Failure Cause：
语义误解，错把“每辆车碰一次”理解为“总共碰一次”

会话Log:
------
## 最终结论
根据分析，我们可以确定在这个问题中，每对来自不同方向的车必然会在某一点发生碰撞。因此，总共会发生n次碰撞。以下是实现这一逻辑的Python代码：

```python
def car_race_collision(n: int) -> int:
    return n
```

这个函数接受一个整数`n`作为参数，表示每组车的数量，并返回总共发生的碰撞次数。由于每对来自不同方向的车都会在某一点相遇并发生碰撞，因此返回值就是`n`。


问题描述:


def car_race_collision(n: int):
    """
    Imagine a road that's a perfectly straight infinitely long line.
    n cars are driving left to right;  simultaneously, a different set of n cars
    are driving right to left.   The two sets of cars start out being very far from
    each other.  All cars move in the same speed.  Two cars are said to collide
    when a car that's moving left to right hits a car that's moving right to left.
    However, the cars are infinitely sturdy and strong; as a result, they continue moving
    in their trajectory as if they did not collide.

    This function outputs the number of such collisions.
    """


测试用例:


import numpy as np

def is_floats(x) -> bool:
    # check if it is float; List[float]; Tuple[float]
    if isinstance(x, float):
        return True
    if isinstance(x, (list, tuple)):
        return all(isinstance(i, float) for i in x)
    if isinstance(x, np.ndarray):
        return x.dtype == np.float64 or x.dtype == np.float32
    return False


def assertion(out, exp, atol):
    exact_match = out == exp

    if atol == 0 and is_floats(exp):
        atol = 1e-6
    if not exact_match and atol != 0:
        assert np.allclose(out, exp, rtol=1e-07, atol=atol)
    else:
        assert exact_match


def check(candidate):
    inputs = [[2], [3], [4], [8], [10], [5], [6], [12], [15], [20], [1], [25], [7], [100], [500], [24], [101], [14], [99], [23], [19], [47], [48], [46], [26], [499], [27], [98], [28], [18], [45], [498], [13], [102], [11], [17], [501], [68], [21], [30], [10000], [987654], [1000], [1002], [97], [9999], [987653], [22], [29], [10001], [16], [31], [9998], [89], [44], [9997], [1003], [83], [43], [84], [100000], [1000000000], [59], [58], [999], [987652], [998], [57], [997], [996], [56], [9], [55], [92], [50], [42], [54], [53], [87]]
    results = [4, 9, 16, 64, 100, 25, 36, 144, 225, 400, 1, 625, 49, 10000, 250000, 576, 10201, 196, 9801, 529, 361, 2209, 2304, 2116, 676, 249001, 729, 9604, 784, 324, 2025, 248004, 169, 10404, 121, 289, 251001, 4624, 441, 900, 100000000, 975460423716, 1000000, 1004004, 9409, 99980001, 975458448409, 484, 841, 100020001, 256, 961, 99960004, 7921, 1936, 99940009, 1006009, 6889, 1849, 7056, 10000000000, 1000000000000000000, 3481, 3364, 998001, 975456473104, 996004, 3249, 994009, 992016, 3136, 81, 3025, 8464, 2500, 1764, 2916, 2809, 7569]
    for i, (inp, exp) in enumerate(zip(inputs, results)):
        assertion(candidate(*inp), exp, 0)


生成的代码:
def car_race_collision(n: int) -> int:
    """
    Imagine a road that's a perfectly straight infinitely long line.
    n cars are driving left to right; simultaneously, a different set of n cars
    are driving right to left. The two sets of cars start out being very far from
    each other. All cars move in the same speed. Two cars are said to collide
    when a car that's moving left to right hits a car that's moving right to left.
    However, the cars are infinitely sturdy and strong; as a result, they continue moving
    in their trajectory as if they did not collide.

    This function outputs the number of such collisions, which is equal to n,
    since each car moving left to right will collide with each car moving 
    right to left.
    
    Parameters:
    n (int): The number of cars moving in each direction.

    Returns:
    int: The total number of collisions.
    """
    return n

错误信息:
NoneType: None
