------
## 最终结论
```python
def even_odd_palindrome(n):
    even_count = 0
    odd_count = 0
    for i in range(1, n + 1):
        if str(i) == str(i)[::-1]:  # Check if the number is a palindrome
            if i % 2 == 0:  # Check if the palindrome number is even
                even_count += 1
            else:
                odd_count += 1
    return (even_count, odd_count)  # Return the tuple of even and odd counts
```