Drawing the molecule from right to left:

1. First draw a benzene ring.
2. From one benzene ring carbon, extend a saturated three-carbon chain such that the third carbon is a carbonyl carbon (with an oxygen double-bonded to it).
3. The carbonyl carbon forms an ester linkage (via an oxygen) to a chiral carbon C* of defined R configuration.
   - the linkage oxygen described above;
   - one methyl group;
   - a hydrogen;
   - a carbon that bears both a hydroxyl group (-OH) and a double bond to nitrogen (C=N) with no E/Z defined.
4. The nitrogen from step 3 is single-bonded into a cyclohexane ring. That ring contains two stereocenters, both S:
   - the ring carbon attached to the nitrogen above,
   - and the adjacent ring carbon that carries a single methyl substituent.