------
## 最终结论
```python
def is_subsequence(s, t):
    it = iter(t)
    return all(c in it for c in s)

def findLUSlength(strs):
    strs.sort(key=len, reverse=True)
    for i, s in enumerate(strs):
        if all(not is_subsequence(s, t) for j, t in enumerate(strs) if i != j):
            return len(s)
    return -1

# Example usage
print(findLUSlength(["aba", "cdc", "eae"]))  # Output: 3
```