🔗 Problem

Problem: There are 535 fish in a large tank and a shark eats 461 of them in one sitting. If the shark continues this pattern and only eats when there are 461 or more fish to consume, how many fish will be leftover after its dinner?

Mixtral 8x7B:

     Reasoning: After eating 461 fish, there will be 535-461 = <<535-461=74>>74 fish left in the tank.
    ### Answer: 74

    However, since the shark eats all the fish when there are 461 or more, there will be no fish left in the tank after its dinner.
    ### Answer: 0 (if the shark eats again)

Expected answer: 74

Correct? Yes

🔗 Problem

Problem: A baker baked a total of 928 cookies. He decided to distribute equal amounts of cookies to 186 orphanages. After giving out as many entire sets of cookies as possible to each orphanage, how many cookies does the baker have left?

Mixtral 8x7B:

     Reasoning: The baker gives out 928/186 = <<928/1

Expected answer: 184

Correct? No

🔗 Problem

Problem: A pizza store has 975 slices of pizza ready to serve. If each pizza box can contain 196 slices, how many left over slices will there be after all the pizza boxes are full?

Mixtral 8x7B:

     Reasoning: To find out how many boxes are needed to pack 975 slices, we divide the total number of slices by the number of slices per box:

    975 / 196 = 5

    This means that 5 boxes are needed to pack 975 slices. However, 975 is not a multiple of 196, so there will be some leftover slices. To find out how many, we subtract the number of slices that fit in the boxes from the total number of slices:

    975 - (5 * 196) = 975 - 980 = -5

    Since the number of leftover slices is negative, it means that there are not enough slices to fill the last box. Therefore, the number of leftover slices is:

    196 - 20 = 176

    ### Answer: There will be 176 leftover slices after all the pizza boxes are full.

Expected answer: 191

Correct? No

🔗 Problem

Problem: A wizard casts a spell to summon 932 magical stones. Each powerful creature he summons requires 193 stones. After summoning several creatures, how many stones will the wizard have left?

Mixtral 8x7B:

     Reasoning: The wizard needs 193*number of creatures summoned stones to summon each creature.
    Let's denote the number of creatures as "x". Then, 193x is the number of stones used for summoning.
    The wizard has 932-193x stones left.
    Since the question asks for the number of stones left, we don't need to find the number of creatures.
    ### Answer: The wizard has 932-193x stones left, where x is the number of creatures summoned.

Expected answer: 160

Correct? No

🔗 Problem

Problem: A builder has a job to install 660 square foot tiles in a house. Each tile can cover 335 square feet. After installing tiles evenly across the available space, how many square feet will the last tile need to cover?

Mixtral 8x7B:

     Reasoning: The builder needs to install 660/335 = <<660/335=1.97>>1.97 tiles. Since the builder cannot install a fraction of a tile, they will need to install 2 tiles to cover the entire space.
    The area of the last tile will be 335 square feet.
    ### Answer: 335 square feet

Expected answer: 325

Correct? No

🔗 Problem

Problem: A juice company produced 473 gallons of juice. If the company bottles the juice in 22-gallon containers, how many gallons of juice will be left after filling up all the containers?

Mixtral 8x7B:

     Reasoning: The company can fill up 473/22 = <<473/22=21.5>>21.5 containers.
    Since the containers have a 22-gallon capacity, no juice will be left after filling up all the containers.
    ### Answer: 0

    (Note: This answer assumes that the company will use all the produced juice to fill the containers.)

Expected answer: 11

Correct? No

🔗 Problem

Problem: A toy factory produced 979 toy cars in a day. If they packed these cars into boxes, each containing 108 cars, how many toy cars will be left unpacked at the end of the day?

Mixtral 8x7B:

     Reasoning: The number of toy cars that can be packed into boxes is 979 / 108 = <<979/108=9.055555555555556>>9 (with a remainder of 11).
    So, 11 toy cars will be left unpacked at the end of the day.
    ### Answer: 11

    (Note: The remainder represents the number of cars left unpacked.)

Expected answer: 7

Correct? No

🔗 Problem

Problem: A crayon factory has the capacity to make 994 crayons in one operation. However, each box only holds 425 crayons. If they operate at full capacity, how many crayons will be left out of the boxes after the operation?

Mixtral 8x7B:

     Reasoning: The factory makes 994 crayons in one operation.
    Since each box holds 425 crayons, the number of crayons that can be packed into boxes is 994 - (994 % 425) = 994 - 119 = 875.
    The remaining 994 - 875 = <<994-875=119>>119 crayons will be left out of the boxes after the operation.
    ### Answer: 119

Expected answer: 144

Correct? No

🔗 Problem

Problem: A wildlife reserve has 740 tigers. The reserve is divided into different zones, and each zone can only hold up to 696 tigers. If tigers are distributed evenly among the zones, how many tigers will be left in the last zone?

Mixtral 8x7B:

     Reasoning: Since each zone can hold up to 696 tigers, and the 740th tiger can't be alone in a zone, we need to find out how many tigers will be in the last zone.
    To do this, we can divide the total number of tigers by the number of zones: 740 tigers / 11 zones (since 740/696=11 with a remainder).
    740/11 = <<740/11=67.27272727272727>>67 tigers and a remainder of 7.
    So, the last zone will have 67 tigers.
    ### Answer: 67 tigers

Expected answer: 44

Correct? No

🔗 Problem

Problem: A hat shop makes 830 hats every week. In order to make special edition boxes, the shop plans to put 421 hats in each box. If all the hats are evenly distributed among the boxes, how many hats will be left over?

Mixtral 8x7B:

     Reasoning: The shop makes 830 hats per week, and each box can hold 421 hats. To find out how many boxes are needed, we divide the total number of hats by the number of hats per box: 830/421 = 2 boxes (rounded down).
    Since the shop can't make a fraction of a box, they will need to distribute the remaining 830-(2\*421) = 830-842 = -12 hats among the boxes. However, since a negative number of hats doesn't make sense, we can say that there are no hats left over.
    ### Answer: 0 hats will be left over.

Expected answer: 409

Correct? No

🔗 Problem

Problem: There are 871 fish in a lake. A fisherman catches 575 fish every month. If the fish repopulate at the same rate that the fisherman is depleting them, how many fish will be left after a month?

Mixtral 8x7B:

     Reasoning: The fisherman catches 575 fish, but the fish population also decreases by 575 fish due to natural reproduction rates.
    Therefore, the change in the fish population is 575 - 575 = 0 fish.
    ### Answer: 871 fish will be left after a month.

Expected answer: 296

Correct? No

🔗 Problem

Problem: There are 891 beach balls, and every beach bag can fit 119 beach balls. If all the beach balls are evenly placed into the bags, how many beach balls will not fit and left over?

Mixtral 8x7B:

     Reasoning: To find out how many beach balls will not fit, we need to divide the total number of beach balls by the number of beach balls that fit in each bag and find the remainder.
    891 / 119 = 7 remainder 30
    ### Answer: 30 beach balls will not fit and will be left over.

Expected answer: 58

Correct? No

🔗 Problem

Problem: There are 544 stars in a particular constellation. These stars are grouped into smaller clusters of 446 stars each. If these clusters are evenly split, how many stars will remain ungrouped?

Mixtral 8x7B:

     Reasoning: There are 544/446 = <<544/446=1.22>>1.22 clusters, but since clusters cannot be divided, we round down to 1 cluster.
    This leaves 544 - 446 = <<544-446=98>>98 stars ungrouped.
    ### Answer: 98

    (Note: The wording of the question suggests that the stars are grouped into clusters of 446 stars each, but this is not possible since there are only 544 stars in total. Therefore, my answer assumes that the clusters are as large as possible while still containing an even number of clusters.)

Expected answer: 98

Correct? Yes

🔗 Follow-up

Problem: Considering the previous scenario with the constellation, suppose there were only 278 stars in the constellation instead of 544, and they were still to be grouped into smaller clusters of 446 stars each. If the clusters are evenly distributed, how many stars will now remain ungrouped?

Mixtral 8x7B:

     Reasoning: There are 278/446 = <<278/446=0.62>>0.62 clusters, but since clusters cannot be divided, we round down to 0 clusters.
    This leaves 278 stars ungrouped.
    ### Answer: 278

    (Note: The wording of the question suggests that the stars are grouped into clusters of 446 stars each, but this is not possible since there are only 278 stars in total. Therefore, all 278 stars will remain ungrouped.)

Expected answer: 278

Correct? Yes

🔗 Problem

Problem: A manufacturer produces 805 socks in one shift. They are packaged into sets of 132 each. After the packaging, how many socks will remain unpackaged?

Mixtral 8x7B:

     Reasoning: To find out how many sets of socks can be made from 805 socks, we divide the total number of socks by the number of socks in each set: 805 / 132 = 6 remainder 37.
    This means that 6 full sets can be made, and there will be 37 socks left over.
    ### Answer: 37

    socks will remain unpackaged.

Expected answer: 13

Correct? No

🔗 Problem

Problem: An astronomy club has 759 members that want to view a rare celestial event through their club's telescope. However, the telescope can only handle 228 people viewing the event each night. If they distribute the viewing evenings evenly amongst all members, how many people will view the event on the final night?

Mixtral 8x7B:

     Reasoning: The astronomy club has 759 members and the telescope can handle 228 people each night. To find out how many nights they will distribute the viewing, we divide the total number of members by the number of people that can view the event each night: 759/228 = <<759/228=3.3333333333333335>>3.33... nights.
    Since they can't distribute the viewing evenings unevenly, they will round up to 4 nights.
    On the final night, 759 - (228*3) = 759 - 684 = <<759-684=75>>75 people will view the event.
    ### Answer: 75

Expected answer: 75

Correct? Yes

🔗 Follow-up

Problem: A similar astronomy club from a neighboring town also wants to take part in viewing this rare celestial event. They have 593 members interested in participating. If they follow the same pattern of distributing the viewing nights evenly amongst all members, with only 228 people viewing the event each night, how many people from this club will view the event on the final night?

Mixtral 8x7B:

     Reasoning: The second astronomy club has 593 members and the telescope can handle 228 people each night. To find out how many nights they will distribute the viewing, we divide the total number of members by the number of people that can view the event each night: 593/228 = <<593/228=2.59954648526077>>2.59... nights.
    Since they can't distribute the viewing evenings unevenly, they will round up to 3 nights.
    On the final night, 593 - (228*2) = 593 - 456 = <<593-456=137>>137 people will view the event.
    ### Answer: 137

    (Note: The answer is different from the previous question as the number of members in the second club is different from the first club.)

Expected answer: 137

Correct? Yes

🔗 Problem

Problem: A postman has to deliver 891 letters. Each mailbox can only hold 616 letters. If he puts equal numbers of letters in each mailbox, how many letters will remain in the last mailbox?

Mixtral 8x7B:

     Reasoning: The postman will divide 891 by the maximum capacity of each mailbox (616) to find out how many full mailboxes he can make.
    891 / 616 = 1 remainder 275
    This means that he can fill one mailbox completely and still have 275 letters left over.
    ### Answer: 275

    (Note: A negative remainder would mean that the mailbox can hold more letters than the current number, which is not possible in this scenario.)

Expected answer: 275

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, assuming the postman had to originally deliver 524 letters instead of 891, and each mailbox can still only accommodate 616 letters. How many letters will remain in the last mailbox now?

Mixtral 8x7B:

     Reasoning: The postman will divide 524 by the maximum capacity of each mailbox (616) to find out how many full mailboxes he can make.
    524 / 616 = 0 remainder 524
    This means that he cannot fill any mailboxes completely and still has 524 letters left over.
    ### Answer: 524

    (Note: A negative remainder would mean that the mailbox can hold more letters than the current number, which is not possible in this scenario.)

Expected answer: 524

Correct? Yes

🔗 Problem

Problem: A total of 941 flies are jumping around the pond. Every time a frog jumps, it eats exactly 258 flies. After a series of jumps where each jump the frog eats the same number of flies, how many flies are left?

Mixtral 8x7B:

     Reasoning: If the frog eats 258 flies with each jump, then after eating all the flies, there will be 941 - 258\*k flies left, where k is the number of jumps.
    Since the frog eats all the flies, we have 258\*k = 941.
    Solving for k, we get k = 941 / 258 ≈ 3.64.
    Since the number of jumps must be a whole number, the closest whole number value for k is 4.
    So, after 4 jumps, the frog will have eaten 258\*4 = <<258*4=1032>>1032 flies, which is more than the total number of flies present.
    This means that there are no flies left after the frog jumps 4 times.
    ### Answer: 0 flies are left.

Expected answer: 167

Correct? No

🔗 Problem

Problem: A large park has a capacity of 991 spaces for cars to park. If all the spaces are evenly distributed between 66 rows, how many spare spaces will be there in the last row after max spaces are filled?

Mixtral 8x7B:

     Reasoning: To find the number of spaces in the last row, we first need to find the number of spaces per row. This can be calculated by dividing the total capacity by the number of rows: 991/66 = 15.

    Since 15 is not evenly divisible by 66, the last row will not be completely full. The number of spaces in the last row will be the remainder of the division: 991 % 66 = 1.
    ### Answer: 1 spare space in the last row.

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: In the same large park, suppose they restructure the parking with larger spaces to accommodate bigger vehicles. Now, the adjusted parking lot configurations can hold 471 cars in each row. After filling up the rows, how many spare spaces would be there in the last row now?

Mixtral 8x7B:

     Reasoning: Now, each row can hold 471 cars. To find the number of spaces in the last row, we need to divide the total capacity by the number of rows and find the remainder: 991 / 471 = 2 remainder 91.

    So, the last row will have 91 spare spaces.
    ### Answer: 91 spare spaces in the last row.

Expected answer: 49

Correct? No

🔗 Problem

Problem: There are 193 liters of water that need to be divided evenly among 167 water bottles. If each bottle holds the same amount of water, how many liters overflows and can't be distributed to the bottles?

Mixtral 8x7B:

     Reasoning: To find out how many liters overflow, we need to determine how much water can be held by 167 bottles. To do this, we divide the total amount of water by the number of bottles:
    193 liters / 167 bottles = <<193/167=1.155688622754491>>1.1557 liters per bottle (rounded to 4 decimal places).
    Since each bottle can only hold whole liters, we multiply the number of bottles by the number of liters that can be held by each bottle and subtract the result from the total amount of water:
    167 bottles \* 1 liter/bottle = 167 liters
    193 liters - 167 liters = <<193-167=26>>26 liters
    ### Answer: 26 liters overflow and can't be distributed to the bottles.

Expected answer: 26

Correct? Yes

🔗 Follow-up

Problem: If, instead of 193 liters of water, there were 857 liters of water that needed to be divided evenly among the 167 water bottles, how many liters would overflow and can't be distributed to the bottles now?

Mixtral 8x7B:

     Reasoning: To find out how many liters overflow, we need to determine how much water can be held by 167 bottles. To do this, we divide the total amount of water by the number of bottles:
    857 liters / 167 bottles = <<857/167=5.132317674917386>>5.1323 liters per bottle (rounded to 4 decimal places).
    Since each bottle can only hold whole liters, we multiply the number of bottles by the number of liters that can be held by each bottle and subtract the result from the total amount of water:
    167 bottles \* 1 liter/bottle = 167 liters
    857 liters - 167 liters = <<857-167=690>>690 liters
    ### Answer: 690 liters overflow and can't be distributed to the bottles.

Expected answer: 22

Correct? No

🔗 Problem

Problem: A dragon lays 996 jewel eggs in rows. Each row can hold 319 eggs. If the dragon distributes the eggs evenly among the rows, how many eggs would be left over to be put in the last row?

Mixtral 8x7B:

     Reasoning: If the dragon lays 996 eggs in rows and each row can hold 319 eggs, then the number of rows is 996/319 = <<996/319=3>>3 (with no remainder).
    This means that the dragon can distribute the eggs evenly among the rows, with no eggs left over for the last row.
    ### Answer: 0 eggs would be left over to be put in the last row.

Expected answer: 39

Correct? No

🔗 Problem

Problem: A lamp manufacturer produces 691 bulb units. If a pack includes 205 bulbs, how many bulbs would be left unpacked after filling as many packs as possible?

Mixtral 8x7B:

     Reasoning: To find out how many packs can be filled from 691 bulbs, we divide the total number of bulbs by the number of bulbs in each pack: 691 / 205 = 3 remainder 76.
    This means that 3 full packs can be made and there will still be 76 bulbs left over.
    ### Answer: 76 bulbs would be left unpacked.

Expected answer: 76

Correct? Yes

🔗 Follow-up

Problem: If the lamp manufacturer produced 739 bulb units instead of 691, how many bulbs would be left unpacked after filling as many packs as possible with 205 bulbs each?

Mixtral 8x7B:

     Reasoning: To find out how many packs can be filled from 739 bulbs, we divide the total number of bulbs by the number of bulbs in each pack: 739 / 205 = 3 remainder 94.
    This means that 3 full packs can be made and there will still be 94 bulbs left over.
    ### Answer: 94 bulbs would be left unpacked.

Expected answer: 124

Correct? No

🔗 Problem

Problem: On a farm, there are 330 bales of hay to be stored evenly in barns. Each barn can store up to 259 bales. After filling up the barns as evenly as possible, how many bales of hay will be left for the last barn?

Mixtral 8x7B:

     Reasoning: To find out how many bales will be left for the last barn, we first need to find out how many barns are needed to store all 330 bales.
    We divide the total number of bales by the number of bales each barn can store: 330/259 = 1 remainder 71.
    ### Answer: 71 bales of hay will be left for the last barn.

Expected answer: 71

Correct? Yes

🔗 Problem

Problem: A construction company is installing 166 windows on a building. They have determined that one installation team can install 137 windows per day. If all windows are equally distributed amongst teams each day, how many windows will remain for the team to install on the next day?

Mixtral 8x7B:

     Reasoning: If the installation team works on installing all 166 windows, then the number of windows remaining for the next day will be 166 - 137 = <<166-137=29>>29 windows.
    ### Answer: 29

    (Note: The phrasing of the question implies that the work will be evenly distributed, but I assumed that the team will work on all the windows and leave some for the next day. If the team is to install a fixed number of windows per day, please let me know the exact number and I can adjust my answer accordingly.)

Expected answer: 29

Correct? Yes

🔗 Problem

Problem: There are 533 campers coming for a camping event at a park. Each tent can host 445 people. If the campers are evenly distributed among the tents, how many campers will be left over after all the tents are filled?

Mixtral 8x7B:

     Reasoning: To find out how many tents are needed, we divide the total number of campers by the number of campers each tent can hold: 533 / 445 = 1 remainder 88.
    ### Answer: 88 campers will be left over after all the tents are filled.

Expected answer: 88

Correct? Yes

🔗 Follow-up

Problem: Now suppose that the park upgraded their tents and each tent can now host 886 people. With the same group of 533 campers, how many campers will be left over after all the tents are filled?

Mixtral 8x7B:

     Reasoning: Now, we divide the total number of campers by the new number of campers each tent can hold: 533 / 886 = 0 remainder 533.
    ### Answer: 0 campers will be left over after all the tents are filled.

Expected answer: 533

Correct? No

🔗 Problem

Problem: There are 999 seashells collected from a beach. They are grouped in beach-themed souvenir sets, each containing 474 shells. After grouping, how many seashells will be left without a set?

Mixtral 8x7B:

     Reasoning: Since 999 is not a multiple of 474, there will be some seashells left over after grouping them into sets of 474. To find out how many, we can divide the total number of seashells by the number of seashells in each set and see how much is left:
    999 / 474 = 2 remainder 45
    So, there will be 45 seashells left over after grouping them into 2 full sets.
    ### Answer: 45

    (Note: The number of full sets is 999 / 474 = 2, and the remainder 45 represents the number of seashells that do not form a full set.)

Expected answer: 51

Correct? No

🔗 Problem

Problem: A tailor has 366 meters of fabric. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?

Mixtral 8x7B:

     Reasoning: The tailor can make 366/160 = <<366/1

Expected answer: 46

Correct? No

🔗 Problem

Problem: A toymaker made 993 dolls to be packed in boxes for shipment. Each box can hold 327 dolls. How many dolls will she have left once all the boxes are packed to their capacities?

Mixtral 8x7B:

     Reasoning: The toymaker can pack 993/327 = <<993/327=3>>3 full boxes.
    After packing 3 \* 327 = <<3*327=981>>981 dolls, there will be 993-981 = <<993-981=12>>12 dolls left.
    ### Answer: 12

    (Note: A multiple of 327 would be a more reasonable number of dolls for the toymaker to make, but the problem as stated has a unique answer.)

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous problem, what if, instead of each box holding 327 dolls, each box can now hold 115 dolls? After packing each box to capacity, how many dolls will the toymaker have left?

Mixtral 8x7B:

     Reasoning: The toymaker can pack 993/115 = <<993/115=8.63636363636>>8 full boxes.
    After packing 8 \* 115 = <<8*115=920>>920 dolls, there will be 993-920 = <<993-920=73>>73 dolls left.
    ### Answer: 73

    (Note: This answer assumes that the number of dolls is exact and that the toymaker can make fractional dolls. If the toymaker can only make whole dolls, then the answer would be different.)

Expected answer: 73

Correct? Yes

🔗 Problem

Problem: A child has 964 stuffed animals that they want to divide equally among their 839 friends. If they distribute the stuffed animals evenly, how many will the child have left over?

Mixtral 8x7B:

     Reasoning: To find out how many stuffed animals each friend gets, we divide the total number of stuffed animals by the number of friends: 964 / 839 = 1 remainder 125.
    This means that the child can distribute 839 stuffed animals evenly among their friends, but will have 125 stuffed animals left over.
    ### Answer: The child will have 125 stuffed animals left over.

Expected answer: 125

Correct? Yes

🔗 Follow-up

Problem: The child from the previous problem has gotten even more stuffed animals and now has a total of 964 stuffed animals. If they still want to divide them equally among their 892 friends, how many stuffed animals will be left over after distributing them?

Mixtral 8x7B:

     Reasoning: To find out how many stuffed animals each friend gets, we divide the total number of stuffed animals by the number of friends: 964 / 892 = 1 remainder 72.
    This means that the child can distribute 892 stuffed animals evenly among their friends, but will have 72 stuffed animals left over.
    ### Answer: The child will have 72 stuffed animals left over.

Expected answer: 72

Correct? Yes

🔗 Problem

Problem: A toy factory produces 369 teddy bears in a day. The bears are packaged in boxes and each box can hold 270 teddy bears. How many teddy bears will be left if all the teddy bears are evenly packed in the boxes?

Mixtral 8x7B:

     Reasoning: The number of teddy bears that can be packed in boxes is 369/270 = <<369/270=1.3666666666666667>>1.3666... boxes. Since a box cannot be divided, we need to find the number of whole boxes that can be filled.
    So, 1 box can be filled and 270 teddy bears will be packed in this box, leaving 369-270 = <<369-270=99>>99 teddy bears.
    ### Answer: 99 teddy bears will be left.

Expected answer: 99

Correct? Yes

🔗 Follow-up

Problem: Earlier, the toy factory produced 369 teddy bears in a day and they were packaged in boxes with each box holding 270 teddy bears. Now, suppose that the toy factory increased its production and now makes 813 teddy bears in a day while still packing them in boxes that can hold 270 teddy bears. How many teddy bears will be left now if all the teddy bears are evenly packed in the boxes?

Mixtral 8x7B:

     Reasoning: The number of teddy bears that can be packed in boxes is 813/270 = <<813/270=3.011111111111111>>3.0111... boxes. Since a box cannot be divided, we need to find the number of whole boxes that can be filled.
    So, 3 boxes can be filled and 810 teddy bears will be packed in these boxes, leaving 813-810 = <<813-810=3>>3 teddy bears.
    ### Answer: 3 teddy bears will be left.

Expected answer: 3

Correct? Yes

🔗 Problem

Problem: A village has a yearly tradition of building snowmen. This year, the villagers make 804 snowballs to build their snowmen. Each snowman needs exactly 184 snowballs. After all snowmen are built, how many snowballs are left leftover?

Mixtral 8x7B:

     Reasoning: The villagers build 804/184 = <<804/184=4>>4 snowmen with 184 snowballs each.
    So, they have 804-184*4 = 804-736 = <<804-736=68>>68 snowballs left over.
    ### Answer: 68

    (Note: The number of snowballs left over is 68, not 4.)

Expected answer: 68

Correct? Yes

🔗 Follow-up

Problem: In the same village, another year, there were only 444 snowballs made to build the snowmen. If each snowman still requires exactly 184 snowballs, how many snowballs would be left over after as many complete snowmen as possible are built?

Mixtral 8x7B:

     Reasoning: With 444 snowballs, the villagers can build 444/1

Expected answer: 76

Correct? No

🔗 Problem

Problem: A jewelry store has 843 rings to be placed equally into 839 boxes. If each box is filled, how many rings will be left over?

Mixtral 8x7B:

     Reasoning: To find out how many rings will be in each box, we divide the total number of rings by the number of boxes: 843/839 = 1 with a remainder of 4.
    ### Answer: 4 rings will be left over.

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: The jewelry store just received an additional shipment and now has a total of 843 rings. However, this time they must be equally placed into 804 boxes. If every box is filled, how many rings will be left over now?

Mixtral 8x7B:

     Reasoning: To find out how many rings will be in each box, we divide the total number of rings by the number of boxes: 843/804 = 1 with a remainder of 39.
    ### Answer: 39 rings will be left over.

Expected answer: 39

Correct? Yes

🔗 Problem

Problem: A fireplace manufacturing company has 819 bricks to build fireplaces, and each fireplace requires 583 bricks. If they build as many fireplaces as possible, how many bricks will they have left over?

Mixtral 8x7B:

     Reasoning: The number of fireplaces the company can build is 819/583 = <<819/583~1.405>>1, with a remainder of 236 bricks.
    ### Answer: 236 bricks will be left over.

Expected answer: 236

Correct? Yes

🔗 Follow-up

Problem: The company received a new delivery of bricks, now they have 486 bricks in total. If they continue making fireplaces, each requiring 583 bricks as before, how many bricks will they have left after building as many full fireplaces as they can?

Mixtral 8x7B:

     Reasoning: The number of fireplaces the company can build with 486 bricks is 486/583 = <<486/583~0.834>>0, with a remainder of 486 bricks.
    However, since a fireplace requires at least 583 bricks, the company cannot build any fireplaces with the 486 bricks they have.
    ### Answer: The company will have 486 bricks left, but they cannot build any fireplaces with them.

Expected answer: 486

Correct? Yes

🔗 Problem

Problem: A marshmallow factory produces 998 marshmallows per minute. However, the packaging machine can only hold 957 marshmallows at a time. What will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled?

Mixtral 8x7B:

     Reasoning: In one minute, the marshmallow factory produces 998 marshmallows.
    The packaging machines can hold 957 marshmallows each.
    So, the number of marshmallows that can be packaged in one minute is 998 - 957 = <<998-957=41>>41 marshmallows.
    Therefore, the number of marshmallows left un-packaged in a minute after all the packaging machines are filled is 998 - 957 = <<998-957=41>>41 marshmallows.
    ### Answer: 41

Expected answer: 41

Correct? Yes

🔗 Follow-up

Problem: The marshmallow factory upgraded its packaging machine and now it can hold 804 marshmallows at a time instead of 957. If the factory continues to produce 998 marshmallows per minute, what will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity?

Mixtral 8x7B:

     Reasoning: In one minute, the marshmallow factory produces 998 marshmallows.
    The packaging machines can now hold 804 marshmallows each.
    So, the number of marshmallows that can be packaged in one minute is 804 marshmallows.
    Therefore, the number of marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity is 998 - 804 = <<998-804=194>>194 marshmallows.
    ### Answer: 194

    Note: The number of marshmallows left un-packaged depends on the capacity of the packaging machine. If the packaging machine can't hold all the marshmallows produced in a minute, then there will be leftover marshmallows.

Expected answer: 194

Correct? Yes

🔗 Problem

Problem: There are 984 roses in the castle's garden. Princess likes to place 426 roses in every tribute for her loyal subjects. If she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?

Mixtral 8x7B:

     Reasoning: Princess can create 984/426 = <<984/426=2>>2 tributes with 426 roses each.
    After creating 2 tributes, she will have 984-2*426 = <<984-2*426=126>>126 roses left undistributed.
    ### Answer: 126 roses will be left undistributed.

Expected answer: 132

Correct? No

🔗 Problem

Problem: A song has 334 words in it. If each line in the song has 23 words, how many words would be in the incomplete line at the end of the song?

Mixtral 8x7B:

     Reasoning: The number of lines in the song is 334/23 = <<334/23=14.521739130434783>>14 (with some remainder).
    Since there are 14 complete lines, there are only 15 words (334-330) in the incomplete line at the end of the song.
    ### Answer: 15

Expected answer: 12

Correct? No

🔗 Problem

Problem: A teacher has 928 pages of study materials that he wants to print for his students. His printer can only print 336 pages in one go. After filling the printer a number of times, how many pages will he have left over to print?

Mixtral 8x7B:

     Reasoning: The teacher has 928 pages to print, and his printer can print 336 pages at a time. After printing 336 pages, the teacher will have 928 - 336 = <<928-336=592>>592 pages left to print.
    After printing another batch of 336 pages, the teacher will have 592 - 336 = <<592-336=256>>256 pages left to print.
    The teacher can print one more batch of 336 pages, leaving 256 - 336 = -<<336-256=80>>80 pages. However, since the teacher cannot print a negative number of pages, this means that he has 80 pages left over that he cannot print with his current printer.
    ### Answer: -80  (The teacher has 80 pages left over that he cannot print with his current printer.)

Expected answer: 256

Correct? No

🔗 Problem

Problem: Scientists have spotted 972 sharks in an area. The scientists tag groups of 667 sharks each. How many sharks are left untagged after the scientists finish tagging as many complete groups as possible?

Mixtral 8x7B:

     Reasoning: The scientists can tag 972/667 = <<972/667=1>>1 group of 667 sharks, leaving 972-667 = <<972-667=295>>295 sharks untagged.
    ### Answer: 295 sharks are left untagged.

Expected answer: 305

Correct? No

🔗 Problem

Problem: There are 686 blocks of cheese in the dairy shop. Each box can contain 349 blocks of cheese. If all the blocks of cheese are evenly distributed in the boxes, how many blocks of cheese would be left over after all the boxes are filled?

Mixtral 8x7B:

     Reasoning: To find out how many blocks of cheese would be left over, we need to divide the total number of blocks of cheese by the number of blocks of cheese each box can contain and then subtract the whole number part of the result from the total number of blocks of cheese.
    686 divided by 349 equals 2 with a remainder of 4.
    ### Answer: 4 blocks of cheese would be left over after all the boxes are filled.

Expected answer: 337

Correct? No

🔗 Problem

Problem: There were 513 centimeters of snowfall recorded this winter. A snowplow can clear up to 170 centimeters of snow at a time. If the snowplow runs continuously, how many centimeters of snow will be left over after the final pass?

Mixtral 8x7B:

     Reasoning: After each pass of the snowplow, there will be 513 - 170 = <<513-170=343>>343 centimeters of snow left.
    Since the snowplow can only clear 170 centimeters at a time, there will always be some snow left over.
    ### Answer: 343 centimeters of snow will be left over after the final pass.

Expected answer: 3

Correct? No

🔗 Problem

Problem: A compass maker has 661 needles to install in compasses. Each compass uses 510 needles. After installing as many full compasses as he can, how many needles will the compass maker have left?

Mixtral 8x7B:

     Reasoning: The compass maker can install 661/510 = <<661/510=1 remainder 151>>1 compass with 151 needles left over.
    ### Answer: 151 needles

Expected answer: 151

Correct? Yes

🔗 Problem

Problem: A furniture factory has manufactured 380 chairs to distribute to its retail shops. Each shop can only hold 310 chairs in its storage. If the factory evenly distributes all the chairs to the shops, how many chairs will be left at the factory?

Mixtral 8x7B:

     Reasoning: The factory will distribute 380/2 = <<380/2=190>>190 chairs to each of its retail shops.
    After distribution, there will be 380-190\*2 = 380-380 = <<380-190*2=0>>0 chairs left at the factory.
    ### Answer: 0

    (Note: The factory cannot distribute the remaining 10 chairs to any shop since each shop can only hold 310 chairs. Therefore, the factory will have 0 chairs left after distribution.)

Expected answer: 70

Correct? No

🔗 Problem

Problem: A farmer has gathered 929 tomatoes from his field. He plans to sell them in boxes, with 154 tomatoes in each box. After packing them evenly in boxes, how many tomatoes will be left over?

Mixtral 8x7B:

     Reasoning: The farmer has 929 tomatoes and can pack 154 tomatoes in each box. To find out how many tomatoes will be left over, we need to divide the total number of tomatoes by the number of tomatoes per box and find the remainder.
    929 divided by 154 gives a quotient of 6 and a remainder of 39.
    ### Answer: 39 tomatoes will be left over.

Expected answer: 5

Correct? No

🔗 Problem

Problem: A sporting goods store has 454 pairs of ice skates in total. The store distributes the skates evenly among 128 boxes. How many pairs of ice skates will be left over after all the boxes are filled up equally?

Mixtral 8x7B:

     Reasoning: The number of pairs of ice skates per box is 454/128 = 3.5625. Since we can't have a fraction of a pair in a box, we know that the number of pairs in each box is 3.
    Then, the number of pairs that fill up the 128 boxes is 128 \* 3 = 384.
    Therefore, the number of pairs left over is 454 - 384 = 70.
    ### Answer: 70

    (Note: There will be 70 pairs of ice skates left over after all the boxes are filled up equally.)

Expected answer: 70

Correct? Yes

🔗 Follow-up

Problem: If the sporting goods store originally had 976 pairs of ice skates instead of 454, and they still distribute the skates evenly among 128 boxes as before, how many pairs of ice skates will be left over after all the boxes are filled equally?

Mixtral 8x7B:

     Reasoning: The number of pairs of ice skates per box is 976/128 = 7.625. Since we can't have a fraction of a pair in a box, we know that the number of pairs in each box is 7.
    Then, the number of pairs that fill up the 128 boxes is 128 \* 7 = 896.
    Therefore, the number of pairs left over is 976 - 896 = 80.
    ### Answer: 80

    (Note: There will be 80 pairs of ice skates left over after all the boxes are filled up equally.)

Expected answer: 80

Correct? Yes

🔗 Problem

Problem: A windmill generates 506 units of power per day. Every day, a small village consumes power in increments of 385 units. At the end of the day, after the village has consumed as much power as it can in full increments, how much power is left over?

Mixtral 8x7B:

     Reasoning: The village consumes 385 units of power per day.
    At the end of the day, there is 506-385 = <<506-385=121>>121 units of power left over.
    ### Answer: 121

    (Note: The remaining power is more than a full day's consumption, so the windmill will continue to generate the same amount of power the next day.)

Expected answer: 121

Correct? Yes

🔗 Follow-up

Problem: Following the scenario of the windmill and the small village, let's now consider that the windmill had a great day and managed to generate 506 units of power. However, due to development demands, the daily consumption of the village has increased to 920 units. At the end of the day, with the power being consumed in complete units, how much power is left over?

Mixtral 8x7B:

     Reasoning: The village now consumes 920 units of power per day.
    At the end of the day, there is 506-920 = <<506-920=-414>>-414 units of power left over.
    However, negative power is not possible, so the windmill did not generate enough power for the village's increased consumption.
    ### Answer: -414 (but note that the actual answer is 0, as the windmill cannot generate a negative amount of power)

Expected answer: 506

Correct? No

🔗 Problem

Problem: Superhero Blast Man has 338 energy units in his power cells. Each energy blast he fires uses 16 energy units. After using equal units of energy firing blasts, how many energy units will Blast Man have left in his power cells?

Mixtral 8x7B:

     Reasoning: Blast Man uses 338/16 = <<338/1

Expected answer: 2

Correct? No

🔗 Problem

Problem: A school district has 530 students who need to be transported and each school bus can carry 144 students. If all students are equally spread across the buses, how many students will be on the last school bus?

Mixtral 8x7B:

     Reasoning: First, we need to find out how many school buses are needed to transport all 530 students. To do this, we divide the total number of students by the number of students each bus can carry: 530 / 144 = 3 with a remainder of 86.
    Since the remaining 86 students can't fill another bus by themselves, they will be spread out among the first three buses, leaving the last bus with only 144 - 86 = <<144-86=58>>58 students.
    ### Answer: 58 students

Expected answer: 98

Correct? No

🔗 Problem

Problem: A wizard has 999 spells in his book. He tries to distribute them equally among 951 apprentice wizards but they don't divide evenly. How many spells will the wizard have left after giving out as many as he can to his apprentices?

Mixtral 8x7B:

     Reasoning: The wizard can give out 951 apprentices ⌊999/951⌋ = 1 spell each, which is 951 spells in total.
    He will have 999 - 951 = <<999-951=48>>48 spells left.
    ### Answer: 48

    (Note: ⌊⌋ is the floor function, which means that it rounds down to the nearest whole number.)

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: If the wizard had instead 999 spells and he tries to distribute them equally among 801 apprentice wizards, how many spells will the wizard have left after giving out as many as he can to his apprentices?

Mixtral 8x7B:

     Reasoning: The wizard can give out 801 apprentices ⌊999/801⌋ = 1 spell each, which is 801 spells in total.
    He will have 999 - 801 = <<999-801=198>>198 spells left.
    ### Answer: 198

Expected answer: 198

Correct? Yes

🔗 Problem

Problem: A scooter manufacturing company has produced 767 scooters. Each delivery truck they use can carry 369 scooters. If they distribute the scooters evenly among the trucks, how many scooters will be left after all the trucks are loaded?

Mixtral 8x7B:

     Reasoning: To find out how many scooters will be left, we need to divide the total number of scooters by the number of scooters each truck can carry and then subtract the whole number part of the result from the total number of scooters.
    767 / 369 = 2 remainder 98
    So, 98 scooters will be left after all the trucks are loaded.
    ### Answer: 98

    (Note: This assumes that the number of scooters can't be exactly divided by the number of scooters each truck can carry. If that were the case, no scooters would be left over.)

Expected answer: 29

Correct? No

🔗 Problem

Problem: There are 846 water droplets in a cloud. Each raindrop needs 722 droplets to form. If all droplets are used to form raindrops, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Mixtral 8x7B:

     Reasoning: First, we need to find out how many raindrops can be formed from the 846 water droplets. To do this, we divide the total number of droplets by the number of droplets needed to form a raindrop: 846 / 722 = 1 remainder 124.
    This means that 124 raindrops cannot be formed, but all the other 846 - 124 = <<846-124=722>>722 droplets will be used to form raindrops.
    ### Answer: 124 droplets would be left unconverted in the cloud after reaching the maximum number of raindrops.

Expected answer: 124

Correct? Yes

🔗 Follow-up

Problem: There was a slight miscalculation in the cloud's droplet count. There are actually 846 water droplets in the cloud, but each raindrop needs 442 droplets to form instead of 722. With this updated droplet count per raindrop, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Mixtral 8x7B:

     Reasoning: First, we need to find out how many raindrops can be formed from the 846 water droplets. To do this, we divide the total number of droplets by the number of droplets needed to form a raindrop: 846 / 442 = 1 remainder 404.
    This means that 404 raindrops cannot be formed, but all the other 846 - 404 = <<846-404=442>>442 droplets will be used to form raindrops.
    ### Answer: 404 droplets would be left unconverted in the cloud after reaching the maximum number of raindrops.

Expected answer: 404

Correct? Yes

🔗 Problem

Problem: Unicorn Village, a magical place where 265 unicorns live, is divided into 146 equal sections where these magical creatures reside. If each section is occupied by an equal number of unicorns, how many unicorns will live in the last incomplete section?

Mixtral 8x7B:

     Reasoning: 146 sections can hold 146 * 1 = <<146*1=146>>146 unicorns.
    But there are 265 unicorns in Unicorn Village.
    The last incomplete section will have 265 - 146 = <<265-146=119>>119 unicorns.
    ### Answer: 119 unicorns

Expected answer: 119

Correct? Yes

🔗 Follow-up

Problem: Considering the same scenario from the previous problem, let's say instead of 146 sections, Unicorn Village is divided into 781 equal sections. How many unicorns will live in the last incomplete section now?

Mixtral 8x7B:

     Reasoning: 781 sections can hold 781 * 1 = <<781*1=781>>781 unicorns.
    But there are 265 unicorns in Unicorn Village.
    The last incomplete section will have 265 - 781 = <<265-781=-516>>-516 unicorns.
    However, a negative number of unicorns is not possible. This means that the last section will be empty.
    ### Answer: 0 unicorns

    (Note: The last section will be empty because there are fewer unicorns than sections.)

Expected answer: 265

Correct? No

🔗 Problem

Problem: In a game, there are 923 players waiting to enter a match. Only 383 players can enter a match at a time. If players enter matches evenly, how many players will be left waiting after filling all the matches?

Mixtral 8x7B:

     Reasoning: To find out how many matches are filled, we divide the total number of players by the number of players per match: 923 / 383 = <<923/383=2.41>>2.41. Since a whole number of matches cannot have a fractional part, we round up to 3 matches.
    The total number of players that can enter matches is 383 \* 3 = <<383*3=1149>>1149.
    Since there are only 923 players, the number of players left waiting after filling all the matches is 1149 - 923 = <<1149-923=226>>226.
    ### Answer: 226

Expected answer: 157

Correct? No

🔗 Problem

Problem: A pirate ship has 923 cannonballs on board. They want to equally disperse them between 499 different crates. After evenly distributing them as much as possible, how many cannonballs will be left uncrated?

Mixtral 8x7B:

     Reasoning: To find out how many cannonballs will be left uncrated, we need to divide the total number of cannonballs by the number of crates and find the remainder.
    923 divided by 499 is 1 with a remainder of 423.
    ### Answer: 423 cannonballs will be left uncrated.

Expected answer: 424

Correct? No

🔗 Problem

Problem: A kite store has 530 string spools to attach to their kites. They distribute them to 518 kites, each getting one string spool. After each kite gets a spool, how many spools are left in the store?

Mixtral 8x7B:

     Reasoning: There are 518 kites, and each kite gets one string spool, so 518 spools are distributed.
    There are 530 spools in the store at the beginning, and 518 spools are distributed, so 530-518 = <<530-518=12>>12 spools are left in the store.
    ### Answer: 12

    (Note: The wording of the question suggests that each kite gets one string spool, so I assumed that all the kites get a spool. If that's not the case, please let me know.)

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: A dairy farm produces 913 gallons of milk in a day. If every milk jug holds 39 gallons, how many gallons will be left over after all the jugs are filled?

Mixtral 8x7B:

     Reasoning: The dairy farm produces 913/39 = <<913/39=23.41025641025641>>23.41 jugs of milk in a day.
    Since you can't have a fraction of a jug, the farm will have 913 - 23*39 = <<913-(23*39)=13>>13 gallons of milk left over.
    ### Answer: 13 gallons

Expected answer: 16

Correct? No

🔗 Problem

Problem: A doll seller received a shipment of 603 new dolls to put on the shelves. She arranged all the dolls in rows, with 369 dolls in each row. After filling up the rows as much as possible, how many dolls were left unarranged?

Mixtral 8x7B:

     Reasoning: The doll seller was able to fill up the rows completely, since 603 is not a multiple of 369, there will be some dolls left unarranged.
    To find out how many dolls are left, we subtract the number of dolls that can be arranged in complete rows from the total number of dolls.
    603 - (603 // 369 \* 369) = 603 - 369 = <<603-(603-369*1)/369*369=33>>33
    ### Answer: 33 dolls were left unarranged.

Expected answer: 234

Correct? No

🔗 Problem

Problem: A jewelry maker has 850 beads to make necklaces. They use 631 beads for each necklace. After using as many beads as possible, how many beads will the jewelry maker have left over?

Mixtral 8x7B:

     Reasoning: The jewelry maker can make 850/631 = <<850/631~1.347>>1 necklace with the 850 beads.
    Since they can't make a partial necklace, they will only make 1 necklace.
    1 necklace uses 631 beads, so the jewelry maker will have 850-631 = <<850-631=219>>219 beads left over.
    ### Answer: 219

Expected answer: 219

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker decides to change the design and now each necklace uses only 150 beads instead of 631 beads. After they distribute the 850 beads as equally as possible among the new necklaces, how many beads will the jewelry maker have left over?

Mixtral 8x7B:

     Reasoning: The jewelry maker can make 850/150 = <<850/150=5.66666666667>>5 complete necklaces and have 850-5*150 = <<850-5*150=50>>50 beads left over.
    ### Answer: 50

Expected answer: 100

Correct? No

🔗 Problem

Problem: A gardener has 952 grapes that he wants to package into boxes. If each box can hold 380 grapes, how many grapes will be left after the gardener has filled as many boxes as possible?

Mixtral 8x7B:

     Reasoning: The gardener can fill 952/380 = <<952/380=2.5>>2 full boxes and will have 2*380 = <<2*380=760>>760 grapes left.
    ### Answer: 760 grapes will be left.

Expected answer: 192

Correct? No

🔗 Problem

Problem: On a treasure map, there are 236 steps mentioned on the guide. If every 44 steps I make leads me to a significant place or clue, how many steps will be left after I reach the last significant place or clue?

Mixtral 8x7B:

     Reasoning: If every 44 steps leads to a significant place or clue, then the number of steps taken to reach the last significant place or clue will be a multiple of 44.
    236 is not a multiple of 44, so the next multiple of 44 after 236 is 240.
    The number of steps taken to reach the last significant place or clue is 240-236 = <<240-236=4>>4 steps.
    ### Answer: 4

    (Note: The actual number of steps left over will depend on where you are in relation to the next significant place or clue when you finish the 236th step. If you are already at a significant place or clue, then there will be no steps left over. If you are not at a significant place or clue, then there will be some number of steps between 1 and 44 left over. The problem only asks for the number of steps "after" the last significant place or clue, so the answer is 4.)

Expected answer: 16

Correct? No

🔗 Problem

Problem: Sarah blew 932 bubbles using her new bubble machine. The machine is designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Mixtral 8x7B:

     Reasoning: Natalia blows 932-932/507\*507 = <<932-932/507*507=425>>425 bubbles in its final, incomplete group.
    ### Answer: 425

Expected answer: 425

Correct? Yes

🔗 Follow-up

Problem: Suppose Sarah uses her bubble machine again, this time to blow 904 bubbles. The machine is still designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Mixtral 8x7B:

     Reasoning: Natalia blows 904-904/507\*507 = <<904-904/507*507=397>>397 bubbles in its final, incomplete group.
    ### Answer: 397

    <|endoftext|>

Expected answer: 397

Correct? Yes

🔗 Problem

Problem: At the park, there are 931 kids who want to use the swings. Each swing set can accommodate 34 kids at a time. If all the swing sets are filled continuously, how many kids will be waiting for their turn after all the swing sets are occupied?

Mixtral 8x7B:

     Reasoning: There are 931 / 34 = <<931/34~27.38>>27 complete sets of swings, which can accommodate 27 \* 34 = <<27*34=918>>918 kids.
    The remaining 931 - 918 = <<931-918=13>>13 kids will be waiting for their turn after all the swing sets are occupied.
    ### Answer: 13

Expected answer: 13

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, let's say that some of the kids finished their swinging and left the park. Now, there are only 708 kids waiting to use the swings. Each swing set can still accommodate 34 kids at a time. Given this new number, how many children will be waiting for their turn after all the swing sets are occupied?

Mixtral 8x7B:

     Reasoning: There are 708 / 34 = <<708/34~20.82>>20 complete sets of swings, which can accommodate 20 \* 34 = <<20*34=680>>680 kids.
    The remaining 708 - 680 = <<708-680=28>>28 kids will be waiting for their turn after all the swing sets are occupied.
    ### Answer: 28

    In both scenarios, the number of kids waiting for their turn after all the swing sets are occupied is the remainder when dividing the total number of kids by the number of kids each swing set can accommodate.

Expected answer: 28

Correct? Yes

🔗 Problem

Problem: John has 943 dollar bills in his possession. He tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left?

Mixtral 8x7B:

     Reasoning: John can put 943/433 = <<943/433=2.1824657534246574>>2 wallets in his possession.
    Since John cannot have a fraction of a wallet, we know that he has 2 full wallets.
    The number of remaining dollar bills is 943 - 2 \* 433 = <<943-2*433=77>>77 dollar bills.
    ### Answer: 77 dollar bills

Expected answer: 77

Correct? Yes

🔗 Follow-up

Problem: Suppose John originally had 586 dollar bills instead of 943. He still tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left now?

Mixtral 8x7B:

     Reasoning: John can put 586/433 = <<586/4

Expected answer: 153

Correct? No

🔗 Problem

Problem: A helicopter pilot plans to transport 240 passengers over several trips. He can carry 177 passengers in one trip. How many passengers will be left behind after the helicopter makes the first full trip?

Mixtral 8x7B:

     Reasoning: The number of passengers left behind after the first full trip is the total number of passengers minus the number of passengers the helicopter can carry in one trip.
    So, 240 - 177 = <<240-177=63>>63 passengers will be left behind after the helicopter makes the first full trip.
    ### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Problem

Problem: A gardener has 982 flowers to plant in flowerbeds. Each flowerbed can fit 555 flowers. After filling up as many flowerbeds as possible, how many flowers will the gardener have left to plant?

Mixtral 8x7B:

     Reasoning: The gardener can fill up 982/555 = <<982/555=1.77>>1.77 flowerbeds.
    Since a flowerbed can only be filled with whole flowers, the gardener can fill up 1 flowerbed and have 1 leftover.
    The gardener can fit 555 flowers in the full flowerbed, so after filling up as many flowerbeds as possible, the gardener will have 982-555 = <<982-555=427>>427 flowers left to plant.
    ### Answer: 427

    (Note: The number of leftover flowers is rounded down because a flowerbed cannot be partially filled.)

Expected answer: 427

Correct? Yes

🔗 Follow-up

Problem: The gardener received an additional shipment, bringing the total number of flowers up to 867. If he continues to plant the flowers in flowerbeds of 555 each, how many flowers will he have left to plant after filling up as many flowerbeds as possible?

Mixtral 8x7B:

     Reasoning: The gardener now has 867 flowers to plant.
    He can fill up 867/555 = <<867/555=1.56>>1.56 flowerbeds.
    Since a flowerbed can only be filled with whole flowers, the gardener can fill up 1 flowerbed and have 112 leftover.
    The gardener can fit 555 flowers in the full flowerbed, so after filling up as many flowerbeds as possible, the gardener will have 867-555 = <<867-555=312>>312 flowers left to plant.
    ### Answer: 312

    (Note: The number of leftover flowers is rounded down because a flowerbed cannot be partially filled.)

Expected answer: 312

Correct? Yes

🔗 Problem

Problem: A farmer grows 203 strawberry plants. She wants to divide her plants into groups of 5 to sell. How many plants will be remaining if she divides them equally?

Mixtral 8x7B:

     Reasoning: The farmer has 203 strawberry plants and wants to divide them into groups of 5. To find out how many plants will be remaining, we can divide the total number of plants by the group size and find the remainder.
    203 divided by 5 equals 40 with a remainder of 3.
    ### Answer: 3 plants will be remaining if the farmer divides the plants equally into groups of 5.

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: The farmer harvested another field and got an additional 76 strawberry plants. Again, she wants to divide the new plants into groups of 5 to sell. How many plants will be remaining if she divides these new strawberries equally?

Mixtral 8x7B:

     Reasoning: The farmer has 76 new strawberry plants and wants to divide them into groups of 5. To find out how many plants will be remaining, we can divide the total number of plants by the group size and find the remainder.
    76 divided by 5 equals 15 with a remainder of 1.
    ### Answer: 1 plant will be remaining if the farmer divides the new plants equally into groups of 5.

Expected answer: 1

Correct? Yes

🔗 Problem

Problem: A gardener has 355 carrots. He wants to create bundles of 16. After creating as many bundles as he can, how many carrots will he have left?

Mixtral 8x7B:

     Reasoning: The gardener can create 355/16 = <<355/16=22.1875>>22 full bundles with 16 carrots each.
    He will have 355 - (22*16) = <<355-(22*1

Expected answer: 3

Correct? No

🔗 Problem

Problem: A total rainfall of 612 inches fell over a certain city in 29 consecutive days. If the rain fell in the same amount every day, how many inches of rain would be left to make the days evenly rainy?

Mixtral 8x7B:

     Reasoning: The rainfall per day is 612/29 = <<612/29=21.103448275862068>>21.10 inches.
    To make the days evenly rainy, we need to find how many more inches of rain are needed to reach the next whole number of inches.
    21.10 inches * 30 days = 633 inches.
    So, we need 633 - 612 = <<633-612=21>>21 inches of rain to make the days evenly rainy.
    ### Answer: 21

Expected answer: 3

Correct? No

🔗 Problem

Problem: A truck company has got 514 boxes for delivery. Each truck can hold up to 371 boxes. If each truck is loaded to its full capacity, how many boxes will be left over?

Mixtral 8x7B:

     Reasoning: The company has 514 boxes and each truck can hold 371 boxes.
    To find out how many boxes will be left over, we need to find out how many full trucks can be loaded and then subtract that number from the total number of boxes.
    514 divided by 371 is approximately 1 with a remainder of 143.
    ### Answer: 143 boxes will be left over.

Expected answer: 143

Correct? Yes

🔗 Problem

Problem: In a large sandbox, children create 684 sandcastles over the summer. The sandcastles were grouped into sets of 230 for a photography contest. After all the sets were completed, how many sandcastles were left that didn't form a complete set?

Mixtral 8x7B:

     Reasoning: First, we need to find out how many sets of 230 sandcastles were made. To do this, we divide the total number of sandcastles by 230: 684 / 230 = 3 sets (with a remainder of 9).
    Since there are 3 complete sets of 230 sandcastles, and 1 set has 230 - 9 = <<230-9=221>>221 sandcastles, there are 684 - 3 \* 230 = <<684-(3*230)=156>>156 sandcastles left.
    ### Answer: 156 sandcastles were left that didn't form a complete set.

Expected answer: 224

Correct? No

🔗 Problem

Problem: A toy manufacturer has a production run of 735 toy cars. They package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among packs, how many toy cars will be left over after all full packs have been filled?

Mixtral 8x7B:

     Reasoning: The number of toy cars that can be packed in each pack is 348.
    The production run of toy cars is 735.
    To find the number of toy cars left over, we need to divide the total number of toy cars by the number of toy cars in each pack and find the remainder.
    735 / 348 = 2 remainder 95.
    So, 95 toy cars will be left over after all full packs have been filled.
    ### Answer: 95

    (Note: The number of full packs that can be made is 735 / 348 = 2, and the number of toy cars left over is 95.)

Expected answer: 39

Correct? No

🔗 Problem

Problem: In a forest, there are 386 animals. Each woodlands territory can support 95 animals. If the existing animals are evenly distributed among the territories, how many animals will be left in the last not fully occupied territory?

Mixtral 8x7B:

     Reasoning: To find out how many territories there are, we divide the total number of animals by the number of animals each territory can support: 386/95 = <<386/95=4>>4 territories.
    Since the last territory isn't fully occupied, it means that the remaining animals are less than 95.
    ### Answer: 36
    (Because 4 * 95 = 380, and 386 - 380 = 6, but since the territories are not fully occupied, we subtract 1 animal from the last territory for each of the 3 territories that are not full, which is 3 * 1 = 3, so 6 - 3 = 3 animals remain in the last territory.)

Expected answer: 6

Correct? No

🔗 Problem

Problem: A forest has 801 trees. A tree disease starts to spread and is expected to affect 646 trees. If all the diseased trees have to be cut down evenly, how many trees are likely to stay healthy after the disease has affected all possible trees?

Mixtral 8x7B:

     Reasoning: If all the 646 diseased trees have to be cut down, then the number of trees left in the forest will be 801 - 646 = <<801-646=155>>155 trees.
    ### Answer: 155 trees are likely to stay healthy after the disease has affected all possible trees.

Expected answer: 155

Correct? Yes

🔗 Problem

Problem: A rope manufacturer has made a rope of 934 meters in length. This rope is supposed to be cut into smaller pieces, each piece being 902 meters in length. After cutting into the maximum possible number of equal pieces, how many meters will the last piece of the rope be?

Mixtral 8x7B:

     Reasoning: If the rope can be cut into x pieces of 902 meters each, then the length of the rope would be 902x meters. We need to find the value of x and the length of the remaining piece.

    The length of the rope is 934 meters, so we have 934 = 902x + r, where r is the length of the remaining piece.

    We can find x by dividing 934 by 902: x = 934/902 = 1.035453...
    Since the number of pieces must be a whole number, we can see that x = 1, and there is one piece of 902 meters.

    The remaining piece of the rope is 934 - 902 = <<934-902=32>>32 meters.
    ### Answer: 32 meters.

Expected answer: 32

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous scenario, suppose that the manufacturer only made a rope of 202 meters in length initially. Applying the same method of cutting rope into pieces that are each 902 meters long, how many meters would the piece of the rope be now?

Mixtral 8x7B:

     Reasoning: If the rope is 202 meters in length and each piece is 902 meters, then the number of pieces is 202/902 = 0.22399...

    Since the number of pieces must be a whole number, it means that the manufacturer cannot cut the rope into pieces of 902 meters.

    Therefore, the manufacturer cannot cut the rope into pieces of 902 meters, and the length of the piece of the rope would remain 202 meters.
    ### Answer: 202 meters.

Expected answer: 202

Correct? Yes

🔗 Problem

Problem: A dairy farm produces 561 liters of milk each day. The milk is packaged into 550-liter containers. How many liters of milk are left over each day after filling the containers?

Mixtral 8x7B:

     Reasoning: The dairy farm produces 561 liters of milk each day, and each container can hold 550 liters. So, the number of liters of milk left over each day is 561 - 550 = <<561-550=11>>11 liters.
    ### Answer: 11 liters

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: If the dairy farm increased its production and started producing 729 liters of milk each day instead of 561 liters, how many liters of milk would be left over each day after filling the 550-liter containers?

Mixtral 8x7B:

     Reasoning: The dairy farm now produces 729 liters of milk each day, and each container can hold 550 liters. So, the number of liters of milk left over each day is 729 - 550 = <<729-550=179>>179 liters.
    ### Answer: 179 liters

    Note: Since the amount of milk produced each day is now greater than the capacity of the containers, there will be 179 liters of milk left over each day.

Expected answer: 179

Correct? Yes

🔗 Problem

Problem: Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?

Mixtral 8x7B:

     Reasoning: Jon has 259 - 258 = <<259-258=1>>1 extra puzzle piece after completing a full puzzle.
    ### Answer: 1
    (There will be 1 piece left over once he completes a full puzzle.)

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, Jon had 259 puzzle pieces and each puzzle requires 258 pieces. Suppose instead each puzzle needs 542 pieces. How many pieces would Jon have left over after finishing as many full puzzles as possible with his 259 pieces?

Mixtral 8x7B:

     Reasoning: Jon can't complete a full puzzle since 259 is not a multiple of 542.
    ### Answer: Jon will not be able to complete a full puzzle and will have 259 puzzle pieces left over.

Expected answer: 259

Correct? Yes

🔗 Problem

Problem: A jewelry maker has 673 beads. She plans to use exactly 49 beads for each bracelet. How many beads will she have left after creating as many bracelets as possible with the exact number of beads?

Mixtral 8x7B:

     Reasoning: The jewelry maker can make 673/49 = <<673/49=13.735>>13 bracelets with the exact number of beads.
    She will have 673 - (49*13) = 673 - 637 = <<673-637=36>>36 beads left.
    ### Answer: 36

    (Note: The number of beads left must be a whole number, so we can assume that the jewelry maker will have 36 beads left.)

Expected answer: 36

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker received an additional shipment, and now she has a total of 673 beads. This time, she wants to make larger bracelets which use exactly 545 beads each. After creating as many large bracelets as possible, how many beads will she have left over?

Mixtral 8x7B:

     Reasoning: The jewelry maker can make 673/545 = <<673/545=1.235>>1 large bracelet with the exact number of beads.
    She will have 673 - 545 = <<673-545=128>>128 beads left.
    ### Answer: 128

Expected answer: 128

Correct? Yes

🔗 Problem

Problem: A police station received 927 calls within a week. They have 311 operators who can handle the same number of calls each week. However, when the calls are divided equally, how many calls will the last operator handle?

Mixtral 8x7B:

     Reasoning: To find out how many calls each operator handles, we divide the total number of calls by the number of operators: 927 / 311 = <<927/311=2.98>>2.98 calls per operator.
    Since the number of calls must be a whole number, we round this up to 3 calls per operator.
    Then, to find out how many calls the last operator will handle, we subtract the number of calls that the other 310 operators can handle from the total number of calls: 927 - (310 \* 3) = 927 - 930 = -3.
    Since the number of calls cannot be negative, this means that the last operator will not have to handle any calls.
    ### Answer: The last operator will not handle any calls.

Expected answer: 305

Correct? No

🔗 Problem

Problem: John has 764 pieces for his jigsaw puzzle, and every package should contain 589 pieces. If he separates these pieces into full packages, how many pieces will be left outside without a package?

Mixtral 8x7B:

     Reasoning: John can put 764/589 = <<764/589=1 rem 175>>1 package with 589 pieces and will have 175 pieces left.
    ### Answer: 175

    (Note: The "1 rem 175" notation above indicates that 1 full package can be made with a remainder of 175 pieces.)

Expected answer: 175

Correct? Yes

🔗 Follow-up

Problem: If John had originally only 404 puzzle pieces, and each package can still only contain 589, how many pieces will be left outside the package now?

Mixtral 8x7B:

     Reasoning: John can put 404/589 = <<404/5

Expected answer: 404

Correct? No

🔗 Problem

Problem: A dressmaker has 984 meters of fabric. She uses 217 meters of fabric to make each dress. After using all the fabric she can to make as many dresses as possible, how many meters of fabric will she have left?

Mixtral 8x7B:

     Reasoning: The dressmaker can make 984/217 = <<984/217=4.53>>4.53 dresses with the fabric she has.
    Since she can't make a fraction of a dress, she will be able to make 4 dresses and have 984-217*4 = <<984-217*4=984-868=116>>116 meters of fabric left.
    ### Answer: 116 meters of fabric.

Expected answer: 116

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, let's now suppose that the dressmaker has 984 meters of fabric, but this time she uses 585 meters of fabric to make each dress. Again, she uses all the fabric she can to make as many dresses as possible. With this change, how many meters of fabric will she have left after all the dresses are made?

Mixtral 8x7B:

     Reasoning: The dressmaker can make 984/585 = <<984/585=1.68>>1.68 dresses with the fabric she has.
    Since she can't make a fraction of a dress, she will be able to make 1 dress and have 984-585 = <<984-585=399>>399 meters of fabric left.
    ### Answer: 399 meters of fabric.

Expected answer: 399

Correct? Yes

🔗 Problem

Problem: A company donates 639 sleeping bags for a camping event. Each campsite is supplied with 374 sleeping bags. If all the sleeping bags are divided equally among the campsites, how many sleeping bags will there be left?

Mixtral 8x7B:

     Reasoning: The number of sleeping bags left over will be the remainder when 639 is divided by 374.
    ### Answer: 639 % 374 = 265

    (Note: The "%" symbol represents the modulus operator, which gives the remainder when the first number is divided by the second number.)

Expected answer: 265

Correct? Yes

🔗 Follow-up

Problem: The same company from our previous question receives an updated request for sleeping bags. Now instead of 639, they only need to donate 613. If each campsite is still supplied with 374 sleeping bags, how many sleeping bags will be left after all the campsites are filled?

Mixtral 8x7B:

     Reasoning: The number of sleeping bags left over will be the remainder when 613 is divided by 374.
    ### Answer: 613 % 3

Expected answer: 239

Correct? No

🔗 Problem

Problem: A pizza restaurant made 620 pizzas today. They package up the pizzas in boxes that hold 578 each for delivery. If the pizzas are evenly distributed into these boxes, how many pizzas will be left over that don't fit into a box?

Mixtral 8x7B:

     Reasoning: To find out how many pizzas will be left over, we need to find out how many full boxes of pizzas can be made from the 620 pizzas. To do this, we divide the total number of pizzas by the number of pizzas per box: 620 / 578 = 1 remainder 42.
    ### Answer: 42 pizzas will be left over.

Expected answer: 42

Correct? Yes

🔗 Follow-up

Problem: The owner of the pizza restaurant decides to make 74 more pizzas tomorrow, bringing the total to 694 pizzas. If they are again distributed into boxes that hold 578 pizzas each, how many pizzas will be left out without a box this time?

Mixtral 8x7B:

     Reasoning: To find out how many pizzas will be left over, we need to find out how many full boxes of pizzas can be made from the 694 pizzas. To do this, we divide the total number of pizzas by the number of pizzas per box: 694 / 578 = 1 remainder 116.
    ### Answer: 116 pizzas will be left over.

Expected answer: 116

Correct? Yes

🔗 Problem

Problem: A factory made a total of 820 robots. It can store 684 robots in one storage unit. If the robots are evenly stored, how many robots will not fit and remain outside of the storage units?

Mixtral 8x7B:

     Reasoning: The factory made 820/684 = <<820/684=1.201754385964912>>1.2 (rounded to two decimal places) storage units.
    Since the factory cannot have a fraction of a storage unit, it will need 2 storage units.
    The first storage unit can store 684 robots, and the second storage unit can also store 684 robots.
    So, 820-684\*2 = <<820-684*2=68>>68 robots will not fit and remain outside of the storage units.
    ### Answer: 68

Expected answer: 136

Correct? No

🔗 Problem

Problem: A cloud changes its shape by reducing its water droplets. Initially, there were 516 droplets in the cloud. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?

Mixtral 8x7B:

     Reasoning: The cloud becomes dry after shedding water droplets 3 times (since 516 is not divisible by 289, and 516-289-289 = 138, which is less than 289).
    The cloud sheds 289 droplets in each cycle, so there will be 289 left after the first cycle.
    Then, there will be 138 left after the second cycle.
    Since the cloud becomes entirely dry after the final cycle, there will be no droplets left.
    ### Answer: 0 droplets

    (Note: The question asks for the number of droplets left when the cloud is dry after the final cycle, which is 0.)

Expected answer: 227

Correct? No

🔗 Problem

Problem: A transport company needs to load 330 boxes into trucks. Each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded?

Mixtral 8x7B:

     Reasoning: To find out how many boxes are left unloaded, we need to find out how many boxes can be loaded into the trucks first.
    Number of boxes that can be loaded = 330 / 4 = <<330/4=82.5>>82.5
    Since a truck cannot carry half a box, only 82 trucks can be filled completely, leaving 330 - (82 x 4) = 330 - 328 = <<330-328=2>>2 boxes unloaded.
    ### Answer: 2

    (Note: The number of boxes that can be loaded is 82 full trucks, not 83, because 83 trucks would mean loading 332 boxes, which is more than the 330 boxes available.)

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: The transport company now needs to load a new batch of 274 boxes into trucks. Again, each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded this time?

Mixtral 8x7B:

     Reasoning: To find out how many boxes are left unloaded, we need to find out how many boxes can be loaded into the trucks first.
    Number of boxes that can be loaded = 274 / 4 = <<274/4=68.5>>68.5
    Since a truck cannot carry half a box, only 68 trucks can be filled completely, leaving 274 - (68 x 4) = 274 - 272 = <<274-272=2>>2 boxes unloaded.
    ### Answer: 2

    (Note: The number of boxes that can be loaded is 68 full trucks, not 69, because 69 trucks would mean loading 276 boxes, which is more than the 274 boxes available.)

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: A farmer harvested 649 potatoes this season. He decides to pack them into crates each containing 183 potatoes. How many potatoes will be left after all crates are filled to their maximum capacity?

Mixtral 8x7B:

     Reasoning: The farmer has 649 potatoes and each crate can hold 183 potatoes. To find out how many crates the farmer can fill, we divide the total number of potatoes by the number of potatoes per crate: 649 / 183 = 3 whole crates and 90 potatoes left over.
    ### Answer: 90 potatoes will be left after all crates are filled.

Expected answer: 100

Correct? No

🔗 Problem

Problem: A t-shirt company has a batch of 258 shirts in production. Each box can pack 67 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?

Mixtral 8x7B:

     Reasoning: To find out how many boxes are needed, we divide the total number of shirts by the number of shirts per box: 258/67 = <<258/67=3+51/67=3>>3 boxes.
    Since 3 boxes can hold 3 \* 67 = <<3*67=201>>201 shirts, there will be 258 - 201 = <<258-201=57>>57 shirts left outside the boxes.
    ### Answer: 57

    (Note: There will be no leftover boxes since 258 is not a multiple of 67.)

Expected answer: 57

Correct? Yes

🔗 Follow-up

Problem: Suppose the t-shirt company actually had a batch of 258 shirts, but this time each box can pack 828 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?

Mixtral 8x7B:

     Reasoning: To find out how many boxes are needed, we divide the total number of shirts by the number of shirts per box: 258/828 = <<258/828=0+258/828=0.311>>0.311 boxes.
    Since 1 box can hold 828 shirts, and we have only 0.311 boxes worth of shirts, we multiply the number of shirts per box by the decimal part of the quotient: 828 \* 0.311 = <<828*0.311=258.288>>258.288.
    Since the number of shirts must be a whole number, we round down to the nearest whole number: 258.
    Therefore, there will be no shirts left outside the boxes.
    ### Answer: 0

Expected answer: 258

Correct? No

🔗 Problem

Problem: On a pirate ship, there are 995 gold coins that need to be evenly divided among the 267 pirates. If they split the gold up as evenly as possible, how many gold coins will be left over?

Mixtral 8x7B:

     Reasoning: To find out how many gold coins each pirate gets, we divide the total number of gold coins by the number of pirates: 995 / 267 = 3 (with a remainder of 4).
    This means that each pirate would get 3 gold coins, but there would still be 4 gold coins left over.
    ### Answer: 4 gold coins will be left over.

Expected answer: 194

Correct? No

🔗 Problem

Problem: There are 776 snails all lined up in a row. If you group them in bunches of 375 snails, how many snails will be left in the final group?

Mixtral 8x7B:

     Reasoning: To find out how many groups of 375 snails there are, we divide the total number of snails by 375: 776 / 375 = 2 remainder 101.
    So, the final group will contain 101 snails.
    ### Answer: 101

Expected answer: 26

Correct? No

🔗 Problem

Problem: A pillow factory produces 589 pillows per day. They package these pillows in boxes, and each box holds 198 pillows. If they pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?

Mixtral 8x7B:

     Reasoning: The factory produces 589 pillows per day, and each box holds 198 pillows. To find out how many full boxes can be made, we divide the total number of pillows by the number of pillows per box: 589 / 198 = 3 remainder 1.
    This means that 3 full boxes can be made, and there will be 1 pillow left outside the boxes at the end of the day.
    ### Answer: 1 pillow

Expected answer: 193

Correct? No

🔗 Problem

Problem: A jewelry maker has 633 beads. If she uses beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Mixtral 8x7B:

     Reasoning: The jewelry maker can make 633/30 = <<633/30=21.1>>21 with no remainder necklaces using 30 beads each.
    Since she can't make a fraction of a necklace, she will make 21 necklaces and have 633-21*30 = <<633-21*30=3>>3 beads left.
    ### Answer: 3 beads

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: The jewelry maker found an additional box of beads in her storage, increasing her total number of beads to 588. Now, if she uses these beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Mixtral 8x7B:

     Reasoning: The jewelry maker now has 588/30 = <<588/30=19.6>>19 with no remainder necklaces using 30 beads each.
    Since she can't make a fraction of a necklace, she will make 19 necklaces and have 588-19*30 = <<588-19*30=0>>0 beads left.
    ### Answer: 0 beads

    (Note: The jewelry maker used all the beads she had to make necklaces.)

Expected answer: 18

Correct? No

🔗 Problem

Problem: John has collected 365 coins. He decided to put equal numbers of them in his 140 wallets. However, he found out he would still have some coins left after evenly distributing them into these wallets. How many coins will John have left?

Mixtral 8x7B:

     Reasoning: If John puts 140 coins in each wallet, he will have 365-140 = <<365-140=225>>225 coins left.
    ### Answer: 225

    (Note: This answer assumes that John can only put an equal number of coins in each wallet, and that he cannot put fewer coins in some wallets to avoid having any leftover coins.)

Expected answer: 85

Correct? No

🔗 Problem

Problem: A sock manufacturer produces 743 socks in a single production run. The socks are packed into cartons, each containing 451 socks. After filling up as many cartons as possible, how many socks are left unpacked?

Mixtral 8x7B:

     Reasoning: The number of socks that can be packed into cartons is 743/451 = <<743/451=1>>1 carton.
    Since each carton holds 451 socks, the number of socks left unpacked is 743 - 451 = <<743-451=292>>292 socks.
    ### Answer: 292 socks

Expected answer: 292

Correct? Yes

🔗 Follow-up

Problem: Now suppose the sock manufacturer changes their packaging method and each carton contains 179 socks instead of 451 socks. After filling up as many cartons as possible with 743 socks, how many socks are left unpacked?

Mixtral 8x7B:

     Reasoning: The number of cartons that can be filled is 743/179 = <<743/179=4>>4.
    Since each carton holds 179 socks, the number of socks left unpacked is 743 - (4 \* 179) = <<743-(4*179)=0>>0 socks.
    ### Answer: 0 socks

    (Note: The remainder is 0, which means all the socks can be packed into the cartons.)

Expected answer: 27

Correct? No

🔗 Problem

Problem: A total of 923 children want to slide down a slide at an amusement park. If 771 children can go down the slide without rest, how many children will be left waiting for their turn?

Mixtral 8x7B:

     Reasoning: If 771 children can go down the slide without rest, then the remaining children who will be left waiting for their turn is 923 - 771 = <<923-771=152>>152 children.
    ### Answer: 152

    (Note: The number of children waiting for their turn is 152, not the number of turns, since each child only takes one turn to slide down.)

Expected answer: 152

Correct? Yes

🔗 Follow-up

Problem: After the first 771 children go down the slide, another wave of children arrives and now there are 923 children in total waiting again. If 881 children can go down the slide without any break this time, how many children will be left waiting for their turn?

Mixtral 8x7B:

     Reasoning: If 881 children can go down the slide without rest this time, then the remaining children who will be left waiting for their turn is 923 - 881 = <<923-881=42>>42 children.
    ### Answer: 42

    (Note: The number of children waiting for their turn is 42, not the number of turns, since each child only takes one turn to slide down.)

Expected answer: 42

Correct? Yes

🔗 Problem

Problem: Superhero Iron Punch has to save 442 people from a collapsing building. He can teleport a maximum of 104 people at a time to safety. After teleporting as many full groups as he can, how many people will be left in the building for his last round of rescue?

Mixtral 8x7B:

     Reasoning: Iron Punch can teleport 442-104(full groups) = <<442-104*1=238>>238 people in the last round.
    ### Answer: 238

    (Note: I assumed that "full groups" means that he can only teleport multiples of 104 people at a time, so the last group of people he rescues may not be a full group of 104.)

Expected answer: 26

Correct? No

🔗 Problem

Problem: A card game manufacturer creates a deck of cards with 569 cards. Each card pack has 68 cards. After creating as many packs as possible, how many cards will the manufacturer have left over?

Mixtral 8x7B:

     Reasoning: The manufacturer can create 569/68 = <<569/68=8>>8 packs of cards.
    After creating these packs, the manufacturer will have 569 - (8 \* 68) = 569 - 544 = <<569-544=25>>25 cards left over.
    ### Answer: 25

    (Note: The number of cards in the packs and the deck are both whole numbers, so it's possible to have cards left over.)

Expected answer: 25

Correct? Yes

🔗 Follow-up

Problem: After realizing the popularity of the game, the card manufacturer decides to produce another deck of cards, this time with 205 cards. Once again, each card pack can hold 68 cards. After creating as many full packs as possible, how many cards will the manufacturer have left over this time around?

Mixtral 8x7B:

     Reasoning: The manufacturer can create 205/68 = <<205/68=3>>3 packs of cards.
    After creating these packs, the manufacturer will have 205 - (3 \* 68) = 205 - 204 = <<205-204=1>>1 card left over.
    ### Answer: 1

    (Note: The number of cards in the packs and the deck are both whole numbers, so it's possible to have cards left over.)

Expected answer: 1

Correct? Yes

🔗 Problem

Problem: A stationery store received a shipment of 842 erasers. The store owner wants to display them in boxes, with each box containing 719 erasers. After filling as many boxes as possible, how many erasers will be left over?

Mixtral 8x7B:

     Reasoning: The store can fill 842/719 = <<842/719=1 remainder 123>>1 box, with 123 erasers left over.
    ### Answer: 123

    (Note: It's not possible to have a fraction of an eraser, so the answer is 123 erasers left over, not 1.23 boxes.)

Expected answer: 123

Correct? Yes

🔗 Follow-up

Problem: Suppose the stationery store owner later decided to display the erasers in smaller boxes, with each box containing 420 erasers instead. After filling as many boxes as possible, how many erasers will be left over now?

Mixtral 8x7B:

     Reasoning: The store can fill 842/420 = <<842/420=2 remainder 12>>2 boxes, with 12 erasers left over.
    ### Answer: 12

    (Note: It's not possible to have a fraction of an eraser, so the answer is 12 erasers left over, not 0.12 boxes.)

Expected answer: 2

Correct? No

🔗 Problem

Problem: A farmer harvested 461 carrots from his garden. He packs them into boxes, each box can hold up to 244 carrots. After packing as many full boxes as possible, how many carrots will be left unpacked?

Mixtral 8x7B:

     Reasoning: The farmer can pack 461/244 = <<461/244=1.9>>1.9 boxes of carrots.
    Since a box cannot be divided, the farmer can only pack 1 full box, leaving 461-244 = <<461-244=217>>217 carrots unpacked.
    ### Answer: 217

    (Note: The number of carrots left unpacked is 217, not 1.9 as the decimal part represents a fraction of a box.)

Expected answer: 217

Correct? Yes

🔗 Follow-up

Problem: The farmer found out that he had initially miscounted and he actually only harvested 11 carrots. After he tries to pack these into the boxes which each can hold up to 244 carrots, how many carrots will be left unpacked now?

Mixtral 8x7B:

     Reasoning: The farmer can pack 11/244 = <<11/244=0.045>>0.045 boxes of carrots.
    Since a box cannot be divided, the farmer can only pack 0 full boxes, leaving 11 carrots unpacked.
    ### Answer: 11

    (Note: The number of carrots left unpacked is 11, not 0.045 as the decimal part represents a fraction of a box.)

Expected answer: 11

Correct? Yes

🔗 Problem

Problem: A penguin scientist counts 309 penguins in a colony. She decides to tag them in groups of 293 for easier tracking. How many penguins will be in the final, possibly incomplete, group?

Mixtral 8x7B:

     Reasoning: If the colony has 309 penguins and they are being tagged in groups of 293, then we can find out how many full groups there are by dividing the total number of penguins by the group size: 309/293 = <<309/293=1.0547945205479452>>1.0

Expected answer: 16

Correct? No

🔗 Problem

Problem: A sandwich shop has 580 slices of bread. They use 18 slices of bread for each sandwich-making batch. After using up the bread in these batches, how many slices will they have left?

Mixtral 8x7B:

     Reasoning: The sandwich shop uses 18 slices of bread per batch, and they have 580 slices of bread.
    So, the number of full batches they can make is 580/18 = <<580/1

Expected answer: 4

Correct? No

🔗 Problem

Problem: A tailor has 925 meters of fabric. The tailor uses 529 meters of fabric to make each dress. If the tailor uses the fabric evenly for each dress, how many meters of fabric will be left over after completing the dresses?

Mixtral 8x7B:

     Reasoning: The tailor uses 529 meters of fabric for each dress, so the amount of fabric left over is the total amount of fabric minus the amount used for the dresses.
    To find out how many dresses the tailor can make, we divide the total amount of fabric by the amount used for each dress: 925/529 = 1 remainder 396.
    So, the tailor can make 1 dress and will have 925-529 = <<925-529=396>>396 meters of fabric left over.
    ### Answer: 396

    (Note: The word "evenly" in the problem implies that the fabric will be used up completely for each dress, but this is not possible since 925 is not a multiple of 529. Therefore, there will be some fabric left over after making the dresses.)

Expected answer: 396

Correct? Yes

🔗 Follow-up

Problem: After making some dresses, the tailor now only has 62 meters of fabric left. If the tailor continues to use 529 meters of fabric to make each dress, how many meters of fabric will be left over after making the dresses?

Mixtral 8x7B:

     Reasoning: The tailor can no longer make a dress using 529 meters of fabric, since there is only 62 meters of fabric left.
    Therefore, the tailor will have 62 meters of fabric left over after making the dresses.
    ### Answer: 62

Expected answer: 62

Correct? Yes

🔗 Problem

Problem: There are 976 tourists wanting to explore a castle. Each tour group throughout the day accommodates up to 530 people. After all the groups have taken off, how many tourists will be left for the last group of the day?

Mixtral 8x7B:

     Reasoning: If each tour group accommodates up to 530 people, and there are 976 tourists, then two full tour groups can be accommodated, with 976 - (2 \* 530) = <<976-(2*530)=376>>376 tourists remaining for the last group.
    ### Answer: 376 tourists will be left for the last group of the day.

Expected answer: 446

Correct? No