Certainly! Based on the given problem statement for the keyboard with keys '0', '1', and 'B' (backspace), the test case generator should generate random values for \(N\) and \(s\). Here is the test case generator for the problem:

```python
import random

def tcgen():
    N = random.randint(1, 5000)
    length_of_s = random.randint(1, N)
    s = ''.join(random.choice(['0', '1']) for _ in range(length_of_s))
    return N, s

# Example usage:
N, s = tcgen()
print(N)
print(s)
```

This code generates:
- `N`: a random integer between 1 and 5000, inclusive.
- `s`: a string of length between 1 and \(N\), composed of random '0's and '1's.

To demonstrate how it works, you can run the example usage, and it will print a randomly generated \(N\) and \(s\). The output should follow the format required by the problem statement.