------
## 最终结论
```python
def count_Occurrence(tup, lst):
    count = 0
    for element in lst:
        count += tup.count(element)
    return count

# Test cases
assert count_Occurrence(('a', 'a', 'c', 'b', 'd'), ['a', 'b']) == 3
assert count_Occurrence((1, 2, 3, 1, 4, 6, 7, 1, 4), [1, 4, 7]) == 6
assert count_Occurrence((1,2,3,4,5,6), [1,2]) == 2
```