int main()
{
	int n,a,b,c,d,e,f;
	scanf("%d/n",&n);
	a=n/100;
	b=(n%100)/50;
	c=(n-100*a-50*b)/20;
	d=(n-100*a-50*b-20*c)/10;
	e=(n-100*a-50*b-20*c-10*d)/5;
	f=(n-100*a-50*b-20*c-10*d)%5;
	printf("%d\n%d\n%d\n%d\n%d\n%d\n",a,b,c,d,e,f);
	return 0;
}


