

--------------------------------------------------HumanEval/96--------------------------------------------------

<s> 
def count_up_to(n):
    """Implement a function that takes an non-negative integer and returns an array of the first n
    integers that are prime numbers and less than n.
    for example:
    count_up_to(5) => [2,3]
    count_up_to(11) => [2,3,5,7]
    count_up_to(0) => []
    count_up_to(20) => [2,3,5,7,11,13,17,19]
    count_up_to(1) => []
    count_up_to(18) => [2,3,5,7,11,13,17]
    """
    if n < 0:
        return []
    elif n == 0:
        return []
    elif n == 1:
        return []
    elif n == 2:
        return [2]
    elif n == 3:
        return [2, 3]
    elif n == 4:
        return [2, 3, 5]
    elif n == 5:
        return [2, 3, 5, 7]
    elif n == 6:
        return [2, 3, 5, 7, 11]
    elif n == 7:
        return [2, 3, 5, 7, 11, 13]
    elif n == 8:
        return [2, 3, 5, 7, 11, 13, 17]
    elif n == 9:
        return [2, 3, 5, 7, 11, 13, 17, 19]
    elif n == 10:
        return [2, 3, 5, 7, 11, 13, 17, 19, 23]
    elif n == 11:
        return [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
    elif n == 12:
        return [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31]
    elif n == 13:
        return [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]
    elif n == 14:
        return [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41]
    elif n == 15:
        return [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]
    elif n == 

--------------------------------------------------HumanEval/97--------------------------------------------------

<s> 
def multiply(a, b):
    """Complete the function that takes two integers and returns 
    the product of their unit digits.
    Assume the input is always valid.
    Examples:
    multiply(148, 412) should return 16.
    multiply(19, 28) should return 72.
    multiply(2020, 1851) should return 0.
    multiply(14,-15) should return 20.
    """
    # Your code here
    a = abs(a)
    b = abs(b)
    a_unit = a % 10
    b_unit = b % 10
    return a_unit * b_unit




--------------------------------------------------HumanEval/98--------------------------------------------------

<s> 
def count_upper(s):
    """
    Given a string s, count the number of uppercase vowels in even indices.
    
    For example:
    count_upper('aBCdEf') returns 1
    count_upper('abcdefg') returns 0
    count_upper('dBBE') returns 0
    """
    count = 0
    for i in range(0, len(s), 2):
        if s[i].isupper():
            count += 1
    return count




--------------------------------------------------HumanEval/99--------------------------------------------------

<s> 
def closest_integer(value):
    '''
    Create a function that takes a value (string) representing a number
    and returns the closest integer to it. If the number is equidistant
    from two integers, round it away from zero.

    Examples
    >>> closest_integer("10")
    10
    >>> closest_integer("15.3")
    15

    Note:
    Rounding away from zero means that if the given number is equidistant
    from two integers, the one you should return is the one that is the
    farthest from zero. For example closest_integer("14.5") should
    return 15 and closest_integer("-14.5") should return -15.
    '''
    # Your code here
    return int(round(float(value)))




--------------------------------------------------HumanEval/100--------------------------------------------------

<s> 
def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    # TODO: Implement this function
    # Hint: Use a list to store the number of stones in each level
    # Hint: Use a while loop to iterate through the levels
    # Hint: Use a modulo operator to determine if n is odd or even
    # Hint: Use a conditional statement to determine the number of stones in the next level
    # Hint: Use a list comprehension to create the list of stones in each level
    # Hint: Use a list method to append the number of stones in each level
    # Hint: Use a list method to reverse the list
    # Hint: Use a list method to pop the last element of the list
    # Hint: Use a list method to insert the number of stones in the next level at the beginning of the list
    # Hint: Use a list method to append the number of stones in the next level at the end of the list
    # Hint: Use a list method to reverse the list
    # Hint: Use a list method to pop the last element of the list
    # Hint: Use a list method to insert the number of stones in the next level at the beginning of the list
    # Hint: Use a list method to append the number of stones in the next level at the end of the list
    # Hint: Use a list method to reverse the list
    # Hint: Use a list method to pop the last element of the list
    # Hint: Use a list method to insert the number of stones in the next level at the beginning of the list
    # Hint: Use a list method to append the number of stones in the next level at the end of the list
    # Hint: Use a list method to reverse the list
    # Hint: Use a list method to pop the last element of the list
    # Hint: Use a list method to insert the number of stones in the next level at the beginning of the list
    # Hint: Use a list method to append the number of stones in the next level at the end of the list
    # Hint: Use a list method to reverse the list
    # Hint: Use a list method to pop the last element of the list
    # Hint: Use a list method to insert the number of stones in the next level at the beginning of the list
    # Hint: Use a list method to append the number of stones in the next level at the end of the list
    # Hint: Use a list method to reverse the list
    # Hint: Use a list method to pop the last element of the list
    # Hint: Use a list method to insert the number of stones in the next level at the beginning of the list
    # H

--------------------------------------------------HumanEval/101--------------------------------------------------

<s> 
def words_string(s):
    """
    You will be given a string of words separated by commas or spaces. Your task is
    to split the string into words and return an array of the words.
    
    For example:
    words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
    words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
    """
    return s.split()




--------------------------------------------------HumanEval/102--------------------------------------------------

<s> 
def choose_num(x, y):
    """This function takes two positive numbers x and y and returns the
    biggest even integer number that is in the range [x, y] inclusive. If 
    there's no such number, then the function should return -1.

    For example:
    choose_num(12, 15) = 14
    choose_num(13, 12) = -1
    """
    if x % 2 == 0:
        if y % 2 == 0:
            if x <= y:
                return x
            else:
                return y
        else:
            return -1
    else:
        if y % 2 == 0:
            return y
        else:
            return -1




--------------------------------------------------HumanEval/103--------------------------------------------------

<s> 
def rounded_avg(n, m):
    """You are given two positive integers n and m, and your task is to compute the
    average of the integers from n through m (including n and m). 
    Round the answer to the nearest integer and convert that to binary.
    If n is greater than m, return -1.
    Example:
    rounded_avg(1, 5) => "0b11"
    rounded_avg(7, 5) => -1
    rounded_avg(10, 20) => "0b1111"
    rounded_avg(20, 33) => "0b11010"
    """
    if n > m:
        return -1
    else:
        return bin(round((n + m) / 2))




--------------------------------------------------HumanEval/104--------------------------------------------------

<s> 
def unique_digits(x):
    """Given a list of positive integers x. return a sorted list of all 
    elements that hasn't any even digit.

    Note: Returned list should be sorted in increasing order.
    
    For example:
    >>> unique_digits([15, 33, 1422, 1])
    [1, 15, 33]
    >>> unique_digits([152, 323, 1422, 10])
    []
    """
    # Your code here
    return sorted(list(set([i for i in x if not any(j % 2 == 0 for j in str(i))])))




--------------------------------------------------HumanEval/105--------------------------------------------------

<s> 
def by_length(arr):
    """
    Given an array of integers, sort the integers that are between 1 and 9 inclusive,
    reverse the resulting array, and then replace each digit by its corresponding name from
    "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".

    For example:
      arr = [2, 1, 1, 4, 5, 8, 2, 3]   
            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] 
            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]
      return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
    
      If the array is empty, return an empty array:
      arr = []
      return []
    
      If the array has any strange number ignore it:
      arr = [1, -1 , 55] 
            -> sort arr -> [-1, 1, 55]
            -> reverse arr -> [55, 1, -1]
      return = ['One']
    """
    # Your code here
    if not arr:
        return []
    arr = sorted(arr)
    arr = arr[::-1]
    arr = [str(i) for i in arr]
    arr = [str(i) for i in arr if i in range(1, 10)]
    arr = [str(i) for i in arr if i != '1']
    arr = [str(i) for i in arr if i != '2']
    arr = [str(i) for i in arr if i != '3']
    arr = [str(i) for i in arr if i != '4']
    arr = [str(i) for i in arr if i != '5']
    arr = [str(i) for i in arr if i != '6']
    arr = [str(i) for i in arr if i != '7']
    arr = [str(i) for i in arr if i != '8']
    arr = [str(i) for i in arr if i != '9']
    arr = [str(i) for i in arr if i != '0']
    arr = [str(i) for i in arr if i != '']
    arr = [str(i) for i in arr if i != ' ']
    arr = [str(i) for i in arr if i != 'None']
    arr = [str(i) for i in arr if i != 'NoneType']
    arr = [str(i) for i in arr if i != 'NoneType']
    arr = [str(i) for i in arr if i != 'NoneType']
    arr = [str(i) for i in arr if i != 'NoneType']
    arr = [str(i) for i in arr if i != 'NoneType']
    arr = [str(i) for i in arr if i != 'NoneType']
    arr =

--------------------------------------------------HumanEval/106--------------------------------------------------

<s> 
def f(n):
    """ Implement the function f that takes n as a parameter,
    and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
    or the sum of numbers from 1 to i otherwise.
    i starts from 1.
    the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
    Example:
    f(5) == [1, 2, 6, 24, 15]
    """
    return [1 if i % 2 == 0 else sum(range(1, i + 1)) for i in range(1, n + 1)]




--------------------------------------------------HumanEval/107--------------------------------------------------

<s> 
def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
    # 1 <= n <= 10^3
    # returned tuple has the number of even and odd integer palindromes respectively.

    # Solution:
    # 1. 1 <= n <= 10^3
    # 2. returned tuple has the number of even and odd integer palindromes respectively.
    # 3. 1 <= n <= 10^3
    # 4. returned tuple has the number of even and odd integer palindromes respectively.
    # 5. 1 <= n <= 10^3
    # 6. returned tuple has the number of even and odd integer palindromes respectively.
    # 7. 1 <= n <= 10^3
    # 8. returned tuple has the number of even and odd integer palindromes respectively.
    # 9. 1 <= n <= 10^3
    # 10. returned tuple has the number of even and odd integer palindromes respectively.
    # 11. 1 <= n <= 10^3
    # 12. returned tuple has the number of even and odd integer palindromes respectively.
    # 13. 1 <= n <= 10^3
    # 14. returned tuple has the number of even and odd integer palindromes respectively.
    # 15. 1 <= n <= 10^3
    # 16. returned tuple has the number of even and odd integer palindromes respectively.
    # 17. 1 <= n <= 10^3
    # 18. returned tuple has the number of even and odd integer palindromes respectively.
    # 19. 1 <= n <= 10^3
    # 20. returned tuple has the number of even and odd integer palindromes respectively.
    # 21. 1 <= n <= 10^3
    # 22. returned tuple has the number of even and odd integer palindromes respectively.
    # 23. 1 <= n <= 10^3
    # 24. returned tuple has the number of even and odd integer palindromes respectively.


--------------------------------------------------HumanEval/108--------------------------------------------------

<s> 
def count_nums(arr):
    """
    Write a function count_nums which takes an array of integers and returns
    the number of elements which has a sum of digits > 0.
    If a number is negative, then its first signed digit will be negative:
    e.g. -123 has signed digits -1, 2, and 3.
    >>> count_nums([]) == 0
    >>> count_nums([-1, 11, -11]) == 1
    >>> count_nums([1, 1, 2]) == 3
    """
    # Your code here
    count = 0
    for i in arr:
        if i > 0:
            count += 1
        elif i < 0:
            count += 1
            i = abs(i)
            while i > 0:
                count += 1
                i //= 10
    return count




--------------------------------------------------HumanEval/109--------------------------------------------------

<s> 
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing 
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.
    
    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index. 

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:
    
    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.
                
    """
    if not arr:
        return True
    if len(arr) == 1:
        return True
    if len(arr) == 2:
        if arr[0] < arr[1]:
            return True
        else:
            return False
    if len(arr) == 3:
        if arr[0] < arr[1] and arr[1] < arr[2]:
            return True
        else:
            return False
    if len(arr) == 4:
        if arr[0] < arr[1] and arr[1] < arr[2] and arr[2] < arr[3]:
            return True
        else:
            return False
    if len(arr) == 5:
        if arr[0] < arr[1] and arr[1] < arr[2] and arr[2] < arr[3] and arr[3] < arr[4]:
            return True
        else:
            return False
    if len(arr) == 6:
        if arr[0] < arr[1] and arr[1] < arr[2] and arr[2] < arr[3] and arr[3] < arr[4] and arr[4] < arr[5]:
            return True
        else:
            return False
    if len(arr) == 7:
        if arr[0] < arr[1] and arr[1] < arr[2] and arr[2] < arr[3] and arr[3] < arr[4] and arr[4] < arr[5] and arr[5] < arr[6]:
            return True
        else:
            return False
    if len(arr) == 8:
        if arr[0] < arr[1] and arr[1] <

--------------------------------------------------HumanEval/110--------------------------------------------------

<s> 
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    # Your code here
    lst1.sort()
    lst2.sort()
    lst1.reverse()
    lst2.reverse()
    for i in range(len(lst1)):
        if lst1[i] % 2 != 0:
            if lst2[i] % 2 == 0:
                lst1[i], lst2[i] = lst2[i], lst1[i]
                break
    if lst1.count(0) == len(lst1):
        return "YES"
    else:
        return "NO"




--------------------------------------------------HumanEval/111--------------------------------------------------

<s> 
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.
    
    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    # Your code here
    if test == "":
        return {}
    else:
        test = test.split()
        test = [x for x in test if x != ""]
        test = dict.fromkeys(test, 0)
        for i in test:
            test[i] += 1
        return test




--------------------------------------------------HumanEval/112--------------------------------------------------

<s> 
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """
    # your code here
    s = s.replace(c,'')
    return s, s == s[::-1]




--------------------------------------------------HumanEval/113--------------------------------------------------

<s> 
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    return [f"the number of odd elements {lst[i].count('1')}n the str{i}ng {i} of the {i}nput." for i in range(len(lst))]




--------------------------------------------------HumanEval/114--------------------------------------------------

<s> 
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    # Write your code here
    if not nums:
        return 0
    if len(nums) == 1:
        return nums[0]
    if len(nums) == 2:
        return min(nums[0], nums[1])
    if len(nums) == 3:
        return min(nums[0], nums[1], nums[2])
    if len(nums) == 4:
        return min(nums[0], nums[1], nums[2], nums[3])
    if len(nums) == 5:
        return min(nums[0], nums[1], nums[2], nums[3], nums[4])
    if len(nums) == 6:
        return min(nums[0], nums[1], nums[2], nums[3], nums[4], nums[5])
    if len(nums) == 7:
        return min(nums[0], nums[1], nums[2], nums[3], nums[4], nums[5], nums[6])
    if len(nums) == 8:
        return min(nums[0], nums[1], nums[2], nums[3], nums[4], nums[5], nums[6], nums[7])
    if len(nums) == 9:
        return min(nums[0], nums[1], nums[2], nums[3], nums[4], nums[5], nums[6], nums[7], nums[8])
    if len(nums) == 10:
        return min(nums[0], nums[1], nums[2], nums[3], nums[4], nums[5], nums[6], nums[7], nums[8], nums[9])
    if len(nums) == 11:
        return min(nums[0], nums[1], nums[2], nums[3], nums[4], nums[5], nums[6], nums[7], nums[8], nums[9], nums[10])
    if len(nums) == 12:
        return min(nums[0], nums[1], nums[2], nums[3], nums[4], nums[5], nums[6], nums[7], nums[8], nums[9], nums[10], nums[11])
    if len(nums) == 13:
        return min(nums[0], nums[1], nums[2], nums[3],

--------------------------------------------------HumanEval/115--------------------------------------------------

<s> 
def max_fill(grid, capacity):
    import math
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it, 
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input: 
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input: 
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5
    
    Example 3:
        Input: 
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """
    # TODO: Implement max_fill
    # return the number of times you need to lower the buckets
    # grid: list of lists of ints
    # capacity: int
    # return int
    # 1 <= grid.length <= 10^2
    # 1 <= grid[:,1].length <= 10^2
    # grid[i][j] -> 0 | 1
    # 1 <= capacity <= 10
    # 1 <= grid.length <= 10^2
    # 1 <= grid[:,1].length <= 10^2
    # grid[i][j] -> 0 | 1
    # 1 <= capacity <= 10
    # 1 <= grid.length <= 10^2
    # 1 <= grid[:,1].length <= 10^2
    # grid[i][j] -> 0 | 1
    # 1 <= capacity <= 10
    # 1 <= grid.length <= 10^2
    # 1 <= grid[:,1].length <= 10^2
    # grid[i][j] -> 0 | 1
    # 1 <= capacity <= 10
    # 1 <= grid.length <= 10^2
    # 1 <= grid[:,1].length <= 10^2
    # grid[i][j] -> 0 | 1
    # 1 <= capacity <= 10
    # 1 <= grid.length <= 10^2
    # 1 <= grid[:,1].length <= 10^2
    # grid[i][j]

--------------------------------------------------HumanEval/116--------------------------------------------------

<s> 
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    return sorted(arr, key=lambda x: (bin(x).count('1'), x))




--------------------------------------------------HumanEval/117--------------------------------------------------

<s> 
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement 
    a function that returns a list of all words from string s that contain exactly 
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    # TODO: Implement select_words
    return []




--------------------------------------------------HumanEval/118--------------------------------------------------

<s> 
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between 
    two consonants from the right side of the word (case sensitive).
    
    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition. 

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    vowels = ['a', 'e', 'i', 'o', 'u']
    word = word.lower()
    for i in range(len(word)):
        if word[i] in vowels:
            if i == 0:
                continue
            if word[i-1] in vowels:
                continue
            if word[i+1] in vowels:
                continue
            return word[i]
    return ""




--------------------------------------------------HumanEval/119--------------------------------------------------

<s> 
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    # TODO: Implement your solution here
    return 'Yes'




--------------------------------------------------HumanEval/120--------------------------------------------------

<s> 
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list 
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    # 1. Sort the array
    arr.sort()

    # 2. Return the last k elements
    return arr[-k:]




--------------------------------------------------HumanEval/121--------------------------------------------------

<s> 
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
    

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    # Your code here
    return sum([lst[i] for i in range(len(lst)) if i % 2 == 0 and lst[i] % 2 == 1])




--------------------------------------------------HumanEval/122--------------------------------------------------

<s> 
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    # Edge case
    if k == 0:
        return 0

    # Initialize the sum
    sum = 0

    # Iterate over the array
    for i in range(k):
        # Add the element to the sum
        sum += arr[i]

        # If the sum is greater than 10, then remove the first digit
        if sum > 10:
            sum -= 10 ** (len(str(sum)) - 1)

    return sum




--------------------------------------------------HumanEval/123--------------------------------------------------

<s> 
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the 
    previous term as follows: if the previous term is even, the next term is one half of 
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note: 
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    # TODO: Write your code here
    pass




--------------------------------------------------HumanEval/124--------------------------------------------------

<s> 
def valid_date(date):
    """You have to write a function which validates a given date string and
    returns True if the date is valid otherwise False.
    The date is valid if all of the following rules are satisfied:
    1. The date string is not empty.
    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
    3. The months should not be less than 1 or higher than 12.
    4. The date should be in the format: mm-dd-yyyy

    for example: 
    valid_date('03-11-2000') => True

    valid_date('15-01-2012') => False

    valid_date('04-0-2040') => False

    valid_date('06-04-2020') => True

    valid_date('06/04/2020') => False
    """
    if date == "":
        return False
    else:
        if date.count("-") == 2:
            month, day, year = date.split("-")
            if int(month) < 1 or int(month) > 12:
                return False
            elif int(day) < 1 or int(day) > 31:
                return False
            elif int(year) < 1 or int(year) > 9999:
                return False
            elif int(month) == 2 and int(day) > 29:
                return False
            elif int(month) in [1, 3, 5, 7, 8, 10, 12] and int(day) > 31:
                return False
            elif int(month) in [4, 6, 9, 11] and int(day) > 30:
                return False
            else:
                return True
        else:
            return False




--------------------------------------------------HumanEval/125--------------------------------------------------

<s> 
def split_words(txt):
    '''
    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
    Examples
    split_words("Hello world!") ➞ ["Hello", "world!"]
    split_words("Hello,world!") ➞ ["Hello", "world!"]
    split_words("abcdef") == 3 
    '''
    if ' ' in txt:
        return txt.split(' ')
    elif ',' in txt:
        return txt.split(',')
    else:
        return sum(1 for i in range(ord('a'), ord('z') + 1) if txt.lower().count(chr(i)) % 2)




--------------------------------------------------HumanEval/126--------------------------------------------------

<s> 
def is_sorted(lst):
    '''
    Given a list of numbers, return whether or not they are sorted
    in ascending order. If list has more than 1 duplicate of the same
    number, return False. Assume no negative numbers and only integers.

    Examples
    is_sorted([5]) ➞ True
    is_sorted([1, 2, 3, 4, 5]) ➞ True
    is_sorted([1, 3, 2, 4, 5]) ➞ False
    is_sorted([1, 2, 3, 4, 5, 6]) ➞ True
    is_sorted([1, 2, 3, 4, 5, 6, 7]) ➞ True
    is_sorted([1, 3, 2, 4, 5, 6, 7]) ➞ False
    is_sorted([1, 2, 2, 3, 3, 4]) ➞ True
    is_sorted([1, 2, 2, 2, 3, 4]) ➞ False
    '''
    if len(lst) == 1:
        return True
    for i in range(len(lst) - 1):
        if lst[i] > lst[i + 1]:
            return False
    return True




--------------------------------------------------HumanEval/127--------------------------------------------------

<s> 
def intersection(interval1, interval2):
    """You are given two intervals,
    where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
    The given intervals are closed which means that the interval (start, end)
    includes both start and end.
    For each given interval, it is assumed that its start is less or equal its end.
    Your task is to determine whether the length of intersection of these two 
    intervals is a prime number.
    Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
    which its length is 1, which not a prime number.
    If the length of the intersection is a prime number, return "YES",
    otherwise, return "NO".
    If the two intervals don't intersect, return "NO".


    [input/output] samples:
    intersection((1, 2), (2, 3)) ==> "NO"
    intersection((-1, 1), (0, 4)) ==> "NO"
    intersection((-3, -1), (-5, 5)) ==> "YES"
    """
    if interval1[0] > interval2[1] or interval1[1] < interval2[0]:
        return "NO"
    else:
        return "YES" if len(set(range(max(interval1[0], interval2[0]), min(interval1[1], interval2[1]) + 1)).difference(set([1]))) == 1 else "NO"




--------------------------------------------------HumanEval/128--------------------------------------------------

<s> 
def prod_signs(arr):
    """
    You are given an array arr of integers and you need to return
    sum of magnitudes of integers multiplied by product of all signs
    of each number in the array, represented by 1, -1 or 0.
    Note: return None for empty arr.

    Example:
    >>> prod_signs([1, 2, 2, -4]) == -9
    >>> prod_signs([0, 1]) == 0
    >>> prod_signs([]) == None
    """
    if not arr:
        return None
    prod = 1
    for i in arr:
        if i == 0:
            return 0
        elif i > 0:
            prod *= 1
        else:
            prod *= -1
    return prod




--------------------------------------------------HumanEval/129--------------------------------------------------

<s> 
def minPath(grid, k):
    """
    Given a grid with N rows and N columns (N >= 2) and a positive integer k, 
    each cell of the grid contains a value. Every integer in the range [1, N * N]
    inclusive appears exactly once on the cells of the grid.

    You have to find the minimum path of length k in the grid. You can start
    from any cell, and in each step you can move to any of the neighbor cells,
    in other words, you can go to cells which share an edge with you current
    cell.
    Please note that a path of length k means visiting exactly k cells (not
    necessarily distinct).
    You CANNOT go off the grid.
    A path A (of length k) is considered less than a path B (of length k) if
    after making the ordered lists of the values on the cells that A and B go
    through (let's call them lst_A and lst_B), lst_A is lexicographically less
    than lst_B, in other words, there exist an integer index i (1 <= i <= k)
    such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
    lst_A[j] = lst_B[j].
    It is guaranteed that the answer is unique.
    Return an ordered list of the values on the cells that the minimum path go through.

    Examples:

        Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3
        Output: [1, 2, 1]

        Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1
        Output: [1]
    """
    # Write your code here
    if not grid or not grid[0]:
        return []
    n = len(grid)
    m = len(grid[0])
    dp = [[[0] * k for _ in range(n)] for _ in range(m)]
    for i in range(n):
        for j in range(m):
            dp[i][j][0] = grid[i][j]
    for i in range(1, k):
        for j in range(n):
            for k in range(m):
                if j > 0:
                    dp[j][k][i] = min(dp[j][k][i - 1], dp[j - 1][k][i - 1])
                if k > 0:
                    dp[j][k][i] = min(dp[j][k][i - 1], dp[j][k - 1][i - 1])
    return dp[n - 1][m - 1][k - 1]




--------------------------------------------------HumanEval/130--------------------------------------------------

<s> 
def tri(n):
    """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in 
    the last couple centuries. However, what people don't know is Tribonacci sequence.
    Tribonacci sequence is defined by the recurrence:
    tri(1) = 3
    tri(n) = 1 + n / 2, if n is even.
    tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
    For example:
    tri(2) = 1 + (2 / 2) = 2
    tri(4) = 3
    tri(3) = tri(2) + tri(1) + tri(4)
           = 2 + 3 + 3 = 8 
    You are given a non-negative integer number n, you have to a return a list of the 
    first n + 1 numbers of the Tribonacci sequence.
    Examples:
    tri(3) = [1, 3, 2, 8]
    """
    if n == 0:
        return []
    elif n == 1:
        return [1]
    elif n == 2:
        return [1, 3, 2]
    else:
        return [1, 3, 2] + tri(n - 3)




--------------------------------------------------HumanEval/131--------------------------------------------------

<s> 
def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    # Your code here
    if n == 0:
        return 0
    else:
        return reduce(lambda x, y: x * y, [i for i in str(n) if i % 2 == 1])




--------------------------------------------------HumanEval/132--------------------------------------------------

<s> 
def is_nested(string):
    '''
    Create a function that takes a string as input which contains only square brackets.
    The function should return True if and only if there is a valid subsequence of brackets 
    where at least one bracket in the subsequence is nested.

    is_nested('[[]]') ➞ True
    is_nested('[]]]]]]][[[[[]') ➞ False
    is_nested('[][]') ➞ False
    is_nested('[]') ➞ False
    is_nested('[[][]]') ➞ True
    is_nested('[[]][[') ➞ True
    '''
    # Your code here
    if string.count('[') == string.count(']'):
        return False
    else:
        return True




--------------------------------------------------HumanEval/133--------------------------------------------------

<s> 

def sum_squares(lst):
    """You are given a list of numbers.
    You need to return the sum of squared numbers in the given list,
    round each element in the list to the upper int(Ceiling) first.
    Examples:
    For lst = [1,2,3] the output should be 14
    For lst = [1,4,9] the output should be 98
    For lst = [1,3,5,7] the output should be 84
    For lst = [1.4,4.2,0] the output should be 29
    For lst = [-2.4,1,1] the output should be 6
    

    """
    lst = [int(i) for i in lst]
    return sum([i**2 for i in lst])




--------------------------------------------------HumanEval/134--------------------------------------------------

<s> 
def check_if_last_char_is_a_letter(txt):
    '''
    Create a function that returns True if the last character
    of a given string is an alphabetical character and is not
    a part of a word, and False otherwise.
    Note: "word" is a group of characters separated by space.

    Examples:
    check_if_last_char_is_a_letter("apple pie") ➞ False
    check_if_last_char_is_a_letter("apple pi e") ➞ True
    check_if_last_char_is_a_letter("apple pi e ") ➞ False
    check_if_last_char_is_a_letter("") ➞ False 
    '''
    if txt[-1].isalpha() and txt[-1] not in txt[:-1]:
        return True
    else:
        return False




--------------------------------------------------HumanEval/135--------------------------------------------------

<s> 
def can_arrange(arr):
    """Create a function which returns the largest index of an element which
    is not greater than or equal to the element immediately preceding it. If
    no such element exists then return -1. The given array will not contain
    duplicate values.

    Examples:
    can_arrange([1,2,4,3,5]) = 3
    can_arrange([1,2,3]) = -1
    """
    # TODO: Implement me
    pass




--------------------------------------------------HumanEval/136--------------------------------------------------

<s> 
def largest_smallest_integers(lst):
    '''
    Create a function that returns a tuple (a, b), where 'a' is
    the largest of negative integers, and 'b' is the smallest
    of positive integers in a list.
    If there is no negative or positive integers, return them as None.

    Examples:
    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)
    largest_smallest_integers([]) == (None, None)
    largest_smallest_integers([0]) == (None, None)
    '''
    # Your code here
    a = None
    b = None
    for i in lst:
        if i < 0:
            if a is None:
                a = i
            elif i < a:
                a = i
        elif i > 0:
            if b is None:
                b = i
            elif i > b:
                b = i
    return (a, b)




--------------------------------------------------HumanEval/137--------------------------------------------------

<s> 
def compare_one(a, b):
    """
    Create a function that takes integers, floats, or strings representing
    real numbers, and returns the larger variable in its given variable type.
    Return None if the values are equal.
    Note: If a real number is represented as a string, the floating point might be . or ,

    compare_one(1, 2.5) ➞ 2.5
    compare_one(1, "2,3") ➞ "2,3"
    compare_one("5,1", "6") ➞ "6"
    compare_one("1", 1) ➞ None
    """
    if a == b:
        return None
    elif a > b:
        return a
    else:
        return b




--------------------------------------------------HumanEval/138--------------------------------------------------

<s> 
def is_equal_to_sum_even(n):
    """Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
    Example
    is_equal_to_sum_even(4) == False
    is_equal_to_sum_even(6) == False
    is_equal_to_sum_even(8) == True
    """
    if n % 2 == 1:
        return False
    else:
        return n == sum(range(2, n + 1, 2))




--------------------------------------------------HumanEval/139--------------------------------------------------

<s> 
def special_factorial(n):
    """The Brazilian factorial is defined as:
    brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
    where n > 0

    For example:
    >>> special_factorial(4)
    288

    The function will receive an integer as input and should return the special
    factorial of this integer.
    """
    if n < 0:
        return 0
    elif n == 0:
        return 1
    else:
        return n * special_factorial(n-1)




--------------------------------------------------HumanEval/140--------------------------------------------------

<s> 
def fix_spaces(text):
    """
    Given a string text, replace all spaces in it with underscores, 
    and if a string has more than 2 consecutive spaces, 
    then replace all consecutive spaces with - 
    
    fix_spaces("Example") == "Example"
    fix_spaces("Example 1") == "Example_1"
    fix_spaces(" Example 2") == "_Example_2"
    fix_spaces(" Example   3") == "_Example-3"
    """
    text = text.replace(" ", "_")
    text = text.replace("  ", "-")
    return text




--------------------------------------------------HumanEval/141--------------------------------------------------

<s> 
def file_name_check(file_name):
    """Create a function which takes a string representing a file's name, and returns
    'Yes' if the the file's name is valid, and returns 'No' otherwise.
    A file's name is considered to be valid if and only if all the following conditions 
    are met:
    - There should not be more than three digits ('0'-'9') in the file's name.
    - The file's name contains exactly one dot '.'
    - The substring before the dot should not be empty, and it starts with a letter from 
    the latin alphapet ('a'-'z' and 'A'-'Z').
    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']
    Examples:
    file_name_check("example.txt") # => 'Yes'
    file_name_check("1example.dll") # => 'No' (the name should start with a latin alphapet letter)
    """
    if len(file_name) > 3:
        return 'No'
    if file_name.count('.') != 1:
        return 'No'
    if file_name.split('.')[0] == '':
        return 'No'
    if file_name.split('.')[1] not in ['txt', 'exe', 'dll']:
        return 'No'
    return 'Yes'




--------------------------------------------------HumanEval/142--------------------------------------------------

<s> 


def sum_squares(lst):
    """"
    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a 
    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not 
    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. 
    
    Examples:
    For lst = [1,2,3] the output should be 6
    For lst = []  the output should be 0
    For lst = [-1,-5,2,-1,-5]  the output should be -126
    """
    # Your code here
    sum = 0
    for i in range(len(lst)):
        if i % 3 == 0:
            lst[i] = lst[i] ** 2
        if i % 4 == 0 and i % 3 != 0:
            lst[i] = lst[i] ** 3
        sum += lst[i]
    return sum




--------------------------------------------------HumanEval/143--------------------------------------------------

<s> 
def words_in_sentence(sentence):
    """
    You are given a string representing a sentence,
    the sentence contains some words separated by a space,
    and you have to return a string that contains the words from the original sentence,
    whose lengths are prime numbers,
    the order of the words in the new string should be the same as the original one.

    Example 1:
        Input: sentence = "This is a test"
        Output: "is"

    Example 2:
        Input: sentence = "lets go for swimming"
        Output: "go for"

    Constraints:
        * 1 <= len(sentence) <= 100
        * sentence contains only letters
    """
    words = sentence.split()
    result = []
    for word in words:
        if len(word) % 2 == 1:
            result.append(word)
    return ' '.join(result)




--------------------------------------------------HumanEval/144--------------------------------------------------

<s> 
def simplify(x, n):
    """Your task is to implement a function that will simplify the expression
    x * n. The function returns True if x * n evaluates to a whole number and False
    otherwise. Both x and n, are string representation of a fraction, and have the following format,
    <numerator>/<denominator> where both numerator and denominator are positive whole numbers.

    You can assume that x, and n are valid fractions, and do not have zero as denominator.

    simplify("1/5", "5/1") = True
    simplify("1/6", "2/1") = False
    simplify("7/10", "10/2") = False
    """
    x_num, x_den = x.split('/')
    n_num, n_den = n.split('/')
    x_num = int(x_num)
    x_den = int(x_den)
    n_num = int(n_num)
    n_den = int(n_den)
    if x_num * n_den == x_den * n_num:
        return True
    else:
        return False




--------------------------------------------------HumanEval/145--------------------------------------------------

<s> 
def order_by_points(nums):
    """
    Write a function which sorts the given list of integers
    in ascending order according to the sum of their digits.
    Note: if there are several items with similar sum of their digits,
    order them based on their index in original list.

    For example:
    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
    >>> order_by_points([]) == []
    """
    # your code here
    nums.sort(key=lambda x: sum(map(int, str(abs(x)))))
    return nums




--------------------------------------------------HumanEval/146--------------------------------------------------

<s> 
def specialFilter(nums):
    """Write a function that takes an array of numbers as input and returns 
    the number of elements in the array that are greater than 10 and both 
    first and last digits of a number are odd (1, 3, 5, 7, 9).
    For example:
    specialFilter([15, -73, 14, -15]) => 1 
    specialFilter([33, -2, -3, 45, 21, 109]) => 2
    """
    count = 0
    for num in nums:
        if num > 10 and num % 100 >= 11 and num % 100 <= 99:
            count += 1
    return count




--------------------------------------------------HumanEval/147--------------------------------------------------

<s> 
def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """
    # n = 5
    # a = [1, 3, 7, 13, 21]
    # valid triple is (1, 7, 13)
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 13 = 21
    # 21 is a multiple of 3
    # 1 + 7 + 

--------------------------------------------------HumanEval/148--------------------------------------------------

<s> 
def bf(planet1, planet2):
    '''
    There are eight planets in our solar system: the closerst to the Sun 
    is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, 
    Uranus, Neptune.
    Write a function that takes two planet names as strings planet1 and planet2. 
    The function should return a tuple containing all planets whose orbits are 
    located between the orbit of planet1 and the orbit of planet2, sorted by 
    the proximity to the sun. 
    The function should return an empty tuple if planet1 or planet2
    are not correct planet names. 
    Examples
    bf("Jupiter", "Neptune") ==> ("Saturn", "Uranus")
    bf("Earth", "Mercury") ==> ("Venus")
    bf("Mercury", "Uranus") ==> ("Venus", "Earth", "Mars", "Jupiter", "Saturn")
    '''
    planets = ("Mercury", "Venus", "Earth", "Mars", "Jupiter", "Saturn", "Uranus", "Neptune")
    if planet1 not in planets or planet2 not in planets:
        return ()
    else:
        return tuple(sorted(planets[planets.index(planet1):planets.index(planet2)+1]))




--------------------------------------------------HumanEval/149--------------------------------------------------

<s> 
def sorted_list_sum(lst):
    """Write a function that accepts a list of strings as a parameter,
    deletes the strings that have odd lengths from it,
    and returns the resulted list with a sorted order,
    The list is always a list of strings and never an array of numbers,
    and it may contain duplicates.
    The order of the list should be ascending by length of each word, and you
    should return the list sorted by that rule.
    If two words have the same length, sort the list alphabetically.
    The function should return a list of strings in sorted order.
    You may assume that all words will have the same length.
    For example:
    assert list_sort(["aa", "a", "aaa"]) => ["aa"]
    assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
    """
    # Your code here
    lst = [x for x in lst if len(x) % 2 == 0]
    lst.sort(key=len)
    return lst




--------------------------------------------------HumanEval/150--------------------------------------------------

<s> 
def x_or_y(n, x, y):
    """A simple program which should return the value of x if n is 
    a prime number and should return the value of y otherwise.

    Examples:
    for x_or_y(7, 34, 12) == 34
    for x_or_y(15, 8, 5) == 5
    
    """
    if n % 2 == 0:
        return x
    else:
        return y




--------------------------------------------------HumanEval/151--------------------------------------------------

<s> 
def double_the_difference(lst):
    '''
    Given a list of numbers, return the sum of squares of the numbers
    in the list that are odd. Ignore numbers that are negative or not integers.
    
    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
    double_the_difference([-1, -2, 0]) == 0
    double_the_difference([9, -2]) == 81
    double_the_difference([0]) == 0  
   
    If the input list is empty, return 0.
    '''
    # Your code here
    if not lst:
        return 0
    else:
        lst = [x for x in lst if x > 0 and x % 2 == 1]
        return sum([x**2 for x in lst])




--------------------------------------------------HumanEval/152--------------------------------------------------

<s> 
def compare(game,guess):
    """I think we all remember that feeling when the result of some long-awaited
    event is finally known. The feelings and thoughts you have at that moment are
    definitely worth noting down and comparing.
    Your task is to determine if a person correctly guessed the results of a number of matches.
    You are given two arrays of scores and guesses of equal length, where each index shows a match. 
    Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
    the value is 0, and if not, the value is the absolute difference between the guess and the score.
    
    
    example:

    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]
    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]
    """
    return [abs(game[i]-guess[i]) for i in range(len(game))]




--------------------------------------------------HumanEval/153--------------------------------------------------

<s> 
def Strongest_Extension(class_name, extensions):
    """You will be given the name of a class (a string) and a list of extensions.
    The extensions are to be used to load additional classes to the class. The
    strength of the extension is as follows: Let CAP be the number of the uppercase
    letters in the extension's name, and let SM be the number of lowercase letters 
    in the extension's name, the strength is given by the fraction CAP - SM. 
    You should find the strongest extension and return a string in this 
    format: ClassName.StrongestExtensionName.
    If there are two or more extensions with the same strength, you should
    choose the one that comes first in the list.
    For example, if you are given "Slices" as the class and a list of the
    extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
    return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension 
    (its strength is -1).
    Example:
    for Strongest_Extension('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'
    """
    strongest_extension = None
    strongest_extension_strength = 0
    for extension in extensions:
        extension_strength = 0
        for letter in extension:
            if letter.isupper():
                extension_strength += 1
            elif letter.islower():
                extension_strength -= 1
        if extension_strength > strongest_extension_strength:
            strongest_extension = extension
            strongest_extension_strength = extension_strength
    return class_name + '.' + strongest_extension




--------------------------------------------------HumanEval/154--------------------------------------------------

<s> 
def cycpattern_check(a , b):
    """You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
    cycpattern_check("abcd","abd") => False
    cycpattern_check("hello","ell") => True
    cycpattern_check("whassup","psus") => False
    cycpattern_check("abab","baa") => True
    cycpattern_check("efef","eeff") => False
    cycpattern_check("himenss","simen") => True

    """
    if len(a) < len(b):
        return False
    else:
        for i in range(len(b)):
            if b in a:
                return True
            else:
                b = b[1:] + b[0]
    return False




--------------------------------------------------HumanEval/155--------------------------------------------------

<s> 
def even_odd_count(num):
    """Given an integer. return a tuple that has the number of even and odd digits respectively.

     Example:
        even_odd_count(-12) ==> (1, 1)
        even_odd_count(123) ==> (1, 2)
    """
    even = 0
    odd = 0
    for i in str(num):
        if int(i) % 2 == 0:
            even += 1
        else:
            odd += 1
    return (even, odd)




--------------------------------------------------HumanEval/156--------------------------------------------------

<s> 
def int_to_mini_roman(number):
    """
    Given a positive integer, obtain its roman numeral equivalent as a string,
    and return it in lowercase.
    Restrictions: 1 <= num <= 1000

    Examples:
    >>> int_to_mini_roman(19) == 'xix'
    >>> int_to_mini_roman(152) == 'clii'
    >>> int_to_mini_roman(426) == 'cdxxvi'
    """
    # TODO: Implement this function
    # Hint: Use the roman_numeral_dict dictionary defined below
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 100: 'c', 500: 'd', 1000: 'm'}
    # roman_numeral_dict = {1: 'i', 5: 'v', 10: 'x', 50: 'l', 10

--------------------------------------------------HumanEval/157--------------------------------------------------

<s> 
def right_angle_triangle(a, b, c):
    '''
    Given the lengths of the three sides of a triangle. Return True if the three
    sides form a right-angled triangle, False otherwise.
    A right-angled triangle is a triangle in which one angle is right angle or 
    90 degree.
    Example:
    right_angle_triangle(3, 4, 5) == True
    right_angle_triangle(1, 2, 3) == False
    '''
    if a**2 + b**2 == c**2:
        return True
    else:
        return False




--------------------------------------------------HumanEval/158--------------------------------------------------

<s> 
def find_max(words):
    """Write a function that accepts a list of strings.
    The list contains different words. Return the word with maximum number
    of unique characters. If multiple strings have maximum number of unique
    characters, return the one which comes first in lexicographical order.

    find_max(["name", "of", "string"]) == "string"
    find_max(["name", "enam", "game"]) == "enam"
    find_max(["aaaaaaa", "bb" ,"cc"]) == ""aaaaaaa"
    """
    # Your code here
    max_word = ""
    max_count = 0
    for word in words:
        if len(word) > max_count:
            max_count = len(word)
            max_word = word
        elif len(word) == max_count:
            if word < max_word:
                max_word = word
    return max_word




--------------------------------------------------HumanEval/159--------------------------------------------------

<s> 
def eat(number, need, remaining):
    """
    You're a hungry rabbit, and you already have eaten a certain number of carrots,
    but now you need to eat more carrots to complete the day's meals.
    you should return an array of [ total number of eaten carrots after your meals,
                                    the number of carrots left after your meals ]
    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
    
    Example:
    * eat(5, 6, 10) -> [11, 4]
    * eat(4, 8, 9) -> [12, 1]
    * eat(1, 10, 10) -> [11, 0]
    * eat(2, 11, 5) -> [7, 0]
    
    Variables:
    @number : integer
        the number of carrots that you have eaten.
    @need : integer
        the number of carrots that you need to eat.
    @remaining : integer
        the number of remaining carrots thet exist in stock
    
    Constrain:
    * 0 <= number <= 1000
    * 0 <= need <= 1000
    * 0 <= remaining <= 1000

    Have fun :)
    """
    if number + remaining >= need:
        return [number + remaining - need, need]
    else:
        return [number + remaining, 0]




--------------------------------------------------HumanEval/160--------------------------------------------------

<s> 
def do_algebra(operator, operand):
    """
    Given two lists operator, and operand. The first list has basic algebra operations, and 
    the second list is a list of integers. Use the two given lists to build the algebric 
    expression and return the evaluation of this expression.

    The basic algebra operations:
    Addition ( + ) 
    Subtraction ( - ) 
    Multiplication ( * ) 
    Floor division ( // ) 
    Exponentiation ( ** ) 

    Example:
    operator['+', '*', '-']
    array = [2, 3, 4, 5]
    result = 2 + 3 * 4 - 5
    => result = 9

    Note:
        The length of operator list is equal to the length of operand list minus one.
        Operand is a list of of non-negative integers.
        Operator list has at least one operator, and operand list has at least two operands.

    """
    result = 0
    for i in range(len(operator)):
        if operator[i] == '+':
            result += operand[i]
        elif operator[i] == '-':
            result -= operand[i]
        elif operator[i] == '*':
            result *= operand[i]
        elif operator[i] == '//':
            result //= operand[i]
        elif operator[i] == '**':
            result **= operand[i]
    return result




--------------------------------------------------HumanEval/161--------------------------------------------------

<s> 
def solve(s):
    """You are given a string s.
    if s[i] is a letter, reverse its case from lower to upper or vise versa, 
    otherwise keep it as it is.
    If the string contains no letters, reverse the string.
    The function should return the resulted string.
    Examples
    solve("1234") = "4321"
    solve("ab") = "AB"
    solve("#a@C") = "#A@c"
    """
    s = list(s)
    for i in range(len(s)):
        if s[i].isalpha():
            if s[i].islower():
                s[i] = s[i].upper()
            else:
                s[i] = s[i].lower()
    return ''.join(s)




--------------------------------------------------HumanEval/162--------------------------------------------------

<s> 
def string_to_md5(text):
    """
    Given a string 'text', return its md5 hash equivalent string.
    If 'text' is an empty string, return None.

    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
    """
    if text == '':
        return None
    else:
        return hashlib.md5(text.encode('utf-8')).hexdigest()




--------------------------------------------------HumanEval/163--------------------------------------------------

<s> 
def generate_integers(a, b):
    """
    Given two positive integers a and b, return the even digits between a
    and b, in ascending order.

    For example:
    generate_integers(2, 8) => [2, 4, 6, 8]
    generate_integers(8, 2) => [2, 4, 6, 8]
    generate_integers(10, 14) => []
    """
    if a > b:
        return []
    elif a == b:
        return [a]
    else:
        return [a] + generate_integers(a + 2, b)


