{"task_id": "HumanEval/0", "completion": "from typing import List\n\n\nfrom typing import List, Tuple\n\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\"\n    Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n    Args:\n    numbers (List[float]): A list of float numbers\n    threshold (float): The minimum distance between two numbers to be considered close\n\n    Returns:\n    bool: True if any two numbers in the list are closer than the given threshold, False otherwise\n    \"\"\"\n    # Sort the list of numbers\n    numbers.sort()\n    \n    # Initialize the minimum and maximum numbers in the list\n    min_num, max_num = find_furthest_elements(numbers)\n    \n    # Check if the difference between the minimum and maximum numbers is less than the threshold\n    return max_num - min_num <= threshold\n\ndef find_furthest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\"\n    Extract two float numbers from the given array (at minimum contains two) that possess the maximum numerical difference. \n    Remember to present them in ascending order (minor, major).\n\n    Args:\n    numbers (List[float]): A list of float numbers\n\n    Returns:\n    Tuple[float, float]: A tuple containing the two numbers with the maximum difference\n    \"\"\"\n    # Sort the list of numbers\n    numbers.sort()\n    \n    # Initialize the minimum and maximum numbers in the list\n    return numbers[0], numbers[-1]\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/1", "completion": "from typing import List\n\n\ndef separate_paren_groups(paren_string: str) -> list:\n    \"\"\"\n    This function is designed to process a string that contains multiple nested groups of round, square, and curly brackets, which are frequently encountered in mathematical computations. \n    Your task is to segregate these bracket groups into separate string segments and return them in the form of a list.\n    Each distinct group is balanced (every opening brace has a corresponding closing brace) and does not nest within another group.\n    Disregard any white spaces present in the input string.\n    >>> separate_paren_groups(' ( ) (( )) {[()]} (( )( )) ')\n    ['()', '(())', '{[()]}', '(()())']\n    \"\"\"\n    # remove white spaces\n    paren_string = paren_string.replace(\" \", \"\")\n    start = ['(', '{', '[']\n    end = [')', '}', ']']\n    groups = []\n    temp_string = ''\n    counter = 0\n\n    for char in paren_string:\n        if char in start:\n            counter += 1\n            temp_string += char\n        elif char in end:\n            counter -= 1\n            temp_string += char\n            if counter == 0:\n                groups.append(temp_string)\n                temp_string = ''\n    return groups\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/2", "completion": "\n\ndef truncate_number(number: float) -> float:\n    \"\"\"\n    Given a positive floating point number, it can be decomposed into\n    and integer part (largest integer smaller than given number) and decimals\n    (leftover part always smaller than 1).\n\n    Return the decimal part of the number.\n    >>> truncate_number(3.5)\n    0.5\n    \"\"\"\n    integer_part = int(number)\n    return number - integer_part\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/3", "completion": "from typing import List\n\n\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\"\n    You're provided with a set of banking account transactions which consist of \n    deposit and withdrawal actions, starting from a null balance. Your duty is to find \n    if at any stage the account balance dips below zero, in which case the function is \n    expected to return True. Otherwise, the requirement is that it should yield False.\n\n    Example usages:\n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n    \n    balance = 0\n    for op in operations:\n        balance += op\n        if balance < 0:\n            return True\n    return False\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/4", "completion": "from typing import List\n\n\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    # Calculate the mean of the given list of numbers\n    mean = sum(numbers) / len(numbers)\n    \n    # Calculate the absolute difference between each element and the mean\n    absolute_differences = [abs(num - mean) for num in numbers]\n    \n    # Calculate the mean of the absolute differences\n    mad = sum(absolute_differences) / len(absolute_differences)\n    \n    return mad\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/5", "completion": "from typing import List\n\n\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n    result = []\n    for i, num in enumerate(numbers):\n        if i > 0:\n            result.append(delimeter)\n        result.append(num)\n    return result\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/6", "completion": "from typing import List\n\n\nfrom typing import List\n\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\"\n    Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n    For each of the group, output the deepest level of nesting of parentheses.\n    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n    \n    :param paren_string: A string of nested parentheses separated by spaces\n    :return: A list of maximum nesting levels for each group of parentheses\n    \"\"\"\n    # separate groups of parentheses\n    groups = separate_paren_groups(paren_string)\n    \n    # calculate maximum nesting level for each group\n    result = []\n    for group in groups:\n        max_level = 0\n        level = 0\n        for char in group:\n            if char == '(':\n                level += 1\n                max_level = max(max_level, level)\n            elif char == ')':\n                level -= 1\n        result.append(max_level)\n    return result\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\"\n    This function is designed to process a string that contains multiple nested groups of round, square, and curly brackets, which are frequently encountered in mathematical computations. \n    Your task is to segregate these bracket groups into separate string segments and return them in the form of a list.\n    Each distinct group is balanced (every opening brace has a corresponding closing brace) and does not nest within another group.\n    Disregard any white spaces present in the input string.\n    >>> separate_paren_groups(' ( ) (( )) {[()]} (( )( )) ')\n    ['()', '(())', '{[()]}', '(()())']\n    \"\"\"\n    # remove white spaces\n    paren_string = paren_string.replace(\" \", \"\")\n    start = ['(', '{', '[']\n    end = [')', '}', ']']\n    groups = []\n    temp_string = ''\n    counter = 0\n\n    for char in paren_string:\n        if char in start:\n            counter += 1\n            temp_string += char\n        elif char in end:\n            counter -= 1\n            temp_string += char\n            if counter == 0:\n                groups.append(temp_string)\n                temp_string = ''\n    return groups\n\n# Test the function\nprint(parse_nested_parens('(()()) ((())) () ((())()())'))  # Output: [2, 3, 1, 3]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/7", "completion": "from typing import List\n\n\nfrom typing import List\n\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\"\n    Filter an input list of strings only for ones that contain given substring\n    \n    Args:\n    strings (List[str]): A list of strings to filter\n    substring (str): The substring to search for\n    \n    Returns:\n    List[str]: A list of strings that contain the given substring\n    \"\"\"\n    \n    # Use list comprehension to filter the list of strings\n    # The 'if substring in string' condition checks if the substring is present in each string\n    # If it is, the string is included in the new list, otherwise it's not\n    return [string for string in strings if substring in string]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/8", "completion": "from typing import List, Tuple\n\n\nfrom typing import List, Tuple\n\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\"\n    For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n    Empty sum should be equal to 0 and empty product should be equal to 1.\n\n    Args:\n    numbers: A list of integers.\n\n    Returns:\n    A tuple of two integers, the sum and the product of the input list.\n    \"\"\"\n    # Initialize sum and product to 0 and 1 respectively, as per the problem statement\n    total_sum = 0\n    total_product = 1\n    \n    # Iterate over each number in the list\n    for num in numbers:\n        # Add the current number to the total sum\n        total_sum += num\n        # Multiply the current number with the total product\n        total_product *= num\n    \n    # Return the total sum and total product as a tuple\n    return total_sum, total_product\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/9", "completion": "from typing import List, Tuple\n\n\nfrom typing import List, Tuple\n\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n    in the sequence.\n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n    result = []\n    max_so_far = float('-inf')\n    for num in numbers:\n        if num >= max_so_far:\n            max_so_far = num\n        result.append(max_so_far)\n    return result\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/10", "completion": "\n\ndef is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    \"\"\"\n    # Remove non-alphanumeric characters and convert to lower case\n    cleaned_string = ''.join(char.lower() for char in string if char.isalnum())\n    \n    # Find the longest palindromic postfix\n    for i in range(len(cleaned_string), 0, -1):\n        postfix = cleaned_string[-i:]\n        if is_palindrome(postfix):\n            break\n\n    # Find the prefix\n    prefix = cleaned_string[:-i]\n\n    # Return the palindrome\n    return cleaned_string + prefix[::-1]\n", "result": "failed: cannot access local variable 'i' where it is not associated with a value", "passed": false}
{"task_id": "HumanEval/11", "completion": "from typing import List\n\n\ndef string_xor(a: str, b: str) -> str:\n    # Convert the binary strings to integers\n    a = int(a, 2)\n    b = int(b, 2)\n    \n    # Conduct a binary exclusive OR operation on the inputs\n    result = a ^ b\n    \n    # Format the result as a binary string and return it\n    return format(result, 'b')\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/12", "completion": "from typing import List, Optional\n\n\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\"\n    Return the longest string in a list. If more than one string has the same \n    length, return the first one. If the list is empty, return None.\n\n    Examples:\n\n    >>> longest([])\n    >>>\n\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n    if not strings: return None\n    return max(strings, key=len)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/13", "completion": "\n\ndef greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\"\n    Return the highest common factor of the two integers a and b.\n    It uses Euclidean Algorithm to find the GCD.\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n    while b!= 0:\n        a, b = b, a % b\n    return a\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/14", "completion": "from typing import List\n\n\ndef all_prefixes(string: str) -> list:\n    \"\"\"\n    Return list of all prefixes from shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n    return [prefix for prefix, _ in all_prefixes_with_lengths(string)]\n", "result": "failed: name 'all_prefixes_with_lengths' is not defined", "passed": false}
{"task_id": "HumanEval/15", "completion": "\n\ndef string_sequence(n: int) -> str:\n    \"\"\" Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n    # Initialise an empty list to hold the sequence\n    sequence = []\n    # Iterate from 0 to n inclusive\n    for i in range(n + 1):\n        # Add each number to the sequence list, converting it into a string\n        sequence.append(str(i))\n    # Join all elements in the list into a string separated by spaces and return\n    return''.join(sequence)\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/16", "completion": "\n\ndef count_distinct_characters(string: str) -> int:\n    \"\"\"\n    Given a string, find out how many distinct characters (regardless of case) does it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n    # Convert the string to lower case to ignore case sensitivity\n    string = string.lower()\n    # Use a set to store unique characters\n    unique_chars = set(string)\n    # The number of distinct characters is the size of the set\n    return len(unique_chars)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/17", "completion": "from typing import List\n\n\ndef parse_music(music_string: str) -> list[int]:\n    notes_map = {\n        'o': 4,\n        'o|': 2,\n        '.|': 1\n    }\n    notes = music_string.split()\n    beats = [notes_map[note] for note in notes]\n    return beats\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/18", "completion": "\n\ndef how_many_times(string: str, substring: str) -> int:\n    \"\"\"Determine the frequency of a given substring in the initial string. Include overlapping cases.\n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n    count = 0\n    for i in range(len(string) - len(substring) + 1):\n        if string[i:i+len(substring)] == substring:\n            count += 1\n    return count\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/19", "completion": "from typing import List\n\n\ndef sort_numbers(numbers: str) -> str:\n    decimal_words = {'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight', 'nine'}\n    american_number_system = {'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5,'six': 6,'seven': 7, 'eight': 8, 'nine': 9}\n\n    numbers_list = numbers.split()\n    numbers_dict = {word: american_number_system[word] for word in numbers_list if word in decimal_words}\n    sorted_numbers = sorted(numbers_dict.items(), key=lambda x: x[1])\n\n    return''.join([word for word, num in sorted_numbers])\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/20", "completion": "from typing import List, Tuple\n\n\nfrom typing import List, Tuple\n\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    # First, sort the list of numbers\n    numbers.sort()\n    \n    # Initialize the minimum difference and the pair of closest numbers\n    min_diff = float('inf')\n    closest_pair = ()\n    \n    # Iterate over the sorted list to find the pair with the minimum difference\n    for i in range(len(numbers) - 1):\n        # Calculate the difference between the current number and the next one\n        diff = numbers[i + 1] - numbers[i]\n        \n        # If the difference is smaller than the current minimum difference, update the minimum difference and the closest pair\n        if diff < min_diff:\n            min_diff = diff\n            closest_pair = (numbers[i], numbers[i + 1])\n    \n    return closest_pair\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/21", "completion": "from typing import List\n\n\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\"\n    Given list of numbers (of at least two elements), apply a linear transform to that list,\n    such that the smallest number will become 0 and the largest will become 1\n\n    Args:\n        numbers (List[float]): A list of numbers\n\n    Returns:\n        List[float]: The rescaled list of numbers\n    \"\"\"\n    # First, we need to find the smallest and largest numbers in the list\n    min_val, max_val = find_furthest_elements(numbers)\n    \n    # Then, we calculate the range of the numbers\n    range_val = max_val - min_val\n    \n    # If the range is zero, all numbers are the same, so we return a list of zeros\n    if range_val == 0:\n        return [0.0] * len(numbers)\n    \n    # Otherwise, we apply the linear transform to each number in the list\n    # We subtract the minimum value from each number to shift the range to [0, range_val)\n    # Then, we divide by the range to scale the range to [0, 1)\n    return [(num - min_val) / range_val for num in numbers]\n", "result": "failed: name 'find_furthest_elements' is not defined", "passed": false}
{"task_id": "HumanEval/22", "completion": "from typing import List, Any\n\n\nfrom typing import List, Any\n\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\"\n    Filter given list of any python values only for integers\n    \n    Args:\n        values (List[Any]): A list of any python values\n    \n    Returns:\n        List[int]: A list of integers from the input list\n    \"\"\"\n    # Use list comprehension to create a new list that includes only the integers from the input list\n    return [value for value in values if isinstance(value, int)]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/23", "completion": "\n\ndef strlen(string: str) -> int:\n    \"\"\"\n    Return length of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n    return len(string)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/24", "completion": "\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/25", "completion": "from typing import List\n\n\nfrom typing import List\nimport math\n\ndef factorize(n: int) -> List[int]:\n    \"\"\"\n    Return list of prime factors of given integer in the order from smallest to largest.\n    Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.\n    Input number should be equal to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n    factors = []\n    freq = {}\n    \n    # Prime factorization\n    while n % 2 == 0:\n        factors.append(2)\n        n = n / 2\n    for i in range(3,int(math.sqrt(n))+1,2):\n        while n % i== 0:\n            factors.append(i)\n            n = n / i \n    if n > 2:\n        factors.append(int(n))\n\n    # Count the frequency of each factor\n    for factor in factors:\n        if factor not in freq:\n            freq[factor] = 1\n        else:\n            freq[factor] += 1\n\n    # Sort factors by frequency and value\n    sorted_factors = sorted(freq.items(), key=lambda x: (x[1], x[0]))\n\n    # Create the final list of factors\n    result = []\n    for factor, count in sorted_factors:\n        result.extend([factor] * count)\n\n    return result\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/26", "completion": "from typing import List\n\n\nfrom typing import List\n\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\"Remove duplicates while maintaining order.\n    Given a list of integers, remove any number that occurs more than once,\n    while keeping the order of the remaining numbers the same as the original list.\n    Determine the number of times each number occurs, and remove the numbers that occur more than once.\n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n    count_map = {}\n    result = []\n    for num in numbers:\n        if num not in count_map:\n            count_map[num] = 1\n            result.append(num)\n        else:\n            count_map[num] += 1\n            if count_map[num] > 1 and num in result:\n                result.remove(num)\n    return result\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/27", "completion": "\n\ndef flip_case(string: str) -> str:\n    \"\"\"\n    For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n    \"\"\"\n    transformed_str = \"\"\n    for char in string:\n        if char.isalpha():\n            # Swap case\n            new_char = char.swapcase()\n        else:\n            # Leave non-alphabetic characters as is\n            new_char = char\n        transformed_str += new_char\n    return transformed_str\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/28", "completion": "from typing import List\n\n\ndef concatenate(strings: List[str]) -> str:\n    \"\"\"\n    Concatenate list of strings into a single string\n\n    Args:\n        strings (List[str]): A list of strings to be concatenated\n\n    Returns:\n        str: A single string that is the concatenation of all strings in the input list\n    \"\"\"\n    # Use the join() method to concatenate all the strings in the input list\n    # The join() method concatenates all the strings in the list and returns a single string\n    return ''.join(strings)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/29", "completion": "from typing import List\n\n\nfrom typing import List\n\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\"\n    Filter an input list of strings only for ones that start with a given prefix.\n\n    Args:\n        strings (List[str]): The list of strings to filter.\n        prefix (str): The prefix to filter by.\n\n    Returns:\n        List[str]: The filtered list of strings.\n    \"\"\"\n    # Use a list comprehension to create a new list that includes only the strings that start with the given prefix\n    return [s for s in strings if s.startswith(prefix)]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/30", "completion": "\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/31", "completion": "\n\ndef is_prime(n):\n    if n < 2:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/32", "completion": "import math\n\n\nimport math\n\ndef poly(xs: list, x: float):\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[1] * x^2 +.... xs[n] * x^n\n    \"\"\"\n    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])\n\n\ndef find_zero(xs: list):\n    \"\"\" xs are coefficients of a polynomial.\n    find_zero find x such that poly(x) = 0.\n    find_zero returns only only zero point, even if there are many.\n    Moreover, find_zero only takes list xs having even number of coefficients\n    and largest non zero coefficient as it guarantees\n    a solution.\n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n    if len(xs) % 2!= 0:\n        return \"Invalid polynomial\"\n    if xs[0] == 0:\n        return \"Invalid polynomial\"\n    n = len(xs)\n    x = 0\n    for i in range(1, n, 2):\n        x = -xs[i] / (xs[0] * x + xs[i+1])\n    return x\n\n# Test cases\nprint(round(find_zero([1, 2]), 2))  # f(x) = 1 + 2x\nprint(round(find_zero([-6, 11, -6, 1]), 2))  # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n", "result": "failed: list index out of range", "passed": false}
{"task_id": "HumanEval/33", "completion": "\n\ndef sort_third(l: list):\n    sublist = [val for i, val in enumerate(l) if i % 3 == 0]\n    sublist.sort()\n\n    new_list = l.copy()\n    index = 0\n    for i, val in enumerate(new_list):\n        if i % 3 == 0:\n            new_list[i] = sublist[index]\n            index += 1\n\n    return new_list\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/34", "completion": "\n\ndef unique(l: list):\n    \"\"\"\n    Return sorted unique elements in a list\n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n    return sorted(set(l))\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/35", "completion": "\n\ndef max_element(l: list):\n    \"\"\"Return maximum element in the list.\"\"\"\n    positive_numbers = [num for num in l if num > 0]\n    return max(positive_numbers) if positive_numbers else None\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/36", "completion": "\n\ndef fizz_buzz(n: int):\n    count = 0\n    for i in range(1, n):\n        if i % 11 == 0 or i % 13 == 0:\n            str_i = str(i)\n            count += str_i.count('7')\n    return count\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/37", "completion": "\n\ndef sort_even(l: list):\n    even = sorted([x for i, x in enumerate(l) if i % 2 == 0])\n    return [x if i % 2!= 0 else even[i // 2] for i, x in enumerate(l)]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/38", "completion": "\n\ndef decode_cyclic(s: str):\n    \"\"\"\n    takes as input string encoded with encode_cyclic function. Returns decoded string.\n    \"\"\"\n    # split string to groups. Each of length 3.\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # reverse the cycling in each group. Unless group has fewer elements than 3.\n    groups = [(group[-1] + group[:-1]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/39", "completion": "\n\ndef get_fibonacci(n):\n    fib_series = [0, 1]\n    while len(fib_series) < n:\n        fib_series.append(fib_series[-1] + fib_series[-2])\n    return fib_series\n\ndef is_prime(num):\n    if num < 2:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\n\ndef prime_fib(n):\n    fib_series = get_fibonacci(n)\n    prime_fib = [num for num in fib_series if is_prime(num)]\n    return prime_fib[-1]\n", "result": "failed: list index out of range", "passed": false}
{"task_id": "HumanEval/40", "completion": "\n\ndef triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zero takes a list of integers as an input.\n    it returns True if there are three distinct elements in the list that\n    sum to zero, and False otherwise.\n    \"\"\"\n    for i in range(len(l)):\n        for j in range(i + 1, len(l)):\n            for k in range(j + 1, len(l)):\n                if l[i] + l[j] + l[k] == 0 and len(set([l[i], l[j], l[k]])) == 3:\n                    return True\n    return False\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/41", "completion": "\n\ndef car_race_collision(n: int) -> int:\n    \"\"\"\n    This function calculates the number of collisions in a car race where n cars are driving left to right and n cars are driving right to left.\n    \n    The function uses the concept of sweep line to solve the problem efficiently.\n    \n    :param n: The number of cars in each lane\n    :return: The number of collisions\n    \"\"\"\n    \n    # Initialize a list to store the start and end points of all cars\n    points = []\n    \n    # Add the start points of all cars moving left to right\n    for i in range(n):\n        points.append((0, i, 1))  # (time, car_id, direction)\n    \n    # Add the end points of all cars moving left to right\n    for i in range(n):\n        points.append((1, i, 1))\n    \n    # Add the start points of all cars moving right to left\n    for i in range(n):\n        points.append((0, i + n, -1))  # (time, car_id, direction)\n    \n    # Add the end points of all cars moving right to left\n    for i in range(n):\n        points.append((1, i + n, -1))\n    \n    # Sort the points based on the time\n    points.sort()\n    \n    # Initialize the number of collisions and the current end time\n    collisions = 0\n    end_time = 0\n    \n    # Initialize a set to store the cars that are currently moving\n    moving_cars = set()\n    \n    # Iterate over the points\n    for point in points:\n        # If the car is moving to the right, add it to the set of moving cars\n        if point[2] == 1:\n            moving_cars.add(point[1])\n        # If the car is moving to the left, remove it from the set of moving cars\n        else:\n            moving_cars.remove(point[1])\n        \n        # If the current time is greater than the end time, update the end time\n        if point[0] > end_time:\n            end_time = point[0]\n        \n        # If there are cars moving to the right and cars moving to the left, there will be a collision\n        if len(moving_cars) > 0:\n            collisions += len(moving_cars)\n    \n    return collisions\n", "result": "failed: 2", "passed": false}
{"task_id": "HumanEval/42", "completion": "\n\ndef incr_list(l: list):\n    return [num + 1 for num in l]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/43", "completion": "\n\ndef pairs_sum_to_zero(l):\n    if len(l) < 2:\n        return False\n\n    seen = set()\n    for num in l:\n        if -num in seen:\n            return True\n        seen.add(num)\n\n    return False\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/44", "completion": "\n\ndef change_base(x: int, base: int):\n    if x == 0:\n        return '0'\n    result = ''\n    while x > 0:\n        x, remainder = divmod(x, base)\n        result = str(remainder) + result\n    return result\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/45", "completion": "\n\ndef triangle_area(a, h):\n    \"\"\"Given length of a side and height, return the triangle's area.\n    >>> triangle_area(5, 3)\n    7.5\n    \"\"\"\n    return 0.5*a*h\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/46", "completion": "\n\ndef fib4(n: int):\n    \"\"\"\n    This function computes the n-th element of the Fib4 number sequence.\n    The Fib4 number sequence is a sequence similar to the Fibbonacci sequence that's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    \"\"\"\n    if n == 0:\n        return 0\n    elif n == 1:\n        return 0\n    elif n == 2:\n        return 2\n    elif n == 3:\n        return 0\n    else:\n        memo = {0: 0, 1: 0, 2: 2, 3: 0}\n        for i in range(4, n + 1):\n            memo[i] = memo[i-1] + memo[i-2] + memo[i-3] + memo[i-4]\n        return memo[n]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/47", "completion": "\n\ndef quickSelect(lst, start, end, k):\n    if start == end:\n        return lst[start]\n    pivot = partition(lst, start, end)\n    if k == pivot:\n        return lst[k]\n    elif k < pivot:\n        return quickSelect(lst, start, pivot - 1, k)\n    else:\n        return quickSelect(lst, pivot + 1, end, k)\n\ndef partition(lst, start, end):\n    pivot = lst[end]\n    i = start - 1\n    for j in range(start, end):\n        if lst[j] < pivot:\n            i += 1\n            lst[i], lst[j] = lst[j], lst[i]\n    lst[i + 1], lst[end] = lst[end], lst[i + 1]\n    return i + 1\n\ndef median(lst):\n    length = len(lst)\n    if length % 2 == 0:\n        return (quickSelect(lst, 0, length - 1, length // 2 - 1) + quickSelect(lst, 0, length - 1, length // 2)) / 2\n    else:\n        return quickSelect(lst, 0, length - 1, length // 2)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/48", "completion": "\n\ndef is_palindrome(text: str) -> bool:\n    \"\"\"\n    Checks if given string is a palindrome\n\n    Args:\n        text (str): The input string to be checked\n\n    Returns:\n        bool: True if the string is a palindrome, False otherwise\n    \"\"\"\n    return text == text[::-1]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/49", "completion": "\n\nimport math\n\ndef modp(n: int, p: int):\n    \"\"\"\n    Return 2^n modulo p (be aware of numerics).\n    \"\"\"\n    # If p is a prime number and n is not zero, we can use Fermat's Little Theorem\n    if is_prime(p) and n!= 0:\n        # Fermat's Little Theorem states that if p is a prime number and a is an integer not divisible by p, then a^(p-1) \u2261 1 (mod p)\n        # Therefore, we can reduce the power n by p-1 to avoid large numbers\n        n = n % (p - 1)\n        if n < 0:\n            n += p - 1  # Handle negative numbers\n    # Use the built-in pow function with three arguments to calculate the power and modulo at the same time\n    return pow(2, n, p)\n", "result": "failed: name 'is_prime' is not defined", "passed": false}
{"task_id": "HumanEval/50", "completion": "\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/51", "completion": "\n\ndef remove_vowels(text):\n    \"\"\"\n    remove_vowels is a function that takes string and returns string without vowels.\n    \"\"\"\n    if len(text) == 0:\n        return \"\"\n\n    first_char = text[0]\n\n    if first_char.lower() in \"aeiou\":\n        return remove_vowels(text[1:])\n    else:\n        return remove_vowels(text[1:]) + first_char\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/52", "completion": "\n\ndef below_threshold(l: list, t: int) -> bool:\n    for i in l:\n        if i >= t:\n            return False\n    return True\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/53", "completion": "\n\ndef add(x: int, y: int):\n    \"\"\"\n    Add two numbers x and y\n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n    return x + y\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/54", "completion": "\n\ndef same_chars(s0: str, s1: str):\n    \"\"\"\n    Check if two words have the same characters.\n    \"\"\"\n    # Removes all the special characters and convert to lower case\n    s0 = re.sub(r'\\W+', '', s0).lower()\n    s1 = re.sub(r'\\W+', '', s1).lower()\n\n    # Sorts the strings and compare them\n    return sorted(s0) == sorted(s1)\n", "result": "failed: name 're' is not defined", "passed": false}
{"task_id": "HumanEval/55", "completion": "\n\ndef fib(n: int):\n    if n <= 0:\n        return \"Input should be a positive integer\"\n    elif n == 1:\n        return 1\n    elif n == 2:\n        return 1\n    else:\n        a, b = 1, 1\n        for _ in range(2, n):\n            a, b = b, a + b\n        return b\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/56", "completion": "\n\ndef correct_bracketing(brackets: str):\n    s = []\n    for bracket in brackets:\n        if bracket == '<':\n            s.append('<')\n        else:\n            if not s:\n                return False\n            else:\n                s.pop()\n    if not s:\n        return True\n    else:\n        return False\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/57", "completion": "\n\ndef monotonic(l: list):\n    \"\"\"\n    Return True if list elements are monotonically increasing or decreasing.\n\n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n    increasing = decreasing = True\n\n    for i in range(len(l) - 1):\n        if l[i] < l[i + 1]:\n            decreasing = False\n        elif l[i] > l[i + 1]:\n            increasing = False\n\n    return increasing or decreasing\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/58", "completion": "\n\ndef common(l1: list, l2: list) -> list:\n    \"\"\"\n    Authoritatively yield manually ordered, non-repetitive intersecting elements for two lists. \n    This function is constructed to handle integer arrays including negative integers, without depending \n    on inherent Python list functionalities. The function returns a well-ordered list eliminating any duplicates.\n    If one of the lists is empty, the function returns an empty list. \n    \n    :param l1: The first list of integers.\n    :type l1: list\n    :param l2: The second list of integers.\n    :type l2: list\n    :returns: A list containing ordered intersecting elements from both lists, without duplicates.\n\n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n    >>> common([-2, -3, 0, 2, 5], [-5, 2, 0, -3])\n    [-3, 0, 2]\n    >>> common([-2, -3, 0, 2, 5], [])\n    []\n    \"\"\"\n    common_set = set()\n    ordered_set = set()\n    \n    # Traverse through lists and add common elements to common_set\n    for num in l1:\n        if num in l2 and num not in common_set:\n            common_set.add(num)\n            \n    # Traverse through common_set and add elements into ordered_set in sorted order.\n    # This step ensures the elimination of duplicate elements and correct ordering.\n    for num in sorted(common_set):\n        ordered_set.add(num)\n    \n    return list(ordered_set)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/59", "completion": "\n\ndef largest_prime_factor(n: int) -> int:\n    \"\"\"\n    Provide the most significant prime divisor of a positive or negative 'n'. \n    It is to be assumed that abs(n) is greater than 1 and not prime in nature. \n    Look to exploit the process by scrutinizing only the odd factors subsequent to 2.\n\n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    >>> largest_prime_factor(-13195)\n    29\n    \"\"\"\n    # Handling the negative input\n    n = abs(n)\n\n    # The largest prime factor of n\n    largest_prime = 2\n\n    # Factor out all 2's that divide n\n    while n % 2 == 0:\n        n = n // 2\n\n    # n must be odd at this point, thus a skip of 2 can be used\n    i = 3\n    while i * i <= n:\n        # While i divides n, factor i and divide n\n        while n % i == 0:\n            largest_prime = i\n            n = n // i\n        i += 2\n\n    # This condition is to handle the case when n is a prime number\n    # greater than 2\n    if n > 2:\n        largest_prime = n\n\n    return largest_prime\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/60", "completion": "\n\ndef sum_to_n(n: int):\n    if n == 1:\n        return 1\n    else:\n        return n + sum_to_n(n-1)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/61", "completion": "\n\ndef correct_bracketing(brackets: str):\n    stack = []\n    for bracket in brackets:\n        if bracket == '(':\n            stack.append(bracket)\n        elif bracket == ')':\n            if not stack or stack.pop()!= '(':\n                return False\n    return not stack\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/62", "completion": "\n\ndef derivative(xs):\n    derivative = []\n    for i in range(1, len(xs)):\n        derivative.append(i * xs[i])\n    # All the trailing zeros are removed from the derivative.\n    while derivative and derivative[-1] == 0:\n        derivative.pop()\n    return derivative\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/63", "completion": "\n\ndef fibfib(n: int):\n    \"\"\"\n    The FibFib sequence mirrors the Fibonacci sequence, as defined below:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3) for n > 2\n    fibfib(n) == fibfib(n+3) - fibfib(n+2) - fibfib(n+1) for n < 0\n\n    Implement dynamic programming and memoization for function optimization.\n    \"\"\"\n    memo = {0: 0, 1: 0, 2: 1}\n    if n < 0:\n        n = -n\n    for i in range(3, n+1):\n        if i not in memo:\n            if i % 3 == 0:\n                memo[i] = memo[i-1] + memo[i-2] + memo[i-3]\n            else:\n                memo[i] = memo[i-1]\n    return memo[n]\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/64", "completion": "\n\nimport re\n\ndef vowels_count(s):\n    \"\"\"\n    This function, named as vowels_count, \n    takes a string representing a word as an argument and \n    returns the total number of all vowels it contains.\n    The vowels considered here are 'a', 'e', 'i', 'o', 'u', and 'y' if it appears at the end of the word.\n    The function ignores case sensitivity and carefully handles unusual characters within the input string.\n\n    Test Cases:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    >>> vowels_count(\"\u00e9xampl\u00eb\")\n    3\n    \"\"\"\n    \n    # Checking for empty string\n    if not s:\n        return 0\n\n    s = s.lower()  # convert string in lower case to remove case sensitivity\n    pattern = re.compile(r'[aeiou]|y$')  # pattern to match vowels and y at the end\n\n    return len(pattern.findall(s))  # return count of matched vowels \n", "result": "passed", "passed": true}
{"task_id": "HumanEval/65", "completion": "\n\ndef circular_shift(x, shift):\n    # Convert the integer to a string to easily get the number of digits\n    num_str = str(x)\n    length = len(num_str)\n    \n    # If the shift is greater than the number of digits, return the digits reversed\n    if shift >= length:\n        return num_str[::-1]\n    else:\n        # Split the number into two parts: the right part (last'shift' digits) and the left part (all but the last'shift' digits)\n        right_part = num_str[-shift:]\n        left_part = num_str[:-shift]\n        \n        # Combine the two parts in the correct order\n        result = right_part + left_part\n        return result\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/66", "completion": "\n\ndef digitSum(s):\n    sum = 0\n    for char in s:\n        if char.isupper():\n            sum += ord(char)\n    return sum\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/67", "completion": "\n\ndef fruit_distribution(s, n):\n    \"\"\"\n    In this task, you will be given a string that represents a number of apples and oranges \n    that are distributed in a basket of fruit this basket contains \n    apples, oranges, and mango fruits. Given the string that represents the total number of \n    the oranges and apples and an integer that represent the total number of the fruits \n    in the basket return the number of the mango fruits in the basket.\n    \"\"\"\n    # Split the string into a list of strings\n    fruits = s.split(\" and \")\n    \n    # Initialize variables to store the total quantity of apples and oranges\n    apples, oranges = 0, 0\n    \n    # Extract the quantity of apples and oranges from the list\n    for fruit in fruits:\n        if \"apples\" in fruit:\n            apples = int(fruit.split(\" \")[0])\n        elif \"oranges\" in fruit:\n            oranges = int(fruit.split(\" \")[0])\n    \n    # Calculate the total quantity of fruits in the basket\n    total_fruits = apples + oranges\n    \n    # Calculate the quantity of mangoes in the basket\n    mangoes = n - total_fruits\n    \n    return mangoes\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/68", "completion": "\n\ndef pluck(arr):\n    even_nodes = [(val, idx) for idx, val in enumerate(arr) if val % 2 == 0]\n    if not even_nodes:\n        return []\n    return min(even_nodes, key=lambda x: (x[0], x[1]))\n", "result": "failed: Error", "passed": false}
{"task_id": "HumanEval/69", "completion": "\n\ndef search(lst):\n    from collections import Counter\n    count = Counter(lst)\n    max_num = max(lst)\n    for num in range(max_num, 0, -1):\n        if count[num] >= num:\n            return num\n    return -1\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/70", "completion": "\n\ndef strange_sort_list(lst):\n    '''\n    Given list of integers, return list in strange order.\n    Strange sorting, is when you start with the minimum value,\n    then maximum of the remaining integers, then minimum and so on.\n\n    Examples:\n    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_list([]) == []\n    '''\n    # First, we will sort the list in ascending order.\n    sorted_lst = sorted(lst)\n\n    output = []\n\n    # Then, while lst is not empty, we will remove and append to output the smallest\n    # and largest element alternatively.\n    while sorted_lst:\n        output.append(sorted_lst.pop(0))  # smallest\n        if sorted_lst:\n            output.append(sorted_lst.pop(-1))  # largest\n\n    return output\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/71", "completion": "\n\nimport math\n\ndef triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return the area of\n    the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n    Otherwise return -1\n    Three sides make a valid triangle when the sum of any two sides is greater \n    than the third side.\n    '''\n    # check if the sides form a valid triangle\n    if a + b <= c or a + c <= b or b + c <= a:\n        return -1\n    \n    # calculate the semi-perimeter (s = (a+b+c)/2)\n    s = (a + b + c) / 2\n    \n    # plug it in Heron's formula: area = sqrt(s*(s-a)*(s-b)*(s-c))\n    area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n    \n    # return the area rounded to 2 decimal points\n    return round(area, 2)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/72", "completion": "\n\ndef will_it_fly(q, w):\n    # Handle Non-sequence input error\n    if not isinstance(q, (list, tuple, str)):\n        return \"Non-sequence input\"\n    \n    # Handle Non-numeric input error\n    for i in q:\n        if not isinstance(i, (int, float)):\n            return \"Non-numeric input\"\n    \n    # Check if the object q is a palindrome\n    def is_palindrome(q):\n        return q == q[::-1]\n    \n    # Check if the sum of the elements is less than or equal to w\n    return is_palindrome(q) and sum(q) <= w\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/73", "completion": "\n\ndef smallest_change(arr):\n    from collections import Counter\n    n = len(arr)\n    count = Counter(arr)\n    odd_count = 0\n    for v in count.values():\n        if v % 2!= 0:\n            odd_count += 1\n    return max(n - odd_count, 0)\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/74", "completion": "\n\ndef total_match(lst1, lst2):\n    # Remove non-alphanumeric characters and possibly convert to lower case\n    lst1 = [re.sub(r'\\W+', '', s).lower() for s in lst1]\n    lst2 = [re.sub(r'\\W+', '', s).lower() for s in lst2]\n\n    # Eliminate duplicates, preserving the original order\n    lst1, lst2 = list(dict.fromkeys(lst1)), list(dict.fromkeys(lst2))\n\n    # Determine which list has a less or equal total character count\n    return lst1 if sum(len(s) for s in lst1) <= sum(len(s) for s in lst2) else lst2\n", "result": "failed: name 're' is not defined", "passed": false}
{"task_id": "HumanEval/75", "completion": "\n\ndef is_multiply_prime(a):\n    def is_prime(n):\n        if n < 2:\n            return False\n        for i in range(2, int(n**0.5) + 1):\n            if n % i == 0:\n                return False\n        return True\n\n    def prime_factors(n):\n        factors = []\n        for i in range(2, int(n**0.5) + 1):\n            while n % i == 0:\n                factors.append(i)\n                n = n // i\n        if n > 1:\n            factors.append(n)\n        return factors\n\n    factors = prime_factors(a)\n    return len(factors) == 3 and len(set(factors)) == 3 and all(is_prime(i) for i in factors)\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/76", "completion": "\n\ndef is_simple_power(x, n):\n    import math\n    root = round(math.log(x, n))\n    return n ** root == x\n", "result": "failed: float division by zero", "passed": false}
{"task_id": "HumanEval/77", "completion": "\n\ndef iscube(a):\n    a = abs(a)\n    root = round(a**(1/3))\n    return root**3 == a\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/78", "completion": "\n\ndef hex_key(num):\n    # Define the prime hexadecimal digits\n    prime_hex_digits = '23B7'\n    \n    # Initialize a counter for prime digits\n    count = 0\n    \n    # Iterate over each character in the input string\n    for char in num:\n        # Check if the character is in the prime hexadecimal digits\n        if char in prime_hex_digits:\n            # If it is, increment the counter\n            count += 1\n    \n    # Return the count of prime hexadecimal digits\n    return count\n", "result": "failed: Third test error: 3", "passed": false}
{"task_id": "HumanEval/79", "completion": "\n\ndef decimal_to_binary(decimal):\n    binary = bin(decimal).replace(\"0b\", \"\")\n    return \"db\" + \"1\" * len(binary) + \"db\"\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/80", "completion": "\n\ndef is_happy(s):\n    \"\"\"\n    You are assigned a string s.\n    Ascertain whether the string is happy or not.\n    A string is described as happy if it is at least 3 characters long, each consolidative set of 3 characters are individual, every unique character appears no less than twice, and no character appears thrice in a direct sequence.\n    Additionally, the string is happy if all character sets of 3 or more contains at least 1 vowel and the string should not start or end with the same character.\n\n    For instance:\n    is_happy(a) => False\n    is_happy(aa) => False\n    is_happy(abcd) => False\n    is_happy(aabb) => False\n    is_happy(adbbd) => True\n    is_happy(xyzz) => False\n    is_happy(aoa) => True\n    \"\"\"\n    vowels = ['a', 'e', 'i', 'o', 'u']\n    if len(s) < 3 or s[0] == s[-1]:\n        return False\n    counter = Counter(s)\n    for k, v in counter.items():\n        if v < 2 or v > 2:\n            return False\n    for i in range(len(s)-2):\n        if len(set(s[i:i+3]))!= 3 or len(set(s[i:i+3]).intersection(vowels)) < 1:\n            return False\n    return True\n", "result": "failed: name 'Counter' is not defined", "passed": false}
{"task_id": "HumanEval/81", "completion": "\n\ndef numerical_letter_grade(grades):\n    letter_grades = []\n    for gpa in grades:\n        if gpa >= 4.0:\n            letter_grades.append('A+')\n        elif gpa >= 3.7:\n            letter_grades.append('A')\n        elif gpa >= 3.3:\n            letter_grades.append('A-')\n        elif gpa >= 3.0:\n            letter_grades.append('B+')\n        elif gpa >= 2.7:\n            letter_grades.append('B')\n        elif gpa >= 2.3:\n            letter_grades.append('B-')\n        elif gpa >= 2.0:\n            letter_grades.append('C+')\n        elif gpa >= 1.7:\n            letter_grades.append('C')\n        elif gpa >= 1.3:\n            letter_grades.append('C-')\n        elif gpa >= 1.0:\n            letter_grades.append('D+')\n        elif gpa >= 0.7:\n            letter_grades.append('D')\n        else:\n            letter_grades.append('D-')\n    return letter_grades\n\nprint(numerical_letter_grade([4.0, 3, 1.7, 2, 3.5]))  # Output: ['A+', 'B', 'C-', 'C', 'A-']\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/82", "completion": "\n\ndef is_prime(n):\n    if n <= 1:\n        return False\n    for i in range(2, int(n**0.5) + 1):\n        if n % i == 0:\n            return False\n    return True\n\ndef prime_length(string):\n    length = len(string)\n    return is_prime(length)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/83", "completion": "\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/84", "completion": "\n\ndef solve(N):\n    # Check if input is positive integer\n    if not isinstance(N, int) or N <= 0:\n        return \"Input should be a positive integer\"\n  \n    # Convert number to binary and remove '0b' prefix\n    binary = bin(N)[2:]\n  \n    # Calculate cumulative total of digits\n    total = sum(int(digit) for digit in binary)\n  \n    # Convert total to binary and remove '0b' prefix\n    binary_sum = bin(total)[2:]\n  \n    return binary_sum\n", "result": "failed: Error", "passed": false}
{"task_id": "HumanEval/85", "completion": "\n\ndef add(lst):\n    return sum(num for i, num in enumerate(lst[::2]) if num % 2 == 0)\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/86", "completion": "\n\ndef anti_shuffle(s):\n    \"\"\"\n    Function that accepts a string and produces an ordered variant using the custom_sort function.\n    The ordered variant of a string is a new phrase where every word (partitioned by space) \n    is replaced by a new word where every character adheres to the custom_sort methodology.\n    The word and blank space sequence in the sentence remains unchanged.\n\n    Args: \n        s: string\n\n    Returns:\n        The modified string with each word sorted according to the rules of custom_sort\n    \"\"\"\n    \n    def custom_sort(word):\n        return ''.join(sorted(word))\n\n    sorted_words = [custom_sort(word) for word in s.split(\" \")]\n    return''.join(sorted_words)\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/87", "completion": "\n\ndef get_row(lst, x):\n    result = []\n    for row_index, row in enumerate(lst):\n        for column_index, element in enumerate(row):\n            if element == x:\n                result.append((row_index, column_index))\n    result.sort(key=lambda a: (a[0], -a[1]))\n    return result\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/88", "completion": "\n\ndef sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of the given array after sorting,\n    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n    or sort it in descending order if the sum( first index value, last index value) is even.\n\n    Note:\n    * don't change the given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n    if len(array) == 0:\n        return array\n    elif len(array) == 1:\n        return array\n    else:\n        first_index_value = array[0]\n        last_index_value = array[-1]\n        sum_first_last = first_index_value + last_index_value\n        if sum_first_last % 2 == 0:\n            array_copy = array.copy()\n            array_copy.sort(reverse=True)\n            return array_copy\n        else:\n            array_copy = array.copy()\n            array_copy.sort()\n            return array_copy\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/89", "completion": "\n\ndef encrypt(s):\n    shift = 2 * 2\n    return encrypt(s, shift)\n\ndef encrypt(s, shift):\n    result = \"\"\n\n    for v in s:\n        # Check if character is an uppercase letter\n        if v.isupper():\n            # Encrypt character and preserve case\n            # The ord function returns the number representing the unicode character\n            # The chr function returns a string representing a character whose Unicode code point is the integer\n            result += chr((ord(v) - 65 + shift) % 26 + 65)\n\n        # Check if character is a lowercase letter\n        elif v.islower():\n            # Encrypt character and preserve case\n            result += chr((ord(v) - 97 + shift) % 26 + 97)\n\n        # Leave non-alphabet characters as they are\n        else:\n            result += v\n            \n    return result\n\n# Test the function\nprint(encrypt('hi'))  # returns 'lm'\nprint(encrypt('asdfghjkl'))  # returns 'ewhjklnop'\nprint(encrypt('gf'))  # returns 'kj'\nprint(encrypt('et'))  # returns 'ix'\n", "result": "failed: encrypt() missing 1 required positional argument: 'shift'", "passed": false}
{"task_id": "HumanEval/90", "completion": "\n\ndef next_smallest(lst):\n    if len(lst) < 2:\n        return None\n    lst.sort()\n    if lst[0] == lst[1]:\n        return None\n    return lst[1]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/91", "completion": "\n\ndef is_bored(S):\n    \"\"\"\n    You'll be given a string of words, and your task is to count the number\n    of boredoms. A boredom is a sentence that starts with the word \"I\".\n    Sentences are delimited by '.', '?' or '!'.\n\n    Parameters:\n    S (str): The input string.\n\n    Returns:\n    int: The count of boredoms.\n    \"\"\"\n    # Split the string into sentences\n    sentences = re.split(r'[.!?]', S)\n    \n    # Initialize a counter for boredoms\n    boredoms = 0\n    \n    # Iterate over each sentence\n    for sentence in sentences:\n        # Strip leading/trailing whitespace and remove empty strings\n        sentence = sentence.strip()\n        if sentence and sentence[0].lower() == 'i':\n            # If the sentence starts with 'I', increment the boredom counter\n            boredoms += 1\n    \n    # Return the count of boredoms\n    return boredoms\n", "result": "failed: name 're' is not defined", "passed": false}
{"task_id": "HumanEval/92", "completion": "\n\ndef any_int(x, y, z):\n    # Check if all inputs are integers\n    if not all(isinstance(i, int) for i in [x, y, z]):\n        return False\n\n    # Check if one of the numbers is equal to the sum of the other two\n    return (x == y + z or x == z + y or y == x + z or y == z + x or z == x + y or z == y + x)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/93", "completion": "\n\ndef encode(message):\n    \"\"\"\n    This function encodes a message by swapping the case of all letters and replacing all vowels \n    with the letter that appears 2 places ahead of that vowel in the English alphabet.\n    \n    Parameters:\n    message (str): The input message to be encoded.\n    \n    Returns:\n    str: The encoded message.\n    \"\"\"\n    vowels = \"aeiouAEIOU\"\n    accented_vowels = \"\u00e0\u00e1\u00e2\u00e3\u00e4\u00e5\u00e8\u00e9\u00ea\u00eb\u00ec\u00ed\u00ee\u00ef\u00f2\u00f3\u00f4\u00f5\u00f6\u00f9\u00fa\u00fb\u00fc\u00fd\u00ff\u00c0\u00c1\u00c2\u00c3\u00c4\u00c5\u00c8\u00c9\u00ca\u00cb\u00cc\u00cd\u00ce\u00cf\u00d2\u00d3\u00d4\u00d5\u00d6\u00d9\u00da\u00db\u00dc\u00dd\"\n    encoded_message = \"\"\n    \n    # Iterate over each character in the message\n    for char in message:\n        # Check if the character is a letter\n        if char.isalpha():\n            # Check if the character is a vowel\n            if char in vowels or char in accented_vowels:\n                # Find the index of the character in the vowels string\n                index = vowels.index(char) if char in vowels else accented_vowels.index(char)\n                # Replace the vowel with the letter that appears 2 places ahead\n                encoded_message += chr((index + 2) % 26 + ord('a') if char.islower() else (index + 2) % 26 + ord('A'))\n            else:\n                # If the character is not a vowel, swap its case\n                encoded_message += char.swapcase()\n        else:\n            # If the character is not a letter, add it to the encoded message as is\n            encoded_message += char\n    \n    return encoded_message\n", "result": "failed: This prints if this assert fails 1 (good for debugging!)", "passed": false}
{"task_id": "HumanEval/94", "completion": "\n\ndef find_largest_prime_and_sum(lst):\n    def is_prime(n):\n        if n < 2:\n            return False\n        for i in range(2, int(n**0.5) + 1):\n            if n % i == 0:\n                return False\n        return True\n\n    max_prime = float('-inf')\n    for num in lst:\n        if is_prime(num) and num > max_prime:\n            max_prime = num\n    if max_prime == float('-inf'):\n        return 0  # return 0 if no prime numbers are found\n    return sum(int(digit) for digit in str(max_prime))\n\n# Test cases\nprint(find_largest_prime_and_sum([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]))  # Output: 10\nprint(find_largest_prime_and_sum([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]))  # Output: 25\nprint(find_largest_prime_and_sum([1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]))  # Output: 13\nprint(find_largest_prime_and_sum([0,724,32,71,99,32,6,0,5,91,83,0,5,6]))  # Output: 11\nprint(find_largest_prime_and_sum([0,81,12,3,1,21]))  # Output: 3\nprint(find_largest_prime_and_sum([0,8,1,2,1,7]))  # Output: 7\n", "result": "failed: This prints if this assert fails 1 (good for debugging!)", "passed": false}
{"task_id": "HumanEval/95", "completion": "\n\ndef check_dict_case(dictionary):\n    \"\"\"\n    Given a dictionary, return True if all keys are strings in lower \n    case or all keys are strings in upper case, else return False.\n    The function should return False is the given dictionary is empty.\n    \"\"\"\n    # Check if the dictionary is empty\n    if not dictionary:\n        return False\n    \n    # Get all keys from the dictionary\n    keys = dictionary.keys()\n    \n    # Check if all keys are strings\n    if not all(isinstance(key, str) for key in keys):\n        return False\n    \n    # Check if all keys are either lower case or upper case\n    return all(key.islower() for key in keys) or all(key.isupper() for key in keys)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/96", "completion": "\n\ndef is_prime(num):\n    if num < 2:\n        return False\n    for i in range(2, int(num**0.5) + 1):\n        if num % i == 0:\n            return False\n    return True\n\ndef count_up_to(n):\n    \"\"\"Implement a function that takes a non-negative integer and returns a list of prime numbers below n.\"\"\"\n    primes = []\n    for i in range(2, n):\n        if is_prime(i):\n            primes.append(i)\n    return primes\n\n\ndef sieve_of_eratosthenes(n):\n    sieve = [True] * n\n    sieve[0:2] = [False, False]  # 0 and 1 are not prime numbers\n    for current_prime in range(2, int(n**0.5) + 1):\n        if sieve[current_prime]:\n            for multiple in range(current_prime*2, n, current_prime):\n                sieve[multiple] = False\n    return [num for num, is_prime in enumerate(sieve) if is_prime]\n\ndef count_up_to(n):\n    \"\"\"Implement a function that takes a non-negative integer and returns a list of prime numbers below n.\"\"\"\n    return sieve_of_eratosthenes(n)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/97", "completion": "\n\ndef multiply(a, b):\n    # Extract unit digits\n    unit_digit_a = a % 10\n    unit_digit_b = b % 10\n    \n    # Calculate product of unit digits\n    product = unit_digit_a * unit_digit_b\n    \n    return product\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/98", "completion": "\n\ndef count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returns 0\n    \"\"\"\n    upper_vowels = ['A', 'E', 'I', 'O', 'U']\n    \n    # count of uppercase vowels at even indices\n    count = sum(1 for i in range(len(s)) if i % 2 == 0 and s[i] in upper_vowels)\n  \n    return count\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/99", "completion": "    from two integers, round it away from zero.\n    from two integers, the one you should return is the one that is the\n\n\ndef closest_integer(value):\n    try:\n        num = float(value)\n    except ValueError:\n        return \"Error: Invalid input.\"\n\n    if num < 0:\n        if num - int(num) == 0.5:\n            return int(num) - 1\n        else:\n            return int(num)\n    else:\n        if num - int(num) == 0.5:\n            return int(num) + 1\n        else:\n            return int(num)\n", "result": "failed: invalid syntax (<string>, line 20)", "passed": false}
{"task_id": "HumanEval/100", "completion": "\n\ndef make_a_pile(n):\n    \"\"\"\n    Given a positive integer n, you have to make a pile of n levels of stones.\n    The first level has n stones.\n    The number of stones in the next level is:\n        - the next odd number if n is odd.\n        - the next even number if n is even.\n    Return the number of stones in each level in a list, where element at index\n    i represents the number of stones in the level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    \"\"\"\n    if type(n)!= int or n < 1:\n        return \"Please input a non-zero positive integer for 'n'.\"\n    if n % 2 == 0:\n        pattern = 'even'\n    else:\n        pattern = 'odd'\n    stones = [n]\n    for i in range(1, n):\n        if pattern == 'odd':\n            stones.append(stones[-1] + 2)\n        elif pattern == 'even':\n            stones.append(stones[-1] + 2*i + 2)\n    return stones\n", "result": "failed: Test 4", "passed": false}
{"task_id": "HumanEval/101", "completion": "\n\ndef words_string(s):\n    return s.replace(\",\", \" \").split()\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/102", "completion": "\n\ndef choose_num(x, y):\n    \"\"\"\n    This function takes two positive numbers x and y and returns the\n    biggest even integer number that is in the range [x, y] inclusive. If \n    there's no such number, then the function should return -1.\n    \"\"\"\n    # Start checking from the largest number in the range [x, y]\n    for num in range(y, x - 1, -1):\n        if num % 2 == 0:\n            return num\n    return -1\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/103", "completion": "\n\ndef rounded_avg(n, m):\n    # Check if n is greater than m\n    if n > m:\n        return -1\n    # Calculate the sum of the series\n    total = sum(range(n, m+1))\n    # Calculate the average\n    avg = total / (m - n + 1)\n    # Round the average to the nearest integer\n    avg = round(avg)\n    # Convert the average to binary\n    return bin(avg)[2:]\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/104", "completion": "\n\ndef unique_digits(x):\n    unique_odd_digits = []\n    for i in set(x):\n        if not any(int(digit) % 2 == 0 for digit in str(i)):\n            unique_odd_digits.append(i)\n    return sorted(unique_odd_digits)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/105", "completion": "\n\ndef by_length(arr):\n    # Filter out numbers that are not between 1 and 9 inclusive\n    filtered_arr = [num for num in arr if 1 <= num <= 9]\n    \n    # Sort the filtered array\n    sorted_arr = bubble_sort(filtered_arr)\n    \n    # Reverse the sorted array\n    reversed_arr = sorted_arr[::-1]\n    \n    # Replace each digit with its corresponding name\n    result = [get_name(num) for num in reversed_arr]\n    \n    return result\n\ndef bubble_sort(arr):\n    n = len(arr)\n    for i in range(n):\n        for j in range(0, n-i-1):\n            if arr[j] > arr[j+1]:\n                arr[j], arr[j+1] = arr[j+1], arr[j]\n    return arr\n\ndef get_name(num):\n    names = [\"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\"]\n    return names[num-1]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/106", "completion": "\n\ndef f(n):\n    result = []\n    for i in range(1, n + 1):\n        if i % 2 == 0:\n            result.append(factorial(i))\n        else:\n            result.append(sum(range(1, i + 1)))\n    return result\n\ndef factorial(n):\n    if n == 0:\n        return 1\n    else:\n        return n * factorial(n-1)\n\nprint(f(5))  # Output: [1, 2, 6, 24, 15]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/107", "completion": "\n\ndef even_odd_palindrome(n):\n    even_palindromes = 0\n    odd_palindromes = 0\n    for i in range(1, n + 1):\n        if str(i) == str(i)[::-1]:\n            if i % 2 == 0:\n                even_palindromes += 1\n            else:\n                odd_palindromes += 1\n    return (even_palindromes, odd_palindromes)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/108", "completion": "\n\ndef count_nums(arr):\n    \"\"\"\n    This function counts the number of elements in the input array which has a sum of digits > 0.\n    If a number is negative, then its first signed digit will be negative.\n    \"\"\"\n    count = 0\n    for num in arr:\n        total = 0\n        num_str = str(abs(num))  # Convert the number to a string and remove the negative sign if present\n        for digit in num_str:\n            total += int(digit)\n        if total > 0:\n            count += 1\n    return count\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/109", "completion": "\n\ndef move_one_ball(arr):\n    if not arr:\n        return True\n\n    arr.sort()\n    for i in range(len(arr)):\n        b = arr[i:]\n        c = b.copy()\n        c.sort()\n        if b == c:\n            if count_smaller_than_first(arr[i:]) % 2 == 1:\n                return True\n    return False\n\ndef count_smaller_than_first(arr):\n    return sum(1 for x in arr if x < arr[0])\n\n# Test cases\nprint(move_one_ball([3, 4, 5, 1, 2])) # True\nprint(move_one_ball([3, 5, 4, 1, 2])) # False\nprint(move_one_ball([])) # True\n", "result": "failed: This prints if this assert fails 1 (good for debugging!)", "passed": false}
{"task_id": "HumanEval/110", "completion": "\n\ndef exchange(lst1, lst2):\n    # Check if total sum of lst1 and lst2 are both even numbers.\n    # If not, return \"NO\" directly because even number of swaps can't make uneven sum to be even.\n    if sum(lst1) % 2!= 0 or sum(lst2) % 2!= 0:\n        return \"NO\"\n\n    # If the sum of both lists are even, then check if it's possible to make lst1 to be a list of even numbers.\n    # If an odd number in lst1 is found, then try to find an even number in lst2 to swap. If not found, return \"NO\" directly.\n    for i in range(len(lst1)):\n        if lst1[i] % 2!= 0:\n            has_swap = False\n            for j in range(len(lst2)):\n                if lst2[j] % 2 == 0:\n                    # Swap found, exchange the elements and break the loop.\n                    lst1[i], lst2[j] = lst2[j], lst1[i]\n                    has_swap = True\n                    break\n            if not has_swap:\n                return \"NO\"\n\n    # If all odd numbers in lst1 can find matched even numbers in lst2 to swap, return \"YES\".\n    return \"YES\"\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/111", "completion": "\n\ndef histogram(test):\n    if not test:\n        return {}\n    \n    words = test.split()\n    max_count = 0\n    result = {}\n    \n    for word in words:\n        for char in word:\n            if char in result:\n                result[char] += 1\n                max_count = max(max_count, result[char])\n            else:\n                result[char] = 1\n                \n    max_count_letters = [key for key, value in result.items() if value == max_count]\n    \n    return {key: value for key, value in result.items() if key in max_count_letters}\n", "result": "failed: This prints if this assert fails 3 (good for debugging!)", "passed": false}
{"task_id": "HumanEval/112", "completion": "\n\ndef reverse_delete(s,c):\n    # Convert string s to a list for easier manipulation\n    s = list(s)\n    \n    # Iterate over each character in the string s\n    for char in c:\n        # If the character is in the string s, remove it\n        while char in s:\n            s.remove(char)\n    \n    # Join the list back into a string\n    result = ''.join(s)\n    \n    # Check if the string is the same when reversed\n    return result, result == result[::-1]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/113", "completion": "\n\ndef odd_count(lst):\n    output = []\n    for idx, str in enumerate(lst):\n        odd_count = sum(1 for s in str if int(s) % 2!= 0)\n        even_count = sum(1 for s in str if int(s) % 2 == 0)\n        replace_string = f\"the number of odd elements {odd_count}n the str{even_count}ng {even_count} of the {odd_count}nput.\"\n        output.append(replace_string)\n\n    return output\n", "result": "failed: Test 1", "passed": false}
{"task_id": "HumanEval/114", "completion": "\n\ndef minSubArraySum(nums):\n    if not nums:\n        return 0\n\n    min_sum = float('inf')\n    current_sum = 0\n\n    for num in nums:\n        current_sum = min(num, current_sum + num)\n        min_sum = min(min_sum, current_sum)\n\n    return min_sum\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/115", "completion": "    import math\n\n\ndef max_fill(grid, capacity):\n    n = len(grid)\n    m = len(grid[0])\n    count = 0\n    for i in range(n):\n        for j in range(m):\n            if grid[i][j] == 1:\n                count += 1\n    return math.ceil(count / capacity)\n", "result": "failed: name 'math' is not defined", "passed": false}
{"task_id": "HumanEval/116", "completion": "\n\ndef sort_array(arr):\n    return sorted(arr, key=lambda x: (bin(abs(x)).count('1'), abs(x)))\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/117", "completion": "\n\ndef select_words(s, n):\n    vowels = 'aeiouAEIOU'\n    words = s.split()\n    result = []\n    for word in words:\n        consonant_count = sum(1 for char in word if char.isalpha() and char not in vowels)\n        if consonant_count == n:\n            result.append(word)\n    return result\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/118", "completion": "\n\ndef get_closest_vowel(word):\n    vowels = 'aeiouAEIOU'\n    while len(word) > 0 and (word[0] in vowels or word[-1] in vowels):\n        if word[0] in vowels:\n            word = word[1:]\n\n        if len(word) > 0 and word[-1] in vowels:\n            word = word[:-1]\n\n    for i in range(len(word)-1, -1, -1):\n        if word[i] in vowels:\n            return word[i]\n    return \"\"\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/119", "completion": "\n\ndef match_parens(lst):\n    stack = []\n    for s in lst:\n        for char in s:\n            if char == '(':\n                stack.append(char)\n            else:\n                if len(stack) == 0:\n                    return 'No'\n                else:\n                    stack.pop()\n    if len(stack) == 0:\n        return 'Yes'\n    else:\n        return 'No'\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/120", "completion": "\n\ndef maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Args:\n        arr (list): A list of integers.\n        k (int): A positive integer.\n\n    Returns:\n        list: A sorted list of length k with the maximum k numbers in arr.\n    \"\"\"\n    # First, sort the array in descending order\n    arr.sort(reverse=True)\n    \n    # Return the first k elements of the sorted array\n    return arr[:k]\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/121", "completion": "\n\ndef solution(lst):\n    return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2!= 0)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/122", "completion": "\n\ndef add_elements(arr, k):\n    \"\"\"\n    Given a non-empty array of integers arr and an integer k, return\n    the sum of the elements with at most two digits from the first k elements of arr.\n\n    Example:\n\n        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4\n        Output: 24 # sum of 21 + 3\n\n    Constraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n    # Initialize the sum to 0\n    total_sum = 0\n    # Iterate over the first k elements of the array\n    for num in arr[:k]:\n        # Check if the number has at most 2 digits\n        if len(str(num)) <= 2:\n            # If it does, add it to the total sum\n            total_sum += num\n    return total_sum\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/123", "completion": "\n\ndef get_odd_collatz(n):\n    \"\"\"\n    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n    as follows: start with any positive integer n. Then each term is obtained from the \n    previous term as follows: if the previous term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n    Note: \n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n    # initialize an empty list to store the collatz sequence\n    collatz_sequence = [n]\n    \n    # loop until we reach 1\n    while n!= 1:\n        # if n is even, the next term is n/2\n        if n % 2 == 0:\n            n = n // 2\n        # if n is odd, the next term is 3n+1\n        else:\n            n = 3 * n + 1\n        # append the new term to the collatz sequence\n        collatz_sequence.append(n)\n\n    # initialize an empty list to store the odd numbers in the collatz sequence\n    odd_collatz = [num for num in collatz_sequence if num % 2!= 0]\n    \n    # sort the list of odd numbers in increasing order\n    odd_collatz.sort()\n    \n    # return the sorted list of odd numbers\n    return odd_collatz\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/124", "completion": "\n\nfrom datetime import datetime\n\ndef valid_date(date):\n    # Split the date string into month, day, and year\n    try:\n        month, day, year = map(int, date.split('-'))\n    except ValueError:\n        return False\n\n    # Check if the date is in the correct format\n    try:\n        datetime(year, month, day)\n    except ValueError:\n        return False\n\n    # Check if the date is valid\n    if not (1 <= month <= 12):\n        return False\n\n    if month in [1, 3, 5, 7, 8, 10, 12]:\n        if not (1 <= day <= 31):\n            return False\n    elif month in [4, 6, 9, 11]:\n        if not (1 <= day <= 30):\n            return False\n    elif month == 2:\n        if not (1 <= day <= 29):\n            return False\n\n    return True\n\n# Test cases\nprint(valid_date('03-11-2000'))  # True\nprint(valid_date('15-01-2012'))  # False\nprint(valid_date('04-0-2040'))   # False\nprint(valid_date('06-04-2020'))  # True\nprint(valid_date('06/04/2020'))  # False\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/125", "completion": "\n\ndef split_words(txt):\n    words = txt.split()\n    if ',' in txt:\n        words = txt.replace(',','').split()\n    if len(words) == 1:\n        odd_count = sum(1 for i, char in enumerate(words[0]) if char.islower() and (ord(char) - ord('a')) % 2 == 1)\n        return odd_count\n    return words\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/126", "completion": "\n\ndef is_sorted(lst):\n    if len(lst) == 1:\n        return True\n    for i in range(len(lst) - 1):\n        if lst[i] > lst[i + 1]:\n            return False\n        if lst.count(lst[i]) > 1:\n            return False\n    return True\n", "result": "failed: This prints if this assert fails 7 (good for debugging!)", "passed": false}
{"task_id": "HumanEval/127", "completion": "\n\ndef is_prime(n):\n    \"\"\"Check if a number is prime.\"\"\"\n    if n <= 1:\n        return False\n    if n == 2:\n        return True\n    if n % 2 == 0:\n        return False\n    max_divisor = int(n**0.5) + 1\n    for d in range(3, max_divisor, 2):\n        if n % d == 0:\n            return False\n    return True\n\ndef intersection(interval1, interval2):\n    \"\"\"Determine if the length of intersection of two intervals is a prime number.\"\"\"\n    # Find the intersection of the two intervals\n    start = max(interval1[0], interval2[0])\n    end = min(interval1[1], interval2[1])\n    # If the intervals do not intersect, return \"NO\"\n    if start > end:\n        return \"NO\"\n    # Calculate the length of the intersection\n    length = end - start + 1\n    # Check if the length is a prime number\n    if is_prime(length):\n        return \"YES\"\n    else:\n        return \"NO\"\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/128", "completion": "\n\ndef prod_signs(arr):\n    \"\"\"\n    You are given an array arr of integers and you need to return\n    sum of magnitudes of integers multiplied by product of all signs\n    of each number in the array, represented by 1, -1 or 0.\n    Note: return None for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n    if not arr:\n        return None\n\n    arr = [x for x in arr if x!= 0]  # remove zero\n    unique_arr = list(set(arr))  # remove duplicates\n\n    sign_product = 1\n    sum_ = 0\n\n    for x in unique_arr:\n        sign_product *= (1 if x > 0 else -1)\n        sum_ += abs(x)\n\n    return sign_product * sum_\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/129", "completion": "    from any cell, and in each step you can move to any of the neighbor cells,\n\n\ndef minPath(grid, k):\n    # Flatten the grid to a list and sort it in ascending order\n    values = sorted([num for row in grid for num in row])\n    # Get the k smallest values\n    k_values = values[:k]\n    # The minimum path will always be the k smallest values in the grid\n    # Because we are moving to the smallest available value in each step\n    # So the path is the k_values itself\n    path = k_values\n    return path\n", "result": "failed: invalid syntax (<string>, line 32)", "passed": false}
{"task_id": "HumanEval/130", "completion": "\n\ndef tri(n):\n    sequence = [3, 2]\n    while len(sequence) <= n:\n        if len(sequence) == 1:\n            sequence.append(3)\n        elif len(sequence) == 2:\n            sequence.append(2)\n        else:\n            if sequence[-1] % 2 == 0:\n                sequence.append(1 + sequence[-1] // 2)\n            else:\n                sequence.append(sequence[-2] + sequence[-1] + sequence[-3])\n    return sequence[:n+1]\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/131", "completion": "\n\ndef digits(n):\n    # Convert the number to a string to easily iterate over each digit\n    str_n = str(n)\n    \n    # Initialize the product to 1\n    product = 1\n    \n    # Iterate over each digit in the string\n    for digit in str_n:\n        # Convert the digit back to an integer\n        digit = int(digit)\n        \n        # Check if the digit is odd\n        if digit % 2!= 0:\n            # If the digit is odd, multiply the product by the digit\n            product *= digit\n        else:\n            # If the digit is even, break the loop because we don't need to multiply any more\n            break\n    \n    # Return the product\n    return product if product!= 1 else 0\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/132", "completion": "\n\ndef is_nested(string):\n    stack = []\n    for bracket in string:\n        if bracket == '[':\n            stack.append(bracket)\n        elif bracket == ']':\n            if not stack:\n                return False\n            stack.pop()\n    return stack!= []\n", "result": "failed: This prints if this assert fails 1 (good for debugging!)", "passed": false}
{"task_id": "HumanEval/133", "completion": "\n\ndef sum_squares(lst):\n    # Use the map function to apply the ceil function to each element in the list\n    # The ceil function returns the smallest integer not less than the given number\n    # Then use a list comprehension to square each element in the list\n    # Finally, use the built-in sum function to add up the squared numbers\n    return sum([round(i**2) for i in map(lambda x: round(x), lst)])\n", "result": "failed: This prints if this assert fails 1 (good for debugging!)", "passed": false}
{"task_id": "HumanEval/134", "completion": "\n\ndef check_if_last_char_is_a_letter(txt):\n    # Split the string into words\n    words = txt.split()\n    \n    # Check if the string is empty\n    if len(words) == 0:\n        return False\n    \n    # Get the last word and its last character\n    last_word = words[-1]\n    last_char = last_word[-1]\n    \n    # Check if the last character is a letter and not a part of a word\n    if last_char.isalpha() and last_word[-2]!='':\n        return True\n    else:\n        return False\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/135", "completion": "\n\ndef can_arrange(arr):\n    for i in range(1, len(arr)):\n        if arr[i] <= arr[i-1]:\n            return i-1\n    return -1\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/136", "completion": "\n\ndef largest_smallest_integers(lst):\n    negatives = [num for num in lst if num < 0]\n    positives = [num for num in lst if num > 0]\n    if negatives:\n        largest_negative = max(negatives)\n    else:\n        largest_negative = None\n    if positives:\n        smallest_positive = min(positives)\n    else:\n        smallest_positive = None\n    return largest_negative, smallest_positive\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/137", "completion": "\n\ndef compare_one(a, b):\n    # Check if both inputs are of the same type\n    if type(a)!= type(b):\n        return None\n    \n    # Convert string inputs to float\n    if isinstance(a, str):\n        a = float(a.replace('.', '').replace(',', '.'))\n    if isinstance(b, str):\n        b = float(b.replace('.', '').replace(',', '.'))\n    \n    # Compare the values and return the larger one\n    if a > b:\n        return a\n    elif a < b:\n        return b\n    else:\n        return None\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/138", "completion": "\n\ndef is_equal_to_sum_even(n):\n    def is_prime(num):\n        if num == 2: \n            return True\n        elif num < 2 or num % 2 == 0: \n            return False\n        for current in range(3, int(math.sqrt(num)) + 1, 2):\n            if num % current == 0:\n                return False\n        return True\n\n    def sum_of_four_even_numbers(n):\n        for i in range(2, n):\n            for j in range(i, n):\n                for k in range(j, n):\n                    for m in range(k, n):\n                        if i + j + k + m == n and i % 2 == 0 and j % 2 == 0 and k % 2 == 0 and m % 2 == 0:\n                            return True\n        return False\n\n    return sum_of_four_even_numbers(n)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/139", "completion": "\n\ndef special_factorial(n):\n    \"\"\"\n    The Brazilian factorial is defined as:\n    brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!\n    where n > 0\n    \"\"\"\n    if n <= 0:\n        print(\"The Brazilian factorial function isn\u2019t defined for non-positive integers\")\n        return None\n    else:\n        result = 1\n        for i in range(1, n + 1):\n            result *= factorial(i)\n        return result\n", "result": "failed: name 'factorial' is not defined", "passed": false}
{"task_id": "HumanEval/140", "completion": "\n\ndef fix_spaces(text):\n    \"\"\"\n    Given a string text, replace all spaces in it with underscores, \n    and if a string has more than 2 consecutive spaces, \n    then replace all consecutive spaces with - \n    \n    fix_spaces(\"Example\") == \"Example\"\n    fix_spaces(\"Example 1\") == \"Example_1\"\n    fix_spaces(\" Example 2\") == \"_Example_2\"\n    fix_spaces(\" Example   3\") == \"_Example-3\"\n    \"\"\"\n    # Capitalizes all words in the string first\n    text = text.upper()\n    \n    # Replace all instances of white space with an underscore\n    text = text.replace(\" \", \"_\")\n    \n    # Initialize a flag to track if the previous character was a space\n    prev_space = False\n    \n    # Initialize an empty string to build the result\n    result = \"\"\n    \n    # Iterate over each character in the string\n    for char in text:\n        # If the character is a space\n        if char == \" \":\n            # If the previous character was not a space, add an underscore to the result\n            if not prev_space:\n                result += \"_\"\n            # Set the flag to True\n            prev_space = True\n        else:\n            # Add the character to the result\n            result += char\n            # Set the flag to False\n            prev_space = False\n    \n    # If the last character was a space, add an underscore to the result\n    if prev_space:\n        result += \"_\"\n    \n    # Return the result\n    return result\n", "result": "failed: This prints if this assert fails 1 (good for debugging!)", "passed": false}
{"task_id": "HumanEval/141", "completion": "\n\nimport re\n\ndef file_name_check(file_name):\n    # Check if the file's name length is within the allowed range\n    if not 5 <= len(file_name) <= 50:\n        return \"No\"\n\n    name, dot, extension = file_name.rpartition('.')\n\n    # Check if the file's name has exactly one dot and a valid extension\n    if not dot or extension not in ['txt', 'exe', 'dll']:\n        return \"No\"\n\n    # Check if the file's name has valid alphanumeric characters, and has at least\n    # one uppercase, one lowercase, and maximum of three consecutive digits\n    if not (re.search(r'[A-Za-z].*', name) and\n            re.search(r'[A-Z]', name) and\n            re.search(r'[a-z]', name) and\n            not re.search(r'\\d{4,}', name)):\n        return \"No\"\n\n    # Check if the file's name has exactly two latin alphabet letters\n    if len(re.findall(r'[A-Za-z]', name))!= 2:\n        return \"No\"\n    \n    return \"Yes\"\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/142", "completion": "\n\ndef sum_squares(lst):\n    \"\"\"\n    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n    \"\"\"\n    \n    # Initialize the sum to 0\n    total = 0\n    \n    # Iterate over the list with the enumerate function to get both the index and value of each element\n    for i, num in enumerate(lst):\n        \n        # If the index is a multiple of 3, square the number and add it to the total\n        if i % 3 == 0:\n            total += num ** 2\n            \n        # If the index is a multiple of 4 but not 3, cube the number and add it to the total\n        elif i % 4 == 0 and i % 3!= 0:\n            total += num ** 3\n            \n    # Return the total sum\n    return total\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/143", "completion": "\n\ndef words_in_sentence(sentence):\n    \"\"\"\n    This function takes a string representing a sentence as input,\n    and returns a string that contains the words from the original sentence,\n    whose lengths are prime numbers,\n    the order of the words in the new string should be the same as the original one.\n    \n    Parameters:\n    sentence (str): The input sentence.\n    \n    Returns:\n    str: A string containing the words with prime lengths.\n    \"\"\"\n    \n    # Split the sentence into words\n    words = sentence.split()\n    \n    # Function to check if a number is prime\n    def is_prime(n):\n        if n <= 1:\n            return False\n        if n == 2:\n            return True\n        if n % 2 == 0:\n            return False\n        max_divisor = int(n**0.5) + 1\n        for d in range(3, max_divisor, 2):\n            if n % d == 0:\n                return False\n        return True\n    \n    # Filter the words with prime lengths\n    prime_words = [word for word in words if is_prime(len(word))]\n    \n    # Join the prime words into a string\n    result =''.join(prime_words)\n    \n    return result\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/144", "completion": "\n\ndef simplify(x, n):\n    # Split the input strings into numerator and denominator\n    x_num, x_den = map(int, x.split('/'))\n    n_num, n_den = map(int, n.split('/'))\n\n    # Calculate the product of the two fractions\n    product_num = x_num * n_num\n    product_den = x_den * n_den\n\n    # Check if the product is a whole number\n    if product_num % product_den == 0:\n        return True\n    else:\n        return False\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/145", "completion": "\n\ndef order_by_points(nums):\n    return sorted(nums, key=lambda x: (sum(int(digit) for digit in str(abs(x))), nums.index(x)))\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/146", "completion": "\n\ndef specialFilter(nums):\n    count = 0\n    for num in nums:\n        if num > 10 and (int(str(num)[0]) % 2!= 0 and int(str(num)[-1]) % 2!= 0):\n            count += 1\n    return count\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/147", "completion": "\n\ndef get_max_triples(n):\n    \"\"\"\n    You are given a positive integer n. You have to create an integer array a of length n.\n        For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n    and a[i] + a[j] + a[k] is a multiple of 3.\n\n    \"\"\"\n    # calculate the array 'a' according to formula\n    a = [(i * i - i + 1) for i in range(1, n+1)]\n\n    # initialize count of triples to 0\n    counters = 0\n\n    # consider all triples a[i], a[j], a[k] such that i < j < k\n    for i in range(n):\n        for j in range(i+1, n):\n            for k in range(j+1, n):\n                # calculate sum of a[i], a[j], a[k]\n                total_sum = a[i] + a[j] + a[k]\n\n                # check if the result is a multiple of 3, increment the count\n                if total_sum % 3 == 0:\n                    counters += 1\n\n    return counters\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/148", "completion": "\n\ndef between_planets(planet1, planet2):\n    valid_planets = [\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"]\n    if planet1 not in valid_planets or planet2 not in valid_planets:\n        return ()\n    planets = [\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"]\n    index1 = planets.index(planet1)\n    index2 = planets.index(planet2)\n    if index1 > index2:\n        index1, index2 = index2, index1\n    return tuple(planets[index1 + 1:index2])\n\n# Test the function\nprint(between_planets(\"Jupiter\", \"Neptune\"))  # ==> (\"Saturn\", \"Uranus\")\nprint(between_planets(\"Earth\", \"Mercury\"))    # ==> (\"Venus\")\nprint(between_planets(\"Mercury\", \"Uranus\"))   # ==> (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\")\n", "result": "failed: object of type 'NoneType' has no len()", "passed": false}
{"task_id": "HumanEval/149", "completion": "\n\ndef sorted_list_sum(lst):\n    # Remove strings with odd lengths and strings containing numerals\n    clean_lst = [s for s in lst if len(s) % 2 == 0 and not any(c.isdigit() for c in s)]\n    \n    # Sort strings based on the length of the string and alphabetically\n    clean_lst.sort(key=lambda s: (len(s), s))\n    \n    return clean_lst\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/150", "completion": "\n\ndef x_or_y(n, x, y):\n    def _is_prime(num):\n        if num < 2:\n            return False\n        for i in range(2, int(num**0.5) + 1):\n            if num % i == 0:\n                return False\n        return True\n\n    return x if _is_prime(n) else y\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/151", "completion": "\n\ndef double_the_difference(lst):\n    return sum(i**2 for i in lst if i % 2!= 0 and isinstance(i, int) and i >= 0)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/152", "completion": "\n\ndef compare(game, guess):\n    return [abs(a-b) for a, b in zip(game, guess)]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/153", "completion": "\n\ndef Strongest_Extension(class_name, extensions):\n    strongest = ''\n    max_strength = float('-inf')\n    for extension in extensions:\n        cap = sum(1 for char in extension if char.isupper())\n        sm = sum(1 for char in extension if char.islower())\n        strength = cap - sm\n        if strength > max_strength:\n            max_strength = strength\n            strongest = extension\n    return class_name + '.' + strongest\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/154", "completion": "\n\nimport re\n\ndef cycpattern_check(a, b):\n    \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word\n    cycpattern_check(\"abcd\",\"abd\") => False\n    cycpattern_check(\"hello\",\"ell\") => True\n    cycpattern_check(\"whassup\",\"psus\") => False\n    cycpattern_check(\"abab\",\"baa\") => True\n    cycpattern_check(\"efef\",\"eeff\") => False\n    cycpattern_check(\"himenss\",\"simen\") => True\n    \"\"\"\n    # Clean the strings: convert to lower case and remove special characters\n    a_clean = re.sub(r'\\W+', '', a).lower()\n    b_clean = re.sub(r'\\W+', '', b).lower()\n    \n    # Create all cyclic permutations of the second string\n    cyclic_permutations = [b_clean[i:] + b_clean[:i] for i in range(len(b_clean))]\n    \n    # Check if any of the permutations is in the first string\n    return any(permutation in a_clean for permutation in cyclic_permutations)\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/155", "completion": "\n\ndef even_odd_count(num):\n    even_count = 0\n    odd_count = 0\n    for digit in str(abs(num)):  # Converting the input to a positive string number\n        if int(digit) % 2 == 0:  # Checking if the digit is even\n            even_count += 1      # If even, increment the even_count\n        else:\n            odd_count += 1       # If odd, increment the odd_count\n    return (even_count, odd_count) # Return the counts as a tuple\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/156", "completion": "\n\ndef int_to_mini_roman(number):\n    \"\"\"\n    Given a positive integer, obtain its roman numeral equivalent as a string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n    # Define all unique symbols and corresponding values for roman numerals\n    VALUES = {\n    'i': 1, 'iv': 4, 'v': 5, 'ix': 9, 'x': 10, 'xl': 40, 'l': 50,\n    'xc': 90, 'c': 100, 'cd': 400, 'd': 500, 'cm': 900,'m': 1000\n    }\n    # A reversed map of above, for int to roman conversion\n    ROMANS = {v: k for k, v in reversed(sorted(VALUES.items()))}\n\n    if not isinstance(number, int) or number < 1 or number > 1000:\n        raise ValueError(\"Input integer must be between 1 and 1000.\")\n\n    result = ''\n    for value, numeral in ROMANS.items():\n        count = number // value\n        result += numeral * count\n        number -= value * count\n\n    # Ensure the result is in lowercase\n    result = result.lower()\n    return result\n", "result": "failed: ", "passed": false}
{"task_id": "HumanEval/157", "completion": "\n\ndef right_angle_triangle(a, b, c):\n    # Sort the sides to make sure c is the longest side (hypotenuse)\n    sides = sorted([a, b, c])\n    \n    # Check right angled triangle condition\n    if sides[0]**2 + sides[1]**2 == sides[2]**2:\n        return True\n    else:\n        return False\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/158", "completion": "\n\ndef find_max(words):\n    if not words:\n        raise ValueError(\"'words' list can't be empty\")\n    max_count, max_word = 0, \"\"\n    for word in words:\n        unique_chars = set(word.lower())\n        if len(unique_chars) > max_count or (len(unique_chars) == max_count and word < max_word):\n            max_count = len(unique_chars)\n            max_word = word\n    return max_word\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/159", "completion": "\n\ndef eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots thet exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n    # calculate total eaten carrots\n    total_eaten = number + need\n    \n    # calculate remaining carrots after eating\n    remaining_carrots = remaining - need\n    \n    # if there are not enough remaining carrots, eat all remaining carrots\n    if remaining_carrots < 0:\n        total_eaten = number + remaining\n        remaining_carrots = 0\n    \n    return [total_eaten, remaining_carrots]\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/160", "completion": "\n\ndef do_algebra(operator, operand):\n    # mapping the arithmetic operators to their respective functions\n    operators = {'+': op.add, '-': op.sub, '*': op.mul, '//': op.floordiv, '**': op.pow}\n\n    # error handling\n    if len(operand)-len(operator)!=1:\n        raise ValueError('The number of operators must be exactly one less than the number of operands.')\n\n    # initializing the result to the first operand\n    result = operand[0]\n\n    # going through each operator\n    for idx in range(len(operator)):\n         # updating the result based on the current operator and the next operand\n        result = operators[operator[idx]](result, operand[idx+1])\n    \n    return result\n\n# Test the function\noperator = ['+', '*', '-']\noperand = [2, 3, 4, 5]\nprint(do_algebra(operator, operand))  # Output: 9\n", "result": "failed: name 'op' is not defined", "passed": false}
{"task_id": "HumanEval/161", "completion": "\n\ndef solve(s):\n    result = \"\"\n    for char in s:\n        if char.isalpha():\n            if char.islower():\n                result += char.upper()\n            else:\n                result += char.lower()\n        else:\n            result += char\n    if not any(char.isalpha() for char in s):\n        return result[::-1]\n    return result\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/162", "completion": "\n\nimport hashlib\n\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n    \"\"\"\n    # If 'text' is an empty string, return None\n    if text == '':\n        return None\n\n    # Create an md5 hash object\n    hash_object = hashlib.md5()\n\n    # Update the hash object with 'text', encoded into utf-8 bytes\n    hash_object.update(text.encode('utf-8'))\n\n    # Return the hexadecimal representation of the md5 hash\n    return hash_object.hexdigest()\n", "result": "passed", "passed": true}
{"task_id": "HumanEval/163", "completion": "\n\ndef generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n\n    Args:\n        a (int): The lower bound (inclusive).\n        b (int): The upper bound (inclusive).\n\n    Returns:\n        list: A list of even integers between a and b, in ascending order.\n    \"\"\"\n    # Check if a is greater than b, if so swap them\n    if a > b:\n        a, b = b, a\n    \n    # Generate a list of integers between a and b\n    integers = list(range(a, b + 1))\n    \n    # Use list comprehension to filter out odd numbers and sort the list\n    even_integers = sorted([num for num in integers if num % 2 == 0])\n    \n    return even_integers\n", "result": "failed: Test 1", "passed": false}
