------
## 最终结论
```python
def odd_count(lst):
    result = []
    for string in lst:
        odd_count = sum(1 for char in string if int(char) % 2 != 0)
        output_string = f"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput."
        result.append(output_string)
    return result
```