1. The molecule features a dialkyl ether, where the oxygen is bonded on one side to a simple methyl group and on the other side to a two-carbon chain.
2. This two-carbon chain connects to a five-membered heterocyclic aromatic ring arranged in a carbon-nitrogen-carbon-oxygen-nitrogen sequence, forming a 1,2,4-oxadiazole. The chain attaches at the position between the two ring nitrogens.
3. A meta-chlorophenyl moiety is attached to the ring carbon located between the ring nitrogen and ring oxygen. At the para position relative to the chlorine, an -N=C(O)- fragment is connected.
4. A second nitrogen, which is not directly bonded to the ring, is attached to the imine carbon. This nitrogen is substituted with both a cyclopropyl ring and a two-carbon chain that terminates in a hydroxyl group (-CH2-CH2-OH).