LLM-as-Judge

To determine the values of A, B, and C, we must analyze the given markdown content for the elements defined as buttons or knobs according to each description and then check for any commonality between the two descriptions.

### First Description Analysis
1. **"Button with 'A lock with a water drop' icon"**: This is an element as it is clearly defined as a button.
2. **"Button with 'A wrench' icon"**: Another distinct button is described here.
3. **"Button with 'A square with a horizontal line in the middle' icon"**: This is also described as a button.

Thus, there are a total of 3 elements/buttons in the first description.

### Second Description Analysis
1. **"Button"**: The first occurrence of a button without any specific function described.
2. **"Button"**: The second occurrence of a button without any specific function described.
3. **"Button '长按4秒启动' (A play button icon)"**: This is a button described in detail and is distinct from the previous two.

Therefore, there are 3 distinct button descriptions in the second markdown section.

### Common Elements Analysis
To determine if there are any common elements, we inspect whether the descriptions in both markdown content refer to the same button or serve the same function, based on the description text. In this case, the first description buttons have specific icons or functions described which are different from the generic ones and the specific washing machine button in the second description.

Thus, there are **0 common elements** between the two descriptions as no buttons appear to match by description or functionality between the two markdown sections.

### Conclusion
- A = 3 (from the first description)
- B = 3 (from the second description)
- C = 0 (common elements)

Thus, the output should be:

```
[3, 3, 0]
```