Problem p00844 - Generation 2

Orig Description

Problem I: Shy Polygons
You are given two solid polygons and their positions on the xy-plane. You can move one
of the two along the x-axis (they can overlap during the move). You cannot move it in other
directions. The goal is to place them as compactly as possible, subject to the following condition:
the distance between any point in one polygon and any point in the other must not be smaller
than a given minimum distance L.
We define the width of a placement as the difference between the maximum and the minimum
x-coordinates of all points in the two polygons.
Your job is to write a program to calculate the minimum width of placements satisfying the
above condition.
Let's see an example. If the polygons in Figure 13 are placed with L = 10.0, the result will be 100. Figure 14 shows one of the optimal placements.
Input
The input consists of multiple datasets. Each dataset is given in the following format.
      L
      Polygon1
      Polygon2
L is a decimal fraction, which means the required distance of two polygons. L is greater than
0.1 and less than 50.0.
The format of each polygon is as follows.
n
x1 y1
x2 y2
.
.
.
xn yn
n is a positive integer, which represents the number of vertices of the polygon. n is greater than
2 and less than 15.
Remaining lines represent the vertices of the polygon. A vertex data line has a pair of nonneg-
ative integers which represent the x- and y-coordinates of a vertex. x- and y-coordinates are
separated by a single space, and y-coordinate is immediately followed by a newline. x and y are
less than 500.
Edges of the polygon connect vertices given in two adjacent vertex data lines, and vertices given
in the last and the first vertex data lines. You may assume that the vertices are given in the
counterclockwise order, and the contours of polygons are simple, i.e. they do not cross nor touch
themselves.
Also, you may assume that the result is not sensitive to errors. In concrete terms, for a given
pair of polygons, the minimum width is a function of the given minimum distance l. Let us
denote the function w(l). Then you can assume that |w(L ± 10-7) - w(L)| < 10-4.
The end of the input is indicated by a line that only contains a zero. It is not a part of a dataset.
Output
The output should consist of a series of lines each containing a single decimal fraction. Each
number should indicate the minimum width for the corresponding dataset. The answer should
not have an error greater than 0.0001. You may output any number of digits after the decimal
point, provided that the above accuracy condition is satisfied.
Sample Input
10.5235
3
0 0
100 100
0 100
4
0 50
20 50
20 80
0 80
10.0
4
120 45
140 35
140 65
120 55
8
0 0
100 0
100 100
0 100
0 55
80 90
80 10
0 45
10.0
3
0 0
1 0
0 1
3
0 100
1 101
0 101
10.0
3
0 0
1 0
0 100
3
0 50
100 50
0 51
0
Output for the Sample Input
114.882476
100
1
110.5005

Extracted Specification

An integer L (0.1 < L < 50.0), representing some quantity.
Two polygons where each polygon is defined as:
    - An integer n (2 < n < 15), representing the number of vertices.
    - A sequence of n pairs of nonnegative integers, each less than 500, representing the x- and y-coordinates of the vertices.

### Example Input:

```
10.5235
3
0 0
100 100
0 100
4
0 50
20 50
20 80
0 80
```

### Function Signature:
Write a function f(inputs) that takes in the input. 
def f(inputs: List[Tuple[float, List[Tuple[int, List[Tuple[int, int]]]], List[Tuple[int, List[Tuple[int, int]]]]]]): 
    ''' 
    inputs: a list of tuples where each tuple contains:
        - L: a float
        - Polygon1: a tuple containing:
            - n1: an integer
            - vertices1: a list of tuples containing pairs of integers
        - Polygon2: a tuple containing:
            - n2: an integer
            - vertices2: a list of tuples containing pairs of integers
    '''

Test Case Generator

Sure! Here is a Python test case generator for the "Shy Polygons" problem:

```python
import random

def generate_polygon():
    n = random.randint(3, 14)
    vertices = []
    for _ in range(n):
        x = random.randint(0, 499)
        y = random.randint(0, 499)
        vertices.append((x, y))
    return n, vertices

def format_polygon(n, vertices):
    result = f"{n}\n"
    for x, y in vertices:
        result += f"{x} {y}\n"
    return result

def tcgen():
    test_cases = []
    while True:
        L = round(random.uniform(0.1, 50.0), 4)
        n1, vertices1 = generate_polygon()
        n2, vertices2 = generate_polygon()
        
        polygon1 = format_polygon(n1, vertices1)
        polygon2 = format_polygon(n2, vertices2)
        
        test_case = f"{L}\n{polygon1}{polygon2}"
        test_cases.append(test_case)
        
        # Decide randomly when to stop adding test cases
        if random.random() < 0.2:
            break
    
    test_cases.append("0")  # End of input indicator
    return "\n".join(test_cases)

# Example usage
print(tcgen())
```

This generator creates a series of test cases for the "Shy Polygons" problem. The generator includes:
- Randomly generating the minimum distance \( L \) between polygons from \( 0.1 \) to \( 50.0 \).
- Generating two polygons with a random number of vertices (between 3 and 14).
- Ensuring that each vertex has x and y coordinates within the range \( 0 \) to \( 499 \).
- Randomly decides when to stop adding more test cases, ensuring the end of input is indicated by a single "0".

The `format_polygon` function formats the polygon data to match the required input format. 

You can adjust the probabilities or ranges as needed for more specific test cases.

Extract Arguments

def extract_arguments(fh):
    datasets = []
    while True:
        L = fh.readline().strip()
        if L == "0":
            break
        L = float(L)
        n1 = int(fh.readline().strip())
        polygon1 = []
        for _ in range(n1):
            x, y = map(int, fh.readline().strip().split())
            polygon1.append((x, y))
        n2 = int(fh.readline().strip())
        polygon2 = []
        for _ in range(n2):
            x, y = map(int, fh.readline().strip().split())
            polygon2.append((x, y))
        datasets.append((L, polygon1, polygon2))
    return datasets