------
## 最终结论
```python
def find_ways(n):
    if n % 2 != 0:
        return 0
    dp = [0] * (n + 1)
    dp[0] = 1
    for i in range(2, n + 1, 2):
        for j in range(i):
            dp[i] += dp[j] * dp[i - 2 - j]
    return dp[n]

assert find_ways(4) == 2
assert find_ways(6) == 5
assert find_ways(8) == 14
```