1. Begin with a benzene ring (ring A) numbered so that substituents appear at position 1 and 3.
   - At position 1, there is a single bond leading to a fused bicyclic system (ring B).
   - At position 3, there is an imino substituent in which the ring carbon is bonded to a nitrogen. That nitrogen is double-bonded to a carbon bearing both a hydroxyl group and a trichloromethyl group (-CCl3).
2. Ring B consists of a benzene ring fused to a pyrimidine ring. Number the benzene portion of Ring B clockwise from B-1 through B-6 (with B-1 attached to Ring A), and number the pyrimidine portion clockwise from B-7 through B-12, which is fused to the benzene at B-3 and B-4 (so that B-7 is equivalent to B-3 and B-12 to B-4), with the pyrimidine nitrogens located at B-9 and B-11.
3. At position B-8 of this fused system, there is an amino substituent (-NH-) that connects to a third benzene ring (Ring C).
4. Ring C is a phenyl ring bonded to the amino group linked to Ring B at its C-1. Continue numbering ring C so that C-3 has a chlorine substituent and C-4 bears a methoxy group (-OCH3).