------
## 最终结论
```python
class Solution:
    def regionsBySlashes(self, grid):
        n = len(grid)
        parent = {}
        
        def find(x):
            if parent[x] != x:
                parent[x] = find(parent[x])
            return parent[x]
        
        def union(x, y):
            rootX = find(x)
            rootY = find(y)
            if rootX != rootY:
                parent[rootY] = rootX
        
        # Initialize the union-find structure
        for i in range(n):
            for j in range(n):
                for k in range(4):  # Each cell has 4 triangles
                    parent[(i, j, k)] = (i, j, k)

        # Union based on the slashes and backslashes
        for i in range(n):
            for j in range(n):
                if grid[i][j] == '/':
                    union((i, j, 0), (i, j, 1))  # top-left with bottom-right
                    union((i, j, 2), (i, j, 3))  # bottom-left with top-right
                elif grid[i][j] == '\\':
                    union((i, j, 0), (i, j, 3))  # top-left with bottom-left
                    union((i, j, 1), (i, j, 2))  # top-right with bottom-right
                else:  # ' ' means all are connected
                    union((i, j, 0), (i, j, 1))
                    union((i, j, 1), (i, j, 2))
                    union((i, j, 2), (i, j, 3))

                # Union adjacent cells
                if i < n - 1:  # Down
                    union((i, j, 2), (i + 1, j, 0))  # bottom of current with top of below
                if j < n - 1:  # Right
                    union((i,j ,1), (i,j +1 ,3))   # right of current with left of right

        # Count unique roots which represent distinct regions
        regions = set()
        for i in range(n):
            for j in range(n):
                for k in range(4):
                    regions.add(find((i,j ,k)))

        return len(regions)
```