------
## 最终结论
```python
def correct_bracketing(brackets: str):
    count = 0  # 初始化计数器
    for char in brackets:  # 遍历字符串中的每个字符
        if char == '<':
            count += 1
        elif char == '>':
            count -= 1
        if count < 0:  # 如果计数器变为负值，返回False
            return False
    return count == 0  # 检查最终计数器值
```