int main(int argc, char* argv[])
{
	int n,a[5],b[4],c[3],d[2];
	int n1,n2,n3,n4;
	scanf("%d",&n);
	if(n/10000!=0)
	{a[0]=n/10000;
	a[1]=(n-a[0]*10000)/1000;
	a[2]=(n-a[0]*10000-a[1]*1000)/100;
	a[3]=(n-a[0]*10000-a[1]*1000-a[2]*100)/10;
	a[4]=n-a[0]*10000-a[1]*1000-a[2]*100-a[3]*10;
	n1=a[4]*10000+a[3]*1000+a[2]*100+a[1]*10+a[0];
	printf("%d\n",n1);
	}
	if(n/10000==0&&n/1000!=0)
	{b[0]=n/1000;
	b[1]=(n-b[0]*1000)/100;
	b[2]=(n-b[0]*1000-b[1]*100)/10;
	b[3]=n-b[0]*1000-b[1]*100-b[2]*10;
    n2=b[3]*1000+b[2]*100+b[1]*10+b[0];
	printf("%d\n",n2);
	}
	if(n/10000==0&&n/1000==0&&n/100!=0)
	{c[0]=n/100;
	c[1]=(n-c[0]*100)/10;
	c[2]=n-c[0]*100-c[1]*10;
	n3=c[2]*100+c[1]*10+c[0];
	printf("%d\n",n3);
	}
	if(n/10000==0&&n/1000==0&&n/100==0&&n/10!=0)
	{d[0]=n/10;
	d[1]=n-d[0]*10;
	n4=d[1]*10+d[0];
	printf("%d\n",n4);
	}
	if(n/10000==0&&n/1000==0&&n/100==0&&n/10==0)
	{printf("%d\n",n);}
	return 0;
}