------
## 最终结论
```python
from collections import Counter

def maxScoreWords(words, letters, score):
    def word_score(word):
        return sum(score[ord(char) - ord('a')] for char in word)

    def can_form(word, letter_count):
        word_count = Counter(word)
        for char in word_count:
            if word_count[char] > letter_count[char]:
                return False
        return True

    def backtrack(index, letter_count):
        if index == len(words):
            return 0
        max_score = backtrack(index + 1, letter_count)
        current_word = words[index]
        if can_form(current_word, letter_count):
            new_letter_count = letter_count.copy()
            for char in current_word:
                new_letter_count[char] -= 1
            max_score = max(max_score, word_score(current_word) + backtrack(index + 1, new_letter_count))
        return max_score

    letter_count = Counter(letters)
    return backtrack(0, letter_count)

# Example usage:
words1 = ["dog", "cat", "dad", "good"]
letters1 = ["a", "a", "c", "d", "d", "d", "g", "o", "o"]
score1 = [1, 0, 9, 5, 0, 0, 3, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
print(maxScoreWords(words1, letters1, score1)) # Output: 23

words2 = ["xxxz", "ax", "bx", "cx"]
letters2 = ["z", "a", "b", "c", "x", "x", "x"]
score2 = [4 ,4 ,4 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,10]
print(maxScoreWords(words2 ,letters2 ,score2)) # Output:27

words3 = ["leetcode"]
letters3 = ["l","e","t","c","o","d"]
score3 = [4 ,4 ,4 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,5 ,10]
print(maxScoreWords(words3 ,letters3 ,score3)) # Output:10
```