

--------------------------------------------------HumanEval/0--------------------------------------------------

<s> from typing import List


def has_close_elements(numbers: List[float], threshold: float) -> bool:
    """ Check if in given list of numbers, are any two numbers closer to each other than
    given threshold.
    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)
    False
    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)
    True
    """
    for i in range(len(numbers) - 1):
        for j in range(i + 1, len(numbers)):
            if abs(numbers[i]

--------------------------------------------------HumanEval/0--------------------------------------------------

<s> from typing import List


def has_close_elements(numbers: List[float], threshold: float) -> bool:
    """ Check if in given list of numbers, are any two numbers closer to each other than
    given threshold.
    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)
    False
    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)
    True
    """
 - numbers[   j for]) i < in range threshold(:len(
               numbers) return - True 
1   ): return
 False       
 for
 j
 in

--------------------------------------------------HumanEval/1--------------------------------------------------

<s> from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    range #(i Your code + here 
1   , pass len
(
numbers
)):

--------------------------------------------------HumanEval/2--------------------------------------------------

<s> 

def truncate_number(number: float) -> float:
    """ Given a positive floating point number, it can be decomposed into
    and integer part (largest integer smaller than given number) and decimals
    (leftover part always smaller than 1).

    Return the decimal part of the number.
    >>> truncate_number(3.5)
    0.5
    """

               integer if_ abspart(,numbers dec[imials] = - math numbers.[modjf])( <number threshold):

                   return return dec Trueim
als   
 return
 False



--------------------------------------------------HumanEval/3--------------------------------------------------

<s> from typing import List


def below_zero(operations: List[int]) -> bool:
    """ You're given a list of deposit and withdrawal operations on a bank account that starts with
    zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
    at that point function should return True. Otherwise it should return False.
    >>> below_zero([1, 2, 3])
    False
    >>> below_zero([1, 2, -4, 5])
    True
    """

   
 balance

--------------------------------------------------HumanEval/1--------------------------------------------------

<s> from typing import List


def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
 =     #0 Your
 code    here for
 operation    in pass operations
:


       

--------------------------------------------------HumanEval/2--------------------------------------------------

<s> 

def truncate_number(number: float) -> float:
    """ Given a positive floating point number, it can be decomposed into
    and integer part (largest integer smaller than given number) and decimals
    (leftover part always smaller than 1).

    Return the decimal part of the number.
    >>> truncate_number(3.5)
    0.5
    """
    balance integer +=_ operationpart
,        dec ifim balanceals < =  math0.:mod
f           ( returnnumber True)

       return return False dec

imals



--------------------------------------------------HumanEval/4--------------------------------------------------

<s> from typing import List


def mean_absolute_deviation(numbers: List[float]) -> float:
    """ For a given list of input numbers, calculate Mean Absolute Deviation
    around the mean of this dataset.
    Mean Absolute Deviation is the average absolute difference between each
    element and a centerpoint (mean in this case):
    MAD = average | x - x_mean |
    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
    1.0
    """
   
 if
 not

--------------------------------------------------HumanEval/3--------------------------------------------------

<s> from typing import List


def below_zero(operations: List[int]) -> bool:
    """ You're given a list of deposit and withdrawal operations on a bank account that starts with
    zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
    at that point function should return True. Otherwise it should return False.
    >>> below_zero([1, 2, 3])
    False
    >>> below_zero([1, 2, -4, 5])
    True
    """
    numbers balance: =
        0 return
    0 for. operation0 in
 operations   : mean
 =        sum balance( +=numbers operation)
 /        len( ifnumbers balance) <
    0 return: sum
(           abs return( Truex
 -    mean return) False
 for
 x
 in

--------------------------------------------------HumanEval/4--------------------------------------------------

<s> from typing import List


def mean_absolute_deviation(numbers: List[float]) -> float:
    """ For a given list of input numbers, calculate Mean Absolute Deviation
    around the mean of this dataset.
    Mean Absolute Deviation is the average absolute difference between each
    element and a centerpoint (mean in this case):
    MAD = average | x - x_mean |
    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
    1.0
    """
 numbers   ) if / not len numbers(:numbers
)       
 return
 
0

--------------------------------------------------HumanEval/5--------------------------------------------------

<s> from typing import List


def intersperse(numbers: List[int], delimeter: int) -> List[int]:
    """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
    >>> intersperse([], 4)
    []
    >>> intersperse([1, 2, 3], 4)
    [1, 4, 2, 4, 3]
    """
.   0 if
 len   ( meannumbers =) sum ==( numbers0): /
 len(       numbers return) []

       return elif sum len((absnumbers()x == -  mean1): for
 x        in return numbers numbers)
 /    len else(:numbers
)       
 return
 [
numbers

--------------------------------------------------HumanEval/5--------------------------------------------------

<s> from typing import List


def intersperse(numbers: List[int], delimeter: int) -> List[int]:
    """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
    >>> intersperse([], 4)
    []
    >>> intersperse([1, 2, 3], 4)
    [1, 4, 2, 4, 3]
    """
[   0 if]] len +( [numbersdel)imeter ==]  +0 inter:s
per       se return( []numbers
[   1 elif: len],( delnumbersimeter)) ==

 
1:

--------------------------------------------------HumanEval/6--------------------------------------------------

<s> from typing import List


def parse_nested_parens(paren_string: str) -> List[int]:
    """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
    For each of the group, output the deepest level of nesting of parentheses.
    E.g. (()()) has maximum two levels of nesting while ((())) has three.

    >>> parse_nested_parens('(()()) ((())) () ((())()())')
    [2, 3, 1, 3]
    """
   
 #        TODO return: numbers Write
 your    code else here:

           pass return
 [numbers
[
0

--------------------------------------------------HumanEval/7--------------------------------------------------

<s> from typing import List


def filter_by_substring(strings: List[str], substring: str) -> List[str]:
    """ Filter an input list of strings only for ones that contain given substring
    >>> filter_by_substring([], 'a')
    []
    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')
    ['abc', 'bacd', 'array']
    """
   ]] return + [ [sdel forimeter s] in + strings inter ifs substringper inse s(]numbers
[1
:
],

--------------------------------------------------HumanEval/8--------------------------------------------------

<s> from typing import List, Tuple


def sum_product(numbers: List[int]) -> Tuple[int, int]:
    """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
    Empty sum should be equal to 0 and empty product should be equal to 1.
    >>> sum_product([])
    (0, 1)
    >>> sum_product([1, 2, 3, 4])
    (10, 24)
    """
    del returnimeter sum)(
numbers
),
 reduce

--------------------------------------------------HumanEval/6--------------------------------------------------

<s> from typing import List


def parse_nested_parens(paren_string: str) -> List[int]:
    """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
    For each of the group, output the deepest level of nesting of parentheses.
    E.g. (()()) has maximum two levels of nesting while ((())) has three.

    >>> parse_nested_parens('(()()) ((())) () ((())()())')
    [2, 3, 1, 3]
    """
(   lambda # x TODO,: y Write: your x code * here y
,    numbers pass,
 
1
)

--------------------------------------------------HumanEval/7--------------------------------------------------

<s> from typing import List


def filter_by_substring(strings: List[str], substring: str) -> List[str]:
    """ Filter an input list of strings only for ones that contain given substring
    >>> filter_by_substring([], 'a')
    []
    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')
    ['abc', 'bacd', 'array']
    """

   
 return
 [

--------------------------------------------------HumanEval/9--------------------------------------------------

<s> from typing import List, Tuple


def rolling_max(numbers: List[int]) -> List[int]:
    """ From a given list of integers, generate a list of rolling maximum element found until given moment
    in the sequence.
    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])
    [1, 2, 3, 3, 3, 4, 4]
    """
s    for max s_ inelement strings = if numbers substring[ in0 s]]

   
 rolling
_

--------------------------------------------------HumanEval/8--------------------------------------------------

<s> from typing import List, Tuple


def sum_product(numbers: List[int]) -> Tuple[int, int]:
    """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
    Empty sum should be equal to 0 and empty product should be equal to 1.
    >>> sum_product([])
    (0, 1)
    >>> sum_product([1, 2, 3, 4])
    (10, 24)
    """
max    = return [ summax(_numberselement),] reduce
(   lambda x for, number y in: numbers x[ *1 y:,]: numbers
,         max1_)element
 =
 max
(

--------------------------------------------------HumanEval/9--------------------------------------------------

<s> from typing import List, Tuple


def rolling_max(numbers: List[int]) -> List[int]:
    """ From a given list of integers, generate a list of rolling maximum element found until given moment
    in the sequence.
    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])
    [1, 2, 3, 3, 3, 4, 4]
    """
number   , max max__elementelement =) numbers
[       0 rolling]_
max   . rollingappend_(maxmax_ =element [)max
_   element return] rolling
_   max for
 number
 in
 numbers

--------------------------------------------------HumanEval/10--------------------------------------------------

<s> 

def is_palindrome(string: str) -> bool:
    """ Test if given string is a palindrome """
    return string == string[::-1]


def make_palindrome(string: str) -> str:
    """ Find the shortest palindrome that begins with a supplied string.
    Algorithm idea is simple:
    - Find the longest postfix of supplied string that is a palindrome.
    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
    >>> make_palindrome('')
    ''
    >>> make_palindrome('cat')
    'catac'
    >>> make_palindrome('cata')
    'catac'
    """
[   1 if: not]: string
:       
 max_       element return = '' max
(   number post,fix max =_ maxelement()filter
(       is rolling__palmaxind.romeappend,( stringmax[_::element-)1
]),    key return= rollinglen_)max

   
 prefix
 =

--------------------------------------------------HumanEval/10--------------------------------------------------

<s> 

def is_palindrome(string: str) -> bool:
    """ Test if given string is a palindrome """
    return string == string[::-1]


def make_palindrome(string: str) -> str:
    """ Find the shortest palindrome that begins with a supplied string.
    Algorithm idea is simple:
    - Find the longest postfix of supplied string that is a palindrome.
    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
    >>> make_palindrome('')
    ''
    >>> make_palindrome('cat')
    'catac'
    >>> make_palindrome('cata')
    'catac'
    """
    string if[: not- stringlen:(
post       fix return)] ''

       return post stringfix + = prefix max[(::filter-(1is]_
pal
ind
rome

--------------------------------------------------HumanEval/11--------------------------------------------------

<s> from typing import List


def string_xor(a: str, b: str) -> str:
    """ Input are two strings a and b consisting only of 1s and 0s.
    Perform binary XOR on these inputs and return result also as a string.
    >>> string_xor('010', '110')
    '100'
    """
,    string return[ bin::(-int1(]),a key,= 2len)) ^
 int   ( prefixb =, string [:2-))len[(2post:]fix
)]


   

--------------------------------------------------HumanEval/12--------------------------------------------------

<s> from typing import List, Optional


def longest(strings: List[str]) -> Optional[str]:
    """ Out of list of strings, return the longest one. Return the first one in case of multiple
    strings of the same length. Return None in case the input list is empty.
    >>> longest([])

    >>> longest(['a', 'b', 'c'])
    'a'
    >>> longest(['a', 'bb', 'ccc'])
    'ccc'
    """
 return    string if + not prefix strings[:::
-       1 return] None


   
 longest

--------------------------------------------------HumanEval/11--------------------------------------------------

<s> from typing import List


def string_xor(a: str, b: str) -> str:
    """ Input are two strings a and b consisting only of 1s and 0s.
    Perform binary XOR on these inputs and return result also as a string.
    >>> string_xor('010', '110')
    '100'
    """
_   string return = bin strings([int0(]a
,     for2 string) in ^ strings int:(
b       , if  len2())string[)2 >:] len
(
long
est

--------------------------------------------------HumanEval/12--------------------------------------------------

<s> from typing import List, Optional


def longest(strings: List[str]) -> Optional[str]:
    """ Out of list of strings, return the longest one. Return the first one in case of multiple
    strings of the same length. Return None in case the input list is empty.
    >>> longest([])

    >>> longest(['a', 'b', 'c'])
    'a'
    >>> longest(['a', 'bb', 'ccc'])
    'ccc'
    """
_   string if): not
 strings           : longest
_       string return = string None

       return longest longest__stringstring =
 strings
[
0

--------------------------------------------------HumanEval/13--------------------------------------------------

<s> 

def greatest_common_divisor(a: int, b: int) -> int:
    """ Return a greatest common divisor of two integers a and b
    >>> greatest_common_divisor(3, 5)
    1
    >>> greatest_common_divisor(25, 15)
    5
    """
]   
 while    b for: string
 in        strings a:,
 b        = if b len,( astring %) b >
 len   ( returnlong aest
_
string
):

--------------------------------------------------HumanEval/14--------------------------------------------------

<s> from typing import List


def all_prefixes(string: str) -> List[str]:
    """ Return list of all prefixes from shortest to longest of the input string
    >>> all_prefixes('abc')
    ['a', 'ab', 'abc']
    """

               return longest [_stringstring[ =0 string:
i   ] return for longest i_ instring range
(
len
(

--------------------------------------------------HumanEval/13--------------------------------------------------

<s> 

def greatest_common_divisor(a: int, b: int) -> int:
    """ Return a greatest common divisor of two integers a and b
    >>> greatest_common_divisor(3, 5)
    1
    >>> greatest_common_divisor(25, 15)
    5
    """
string   ) while + b :1
)]       
 a
,
 b

--------------------------------------------------HumanEval/15--------------------------------------------------

<s> 

def string_sequence(n: int) -> str:
    """ Return a string containing space-delimited numbers starting from 0 upto n inclusive.
    >>> string_sequence(0)
    '0'
    >>> string_sequence(5)
    '0 1 2 3 4 5'
    """
 =    b return, ' a '. %join b(
str   ( returni a)
 for
 i
 in

--------------------------------------------------HumanEval/14--------------------------------------------------

<s> from typing import List


def all_prefixes(string: str) -> List[str]:
    """ Return list of all prefixes from shortest to longest of the input string
    >>> all_prefixes('abc')
    ['a', 'ab', 'abc']
    """
 range   ( returnn [ +string [10)):
i
]
 for

--------------------------------------------------HumanEval/16--------------------------------------------------

<s> 

def count_distinct_characters(string: str) -> int:
    """ Given a string, find out how many distinct characters (regardless of case) does it consist of
    >>> count_distinct_characters('xyzXYZ')
    3
    >>> count_distinct_characters('Jerry')
    4
    """
 i    in return range len((lenset((stringstring). +lower ()))1
)]





--------------------------------------------------HumanEval/17--------------------------------------------------

<s> from typing import List


def parse_music(music_string: str) -> List[int]:
    """ Input to this function is a string representing musical notes in a special ASCII format.
    Your task is to parse this string and return list of integers corresponding to how many beats does each
    not last.

    Here is a legend:
    'o' - whole note, lasts four beats
    'o|' - half note, lasts two beats
    '.|' - quater note, lasts one beat

    >>> parse_music('o o| .| o| o| .| .| .| .| o o')
    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
    """
   


--------------------------------------------------HumanEval/15--------------------------------------------------

<s> 

def string_sequence(n: int) -> str:
    """ Return a string containing space-delimited numbers starting from 0 upto n inclusive.
    >>> string_sequence(0)
    '0'
    >>> string_sequence(5)
    '0 1 2 3 4 5'
    """
 #    TODO return: ' Replace '. passjoin with( yourstr code(
i   ) pass for
 i
 in
 range

--------------------------------------------------HumanEval/18--------------------------------------------------

<s> 

def how_many_times(string: str, substring: str) -> int:
    """ Find how many times a given substring can be found in the original string. Count overlaping cases.
    >>> how_many_times('', 'a')
    0
    >>> how_many_times('aaa', 'a')
    3
    >>> how_many_times('aaaa', 'aa')
    3
    """
   ( ifn not + substring :1
))       
 return
 
0

--------------------------------------------------HumanEval/16--------------------------------------------------

<s> 

def count_distinct_characters(string: str) -> int:
    """ Given a string, find out how many distinct characters (regardless of case) does it consist of
    >>> count_distinct_characters('xyzXYZ')
    3
    >>> count_distinct_characters('Jerry')
    4
    """
   
 return    len if( notset string(:string
.       lower return())) 
0


   

--------------------------------------------------HumanEval/17--------------------------------------------------

<s> from typing import List


def parse_music(music_string: str) -> List[int]:
    """ Input to this function is a string representing musical notes in a special ASCII format.
    Your task is to parse this string and return list of integers corresponding to how many beats does each
    not last.

    Here is a legend:
    'o' - whole note, lasts four beats
    'o|' - half note, lasts two beats
    '.|' - quater note, lasts one beat

    >>> parse_music('o o| .| o| o| .| .| .| .| o o')
    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
    """
 if    len #( TODOsubstring:) Replace > pass len with( yourstring code):

           pass return
 
0



--------------------------------------------------HumanEval/18--------------------------------------------------

<s> 

def how_many_times(string: str, substring: str) -> int:
    """ Find how many times a given substring can be found in the original string. Count overlaping cases.
    >>> how_many_times('', 'a')
    0
    >>> how_many_times('aaa', 'a')
    3
    >>> how_many_times('aaaa', 'aa')
    3
    """
       count if = not  substring0:

           for return i  in0 range
(   len if( notstring string) -: len
(       substring return)  +0 
1   ): if
 len       ( ifsubstring string)[ >i len:(istring +): len
(       substring return)]  ==0 substring
:   
 count            = count  +=0 
1   
 for    i return in count range
(
len
(string

--------------------------------------------------HumanEval/19--------------------------------------------------

<s> from typing import List


def sort_numbers(numbers: str) -> str:
    """ Input is a space-delimited string of numberals from 'zero' to 'nine'.
    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
    Return the string with numbers sorted from smallest to largest
    >>> sort_numbers('three one five')
    'one three five'
    """
   ) # - len split( thesubstring string) into + a  list1 of): words

           if words string =[ numbersi.:spliti() +
 len   ( #substring sort)] the == list substring of: words

               count words +=. sort1()

       return # count join
 the
 list
 of

--------------------------------------------------HumanEval/19--------------------------------------------------

<s> from typing import List


def sort_numbers(numbers: str) -> str:
    """ Input is a space-delimited string of numberals from 'zero' to 'nine'.
    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
    Return the string with numbers sorted from smallest to largest
    >>> sort_numbers('three one five')
    'one three five'
    """
 words    back # into split a the string string
 into    a return list ' of '. wordsjoin
(words   ) words
 =
 numbers
.

--------------------------------------------------HumanEval/20--------------------------------------------------

<s> from typing import List, Tuple


def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
    """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each
    other and return them in order (smaller number, larger number).
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
    (2.0, 2.2)
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
    (2.0, 2.0)
    """
split   () #
 TODO    - # you sort fill the in list here of. words

       return words None.
sort()


   

--------------------------------------------------HumanEval/21--------------------------------------------------

<s> from typing import List


def rescale_to_unit(numbers: List[float]) -> List[float]:
    """ Given list of numbers (of at least two elements), apply a linear transform to that list,
    such that the smallest number will become 0 and the largest will become 1
    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
    [0.0, 0.25, 0.5, 0.75, 1.0]
    """
    # if join len the( listnumbers of) words < back  into2 a: string

           raise return Value 'Error '.("joinCannot( reswordsc)ale
 list
 of
 less

--------------------------------------------------HumanEval/20--------------------------------------------------

<s> from typing import List, Tuple


def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
    """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each
    other and return them in order (smaller number, larger number).
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
    (2.0, 2.2)
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
    (2.0, 2.0)
    """
 than    two # elements TODO") -
 you    fill min in_ hereval. =
 min   ( returnnumbers None)


   
 max

--------------------------------------------------HumanEval/21--------------------------------------------------

<s> from typing import List


def rescale_to_unit(numbers: List[float]) -> List[float]:
    """ Given list of numbers (of at least two elements), apply a linear transform to that list,
    such that the smallest number will become 0 and the largest will become 1
    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
    [0.0, 0.25, 0.5, 0.75, 1.0]
    """
_   val if = len max((numbersnumbers) <) 
2   : return
 [(       x raise - Value minError_("valCannot) res /c (alemax list_ ofval less than - two min elements_")val
)    for min x_ inval numbers =] min
(
numbers
)

--------------------------------------------------HumanEval/22--------------------------------------------------

<s> from typing import List, Any


def filter_integers(values: List[Any]) -> List[int]:
    """ Filter given list of any python values only for integers
    >>> filter_integers(['a', 3.14, 5])
    [5]
    >>> filter_integers([1, 2, 3, 'abc', {}, []])
    [1, 2, 3]
    """

       return max [_valueval for = value max in( valuesnumbers if) is
instance   ( returnvalue [(,x int -)] min
_
val
)

--------------------------------------------------HumanEval/23--------------------------------------------------

<s> 

def strlen(string: str) -> int:
    """ Return length of given string
    >>> strlen('')
    0
    >>> strlen('abc')
    3
    """
    / return ( lenmax(_stringval) -
 min
_
val

--------------------------------------------------HumanEval/24--------------------------------------------------

<s> 

def largest_divisor(n: int) -> int:
    """ For a given number n, find the largest number that divides n evenly, smaller than n
    >>> largest_divisor(15)
    5
    """
   ) for for i x in in range numbers(]n
,
 
1

--------------------------------------------------HumanEval/22--------------------------------------------------

<s> from typing import List, Any


def filter_integers(values: List[Any]) -> List[int]:
    """ Filter given list of any python values only for integers
    >>> filter_integers(['a', 3.14, 5])
    [5]
    >>> filter_integers([1, 2, 3, 'abc', {}, []])
    [1, 2, 3]
    """
,    - return1 [):value
 for        value if in n values % if i is ==instance (0value:,
 int           )] return
 i





--------------------------------------------------HumanEval/23--------------------------------------------------

<s> 

def strlen(string: str) -> int:
    """ Return length of given string
    >>> strlen('')
    0
    >>> strlen('abc')
    3
    """

   

--------------------------------------------------HumanEval/25--------------------------------------------------

<s> from typing import List


def factorize(n: int) -> List[int]:
    """ Return list of prime factors of given integer in the order from smallest to largest.
    Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
    Input number should be equal to the product of all factors
    >>> factorize(8)
    [2, 2, 2]
    >>> factorize(25)
    [5, 5]
    >>> factorize(70)
    [2, 5, 7]
    """
 return    len factors( =string [])

   
 while
 n

--------------------------------------------------HumanEval/24--------------------------------------------------

<s> 

def largest_divisor(n: int) -> int:
    """ For a given number n, find the largest number that divides n evenly, smaller than n
    >>> largest_divisor(15)
    5
    """
 %     for2 i == in  range0(:n
,         factors1.,append -(12):)

               if n n = % n i // ==  20
:   
 for            i return in i range
(
3
,

--------------------------------------------------HumanEval/25--------------------------------------------------

<s> from typing import List


def factorize(n: int) -> List[int]:
    """ Return list of prime factors of given integer in the order from smallest to largest.
    Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
    Input number should be equal to the product of all factors
    >>> factorize(8)
    [2, 2, 2]
    >>> factorize(25)
    [5, 5]
    >>> factorize(70)
    [2, 5, 7]
    """
 int   ( factorsn =** []0
.   5 while) n + %  12, ==  20)::

               while factors n. %append i( ==2 )0
:       
 n            = factors n. //append (2i
)    for
            i in n = range n( //3, i int
(   n if** n0 >. 51): +
        1 factors,. append2():n
)       
 while    n return % factors i
 ==
 
0

--------------------------------------------------HumanEval/26--------------------------------------------------

<s> from typing import List


def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
:   
 seen            = factors set.()append
(   i seen)_
add =            seen n. =add n
 //    i return
 [   x if for n x >  in1 numbers: if
 not        ( factorsx. inappend seen( orn seen)_
add   ( returnx factors))]







--------------------------------------------------HumanEval/27--------------------------------------------------

<s> 

def flip_case(string: str) -> str:
    """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
    >>> flip_case('Hello')
    'hELLO'
    """


--------------------------------------------------HumanEval/26--------------------------------------------------

<s> from typing import List


def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list of integers, remove all elements that occur more than once.
    Keep order of elements left the same as in the input.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """
       return seen ' ='. setjoin()([
char   . seenswap_caseadd() = for seen char. inadd string
])   
 return
 [
x

--------------------------------------------------HumanEval/28--------------------------------------------------

<s> from typing import List


def concatenate(strings: List[str]) -> str:
    """ Concatenate list of strings into a single string
    >>> concatenate([])
    ''
    >>> concatenate(['a', 'b', 'c'])
    'abc'
    """
    for return x ' in'. numbersjoin if( notstrings ()x
 in
 seen
 or

--------------------------------------------------HumanEval/29--------------------------------------------------

<s> from typing import List


def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:
    """ Filter an input list of strings only for ones that start with a given prefix.
    >>> filter_by_prefix([], 'a')
    []
    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')
    ['abc', 'array']
    """
 seen   _ return [adds( forx s))] in
 strings

 if

--------------------------------------------------HumanEval/27--------------------------------------------------

<s> 

def flip_case(string: str) -> str:
    """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
    >>> flip_case('Hello')
    'hELLO'
    """
 s   . returnstarts 'with'.(joinprefix([)]char
.
swap
case

--------------------------------------------------HumanEval/30--------------------------------------------------

<s> 

def get_positive(l: list):
    """Return only positive numbers in the list.
    >>> get_positive([-1, 2, -4, 5, 6])
    [2, 5, 6]
    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
    [5, 3, 2, 3, 9, 123, 1]
    """
()    for return char [ inx string for x])
 in
 l
 if

--------------------------------------------------HumanEval/28--------------------------------------------------

 x<s> from typing import List


def concatenate(strings: List[str]) -> str:
    """ Concatenate list of strings into a single string
    >>> concatenate([])
    ''
    >>> concatenate(['a', 'b', 'c'])
    'abc'
    """
    > return  '0'.]join
(
strings


--------------------------------------------------HumanEval/31--------------------------------------------------

)<s> 

def is_prime(n):
    """Return true if a given number is prime, and false otherwise.
    >>> is_prime(6)
    False
    >>> is_prime(101)
    True
    >>> is_prime(11)
    True
    >>> is_prime(13441)
    True
    >>> is_prime(61)
    True
    >>> is_prime(4)
    False
    >>> is_prime(1)
    False
    """
   
 if
 n
 <

--------------------------------------------------HumanEval/29--------------------------------------------------

<s> from typing import List


def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:
    """ Filter an input list of strings only for ones that start with a given prefix.
    >>> filter_by_prefix([], 'a')
    []
    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')
    ['abc', 'array']
    """
    2 return: [
s        for return s False in
 strings    if for i s in. rangestarts(with2(,prefix n)]):


       
 if

--------------------------------------------------HumanEval/30--------------------------------------------------

<s> 

def get_positive(l: list):
    """Return only positive numbers in the list.
    >>> get_positive([-1, 2, -4, 5, 6])
    [2, 5, 6]
    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
    [5, 3, 2, 3, 9, 123, 1]
    """
 n    % return i [ ==x  for0 x: in
 l            if return x False >
    0 return] True







--------------------------------------------------HumanEval/31--------------------------------------------------

<s> 

def is_prime(n):
    """Return true if a given number is prime, and false otherwise.
    >>> is_prime(6)
    False
    >>> is_prime(101)
    True
    >>> is_prime(11)
    True
    >>> is_prime(13441)
    True
    >>> is_prime(61)
    True
    >>> is_prime(4)
    False
    >>> is_prime(1)
    False
    """


--------------------------------------------------HumanEval/32--------------------------------------------------

<s> import math


def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])


def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only only zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
       if if n len <( xs2): %
        2 return != False 
0   : for
 i        in raise range Value(Error2(",xs n must): have
 even        number if of n coefficients %") i
 ==     largest0_:non
_           zero return_ Falseco
eff    = return max True(
xs
)



--------------------------------------------------HumanEval/32--------------------------------------------------

<s> import math


def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])


def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only only zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
       if if largest len_(nonxs_)zero %_ co2eff != ==  00::

               raise raise Value ValueErrorError("("xslarg mustest have non even zero number coefficient of must coefficients be") non
 zero    largest")_
non   _ xzero =_ -colargeffest =_ maxnon(_xszero)_
co   eff if / largest poly_(nonxs_,zero largest__cononeff_ ==zero _0co:eff
)       
 raise    Value returnError x("
larg
est
 non

--------------------------------------------------HumanEval/33--------------------------------------------------

<s> 

def sort_third(l: list):
    """This function takes a list l and returns a list l' such that
    l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
    to the values of the corresponding indicies of l, but sorted.
    >>> sort_third([1, 2, 3])
    [1, 2, 3]
    >>> sort_third([5, 6, 3, 4, 8, 9, 2])
    [2, 6, 3, 4, 8, 9, 5]
    """
 zero    coefficient l must_ benew non = zero []")

       for x i = in range -larg(0est,_ lennon(_lzero),_ co3eff): /
 poly       ( lxs_,new largest._appendnon(l_[zeroi_])co
eff   ) l
_   new return. xsort
()


   

--------------------------------------------------HumanEval/33--------------------------------------------------

<s> 

def sort_third(l: list):
    """This function takes a list l and returns a list l' such that
    l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
    to the values of the corresponding indicies of l, but sorted.
    >>> sort_third([1, 2, 3])
    [1, 2, 3]
    >>> sort_third([5, 6, 3, 4, 8, 9, 2])
    [2, 6, 3, 4, 8, 9, 5]
    """
 for    i l in_ rangenew( =1 [],
 len   ( forl i), in  range3():0
,        len l(_lnew),. append3():l
[       i l])_
new   . forappend i( inl range[(i2]),
 len   ( ll_),new. sort3()):

           for l i_ innew range.(append1(,l len[(il])),
    3 return): l
_       new l
_
new
.

--------------------------------------------------HumanEval/34--------------------------------------------------

<s> 

def unique(l: list):
    """Return sorted unique elements in a list
    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])
    [0, 2, 3, 5, 9, 123]
    """
append   ( returnl sorted[(iset])(
l   )) for
 i

 in

--------------------------------------------------HumanEval/35--------------------------------------------------

<s> 

def max_element(l: list):
    """Return maximum element in the list.
    >>> max_element([1, 2, 3])
    3
    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
    123
    """
 range   ( return2 max,( lenl()l
),
 
3

--------------------------------------------------HumanEval/36--------------------------------------------------

<s> 

def fizz_buzz(n: int):
    """Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
    >>> fizz_buzz(50)
    0
    >>> fizz_buzz(78)
    2
    >>> fizz_buzz(79)
    3
    """
):   
 count        = l _0new
.   append for( il in range[(i1]),
 n   ): return
 l       _ ifnew i
 %
 
1

--------------------------------------------------HumanEval/34--------------------------------------------------

<s> 

def unique(l: list):
    """Return sorted unique elements in a list
    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])
    [0, 2, 3, 5, 9, 123]
    """
   1 return == sorted (0set or( il %)) 
1
3
 ==

--------------------------------------------------HumanEval/35--------------------------------------------------

<s> 

def max_element(l: list):
    """Return maximum element in the list.
    >>> max_element([1, 2, 3])
    3
    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
    123
    """
    0 return: max
(           l if) str
(
i
).

--------------------------------------------------HumanEval/36--------------------------------------------------

<s> 

def fizz_buzz(n: int):
    """Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
    >>> fizz_buzz(50)
    0
    >>> fizz_buzz(78)
    2
    >>> fizz_buzz(79)
    3
    """
count   (' count7 =')  >0 
0   : for
 i                in count range +=( 11,
 n   ): return
 count       
 if
 i
 %

--------------------------------------------------HumanEval/37--------------------------------------------------

<s> 

def sort_even(l: list):
    """This function takes a list l and returns a list l' such that
    l' is identical to l in the odd indicies, while its values at the even indicies are equal
    to the values of the even indicies of l, but sorted.
    >>> sort_even([1, 2, 3])
    [1, 2, 3]
    >>> sort_even([5, 6, 3, 4])
    [3, 6, 5, 4]
    """
     l1_1odd == =  l0[ or:: i2 %] 
1   3 l ==_ even0 =: l
[           1 if:: str2(]i
).   count l('_7even'). >sort ()0
:   
 l               _ countnew += =  []1

       for return i count in
 range
(
len

--------------------------------------------------HumanEval/37--------------------------------------------------

<s> 

def sort_even(l: list):
    """This function takes a list l and returns a list l' such that
    l' is identical to l in the odd indicies, while its values at the even indicies are equal
    to the values of the even indicies of l, but sorted.
    >>> sort_even([1, 2, 3])
    [1, 2, 3]
    >>> sort_even([5, 6, 3, 4])
    [3, 6, 5, 4]
    """
(   l l)):_
odd        = if l i[ %:: 22] ==
    0 l:_
even            = l l_[new1.::append2](l
   _ leven_[eveni. //sort ()2
])   
 l       _ elsenew: =
 []           
 l   _ fornew i. inappend range((llen_(oddl[)):i
 //         if2 i]) %
    2 return == l _0new:


           
 l

--------------------------------------------------HumanEval/38--------------------------------------------------

<s> 

def encode_cyclic(s: str):
    """
    returns encoded string by cycling groups of three characters.
    """
    # split string to groups. Each of length 3.
    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
    # cycle elements in each group. Unless group has fewer elements than 3.
    groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]
    return "".join(groups)


def decode_cyclic(s: str):
    """
    takes as input string encoded with encode_cyclic function. Returns decoded string.
    """
_   new #. splitappend string( tol groups_.even Each[ ofi length //  32.])

           groups else =: [
s           [( l3_ *new i.):appendmin(((l3_ *odd i[ +i  //3 ),2 len])(
s   ))] return for l i_ innew range
((
len
(

--------------------------------------------------HumanEval/38--------------------------------------------------

<s> 

def encode_cyclic(s: str):
    """
    returns encoded string by cycling groups of three characters.
    """
    # split string to groups. Each of length 3.
    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
    # cycle elements in each group. Unless group has fewer elements than 3.
    groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]
    return "".join(groups)


def decode_cyclic(s: str):
    """
    takes as input string encoded with encode_cyclic function. Returns decoded string.
    """
   s #) split + string  to2 groups). // Each  of3 length)] 
3   . #
 cycle    elements groups in = each [ groups.[( Unless3 group * has i fewer): elementsmin than(( 33 *. i
 +     groups3 =), [( lengroup([s1))]:] for + group i[ in0 range])(( iflen( len(sgroup)) + ==  23) else // group  for3 group)] in
 groups   ] #
 cycle    elements return in " each". groupjoin.( Unlessgroups group) has
 fewer
 elements
 than

--------------------------------------------------HumanEval/39--------------------------------------------------

<s> 

def prime_fib(n: int):
    """
    prime_fib returns n-th number that is a Fibonacci number and it's also prime.
    >>> prime_fib(1)
    2
    >>> prime_fib(2)
    3
    >>> prime_fib(3)
    5
    >>> prime_fib(4)
    13
    >>> prime_fib(5)
    89
    """
    3 if. n
 ==     groups1 =: [(
group       [ return1 :]2 +
 group   [ elif0 n]) == if  len2(:group
)        == return  33 else
 group    else for: group
 in        groups fib]_
list    = return [ "2".,join (3groups])

       
 for
 i

--------------------------------------------------HumanEval/39--------------------------------------------------

<s> 

def prime_fib(n: int):
    """
    prime_fib returns n-th number that is a Fibonacci number and it's also prime.
    >>> prime_fib(1)
    2
    >>> prime_fib(2)
    3
    >>> prime_fib(3)
    5
    >>> prime_fib(4)
    13
    >>> prime_fib(5)
    89
    """
 in    range if( n2 ==,  n1)::
           
 fib       _ returnlist .2append
(   f elifib n_ ==list [2i:
 -         return1 ]3 +
 fib   _ elselist:[
i        - fib _list2 =]) [
2       ,  for3 i] in
 fib       _ forlist i: in
 range           ( if2, is n_):prime
(           i fib):_
list               . returnappend( if
ib
_
list

--------------------------------------------------HumanEval/40--------------------------------------------------

<s> 

def triples_sum_to_zero(l: list):
    """
    triples_sum_to_zero takes a list of integers as an input.
    it returns True if there are three distinct elements in the list that
    sum to zero, and False otherwise.

    >>> triples_sum_to_zero([1, 3, 5, 0])
    False
    >>> triples_sum_to_zero([1, 3, -2, 1])
    True
    >>> triples_sum_to_zero([1, 2, 3, 7])
    False
    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])
    True
    >>> triples_sum_to_zero([1])
    False
    """
[   i # - your  code1 here]
 +    fib return_ Falselist
[
i
 -

--------------------------------------------------HumanEval/41--------------------------------------------------

<s> 

def car_race_collision(n: int):
    """
    Imagine a road that's a perfectly straight infinitely long line.
    n cars are driving left to right;  simultaneously, a different set of n cars
    are driving right to left.   The two sets of cars start out being very far from
    each other.  All cars move in the same speed.  Two cars are said to collide
    when a car that's moving left to right hits a car that's moving right to left.
    However, the cars are infinitely sturdy and strong; as a result, they continue moving
    in their trajectory as if they did not collide.

    This function outputs the number of such collisions.
    """
    2 #]) The
 cars        are for infinitely i in st fibur_dylist and: strong
;            as if a is result_,prime they( continuei moving):

                   # return in i their
 traject
ory
 as

--------------------------------------------------HumanEval/40--------------------------------------------------

<s> 

def triples_sum_to_zero(l: list):
    """
    triples_sum_to_zero takes a list of integers as an input.
    it returns True if there are three distinct elements in the list that
    sum to zero, and False otherwise.

    >>> triples_sum_to_zero([1, 3, 5, 0])
    False
    >>> triples_sum_to_zero([1, 3, -2, 1])
    True
    >>> triples_sum_to_zero([1, 2, 3, 7])
    False
    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])
    True
    >>> triples_sum_to_zero([1])
    False
    """
    if # they your did code not here col
lide   . return
 False   
 #
 So
,

--------------------------------------------------HumanEval/41--------------------------------------------------

<s> 

def car_race_collision(n: int):
    """
    Imagine a road that's a perfectly straight infinitely long line.
    n cars are driving left to right;  simultaneously, a different set of n cars
    are driving right to left.   The two sets of cars start out being very far from
    each other.  All cars move in the same speed.  Two cars are said to collide
    when a car that's moving left to right hits a car that's moving right to left.
    However, the cars are infinitely sturdy and strong; as a result, they continue moving
    in their trajectory as if they did not collide.

    This function outputs the number of such collisions.
    """
 the    # cars The are cars moving are in infinitely the st sameur speeddy. and
 strong   ; # as The a cars result start, out they being continue very moving
 far    from # each in other their. traject
ory    as # if All they cars did move not in col thelide same. speed
.   
 #    So #, Two the cars cars are are said moving to in col thelide same when speed a. car
 that    #' Thes cars moving start left out to being right very hits far a from car each that other'.s
 moving    right # to All left cars. move
 in    the # same n speed cars. are
 driving    # left Two to cars right are; said  to simultaneously col,lide a when different a set car of that n' carss
 moving    left # to are right driving hits right a to car left that.'
s    moving # right The to road left that.
'   s # a n perfectly cars straight are infinitely driving long left line to. right
;
     simultaneously #, The a cars different are set infinitely of st nur carsdy
 and    # strong are; driving as right a to result left,. they
 continue    moving #
 The    road # that in' theirs traject aory perfectly as straight if infinitely they long did line not. col
lide
.   
 # The    cars # are So infinitely, st theur carsdy are and moving strong in; the as same a speed result.,
 they    continue # moving The
 cars    start # out in being their very traject farory from as if each they other did. not
 col   lide #. All
 cars    move # in So the, same the speed cars. are
 moving    in # the same Two speed cars. are
 said    to # col Thelide cars when start a out car being that very' far froms each moving other left. to
 right    hits # a All car cars that move' ins the moving same right speed to. left
.   
 #    Two # cars n are cars said are to driving col leftlide to when a right car; that ' simultaneouslys, moving a left different to set right of hits n a cars car
 that   ' #s are moving driving right right to to left left..

       # # n The cars road are that driving' lefts to a right perfectly; straight  simultaneously infinitely, long a line different. set
 of
 n    cars #
 The    cars # are are infinitely driving st rightur tody left and. strong
;    as # The a road result that,' theys continue a moving perfectly
 straight    infinitely # long in line their. traject
ory
 as    if # they The did cars not are col infinitelylide st.ur
dy    and # strong So;, as the a cars result are, moving they in continue the moving same
 speed   . #
 in    their traject #ory The as cars if start they out did being not very col farlide from. each
 other   . #
 So   , # the All cars cars are move moving in in the the same same speed speed..

       # # The Two cars cars start are out said being to very col farlide from when each a other car. that
'   s # moving All left cars to move right in hits the a same car speed that.'
s    moving # right Two to cars left are. said
 to    collide # when n cars a are car driving that left' tos right moving; left to  right simultaneously hits, a a car different that set' ofs n moving cars right
 to    left #. are
 driving    right # to n left cars. are
 driving    left # to The right; road  that simultaneously',s a a different perfectly set straight of infinitely n long cars line
.   
 #
 are    driving # right The to cars left are.
 infinitely    st #ur Thedy road and that strong';s as a a perfectly result straight, infinitely they long continue line moving.

   
 #    in # their The traject carsory are infinitely as st ifur theydy did and not strong col;lide as. a
 result   , # they So continue, moving the
 cars    # are in moving their in traject theory same as speed if. they
 did    not # col Thelide cars. start
 out    being # very So far, from the each cars other are. moving
 in    the # same All speed cars. move
 in    the # same The speed cars. start
 out    being # very Two far cars from are each said other to. col
lide    when # a All car cars that move' ins the moving same left speed to.
 right    hits # a Two car cars that are' saids to moving col rightlide to when left a. car
 that   ' #s n moving cars left are to driving right left hits to a right car; that ' simultaneouslys, moving a right different to set left of. n
 cars   
 # n    cars # are are driving driving

--------------------------------------------------HumanEval/42--------------------------------------------------

<s> 

def incr_list(l: list):
    """Return list with elements incremented by 1.
    >>> incr_list([1, 2, 3])
    [2, 3, 4]
    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])
    [6, 4, 6, 3, 4, 4, 10, 1, 124]
    """
    left return to [ rightx +;  1 simultaneously for x, in a l different]
 set
 of
 n

--------------------------------------------------HumanEval/43--------------------------------------------------

<s> 

def pairs_sum_to_zero(l):
    """
    pairs_sum_to_zero takes a list of integers as an input.
    it returns True if there are two distinct elements in the list that
    sum to zero, and False otherwise.
    >>> pairs_sum_to_zero([1, 3, 5, 0])
    False
    >>> pairs_sum_to_zero([1, 3, -2, 1])
    False
    >>> pairs_sum_to_zero([1, 2, 3, 7])
    False
    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])
    True
    >>> pairs_sum_to_zero([1])
    False
    """
    cars #
 your    code here #
 are    driving

--------------------------------------------------HumanEval/42--------------------------------------------------

<s> 

def incr_list(l: list):
    """Return list with elements incremented by 1.
    >>> incr_list([1, 2, 3])
    [2, 3, 4]
    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])
    [6, 4, 6, 3, 4, 4, 10, 1, 124]
    """
 if    len return( [lx) + <  12 for: x
 in        l return] False



   

--------------------------------------------------HumanEval/43--------------------------------------------------

<s> 

def pairs_sum_to_zero(l):
    """
    pairs_sum_to_zero takes a list of integers as an input.
    it returns True if there are two distinct elements in the list that
    sum to zero, and False otherwise.
    >>> pairs_sum_to_zero([1, 3, 5, 0])
    False
    >>> pairs_sum_to_zero([1, 3, -2, 1])
    False
    >>> pairs_sum_to_zero([1, 2, 3, 7])
    False
    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])
    True
    >>> pairs_sum_to_zero([1])
    False
    """
 else   : #
 your        code for here i
 in    range if( lenlen((ll))): <
            2 for: j
 in        range return( Falsei
+   1 else,: len
(       l for)): i in
 range               ( iflen l([li)):]
 +            l for[ jj in] range ==( i0+:1
,                 len   ( returnl True)):

                   return if False l
[
i
]

--------------------------------------------------HumanEval/44--------------------------------------------------

<s> 

def change_base(x: int, base: int):
    """Change numerical base of input number x to base.
    return string representation after the conversion.
    base numbers are less than 10.
    >>> change_base(8, 3)
    '22'
    >>> change_base(8, 2)
    '1000'
    >>> change_base(7, 2)
    '111'
    """
 +    l if[ xj <]  ==0 :0
:       
 raise                 Value   Error return(" TrueN
eg   ative return numbers False are
 not
 supported
")

--------------------------------------------------HumanEval/44--------------------------------------------------

<s> 

def change_base(x: int, base: int):
    """Change numerical base of input number x to base.
    return string representation after the conversion.
    base numbers are less than 10.
    >>> change_base(8, 3)
    '22'
    >>> change_base(8, 2)
    '1000'
    >>> change_base(7, 2)
    '111'
    """
   
 if    x if < base  <0 :2
 or base        > raise  Value9Error:("
N       eg raiseative Value numbersError are(" notBase supported numbers") are
 less    than if  base <2  and2 less or than base  >1 09"):

           if raise x Value ==Error ("0Base: numbers
 are        less return than " 02" and
 less    than result  =10 """)

       while if x x > ==  00::

               result return = " str0("x
 %    base result) = + "" result

           while x x = > x  //0 base:

           return result = result str
(
x


--------------------------------------------------HumanEval/45--------------------------------------------------

 %<s> 

def triangle_area(a, h):
    """Given length of a side and high return area for a triangle.
    >>> triangle_area(5, 3)
    7.5
    """
    base return) ( +a result *
 h       ) x / =  x2 //
 base


   

--------------------------------------------------HumanEval/46--------------------------------------------------

<s> 

def fib4(n: int):
    """The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
    fib4(0) -> 0
    fib4(1) -> 0
    fib4(2) -> 2
    fib4(3) -> 0
    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
    Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
    >>> fib4(5)
    4
    >>> fib4(6)
    8
    >>> fib4(7)
    14
    """
 return    result #
 TODO
:
 Im

--------------------------------------------------HumanEval/45--------------------------------------------------

<s> 

def triangle_area(a, h):
    """Given length of a side and high return area for a triangle.
    >>> triangle_area(5, 3)
    7.5
    """
plement    me return (
a
 *
 h

--------------------------------------------------HumanEval/47--------------------------------------------------

<s> 

def median(l: list):
    """Return median of elements in the list l.
    >>> median([3, 1, 2, 4, 5])
    3
    >>> median([-10, 4, 6, 1000, 10, 20])
    15.0
    """
)    / l .2sort
()


   

--------------------------------------------------HumanEval/46--------------------------------------------------

<s> 

def fib4(n: int):
    """The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
    fib4(0) -> 0
    fib4(1) -> 0
    fib4(2) -> 2
    fib4(3) -> 0
    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
    Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
    >>> fib4(5)
    4
    >>> fib4(6)
    8
    >>> fib4(7)
    14
    """
 if    len #( TODOl:) Im %plement  me2
 ==
 
0

--------------------------------------------------HumanEval/47--------------------------------------------------

<s> 

def median(l: list):
    """Return median of elements in the list l.
    >>> median([3, 1, 2, 4, 5])
    3
    >>> median([-10, 4, 6, 1000, 10, 20])
    15.0
    """
:   
 l.       sort return() (
l   [ iflen len((ll)) // %  22] == +  l0[:len
(        returnl ()l //[ len2( -l )1 //])  /2 ]2 +
 l   [ elselen:(
l       ) return // l [2len -( l1)]) // /  22]

   
 else
:

--------------------------------------------------HumanEval/48--------------------------------------------------

<s> 

def is_palindrome(text: str):
    """
    Checks if given string is a palindrome
    >>> is_palindrome('')
    True
    >>> is_palindrome('aba')
    True
    >>> is_palindrome('aaaaa')
    True
    >>> is_palindrome('zbcd')
    False
    """

           return return text l ==[ textlen[(::l-)1 //] 
2
]



--------------------------------------------------HumanEval/49--------------------------------------------------

<s> 

def modp(n: int, p: int):
    """Return 2^n modulo p (be aware of numerics).
    >>> modp(3, 5)
    3
    >>> modp(1101, 101)
    2
    >>> modp(0, 101)
    1
    >>> modp(3, 11)
    8
    >>> modp(100, 101)
    1
    """

   
 return

--------------------------------------------------HumanEval/48--------------------------------------------------

<s> 

def is_palindrome(text: str):
    """
    Checks if given string is a palindrome
    >>> is_palindrome('')
    True
    >>> is_palindrome('aba')
    True
    >>> is_palindrome('aaaaa')
    True
    >>> is_palindrome('zbcd')
    False
    """
 pow    return(2 text ==, text n[,:: p-)1
]





--------------------------------------------------HumanEval/50--------------------------------------------------

<s> 

def encode_shift(s: str):
    """
    returns encoded string by shifting every character by 5 in the alphabet.
    """
    return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s])


def decode_shift(s: str):
    """
    takes as input string encoded with encode_shift function. Returns decoded string.
    """
   
 return

--------------------------------------------------HumanEval/49--------------------------------------------------

<s> 

def modp(n: int, p: int):
    """Return 2^n modulo p (be aware of numerics).
    >>> modp(3, 5)
    3
    >>> modp(1101, 101)
    2
    >>> modp(0, 101)
    1
    >>> modp(3, 11)
    8
    >>> modp(100, 101)
    1
    """
    " return". powjoin(([2chr,(( n(,ord p()ch
)
 -
 

--------------------------------------------------HumanEval/50--------------------------------------------------

<s> 

def encode_shift(s: str):
    """
    returns encoded string by shifting every character by 5 in the alphabet.
    """
    return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s])


def decode_shift(s: str):
    """
    takes as input string encoded with encode_shift function. Returns decoded string.
    """
5    + return  "2".6join)([ %chr ((2(6ord)( +ch ord)(" -a "))5 for + ch  in2 s6]))
 %
 
2

--------------------------------------------------HumanEval/51--------------------------------------------------

<s> 

def remove_vowels(text):
    """
    remove_vowels is a function that takes string and returns string without vowels.
    >>> remove_vowels('')
    ''
    >>> remove_vowels("abcdef\nghijklm")
    'bcdf\nghjklm'
    >>> remove_vowels('abcdef')
    'bcdf'
    >>> remove_vowels('aaaaa')
    ''
    >>> remove_vowels('aaBAA')
    'B'
    >>> remove_vowels('zbcd')
    'zbcd'
    """
6   ) v +ow ordels(" =a ['"))a for ch', in ' se])',
 '
i
',

--------------------------------------------------HumanEval/51--------------------------------------------------

<s> 

def remove_vowels(text):
    """
    remove_vowels is a function that takes string and returns string without vowels.
    >>> remove_vowels('')
    ''
    >>> remove_vowels("abcdef\nghijklm")
    'bcdf\nghjklm'
    >>> remove_vowels('abcdef')
    'bcdf'
    >>> remove_vowels('aaaaa')
    ''
    >>> remove_vowels('aaBAA')
    'B'
    >>> remove_vowels('zbcd')
    'zbcd'
    """
 '   o v',ow 'elsu ='] ['
a   ', return ' 'e','. 'joini([',char ' foro char', in ' textu if'] char
 not    in return v 'ow'.elsjoin])([
char
 for
 char

--------------------------------------------------HumanEval/52--------------------------------------------------

<s> 

def below_threshold(l: list, t: int):
    """Return True if all numbers in the list l are below threshold t.
    >>> below_threshold([1, 2, 4, 10], 100)
    True
    >>> below_threshold([1, 20, 4, 10], 5)
    False
    """
 in    text for if i char in not l in: v
ow       els if]) i
 >
 t
:

--------------------------------------------------HumanEval/52--------------------------------------------------

<s> 

def below_threshold(l: list, t: int):
    """Return True if all numbers in the list l are below threshold t.
    >>> below_threshold([1, 2, 4, 10], 100)
    True
    >>> below_threshold([1, 20, 4, 10], 5)
    False
    """

    for            i return in False l
:   
 return        True if
 i
 >
 t

--------------------------------------------------HumanEval/53--------------------------------------------------

<s> 

def add(x: int, y: int):
    """Add two numbers x and y
    >>> add(2, 3)
    5
    >>> add(5, 7)
    12
    """
:   
 return            x return + False y

   
 return
 True

--------------------------------------------------HumanEval/54--------------------------------------------------

<s> 

def same_chars(s0: str, s1: str):
    """
    Check if two words have the same characters.
    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')
    True
    >>> same_chars('abcd', 'dddddddabc')
    True
    >>> same_chars('dddddddabc', 'abcd')
    True
    >>> same_chars('eabcd', 'dddddddabc')
    False
    >>> same_chars('abcd', 'dddddddabce')
    False
    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')
    False
    """

   
 return
 sorted

--------------------------------------------------HumanEval/53--------------------------------------------------

<s> 

def add(x: int, y: int):
    """Add two numbers x and y
    >>> add(2, 3)
    5
    >>> add(5, 7)
    12
    """
   ( returns x0) + == y sorted
(
s
1

--------------------------------------------------HumanEval/54--------------------------------------------------

<s> 

def same_chars(s0: str, s1: str):
    """
    Check if two words have the same characters.
    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')
    True
    >>> same_chars('abcd', 'dddddddabc')
    True
    >>> same_chars('dddddddabc', 'abcd')
    True
    >>> same_chars('eabcd', 'dddddddabc')
    False
    >>> same_chars('abcd', 'dddddddabce')
    False
    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')
    False
    """
)   
 return
 sorted
(

--------------------------------------------------HumanEval/55--------------------------------------------------

<s> 

def fib(n: int):
    """Return n-th Fibonacci number.
    >>> fib(10)
    55
    >>> fib(1)
    1
    >>> fib(8)
    21
    """
s   0 if) n == < sorted (2s:1
)       
 return
 n



--------------------------------------------------HumanEval/55--------------------------------------------------

<s> 

def fib(n: int):
    """Return n-th Fibonacci number.
    >>> fib(10)
    55
    >>> fib(1)
    1
    >>> fib(8)
    21
    """
       else if: n
 <         return2 fib:(
n        - return  n1
)    + else fib:(
n        - return  fib2()n
 -
 
1

--------------------------------------------------HumanEval/56--------------------------------------------------

<s> 

def correct_bracketing(brackets: str):
    """ brackets is a string of "<" and ">".
    return True if every opening bracket has a corresponding closing bracket.

    >>> correct_bracketing("<")
    False
    >>> correct_bracketing("<>")
    True
    >>> correct_bracketing("<<><>>")
    True
    >>> correct_bracketing("><<>")
    False
    """
)    + stack fib =( []n
 -     for2 bra)cket
 in
 brackets
:

--------------------------------------------------HumanEval/56--------------------------------------------------

<s> 

def correct_bracketing(brackets: str):
    """ brackets is a string of "<" and ">".
    return True if every opening bracket has a corresponding closing bracket.

    >>> correct_bracketing("<")
    False
    >>> correct_bracketing("<>")
    True
    >>> correct_bracketing("<<><>>")
    True
    >>> correct_bracketing("><<>")
    False
    """

           stack if = bra []cket
 ==    "< for": bra
cket            in stack brackets.:append
(       bra ifcket bra)cket
 ==        "< else"::

                       stack if. lenappend((stackbra)cket ==) 
0       : else
:               
 return            False if
 len           ( elsestack:)
 ==                 stack0.:pop
()               
 return    False return
 len            else(:stack
)                == stack .0pop
()


   

--------------------------------------------------HumanEval/57--------------------------------------------------

<s> 

def monotonic(l: list):
    """Return True is list elements are monotonically increasing or decreasing.
    >>> monotonic([1, 2, 4, 20])
    True
    >>> monotonic([1, 20, 4, 10])
    False
    >>> monotonic([4, 1, 0, -10])
    True
    """
 return    len return( allstack()l ==[ i0]
 <=
 l
[

--------------------------------------------------HumanEval/57--------------------------------------------------

<s> 

def monotonic(l: list):
    """Return True is list elements are monotonically increasing or decreasing.
    >>> monotonic([1, 2, 4, 20])
    True
    >>> monotonic([1, 20, 4, 10])
    False
    >>> monotonic([4, 1, 0, -10])
    True
    """
i    + return  all1(]l for[ ii in] range <=( llen[(il +)  -1 ]1 for)) i or in all range((llen[(il]) >= - l [1i)) + or  all1(]l for[ ii in] range >=( llen[(il +)  -1 ]1 for)) i
 in
 range
(

--------------------------------------------------HumanEval/58--------------------------------------------------

<s> 

def common(l1: list, l2: list):
    """Return sorted unique common elements for two lists.
    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
    [1, 5, 653]
    >>> common([5, 3, 2, 8], [3, 2])
    [2, 3]

    """
len   ( returnl sorted)( -set (1l))1
)
 &
 set

--------------------------------------------------HumanEval/58--------------------------------------------------

<s> 

def common(l1: list, l2: list):
    """Return sorted unique common elements for two lists.
    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
    [1, 5, 653]
    >>> common([5, 3, 2, 8], [3, 2])
    [2, 3]

    """
   ( returnl sorted2())set
(
l
1

--------------------------------------------------HumanEval/59--------------------------------------------------

<s> 

def largest_prime_factor(n: int):
    """Return the largest prime factor of n. Assume n > 1 and is not a prime.
    >>> largest_prime_factor(13195)
    29
    >>> largest_prime_factor(2048)
    2
    """
   ) # & TODO set(:l F2ill)) this
 in


   

--------------------------------------------------HumanEval/59--------------------------------------------------

<s> 

def largest_prime_factor(n: int):
    """Return the largest prime factor of n. Assume n > 1 and is not a prime.
    >>> largest_prime_factor(13195)
    29
    >>> largest_prime_factor(2048)
    2
    """
 pass   
 #
 TODO
:

--------------------------------------------------HumanEval/60--------------------------------------------------

<s> 

def sum_to_n(n: int):
    """sum_to_n is a function that sums numbers from 1 to n.
    >>> sum_to_n(30)
    465
    >>> sum_to_n(100)
    5050
    >>> sum_to_n(5)
    15
    >>> sum_to_n(10)
    55
    >>> sum_to_n(1)
    1
    """
 F   ill return this sum in(
range   ( pass1
,
 n
 +

--------------------------------------------------HumanEval/60--------------------------------------------------

<s> 

def sum_to_n(n: int):
    """sum_to_n is a function that sums numbers from 1 to n.
    >>> sum_to_n(30)
    465
    >>> sum_to_n(100)
    5050
    >>> sum_to_n(5)
    15
    >>> sum_to_n(10)
    55
    >>> sum_to_n(1)
    1
    """
    1 return)) sum
(
range
(

--------------------------------------------------HumanEval/61--------------------------------------------------

<s> 

def correct_bracketing(brackets: str):
    """ brackets is a string of "(" and ")".
    return True if every opening bracket has a corresponding closing bracket.

    >>> correct_bracketing("(")
    False
    >>> correct_bracketing("()")
    True
    >>> correct_bracketing("(()())")
    True
    >>> correct_bracketing(")(()")
    False
    """
1   , # n Your + code  here1
))   
 return
 len
(

--------------------------------------------------HumanEval/61--------------------------------------------------

<s> 

def correct_bracketing(brackets: str):
    """ brackets is a string of "(" and ")".
    return True if every opening bracket has a corresponding closing bracket.

    >>> correct_bracketing("(")
    False
    >>> correct_bracketing("()")
    True
    >>> correct_bracketing("(()())")
    True
    >>> correct_bracketing(")(()")
    False
    """
bra   ckets #) Your == code len here(
bra   ckets return. lenreplace(("bra(",ckets ")"). ==replace len("()",bra ""ckets)).
replace
("
(",

--------------------------------------------------HumanEval/62--------------------------------------------------

<s> 

def derivative(xs: list):
    """ xs represent coefficients of a polynomial.
    xs[0] + xs[1] * x + xs[2] * x^2 + ....
     Return derivative of this polynomial in the same form.
    >>> derivative([3, 1, 2, 4, 5])
    [1, 4, 12, 20]
    >>> derivative([1, 2, 3])
    [2, 6]
    """
 "   "). returnreplace xs("[)",1 "":]))







--------------------------------------------------HumanEval/63--------------------------------------------------

<s> 

def fibfib(n: int):
    """The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
    fibfib(0) == 0
    fibfib(1) == 0
    fibfib(2) == 1
    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
    Please write a function to efficiently compute the n-th element of the fibfib number sequence.
    >>> fibfib(1)
    0
    >>> fibfib(5)
    4
    >>> fibfib(8)
    24
    """


--------------------------------------------------HumanEval/62--------------------------------------------------

<s> 

def derivative(xs: list):
    """ xs represent coefficients of a polynomial.
    xs[0] + xs[1] * x + xs[2] * x^2 + ....
     Return derivative of this polynomial in the same form.
    >>> derivative([3, 1, 2, 4, 5])
    [1, 4, 12, 20]
    >>> derivative([1, 2, 3])
    [2, 6]
    """
       if return n xs ==[ 1:]0
:


       

--------------------------------------------------HumanEval/63--------------------------------------------------

<s> 

def fibfib(n: int):
    """The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
    fibfib(0) == 0
    fibfib(1) == 0
    fibfib(2) == 1
    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
    Please write a function to efficiently compute the n-th element of the fibfib number sequence.
    >>> fibfib(1)
    0
    >>> fibfib(5)
    4
    >>> fibfib(8)
    24
    """
 return     if0 n
 ==     if0 n: ==
        1 return: 
0       
 return     if0 n
 ==     if1 n: ==
        2 return: 
0       
 return     if1 n
 ==     return2 fib:f
ib       ( returnn -11
)    + return fib fibffibib((nn--21)) + + fib fibffibib((nn--32))
 +
 fib
f

--------------------------------------------------HumanEval/64--------------------------------------------------

<s> 
FIX = """
Add more test cases.
"""

def vowels_count(s):
    """Write a function vowels_count which takes a string representing
    a word as input and returns the number of vowels in the string.
    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
    vowel, but only when it is at the end of the given word.

    Example:
    >>> vowels_count("abcde")
    2
    >>> vowels_count("ACEDY")
    3
    """
ib   ( #n Your- code3 here)

   
 v
ow

--------------------------------------------------HumanEval/64--------------------------------------------------

<s> 
FIX = """
Add more test cases.
"""

def vowels_count(s):
    """Write a function vowels_count which takes a string representing
    a word as input and returns the number of vowels in the string.
    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
    vowel, but only when it is at the end of the given word.

    Example:
    >>> vowels_count("abcde")
    2
    >>> vowels_count("ACEDY")
    3
    """
els    = # [' Youra code', here '
e   ', v 'owiels', = ' ['oa',', ' 'ue',', ' 'yi']',
 '   o count', = ' u0',
 '   y for'] i
 in    s count: =
        0 if
 i    in for i v inow sels::

                   if count i += in  v1ow
els   : if
 s           [- count1 +=]  ==1 '
y   ': if
 s       [- count1 -=]  ==1 '
y   ': return
 count       
 count
 -=
 

--------------------------------------------------HumanEval/65--------------------------------------------------

<s> 
def circular_shift(x, shift):
    """Circular shift the digits of the integer x, shift the digits right by shift
    and return the result as a string.
    If shift > number of digits, return digits reversed.
    >>> circular_shift(12, 1)
    "21"
    >>> circular_shift(12, 2)
    "12"
    """
1   
 digits    = return str count(
x
)



--------------------------------------------------HumanEval/65--------------------------------------------------

<s> 
def circular_shift(x, shift):
    """Circular shift the digits of the integer x, shift the digits right by shift
    and return the result as a string.
    If shift > number of digits, return digits reversed.
    >>> circular_shift(12, 1)
    "21"
    >>> circular_shift(12, 2)
    "12"
    """
       if digits shift = > str( lenx()dig
its   ): if
 shift        > return len digits([dig::its-):1
]       
 return    digits else[:::
-       1 return] digits
[   shift else:]: +
 digits       [: returnshift digits][
shift
:]
 +

--------------------------------------------------HumanEval/66--------------------------------------------------

<s> 
def digitSum(s):
    """Task
    Write a function that takes a string as input and returns the sum of the upper characters only'
    ASCII codes.

    Examples:
        digitSum("") => 0
        digitSum("abAB") => 131
        digitSum("abcCd") => 67
        digitSum("helloE") => 69
        digitSum("woArBld") => 131
        digitSum("aAaaaXa") => 153
    """
 digits   [: uppershift_]ch
ars
 =
 []

--------------------------------------------------HumanEval/66--------------------------------------------------

<s> 
def digitSum(s):
    """Task
    Write a function that takes a string as input and returns the sum of the upper characters only'
    ASCII codes.

    Examples:
        digitSum("") => 0
        digitSum("abAB") => 131
        digitSum("abcCd") => 67
        digitSum("helloE") => 69
        digitSum("woArBld") => 131
        digitSum("aAaaaXa") => 153
    """

       upper for_ charch inars s =: []

           if for char char in. sis:upper
():       
 if            char upper._ischupperars():.
append           ( upperord_(chcharars)).
append   ( returnord sum((charupper))_
ch   ars return) sum
(
upper
_

--------------------------------------------------HumanEval/67--------------------------------------------------

<s> 
def fruit_distribution(s,n):
    """
    In this task, you will be given a string that represents a number of apples and oranges 
    that are distributed in a basket of fruit this basket contains 
    apples, oranges, and mango fruits. Given the string that represents the total number of 
    the oranges and apples and an integer that represent the total number of the fruits 
    in the basket return the number of the mango fruits in the basket.
    for examble:
    fruit_distribution("5 apples and 6 oranges", 19) ->19 - 5 - 6 = 8
    fruit_distribution("0 apples and 1 oranges",3) -> 3 - 0 - 1 = 2
    fruit_distribution("2 apples and 3 oranges", 100) -> 100 - 2 - 3 = 95
    fruit_distribution("100 apples and 1 oranges",120) -> 120 - 100 - 1 = 19
    """
ch   ars app)les
 =
 int
(

--------------------------------------------------HumanEval/67--------------------------------------------------

<s> 
def fruit_distribution(s,n):
    """
    In this task, you will be given a string that represents a number of apples and oranges 
    that are distributed in a basket of fruit this basket contains 
    apples, oranges, and mango fruits. Given the string that represents the total number of 
    the oranges and apples and an integer that represent the total number of the fruits 
    in the basket return the number of the mango fruits in the basket.
    for examble:
    fruit_distribution("5 apples and 6 oranges", 19) ->19 - 5 - 6 = 8
    fruit_distribution("0 apples and 1 oranges",3) -> 3 - 0 - 1 = 2
    fruit_distribution("2 apples and 3 oranges", 100) -> 100 - 2 - 3 = 95
    fruit_distribution("100 apples and 1 oranges",120) -> 120 - 100 - 1 = 19
    """
   s app.lessplit =(" int "()[s0.])split
("    " or)[anges0 =]) int
(   s or.angessplit =(" int "()[s2.])split
("    " return)[ n2 -]) app
les    - return or nanges -
 app
les
 -

--------------------------------------------------HumanEval/68--------------------------------------------------

<s> 
def pluck(arr):
    """
    "Given an array representing a branch of a tree that has non-negative integer nodes
    your task is to pluck one of the nodes and return it.
    The plucked node should be the node with the smallest even value.
    If multiple nodes with the same smallest even value are found return the node that has smallest index.

    The plucked node should be returned in a list, [ smalest_value, its index ],
    If there are no even values or the given array is empty, return [].

    Example 1:
        Input: [4,2,3]
        Output: [2, 1]
        Explanation: 2 has the smallest even value, and 2 has the smallest index.

    Example 2:
        Input: [1,2,3]
        Output: [2, 1]
        Explanation: 2 has the smallest even value, and 2 has the smallest index. 

    Example 3:
        Input: []
        Output: []
    
    Example 4:
        Input: [5, 0, 3, 0, 4, 2]
        Output: [0, 1]
        Explanation: 0 is the smallest value, but  there are two zeros,
                     so we will choose the first zero, which has the smallest index.

    Constraints:
        * 1 <= nodes.length <= 10000
        * 0 <= node.value
    """
 or   anges even
_
nodes
 =

--------------------------------------------------HumanEval/68--------------------------------------------------

<s> 
def pluck(arr):
    """
    "Given an array representing a branch of a tree that has non-negative integer nodes
    your task is to pluck one of the nodes and return it.
    The plucked node should be the node with the smallest even value.
    If multiple nodes with the same smallest even value are found return the node that has smallest index.

    The plucked node should be returned in a list, [ smalest_value, its index ],
    If there are no even values or the given array is empty, return [].

    Example 1:
        Input: [4,2,3]
        Output: [2, 1]
        Explanation: 2 has the smallest even value, and 2 has the smallest index.

    Example 2:
        Input: [1,2,3]
        Output: [2, 1]
        Explanation: 2 has the smallest even value, and 2 has the smallest index. 

    Example 3:
        Input: []
        Output: []
    
    Example 4:
        Input: [5, 0, 3, 0, 4, 2]
        Output: [0, 1]
        Explanation: 0 is the smallest value, but  there are two zeros,
                     so we will choose the first zero, which has the smallest index.

    Constraints:
        * 1 <= nodes.length <= 10000
        * 0 <= node.value
    """
 []   
 even   _ smallestnodes_ =even []_
   value smallest =_ Noneeven
_   value smallest =_ Noneeven
_   value smallest__indexeven =_ Nonevalue
_   index for = index None,
 node    in for enumerate index(,arr node): in
 enumerate       ( ifarr node): %
        2 if == node  %0 :2
 ==             even0_:nodes
.           append even((_nodenodes,. indexappend))((
node           , if index smallest))_
even           _ ifvalue smallest is_ Noneeven or_ nodevalue < is smallest None_ oreven node_ <value smallest:_
even               _ smallestvalue_:even
_               value smallest =_ nodeeven
_               value smallest =_ nodeeven
_               value smallest__indexeven =_ indexvalue
_
index    = if index
 not
 even   _ ifnodes not: even
_       nodes return: []

       
 return    if [] smallest
_
even   _ if smallestvalue__evenindex_ isvalue None_:index
 is        None smallest:_
even       _ smallestvalue__evenindex_ =value even__indexnodes =[ even0_][nodes1[]0
][
1   ] return
 [
small   est return_ [evensmall_estvalue_,even smallest__valueeven,_ smallestvalue__evenindex_]value
_
index
]

--------------------------------------------------HumanEval/69--------------------------------------------------

<s> 
def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''

   
 lst.
sort

--------------------------------------------------HumanEval/69--------------------------------------------------

<s> 
def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
()   
 lst   .sort for i()
 in    range for( ilen in( rangelst()):len
(       lst if)): lst
[       i if] lst >[ 0i and] lst >. count0( andlst lst[.icount(]) >=lst lst[[ii])]: >=
 lst           [ returni]: lst
[i           ] return
 lst   [ returni -]1

   
 return
 -

--------------------------------------------------HumanEval/70--------------------------------------------------

<s> 
def strange_sort_list(lst):
    '''
    Given list of integers, return list in strange order.
    Strange sorting, is when you start with the minimum value,
    then maximum of the remaining integers, then minimum and so on.

    Examples:
    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]
    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]
    strange_sort_list([]) == []
    '''
1   
 lst
.
sort

--------------------------------------------------HumanEval/70--------------------------------------------------

<s> 
def strange_sort_list(lst):
    '''
    Given list of integers, return list in strange order.
    Strange sorting, is when you start with the minimum value,
    then maximum of the remaining integers, then minimum and so on.

    Examples:
    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]
    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]
    strange_sort_list([]) == []
    '''
()    lst
.   sort result() =
 []   
 result    = while [] lst
:   
 while        lst result:.
append       ( resultlst..appendpop((lst0.))pop
(       0 lst)).
append       ( lstmax.(appendlst())max
(       lst lst)).
sort       () lst
.   sort return() result

   
 return
 result

--------------------------------------------------HumanEval/71--------------------------------------------------

<s> 
def triangle_area(a, b, c):
    '''
    Given the lengths of the three sides of a triangle. Return the area of
    the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
    Otherwise return -1
    Three sides make a valid triangle when the sum of any two sides is greater 
    than the third side.
    Example:
    triangle_area(3, 4, 5) == 6.00
    triangle_area(1, 2, 10) == -1
    '''

   
 if
 a

--------------------------------------------------HumanEval/71--------------------------------------------------

<s> 
def triangle_area(a, b, c):
    '''
    Given the lengths of the three sides of a triangle. Return the area of
    the triangle rounded to 2 decimal points if the three sides form a valid triangle. 
    Otherwise return -1
    Three sides make a valid triangle when the sum of any two sides is greater 
    than the third side.
    Example:
    triangle_area(3, 4, 5) == 6.00
    triangle_area(1, 2, 10) == -1
    '''
    + if b a > + c b and > a c + and c a > + b c and > b b + and c b > + a c: >
 a       : area
 =        ( areaa = * ( ba * * c b) * / c ()4 / * ( (4a * + ( ba + + c b)) +
 c       )) return
 round       ( returnarea round,( area2,) 
2   ) else
:   
 else       : return
 -       1 return
 -
1



--------------------------------------------------HumanEval/72--------------------------------------------------

<s> 
def will_it_fly(q,w):
    '''
    Write a function that returns True if the object q will fly, and False otherwise.
    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.

    Example:
    will_it_fly([1, 2], 5) ➞ False 
    # 1+2 is less than the maximum possible weight, but it's unbalanced.

    will_it_fly([3, 2, 3], 1) ➞ False
    # it's balanced, but 3+2+3 is more than the maximum possible weight.

    will_it_fly([3, 2, 3], 9) ➞ True
    # 3+2+3 is less than the maximum possible weight, and it's balanced.

    will_it_fly([3], 5) ➞ True
    # 3 is less than the maximum possible weight, and it's balanced.
    '''

   
 if

--------------------------------------------------HumanEval/72--------------------------------------------------

<s> 
def will_it_fly(q,w):
    '''
    Write a function that returns True if the object q will fly, and False otherwise.
    The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.

    Example:
    will_it_fly([1, 2], 5) ➞ False 
    # 1+2 is less than the maximum possible weight, but it's unbalanced.

    will_it_fly([3, 2, 3], 1) ➞ False
    # it's balanced, but 3+2+3 is more than the maximum possible weight.

    will_it_fly([3, 2, 3], 9) ➞ True
    # 3+2+3 is less than the maximum possible weight, and it's balanced.

    will_it_fly([3], 5) ➞ True
    # 3 is less than the maximum possible weight, and it's balanced.
    '''
 q    == if [] q: == []
:       
 return        False return
 False   
 if    sum if( sumq()q <=) w <= and w q and == q q ==[ q::[-::1-]:1
]:       
 return        True return
 True   
 else   : else
:       
 return        False return
 False





--------------------------------------------------HumanEval/73--------------------------------------------------

<s> 
def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """

   

--------------------------------------------------HumanEval/73--------------------------------------------------

<s> 
def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum number of elements that
    need to be changed to make the array palindromic. A palindromic array is an array that
    is read the same backwards and forwards. In one change, you can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """
 #    TODO # TODO:: Write Write your your code code here here

       pal palindindromerome = = [] []

       for for i i in in range range((lenlen((arrarr)):)):

               pal palindindromerome..appendappend((arrarr[[ii])])

       for for i i in in range range((lenlen((arrarr)):)):

               pal palindindromerome..appendappend((arrarr[[lenlen((arrarr)-)-ii--11])])

       count count = =  00

       for for i i in in range range((lenlen((arrarr)):)):

               if if arr arr[[ii]] != != pal palindindromerome[[ii]:]:

                       count count += +=  11

       return return count count







--------------------------------------------------HumanEval/74--------------------------------------------------

<s> 
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has 
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''


--------------------------------------------------HumanEval/74--------------------------------------------------

<s> 
def total_match(lst1, lst2):
    '''
    Write a function that accepts two lists of strings and returns the list that has 
    total number of chars in the all strings of the list less than the other list.

    if the two lists have the same number of chars, return the first list.

    Examples
    total_match([], []) ➞ []
    total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''
       lst lst11__totaltotal = = sum sum([([lenlen((ii)) for for i i in in lst lst11])])

       lst lst22__totaltotal = = sum sum([([lenlen((ii)) for for i i in in lst lst22])])

       if if lst lst11_total_ <total lst <2 lst_2total_:total
:       
 return        lst return1 lst
1   
 elif    lst elif1 lst_1total_ >total lst > lst22__totaltotal::

               return return lst lst2
2   
 else   : else
:       
 return        lst return1 lst
1





--------------------------------------------------HumanEval/75--------------------------------------------------

<s> 
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100. 
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """

   

--------------------------------------------------HumanEval/75--------------------------------------------------

<s> 
def is_multiply_prime(a):
    """Write a function that returns true if the given number is the multiplication of 3 prime numbers
    and false otherwise.
    Knowing that (a) is less then 100. 
    Example:
    is_multiply_prime(30) == True
    30 = 2 * 3 * 5
    """
 for    i for in i range in( range1(,1 ,1 0100):0
):       
 if        a if % a i % == i  ==0 :0
:           
 if            is if_ isprime_(primei():i
):               
 if                is if_ isprime_(primea( /a i /): i
):                
                    return    True return
 True   
 return    False return
 False





--------------------------------------------------HumanEval/76--------------------------------------------------

<s> 
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simple power of n if n**int=x
    For example:
    is_simple_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simple_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_power(3, 1) => false
    is_simple_power(5, 3) => false
    """

   

--------------------------------------------------HumanEval/76--------------------------------------------------

<s> 
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simple power of n if n**int=x
    For example:
    is_simple_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simple_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_power(3, 1) => false
    is_simple_power(5, 3) => false
    """
 return    x return == x n == ** n int **( intx( **x ( **1 ( /1 n /)) n
))





--------------------------------------------------HumanEval/77--------------------------------------------------

<s> 
def iscube(a):
    '''
    Write a function that takes an integer a and returns True 
    if this ingeger is a cube of some integer number.
    Note: you may assume the input is always valid.
    Examples:
    iscube(1) ==> True
    iscube(2) ==> False
    iscube(-1) ==> True
    iscube(64) ==> True
    iscube(0) ==> True
    iscube(180) ==> False
    '''
   
 return

--------------------------------------------------HumanEval/77--------------------------------------------------

<s> 
def iscube(a):
    '''
    Write a function that takes an integer a and returns True 
    if this ingeger is a cube of some integer number.
    Note: you may assume the input is always valid.
    Examples:
    iscube(1) ==> True
    iscube(2) ==> False
    iscube(-1) ==> True
    iscube(64) ==> True
    iscube(0) ==> True
    iscube(180) ==> False
    '''
    a return**( a1**/(31)/ ==3 int)( ==a int**((a1**/(31))/
3
))

--------------------------------------------------HumanEval/78--------------------------------------------------

<s> 
def hex_key(num):
    """You have been tasked to write a function that receives 
    a hexadecimal number as a string and counts the number of hexadecimal 
    digits that are primes (prime number, or a prime, is a natural number 
    greater than 1 that is not a product of two smaller natural numbers).
    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
    So you have to determine a number of the following digits: 2, 3, 5, 7, 
    B (=decimal 11), D (=decimal 13).
    Note: you may assume the input is always correct or empty string, 
    and symbols A,B,C,D,E,F are always uppercase.
    Examples:
    For num = "AB" the output should be 1.
    For num = "1077E" the output should be 2.
    For num = "ABED1A33" the output should be 4.
    For num = "123456789ABCDEF0" the output should be 6.
    For num = "2020" the output should be 2.
    """

   
 prime

--------------------------------------------------HumanEval/78--------------------------------------------------

<s> 
def hex_key(num):
    """You have been tasked to write a function that receives 
    a hexadecimal number as a string and counts the number of hexadecimal 
    digits that are primes (prime number, or a prime, is a natural number 
    greater than 1 that is not a product of two smaller natural numbers).
    Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
    So you have to determine a number of the following digits: 2, 3, 5, 7, 
    B (=decimal 11), D (=decimal 13).
    Note: you may assume the input is always correct or empty string, 
    and symbols A,B,C,D,E,F are always uppercase.
    Examples:
    For num = "AB" the output should be 1.
    For num = "1077E" the output should be 2.
    For num = "ABED1A33" the output should be 4.
    For num = "123456789ABCDEF0" the output should be 6.
    For num = "2020" the output should be 2.
    """
_   dig primeits_ =dig [its2 =, [ 23,,  35,,  57,,  ord7(',B ord'),(' ordB(''),D ord')(']D
')   ] count
 =     count0 =
    0 for
 i    in for num i: in
 num       : if
 ord       ( ifi ord)( ini prime)_ indig primeits_:dig
its           : count
 +=             count1 +=
    1 return
 count   
 return

 count

--------------------------------------------------HumanEval/79--------------------------------------------------

<s> 
def decimal_to_binary(decimal):
    """You will be given a number in decimal form and your task is to convert it to
    binary format. The function should return a string, with each character representing a binary
    number. Each character in the string will be '0' or '1'.

    There will be an extra couple of characters 'db' at the beginning and at the end of the string.
    The extra characters are there to help with the format.

    Examples:
    decimal_to_binary(15)   # returns "db1111db"
    decimal_to_binary(32)   # returns "db100000db"
    """

   
 #
 Your

--------------------------------------------------HumanEval/79--------------------------------------------------

<s> 
def decimal_to_binary(decimal):
    """You will be given a number in decimal form and your task is to convert it to
    binary format. The function should return a string, with each character representing a binary
    number. Each character in the string will be '0' or '1'.

    There will be an extra couple of characters 'db' at the beginning and at the end of the string.
    The extra characters are there to help with the format.

    Examples:
    decimal_to_binary(15)   # returns "db1111db"
    decimal_to_binary(32)   # returns "db100000db"
    """
 code    here #
 Your    code return here "
db   " return + " bindb("dec +imal bin)[(2dec:]imal +)[ "2db:]" +
 "
db
"

--------------------------------------------------HumanEval/80--------------------------------------------------

<s> 
def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """

   
 if
 len

--------------------------------------------------HumanEval/80--------------------------------------------------

<s> 
def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """
(   s if) len <( s3): <
        3 return: False

           return for False i
 in    range for( i0 in, range len((0s,), len (3s):),
        3 if): s
[       i if: si[+i3:]i in+ s3[]i in+ s3[:i]:+
3           : return]: False

               return return False True

   
 return
 True

--------------------------------------------------HumanEval/81--------------------------------------------------

<s> 
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write 
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A 
            > 3.3                A- 
            > 3.0                B+
            > 2.7                B 
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+ 
            > 0.7                D 
            > 0.0                D-
              0.0                E
    

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    #
 Your
 code

--------------------------------------------------HumanEval/81--------------------------------------------------

<s> 
def numerical_letter_grade(grades):
    """It is the last week of the semester and the teacher has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only problem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to write 
    a function that can output a list of letter grades using the following table:
             GPA       |    Letter grade
              4.0                A+
            > 3.7                A 
            > 3.3                A- 
            > 3.0                B+
            > 2.7                B 
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+ 
            > 0.7                D 
            > 0.0                D-
              0.0                E
    

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """
 here   
 #    Your letter code_ heregrade
 =    [] letter
_   grade for = g []pa
 in    gr forades g:pa
        in if gr gadespa: >=
        4 if. g0pa: >=
            4 letter._0grade:.
append           (' letterA_+grade').
append       (' elifA g+pa') >=
        3 elif. g7pa: >=
            3 letter._7grade:.
append           (' letterA_')grade
.       append elif(' gApa') >=
        3 elif. g3pa: >=
            3 letter._3grade:.append
('           A letter-_')grade
.       append elif(' gApa- >=') 
3       . elif0 g:pa
 >=             letter3_.grade0.:append
('           B letter+_')grade
.       append elif(' gBpa+ >=') 
2       . elif7 g:pa
 >=             letter2_.grade7.:append('
B           ') letter
_       grade elif. gappendpa(' >=B ')2
.       3 elif: g
pa            >= letter _2grade..3append:('
B           - letter')_
grade       . elifappend g('paB >=- ')2
.       0 elif: g
pa            >= letter _2grade..0append:('
C           + letter')_
grade       . elifappend g('paC >=+ ')1
.       7 elif: g
pa            >= letter _1grade..7append:('
C           ') letter
_       grade elif. gappendpa(' >=C ')1
.       3 elif: g
pa            >= letter _1grade..3append:('
C           - letter')_
grade       . elifappend g('paC >=- ')1
.       0 elif: g
pa            >= letter _1grade..0append:('
D           + letter')_
grade       . elifappend g('paD >=+ ')0
.       7 elif:
 g           pa letter >=_ grade0..append7(':D
')           
 letter       _ elifgrade g.paappend >=(' D0').
0       : elif
 g           pa letter >=_ grade0..append0(':D
-           ') letter
_       grade else.:append
('           D letter-_')grade
.       append else(':E
')           
 letter    return_ lettergrade_.gradeappend
('
E
')

--------------------------------------------------HumanEval/82--------------------------------------------------

<s> 
def prime_length(string):
    """Write a function that takes a string and returns True if the string
    length is a prime number or False otherwise
    Examples
    prime_length('Hello') == True
    prime_length('abcdcba') == True
    prime_length('kittens') == True
    prime_length('orange') == False
    """

       # return Your code letter here_
grade   
 if
 len(
string

--------------------------------------------------HumanEval/82--------------------------------------------------

<s> 
def prime_length(string):
    """Write a function that takes a string and returns True if the string
    length is a prime number or False otherwise
    Examples
    prime_length('Hello') == True
    prime_length('abcdcba') == True
    prime_length('kittens') == True
    prime_length('orange') == False
    """
)    == #  Your2 code: here

           return if True len
(   string elif) len ==( string2): ==
        3 return: True

           return elif True len
(   string elif) len ==( string3): ==
        5 return: True

           return elif True len
(   string elif) len ==( string5): ==
        7 return:
 True       
 return    True elif
 len   ( elifstring len)( ==string )7 ==: 
1       1 return: True

           return elif True len
(   string elif) len ==( string1)1 ==: 
1       3 return: True

           return elif True len
(   string elif) len ==( string1)3 ==: 
1       7 return: True

           return elif True len
(   string elif) len ==( string1)7 ==: 
1       9 return: True

           return elif True len
(   string elif) len ==( string1)9 ==: 
2       3 return: True

           return elif True len
(   string elif) len ==( string2)3 ==: 
2       9 return: True

           return elif True len
(   string elif len) ==(string )2 ==9 :3
1       : return
 True       
 return    True elif
 len   ( elifstring len)( ==string )3 ==1 :3
7       : return
 True       
 return    True elif
 len   ( elifstring len)( ==string )3 ==7 :4
1       : return
 True       
 return    True elif
    len elif( lenstring()string ==)  ==4 14:3
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==4 34:7
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==4 75:3
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==5 35:9
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==5 96:1
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==6 16:7
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==6 77:1
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==7 17:3
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==7 37:9
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==7 98:3
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==8 38:9
:       
 return        True return
 True   
 elif    len elif( lenstring()string ==)  ==8 99:7
:       
 return        True return
 True   

--------------------------------------------------HumanEval/83--------------------------------------------------

<s> 
def starts_one_ends(n):
    """
    Given a positive integer n, return the count of the numbers of n-digit
    positive integers that start or end with 1.
    """
    elif count len =( string0)
    == for  i9 in7 range:(
1       0** return( Truen

--------------------------------------------------HumanEval/83--------------------------------------------------

<s> 
def starts_one_ends(n):
    """
    Given a positive integer n, return the count of the numbers of n-digit
    positive integers that start or end with 1.
    """
-   1 count), =  100
**   n for): i
 in        range if( str1(0i**)[(0n]- ==1 '),1 '1 or0 str**(ni):)[
-       1 if] str ==( 'i1)[':0
]            == count ' +=1 '1 or
 str   ( returni count)[
-
1
]

--------------------------------------------------HumanEval/84--------------------------------------------------

<s> 
def solve(N):
    """Given a positive integer N, return the total sum of its digits in binary.
    
    Example
        For N = 1000, the sum of digits will be 1 the output should be "1".
        For N = 150, the sum of digits will be 6 the output should be "110".
        For N = 147, the sum of digits will be 12 the output should be "1100".
    
    Variables:
        @N integer
             Constraints: 0 ≤ N ≤ 10000.
    Output:
         a string of binary number
    """
    == binary ' =1 bin':(
N           )[ count2 +=:] 
1   
 return    sum return( countint
(
i
)

--------------------------------------------------HumanEval/84--------------------------------------------------

<s> 
def solve(N):
    """Given a positive integer N, return the total sum of its digits in binary.
    
    Example
        For N = 1000, the sum of digits will be 1 the output should be "1".
        For N = 150, the sum of digits will be 6 the output should be "110".
        For N = 147, the sum of digits will be 12 the output should be "1100".
    
    Variables:
        @N integer
             Constraints: 0 ≤ N ≤ 10000.
    Output:
         a string of binary number
    """
 for    i binary in = binary bin)(
N
)[
2

--------------------------------------------------HumanEval/85--------------------------------------------------

<s> 
def add(lst):
    """Given a non-empty list of integers lst. add the even elements that are at odd indices..


    Examples:
        add([4, 2, 6, 7]) ==> 2 
    """
:]   
 #    Your return code sum here(
int   ( eveni_)at for_ iodd in_ binaryind)ices
 =
 
0

--------------------------------------------------HumanEval/85--------------------------------------------------

<s> 
def add(lst):
    """Given a non-empty list of integers lst. add the even elements that are at odd indices..


    Examples:
        add([4, 2, 6, 7]) ==> 2 
    """

       # for Your i code in here range
(   len even(_lstat)):_
odd       _ ifind iices % =  20 !=
    0 for and i lst in[ rangei(]len %( lst2)): == 
0       : if
 i            % even _2 !=at _0odd and_ lstind[icesi +=] lst %[i ]2
 ==     return0 even:_
at           _ evenodd__atind_icesodd
_
ind
ices

--------------------------------------------------HumanEval/86--------------------------------------------------

<s> 
def anti_shuffle(s):
    """
    Write a function that takes a string and returns an ordered version of it.
    Ordered version of string, is a string where all words (separated by space)
    are replaced by a new word where all the characters arranged in
    ascending order based on ascii value.
    Note: You should keep the order of words and blank spaces in the sentence.

    For example:
    anti_shuffle('Hi') returns 'Hi'
    anti_shuffle('hello') returns 'ehllo'
    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'
    """
    += return lst '[ '.ijoin](
sorted   ( returns even._splitat()))_
odd
_
ind

--------------------------------------------------HumanEval/87--------------------------------------------------

<s> 
def get_row(lst, x):
    """
    You are given a 2 dimensional data, as a nested lists,
    which is similar to matrix, however, unlike matrices,
    each row may contain a different number of columns.
    Given lst, and integer x, find integers x in the list,
    and return list of tuples, [(x1, y1), (x2, y2) ...] such that
    each tuple is a coordinate - (row, columns), starting with 0.
    Sort coordinates initially by rows in ascending order.
    Also, sort coordinates of the row by columns in descending order.
    
    Examples:
    get_row([
      [1,2,3,4,5,6],
      [1,2,3,4,1,6],
      [1,2,3,4,5,1]
    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
    get_row([], 1) == []
    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
    """
ices   
 coordinates
 =
 []

--------------------------------------------------HumanEval/86--------------------------------------------------

<s> 
def anti_shuffle(s):
    """
    Write a function that takes a string and returns an ordered version of it.
    Ordered version of string, is a string where all words (separated by space)
    are replaced by a new word where all the characters arranged in
    ascending order based on ascii value.
    Note: You should keep the order of words and blank spaces in the sentence.

    For example:
    anti_shuffle('Hi') returns 'Hi'
    anti_shuffle('hello') returns 'ehllo'
    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'
    """

       return for ' i '. injoin range((sortedlen((slst.)):split
()))       
 for
 j
 in

--------------------------------------------------HumanEval/87--------------------------------------------------

<s> 
def get_row(lst, x):
    """
    You are given a 2 dimensional data, as a nested lists,
    which is similar to matrix, however, unlike matrices,
    each row may contain a different number of columns.
    Given lst, and integer x, find integers x in the list,
    and return list of tuples, [(x1, y1), (x2, y2) ...] such that
    each tuple is a coordinate - (row, columns), starting with 0.
    Sort coordinates initially by rows in ascending order.
    Also, sort coordinates of the row by columns in descending order.
    
    Examples:
    get_row([
      [1,2,3,4,5,6],
      [1,2,3,4,1,6],
      [1,2,3,4,5,1]
    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
    get_row([], 1) == []
    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
    """
 range   ( coordinateslen =( []lst
[   i for])) i: in
 range           ( iflen lst([lsti)):][
j       ] for == j x in: range
(               len coordinates(.lstappend[((ii])),: j
))           
 if    lst coordinates[.isort][(jkey]= ==lambda x x::
 x               [ coordinates0.])append
((   i for, i j in)) range
(   len coordinates(.cosortordinates()):key
=       lambda coordinates x[:i x].[append0(])lst
[   co forordinates i[ ini range][(0len](].coindexordinates()):x
))       
 coordinates   [ coordinatesi.].sortappend((keylst=[lambdaco xordinates:[ xi[][10],] reverse].=indexTrue()x
))   
 return    [( coordinatesi.[sort0(],key i=[lambda2 x]): for x i[ in1 coordinates],] reverse
=
True
)

--------------------------------------------------HumanEval/88--------------------------------------------------

<s> 
def sort_array(array):
    """
    Given an array of non-negative integers, return a copy of the given array after sorting,
    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
    or sort it in descending order if the sum( first index value, last index value) is even.

    Note:
    * don't change the given array.

    Examples:
    * sort_array([]) => []
    * sort_array([5]) => [5]
    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]
    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]
    """

    sum   _ returnfirst [(_ilast[ =0 sum],( iarray[[20],]) array for[- i1 in]) coordinates
]   
 if
 sum
_

--------------------------------------------------HumanEval/88--------------------------------------------------

<s> 
def sort_array(array):
    """
    Given an array of non-negative integers, return a copy of the given array after sorting,
    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
    or sort it in descending order if the sum( first index value, last index value) is even.

    Note:
    * don't change the given array.

    Examples:
    * sort_array([]) => []
    * sort_array([5]) => [5]
    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]
    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]
    """
first   _ sumlast_ %first _2last == =  sum0(:array
[       0 return], sorted array([-array1,]) reverse
=   True) if
 sum   _ elsefirst:_
last        % return  sorted2( ==array )0
:


       

--------------------------------------------------HumanEval/89--------------------------------------------------

<s> 
def encrypt(s):
    """Create a function encrypt that takes a string as an argument and
    returns a string encrypted with the alphabet being rotated. 
    The alphabet should be rotated in a manner such that the letters 
    shift down by two multiplied to two places.
    For example:
    encrypt('hi') returns 'lm'
    encrypt('asdfghjkl') returns 'ewhjklnop'
    encrypt('gf') returns 'kj'
    encrypt('et') returns 'ix'
    """
 return    sorted alphabet( =array ',abc reversedef=ghTrueij)kl
mnop   q elser:st
uv       w returnxyz sorted'(
array   ) rot
ated
_
al

--------------------------------------------------HumanEval/89--------------------------------------------------

<s> 
def encrypt(s):
    """Create a function encrypt that takes a string as an argument and
    returns a string encrypted with the alphabet being rotated. 
    The alphabet should be rotated in a manner such that the letters 
    shift down by two multiplied to two places.
    For example:
    encrypt('hi') returns 'lm'
    encrypt('asdfghjkl') returns 'ewhjklnop'
    encrypt('gf') returns 'kj'
    encrypt('et') returns 'ix'
    """
phabet    = alphabet alphabet =[ '2abc:]def +gh alphabetij[:kl2mn]op
q    encryptedr_ststringuv =w ''xyz
'   
 for    letter rot inated s_:al
phabet        = if alphabet letter[ in2:] alphabet +: alphabet
[:           2 encrypted]_
string    += encrypted rot_ated_stringal =phabet ''[
   al forphabet letter. inindex s(:letter
)]       
 if        letter else in: alphabet
:           
 encrypted           _ encryptedstring_ +=string letter +=
 rot   ated return_ encryptedal_phabetstring[
al
phabet
.

--------------------------------------------------HumanEval/90--------------------------------------------------

<s> 
def next_smallest(lst):
    """
    You are given a list of integers.
    Write a function next_smallest() that returns the 2nd smallest element of the list.
    Return None if there is no such element.
    
    next_smallest([1, 2, 3, 4, 5]) == 2
    next_smallest([5, 1, 4, 3, 2]) == 2
    next_smallest([]) == None
    next_smallest([1, 1]) == None
    """
   index if( lenletter()]lst
)        < else :2
:           
 encrypted       _ returnstring None +=
 letter   
 else   : return
 encrypted       _ lststring.sort
()


       

--------------------------------------------------HumanEval/90--------------------------------------------------

<s> 
def next_smallest(lst):
    """
    You are given a list of integers.
    Write a function next_smallest() that returns the 2nd smallest element of the list.
    Return None if there is no such element.
    
    next_smallest([1, 2, 3, 4, 5]) == 2
    next_smallest([5, 1, 4, 3, 2]) == 2
    next_smallest([]) == None
    next_smallest([1, 1]) == None
    """
 return    lst if[ len1(]lst
)
 <
 

--------------------------------------------------HumanEval/91--------------------------------------------------

<s> 
def is_bored(S):
    """
    You'll be given a string of words, and your task is to count the number
    of boredoms. A boredom is a sentence that starts with the word "I".
    Sentences are delimited by '.', '?' or '!'.
   
    For example:
    >>> is_bored("Hello world")
    0
    >>> is_bored("The sky is blue. The sun is shining. I love this weather")
    1
    """
2   : count
 =         return0 None

       for else i: in
 S       . lstsplit.('sort.'()):

               return if lst i[.1starts]with
('
I
'):

--------------------------------------------------HumanEval/91--------------------------------------------------

<s> 
def is_bored(S):
    """
    You'll be given a string of words, and your task is to count the number
    of boredoms. A boredom is a sentence that starts with the word "I".
    Sentences are delimited by '.', '?' or '!'.
   
    For example:
    >>> is_bored("Hello world")
    0
    >>> is_bored("The sky is blue. The sun is shining. I love this weather")
    1
    """

               count count = +=  01

       for for i i in in S S..splitsplit('('.'?'):):

               if if i i..startsstartswithwith('('II'):'):

                       count count += +=  11

       for for i i in in S S..splitsplit('('?'!'):):

               if if i i..startsstartswithwith('('II'):'):

                       count count += +=  11

       for return i count in
 S
.
split

--------------------------------------------------HumanEval/92--------------------------------------------------

<s> 
def any_int(x, y, z):
    '''
    Create a function that takes 3 numbers.
    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
    Returns false in any other cases.
    
    Examples
    any_int(5, 2, 7) ➞ True
    
    any_int(3, 2, 2) ➞ False

    any_int(3, -2, 1) ➞ True
    
    any_int(3.6, -2.2, 2) ➞ False
  

    
    '''
   (' if!' x): ==
 y        + if z i and. typestarts(withx(')I =='): int
 and            type count( +=y )1 == int
 and    type return( countz
)
 ==
 int

--------------------------------------------------HumanEval/92--------------------------------------------------

<s> 
def any_int(x, y, z):
    '''
    Create a function that takes 3 numbers.
    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
    Returns false in any other cases.
    
    Examples
    any_int(5, 2, 7) ➞ True
    
    any_int(3, 2, 2) ➞ False

    any_int(3, -2, 1) ➞ True
    
    any_int(3.6, -2.2, 2) ➞ False
  

    
    '''
:   
 if        x return == True y
 +    z else and type:(
x       ) return == False int
 and
 type
(

--------------------------------------------------HumanEval/93--------------------------------------------------

<s> 
def encode(message):
    """
    Write a function that takes a message, and encodes in such a 
    way that it swaps case of all letters, replaces all vowels in 
    the message with the letter that appears 2 places ahead of that 
    vowel in the english alphabet. 
    Assume only letters. 
    
    Examples:
    >>> encode('test')
    'TGST'
    >>> encode('This is a message')
    'tHKS KS C MGSSCGG'
    """
   y) # Your == code int here and
 type   ( vzow)els == = int [':a
',        ' returne True',
 '   i else',: '
o       ', return ' Falseu
']


   

--------------------------------------------------HumanEval/93--------------------------------------------------

<s> 
def encode(message):
    """
    Write a function that takes a message, and encodes in such a 
    way that it swaps case of all letters, replaces all vowels in 
    the message with the letter that appears 2 places ahead of that 
    vowel in the english alphabet. 
    Assume only letters. 
    
    Examples:
    >>> encode('test')
    'TGST'
    >>> encode('This is a message')
    'tHKS KS C MGSSCGG'
    """
 message    = # message Your. codelower here()

       v newow_elsmessage = = [' ''a
',    ' fore i', in ' rangei(',len '(omessage',)): '
u       '] if
 message   [ messagei =] message in. vlowerow()els
:   
 new           _ newmessage_ =message '' +=
 message   [ fori i+ in2 range](
len       ( elsemessage:)):

                   new if_ messagemessage[ +=i message][ ini v]ow
els   : return
 new           _ newmessage_
message
 +=
 message

--------------------------------------------------HumanEval/94--------------------------------------------------

<s> 

def skjkasdkd(lst):
    """You are given a list of integers.
    You need to find the largest prime value and return the sum of its digits.

    Examples:
    For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10
    For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25
    For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13
    For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11
    For lst = [0,81,12,3,1,21] the output should be 3
    For lst = [0,8,1,2,1,7] the output should be 7
    """
[   i prime+ =2 []]

           for else i: in
 lst           : new
_       message if += i message >[ i1]:

               return for new j_ inmessage range
(
2
,

--------------------------------------------------HumanEval/94--------------------------------------------------

<s> 

def skjkasdkd(lst):
    """You are given a list of integers.
    You need to find the largest prime value and return the sum of its digits.

    Examples:
    For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10
    For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25
    For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13
    For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11
    For lst = [0,81,12,3,1,21] the output should be 3
    For lst = [0,8,1,2,1,7] the output should be 7
    """
 i   ): prime
 =                [] if
 (   i for % i j in) lst ==: 
0       : if
 i                 >     break1
:           
 else           : for
 j                in prime range.(append2(,i i)):

                   sum if_ (digiits % = j )0 ==
    0 for: i
 in                 prime   : break

                   sum else_:dig
its                += prime sum.(appendint((ix))
 for    x sum in_ strdig(itsi =)) 
0   
 return    sum for_ idig inits prime
:


       

--------------------------------------------------HumanEval/95--------------------------------------------------

<s> 
def check_dict_case(dict):
    """
    Given a dictionary, return True if all keys are strings in lower 
    case or all keys are strings in upper case, else return False.
    The function should return False is the given dictionary is empty.
    Examples:
    check_dict_case({"a":"apple", "b":"banana"}) should return True.
    check_dict_case({"a":"apple", "A":"banana", "B":"banana"}) should return False.
    check_dict_case({"a":"apple", 8:"banana", "a":"apple"}) should return False.
    check_dict_case({"Name":"John", "Age":"36", "City":"Houston"}) should return False.
    check_dict_case({"STATE":"NC", "ZIP":"12345" }) should return True.
    """
 sum   _ ifdig notits dict +=: sum
(        returnint False(
x   ) else for: x
 in        str for( keyi in)) dict
:
               return if sum type_(digkeyits)
 !=
 str
:

--------------------------------------------------HumanEval/95--------------------------------------------------

<s> 
def check_dict_case(dict):
    """
    Given a dictionary, return True if all keys are strings in lower 
    case or all keys are strings in upper case, else return False.
    The function should return False is the given dictionary is empty.
    Examples:
    check_dict_case({"a":"apple", "b":"banana"}) should return True.
    check_dict_case({"a":"apple", "A":"banana", "B":"banana"}) should return False.
    check_dict_case({"a":"apple", 8:"banana", "a":"apple"}) should return False.
    check_dict_case({"Name":"John", "Age":"36", "City":"Houston"}) should return False.
    check_dict_case({"STATE":"NC", "ZIP":"12345" }) should return True.
    """

                   if return not False dict
:           
 elif        key return. Falseis
upper   () else !=: key
.       is forlower key(): in
 dict               : return
 False           
 if        type return( Truekey
)
 !=
 str

--------------------------------------------------HumanEval/96--------------------------------------------------

<s> 
def count_up_to(n):
    """Implement a function that takes an non-negative integer and returns an array of the first n
    integers that are prime numbers and less than n.
    for example:
    count_up_to(5) => [2,3]
    count_up_to(11) => [2,3,5,7]
    count_up_to(0) => []
    count_up_to(20) => [2,3,5,7,11,13,17,19]
    count_up_to(1) => []
    count_up_to(18) => [2,3,5,7,11,13,17]
    """
   : prime
_               list return = False []

               elif for key i. inis rangeupper(()2 !=, key n.):is
       lower if(): is
_               prime return( Falsei
):       
 return            True prime
_
list
.

--------------------------------------------------HumanEval/96--------------------------------------------------

<s> 
def count_up_to(n):
    """Implement a function that takes an non-negative integer and returns an array of the first n
    integers that are prime numbers and less than n.
    for example:
    count_up_to(5) => [2,3]
    count_up_to(11) => [2,3,5,7]
    count_up_to(0) => []
    count_up_to(20) => [2,3,5,7,11,13,17,19]
    count_up_to(1) => []
    count_up_to(18) => [2,3,5,7,11,13,17]
    """
append    prime(_ilist) =
 []   
 return    prime for_ ilist in
 range
(
2

--------------------------------------------------HumanEval/97--------------------------------------------------

<s> 
def multiply(a, b):
    """Complete the function that takes two integers and returns 
    the product of their unit digits.
    Assume the input is always valid.
    Examples:
    multiply(148, 412) should return 16.
    multiply(19, 28) should return 72.
    multiply(2020, 1851) should return 0.
    multiply(14,-15) should return 20.
    """
,    n #): Your code
 here       
 if    is a_ =prime abs((ia):)

               prime b_ =list abs.(appendb()i
)   
 a_   unit return_ primedigit_ =list a
 %
 
1

--------------------------------------------------HumanEval/97--------------------------------------------------

<s> 
def multiply(a, b):
    """Complete the function that takes two integers and returns 
    the product of their unit digits.
    Assume the input is always valid.
    Examples:
    multiply(148, 412) should return 16.
    multiply(19, 28) should return 72.
    multiply(2020, 1851) should return 0.
    multiply(14,-15) should return 20.
    """
0   
 #    Your b code_ hereunit
_   digit a = = b abs %( a1)0

       b return = a abs_(unitb_)digit
 *    b a__unitunit__digitdigit
 =
 a
 %

--------------------------------------------------HumanEval/98--------------------------------------------------

<s> 
def count_upper(s):
    """
    Given a string s, count the number of uppercase vowels in even indices.
    
    For example:
    count_upper('aBCdEf') returns 1
    count_upper('abcdefg') returns 0
    count_upper('dBBE') returns 0
    """
    1 v0ow
els    = b ['_Aunit',_ 'digitE =', b % ' I1',0 '
O   ', return ' aU_']unit
_   digit count * = b _0
unit_   digit for
 i
 in range
(

--------------------------------------------------HumanEval/98--------------------------------------------------

<s> 
def count_upper(s):
    """
    Given a string s, count the number of uppercase vowels in even indices.
    
    For example:
    count_upper('aBCdEf') returns 1
    count_upper('abcdefg') returns 0
    count_upper('dBBE') returns 0
    """
   0 v,ow lenels( =s ['),A ',2 '):E
',        ' ifI s',[ 'iO].',upper '() inU v']ow
els   : count
 =             count0 +=
    1 for
 i    in return range count(
0
,
 len

--------------------------------------------------HumanEval/99--------------------------------------------------

<s> 
def closest_integer(value):
    '''
    Create a function that takes a value (string) representing a number
    and returns the closest integer to it. If the number is equidistant
    from two integers, round it away from zero.

    Examples
    >>> closest_integer("10")
    10
    >>> closest_integer("15.3")
    15

    Note:
    Rounding away from zero means that if the given number is equidistant
    from two integers, the one you should return is the one that is the
    farthest from zero. For example closest_integer("14.5") should
    return 15 and closest_integer("-14.5") should return -15.
    '''
(   s value), =  float2():value
)       
 if    s if[ valuei %]. upper1() == in  v0ow:els
:       
 return            value count
 +=     else1:

           return if count value
 >
 
0

--------------------------------------------------HumanEval/99--------------------------------------------------

<s> 
def closest_integer(value):
    '''
    Create a function that takes a value (string) representing a number
    and returns the closest integer to it. If the number is equidistant
    from two integers, round it away from zero.

    Examples
    >>> closest_integer("10")
    10
    >>> closest_integer("15.3")
    15

    Note:
    Rounding away from zero means that if the given number is equidistant
    from two integers, the one you should return is the one that is the
    farthest from zero. For example closest_integer("14.5") should
    return 15 and closest_integer("-14.5") should return -15.
    '''
:   
 value            = return float int((valuevalue) +
    0 if. value5 %) 
1        == else :0
:           
 return        int return( valuevalue
 -     else0:.
5       ) if
 value
 >
 

--------------------------------------------------HumanEval/100--------------------------------------------------

<s> 
def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
0   : levels
 =            [] return
 int   ( stones =value n +
    0 while. stones5 >) 
0       : else
:       
 if            stones return % int (2value == - 0 :0
.           5 stones) +=
 
1



--------------------------------------------------HumanEval/100--------------------------------------------------

<s> 
def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
           else levels: =
 []           
 stones    += stones  =2 n

           levels while. stonesappend >( st0ones:)

           if return stones levels %
 
2
 ==

--------------------------------------------------HumanEval/101--------------------------------------------------

<s> 
def words_string(s):
    """
    You will be given a string of words separated by commas or spaces. Your task is
    to split the string into words and return an array of the words.
    
    For example:
    words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
    words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
    """
    0 return: s
.           split stones(", += ") 
1


       

--------------------------------------------------HumanEval/102--------------------------------------------------

<s> 
def choose_num(x, y):
    """This function takes two positive numbers x and y and returns the
    biggest even integer number that is in the range [x, y] inclusive. If 
    there's no such number, then the function should return -1.

    For example:
    choose_num(12, 15) = 14
    choose_num(13, 12) = -1
    """
 else   : even
_           num stoness += =  []2

           for levels i. inappend range((stxones,) y +
    1 return): levels

       
 if
 i

--------------------------------------------------HumanEval/101--------------------------------------------------

<s> 
def words_string(s):
    """
    You will be given a string of words separated by commas or spaces. Your task is
    to split the string into words and return an array of the words.
    
    For example:
    words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
    words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
    """
    %  return s2. ==split (",0: ")

           

 even

--------------------------------------------------HumanEval/102--------------------------------------------------

<s> 
def choose_num(x, y):
    """This function takes two positive numbers x and y and returns the
    biggest even integer number that is in the range [x, y] inclusive. If 
    there's no such number, then the function should return -1.

    For example:
    choose_num(12, 15) = 14
    choose_num(13, 12) = -1
    """
_   num evens_.numappends( =i [])

       for if i len in( rangeeven_(numxs,) y == +  01:):

               return if - i1 %
    2 else ==: 
0       : return
 max           ( eveneven__numnumss.)append
(
i
)

--------------------------------------------------HumanEval/103--------------------------------------------------

<s> 
def rounded_avg(n, m):
    """You are given two positive integers n and m, and your task is to compute the
    average of the integers from n through m (including n and m). 
    Round the answer to the nearest integer and convert that to binary.
    If n is greater than m, return -1.
    Example:
    rounded_avg(1, 5) => "0b11"
    rounded_avg(7, 5) => -1
    rounded_avg(10, 20) => "0b1111"
    rounded_avg(20, 33) => "0b11010"
    """

       if if n len >( meven:_
num       s return) - ==1 
0   : else
:       
 return        - binary1 =
    0 else
:       
 for        i return in max range((evenn_,num ms +) 
1
):



--------------------------------------------------HumanEval/103--------------------------------------------------

<s> 
def rounded_avg(n, m):
    """You are given two positive integers n and m, and your task is to compute the
    average of the integers from n through m (including n and m). 
    Round the answer to the nearest integer and convert that to binary.
    If n is greater than m, return -1.
    Example:
    rounded_avg(1, 5) => "0b11"
    rounded_avg(7, 5) => -1
    rounded_avg(10, 20) => "0b1111"
    rounded_avg(20, 33) => "0b11010"
    """
               binary if += n i >
 m       : return
 bin       ( returnint -(1binary
 /    ( elsem: -
 n        + binary  =1 )))0


       
 for

--------------------------------------------------HumanEval/104--------------------------------------------------

<s> 
def unique_digits(x):
    """Given a list of positive integers x. return a sorted list of all 
    elements that hasn't any even digit.

    Note: Returned list should be sorted in increasing order.
    
    For example:
    >>> unique_digits([15, 33, 1422, 1])
    [1, 15, 33]
    >>> unique_digits([152, 323, 1422, 10])
    []
    """
 i    in # range Your( coden here,
 m    + return  sorted1([):i
 for i            in binary x += if i not
 any       ( returnj bin %( int2( ==binary  /0 ( form j - in n str +( i1)))))])







--------------------------------------------------HumanEval/105--------------------------------------------------

<s> 
def by_length(arr):
    """
    Given an array of integers, sort the integers that are between 1 and 9 inclusive,
    reverse the resulting array, and then replace each digit by its corresponding name from
    "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".

    For example:
      arr = [2, 1, 1, 4, 5, 8, 2, 3]   
            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] 
            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]
      return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
    
      If the array is empty, return an empty array:
      arr = []
      return []
    
      If the array has any strange number ignore it:
      arr = [1, -1 , 55] 
            -> sort arr -> [-1, 1, 55]
            -> reverse arr -> [55, 1, -1]
      return = ['One']
    """


--------------------------------------------------HumanEval/104--------------------------------------------------

<s> 
def unique_digits(x):
    """Given a list of positive integers x. return a sorted list of all 
    elements that hasn't any even digit.

    Note: Returned list should be sorted in increasing order.
    
    For example:
    >>> unique_digits([15, 33, 1422, 1])
    [1, 15, 33]
    >>> unique_digits([152, 323, 1422, 10])
    []
    """
       names # = Your [" codeOne here",
 "   Two return", sorted "([Threei", for i " inF xour if", not " anyF(ivej", % " S2ix ==",  "0Se forven j", in " strE(ighti",)) "])N
ine
"]



--------------------------------------------------HumanEval/105--------------------------------------------------

<s> 
def by_length(arr):
    """
    Given an array of integers, sort the integers that are between 1 and 9 inclusive,
    reverse the resulting array, and then replace each digit by its corresponding name from
    "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".

    For example:
      arr = [2, 1, 1, 4, 5, 8, 2, 3]   
            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] 
            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]
      return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
    
      If the array is empty, return an empty array:
      arr = []
      return []
    
      If the array has any strange number ignore it:
      arr = [1, -1 , 55] 
            -> sort arr -> [-1, 1, 55]
            -> reverse arr -> [55, 1, -1]
      return = ['One']
    """
       sorted names_ =arr [" =One sorted",( "filterTwo(",lambda " xThree:",  "1F <=our x", <= " F9ive,", arr "))S
ix   ", revers "edSe_venarr", = " sortedE_ightarr",[ "::N-ine1"]]

       sorted return_ [arrnames =[ sortedi(-filter1(]lambda for x i: in  revers1ed <=_ xarr <= ]9
,
 arr
))

--------------------------------------------------HumanEval/106--------------------------------------------------

<s> 
def f(n):
    """ Implement the function f that takes n as a parameter,
    and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
    or the sum of numbers from 1 to i otherwise.
    i starts from 1.
    the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
    Example:
    f(5) == [1, 2, 6, 24, 15]
    """
   
 result    = revers []ed
_   arr for = i sorted in_ rangearr([1::,- n1 +] 
1   ): return
 [        ifnames i[ %i -21 ==]  for0 i: in
 revers           ed result_.appendarr(]factor
ial
(
i

--------------------------------------------------HumanEval/106--------------------------------------------------

<s> 
def f(n):
    """ Implement the function f that takes n as a parameter,
    and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
    or the sum of numbers from 1 to i otherwise.
    i starts from 1.
    the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
    Example:
    f(5) == [1, 2, 6, 24, 15]
    """
))   
 result        = else []:

               for result i. inappend range((1sum,( nrange +( 11,): i
 +         if1 i))) %
    2 return == result 
0
:



--------------------------------------------------HumanEval/107--------------------------------------------------

<s> 
def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
               result #. Edgeappend case(
factor   ial if( ni <=)) 
1       : else
:       
 return            ( result0.,append (0sum)(
range
(   1 #, Count i even + and  odd1 integer))) pal
ind   rom returnes result

   
 even
_

--------------------------------------------------HumanEval/107--------------------------------------------------

<s> 
def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
count    = #  Edge0 case

       odd if_ ncount <= =  10:

           for return i ( in0 range,( 10,) n
 +
    1 #): Count
 even        and if odd is integer_ palevenind_rompalesind
rome   ( eveni_):count
 =             even0_
count    += odd _1count
 =         else0:

               for odd i_ incount range +=( 11,
 n
 +     return1 ():even
_       count if, is odd__evencount_)pal
ind
rome
(

--------------------------------------------------HumanEval/108--------------------------------------------------

<s> 
def count_nums(arr):
    """
    Write a function count_nums which takes an array of integers and returns
    the number of elements which has a sum of digits > 0.
    If a number is negative, then its first signed digit will be negative:
    e.g. -123 has signed digits -1, 2, and 3.
    >>> count_nums([]) == 0
    >>> count_nums([-1, 11, -11]) == 1
    >>> count_nums([1, 1, 2]) == 3
    """
i   ): #
 Your            code even here_
count    += count  =1 
0
           else for: i
 in            arr odd:_
count        += sum _1dig
its
 =     return0 (
       even if_ icount <,  odd0_:count
)           
 for
 j
 in

--------------------------------------------------HumanEval/108--------------------------------------------------

<s> 
def count_nums(arr):
    """
    Write a function count_nums which takes an array of integers and returns
    the number of elements which has a sum of digits > 0.
    If a number is negative, then its first signed digit will be negative:
    e.g. -123 has signed digits -1, 2, and 3.
    >>> count_nums([]) == 0
    >>> count_nums([-1, 11, -11]) == 1
    >>> count_nums([1, 1, 2]) == 3
    """
 str   ( #i Your): code
 here               
 sum   _ countdig =its  -=0 int
(   j for) i
 in        arr else::

                   sum for_ jdig inits str =( i0
):       
 if                i sum <_ dig0its: +=
 int           ( forj j) in
 str       ( ifi sum):_
dig               its sum >_ dig0its: -=
 int           ( countj +=) 
1       
 else   : return
 count           
 for
 j
 in

--------------------------------------------------HumanEval/109--------------------------------------------------

<s> 
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing 
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.
    
    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index. 

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:
    
    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.
                
    """
 str   ( ifi not): arr
:               
 sum       _ returndig Trueits
 +=    int arr(.jsort)()

           if return sum arr_ ==dig sortedits( >arr )0
:


           

--------------------------------------------------HumanEval/110--------------------------------------------------

<s> 
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
 count    += even _1lst
1    = return all count(
x
 %
 2

--------------------------------------------------HumanEval/109--------------------------------------------------

<s> 
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing 
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.
    
    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index. 

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:
    
    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.
                
    """
    == if  not0 arr for x: in
 lst       1 return) True

       even arr_.lstsort2() =
 all   ( returnx arr % ==  sorted2( ==arr )0
 for
 x
 in

--------------------------------------------------HumanEval/110--------------------------------------------------

<s> 
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
 lst   2 even)_
lst   1 if = even all_(lstx1 % and  even2_ ==lst 20: for
 x        in return lst "1YES)"

       even elif_ evenlst_2lst =1 all and( notx even %_ lst22 ==: 
0        for for x i in in lst range2()len
(   lst if1 even)):_
lst           1 if and lst even1_[lsti2]: %
        2 return != " YES0":

                   elif lst even1_[lsti1] and = not lst even2_.lstpop2(:0
)       
 for                i lst in2 range.(appendlen((lstlst11[)):i
])           
 if                if lst all1([xi] % %  22 == !=  00 for: x
 in                lst lst11):[
i                ]    = return lst "2YES."pop
(   0 elif) not
 even               _ lstlst21. andappend even(_lstlst12:[
i       ]) for
 i                in if range all((lenx( %lst 22)): ==
 0            if for x lst in2 lst[1i):]
 %                    2 return != " YES0":

                   elif lst not2 even[_ilst]1 = and lst even1_.lstpop2(:0
)       
 for                i lst in1 range.(appendlen((lstlst22[)):i
])           
 if                lst if2 all[(ix] % %  22 == !=  00 for: x
 in                lst lst22):[
i                ]    = return lst "1YES."pop
(   0 else):

                       lst return1 ".NOappend"(
lst
2
[

--------------------------------------------------HumanEval/111--------------------------------------------------

<s> 
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.
    
    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
i   ]) #
 Your                code if here
 all   ( dx = % {} 
2    == l  =0 test for.split x() in
 lst   2 for): i
 in                 l   : return
 "       YES if i" in
 d   : else
:           
 d       [ returni "] +=NO "1


       
 else

--------------------------------------------------HumanEval/111--------------------------------------------------

<s> 
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.
    
    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
:   
 #            Your d code[ herei
]    = d  =1 {}

       max l_ =count test =. maxsplit(()d
.   values for()) i
 in    l result: =
 {}       
 if    i for in key d,: value
 in            d d.[itemsi():]
 +=         if1 value
 ==        max else_:count
:           
 d           [ resulti[]key =]  =1 value

       max return_ resultcount
 =
 max
(

--------------------------------------------------HumanEval/112--------------------------------------------------

<s> 
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """
d   . #values your()) code
 here   
 result    = s {} =
 s   . forreplace key(,c value,' in') d
.   items if(): s
 == s       [ if:: value- ==1 max]:_
count       : return
 (           s result,[Truekey)]
 =    value else
:   
 return        result return
 (
s
,

--------------------------------------------------HumanEval/112--------------------------------------------------

<s> 
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """
False   ) #
 your
 code
 here

--------------------------------------------------HumanEval/113--------------------------------------------------

<s> 
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """

       # s Your = code s here.
replace   ( returnc [,'len')([
x    for if x s in == str s([i::)- if1 int]:(
x       ) return% (2s !=, True0)])
 for    i else in: lst
]       
 return
 (
s

--------------------------------------------------HumanEval/114--------------------------------------------------

<s> 
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
,   False #) Write
 your solution
 here



--------------------------------------------------HumanEval/113--------------------------------------------------

<s> 
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
       # if not Your num codes here:

           return return [ len0([
x    for min x_ insum str =( floati(')inf if') int
(   x sum)_% =2  !=0 
0   ]) for for i i in in range lst(]len
(
num
s

--------------------------------------------------HumanEval/114--------------------------------------------------

<s> 
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
)):   
 #        Write sum your_ solution += here num
s   [ ifi not] num
s       : if
 sum       _ return <  min_0sum
:   
 min           _ minsum_ =sum float =(' suminf_')

           if sum sum__ = >  00
:   
 for            i sum in_ range =( len0(
num   s return)): min
_       sum sum
_
 +=
 num

--------------------------------------------------HumanEval/115--------------------------------------------------

<s> 
def max_fill(grid, capacity):
    import math
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it, 
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input: 
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input: 
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5
    
    Example 3:
        Input: 
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """
s   [ wellis] =
 []       
 if    sum for_ i < in min range_(sumlen:(
grid           )): min
_       sum well = sums_.
append       ([ if]) sum
_        > for  j0 in: range
(           len sum(_grid =[ i0]))
:    return
 min           _ ifsum grid
[
i
][

--------------------------------------------------HumanEval/115--------------------------------------------------

<s> 
def max_fill(grid, capacity):
    import math
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it, 
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input: 
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input: 
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5
    
    Example 3:
        Input: 
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """
j   ] well ==s  =1 []:

                   for well is in[ rangei(].lenappend((gridj)):)

       
 wells   . buappendckets([ =]) []

           for for j i in in range range((lenlen((gridwell[si)):]))
:       
 bu           ckets if. gridappend[(icap][acityj)]
 ==
    1 def: fill
(               well well,s bucket[):i
].       append if( wellj ==) len
(
grid   [ bu0ckets]) = - [] 
1   : for
 i            in return range (0len
(       well ifs bucket)): ==
        0 buckets:.
append           ( returncap mathacity.)inf


           if def well fills([wellwell,][ bucket-):1
]        == if well wells ==[ lenwell(][grid0[]:0
])            - return  math1.:inf

                   return if  well0s
[       well if][ bucket- ==1 ]0 -: well
s           [ returnwell math][.0inf]
 +         if1 wells <=[ bucketwell:][
-           1 return]  ==1 well +s fill[(wellwell][ +0 ]:1
,            bucket return - math (.wellinfs
[       well if][ well-s1[] -well well][s-[1well]][ -0 well]s +[ well1][))0
]        + else :1
 <=            bucket return: 
1            + return  min1( +fill fill((wellwell + +  11,, bucket bucket), - fill ((wellwells +[ well1][,- bucket1 -] ( -well wellss[[wellwell][][-01]] + -  well1s))[
well       ][ else0:]
 +             return1 )))1
 +
 min   ( returnfill sum((wellfill +( well1,, bucket bucket)), for fill well(,well bucket +  in1 zip,( bucketwell -s (,well busckets[))well
][
-
1

--------------------------------------------------HumanEval/116--------------------------------------------------

<s> 
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
]    return - sorted well(sarr[,well key=][binary0_]ones +) 

1
)))

--------------------------------------------------HumanEval/117--------------------------------------------------

<s> 
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement 
    a function that returns a list of all words from string s that contain exactly 
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """

   
 # TODO   : return Im sumplement( select_fillwords(
well   , return [] bucket
)
 for
 well

--------------------------------------------------HumanEval/118--------------------------------------------------

<s> 
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between 
    two consonants from the right side of the word (case sensitive).
    
    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition. 

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
   , # bucket Your in code here zip
(   well ifs len(,word bu)ckets <= ))2
:


        return

--------------------------------------------------HumanEval/116--------------------------------------------------

<s> 
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    "" return
 sorted   ( conarrson,ants key == []binary
_   ones v)ow
els
 =
 []

--------------------------------------------------HumanEval/117--------------------------------------------------

<s> 
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement 
    a function that returns a list of all words from string s that contain exactly 
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """

       # for TODO i: in Im rangeplement( selectlen_(wordsword
)):   
 return        [] if
 word
[
i

--------------------------------------------------HumanEval/118--------------------------------------------------

<s> 
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between 
    two consonants from the right side of the word (case sensitive).
    
    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition. 

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
].   is #upper Your(): code
 here           
 con   son ifants len.(appendword()word <=[ i2]):

               elif return word ""[
i   ]. conissonlowerants(): =
 []           
 v   ow velsow.elsappend =( []word
[   i for]) i
 in    range if( lenlen((conwordson)):ants
)        == if  word0[ ori len].(isvupperow():els
)            == con son0ants:.
append       ( returnword ""[
i   ]) for
 i        in elif range word([leni(].conissonlowerants():)
 -             v1ow):els
.       append if( conwordson[antsi[])i
].   is ifupper len()( andcon consonsonantsants)[ ==i  +0  or1 len].(isvupperow():els
)            == continue 
0       : if
 con       son returnants ""[
i   ]. foris ilower in() range and( conlenson(antscon[soniants +)  -1 ].1is):lower
():       
 if            con continueson
ants       [ ifi con].sonisantsupper[()i and]. conissonlowerants()[ andi con +son ants1[].iis +upper ():1
].           is continueupper
():       
 if            con returnson vantsow[elsi[].iis +lower ()1 and] con
son       ants if[ conison +ants [1i].is].loweris():upper
()            and continue con
son       ants if[ conison +ants [1i].].isislowerlower():()
 and            con returnson vantsow[elsi[ +i  +1 ].1is]upper
():   
 return            "" return
 v
ow
els

--------------------------------------------------HumanEval/119--------------------------------------------------

<s> 
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
[   i stack + =  []
1   ] for
 par       en if in con lstson:ants
[       i if]. parisen ==upper '()(' and: con
son           ants stack[.iappend +( par1en].)is
       lower else()::

                       return if v stackow:els
[               i stack +. pop()1
]           
 else   : return
 ""               
 return
 '
No

--------------------------------------------------HumanEval/119--------------------------------------------------

<s> 
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
'   
 stack    = if [] not
 stack   : for
 par       en return in ' lstYes:'

           if else par:en
 ==        ' return(' ':No
'           
 stack
.
append

--------------------------------------------------HumanEval/120--------------------------------------------------

<s> 
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list 
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
(   par #en @)param
 {       integer else[]:}
 arr
               if # stack @:param
 {               integer stack}. kpop
()   
 #            @ elsereturn: {
integer               [] return} '
No   ' def
 max   Number if( notself stack,: arr
,        k return): '
Yes       ' #
 Write    your else code: here

               return if ' kNo ==' 
0
:



--------------------------------------------------HumanEval/120--------------------------------------------------

<s> 
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list 
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
               return # [] @
param        { ifinteger k[] ==}  arr1
:   
 #            @ returnparam [ {maxinteger(}arr k)]

           # if @ kreturn == { leninteger([]arr}):

               def return max sortedNumber((arrself),
 arr
,        k left):,
 right        = #  Write0 your, code len here(
arr       ) if - k  ==1 
0       : while
 left            < return right []:

                   if if k arr ==[ left1]: <
            0 return and [ arrmax[(rightarr])] >
        0 if: k
 ==                len break(
arr           ): left
 +=             return1 sorted
(           arr right) -=
 
1       
 left
,        right if = left  ==0 right,: len
(           arr return) sorted -( arr1[:
k        while]) left
 <
 right       : left
_           max if = arr max[(leftarr][: <left  +0  and1 arr])[
right       ] right >_ max0 =: max
(               arr break
[           right left: +=]) 
1       
 if            left right_ -=max  >1 right
_
max       : if
 left            == return right self:.
max           Number return( sortedarr([:arrleft[: +k ])1
],
 k       ) left
_       max else =: max
(           arr return[: selfleft. +max Number1(])arr
[       right right:_],max k =) max
(
arr
[

--------------------------------------------------HumanEval/121--------------------------------------------------

<s> 
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
    

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
right   : return]) sum
([       lst if[i left]_ formax i > in right range_(max0:,
 len(           lst return), self .2max)Number if( lstarr[i[:]left % +  21 !=],  k0)])


       
 else

--------------------------------------------------HumanEval/122--------------------------------------------------

<s> 
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
:

               # Edge return case self
.   max ifNumber k( ==arr [0:right
:       ], return k )0




    #

--------------------------------------------------HumanEval/121--------------------------------------------------

<s> 
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
    

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    Sort return the sum array([
   lst arr[.isort]() for
 i
 in    range #( Initialize0 the, sum len
(   lst sum), =  20)
 if
 lst   [ #i Iter]ate % through  the2 first != k  elements0
])   
 for
 i
 in

--------------------------------------------------HumanEval/122--------------------------------------------------

<s> 
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """

 range   ( #k Edge): case

           # if If k the == digit  count0 of: the
 element        is return <=  02


           if # len Sort( thestr array(
arr   [ arri.]))sort <=() 
2
:   
 #            Initialize # the Add sum the
 element    to sum = the  sum0

            sum
 +=    arr #[ Iteriate] through
 the
 first    k return elements sum

   
 for
 i

--------------------------------------------------HumanEval/123--------------------------------------------------

<s> 
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the 
    previous term as follows: if the previous term is even, the next term is one half of 
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note: 
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
 in    range #( Edgek cases)::

           # if If n the < digit  count1 of: the
 element        is raise <= Value Error2("
n        must if be len a( positivestr integer(.")arr
[
i   ])) # <= TODO :2 Write: your
 code            here #
 Add    the coll elementatz to_list the = sum []

               sum while += n arr !=[ i1]:


           if return n sum %
 
2
 ==

--------------------------------------------------HumanEval/123--------------------------------------------------

<s> 
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the 
    previous term as follows: if the previous term is even, the next term is one half of 
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note: 
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    1 #: Edge
 cases           : coll
atz   _ iflist n. <append (1n:)

               raise n Value =Error n(" //n  must2 be if a n positive % integer .")2
 ==
    0 # else TODO :3 Write * your n code + here 
1   
 coll   atz_ colllistatz =_ []list
.   sort while() n
 !=     return1 coll:atz
_       list if
 n
 %
 

--------------------------------------------------HumanEval/124--------------------------------------------------

<s> 
def valid_date(date):
    """You have to write a function which validates a given date string and
    returns True if the date is valid otherwise False.
    The date is valid if all of the following rules are satisfied:
    1. The date string is not empty.
    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
    3. The months should not be less than 1 or higher than 12.
    4. The date should be in the format: mm-dd-yyyy

    for example: 
    valid_date('03-11-2000') => True

    valid_date('15-01-2012') => False

    valid_date('04-0-2040') => False

    valid_date('06-04-2020') => True

    valid_date('06/04/2020') => False
    """
   2 if == date  ==1 ":":

                   coll returnatz False_
list   . elseappend:(
n       ) month
,        day n, = year n = // date .2split if(" n- %") 
2        == if  int0( elsemonth )3 < *  n1 + or  int1(
month   ) coll >atz 1_2list:.
sort           () return
 False   
 return        coll elifatz int_(listday
)
 <
 

--------------------------------------------------HumanEval/124--------------------------------------------------

<s> 
def valid_date(date):
    """You have to write a function which validates a given date string and
    returns True if the date is valid otherwise False.
    The date is valid if all of the following rules are satisfied:
    1. The date string is not empty.
    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
    3. The months should not be less than 1 or higher than 12.
    4. The date should be in the format: mm-dd-yyyy

    for example: 
    valid_date('03-11-2000') => True

    valid_date('15-01-2012') => False

    valid_date('04-0-2040') => False

    valid_date('06-04-2020') => True

    valid_date('06/04/2020') => False
    """
1    or if int date( ==day ")": >
        3 return False1
:   
 else           : if
 int       ( monthmonth,) day in, [ year1 =, date .3split,(" -5"),
        7 if, int (8month,)  <1 01, or  int1(2month]:)
 >                 return1 False2
:           
 elif            int return( Falsemonth
)        in elif [ int(4day,)  <6 ,1  or9 int,( day1)1 >]: 
3               1 if: int
(           year if) int %( month4) == in  [01:,
                 3   , if  int5(,day )7 <,  18 or, int (1day0), >  1320]::

                                return        False return
 False           
 elif                int else(:month)
 in                 [   4 if, int (6day,)  <9 ,1  or1 int1(]:day
)                > if  int2(9year:)
 %                        4 return == False 
0           : elif
 int                (   month if) int ==( day2): <
                1 if or int int((yearday)) % >  340 ==: 
0                :       
 return                 False   
 if                int else(:day
)                 <     if1 int or( intday()day <)  >1  or int2(9day:)
 >                        2 return9 False:

                                else       : return
 False                
               if elif int int((daymonth)) < ==  12 or: int
(               day if) int >( year2)8 %: 
4                 ==         return0 False:

                            else   : if
 int               ( returnday False)
 <         else1: or
 int           ( returnday True)
 >
 
2

--------------------------------------------------HumanEval/125--------------------------------------------------

<s> 
def split_words(txt):
    '''
    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
    Examples
    split_words("Hello world!") ➞ ["Hello", "world!"]
    split_words("Hello,world!") ➞ ["Hello", "world!"]
    split_words("abcdef") == 3 
    '''
9   : words
 =                 txt.       split return() False

    if                words else ==: []
:                
           words if = int txt(.daysplit(',)') <
    1 if words or == int [](:day
)        count > =  208
:        for
 i                 in        range return(ord False('
a           '), else ord:('z
')               + return1 False):

                   if else chr:(i
).           is returnlower True() and
 i
 %
 

--------------------------------------------------HumanEval/125--------------------------------------------------

<s> 
def split_words(txt):
    '''
    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
    Examples
    split_words("Hello world!") ➞ ["Hello", "world!"]
    split_words("Hello,world!") ➞ ["Hello", "world!"]
    split_words("abcdef") == 3 
    '''
2    != words  =0 txt:.
split               () count
 +=     if1 words
 ==        [] return: count

           words return = words txt
.
split
(',

--------------------------------------------------HumanEval/126--------------------------------------------------

<s> 
def is_sorted(lst):
    '''
    Given a list of numbers, return whether or not they are sorted
    in ascending order. If list has more than 1 duplicate of the same
    number, return False. Assume no negative numbers and only integers.

    Examples
    is_sorted([5]) ➞ True
    is_sorted([1, 2, 3, 4, 5]) ➞ True
    is_sorted([1, 3, 2, 4, 5]) ➞ False
    is_sorted([1, 2, 3, 4, 5, 6]) ➞ True
    is_sorted([1, 2, 3, 4, 5, 6, 7]) ➞ True
    is_sorted([1, 3, 2, 4, 5, 6, 7]) ➞ False
    is_sorted([1, 2, 2, 3, 3, 4]) ➞ True
    is_sorted([1, 2, 2, 2, 3, 4]) ➞ False
    '''
')   
 lst   . ifsort words() ==
 []   : return
 lst        == count lst =
 
0



--------------------------------------------------HumanEval/127--------------------------------------------------

<s> 
def intersection(interval1, interval2):
    """You are given two intervals,
    where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
    The given intervals are closed which means that the interval (start, end)
    includes both start and end.
    For each given interval, it is assumed that its start is less or equal its end.
    Your task is to determine whether the length of intersection of these two 
    intervals is a prime number.
    Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
    which its length is 1, which not a prime number.
    If the length of the intersection is a prime number, return "YES",
    otherwise, return "NO".
    If the two intervals don't intersect, return "NO".


    [input/output] samples:
    intersection((1, 2), (2, 3)) ==> "NO"
    intersection((-1, 1), (0, 4)) ==> "NO"
    intersection((-3, -1), (-5, 5)) ==> "YES"
    """
           for # i Write in your range code( hereord
('   a if'), interval ord1('[z0')]+ >1 interval):2
[           1 if] chr or( intervali1).[is1lower]() < and interval i2 %[ 02]: !=
        0 return: "
NO               " count
 +=     start1 =
 max       ( returninterval count1
[   0 return], words interval
2
[
0

--------------------------------------------------HumanEval/126--------------------------------------------------

<s> 
def is_sorted(lst):
    '''
    Given a list of numbers, return whether or not they are sorted
    in ascending order. If list has more than 1 duplicate of the same
    number, return False. Assume no negative numbers and only integers.

    Examples
    is_sorted([5]) ➞ True
    is_sorted([1, 2, 3, 4, 5]) ➞ True
    is_sorted([1, 3, 2, 4, 5]) ➞ False
    is_sorted([1, 2, 3, 4, 5, 6]) ➞ True
    is_sorted([1, 2, 3, 4, 5, 6, 7]) ➞ True
    is_sorted([1, 3, 2, 4, 5, 6, 7]) ➞ False
    is_sorted([1, 2, 2, 3, 3, 4]) ➞ True
    is_sorted([1, 2, 2, 2, 3, 4]) ➞ False
    '''
])   
 lst   . endsort =() min
(   interval return1 lst[ ==1 lst],
 interval
2
[

--------------------------------------------------HumanEval/127--------------------------------------------------

<s> 
def intersection(interval1, interval2):
    """You are given two intervals,
    where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
    The given intervals are closed which means that the interval (start, end)
    includes both start and end.
    For each given interval, it is assumed that its start is less or equal its end.
    Your task is to determine whether the length of intersection of these two 
    intervals is a prime number.
    Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
    which its length is 1, which not a prime number.
    If the length of the intersection is a prime number, return "YES",
    otherwise, return "NO".
    If the two intervals don't intersect, return "NO".


    [input/output] samples:
    intersection((1, 2), (2, 3)) ==> "NO"
    intersection((-1, 1), (0, 4)) ==> "NO"
    intersection((-3, -1), (-5, 5)) ==> "YES"
    """
   1 #]) Write
 your    code prime here =
 True   
 if    interval for1 i[ in0 range]( >2 interval,2 end[ +1 ]1 or): interval
1       [ if1 end] < % i interval ==2[ 00]::

                   return prime " =NO False"

               break start
 =    max if( primeinterval:1
[       0 return], " intervalYES2"[
0   ]) return
 "   NO end" =
 min
(
interval

--------------------------------------------------HumanEval/128--------------------------------------------------

<s> 
def prod_signs(arr):
    """
    You are given an array arr of integers and you need to return
    sum of magnitudes of integers multiplied by product of all signs
    of each number in the array, represented by 1, -1 or 0.
    Note: return None for empty arr.

    Example:
    >>> prod_signs([1, 2, 2, -4]) == -9
    >>> prod_signs([0, 1]) == 0
    >>> prod_signs([]) == None
    """
1   [ if1 not], arr interval:2
[       1 return]) None

       prod prime = =  True1

       for sum i_ inmag range =( 20,
    end for + i  in1 arr)::

               if if end i % == i 0 ==: 
0           : sum
_           mag prime += =  False0

                   elif break i
 >     if0 prime::

                   prod return * "=YES "1

               sum return_ "magNO +=" i


       
 else

--------------------------------------------------HumanEval/128--------------------------------------------------

<s> 
def prod_signs(arr):
    """
    You are given an array arr of integers and you need to return
    sum of magnitudes of integers multiplied by product of all signs
    of each number in the array, represented by 1, -1 or 0.
    Note: return None for empty arr.

    Example:
    >>> prod_signs([1, 2, 2, -4]) == -9
    >>> prod_signs([0, 1]) == 0
    >>> prod_signs([]) == None
    """
:   
 if            not prod arr *:=
 -       1 return
 None           
 sum   _ prod =mag  +=1 i

       sum return_ summag_ =mag  *0 prod

   
 for
 i

--------------------------------------------------HumanEval/129--------------------------------------------------

<s> 
def minPath(grid, k):
    """
    Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
    each cell of the grid contains a value. Every integer in the range [1, N * N]
    inclusive appears exactly once on the cells of the grid.

    You have to find the minimum path of length k in the grid. You can start
    from any cell, and in each step you can move to any of the neighbor cells,
    in other words, you can go to cells which share an edge with you current
    cell.
    Please note that a path of length k means visiting exactly k cells (not
    necessarily distinct).
    You CANNOT go off the grid.
    A path A (of length k) is considered less than a path B (of length k) if
    after making the ordered lists of the values on the cells that A and B go
    through (let's call them lst_A and lst_B), lst_A is lexicographically less
    than lst_B, in other words, there exist an integer index i (1 <= i <= k)
    such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
    lst_A[j] = lst_B[j].
    It is guaranteed that the answer is unique.
    Return an ordered list of the values on the cells that the minimum path go through.

    Examples:

        Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3
        Output: [1, 2, 1]

        Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1
        Output: [1]
    """
 in    arr N: =
 len       ( ifgrid i) ==
    0: #
 d           p sum[_imag][ +=j ]0 is
 the        minimum elif path i > of  length0 i: from
 cell            ( prodi *,= j )1 to
            the sum bottom_ rightmag
 +=    i #
 corner       . else
:   
 d           p prod = * [[= -float1('
inf           ') sum]_ *mag N += for i _
 in    range return( sumN_mag)] *
 prod   
 #
 lst
[

--------------------------------------------------HumanEval/129--------------------------------------------------

<s> 
def minPath(grid, k):
    """
    Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
    each cell of the grid contains a value. Every integer in the range [1, N * N]
    inclusive appears exactly once on the cells of the grid.

    You have to find the minimum path of length k in the grid. You can start
    from any cell, and in each step you can move to any of the neighbor cells,
    in other words, you can go to cells which share an edge with you current
    cell.
    Please note that a path of length k means visiting exactly k cells (not
    necessarily distinct).
    You CANNOT go off the grid.
    A path A (of length k) is considered less than a path B (of length k) if
    after making the ordered lists of the values on the cells that A and B go
    through (let's call them lst_A and lst_B), lst_A is lexicographically less
    than lst_B, in other words, there exist an integer index i (1 <= i <= k)
    such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
    lst_A[j] = lst_B[j].
    It is guaranteed that the answer is unique.
    Return an ordered list of the values on the cells that the minimum path go through.

    Examples:

        Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3
        Output: [1, 2, 1]

        Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1
        Output: [1]
    """
i   ][ Nj =] len is( thegrid ordered) list
 of    values # on d thep cells[ thati the][j minimum] path is
 the    minimum # path of of length length i i go from through cell. (
i   , lst j =) [[ toNone the] bottom * right N
 for    _ # in corner range.(
N    d)]p
 =    [[ forfloat i(' ininf range')(]N *): N
 for        _ d inp range[(iN][)]i
]    = #  lst0[
i       ][ lstj[]i is][ thei ordered] list = of values [ ongrid the[ cellsi that][ thei minimum]] path

       for # i of in length range i( goN through):.

           for lst j = in [[ rangeNone(]i * + N  for1 _, in N range):(
N           )] d
p   [ fori i][ inj range]( =N min):(
dp       [ dip][[ji -][ i1]] = +  grid0[
i       ][ lstj[],i d][pi[]i = + [ grid1[][ij][i]]] +
 grid   [ fori i][ inj range])(
N           ): lst
[       i for][ jj in] range =( lsti[ +i ][1,j N -): 
1           ] d +p [[gridi[][ij][]j =]] min
(   dp return[ lsti[][0j][ -N  -1 ] +1 grid][
i
][
j

--------------------------------------------------HumanEval/130--------------------------------------------------

<s> 
def tri(n):
    """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
    the last couple centuries. However, what people don't know is Tribonacci sequence.
    Tribonacci sequence is defined by the recurrence:
    tri(1) = 3
    tri(n) = 1 + n / 2, if n is even.
    tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
    For example:
    tri(2) = 1 + (2 / 2) = 2
    tri(4) = 3
    tri(3) = tri(2) + tri(1) + tri(4)
           = 2 + 3 + 3 = 8 
    You are given a non-negative integer number n, you have to a return a list of the 
    first n + 1 numbers of the Tribonacci sequence.
    Examples:
    tri(3) = [1, 3, 2, 8]
    """
   ], trib donpacci[ =i [1 +,  13][,j 2]] +
 grid   [ for ii in][ rangej(])3,
 n            + lst [1i):
][       j if] i = % lst 2[ ==i ][0j:
 -             trib1on]acci. +append [(grid1[ + ii /][ j2]])

           else return: lst
[            trib0on][acciN. -append( t1rib]on
acci[
i
 -

--------------------------------------------------HumanEval/130--------------------------------------------------

<s> 
def tri(n):
    """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
    the last couple centuries. However, what people don't know is Tribonacci sequence.
    Tribonacci sequence is defined by the recurrence:
    tri(1) = 3
    tri(n) = 1 + n / 2, if n is even.
    tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
    For example:
    tri(2) = 1 + (2 / 2) = 2
    tri(4) = 3
    tri(3) = tri(2) + tri(1) + tri(4)
           = 2 + 3 + 3 = 8 
    You are given a non-negative integer number n, you have to a return a list of the 
    first n + 1 numbers of the Tribonacci sequence.
    Examples:
    tri(3) = [1, 3, 2, 8]
    """
    1 trib]on +acci trib =on [acci1[,i  -3 ,2 ]2 +] trib
on   acci for[ ii in + range (13]),
 n    + return  trib1on):acci

       
 if
 i

--------------------------------------------------HumanEval/131--------------------------------------------------

<s> 
def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
 %     #2 Your == code  here0
:   
 odd           _ tribdigonitsacci =. []append
   ( for1 digit + in i str /( n2):)

               if else int:(
digit           ) trib %on acci2. ==append (1t:rib
on           acci odd_[digiits -. append1(]int +( tribdigiton))acci
[   i if - len (2odd]_ +digits trib)on ==acci [0i: +
        1 return]) 0

       return else trib:on
acci       
 return
 int
(''.

--------------------------------------------------HumanEval/131--------------------------------------------------

<s> 
def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
   join #( Yourmap code( herestr
,    odd_ odddig_itsdig)))its
 =
 []



--------------------------------------------------HumanEval/132--------------------------------------------------

<s> 
def is_nested(string):
    '''
    Create a function that takes a string as input which contains only square brackets.
    The function should return True if and only if there is a valid subsequence of brackets 
    where at least one bracket in the subsequence is nested.

    is_nested('[[]]') ➞ True
    is_nested('[]]]]]]][[[[[]') ➞ False
    is_nested('[][]') ➞ False
    is_nested('[]') ➞ False
    is_nested('[[][]]') ➞ True
    is_nested('[[]][[') ➞ True
    '''
       for brackets digit = in [' str[(',n']):']

           if nested int =( Falsedigit
)    % for  i2 in == string: 
1       : if
 i            in odd brackets_:dig
its           . ifappend i( ==int '(['digit:))

                   nested if = len True(
odd           _ elsedig:its
)                == nested  =0 False:

           return return True  if0 nested
 else    False else
:


       

--------------------------------------------------HumanEval/133--------------------------------------------------

<s> 

def sum_squares(lst):
    """You are given a list of numbers.
    You need to return the sum of squared numbers in the given list,
    round each element in the list to the upper int(Ceiling) first.
    Examples:
    For lst = [1,2,3] the output should be 14
    For lst = [1,4,9] the output should be 98
    For lst = [1,3,5,7] the output should be 84
    For lst = [1.4,4.2,0] the output should be 29
    For lst = [-2.4,1,1] the output should be 6
    

    """
 return    int lst(' ='. [joinround((mapi()str for, i odd in_ lstdig]its
)))   
 return
 sum
([

--------------------------------------------------HumanEval/132--------------------------------------------------

<s> 
def is_nested(string):
    '''
    Create a function that takes a string as input which contains only square brackets.
    The function should return True if and only if there is a valid subsequence of brackets 
    where at least one bracket in the subsequence is nested.

    is_nested('[[]]') ➞ True
    is_nested('[]]]]]]][[[[[]') ➞ False
    is_nested('[][]') ➞ False
    is_nested('[]') ➞ False
    is_nested('[[][]]') ➞ True
    is_nested('[[]][[') ➞ True
    '''
i   ** brackets2 = for ['[ i', in'] lst']])


   
 nested

--------------------------------------------------HumanEval/134--------------------------------------------------

<s> 
def check_if_last_char_is_a_letter(txt):
    '''
    Create a function that returns True if the last character
    of a given string is an alphabetical character and is not
    a part of a word, and False otherwise.
    Note: "word" is a group of characters separated by space.

    Examples:
    check_if_last_char_is_a_letter("apple pie") ➞ False
    check_if_last_char_is_a_letter("apple pi e") ➞ True
    check_if_last_char_is_a_letter("apple pi e ") ➞ False
    check_if_last_char_is_a_letter("") ➞ False 
    '''
 =    False return
 txt   [- for1 i]. inis stringalpha:()
 and        not if txt i. insplit brackets():[-
1           ] if
 i
 ==
 '

--------------------------------------------------HumanEval/135--------------------------------------------------

<s> 
def can_arrange(arr):
    """Create a function which returns the largest index of an element which
    is not greater than or equal to the element immediately preceding it. If
    no such element exists then return -1. The given array will not contain
    duplicate values.

    Examples:
    can_arrange([1,2,4,3,5]) = 3
    can_arrange([1,2,3]) = -1
    """
['   : #
 TODO               : nested Write = solution True here

               else pass:


               
 nested

--------------------------------------------------HumanEval/136--------------------------------------------------

<s> 
def largest_smallest_integers(lst):
    '''
    Create a function that returns a tuple (a, b), where 'a' is
    the largest of negative integers, and 'b' is the smallest
    of positive integers in a list.
    If there is no negative or positive integers, return them as None.

    Examples:
    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)
    largest_smallest_integers([]) == (None, None)
    largest_smallest_integers([0]) == (None, None)
    '''
    = largest False =
 None   
 return    True smallest if = nested None else
 False    for
 i
 in
 lst

--------------------------------------------------HumanEval/133--------------------------------------------------

<s> 

def sum_squares(lst):
    """You are given a list of numbers.
    You need to return the sum of squared numbers in the given list,
    round each element in the list to the upper int(Ceiling) first.
    Examples:
    For lst = [1,2,3] the output should be 14
    For lst = [1,4,9] the output should be 98
    For lst = [1,3,5,7] the output should be 84
    For lst = [1.4,4.2,0] the output should be 29
    For lst = [-2.4,1,1] the output should be 6
    

    """
:   
 lst        = [ ifround i( <i )0 for and i ( inlargest lst is] None
 or    i return > sum largest([):i
**           2 largest for = i i in
 lst       ]) elif
 i
 >
 

--------------------------------------------------HumanEval/134--------------------------------------------------

<s> 
def check_if_last_char_is_a_letter(txt):
    '''
    Create a function that returns True if the last character
    of a given string is an alphabetical character and is not
    a part of a word, and False otherwise.
    Note: "word" is a group of characters separated by space.

    Examples:
    check_if_last_char_is_a_letter("apple pie") ➞ False
    check_if_last_char_is_a_letter("apple pi e") ➞ True
    check_if_last_char_is_a_letter("apple pi e ") ➞ False
    check_if_last_char_is_a_letter("") ➞ False 
    '''
0    and return ( txtsmall[-est1 is]. Noneis oralpha i() < and smallest not): txt
.           split smallest() =[- i1
]   
 return
 (
larg

--------------------------------------------------HumanEval/135--------------------------------------------------

<s> 
def can_arrange(arr):
    """Create a function which returns the largest index of an element which
    is not greater than or equal to the element immediately preceding it. If
    no such element exists then return -1. The given array will not contain
    duplicate values.

    Examples:
    can_arrange([1,2,4,3,5]) = 3
    can_arrange([1,2,3]) = -1
    """
est   , # smallest TODO):
 Write
 solution
 here

--------------------------------------------------HumanEval/137--------------------------------------------------

<s> 
def compare_one(a, b):
    """
    Create a function that takes integers, floats, or strings representing
    real numbers, and returns the larger variable in its given variable type.
    Return None if the values are equal.
    Note: If a real number is represented as a string, the floating point might be . or ,

    compare_one(1, 2.5) ➞ 2.5
    compare_one(1, "2,3") ➞ "2,3"
    compare_one("5,1", "6") ➞ "6"
    compare_one("1", 1) ➞ None
    """

       if pass a
 ==
 b
:

--------------------------------------------------HumanEval/136--------------------------------------------------

<s> 
def largest_smallest_integers(lst):
    '''
    Create a function that returns a tuple (a, b), where 'a' is
    the largest of negative integers, and 'b' is the smallest
    of positive integers in a list.
    If there is no negative or positive integers, return them as None.

    Examples:
    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)
    largest_smallest_integers([]) == (None, None)
    largest_smallest_integers([0]) == (None, None)
    '''

           largest return = None None

       elif smallest float =( Nonea
)    > for float i( inb lst)::

               return if a i
 <     else0: and
 (larg       est return is b None
 or
 i
 >

--------------------------------------------------HumanEval/138--------------------------------------------------

<s> 
def is_equal_to_sum_even(n):
    """Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
    Example
    is_equal_to_sum_even(4) == False
    is_equal_to_sum_even(6) == False
    is_equal_to_sum_even(8) == True
    """
    largest #): TODO
:            Im largestplement = this i function

           elif if i n > %  02 and == ( small0est: is
 None        or if i n < == smallest ):8
:           
 smallest            = return i True

           return else (:larg
est           , return smallest False)

   
 else
:

--------------------------------------------------HumanEval/137--------------------------------------------------

<s> 
def compare_one(a, b):
    """
    Create a function that takes integers, floats, or strings representing
    real numbers, and returns the larger variable in its given variable type.
    Return None if the values are equal.
    Note: If a real number is represented as a string, the floating point might be . or ,

    compare_one(1, 2.5) ➞ 2.5
    compare_one(1, "2,3") ➞ "2,3"
    compare_one("5,1", "6") ➞ "6"
    compare_one("1", 1) ➞ None
    """

           if return a False ==
 b
:



--------------------------------------------------HumanEval/139--------------------------------------------------

<s> 
def special_factorial(n):
    """The Brazilian factorial is defined as:
    brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
    where n > 0

    For example:
    >>> special_factorial(4)
    288

    The function will receive an integer as input and should return the special
    factorial of this integer.
    """
           return if None n
 <     elif0 float:(
a       ) return > None float
(   b else)::

               return bra azil
ian   _ elsefactor:ial
 =         return1 b

       
 for
 i in

--------------------------------------------------HumanEval/138--------------------------------------------------

<s> 
def is_equal_to_sum_even(n):
    """Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
    Example
    is_equal_to_sum_even(4) == False
    is_equal_to_sum_even(6) == False
    is_equal_to_sum_even(8) == True
    """
    range #( TODOn:, Im plement0 this, function -
1   ): if
 n            % bra zil2ian ==_ factor0ial: *
=        i if
 n        return == bra zil8ian:_
factor           ial return
 True


       

--------------------------------------------------HumanEval/140--------------------------------------------------

<s> 
def fix_spaces(text):
    """
    Given a string text, replace all spaces in it with underscores, 
    and if a string has more than 2 consecutive spaces, 
    then replace all consecutive spaces with - 
    
    fix_spaces("Example") == "Example"
    fix_spaces("Example 1") == "Example_1"
    fix_spaces(" Example 2") == "_Example_2"
    fix_spaces(" Example   3") == "_Example-3"
    """
 else   : text
 =            text return. Falsereplace
("    ", else "_:")

           return while False "
 
 "
 in

--------------------------------------------------HumanEval/139--------------------------------------------------

<s> 
def special_factorial(n):
    """The Brazilian factorial is defined as:
    brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
    where n > 0

    For example:
    >>> special_factorial(4)
    288

    The function will receive an integer as input and should return the special
    factorial of this integer.
    """
 text   : if
 n        < text  = text0.:replace
("         return ", None "-
")   
 else   : return
 text       
 bra
zil
ian

--------------------------------------------------HumanEval/141--------------------------------------------------

<s> 
def file_name_check(file_name):
    """Create a function which takes a string representing a file's name, and returns
    'Yes' if the the file's name is valid, and returns 'No' otherwise.
    A file's name is considered to be valid if and only if all the following conditions 
    are met:
    - There should not be more than three digits ('0'-'9') in the file's name.
    - The file's name contains exactly one dot '.'
    - The substring before the dot should not be empty, and it starts with a letter from 
    the latin alphapet ('a'-'z' and 'A'-'Z').
    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']
    Examples:
    file_name_check("example.txt") # => 'Yes'
    file_name_check("1example.dll") # => 'No' (the name should start with a latin alphapet letter)
    """
_   factor ifial len =( file1_
name       . forsplit i(". in") range[(0n]), >  03,: -
1       ): return
 "           No bra"zil
ian   _ eliffactor lenial( *file=_ iname
.       split return(" bra."zil))ian !=_ factor2ial:


       
 return

--------------------------------------------------HumanEval/140--------------------------------------------------

<s> 
def fix_spaces(text):
    """
    Given a string text, replace all spaces in it with underscores, 
    and if a string has more than 2 consecutive spaces, 
    then replace all consecutive spaces with - 
    
    fix_spaces("Example") == "Example"
    fix_spaces("Example 1") == "Example_1"
    fix_spaces(" Example 2") == "_Example_2"
    fix_spaces(" Example   3") == "_Example-3"
    """
    " textNo =" text
.   replace elif(" not ", file "__")name
[   0 while]. "is alpha "(): in
 text       : return
 "       No text" =
 text   . elifreplace file(" _ ",name "-.")split
(".   ") return[ text1
]
 not
 in

--------------------------------------------------HumanEval/141--------------------------------------------------

<s> 
def file_name_check(file_name):
    """Create a function which takes a string representing a file's name, and returns
    'Yes' if the the file's name is valid, and returns 'No' otherwise.
    A file's name is considered to be valid if and only if all the following conditions 
    are met:
    - There should not be more than three digits ('0'-'9') in the file's name.
    - The file's name contains exactly one dot '.'
    - The substring before the dot should not be empty, and it starts with a letter from 
    the latin alphapet ('a'-'z' and 'A'-'Z').
    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']
    Examples:
    file_name_check("example.txt") # => 'Yes'
    file_name_check("1example.dll") # => 'No' (the name should start with a latin alphapet letter)
    """
 ["   txt if", len "(exefile",_ "namedll."]split:(".
")       [ return0 "])No >" 
3   : else
:       
 return        " returnNo ""Yes
"   
 elif
 len
(

--------------------------------------------------HumanEval/142--------------------------------------------------

<s> 


def sum_squares(lst):
    """"
    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a 
    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not 
    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. 
    
    Examples:
    For lst = [1,2,3] the output should be 6
    For lst = []  the output should be 0
    For lst = [-1,-5,2,-1,-5]  the output should be -126
    """
file   _ #name Your. codesplit here("
."   )) for != i  in2 range:(
len       ( returnlst ")):No
"       
 if    i elif % not  file3_ ==name [00:].
is           alpha lst():[
i]        = return lst "[Noi"]
 **     elif2 file
_       name if. isplit %(". ")4[ ==1 ]0 not and in i [" %txt ",3 " !=exe ",0 ":dll
           "] lst:[
i       ] return = " lstNo["i
]    ** else :3

           return return " sumYes("lst
)






--------------------------------------------------HumanEval/142--------------------------------------------------

<s> 


def sum_squares(lst):
    """"
    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a 
    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not 
    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. 
    
    Examples:
    For lst = [1,2,3] the output should be 6
    For lst = []  the output should be 0
    For lst = [-1,-5,2,-1,-5]  the output should be -126
    """
   

--------------------------------------------------HumanEval/143--------------------------------------------------

<s> 
def words_in_sentence(sentence):
    """
    You are given a string representing a sentence,
    the sentence contains some words separated by a space,
    and you have to return a string that contains the words from the original sentence,
    whose lengths are prime numbers,
    the order of the words in the new string should be the same as the original one.

    Example 1:
        Input: sentence = "This is a test"
        Output: "is"

    Example 2:
        Input: sentence = "lets go for swimming"
        Output: "go for"

    Constraints:
        * 1 <= len(sentence) <= 100
        * sentence contains only letters
    """
    # prime Your_ codewords here =
 []   
 for    i for in word range in( sentencelen.(splitlst():)):

               if if is i_ %prime (3len ==( word0))::

                       prime lst_[wordsi.]append =( lstword[)i
]
 **     return2 '
 '.       join if( iprime %_ words4) ==
 
0
 and

--------------------------------------------------HumanEval/144--------------------------------------------------

<s> 
def simplify(x, n):
    """Your task is to implement a function that will simplify the expression
    x * n. The function returns True if x * n evaluates to a whole number and False
    otherwise. Both x and n, are string representation of a fraction, and have the following format,
    <numerator>/<denominator> where both numerator and denominator are positive whole numbers.

    You can assume that x, and n are valid fractions, and do not have zero as denominator.

    simplify("1/5", "5/1") = True
    simplify("1/6", "2/1") = False
    simplify("7/10", "10/2") = False
    """
 i    % x _3num !=,  x0_den:om
 =            x lst.[spliti('/]') =
 lst   [ ni_]num **,  n3_
den   om return = sum n(.lstsplit)('/
')


   

--------------------------------------------------HumanEval/143--------------------------------------------------

<s> 
def words_in_sentence(sentence):
    """
    You are given a string representing a sentence,
    the sentence contains some words separated by a space,
    and you have to return a string that contains the words from the original sentence,
    whose lengths are prime numbers,
    the order of the words in the new string should be the same as the original one.

    Example 1:
        Input: sentence = "This is a test"
        Output: "is"

    Example 2:
        Input: sentence = "lets go for swimming"
        Output: "go for"

    Constraints:
        * 1 <= len(sentence) <= 100
        * sentence contains only letters
    """
 x   _ primenum_ =words int =( []x
_   num for) word
 in    sentence x._splitden():om
 =        int if( isx__primeden(omlen)(
word   )): n
_           num prime =_ intwords(.nappend_(numword))

   
 n   _ returnden 'om '. =join int((primen__wordsden)om
)


   

--------------------------------------------------HumanEval/144--------------------------------------------------

<s> 
def simplify(x, n):
    """Your task is to implement a function that will simplify the expression
    x * n. The function returns True if x * n evaluates to a whole number and False
    otherwise. Both x and n, are string representation of a fraction, and have the following format,
    <numerator>/<denominator> where both numerator and denominator are positive whole numbers.

    You can assume that x, and n are valid fractions, and do not have zero as denominator.

    simplify("1/5", "5/1") = True
    simplify("1/6", "2/1") = False
    simplify("7/10", "10/2") = False
    """
 if    x x__numnum *, n x__dendenomom == = x x_.densplitom('/ *') n
_   num n:_
num       , return n True_
den   om else =: n
.       split return('/ False')


   
 x

--------------------------------------------------HumanEval/145--------------------------------------------------

<s> 
def order_by_points(nums):
    """
    Write a function which sorts the given list of integers
    in ascending order according to the sum of their digits.
    Note: if there are several items with similar sum of their digits,
    order them based on their index in original list.

    For example:
    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
    >>> order_by_points([]) == []
    """
_   num # = your int code( herex
_   num num)s
.   sort x(_key=densumom_ =of int_(digxits_)den
om   ) return
 num   s n
_
num
 =

--------------------------------------------------HumanEval/146--------------------------------------------------

<s> 
def specialFilter(nums):
    """Write a function that takes an array of numbers as input and returns 
    the number of elements in the array that are greater than 10 and both 
    first and last digits of a number are odd (1, 3, 5, 7, 9).
    For example:
    specialFilter([15, -73, 14, -15]) => 1 
    specialFilter([33, -2, -3, 45, 21, 109]) => 2
    """
 int   ( countn =_ num0)
   
 for    num n in_ numdensom: =
 int       ( ifn num_ >den om1)0
 and    ( ifnum // x _1num0 * % n _2den !=om  ==0 x and_ numden %om  *1 n0_ %num :2
 !=        0 return): True

               count else +=: 
1       
 return    False return
 count





--------------------------------------------------HumanEval/145--------------------------------------------------

<s> 
def order_by_points(nums):
    """
    Write a function which sorts the given list of integers
    in ascending order according to the sum of their digits.
    Note: if there are several items with similar sum of their digits,
    order them based on their index in original list.

    For example:
    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
    >>> order_by_points([]) == []
    """

   

--------------------------------------------------HumanEval/147--------------------------------------------------

<s> 
def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """
 #    your # code code here here

       num arrs =. [sorti(*keyi=-sumi_+of1_ fordig iits in) range
   ( return1 num,sn
+
1
)]

--------------------------------------------------HumanEval/146--------------------------------------------------

<s> 
def specialFilter(nums):
    """Write a function that takes an array of numbers as input and returns 
    the number of elements in the array that are greater than 10 and both 
    first and last digits of a number are odd (1, 3, 5, 7, 9).
    For example:
    specialFilter([15, -73, 14, -15]) => 1 
    specialFilter([33, -2, -3, 45, 21, 109]) => 2
    """

       count count = =  00

       for for num i in in num ranges(:n
-       2 if): num
 >         for1 j0 in and range ((numi //+ 11,0n %- 12): !=
            0 for and num k % in  range1(0j %+ 12, !=n ):0
):               
 if            arr count[ +=i ]+1arr
[   j return]+ countarr
[
k
]

--------------------------------------------------HumanEval/147--------------------------------------------------

<s> 
def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """
%   3 #== code0 here:

                    arr    = count [+=i1*
i   - returni count+
1
 for
 i
 in

--------------------------------------------------HumanEval/148--------------------------------------------------

<s> 
def bf(planet1, planet2):
    '''
    There are eight planets in our solar system: the closerst to the Sun 
    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, 
    Uranus, Neptune.
    Write a function that takes two planet names as strings planet1 and planet2. 
    The function should return a tuple containing all planets whose orbits are 
    located between the orbit of planet1 and the orbit of planet2, sorted by 
    the proximity to the sun. 
    The function should return an empty tuple if planet1 or planet2
    are not correct planet names. 
    Examples
    bf("Jupiter", "Neptune") ==> ("Saturn", "Uranus")
    bf("Earth", "Mercury") ==> ("Venus")
    bf("Mercury", "Uranus") ==> ("Venus", "Earth", "Mars", "Jupiter", "Saturn")
    '''
 range   ( plan1ets, =n ("Mer+cur1y)]",
 "   V counten =us ",0 "
E   arth for", i " inM rangears(",n "-J2up):iter
",        " forS jat inurn range",( "iU+ran1us,",n "-Ne1pt):une
")           
 for    k if in planet range1( notj in+ plan1ets, orn planet):2
 not                in if plan arrets[:i
]+       arr return[ ()j
]+   arr else[:k
]       % return3 tuple==(0sorted:(
plan                ets   [ countplan+=ets1.
index   ( returnplan countet
1
):
plan
ets

--------------------------------------------------HumanEval/148--------------------------------------------------

<s> 
def bf(planet1, planet2):
    '''
    There are eight planets in our solar system: the closerst to the Sun 
    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, 
    Uranus, Neptune.
    Write a function that takes two planet names as strings planet1 and planet2. 
    The function should return a tuple containing all planets whose orbits are 
    located between the orbit of planet1 and the orbit of planet2, sorted by 
    the proximity to the sun. 
    The function should return an empty tuple if planet1 or planet2
    are not correct planet names. 
    Examples
    bf("Jupiter", "Neptune") ==> ("Saturn", "Uranus")
    bf("Earth", "Mercury") ==> ("Venus")
    bf("Mercury", "Uranus") ==> ("Venus", "Earth", "Mars", "Jupiter", "Saturn")
    '''
.   index plan(etsplan =et ("2Mer)+cur1y],", key "=Vlambdaen xus:", plan "etsE.arthindex",( "xM)))ars
",
 "
J

--------------------------------------------------HumanEval/149--------------------------------------------------

up<s> 
def sorted_list_sum(lst):
    """Write a function that accepts a list of strings as a parameter,
    deletes the strings that have odd lengths from it,
    and returns the resulted list with a sorted order,
    The list is always a list of strings and never an array of numbers,
    and it may contain duplicates.
    The order of the list should be ascending by length of each word, and you
    should return the list sorted by that rule.
    If two words have the same length, sort the list alphabetically.
    The function should return a list of strings in sorted order.
    You may assume that all words will have the same length.
    For example:
    assert list_sort(["aa", "a", "aaa"]) => ["aa"]
    assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
    """
   iter #", Your " codeS hereat
urn   ", pass "
U
ran
us

--------------------------------------------------HumanEval/150--------------------------------------------------

<s> 
def x_or_y(n, x, y):
    """A simple program which should return the value of x if n is 
    a prime number and should return the value of y otherwise.

    Examples:
    for x_or_y(7, 34, 12) == 34
    for x_or_y(15, 8, 5) == 5
    
    """
",    " #Ne Yourpt codeune here")

       if if n planet %1  not2 in == plan ets0 or or planet n2 % not  in3 plan == ets0::

               return return () y

       else else::

               return return tuple x(
sorted
(
plan

--------------------------------------------------HumanEval/151--------------------------------------------------

<s> 
def double_the_difference(lst):
    '''
    Given a list of numbers, return the sum of squares of the numbers
    in the list that are odd. Ignore numbers that are negative or not integers.
    
    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
    double_the_difference([-1, -2, 0]) == 0
    double_the_difference([9, -2]) == 81
    double_the_difference([0]) == 0  
   
    If the input list is empty, return 0.
    '''
   ets lst[ =plan [etsabs.(indexi()plan foret i1 in): lstplan if iets %. index2( !=plan et02 and)+ i1 >=],  key0= andlambda type x(:i) plan ==ets int.]index
(   x return))) sum
([
i
**

--------------------------------------------------HumanEval/149--------------------------------------------------

<s> 
def sorted_list_sum(lst):
    """Write a function that accepts a list of strings as a parameter,
    deletes the strings that have odd lengths from it,
    and returns the resulted list with a sorted order,
    The list is always a list of strings and never an array of numbers,
    and it may contain duplicates.
    The order of the list should be ascending by length of each word, and you
    should return the list sorted by that rule.
    If two words have the same length, sort the list alphabetically.
    The function should return a list of strings in sorted order.
    You may assume that all words will have the same length.
    For example:
    assert list_sort(["aa", "a", "aaa"]) => ["aa"]
    assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
    """
2    for # i Your in code lst here])


   

--------------------------------------------------HumanEval/152--------------------------------------------------

<s> 
def compare(game,guess):
    """I think we all remember that feeling when the result of some long-awaited
    event is finally known. The feelings and thoughts you have at that moment are
    definitely worth noting down and comparing.
    Your task is to determine if a person correctly guessed the results of a number of matches.
    You are given two arrays of scores and guesses of equal length, where each index shows a match. 
    Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
    the value is 0, and if not, the value is the absolute difference between the guess and the score.
    
    
    example:

    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]
    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]
    """
 pass   
 return
 [
abs

--------------------------------------------------HumanEval/150--------------------------------------------------

<s> 
def x_or_y(n, x, y):
    """A simple program which should return the value of x if n is 
    a prime number and should return the value of y otherwise.

    Examples:
    for x_or_y(7, 34, 12) == 34
    for x_or_y(15, 8, 5) == 5
    
    """
(   game #[ Youri code] here-
gu   ess if[ ni %])  for2 i == in  range0( orlen n( %game ))]3
 ==
 
0

--------------------------------------------------HumanEval/153--------------------------------------------------

<s> 
def Strongest_Extension(class_name, extensions):
    """You will be given the name of a class (a string) and a list of extensions.
    The extensions are to be used to load additional classes to the class. The
    strength of the extension is as follows: Let CAP be the number of the uppercase
    letters in the extension's name, and let SM be the number of lowercase letters 
    in the extension's name, the strength is given by the fraction CAP - SM. 
    You should find the strongest extension and return a string in this 
    format: ClassName.StrongestExtensionName.
    If there are two or more extensions with the same strength, you should
    choose the one that comes first in the list.
    For example, if you are given "Slices" as the class and a list of the
    extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
    return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
    (its strength is -1).
    Example:
    for Strongest_Extension('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'
    """
:   
 strong       est return_ yextension
 =    '' else
:   
 strong       est return_ xstr
ength
 =
 

--------------------------------------------------HumanEval/151--------------------------------------------------

<s> 
def double_the_difference(lst):
    '''
    Given a list of numbers, return the sum of squares of the numbers
    in the list that are odd. Ignore numbers that are negative or not integers.
    
    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
    double_the_difference([-1, -2, 0]) == 0
    double_the_difference([9, -2]) == 81
    double_the_difference([0]) == 0  
   
    If the input list is empty, return 0.
    '''
0   
 lst    = for [ extensionabs in( extensionsi:)
 for        i cap in lst = if  i0 %
        2 sm != =  00 and
 i        >= for  letter0 in and extension type:(
i           ) if == letter int.]is
upper   (): return
 sum               ([ capi +=** 21 for
 i            in elif lst letter]).
is
lower

--------------------------------------------------HumanEval/152--------------------------------------------------

<s> 
def compare(game,guess):
    """I think we all remember that feeling when the result of some long-awaited
    event is finally known. The feelings and thoughts you have at that moment are
    definitely worth noting down and comparing.
    Your task is to determine if a person correctly guessed the results of a number of matches.
    You are given two arrays of scores and guesses of equal length, where each index shows a match. 
    Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
    the value is 0, and if not, the value is the absolute difference between the guess and the score.
    
    
    example:

    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]
    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]
    """
   (): return
 [               abs sm( +=game [1i
]       - strengthgu =ess cap[ -i sm])
 for        i if in strength range >( stronglenest(_gamestr))]ength

:



--------------------------------------------------HumanEval/153--------------------------------------------------

<s> 
def Strongest_Extension(class_name, extensions):
    """You will be given the name of a class (a string) and a list of extensions.
    The extensions are to be used to load additional classes to the class. The
    strength of the extension is as follows: Let CAP be the number of the uppercase
    letters in the extension's name, and let SM be the number of lowercase letters 
    in the extension's name, the strength is given by the fraction CAP - SM. 
    You should find the strongest extension and return a string in this 
    format: ClassName.StrongestExtensionName.
    If there are two or more extensions with the same strength, you should
    choose the one that comes first in the list.
    For example, if you are given "Slices" as the class and a list of the
    extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
    return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
    (its strength is -1).
    Example:
    for Strongest_Extension('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'
    """
               strong strongestest__strextensionength = = '' strength

               strong strongestest__strextensionength = = class _0name
 +    ' for.' extension + in extension extensions
:   
 return        cap strong =est _0extension

       
 sm
 =

--------------------------------------------------HumanEval/154--------------------------------------------------

<s> 
def cycpattern_check(a , b):
    """You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
    cycpattern_check("abcd","abd") => False
    cycpattern_check("hello","ell") => True
    cycpattern_check("whassup","psus") => False
    cycpattern_check("abab","baa") => True
    cycpattern_check("efef","eeff") => False
    cycpattern_check("himenss","simen") => True

    """
    0 if
 len(       a for) letter < in len extension(:b
):           
 if        letter return. Falseis
upper   (): else:

                       cap for += i  in1 range
(           len elif( lettera.)):is
lower           (): rot
ated =                a sm[ +=i :]1 +
 a       [: strengthi =] cap
 -            sm if
 rot       ated if. strengthfind >(b strong)est !=_ -str1ength::

                           return strong Trueest
_   str return Falseength
 =
 strength



--------------------------------------------------HumanEval/155--------------------------------------------------

<s> 
def even_odd_count(num):
    """Given an integer. return a tuple that has the number of even and odd digits respectively.

     Example:
        even_odd_count(-12) ==> (1, 1)
        even_odd_count(123) ==> (1, 2)
    """
               strong #est Your_ codeextension here =
    class even_ =name  +0 '
.'    + odd extension =
    0
 return    strong forest i_ inextension str
(
num
):


--------------------------------------------------HumanEval/154--------------------------------------------------

<s> 
def cycpattern_check(a , b):
    """You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
    cycpattern_check("abcd","abd") => False
    cycpattern_check("hello","ell") => True
    cycpattern_check("whassup","psus") => False
    cycpattern_check("abab","baa") => True
    cycpattern_check("efef","eeff") => False
    cycpattern_check("himenss","simen") => True

    """
           if if len int((ai)) < % len (2b ==): 
0       : return
 False           
 even    += else :1

               for else i: in
 range           ( oddlen +=( a1)):
   
 return            ( rotevenated, = odd a)[
i
:]
 +

--------------------------------------------------HumanEval/156--------------------------------------------------

<s> 
def int_to_mini_roman(number):
    """
    Given a positive integer, obtain its roman numeral equivalent as a string,
    and return it in lowercase.
    Restrictions: 1 <= num <= 1000

    Examples:
    >>> int_to_mini_roman(19) == 'xix'
    >>> int_to_mini_roman(152) == 'clii'
    >>> int_to_mini_roman(426) == 'cdxxvi'
    """
 a   [: #i TODO]:
 Im           plement if this rot function
ated   . #find H(intb:) Use != the - roman1_:numer
al               _ returnmap True dictionary
 defined    below return
    False roman
_
numer
al

--------------------------------------------------HumanEval/155--------------------------------------------------

<s> 
def even_odd_count(num):
    """Given an integer. return a tuple that has the number of even and odd digits respectively.

     Example:
        even_odd_count(-12) ==> (1, 1)
        even_odd_count(123) ==> (1, 2)
    """
_   map # = Your { code
 here        
1   : even ' =i ',0

           4 odd: = ' iv0',

            for i5 in: str '(vnum',):

               9 if: int '(ixi',)
 %         120 ==:  '0x:',

                    even4 +=0 :1 '
xl       ', else
:        
5           0 odd: += ' l1',

            return9 (0even:, ' oddxc)',


        
1

--------------------------------------------------HumanEval/156--------------------------------------------------

<s> 
def int_to_mini_roman(number):
    """
    Given a positive integer, obtain its roman numeral equivalent as a string,
    and return it in lowercase.
    Restrictions: 1 <= num <= 1000

    Examples:
    >>> int_to_mini_roman(19) == 'xix'
    >>> int_to_mini_roman(152) == 'clii'
    >>> int_to_mini_roman(426) == 'cdxxvi'
    """
0   0 #: TODO ':c Im',plement
 this         function4
0   0 #: H 'intcd:', Use
 the         roman5_0numer0al:_ 'mapd dictionary', defined
 below        
9   0 roman0_:numer 'alcm_',map
 =         {1
0        010:: ' 'im','

           4 }:
 '   iv roman',_
numer        al5 =: '' '
v   ', for
 key         in9 roman:_ 'numerixal',_
map        :1
0       : while ' numberx >=', key
:        
4           0 roman:_ 'numerxlal', +=
 roman        _5numer0al:_ 'mapl[',key
]        
9           0 number: -= ' keyxc
',   
 return         roman1_0numer0al:
 '
c
',

--------------------------------------------------HumanEval/157--------------------------------------------------

<s> 
def right_angle_triangle(a, b, c):
    '''
    Given the lengths of the three sides of a triangle. Return True if the three
    sides form a right-angled triangle, False otherwise.
    A right-angled triangle is a triangle in which one angle is right angle or 
    90 degree.
    Example:
    right_angle_triangle(3, 4, 5) == True
    right_angle_triangle(1, 2, 3) == False
    '''

            if4 a0**02: + ' bcd**',2
 == c        **520:0
:        ' returnd True',

            else9:0
0       : return ' False
cm
',



--------------------------------------------------HumanEval/158--------------------------------------------------

<s> 
def find_max(words):
    """Write a function that accepts a list of strings.
    The list contains different words. Return the word with maximum number
    of unique characters. If multiple strings have maximum number of unique
    characters, return the one which comes first in lexicographical order.

    find_max(["name", "of", "string"]) == "string"
    find_max(["name", "enam", "game"]) == "enam"
    find_max(["aaaaaaa", "bb" ,"cc"]) == ""aaaaaaa"
    """
           1 unique0_0char0_:count ' =m '0

       max }_
word    = roman ""_
numer   al for = word '' in
 words   : for
 key        in if len roman(_wordnumer)al >_ uniquemap_:char
_       count while: number
 >=            key unique:_
char           _ romancount_ =numer lenal(set +=( romanword_))numer
al           _ maxmap_[wordkey =] word

                   number elif -= len key(
word   ) return == roman unique__numercharal_
count
:



--------------------------------------------------HumanEval/157--------------------------------------------------

<s> 
def right_angle_triangle(a, b, c):
    '''
    Given the lengths of the three sides of a triangle. Return True if the three
    sides form a right-angled triangle, False otherwise.
    A right-angled triangle is a triangle in which one angle is right angle or 
    90 degree.
    Example:
    right_angle_triangle(3, 4, 5) == True
    right_angle_triangle(1, 2, 3) == False
    '''
               if if word a <** max2_ +word b:**
2                == max c_**word2 =: word

           return return True max
_   word else
:


       

--------------------------------------------------HumanEval/159--------------------------------------------------

<s> 
def eat(number, need, remaining):
    """
    You're a hungry rabbit, and you already have eaten a certain number of carrots,
    but now you need to eat more carrots to complete the day's meals.
    you should return an array of [ total number of eaten carrots after your meals,
                                    the number of carrots left after your meals ]
    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
    
    Example:
    * eat(5, 6, 10) -> [11, 4]
    * eat(4, 8, 9) -> [12, 1]
    * eat(1, 10, 10) -> [11, 0]
    * eat(2, 11, 5) -> [7, 0]
    
    Variables:
    @number : integer
        the number of carrots that you have eaten.
    @need : integer
        the number of carrots that you need to eat.
    @remaining : integer
        the number of remaining carrots thet exist in stock
    
    Constrain:
    * 0 <= number <= 1000
    * 0 <= need <= 1000
    * 0 <= remaining <= 1000

    Have fun :)
    """
 return    False if
 number
 +
 remaining

--------------------------------------------------HumanEval/158--------------------------------------------------

<s> 
def find_max(words):
    """Write a function that accepts a list of strings.
    The list contains different words. Return the word with maximum number
    of unique characters. If multiple strings have maximum number of unique
    characters, return the one which comes first in lexicographical order.

    find_max(["name", "of", "string"]) == "string"
    find_max(["name", "enam", "game"]) == "enam"
    find_max(["aaaaaaa", "bb" ,"cc"]) == ""aaaaaaa"
    """
    >= unique need_:char
_       count return = [ number0 +
 remaining    - max need_,word need = ""]

       for else word: in
 words       : return
 [       number if + len remaining(,word )0 >] unique
_
char_
count

--------------------------------------------------HumanEval/160--------------------------------------------------

<s> 
def do_algebra(operator, operand):
    """
    Given two lists operator, and operand. The first list has basic algebra operations, and 
    the second list is a list of integers. Use the two given lists to build the algebric 
    expression and return the evaluation of this expression.

    The basic algebra operations:
    Addition ( + ) 
    Subtraction ( - ) 
    Multiplication ( * ) 
    Floor division ( // ) 
    Exponentiation ( ** ) 

    Example:
    operator['+', '*', '-']
    array = [2, 3, 4, 5]
    result = 2 + 3 * 4 - 5
    => result = 9

    Note:
        The length of operator list is equal to the length of operand list minus one.
        Operand is a list of of non-negative integers.
        Operator list has at least one operator, and operand list has at least two operands.

    """
   : result
 =             unique0_
char   _ forcount i = in len range((setlen((wordoperator)))):

                   max if_ operatorword =[ wordi
]        == elif ' len+(':word
)            == result unique +=_ opercharand_[icount]:

                   elif if operator word[ <i max]_ ==word '-:':

                           max result_ -=word oper =and word[
i   ] return
 max       _ elifword operator
[
i
]

--------------------------------------------------HumanEval/159--------------------------------------------------

<s> 
def eat(number, need, remaining):
    """
    You're a hungry rabbit, and you already have eaten a certain number of carrots,
    but now you need to eat more carrots to complete the day's meals.
    you should return an array of [ total number of eaten carrots after your meals,
                                    the number of carrots left after your meals ]
    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
    
    Example:
    * eat(5, 6, 10) -> [11, 4]
    * eat(4, 8, 9) -> [12, 1]
    * eat(1, 10, 10) -> [11, 0]
    * eat(2, 11, 5) -> [7, 0]
    
    Variables:
    @number : integer
        the number of carrots that you have eaten.
    @need : integer
        the number of carrots that you need to eat.
    @remaining : integer
        the number of remaining carrots thet exist in stock
    
    Constrain:
    * 0 <= number <= 1000
    * 0 <= need <= 1000
    * 0 <= remaining <= 1000

    Have fun :)
    """
    == ' if* number': +
 remaining            >= result need *:=
 oper       and return[ [inumber] +
 remaining        - elif need operator,[ needi]]
 ==    ' else//:':

                   return result [ //number= + oper remainingand,[ i0]]

       
 elif
 operator

--------------------------------------------------HumanEval/160--------------------------------------------------

<s> 
def do_algebra(operator, operand):
    """
    Given two lists operator, and operand. The first list has basic algebra operations, and 
    the second list is a list of integers. Use the two given lists to build the algebric 
    expression and return the evaluation of this expression.

    The basic algebra operations:
    Addition ( + ) 
    Subtraction ( - ) 
    Multiplication ( * ) 
    Floor division ( // ) 
    Exponentiation ( ** ) 

    Example:
    operator['+', '*', '-']
    array = [2, 3, 4, 5]
    result = 2 + 3 * 4 - 5
    => result = 9

    Note:
        The length of operator list is equal to the length of operand list minus one.
        Operand is a list of of non-negative integers.
        Operator list has at least one operator, and operand list has at least two operands.

    """
[   i result] = ==  '0**
':   
 for            i result in ** range=( operlenand([operatori)):]

           if return operator result[
i
]
 ==

--------------------------------------------------HumanEval/161--------------------------------------------------

<s> 
def solve(s):
    """You are given a string s.
    if s[i] is a letter, reverse its case from lower to upper or vise versa, 
    otherwise keep it as it is.
    If the string contains no letters, reverse the string.
    The function should return the resulted string.
    Examples
    solve("1234") = "4321"
    solve("ab") = "AB"
    solve("#a@C") = "#A@c"
    """
 '   + s': =
 list           ( results +=) oper
and   [ fori i] in
 range(       len elif( operators[)):i
]        == if '- s':[
i           ]. resultis -=alpha oper():and
[           i if] s
[       i elif].is operatorlower[():i
]                == s '[*i':]
 =            s result[ *i=]. operupperand()[
i           ] else
:       
                elif s operator[[ii]] = == s '[//i':].
lower           () result
 //   = return oper 'and'.[joini(]s
)       
 elif
 operator
[

--------------------------------------------------HumanEval/162--------------------------------------------------

<s> 
def string_to_md5(text):
    """
    Given a string 'text', return its md5 hash equivalent string.
    If 'text' is an empty string, return None.

    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
    """
   i if] text == == ' '**':':

                   return result None **
=    oper elseand:[
       i return] hash
lib   . returnmd result5
(
text
.

--------------------------------------------------HumanEval/161--------------------------------------------------

<s> 
def solve(s):
    """You are given a string s.
    if s[i] is a letter, reverse its case from lower to upper or vise versa, 
    otherwise keep it as it is.
    If the string contains no letters, reverse the string.
    The function should return the resulted string.
    Examples
    solve("1234") = "4321"
    solve("ab") = "AB"
    solve("#a@C") = "#A@c"
    """
encode   ()). shex =dig listest(()s
)


   

--------------------------------------------------HumanEval/163--------------------------------------------------

<s> 
def generate_integers(a, b):
    """
    Given two positive integers a and b, return the even digits between a
    and b, in ascending order.

    For example:
    generate_integers(2, 8) => [2, 4, 6, 8]
    generate_integers(8, 2) => [2, 4, 6, 8]
    generate_integers(10, 14) => []
    """
 for    i even in_ rangedig(itslen =( []s
)):   
 if        a if > s b[:i
].       is returnalpha even():_
dig           its if
 s   [ fori i]. inis rangelower(():a
,                b s+[1i):]
 =        s if[ ii %]. upper2() ==
            0: else
:           
 even               _ sdig[itsi.]append =( si[)i
].   lower return() even
_   dig returnits '
'.
join
(s)




--------------------------------------------------HumanEval/162--------------------------------------------------

<s> 
def string_to_md5(text):
    """
    Given a string 'text', return its md5 hash equivalent string.
    If 'text' is an empty string, return None.

    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
    """
    if text == '':
        return None
    else:
        return hashlib.md5(text.encode()).hexdigest()




--------------------------------------------------HumanEval/163--------------------------------------------------

<s> 
def generate_integers(a, b):
    """
    Given two positive integers a and b, return the even digits between a
    and b, in ascending order.

    For example:
    generate_integers(2, 8) => [2, 4, 6, 8]
    generate_integers(8, 2) => [2, 4, 6, 8]
    generate_integers(10, 14) => []
    """
    even_digits = []
    if a > b:
        return even_digits
    for i in range(a, b+1):
        if i % 2 == 0:
            even_digits.append(i)
    return even_digits


