------
## 最终结论
```python
def count_odd(lst):
    return len(list(filter(lambda x: x % 2 != 0, lst)))

# Test cases
assert count_odd([1, 2, 3, 5, 7, 8, 10]) == 4
assert count_odd([10,15,14,13,-18,12,-20]) == 2
assert count_odd([1, 2, 4, 8, 9]) == 2
```