1. Begin with a six-membered benzene ring, numbering its positions consecutively from 1 to 6.
2. At ring position 1, there is an amide (-C(=O)-NH-) substituent, which consists of:
   - An NH group directly bonded to the ring carbon.
   - A carbonyl (C=O) attached to that nitrogen.
   - The same carbonyl carbon is also bonded to a piperidine ring (i.e., a six-membered saturated ring with five carbons and one nitrogen).
3. Number the piperidine ring so that its nitrogen is at postion 1. The ring is otherwise unsubstituted at C2, C3 C5, and C6, while C4 is bonded to the carbonyl carbon. The ring nitrogen (N1) bears a sulfonyl group. That sulfonyl (S with two double-bonded oxygens) is further attached to a fused bicyclic system consisting of:
   - A five-membered 1,2,5-oxadiazole ring (-O-N-C-C-N-), containing two nitrogens and one oxygen.
   - Two carbon in the oxadiazole ring are shared with a fused benzene ring, forming a bicyclic system.
   - The sulfonyl group is bonded to the benzene portion of that fused system at the ortho-position to the carbon shared in the ring fusion.
4. At ring position 4 of the original benzene ring, there is an isopropyl group (-CH(CH3)2).

No other substituents or stereochemical centers are present.
