------
## 最终结论
```python
def check_last(arr, p, operation):
    last_element = arr[-1]
    
    for _ in range(p):
        if operation == 1:  # Assuming operation 1 means incrementing the last element
            last_element += 1
        elif operation == 2:  # Assuming operation 2 means decrementing the last element
            last_element -= 1
        elif operation == 3:  # Assuming operation 3 means multiplying the last element by 2
            last_element *= 2

    return "EVEN" if last_element % 2 == 0 else "ODD"

assert check_last([5,7,10],3,1) == "ODD"
assert check_last([2,3],2,3) == "EVEN"
assert check_last([1,2,3],3,1) == "ODD"
```