🔗 Problem

Problem: A rectangle has a length of 21m and a width of 37m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The perimeter of a rectangle is equal to the sum of the lengths of its two sides that are parallel to each other, plus the sum of the lengths of its two sides that are perpendicular to each other.

    In this case, the length of the rectangle is 21m, and the width is 37m. The perimeter of the rectangle is therefore:

    21 + 21 + 37 + 37 = 116m

    So the perimeter of the rectangle is 116m.

Expected answer: 116

Correct? Yes

🔗 Problem

Problem: A rectangular garden has a length of 50 feet and a width of 20 feet. What is the perimeter of the garden?

Gemma 2B:

      To find the perimeter of the garden, we need to add up the lengths of all its sides. Since the garden is rectangular, it has four sides: two sides of length 50 feet and two sides of length 20 feet.

    So, the perimeter of the garden is:

    50 + 50 + 20 + 20 = 140 feet

    Therefore, the perimeter of the garden is 140 feet.

Expected answer: 140

Correct? Yes

🔗 Problem

Problem: A rectangle has a width of 7m and a length of 26m. What is the area of this rectangle?

Gemma 2B:

      To find the area of a rectangle, you need to multiply the width by the length.

    Width = 7m
    Length = 26m

    Area = Width x Length
    = 7m x 26m
    = 182m^2

    Therefore, the area of the rectangle is 182 square meters.

    ### Answer: 182m^2

Expected answer: 182

Correct? Yes

🔗 Follow-up

Problem: The width of the rectangle stays the same at 7m, but the length extends by 9m to become 35m. What is the area of the rectangle now?

Gemma 2B:

      To find the area of the rectangle now, you need to multiply the width by the new length.

    Width = 7m
    Length = 35m

    Area = Width x Length
    = 7m x 35m
    = 245m^2

    Therefore, the area of the rectangle now is 245 square meters.

    ### Answer: 245m^2

Expected answer: 245

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 50m and a width of 15m. What is its perimeter?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides.

    The length of the rectangle is 50m, and the width is 15m. The perimeter of the rectangle is therefore:

    50 + 50 + 15 + 15 = 120m

    So, the perimeter of the rectangle is 120m.

Expected answer: 130

Correct? No

🔗 Problem

Problem: A rectangular fence has a side length of 5m and another side of 19m. What is the total distance, in meters, around the fence (perimeter)?

Gemma 2B:

      To find the perimeter of the rectangular fence, we need to add up the lengths of all its sides. Since the fence has two sides of equal length, we can simply multiply the length of one side by 2 to find the total perimeter.

    So, the perimeter of the rectangular fence is:

    2 x 5m = 10m + 2 x 19m = 38m

    Therefore, the total distance around the fence is 38 meters.

Expected answer: 48

Correct? No

🔗 Problem

Problem: A rectangle has sides of length 49m and 6m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides.

    Let's label the sides of the rectangle as follows:

    * Side 1: 49m
    * Side 2: 6m
    * Side 3: 49m
    * Side 4: 6m

    The perimeter of the rectangle is the sum of the lengths of all four sides:

    Perimeter = Side 1 + Side 2 + Side 3 + Side 4
    = 49m + 6m + 49m + 6m
    = 100m + 12m
    = 112m

    Therefore, the perimeter of the rectangle is 112m.

Expected answer: 110

Correct? No

🔗 Problem

Problem: Joshua plans to lay a wire around his rectangular garden. If the garden is 7m wide and 26m long, how much wire will Joshua need to enclose the garden completely?

Gemma 2B:

      To find the amount of wire needed to enclose the garden completely, we need to find the perimeter of the garden. The perimeter of a rectangle is the distance around the outside of the rectangle. The formula for the perimeter of a rectangle is:

    Perimeter = 2(width + length)

    In this case, the width of the garden is 7 meters and the length is 26 meters. So, the perimeter of the garden is:

    Perimeter = 2(7 + 26) = 2(33) = 66 meters

    Therefore, Joshua will need 66 meters of wire to enclose the garden completely.

Expected answer: 66

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 18 meters and a width of 11 meters. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 18 meters, and the width is 11 meters.

    So, the perimeter of the rectangle is:

    18 + 18 + 11 + 11 = 58 meters

    Therefore, the perimeter of the rectangle is 58 meters.

    ### Answer: 58 meters

Expected answer: 58

Correct? Yes

🔗 Follow-up

Problem: Suppose the width of the rectangle changed to 44 meters, while the length remained at 18 meters. What would be the new perimeter of the rectangle?

Gemma 2B:

      If the width of the rectangle changed to 44 meters, while the length remained at 18 meters, the new perimeter of the rectangle would be:

    18 + 18 + 44 + 44 = 112 meters

    Therefore, the new perimeter of the rectangle would be 112 meters.

    ### Answer: 112 meters

Expected answer: 124

Correct? No

🔗 Problem

Problem: The dimensions of a rectangle are 22 feet by 39 feet. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides.

    Let's label the dimensions of the rectangle as follows:

    * Length (L) = 22 feet
    * Width (W) = 39 feet

    The perimeter of the rectangle is given by the formula:

    Perimeter = 2(L + W)

    Plugging in the values we get:

    Perimeter = 2(22 + 39)
    Perimeter = 2(61)
    Perimeter = 122 feet

    Therefore, the perimeter of the rectangle is 122 feet.

    ### Answer: 122 feet

Expected answer: 122

Correct? Yes

🔗 Follow-up

Problem: If the length of the rectangle is now 26 feet instead of 39 feet, while the width remains the same at 22 feet, what would then be the new perimeter of the rectangle?

Gemma 2B:

      To find the new perimeter of the rectangle, we need to add the lengths of all four sides.

    Let's label the dimensions of the new rectangle as follows:

    * Length (L) = 26 feet
    * Width (W) = 22 feet

    The perimeter of the new rectangle is given by the formula:

    Perimeter = 2(L + W)

    Plugging in the values we get:

    Perimeter = 2(26 + 22)
    Perimeter = 2(48)
    Perimeter = 96 feet

    Therefore, the new perimeter of the rectangle is 96 feet.

    ### Answer: 96 feet

Expected answer: 96

Correct? Yes

🔗 Problem

Problem: A rectangle has two sides measuring 45m and the other two sides measuring 25m each. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all four sides.

    Let's call the length of the longer sides "a" and the length of the shorter sides "b".

    The perimeter of the rectangle is:

    P = 2a + 2b

    In this case, a = 45m and b = 25m.

    So, the perimeter of the rectangle is:

    P = 2(45) + 2(25)
    P = 90 + 50
    P = 140m

    Therefore, the perimeter of the rectangle is 140m.

Expected answer: 140

Correct? Yes

🔗 Problem

Problem: A rectangular garden has a length of 8m and a width of 5m. What is the perimeter of this garden?

Gemma 2B:

      To find the perimeter of the garden, we need to add up the lengths of all its sides. Since the garden is rectangular, it has four sides: two sides of length 8m and two sides of length 5m.

    So, the perimeter of the garden is:

    8m + 8m + 5m + 5m = 26m

    Therefore, the perimeter of the garden is 26m.

Expected answer: 26

Correct? Yes

🔗 Problem

Problem: In a rectangle, the length is 19 units and the width is 17 units. What is the area of this rectangle?

Gemma 2B:

      To find the area of a rectangle, you need to multiply the length by the width.

    In this case, the length is 19 units and the width is 17 units, so the area of the rectangle is:

    19 x 17 = 323

    So the area of the rectangle is 323 square units.

Expected answer: 323

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 42 meters and a width of 8 meters. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 42 meters, and the width is 8 meters.

    So, the perimeter of the rectangle is:

    42 + 42 + 8 + 8 = 96 meters

    Therefore, the perimeter of the rectangle is 96 meters.

    ### Answer: 96 meters

Expected answer: 100

Correct? No

🔗 Problem

Problem: A rectangle has a width of 16m and a length of 38m. What is the area of this rectangle?

Gemma 2B:

      To find the area of a rectangle, you need to multiply the width by the length.

    Width = 16m
    Length = 38m

    Area = Width x Length
    = 16m x 38m
    = 608m^2

    Therefore, the area of the rectangle is 608 square meters.

    ### Answer: 608m^2

Expected answer: 608

Correct? Yes

🔗 Follow-up

Problem: In the rectangle from the previous problem, suppose we replace the length of 38m with a new length of 22m. What would the new area of the rectangle be?

Gemma 2B:

      To find the new area of the rectangle, we need to multiply the width by the new length.

    Width = 16m
    New Length = 22m

    Area = Width x New Length
    = 16m x 22m
    = 352m^2

    Therefore, the new area of the rectangle would be 352 square meters.

    ### Answer: 352m^2

Expected answer: 352

Correct? Yes

🔗 Problem

Problem: Consider a rectangular plot of land. The plot has a length of 28m and a width of 17m. What is the area of the plot?

Gemma 2B:

      To find the area of the plot, we need to multiply the length by the width.

    Length = 28m
    Width = 17m

    Area = Length x Width
    Area = 28m x 17m
    Area = 496 square meters

    Therefore, the area of the plot is 496 square meters.

Expected answer: 476

Correct? No

🔗 Problem

Problem: A rectangle has a length of 43m and a width of 41m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the sides of a rectangle are equal, so we can simply multiply the length by 4 to find the perimeter.

    In this case, the length of the rectangle is 43m, so the perimeter is:

    43m x 4 = 172m

    Therefore, the perimeter of the rectangle is 172m.

Expected answer: 168

Correct? No

🔗 Problem

Problem: A rectangle has one side that measures 44m, and the other side that measures 17m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides. Let's call the length of the side that measures 44m "a" and the length of the side that measures 17m "b".

    The perimeter of the rectangle is:

    P = 2(a + b)

    Since we know that a = 44m and b = 17m, we can substitute these values into the formula:

    P = 2(44m + 17m)

    P = 2(61m)

    P = 122m

    Therefore, the perimeter of the rectangle is 122m.

    ### Answer: 122m

Expected answer: 122

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, we considered a rectangle with one side that measures 44m, and the other side that measures 17m. What would be the perimeter of the rectangle if instead the length of the second side were 21m?

Gemma 2B:

      To find the perimeter of the rectangle if the length of the second side were 21m, we can use the same formula:

    P = 2(a + b)

    where a is the length of the first side and b is the length of the second side.

    Since we know that a = 44m and b = 21m, we can substitute these values into the formula:

    P = 2(44m + 21m)

    P = 2(65m)

    P = 130m

    Therefore, the perimeter of the rectangle would be 130m if the length of the second side were 21m instead of 17m.

    ### Answer: 130m

Expected answer: 130

Correct? Yes

🔗 Problem

Problem: A rectangle's perimeter is twice the sum of its width and length. If the rectangle's width is 2m and its length is 20m, what is its perimeter?

Gemma 2B:

      The perimeter of a rectangle is the sum of its width and length. Since the perimeter is twice the sum of its width and length, we can write:

    Perimeter = 2(width + length)

    Substituting the values given in the problem, we get:

    Perimeter = 2(2m + 20m)

    Perimeter = 2(22m)

    Perimeter = 44m

    Therefore, the perimeter of the rectangle is 44m.

Expected answer: 44

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 4 meters and a width of 5 meters. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add the lengths of all four sides.

    The length of the rectangle is 4 meters, and the width is 5 meters.

    So, the perimeter of the rectangle is:
    4 + 4 + 5 + 5 = 18 meters.

    ### Answer: 18 meters.

Expected answer: 18

Correct? Yes

🔗 Follow-up

Problem: Consider the same rectangle from before, but now suppose its length is extended to 42 meters while the width remains 5 meters. What would then be the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of the new rectangle, we need to add the lengths of all four sides.

    The length of the rectangle is now 42 meters, and the width is still 5 meters.

    So, the perimeter of the new rectangle is:
    42 + 42 + 5 + 5 = 94 meters.

    ### Answer: 94 meters.

Expected answer: 94

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 45m and a width of 37m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 45m, and the width is 37m.

    So, the perimeter of the rectangle is:

    45 + 45 + 37 + 37 = 164m

    Therefore, the perimeter of the rectangle is 164m.

Expected answer: 164

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 27m and a width of 21m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 27m, and the width is 21m.

    So, the perimeter of the rectangle is:

    27 + 27 + 21 + 21 = 96m

    Therefore, the perimeter of the rectangle is 96m.

Expected answer: 96

Correct? Yes

🔗 Problem

Problem: A rectangular garden has a length of 30m and a width of 20m. What is the perimeter of the garden?

Gemma 2B:

      To find the perimeter of the garden, we need to add up the lengths of all its sides. Since the garden is rectangular, it has four sides: two sides of length 30m and two sides of length 20m.

    So, the perimeter of the garden is:
    30m + 30m + 20m + 20m = 100m

    Therefore, the perimeter of the garden is 100m.

Expected answer: 100

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 30m and a width of 27m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 30m, and the width is 27m.

    So, the perimeter of the rectangle is:

    30 + 30 + 27 + 27 = 114m

    Therefore, the perimeter of the rectangle is 114m.

Expected answer: 114

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 23m and a width of 11m. What is the area of this rectangle?

Gemma 2B:

      To find the area of a rectangle, you need to multiply the length by the width.

    In this case, the length is 23m and the width is 11m, so the area is:

    23m x 11m = 253m^2

    Therefore, the area of the rectangle is 253 square meters.

    ### Answer: 253 m^2

Expected answer: 253

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 3m and a width of 9m. What would be the total perimeter of this rectangle?

Gemma 2B:

      To find the total perimeter of a rectangle, you need to add up the lengths of all its sides. In this case, the length of the rectangle is 3m, and the width is 9m. So, the perimeter of the rectangle would be:

    3m + 3m + 9m + 9m = 24m

    Therefore, the total perimeter of the rectangle is 24m.

Expected answer: 24

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 31m and a width of 6m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. In this case, the length of the rectangle is 31m, and the width is 6m.

    The perimeter of the rectangle is:
    31m + 31m + 6m + 6m = 74m

    So, the perimeter of the rectangle is 74m.

Expected answer: 74

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 12m and a width of 33m. What is the area of this rectangle?

Gemma 2B:

      To find the area of a rectangle, you need to multiply the length by the width.

    In this case, the length is 12m and the width is 33m, so the area is:

    12m x 33m = 408m^2

    Therefore, the area of the rectangle is 408 square meters.

    ### Answer: 408 m^2

Expected answer: 396

Correct? No

🔗 Problem

Problem: A rectangle has a length of 20m and all of its sides are of equal length. What is the perimeter of this rectangle?

Gemma 2B:

      The perimeter of a rectangle is the sum of the lengths of all its sides. Since all the sides of this rectangle are of equal length, we can use the formula P = 4s, where P is the perimeter and s is the length of one side.

    In this case, the length of one side is 20m, so the perimeter of the rectangle is:

    P = 4s = 4(20) = 80m

    Therefore, the perimeter of the rectangle is 80m.

Expected answer: 80

Correct? Yes

🔗 Problem

Problem: A rectangular playground has a length of 35m and a width of 9m. What is the perimeter of the playground?

Gemma 2B:

      To find the perimeter of the rectangular playground, we need to add up the lengths of all its sides.

    The length of the playground is 35m, and the width is 9m.

    So, the perimeter of the playground is:

    35m + 35m + 9m + 9m = 88m

    Therefore, the perimeter of the rectangular playground is 88m.

Expected answer: 88

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 9m and a width of 25m. What is the area of the rectangle?

Gemma 2B:

      To find the area of the rectangle, we need to multiply the length by the width.

    Length = 9m
    Width = 25m

    Area = length x width
    = 9m x 25m
    = 225m^2

    Therefore, the area of the rectangle is 225 square meters.

    ### Answer: 225m^2

Expected answer: 225

Correct? Yes

🔗 Follow-up

Problem: Suppose the length of the rectangle was actually 16m and the width remained the same at 9m. What would be the new area of the rectangle in this case?

Gemma 2B:

      If the length of the rectangle was actually 16m and the width remained the same at 9m, then the area of the rectangle would be:

    Area = length x width
    = 16m x 9m
    = 144m^2

    Therefore, the new area of the rectangle would be 144 square meters.

    ### Answer: 144m^2

Expected answer: 144

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 13m and a width of 43m. What is the area of the rectangle?

Gemma 2B:

      To find the area of the rectangle, we need to multiply the length by the width.

    Length = 13m
    Width = 43m

    Area = length x width
    = 13m x 43m
    = 559m^2

    Therefore, the area of the rectangle is 559 square meters.

    ### Answer: 559 m^2

Expected answer: 559

Correct? Yes

🔗 Follow-up

Problem: Suppose we realized later that the width of the rectangle was actually 42m, not 43m. What would then be the area of the rectangle?

Gemma 2B:

      If the width of the rectangle was actually 42m, not 43m, then the area of the rectangle would be:

    Area = length x width
    = 13m x 42m
    = 546m^2

    Therefore, the area of the rectangle would be 546 square meters.

    ### Answer: 546 m^2

Expected answer: 546

Correct? Yes

🔗 Problem

Problem: A rectangle has a width of 27m and a length of 47m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The perimeter of a rectangle is equal to the sum of the width and length of the rectangle.

    In this case, the width of the rectangle is 27m and the length is 47m. So, the perimeter of the rectangle is:

    Perimeter = width + length
    = 27m + 47m
    = 74m

    Therefore, the perimeter of the rectangle is 74m.

Expected answer: 148

Correct? No

🔗 Problem

Problem: A rectangular football field has an area of 21m * 42m, calculate the area of the football field.

Gemma 2B:

      To calculate the area of the football field, we need to multiply the length by the width.

    Length = 21m
    Width = 42m

    Area = Length x Width
    Area = 21m x 42m
    Area = 862 square meters

    Therefore, the area of the football field is 862 square meters.

    ### Answer: 862 square meters.

Expected answer: 882

Correct? No

🔗 Problem

Problem: A rectangle's area is found by multiplying its length by its width. If the width of a certain rectangle is 27m and the length is 25m, what is the area of the rectangle?

Gemma 2B:

      The area of the rectangle is 27m x 25m = 675m^2.
    ### Answer: 675m^2.

Expected answer: 675

Correct? Yes

🔗 Follow-up

Problem: Suppose the width of the rectangle in the previous problem was not 27m, but was instead 11m, with the length remaining at 25m. What would then be the new area of the rectangle?

Gemma 2B:

      If the width of the rectangle was 11m instead of 27m, and the length remained at 25m, then the area of the rectangle would be 11m x 25m = 275m^2.
    ### Answer: 275m^2.

Expected answer: 275

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 45m and a width of 48m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 45m, and the width is 48m.

    So, the perimeter of the rectangle is:

    45 + 45 + 48 + 48 = 196m

    Therefore, the perimeter of the rectangle is 196m.

    ### Answer: 196m

Expected answer: 186

Correct? No

🔗 Problem

Problem: A rectangle has a length of 11 meters and a width of 7 meters. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 11 meters, and the width is 7 meters.

    So, the perimeter of the rectangle is:

    11 + 11 + 7 + 7 = 36 meters

    Therefore, the perimeter of the rectangle is 36 meters.

    ### Answer: 36 meters

Expected answer: 36

Correct? Yes

🔗 Follow-up

Problem: Suppose the length of the rectangle was instead 10 meters while the width remained 7 meters. What would be the new perimeter of the rectangle?

Gemma 2B:

      If the length of the rectangle was 10 meters instead of 11 meters, the perimeter of the rectangle would be:

    10 + 10 + 7 + 7 = 34 meters

    Therefore, the new perimeter of the rectangle would be 34 meters.

Expected answer: 34

Correct? Yes

🔗 Problem

Problem: A rectangular field has a length of 30m and a width of 2m. Can you calculate the perimeter of the field?

Gemma 2B:

      Yes, I can calculate the perimeter of the field.

    The perimeter of a rectangle is found by adding the lengths of all four sides. In this case, the length of the field is 30m, and the width is 2m. So, the perimeter of the field is:

    30m + 30m + 2m + 2m = 64m

    Therefore, the perimeter of the field is 64m.

Expected answer: 64

Correct? Yes

🔗 Problem

Problem: A rectangle has one side that is 7m long and another side that is 8m long. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add up the lengths of all four sides.

    In this case, the rectangle has one side that is 7m long and another side that is 8m long. The other two sides are the same length as the first two sides, so the perimeter of the rectangle is:

    7m + 8m + 7m + 8m = 22m + 22m = 44m

    Therefore, the perimeter of the rectangle is 44m.

Expected answer: 30

Correct? No

🔗 Problem

Problem: A rectangle has a length of 14m and a width of 18m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add up the lengths of all its sides. In this case, the length of the rectangle is 14m and the width is 18m.

    So, the perimeter of the rectangle is:

    14m + 14m + 18m + 18m = 54m

    Therefore, the perimeter of the rectangle is 54m.

Expected answer: 64

Correct? No

🔗 Problem

Problem: A rectangle has a length of 43 units and a width of 3 units. Calculate the perimeter of this rectangle.

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. In this case, the length of the rectangle is 43 units, and the width is 3 units.

    So, the perimeter of the rectangle is:

    43 + 43 + 3 + 3 = 92

    Therefore, the perimeter of the rectangle is 92 units.

    ### Answer: 92

Expected answer: 92

Correct? Yes

🔗 Follow-up

Problem: Let's consider the same rectangle from before, but this time, the width has increased to 39 units while the length remained the same at 43 units. What is the new perimeter of this rectangle?

Gemma 2B:

      To find the new perimeter of the rectangle, we need to add up the lengths of all its sides. In this case, the length of the rectangle is still 43 units, but the width has increased to 39 units.

    So, the new perimeter of the rectangle is:

    43 + 43 + 39 + 39 = 164

    Therefore, the new perimeter of the rectangle is 164 units.

    ### Answer: 164

Expected answer: 164

Correct? Yes

🔗 Problem

Problem: A rectangle has one side that measures 36 meters and another side that measures 42 meters. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides. Let's call the length of the side that measures 36 meters "a" and the length of the side that measures 42 meters "b".

    The perimeter of the rectangle is:

    P = 2(a + b)

    Since we know that a = 36 and b = 42, we can substitute these values into the formula:

    P = 2(36 + 42)

    P = 2(78)

    P = 156

    Therefore, the perimeter of the rectangle is 156 meters.

    ### Answer: 156

Expected answer: 156

Correct? Yes

🔗 Follow-up

Problem: Now suppose that the longer side of the rectangle measures 48 meters instead of 42. What would be the new perimeter of the rectangle?

Gemma 2B:

      To find the new perimeter of the rectangle, we need to add the lengths of all four sides. Let's call the length of the side that measures 36 meters "a" and the length of the side that measures 48 meters "b".

    The perimeter of the rectangle is:

    P = 2(a + b)

    Since we know that a = 36 and b = 48, we can substitute these values into the formula:

    P = 2(36 + 48)

    P = 2(84)

    P = 168

    Therefore, the new perimeter of the rectangle is 168 meters.

    ### Answer: 168

Expected answer: 168

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 1m and a width of 6m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add up the lengths of all its sides. In this case, the length of the rectangle is 1m and the width is 6m, so the perimeter is:

    1m + 1m + 6m + 6m = 14m

    So, the perimeter of the rectangle is 14m.

Expected answer: 14

Correct? Yes

🔗 Problem

Problem: A rectangle has two sides measuring 45m and two sides measuring 8m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all four sides.

    Let's call the length of the longer sides "a" and the length of the shorter sides "b".

    The perimeter of the rectangle is:

    P = 2a + 2b

    In this case, we know that a = 45m and b = 8m.

    So, the perimeter of the rectangle is:

    P = 2(45) + 2(8)
    = 90 + 16
    = 106m

    Therefore, the perimeter of the rectangle is 106m.

Expected answer: 106

Correct? Yes

🔗 Problem

Problem: A rectangular garden has a length of 25 meters and a width of 37 meters. What is the perimeter of the garden?

Gemma 2B:

      To find the perimeter of the garden, we need to add up the lengths of all its sides. Since the garden is rectangular, it has four sides: two sides of length 25 meters and two sides of length 37 meters.

    So, the perimeter of the garden is:

    25 + 25 + 37 + 37 = 124 meters

    Therefore, the perimeter of the garden is 124 meters.

Expected answer: 124

Correct? Yes

🔗 Problem

Problem: A rectangle has length 36m and width 3m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. In this case, the length of the rectangle is 36m and the width is 3m.

    So, the perimeter of the rectangle is:

    36 + 3 + 3 + 36 = 78m

    Therefore, the perimeter of the rectangle is 78m.

Expected answer: 78

Correct? Yes

🔗 Problem

Problem: A rectangular garden has a length of 45 meters and a width of 50 meters. Calculate the perimeter of the garden.

Gemma 2B:

      To find the perimeter of the garden, we need to add up the lengths of all its sides. Since the garden is rectangular, it has four sides: two sides of length 45 meters and two sides of length 50 meters.

    So, the perimeter of the garden is:

    45 + 45 + 50 + 50 = 180 meters

    Therefore, the perimeter of the garden is 180 meters.

Expected answer: 190

Correct? No

🔗 Problem

Problem: A rectangle has a length of 44m and a width of 34m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 44m, and the width is 34m.

    So, the perimeter of the rectangle is:

    44 + 44 + 34 + 34 = 156m

    Therefore, the perimeter of the rectangle is 156m.

Expected answer: 156

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 42 m and a width of 29 m. Calculate the perimeter of the rectangle.

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides.

    The length of the rectangle is 42 m, and the width is 29 m.

    So, the perimeter of the rectangle is:

    42 + 42 + 29 + 29 = 142 m

    Therefore, the perimeter of the rectangle is 142 m.

    ### Answer: 142 m

Expected answer: 142

Correct? Yes

🔗 Follow-up

Problem: Suppose the width of the rectangle was actually 38 m instead of 29 m. What would then be the new perimeter of the rectangle?

Gemma 2B:

      If the width of the rectangle was actually 38 m instead of 29 m, then the perimeter of the rectangle would be:

    42 + 42 + 38 + 38 = 160 m

    Therefore, the new perimeter of the rectangle would be 160 m.

Expected answer: 160

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 44 meters and a width of 35 meters. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides.

    The length of the rectangle is 44 meters, and the width is 35 meters.

    So, the perimeter of the rectangle is:
    44 + 44 + 35 + 35 = 158 meters.

    Therefore, the perimeter of the rectangle is 158 meters.

Expected answer: 158

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 44m and a width of 45m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the sides of a rectangle are equal, so we can simply multiply the length by 4 to find the perimeter.

    In this case, the length of the rectangle is 44m, so the perimeter is:

    44m x 4 = 176m

    Therefore, the perimeter of the rectangle is 176m.

Expected answer: 178

Correct? No

🔗 Problem

Problem: A rectangle has a length of 3 meters and a width of 39 meters. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add the lengths of all four sides.

    In this case, the length of the rectangle is 3 meters and the width is 39 meters.

    So, the perimeter of the rectangle is:
    3 + 3 + 39 + 39 = 81 meters.

    Therefore, the perimeter of the rectangle is 81 meters.

Expected answer: 84

Correct? No

🔗 Problem

Problem: A rectangular garden has sides that measure 32m and 12m. What is the perimeter of this garden?

Gemma 2B:

      To find the perimeter of the garden, we need to add up the lengths of all its sides. Since the garden is rectangular, it has four sides of equal length.

    Let's call the length of one side "x". Then, the length of the other three sides is also "x".

    The perimeter of the garden is the sum of the lengths of all its sides:

    Perimeter = 4x

    We know that the length of one side is 32 meters, so we can substitute this value into the equation:

    Perimeter = 4(32)
    Perimeter = 128 meters

    Therefore, the perimeter of the garden is 128 meters.

Expected answer: 88

Correct? No

🔗 Problem

Problem: A rectangular swimming pool has a length of 24 feet and a width of 6 feet. What is the perimeter of the swimming pool?

Gemma 2B:

      To find the perimeter of the swimming pool, we need to add up the lengths of all its sides. Since the pool is rectangular, it has four sides: two short sides (the length of the width) and two long sides (the length of the length).

    The perimeter of the swimming pool is:

    2(6) + 2(24) = 2(6) + 48 = 14 + 48 = 62 feet

    Therefore, the perimeter of the swimming pool is 62 feet.

Expected answer: 60

Correct? No

🔗 Problem

Problem: A rectangle has a length of 27m and a width of 21m. What is the area of this rectangle?

Gemma 2B:

      To find the area of a rectangle, you need to multiply the length by the width.

    In this case, the length is 27m and the width is 21m, so the area is:

    27m x 21m = 557m^2

    Therefore, the area of the rectangle is 557 square meters.

    ### Answer: 557 m^2

Expected answer: 567

Correct? No

🔗 Problem

Problem: A rectangle has twice the length of a square. If the square's side is 49m, what is the length of the rectangle?

Gemma 2B:

      Let's start by using the information that the rectangle has twice the length of the square. This means that the length of the rectangle is twice the side of the square, or 2 \* 49 = 98 meters.

    So, the length of the rectangle is 98 meters.

Expected answer: 98

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 50m and a width of 36m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 50m, and the width is 36m.

    So, the perimeter of the rectangle is:

    50 + 50 + 36 + 36 = 172m

    Therefore, the perimeter of the rectangle is 172m.

Expected answer: 172

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 8m and a width of 44m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 8m, and the width is 44m.

    So, the perimeter of the rectangle is:

    8m + 8m + 44m + 44m = 176m

    Therefore, the perimeter of the rectangle is 176m.

Expected answer: 104

Correct? No

🔗 Problem

Problem: If a rectangle has a length of 47 feet and a width of 21 feet, what is the area of the rectangle?

Gemma 2B:

      To find the area of a rectangle, you need to multiply the length by the width.

    In this case, the length is 47 feet and the width is 21 feet, so the area of the rectangle is:

    47 feet x 21 feet = 957 square feet

    Therefore, the area of the rectangle is 957 square feet.

Expected answer: 987

Correct? No

🔗 Problem

Problem: A rectangle has a length of 19m and a breadth of 28m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides.

    The length of the rectangle is 19m, and the breadth is 28m.

    So, the perimeter of the rectangle is:
    19m + 19m + 28m + 28m = 94m

    Therefore, the perimeter of the rectangle is 94m.

    ### Answer: 94m

Expected answer: 94

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, what if the length of the rectangle was 27m instead of 19m while keeping the breadth the same? What would be the new perimeter?

Gemma 2B:

      If the length of the rectangle was 27m instead of 19m, the perimeter would be:
    27m + 27m + 28m + 28m = 109m

    Therefore, the new perimeter would be 109m.

Expected answer: 110

Correct? No

🔗 Problem

Problem: One side of a rectangle is four times the length of the other side. If the longer side measures 39 meters, what is the area of the rectangle when the shorter side is 10 meters?

Gemma 2B:

      Reasoning: Let's call the length of the shorter side "x" meters. Since the longer side is four times the length of the shorter side, the longer side is 4x meters.

    The area of the rectangle is found by multiplying the length and width:

    Area = length x width
    = (4x) x 10
    = 40x

    Since the longer side measures 39 meters, we can set up the equation:

    40x = 39x

    Solving for x, we get:

    x = 39/4
    = 9.75

    So the shorter side of the rectangle is 9.75 meters long.

    Now, we can find the area of the rectangle:

    Area = length x width
    = (4x) x 10
    = 40x
    = 40(9.75)
    = 388.75 square meters

    Therefore, the area of the rectangle is 388.75 square meters.
    ### Answer: 388.75 square meters.

Expected answer: 390

Correct? No

🔗 Problem

Problem: A rectangle has identical sides, each measuring 19 meters. What is the total perimeter of the rectangle?

Gemma 2B:

      Reasoning: The perimeter of a rectangle is the sum of the lengths of all its sides. Since the rectangle has identical sides, the perimeter is 4 times the length of one side.

    The length of one side is 19 meters, so the total perimeter is 4 x 19 = <<4*19=76>>76 meters.

    ### Answer: 76 meters.

Expected answer: 76

Correct? Yes

🔗 Follow-up

Problem: The rectangle mentioned in the previous problem has been resized. The new rectangle now has a length of 19 meters but a width of 6 meters. What is the new total perimeter of the rectangle?

Gemma 2B:

      Reasoning: The perimeter of a rectangle is the sum of the lengths of all its sides. Since the rectangle has been resized, the perimeter will also change.

    The length of the new rectangle is 19 meters, and the width is 6 meters. The perimeter of the new rectangle is therefore:

    Perimeter = 2 x (19 + 6) = <<2*(19+6)=44>>44 meters.

    ### Answer: 44 meters.

Expected answer: 50

Correct? No

🔗 Problem

Problem: The area of a rectangle is given by the equation length * width. If the length is 9m and the width is 26m, what is the area of the rectangle?

Gemma 2B:

      The area of a rectangle is given by the equation length * width. In this case, the length is 9m and the width is 26m, so the area of the rectangle is:

    9m * 26m = 234m^2

    Therefore, the area of the rectangle is 234 square meters.

Expected answer: 234

Correct? Yes

🔗 Problem

Problem: A rectangle has one side measuring 19cm and another side measuring 7cm. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides. Let's call the length of the side measuring 19cm "a" and the length of the side measuring 7cm "b".

    The perimeter of the rectangle is:

    P = 2(a + b)

    Since we know that a = 19cm and b = 7cm, we can substitute these values into the formula:

    P = 2(19cm + 7cm)
    P = 2(26cm)
    P = 52cm

    Therefore, the perimeter of the rectangle is 52cm.

Expected answer: 52

Correct? Yes

🔗 Problem

Problem: A shutter is in the shape of a rectangle. Its length is 10m and its width is 6m. What is the total area of the shutter?

Gemma 2B:

      To find the total area of the shutter, we need to multiply the length by the width.

    Length = 10m
    Width = 6m

    Area = Length x Width
    = 10m x 6m
    = 60m^2

    Therefore, the total area of the shutter is 60m^2.

Expected answer: 60

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 24 units and a width of 15 units. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add the lengths of all four sides.

    The length of the rectangle is 24 units, and the width is 15 units.

    So, the perimeter of the rectangle is:

    24 + 24 + 15 + 15 = 72

    Therefore, the perimeter of the rectangle is 72 units.

    ### Answer: 72

Expected answer: 78

Correct? No

🔗 Problem

Problem: If a rectangular plot of land has a length of 32m and a width of 27m, what is the area of the plot in square meters?

Gemma 2B:

      To find the area of the plot, we need to multiply the length by the width.

    Length = 32m
    Width = 27m

    Area = Length x Width
    Area = 32m x 27m
    Area = 896 square meters

    Therefore, the area of the plot is 896 square meters.

    ### Answer: 896 square meters.

Expected answer: 864

Correct? No

🔗 Problem

Problem: A rectangle has one side that measures 15m and another side that measures 10m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add the lengths of all four sides. In this case, the perimeter would be:

    15m + 15m + 10m + 10m = 40m

    So, the perimeter of the rectangle is 40 meters.

    ### Answer: 40m

Expected answer: 50

Correct? No

🔗 Problem

Problem: A rectangle has a length of 44m and a width of 37m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 44m, and the width is 37m.

    So, the perimeter of the rectangle is:

    44 + 44 + 37 + 37 = 165m

    Therefore, the perimeter of the rectangle is 165m.

Expected answer: 162

Correct? No

🔗 Problem

Problem: A rectangle has length of 14 cm and width 8 cm. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides.

    The length of the rectangle is 14 cm, and the width is 8 cm.

    So, the perimeter of the rectangle is:
    14 cm + 14 cm + 8 cm + 8 cm = 44 cm

    Therefore, the perimeter of the rectangle is 44 cm.

    ### Answer: 44 cm

Expected answer: 44

Correct? Yes

🔗 Follow-up

Problem: If the length of the rectangle remains 14 cm, but the width is increased to 18 cm, what would be the new perimeter of the rectangle now?

Gemma 2B:

      If the length of the rectangle remains 14 cm, but the width is increased to 18 cm, the new perimeter of the rectangle would be:

    14 cm + 14 cm + 18 cm + 18 cm = 64 cm

    Therefore, the new perimeter of the rectangle would be 64 cm.

    ### Answer: 64 cm

Expected answer: 64

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 26m and a width of 28m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the sides of a rectangle are equal, so we can simply multiply the length by 4 to find the perimeter.

    In this case, the length of the rectangle is 26m, so the perimeter is:

    26m x 4 = 104m

    Therefore, the perimeter of the rectangle is 104m.

Expected answer: 108

Correct? No

🔗 Problem

Problem: A rectangle has a length of 15m and a width of 37m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 15m, and the width is 37m.

    So, the perimeter of the rectangle is:

    15m + 15m + 37m + 37m = 109m

    Therefore, the perimeter of the rectangle is 109m.

Expected answer: 104

Correct? No

🔗 Problem

Problem: A rectangle has a length of 42m and a width of 40m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 42m, and the width is 40m.

    So, the perimeter of the rectangle is:

    42m + 42m + 40m + 40m = 164m

    Therefore, the perimeter of the rectangle is 164m.

    ### Answer: 164m

Expected answer: 164

Correct? Yes

🔗 Follow-up

Problem: The rectangle you were previously given now has a length of 42m and the width has been adjusted to 24m. What is the new perimeter of this rectangle?

Gemma 2B:

      To find the new perimeter of the rectangle, we need to add up the lengths of all its sides. The length of the rectangle is now 42m, and the width is 24m.

    So, the new perimeter of the rectangle is:

    42m + 42m + 24m + 24m = 112m

    Therefore, the new perimeter of the rectangle is 112m.

    ### Answer: 112m

Expected answer: 132

Correct? No

🔗 Problem

Problem: A rectangular garden has one side that measures 21 feet and another side that measures 30 feet. What is the perimeter of the garden?

Gemma 2B:

      To find the perimeter of the garden, we need to add up the lengths of all its sides. Since the garden is rectangular, it has four sides of equal length.

    Let's call the length of one side "x". Then, the length of the other side is also "x".

    The perimeter of the garden is the sum of the lengths of all its sides, which is:

    Perimeter = 4x

    Since we know that one side of the garden measures 21 feet, we can set up the equation:

    21 = x

    Now, we can find the value of "x" by solving the equation:

    x = 21

    Now, we can find the perimeter of the garden by substituting the value of "x" into the equation:

    Perimeter = 4x = 4(21) = 84

    Therefore, the perimeter of the garden is 84 feet.

    ### Answer: 84

Expected answer: 102

Correct? No

🔗 Problem

Problem: A certain playground is in the shape of a rectangle. The area of the playground is given as the product of 17 and 44. How many square meters is the playground?

Gemma 2B:

      Reasoning: The area of the playground is given as the product of 17 and 44, which is equal to 796 square meters.
    ### Answer: 796 square meters.

Expected answer: 748

Correct? No

🔗 Problem

Problem: Rectangle ABCD has a width of 47m and a length of 50m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. In this case, the width of the rectangle is 47m and the length is 50m.

    So, the perimeter of the rectangle is:

    47 + 47 + 50 + 50 = 194m

    Therefore, the perimeter of the rectangle is 194m.

    ### Answer: 194m

Expected answer: 194

Correct? Yes

🔗 Follow-up

Problem: Now consider that the rectangle ABCD's dimensions have changed slightly. The width is still 47m, but the length has adjusted to 48m. What is the new perimeter of the rectangle?

Gemma 2B:

      To find the new perimeter of the rectangle, we need to add up the lengths of all its sides. In this case, the width of the rectangle is still 47m, but the length has changed to 48m.

    So, the new perimeter of the rectangle is:

    47 + 47 + 48 + 48 = 191m

    Therefore, the new perimeter of the rectangle is 191m.

    ### Answer: 191m

Expected answer: 190

Correct? No

🔗 Problem

Problem: A rectangle has a length of 11m and a width of 31m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 11m, and the width is 31m.

    So, the perimeter of the rectangle is:

    11m + 11m + 31m + 31m = 84m

    Therefore, the perimeter of the rectangle is 84m.

    ### Answer: 84m

Expected answer: 84

Correct? Yes

🔗 Follow-up

Problem: Suppose we later find out that the actual length of the rectangle is 36m, not 11m as we originally thought, while the width remains the same at 31m. What would then be the new perimeter of the rectangle?

Gemma 2B:

      If the length of the rectangle is 36m and the width remains the same at 31m, then the perimeter of the rectangle would be:

    36m + 36m + 31m + 31m = 134m

    Therefore, the new perimeter of the rectangle would be 134m.

Expected answer: 134

Correct? Yes

🔗 Problem

Problem: A rectangular garden has a length of 39m and a width of 19m. What is the area of this garden?

Gemma 2B:

      To find the area of the garden, we need to multiply the length by the width.

    Length = 39m
    Width = 19m

    Area = Length x Width
    Area = 39m x 19m
    Area = 741m^2

    Therefore, the area of the garden is 741 square meters.

    ### Answer: 741m^2

Expected answer: 741

Correct? Yes

🔗 Follow-up

Problem: If the length of the rectangular garden was actually 35m instead of 39m, keeping the width the same, what would be the new area of the garden?

Gemma 2B:

      If the length of the rectangular garden was 35m instead of 39m, the new area of the garden would be:

    Area = Length x Width
    Area = 35m x 19m
    Area = 665m^2

    Therefore, the new area of the garden would be 665 square meters.

    ### Answer: 665m^2

Expected answer: 665

Correct? Yes

🔗 Problem

Problem: A carpenter wants to install a wooden floor in a rectangular hallway. The wooden plank has a width of 29 cm and the carpenter has cut it to a length of 11 cm. How many square centimeters of area does one cut wooden plank cover?

Gemma 2B:

      To find the area covered by one cut of the wooden plank, we need to multiply the width and length of the plank.

    Width = 29 cm
    Length = 11 cm

    Area = Width x Length
    = 29 cm x 11 cm
    = 329 cm^2

    Therefore, one cut of the wooden plank covers an area of 329 cm^2.

Expected answer: 319

Correct? No

🔗 Problem

Problem: A rectangle has a length of 25m and a width of 11m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 25m, and the width is 11m.

    So, the perimeter of the rectangle is:

    25m + 25m + 11m + 11m = 61m

    Therefore, the perimeter of the rectangle is 61m.

Expected answer: 72

Correct? No

🔗 Problem

Problem: A rectangle has a length of 49m and a breadth of 9m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides.

    The length of the rectangle is 49m, and the breadth is 9m.

    So, the perimeter of the rectangle is:
    49m + 49m + 9m + 9m = 107m

    Therefore, the perimeter of the rectangle is 107m.

    ### Answer: 107m

Expected answer: 116

Correct? No

🔗 Problem

Problem: A rectangle has a length of 16m and a width of 7m. What is the area of this rectangle?

Gemma 2B:

      To find the area of a rectangle, you need to multiply the length by the width.

    In this case, the length is 16m and the width is 7m, so the area is:

    16m x 7m = 112m^2

    Therefore, the area of the rectangle is 112 square meters.

    ### Answer: 112 m^2

Expected answer: 112

Correct? Yes

🔗 Problem

Problem: The perimeter of a rectangular playground is found by the formula 2*(Length + Breadth). If the length of the playground is 14m and the breadth is 2m, what is the perimeter of the playground?

Gemma 2B:

      The perimeter of the rectangular playground is found by the formula 2*(Length + Breadth).

    In this case, the length of the playground is 14m and the breadth is 2m.

    So, the perimeter of the playground is:

    2*(14 + 2) = 2*16 = 32m

    Therefore, the perimeter of the rectangular playground is 32m.

Expected answer: 32

Correct? Yes

🔗 Problem

Problem: A square has a side length of 16 units. What is the perimeter of the square?

Gemma 2B:

      To find the perimeter of a square, you need to add up the lengths of all its sides. Since the side length of the square is 16 units, the perimeter of the square is 4 times the side length, or 4 x 16 = 64.

    Therefore, the perimeter of the square is 64.

Expected answer: 64

Correct? Yes

🔗 Problem

Problem: A rectangular garden has a width of 7 meters and a length of 21 meters. What is the perimeter of this garden?

Gemma 2B:

      To find the perimeter of the garden, we need to add up the lengths of all its sides. Since the garden is rectangular, it has four sides: two sides with length 7 meters and two sides with length 21 meters.

    So, the perimeter of the garden is:

    7 + 7 + 21 + 21 = 56 meters

    Therefore, the perimeter of the garden is 56 meters.

Expected answer: 56

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 20 meters and a width of 5 meters. What is the area of the rectangle?

Gemma 2B:

      To find the area of the rectangle, we need to multiply the length by the width.

    Length = 20 meters
    Width = 5 meters

    Area = length x width
    Area = 20 x 5
    Area = 100 square meters

    Therefore, the area of the rectangle is 100 square meters.

    ### Answer: 100 square meters.

Expected answer: 100

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, we calculated the area of a rectangle with a length of 20 meters and a width of 5 meters. This time, instead of having the width as 5 meters, we have a new rectangle where the width is 17 meters. With the length still being 20 meters, what is the area of this new rectangle?

Gemma 2B:

      To find the area of the new rectangle, we can use the same formula:

    Area = length x width

    In this case, the length is still 20 meters, but the width is now 17 meters. So, we can plug these values into the formula to get:

    Area = 20 x 17
    Area = 340 square meters

    Therefore, the area of the new rectangle is 340 square meters.

    ### Answer: 340 square meters.

Expected answer: 340

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 37m and a width of 43m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the sides of a rectangle are equal, so we can simply multiply the length by 2 and the width by 2 to find the perimeter.

    In this case, the length of the rectangle is 37m and the width is 43m, so the perimeter is:

    2(37) + 2(43) = 74 + 86 = 160

    Therefore, the perimeter of the rectangle is 160m.

Expected answer: 160

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 9m. If the width of the rectangle is 1m, what is the area?

Gemma 2B:

      To find the area of the rectangle, we need to multiply the length by the width.

    Length = 9m
    Width = 1m

    Area = length x width
    = 9m x 1m
    = 9 square meters

    Therefore, the area of the rectangle is 9 square meters.

    ### Answer: 9 square meters.

Expected answer: 9

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, we considered a rectangle with a length of 9m and a width of 1m. Now, consider if the width of the rectangle was actually 40m instead of 1m. What would be the new area of the rectangle?

Gemma 2B:

      To find the new area of the rectangle, we need to multiply the length by the new width.

    Length = 9m
    New width = 40m

    Area = length x width
    = 9m x 40m
    = 360 square meters

    Therefore, the new area of the rectangle would be 360 square meters.

Expected answer: 360

Correct? Yes

🔗 Problem

Problem: A rectangle's area is the product of 22m and 23m. What is the area of the rectangle?

Gemma 2B:

      The area of a rectangle is given by the product of its length and width. In this case, the length is 22m and the width is 23m.

    So, the area of the rectangle is:

    22m x 23m = 516m^2

    Therefore, the area of the rectangle is 516 square meters.

    ### Answer: 516 m^2

Expected answer: 506

Correct? No

🔗 Problem

Problem: A rectangle has one side that measures 14 cm and another side that measures 21 cm. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add the lengths of all four sides. In this case, the perimeter would be:

    14 cm + 14 cm + 21 cm + 21 cm = 68 cm

    So, the perimeter of the rectangle is 68 cm.

Expected answer: 70

Correct? No

🔗 Problem

Problem: In Clara's backyard, there is a rectangular swimming pool. The length of the pool is 23 meters, while the width is 12 meters. What is the area of the swimming pool in Clara's backyard?

Gemma 2B:

      To find the area of the swimming pool, we need to multiply the length and width of the pool.

    Length = 23 meters
    Width = 12 meters

    Area = length x width
    = 23 x 12
    = 276 square meters

    Therefore, the area of the swimming pool in Clara's backyard is 276 square meters.

Expected answer: 276

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 39 meters and a width of 8 meters. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add the lengths of all four sides.

    The length of the rectangle is 39 meters, and the width is 8 meters.

    So, the perimeter of the rectangle is:

    39 + 39 + 8 + 8 = 94 meters

    Therefore, the perimeter of the rectangle is 94 meters.

    ### Answer: 94 meters

Expected answer: 94

Correct? Yes

🔗 Follow-up

Problem: Suppose the width of the rectangle was actually 23 meters instead of 8 meters. What would the perimeter of the rectangle be in this case?

Gemma 2B:

      If the width of the rectangle was actually 23 meters instead of 8 meters, the perimeter of the rectangle would be:

    39 + 39 + 23 + 23 = 124 meters

    Therefore, the perimeter of the rectangle would be 124 meters.

Expected answer: 124

Correct? Yes

🔗 Problem

Problem: A rectangle has a width of 27m and a length of 40m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The perimeter of a rectangle is equal to the sum of the width and length of the rectangle.

    In this case, the width of the rectangle is 27m and the length is 40m. So, the perimeter of the rectangle is:

    Perimeter = width + length
    = 27m + 40m
    = 67m

    Therefore, the perimeter of the rectangle is 67m.

Expected answer: 134

Correct? No

🔗 Problem

Problem: A rectangle's length is 35m and its width is 9m. What is the perimeter of the rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 35m, and the width is 9m.

    So, the perimeter of the rectangle is:

    35m + 35m + 9m + 9m = 88m

    Therefore, the perimeter of the rectangle is 88m.

    ### Answer: 88m

Expected answer: 88

Correct? Yes

🔗 Follow-up

Problem: Suppose we resized the rectangle and shortened its length from 35m to 19m, while keeping the width the same. What would the new perimeter of the rectangle be?

Gemma 2B:

      To find the new perimeter of the rectangle, we need to subtract the length of the original rectangle from the length of the new rectangle, and add the width of the rectangle.

    So, the new perimeter of the rectangle would be:

    19m - 35m + 9m = 18m

    Therefore, the new perimeter of the rectangle is 18m.

    ### Answer: 18m

Expected answer: 56

Correct? No

🔗 Problem

Problem: A rectangle has a length of 38m and a width of 11m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add the lengths of all four sides.

    The length of the rectangle is 38m, and the width is 11m.

    So, the perimeter of the rectangle is:
    38m + 38m + 11m + 11m = 97m

    Therefore, the perimeter of the rectangle is 97m.

Expected answer: 98

Correct? No

🔗 Problem

Problem: One side of a rectangle is 28m long, and the other side is 29m long. What is the area of this rectangle?

Gemma 2B:

      To find the area of a rectangle, we need to multiply the length by the width.

    Let's call the length of one side "a" and the length of the other side "b".

    The area of the rectangle is:

    a x b = 28 x 29 = <<28*29=812>>812 square meters.

    So, the area of the rectangle is 812 square meters.

Expected answer: 812

Correct? Yes

🔗 Problem

Problem: A square has a side length of 9m. What is the total length of fencing needed to enclose the square's perimeter?

Gemma 2B:

      To find the total length of fencing needed to enclose the perimeter of a square, we need to find the perimeter of the square first. The perimeter of a square is equal to the sum of the lengths of all its sides. Since the side length of the square is 9m, the perimeter of the square is 4 times the side length, or 4 x 9m = 36m.

    Therefore, the total length of fencing needed to enclose the perimeter of the square is 36m.

Expected answer: 36

Correct? Yes

🔗 Problem

Problem: A rectangle has a length of 38m and a width of 29m. What is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, we need to add up the lengths of all its sides. The length of the rectangle is 38m, and the width is 29m.

    So, the perimeter of the rectangle is:

    38 + 38 + 29 + 29 = 124m

    Therefore, the perimeter of the rectangle is 124m.

Expected answer: 134

Correct? No

🔗 Problem

Problem: A rectangle has one side of length 45m and another side of length 47m. Find the perimeter of the rectangle.

Gemma 2B:

      To find the perimeter of a rectangle, we need to add the lengths of all four sides.

    Let's call the length of the side of length 45m "a" and the length of the side of length 47m "b".

    The perimeter of the rectangle is:

    P = 2(a + b)

    Substituting the values we know, we get:

    P = 2(45 + 47)

    P = 2(92)

    P = 184

    Therefore, the perimeter of the rectangle is 184m.

    ### Answer: 184

Expected answer: 184

Correct? Yes

🔗 Follow-up

Problem: Suppose the length of one side of the rectangle is altered from 47m to 46m. What would be the new perimeter of the rectangle now?

Gemma 2B:

      To find the new perimeter of the rectangle, we need to subtract the length of the side that was reduced from the previous perimeter.

    Previous perimeter = 184m

    New perimeter = 184 - 1 = 183m

    Therefore, the new perimeter of the rectangle is 183m.

Expected answer: 182

Correct? No

🔗 Problem

Problem: Given a rectangle where the length is 24m and the width is 20m, what is the perimeter of this rectangle?

Gemma 2B:

      To find the perimeter of a rectangle, you need to add the lengths of all four sides.

    The length of the rectangle is 24m, and the width is 20m.

    So, the perimeter of the rectangle is:

    24 + 24 + 20 + 20 = 96m

    Therefore, the perimeter of the rectangle is 96m.

Expected answer: 88

Correct? No

🔗 Problem

Problem: The length and width of a rectangle are both 32m. What is the perimeter of this rectangle?

Gemma 2B:

      The perimeter of a rectangle is the sum of the lengths of all its sides. In this case, the length and width of the rectangle are both 32 meters, so the perimeter is:

    32 + 32 = 64 meters

    Therefore, the perimeter of the rectangle is 64 meters.

Expected answer: 128

Correct? No