180

Expected answer: 180

Correct? Yes

🔗 Follow-up

Problem: After seeing how her tomato stock fared last time, Dalia decides to start with 89 tomatoes this time. She decides again to buy the same quantity from her supplier. How many tomatoes does she have in stock now?

InternLM-Math Base 20B:

      Reasoning: Dalia has 89+89 = <<89+89=178>>178 tomatoes now.
    ### Answer: 178

Expected answer: 178

Correct? Yes

🔗 Problem

Problem: David has 25 pens in his pencil case. His best friend Pam gives him 34 more pens as a gift. How many pens does David have now?

InternLM-Math Base 20B:

     Reasoning: David has 25+34 = <<25+34=59>>59 pens now.
    ### Answer: 59

Expected answer: 59

Correct? Yes

🔗 Follow-up

Problem: David decided to count his pens to make sure he knows how many he has. When counting, he realizes he has as many pens as the total of the 25 pens in his pencil case and the 34 pens Pam gave him. How many pens does David count?

InternLM-Math Base 20B:

      Reasoning: David has 25+34 = <<25+34=59>>59 pens.
    ### Answer: 59

Expected answer: 59

Correct? Yes

🔗 Follow-up

Problem: David rechecks his pencil case and realizes he made a mistake. He actually had 55 pens in his pencil case, not 25. If Pam still gave him 34 pens, how many pens does David have now?

InternLM-Math Base 20B:

      Reasoning: David has 55+34 = <<55+34=89>>89 pens now.
    ### Answer: 89

Expected answer: 89

Correct? Yes

🔗 Problem

Problem: A clothing designer is creating a custom shirt. The length of the shirt is 86 cm. The chest measurement is the length added by 11 cm. The waist measurement is the same as the sum of the two chest measurements. What is the waist measurement of the shirt in cm?

InternLM-Math Base 20B:

     Reasoning: The length of the shirt is 86 cm. The chest measurement is 86+11 = <<86+11=97>>97 cm. The waist measurement is 97+97 = <<97+97=194>>194 cm.
    ### Answer: 194

Expected answer: 194

Correct? Yes

🔗 Follow-up

Problem: The clothing designer decides to adjust the shirt after taking the initial measurements. To ensure a comfortable fit, the designer adds a further 9 cm to the final waist measurement, which was the same as the sum of the two chest measurements. What is the new adjusted waist measurement of the shirt in cm?

InternLM-Math Base 20B:

      Reasoning: The new adjusted waist measurement is 194+9 = <<194+9=203>>203 cm.
    ### Answer: 203

Expected answer: 203

Correct? Yes

🔗 Follow-up

Problem: Recall the clothing designer from before. This time, the designer is creating a shirt with a different length of 99 cm. In this design, the chest measurement is defined as the length added by 11 cm. The waist measurement is set as the sum of the two chest measurements. What is the waist measurement of this new shirt design in cm?

InternLM-Math Base 20B:

      Reasoning: The length of the shirt is 99 cm. The chest measurement is 99+11 = <<99+11=110>>110 cm. The waist measurement is 110+110 = <<110+110=220>>220 cm.
    ### Answer: 220

Expected answer: 220

Correct? Yes

🔗 Problem

Problem: The computer has an initial operating power of 96 Watts. Later, an update increases the operational power by an additional 84 Watts. What is the computer's operation power after the update?

InternLM-Math Base 20B:

     Reasoning: The computer's operating power after the update is 96+84 = <<96+84=180>>180 Watts.
    ### Answer: 180

Expected answer: 180

Correct? Yes

🔗 Follow-up

Problem: Suppose that the computer initially had an operating power of 36 Watts instead of 96 Watts. Then, the same update increases the operational power by an additional 84 Watts. How much operation power would the computer have after the update in this scenario?

InternLM-Math Base 20B:

      Reasoning: The computer's operating power after the update is 36+84 = <<36+84=120>>120 Watts.
    ### Answer: 120

Expected answer: 120

Correct? Yes

🔗 Problem

Problem: A company produces 62 tubes of toothpaste every hour at their plant. Later, the company upgrades their production capacity and is now able to make 40 more tubes every hour. How many tubes of toothpaste can the company produce per hour after the upgrade?

InternLM-Math Base 20B:

     Reasoning: The company produces 62+40 = <<62+40=102>>102 tubes of toothpaste per hour after the upgrade.
    ### Answer: 102

Expected answer: 102

Correct? Yes

🔗 Follow-up

Problem: Suppose the company initially started with a production capacity of 75 tubes of toothpaste every hour instead of 62. After the first upgrade, which still added an additional 40 tubes of toothpaste to their hour production, how many toothpaste tubes can the company produce per hour?

InternLM-Math Base 20B:

      Reasoning: The company produces 75+40 = <<75+40=115>>115 tubes of toothpaste per hour after the upgrade.
    ### Answer: 115

Expected answer: 115

Correct? Yes

🔗 Problem

Problem: At the beginning of the month, a penguin had 31 fish. By the middle of the month, he had as many fish as the initial amount plus 31 more. At the end of the month, he had as many fish as the amount he had in the middle of the month and the initial 31 fish. How many fish did the penguin have at the end of the month?

InternLM-Math Base 20B:

     Reasoning: The penguin had 31+31 = <<31+31=62>>62 fish in the middle of the month.
    The penguin had 62+31 = <<62+31=93>>93 fish at the end of the month.
    ### Answer: 93

Expected answer: 93

Correct? Yes

🔗 Follow-up

Problem: Let's reconsider the original scenario with the penguin. Instead of getting the original 31 extra fish in the middle of the month, the penguin now only gets an additional 21 fish. Using the rest of the fish count as before, how many fish does the penguin have by the end of the month now?

InternLM-Math Base 20B:

      Reasoning: The penguin had 31+21 = <<31+21=52>>52 fish in the middle of the month.
    The penguin had 52+31 = <<52+31=83>>83 fish at the end of the month.
    ### Answer: 83

Expected answer: 83

Correct? Yes

🔗 Problem

Problem: Katie baked 34 cookies in the morning. She baked the same amount in the afternoon. How many cookies did Katie bake in total?

InternLM-Math Base 20B:

     Reasoning: Katie baked 34+34 = <<34+34=68>>68 cookies in total.
    ### Answer: 68

Expected answer: 68

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous problem, what if instead of making 34 cookies in the morning and afternoon, Katie actually baked 23 cookies during each time period? How many cookies did she make in total in that case?

InternLM-Math Base 20B:

      Reasoning: Katie baked 23+23 = <<23+23=46>>46 cookies in total.
    ### Answer: 46

Expected answer: 46

Correct? Yes

🔗 Problem

Problem: Emma bought 17 toothbrushes for her family. Her friend Clarissa then gave her an additional sum of 71 and 38 toothbrushes from her dentist's office. How many toothbrushes does Emma have now?

InternLM-Math Base 20B:

     Reasoning: Emma bought 17 toothbrushes.
    Clarissa gave her 71+38 = <<71+38=109>>109 toothbrushes.
    Emma has 17+109 = <<17+109=126>>126 toothbrushes now.
    ### Answer: 126

Expected answer: 126

Correct? Yes

🔗 Follow-up

Problem: Emma then visited a local health fair where she received an additional 59 toothbrushes to add to her collection. How many toothbrushes does Emma now have in total?

InternLM-Math Base 20B:

      Reasoning: Emma has 126 toothbrushes.
    Emma received 59 more toothbrushes.
    Emma has 126+59 = <<126+59=185>>185 toothbrushes now.
    ### Answer: 185

Expected answer: 185

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, suppose Emma initially bought 17 toothbrushes. But this time, Clarissa gives her an additional sum of 80 and 38 toothbrushes instead of the previous amount she received. How many toothbrushes does Emma have now?

InternLM-Math Base 20B:

      Reasoning: Emma bought 17 toothbrushes.
    Clarissa gave her 80+38 = <<80+38=118>>118 toothbrushes.
    Emma has 17+118 = <<17+118=135>>135 toothbrushes now.
    ### Answer: 135

Expected answer: 135

Correct? Yes

🔗 Problem

Problem: A frog is sitting on a leaf. The leaf is 31 cm from the ground. The frog jumps and reaches an exact same spot on another leaf. How much distance in centimeters did the frog cover in total?

InternLM-Math Base 20B:

     Reasoning: The frog jumped 31+31 = <<31+31=62>>62 cm in total.
    ### Answer: 62

Expected answer: 62

Correct? Yes

🔗 Follow-up

Problem: After jumping to another leaf, the frog decided to jump again to a flower that is 69 cm above from the ground. Considering the distance the frog covered in his previous jumps, how much distance in centimeters did the frog cover in total?

InternLM-Math Base 20B:

      Reasoning: The frog jumped 62+69 = <<62+69=131>>131 cm in total.
    ### Answer: 131

Expected answer: 131

Correct? Yes

🔗 Follow-up

Problem: Suppose instead of the initial 31 cm, the leaves were only 20 cm above the ground when the frog first started jumping. Given the same jumps as before, how much distance in centimeters would the frog cover then?

InternLM-Math Base 20B:

      Reasoning: The frog jumped 20+20 = <<20+20=40>>40 cm in total.
    ### Answer: 40

Expected answer: 40

Correct? Yes

🔗 Problem

Problem: In a summer vacation assignment, Olivia wrote 70 words on her first day and 23 words on the second day. In addition to this, Isabella wrote 17 words in her assignment. Find the total number of words written by both Olivia and Isabella.

InternLM-Math Base 20B:

     Reasoning: Olivia wrote 70+23 = <<70+23=93>>93 words in her assignment.
    Isabella wrote 17 words in her assignment.
    The total number of words written by both Olivia and Isabella is 93+17 = <<93+17=110>>110.
    ### Answer: 110

Expected answer: 110

Correct? Yes

🔗 Follow-up

Problem: Now imagine that after Olivia and Isabella completed their assignments, Isabella decided to write an additional 17 words. With this additional contribution, what is the total number of words written by both Olivia and Isabella?

InternLM-Math Base 20B:

      Reasoning: Olivia wrote 93 words in her assignment.
    Isabella wrote 17+17 = <<17+17=34>>34 words in her assignment.
    The total number of words written by both Olivia and Isabella is 93+34 = <<93+34=127>>127.
    ### Answer: 127

Expected answer: 127

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, consider now that Olivia initially wrote only 4 words on the first day instead of 70, but still wrote 23 words on the second day. Isabella wrote 17 words as before. Given this, how many total words have Olivia and Isabella written now?

InternLM-Math Base 20B:

      Reasoning: Olivia wrote 4+23 = <<4+23=27>>27 words in her assignment.
    Isabella wrote 17 words in her assignment.
    The total number of words written by both Olivia and Isabella is 27+17 = <<27+17=44>>44.
    ### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Problem

Problem: On a morning commute, a bus picks up 48 riders at one stop. At the next stop, it picks up another 18 riders. How many riders are there in all on the bus?

InternLM-Math Base 20B:

     Reasoning: 48+18 = <<48+18=66>>66 riders are on the bus.
    ### Answer: 66

Expected answer: 66

Correct? Yes

🔗 Follow-up

Problem: After the morning commute, the same bus does an afternoon route. The number of riders it picks up is exactly the same as the morning route. How many riders does the bus pick up in total for both the morning and afternoon routes?

InternLM-Math Base 20B:

      Reasoning: 66+66 = <<66+66=132>>132 riders are on the bus.
    ### Answer: 132

Expected answer: 132

Correct? Yes

🔗 Follow-up

Problem: In a new scenario, the bus picks up 48 riders on the morning commute, just like before. But this time at the next stop, it picks up 52 more riders. How many riders are there in all on the bus now?

InternLM-Math Base 20B:

      Reasoning: 48+52 = <<48+52=100>>100 riders are on the bus.
    ### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Problem

Problem: Sophia found a box of old trading cards in the attic. She counted 24 of them as baseball cards and 35 as basketball cards. Later on, she discovered 22 more cards from various sports. How many trading cards has Sophia found in total?

InternLM-Math Base 20B:

     Reasoning: Sophia found 24+35+22 = <<24+35+22=81>>81 trading cards in total.
    ### Answer: 81

Expected answer: 81

Correct? Yes

🔗 Follow-up

Problem: After Sophia counted 24 baseball cards, 35 basketball cards, and another 22 cards from various sports that she had found in the attic, she remembered her old shoebox full of trading cards under her bed. In the shoebox, she found 45 more cards. How many total trading cards does Sophia have now?

InternLM-Math Base 20B:

      Reasoning: Sophia has 24+35+22+45 = <<24+35+22+45=126>>126 trading cards in total.
    ### Answer: 126

Expected answer: 126

Correct? Yes

🔗 Follow-up

Problem: Sophia initially found 24 baseball cards and 35 basketball cards in the attic. Later, she discovered 92 more cards, making it a wide variety of sports cards. How many trading cards has Sophia found in total now?

InternLM-Math Base 20B:

      Reasoning: Sophia found 24+35+92 = <<24+35+92=151>>151 trading cards in total.
    ### Answer: 151

Expected answer: 151

Correct? Yes

🔗 Problem

Problem: For his birthday, Jenny's father receives 16 gifts. Eight more gifts arrive in the mail the next day. In addition, Jenny's dad gets 23 gifts at his office. How many gifts did Jenny's dad receive in total?

InternLM-Math Base 20B:

     Reasoning: Jenny's father received 16+8+23 = <<16+8+23=47>>47 gifts in total.
    ### Answer: 47

Expected answer: 47

Correct? Yes

🔗 Follow-up

Problem: What if Jenny had made a mistake in her original count and her dad actually received 38 gifts initially, not 16? Eight more gifts still arrive in the mail the next day and he still gets the 23 gifts at his office. With these changes, how many gifts did Jenny's dad receive in total now?

InternLM-Math Base 20B:

      Reasoning: Jenny's father received 38+8+23 = <<38+8+23=69>>69 gifts in total.
    ### Answer: 69

Expected answer: 69

Correct? Yes

🔗 Problem

Problem: Let's say you have 30 pencils. You bought an exact same amount more. How many pencils do you have now?

InternLM-Math Base 20B:

     Reasoning: You have 30+30 = <<30+30=60>>60 pencils now.
    ### Answer: 60

Expected answer: 60

Correct? Yes

🔗 Follow-up

Problem: After buying the same amount of additional pencils, you find that your friend has gifted you 15 more pencils. How many pencils do you have in total now?

InternLM-Math Base 20B:

      Reasoning: You have 60+15 = <<60+15=75>>75 pencils now.
    ### Answer: 75

Expected answer: 75

Correct? Yes

🔗 Follow-up

Problem: Let's consider the previous scenario but this time, you initially have 80 pencils instead of 30. If you again bought an exact same amount more, how many pencils would you have now?

InternLM-Math Base 20B:

      Reasoning: You have 80+80 = <<80+80=160>>160 pencils now.
    ### Answer: 160

Expected answer: 160

Correct? Yes

🔗 Problem

Problem: Peter watched 93 minutes of TV in the morning. Later in the evening, he watched another 84 minutes. How many total minutes of TV did Peter watch in a day?

InternLM-Math Base 20B:

     Reasoning: Peter watched 93+84 = <<93+84=177>>177 minutes of TV in a day.
    ### Answer: 177

Expected answer: 177

Correct? Yes

🔗 Follow-up

Problem: Continuing from the last time, after Peter had watched a total of minutes from morning and the evening, he again watched an additional 92 minutes of TV before his bedtime. How many total minutes of TV did Peter watch now in the whole day?

InternLM-Math Base 20B:

      Reasoning: Peter watched 93+84+92 = <<93+84+92=269>>269 minutes of TV in a day.
    ### Answer: 269

Expected answer: 269

Correct? Yes

🔗 Follow-up

Problem: Suppose instead of 93 minutes in the morning, Peter initially watched 83 minutes of TV. He still watched 84 minutes later in the evening. Now, how many total minutes of TV did Peter watch in a day?

InternLM-Math Base 20B:

      Reasoning: Peter watched 83+84 = <<83+84=167>>167 minutes of TV in a day.
    ### Answer: 167

Expected answer: 167

Correct? Yes

🔗 Problem

Problem: Jake has 69 balls. He goes to a store and buys the same amount of balls. How many balls does Jake have now?

InternLM-Math Base 20B:

     Reasoning: Jake has 69+69 = <<69+69=138>>138 balls now.
    ### Answer: 138

Expected answer: 138

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous problem, after Jake buys the same amount of balls from the store, his friend decides to give him an additional 12 balls as a gift. How many balls does Jake have now?

InternLM-Math Base 20B:

      Reasoning: Jake has 138+12 = <<138+12=150>>150 balls now.
    ### Answer: 150

Expected answer: 150

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous problem, let's say Jake initially bought only 54 balls instead of 69. He still doubles that amount by buying the same number of balls from the store. How many balls would Jake have then?

InternLM-Math Base 20B:

      Reasoning: Jake has 54+54 = <<54+54=108>>108 balls now.
    ### Answer: 108

Expected answer: 108

Correct? Yes

🔗 Problem

Problem: A zookeeper takes count of the elephants in the zoo. In the first section, he finds 53 elephants. In the next section, he finds 71 more. On his way out, he realizes that he needs to revisit a previously counted section of 72 elephants. How many elephants did he count altogether?

InternLM-Math Base 20B:

     Reasoning: The zookeeper counted 53+71 = <<53+71=124>>124 elephants in the first two sections. He then revisited a section of 72 elephants. So, he counted 124+72 = <<124+72=196>>196 elephants altogether.
    ### Answer: 196

Expected answer: 196

Correct? Yes

🔗 Follow-up

Problem: After the zookeeper's day shift, he decides to check the recorded count of the elephants during his night shift. He revisits the first two sections counting 53 and 71 elephants and recounts the same number. He then adds this to his previous total count including the section with the 72 elephants. What is his total count of the elephants now after his night shift?

InternLM-Math Base 20B:

      Reasoning: The zookeeper recounted 53+71 = <<53+71=124>>124 elephants in the first two sections. He then added this to his previous total count of 124+72 = <<124+72=196>>196 elephants. So, his total count of the elephants is 196+124 = <<196+124=320>>320.
    ### Answer: 320

Expected answer: 320

Correct? Yes

🔗 Problem

Problem: Sally is organizing her wardrobe and she notices she has a total of 7 dresses and 96 skirts. Later, she also finds another 26 shirts. How many total items of clothing does Sally have in her wardrobe?

InternLM-Math Base 20B:

     Reasoning: Sally has 7 dresses, 96 skirts, and 26 shirts.
    7+96+26 = <<7+96+26=129>>129 total items of clothing.
    ### Answer: 129

Expected answer: 129

Correct? Yes

🔗 Follow-up

Problem: After going through her wardrobe again, Sally realizes she actually has 99 skirts instead of 96. Keeping the count of 7 dresses and 26 shirts the same, how many total items of clothing does Sally have in her wardrobe now?

InternLM-Math Base 20B:

      Reasoning: Sally has 7 dresses, 99 skirts, and 26 shirts.
    7+99+26 = <<7+99+26=132>>132 total items of clothing.
    ### Answer: 132

Expected answer: 132

Correct? Yes

🔗 Problem

Problem: Sarah has managed to bake 80 sandwiches for the local fundraiser. Later in the day, Kevin, her friend, comes over and makes an additional quantity of sandwiches such that in total, the sandwiches he makes added to Sarah's make up 33 more than the number of sandwiches made by Sarah. How many sandwiches did Kevin make?

InternLM-Math Base 20B:

     Reasoning: Let x be the number of sandwiches Kevin made.
    x+80 = 33+x
    x = 33+80-x
    x = 33+80-33
    x = 80
    ### Answer: 80

Expected answer: 113

Correct? No

🔗 Problem

Problem: Gabriella has 31 grapes. She buys 75 more. John has 64 grapes and decides to add to his pile all the grapes that Gabriella has. How many grapes does John have now?

InternLM-Math Base 20B:

     Reasoning: John has 64+31+75 = <<64+31+75=170>>170 grapes.
    ### Answer: 170

Expected answer: 170

Correct? Yes

🔗 Follow-up

Problem: Instead of buying 75 grapes, what if Gabriella had bought 45 grapes initially. In this scenario, she would start with 31 grapes, then buy an additional 45 grapes, and then John would take his 64 grapes and add all the grapes Gabriella has. How many grapes would John have then?

InternLM-Math Base 20B:

      Reasoning: John has 64+31+45 = <<64+31+45=140>>140 grapes.
    ### Answer: 140

Expected answer: 140

Correct? Yes

🔗 Problem

Problem: A queen bee lays 51 eggs and then lays an additional 64 eggs. The worker bees find 53 more eggs in the hive, and then they discover another cache of 79 eggs. How many eggs are in the hive in total?

InternLM-Math Base 20B:

     Reasoning: The queen bee lays 51+64 = <<51+64=115>>115 eggs.
    The worker bees find 53+79 = <<53+79=132>>132 eggs.
    The total number of eggs in the hive is 115+132 = <<115+132=247>>247.
    ### Answer: 247

Expected answer: 247

Correct? Yes

🔗 Follow-up

Problem: Following the discovery of the cache of 79 eggs in the hive, an experienced beekeeper gives the worker bees a batch of 5 eggs from another hive. How many eggs are in the hive now?

InternLM-Math Base 20B:

      Reasoning: The total number of eggs in the hive is 247+5 = <<247+5=252>>252.
    ### Answer: 252

Expected answer: 252

Correct? Yes

🔗 Problem

Problem: A fruit vendor sells 68 bananas in a day. Meanwhile, a small market nearby sells 35 bananas during the same day. How many bananas were sold in total that day?

InternLM-Math Base 20B:

     Reasoning: 68+35 = <<68+35=103>>103 bananas were sold in total that day.
    ### Answer: 103

Expected answer: 103

Correct? Yes

🔗 Follow-up

Problem: From the bananas sold in a day, a fruit vendor picks up the total number of bananas he and the nearby small market have sold. This number is noted down for record keeping. What is the recorded total number of bananas sold in a day?

InternLM-Math Base 20B:

      Reasoning: 68+35 = <<68+35=103>>103 bananas were sold in total that day.
    ### Answer: 103

Expected answer: 103

Correct? Yes

🔗 Follow-up

Problem: Earlier, the fruit vendor sold 68 bananas in a day, but the following day he sells only 49 bananas. The same small market nearby keeps its sales consistent and sells 35 bananas again. How many bananas were sold in total on this new day?

InternLM-Math Base 20B:

      Reasoning: 49+35 = <<49+35=84>>84 bananas were sold in total that day.
    ### Answer: 84

Expected answer: 84

Correct? Yes

🔗 Problem

Problem: Sam's computer has 23GB of storage space left. After compressing some files, he is able to free up an additional 98GB. How much total storage space does Sam's computer have now?

InternLM-Math Base 20B:

     Reasoning: Sam's computer has 23+98 = <<23+98=121>>121GB of storage space.
    ### Answer: 121

Expected answer: 121

Correct? Yes

🔗 Follow-up

Problem: Now, suppose Sam had originally had a total of 96GB of storage space available on his computer instead of 23GB. After compressing the same files, he is still able to free up an additional 98GB. With this scenario, how much total storage space does Sam's computer have now?

InternLM-Math Base 20B:

      Reasoning: Sam's computer has 96+98 = <<96+98=194>>194GB of storage space.
    ### Answer: 194

Expected answer: 194

Correct? Yes

🔗 Problem

Problem: Frank has a fish farm with 77 fish in one of the tanks. One day, he decides to add an additional 19 fish into the tank. How many fish are there in the tank in total?

InternLM-Math Base 20B:

     Reasoning: Frank has 77+19 = <<77+19=96>>96 fish in the tank.
    ### Answer: 96

Expected answer: 96

Correct? Yes

🔗 Follow-up

Problem: Frank continues to grow his fish farm and adds an additional 51 fish into the tank. Now, how many fish are there in the tank in total?

InternLM-Math Base 20B:

      Reasoning: Frank has 96+51 = <<96+51=147>>147 fish in the tank.
    ### Answer: 147

Expected answer: 147

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous question, imagine Frank started with a smaller tank that only had 4 fish. He adds the same number of fish as before, an additional 19 into the tank. How many fish are now in that tank in total?

InternLM-Math Base 20B:

      Reasoning: Frank has 4+19 = <<4+19=23>>23 fish in the tank.
    ### Answer: 23

Expected answer: 23

Correct? Yes

🔗 Problem

Problem: A truck driver starts his journey with 83 gallons of gas in his tank. He stops at the first station and fills up an additional 36 gallons. Then he drives until he needs to refill and adds 99 more gallons. Finally, he stops near his destination and tops off his tank with 7 gallons. How many total gallons of gas did the truck driver use for his journey?

InternLM-Math Base 20B:

     Reasoning: The truck driver used 83+36+99+7 = <<83+36+99+7=223>>223 gallons of gas for his journey.
    ### Answer: 223

Expected answer: 225

Correct? No

🔗 Problem

Problem: Bobby goes to the local park and decides to test how high he can swing on three different swings. On the first swing, he goes 56 feet in the air, then comes back down and goes another 53 feet high. On the second swing, he goes as high as he did on the first one plus an additional 5 feet. On the third swing, he challenges himself and goes as high as he did on the second one plus an additional 34 feet. How high did Bobby swing on the third swing?

InternLM-Math Base 20B:

     Reasoning: Bobby went 56+53 = <<56+53=109>>109 feet high on the first swing.
    He went 56+5 = <<56+5=61>>61 feet high on the second swing.
    He went 61+34 = <<61+34=95>>95 feet high on the third swing.
    ### Answer: 95

Expected answer: 148

Correct? No

🔗 Problem

Problem: Bob starts with a wallet containing $88. He finds $40 on the ground and adds it to his wallet. Later, his mom gives him an additional $56 for doing chores. How much money does Bob have in his wallet now?

InternLM-Math Base 20B:

     Reasoning: Bob has $88+$40 = <<88+40=128>>128 in his wallet. Then, he gets $56 more, so he has $128+$56 = <<128+56=184>>184 in his wallet.
    ### Answer: 184

Expected answer: 184

Correct? Yes

🔗 Follow-up

Problem: In addition to the money Bob has in his wallet, his sister Penny gives him $13 from her piggy bank to help him buy a new game. How much money does Bob have now?

InternLM-Math Base 20B:

      Reasoning: Bob has $184+$13 = <<184+13=197>>197 in his wallet.
    ### Answer: 197

Expected answer: 197

Correct? Yes

🔗 Follow-up

Problem: Instead of finding $40 on the ground, Bob initially finds $53. He adds this to his original $88 he had in the wallet, and his mom still gives him an additional $56 for doing chores. How much money does Bob have in his wallet now?

InternLM-Math Base 20B:

      Reasoning: Bob has $88+$53 = <<88+53=141>>141 in his wallet. Then, he gets $56 more, so he has $141+$56 = <<141+56=197>>197 in his wallet.
    ### Answer: 197

Expected answer: 197

Correct? Yes

🔗 Problem

Problem: In a magical wizard world, Eugene the wizard has 98 magic orbs. Merlin, another wizard, has 71 more orbs than Eugene. Damien, a third wizard, has 59 orbs more than Merlin. How many orbs does Damien have?

InternLM-Math Base 20B:

     Reasoning: Eugene has 98 orbs. Merlin has 98+71 = <<98+71=169>>169 orbs. Damien has 169+59 = <<169+59=228>>228 orbs.
    ### Answer: 228

Expected answer: 228

Correct? Yes

🔗 Follow-up

Problem: In the further adventures of our magical wizards, Gertrude, a wise wizard, acquires 90 orbs more than Damien. How many orbs does Gertrude have now?

InternLM-Math Base 20B:

      Reasoning: Damien has 228 orbs. Gertrude has 228+90 = <<228+90=318>>318 orbs.
    ### Answer: 318

Expected answer: 318

Correct? Yes

🔗 Follow-up

Problem: Let's revisit our magical wizards' adventure, but this time, envision Eugene starting off with a different amount of magic orbs. Suppose Eugene initially had only 85 magic orbs instead of 98. Following the same chain of orb-acquiring, with Merlin having 71 more orbs than Eugene and Damien having 59 more orbs than Merlin, how many orbs would Damien have now?

InternLM-Math Base 20B:

      Reasoning: Eugene has 85 orbs. Merlin has 85+71 = <<85+71=156>>156 orbs. Damien has 156+59 = <<156+59=215>>215 orbs.
    ### Answer: 215

Expected answer: 215

Correct? Yes

🔗 Problem

Problem: Emma has 5 dolls. Sophia gives her the same number of dolls as she already has. How many dolls does Emma have now?

InternLM-Math Base 20B:

     Reasoning: Emma has 5+5 = <<5+5=10>>10 dolls now.
    ### Answer: 10

Expected answer: 10

Correct? Yes

🔗 Follow-up

Problem: Let's say that instead of starting with 5 dolls, Emma originally had 12 dolls. If Sophia gives her the same number of dolls as she originally had, how many dolls does Emma have now?

InternLM-Math Base 20B:

      Reasoning: Emma has 12+12 = <<12+12=24>>24 dolls now.
    ### Answer: 24

Expected answer: 24

Correct? Yes

🔗 Problem

Problem: During a chilly winter, Sally makes a hot chocolate recipe that requires 36 spoons of chocolate and 84 spoons of milk. After she adds the chocolate and milk, she also adds 34 spoons of whipped cream. How many total spoons of ingredients does Sally use for her hot chocolate?

InternLM-Math Base 20B:

     Reasoning: Sally uses 36+84+34 = <<36+84+34=154>>154 spoons of ingredients for her hot chocolate.
    ### Answer: 154

Expected answer: 154

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous problem, what if Sally decided to increase her hot chocolate formula by using 64 spoons of chocolate instead of 36, while keeping the amount of milk and whipped cream identical. How many total spoons of ingredients does Sally now use for her hot chocolate recipe?

InternLM-Math Base 20B:

      Reasoning: Sally uses 64+84+34 = <<64+84+34=182>>182 spoons of ingredients for her hot chocolate.
    ### Answer: 182

Expected answer: 182

Correct? Yes

🔗 Problem

Problem: In a word game, the letter Z is given a score of 3. The score of the letter U is the sum of 31 and the score of Z. What is the score of the letter U?

InternLM-Math Base 20B:

     Reasoning: The score of the letter U is 31+3 = <<31+3=34>>34.
    ### Answer: 34

Expected answer: 34

Correct? Yes

🔗 Follow-up

Problem: In the same word game, the letter C is assigned a score which is the sum of 69 and the score of U. What is the score of the letter C?

InternLM-Math Base 20B:

      Reasoning: The score of the letter C is 69+34 = <<69+34=103>>103.
    ### Answer: 103

Expected answer: 103

Correct? Yes

🔗 Follow-up

Problem: Continuing with the same word game, let's change the rule a bit. Now, the letter Z is given a new score of 90. With the rule still in place that the score of the letter U is the sum of 31 and the score of Z, what is the new score of the letter U?

InternLM-Math Base 20B:

      Reasoning: The score of the letter U is 31+90 = <<31+90=121>>121.
    ### Answer: 121

Expected answer: 121

Correct? Yes

🔗 Problem

Problem: Mathew has 81 ounces of apple juice. He wants to add some orange juice to it. So, he pours in another 99 ounces. After pouring the orange juice, how many ounces of juice does Mathew have overall?

InternLM-Math Base 20B:

     Reasoning: Mathew has 81+99 = <<81+99=180>>180 ounces of juice overall.
    ### Answer: 180

Expected answer: 180

Correct? Yes

🔗 Follow-up

Problem: Continuing from the last problem - Suppose initially, Mathew only had 17 ounces of apple juice instead of 81 ounces. He still adds 99 ounces of orange juice. With this change, how many ounces of juice does Mathew have now?

InternLM-Math Base 20B:

      Reasoning: Mathew has 17+99 = <<17+99=116>>116 ounces of juice overall.
    ### Answer: 116

Expected answer: 116

Correct? Yes

🔗 Problem

Problem: Carla is testing a new feature on her binoculars that allows her to see objects from greater distances. Initially, she sets the view distance at 91 meters. Then, she increases the view distance by 80 more meters. What is the new adjusted viewing distance on her binoculars?

InternLM-Math Base 20B:

     Reasoning: 91+80 = <<91+80=171>>171 meters.
    ### Answer: 171 meters

Expected answer: 171

Correct? Yes

🔗 Follow-up

Problem: Carla is now even more interested and decides to push her new binoculars to their limits. She decides to add another 92 meters to the viewing distance on her binoculars. After making this additional adjustment, what is the total viewing distance on Carla's binoculars now?

InternLM-Math Base 20B:

      Reasoning: 171+92 = <<171+92=263>>263 meters.
    ### Answer: 263 meters

Expected answer: 263

Correct? Yes

🔗 Follow-up

Problem: Carla is considering her initial experimental trial with the binoculars. She thinks back to the first time she adjusted the binoculars, but she remembers that she initially set the view distance to 91 meters, but then increased it by 85 meters, not 80. What was the adjusted viewing distance on her binoculars during her initial trial?

InternLM-Math Base 20B:

      Reasoning: 91+85 = <<91+85=176>>176 meters.
    ### Answer: 176 meters

Expected answer: 176

Correct? Yes

🔗 Problem

Problem: Bobby has 42 keys. He gets another set of keys that has 56 more than the original set. Bobby also has a keychain that includes both the original set of keys and the new set of keys. How many keys does Bobby have in total?

InternLM-Math Base 20B:

     Reasoning: Bobby has 42 keys. He gets another set of keys that has 56 more than the original set. Bobby also has a keychain that includes both the original set of keys and the new set of keys. How many keys does Bobby have in total?

Expected answer: 140

Correct? No

🔗 Problem

Problem: Jordy has 45 carrots. She manages to gather the same amount again from her farm. How many carrots does Jordy have now?

InternLM-Math Base 20B:

     Reasoning: Jordy has 45+45 = <<45+45=90>>90 carrots now.
    ### Answer: 90

Expected answer: 90

Correct? Yes

🔗 Follow-up

Problem: After gathering the same amount of carrots from her farm, Jordy decides to go to the local market where she buys 4 more carrots. How many carrots does Jordy have now?

InternLM-Math Base 20B:

      Reasoning: Jordy has 90+4 = <<90+4=94>>94 carrots now.
    ### Answer: 94

Expected answer: 94

Correct? Yes

🔗 Follow-up

Problem: If originally Jordy had started with 14 carrots instead of 45 and she still managed to gather the same amount from her farm, how many carrots would she have then?

InternLM-Math Base 20B:

      Reasoning: Jordy would have 14+14 = <<14+14=28>>28 carrots.
    ### Answer: 28

Expected answer: 28

Correct? Yes

🔗 Problem

Problem: In a painting competition, one artist uses 43 blue strokes and 53 red strokes to complete his painting. Another artist, inspired by the first one, decides to use 67 more strokes in addition to what the first artist used. A third artist doubles the total number of strokes used by the second artist for her painting. How many strokes did the third artist use in her painting?

InternLM-Math Base 20B:

     Reasoning: The second artist used 43+67 = <<43+67=110>>110 blue strokes and 53+67 = <<53+67=120>>120 red strokes. The third artist used 2(110) = <<2*110=220>>220 blue strokes and 2(120) = <<2*120=240>>240 red strokes. The third artist used 220+240 = <<220+240=460>>460 strokes in her painting.
    ### Answer: 460

Expected answer: 326

Correct? No

🔗 Problem

Problem: You buy 42 ice cream cones for your friends. You then decide to buy the same amount for another group of friends. How many ice cream cones did you buy in total?

InternLM-Math Base 20B:

     Reasoning: You bought 42+42 = <<42+42=84>>84 ice cream cones in total.
    ### Answer: 84

Expected answer: 84

Correct? Yes

🔗 Follow-up

Problem: After you've bought ice cream for both groups of friends, another group of 59 friends shows up! You decide you don't want them to feel left out, so you buy ice cream for them too. How many total ice cream cones have you bought?

InternLM-Math Base 20B:

      Reasoning: You bought 84+59 = <<84+59=143>>143 ice cream cones in total.
    ### Answer: 143

Expected answer: 143

Correct? Yes

🔗 Problem

Problem: Mike's left binocular lens can magnify objects from a distance of 30 miles away, and the right lens can magnify objects that are 56 miles away. He also has a telescope that can magnify objects from a distance of 67 miles away. What is the total distance from which both his binoculars and telescope can magnify objects?

InternLM-Math Base 20B:

     Reasoning: The total distance from which both his binoculars and telescope can magnify objects is 30+56+67 = <<30+56+67=153>>153 miles.
    ### Answer: 153

Expected answer: 153

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, we considered the distance that Mike's binocular's two lenses can magnify. Consider now that we made a mistake and that the left lens can actually magnify objects from a distance of 54 miles away instead of 30 miles. Keeping the right lense and the telescope the same at 56 and 67 miles respectively, what would be the new total distance from which both his binoculars and telescope can magnify objects?

InternLM-Math Base 20B:

      Reasoning: The new total distance from which both his binoculars and telescope can magnify objects is 54+56+67 = <<54+56+67=177>>177 miles.
    ### Answer: 177

Expected answer: 177

Correct? Yes

🔗 Problem

Problem: In the land of the Wizarding World, one wand spells costs 50 magical crystals known as Quiblets. Quintus the wizard adds 5 Quiblets more to this to cast a slightly stronger spell. This amount is then topped up by 25 magical Quiblets to cast the most powerful spell. How many Quiblets does Quintus the wizard need to cast the most powerful spell?

InternLM-Math Base 20B:

     Reasoning: Quintus the wizard needs 50+5+25 = <<50+5+25=80>>80 Quiblets to cast the most powerful spell.
    ### Answer: 80

Expected answer: 80

Correct? Yes

🔗 Follow-up

Problem: As an extension to the previous problem, let's say Quintus the wizard then decides to cast an ancient and profound spell. To cast this spell, he needs to gather an additional number of Quiblets equivalent to his most powerful spell, plus 50 more. How many Quiblets does Quintus the wizard need in total to cast this ancient spell?

InternLM-Math Base 20B:

      Reasoning: Quintus the wizard needs 80+50 = <<80+50=130>>130 Quiblets to cast the ancient spell.
    ### Answer: 130

Expected answer: 130

Correct? Yes

🔗 Follow-up

Problem: As a variation to the previous problem, let's say the most powerful spell that Quintus the wizard wants to cast actually requires an additional 87 Quiblets on top of the slightly stronger spell, not just 25. How many Quiblets does he now need to cast this more demanding powerful spell?

InternLM-Math Base 20B:

      Reasoning: Quintus the wizard needs 50+5+87 = <<50+5+87=142>>142 Quiblets to cast the most powerful spell.
    ### Answer: 142

Expected answer: 142

Correct? Yes