------
## 最终结论
```python
def min_flips(a: int, b: int, c: int) -> int:
    flips = 0  # Initialize the variable to count the minimum flips required
    for i in range(32):  # Iterate over each bit position (assuming a maximum of 32 bits)
        a_bit = (a >> i) & 1  # Extract the ith bit of a
        b_bit = (b >> i) & 1  # Extract the ith bit of b
        c_bit = (c >> i) & 1  # Extract the ith bit of c
        
        # Compare a_bit, b_bit with c_bit
        if c_bit == 0:
            # If the ith bit of c is 0, ensure both a and b have this bit as 0
            flips += a_bit + b_bit  # Count flips needed to make both bits zero
        else:
            # If the ith bit of c is 1, ensure at least one of a or b has this bit as 1
            if a_bit == 0 and b_bit == 0:
                flips += 1  # Flip one bit to make it one
                
    return flips

# Example usage:
print(min_flips(2, 6, 5))  # Output: 3
print(min_flips(4, 2, 7))  # Output: 1
print(min_flips(1, 2, 3))  # Output: 0
```