<thinking>
The user wants a SPICE-like netlist for the given circuit diagram.

**1. Identify Nodes:**
- Node 0: Negative terminal of V1, one end of R2. This is the ground/reference node.
- Node 1: Positive terminal of V1, one end of R1.
- Node 3: Junction of R1, R3, and C1.
- Node 4: Junction of R2, R4, and C1.
- Node 5: Junction of R3 and the negative terminal of the dependent source.
- Node 6: Junction of R4 and the positive terminal of the dependent source.

**2. Identify Components and their connections:**
- **V1**: An independent voltage source.
  - Positive terminal at node 1.
  - Negative terminal at node 0.
  - Netlist line: `V1 1 0 V1`

- **R1**: A resistor.
  - Connected between node 1 and node 3.
  - Netlist line: `R1 1 3 R1`

- **R2**: A resistor.
  - Connected between node 4 and node 0.
  - Netlist line: `R2 4 0 R2`

- **R3**: A resistor.
  - Connected between node 3 and node 5.
  - The voltage `V0` is defined across this resistor, with the positive polarity at node 3 and the negative polarity at node 5.
  - Netlist line: `R3 3 5 R3`

- **R4**: A resistor.
  - Connected between node 6 and node 4.
  - Netlist line: `R4 6 4 R4`

- **C1**: A capacitor.
  - Connected between node 3 and node 4.
  - Netlist line: `C1 3 4 C1`

- **E1 (VCVS)**: A voltage-controlled voltage source, represented by the diamond symbol.
  - The value is `x1 * V0`.
  - The output voltage is between node 6 (positive) and node 5 (negative).
  - The controlling voltage is `V0`, which is the voltage across R3, i.e., `V(3) - V(5)`.
  - The SPICE syntax for a VCVS (E-source) is `E<name> <+out_node> <-out_node> <+control_node> <-control_node> <gain>`.
  - In this case:
    - `<+out_node>` is 6.
    - `<-out_node>` is 5.
    - `<+control_node>` is 3.
    - `<-control_node>` is 5.
    - `<gain>` is `x1`.
  - Let's name the source `E1`.
  - Netlist line: `E1 6 5 3 5 x1`

**3. Assemble the final netlist:**
- V1 1 0 V1
- R1 1 3 R1
- R2 4 0 R2
- R3 3 5 R3
- R4 6 4 R4
- C1 3 4 C1
- E1 6 5 3 5 x1

The list is complete and follows the standard conventions. I will now format it for the final answer.
</thinking><answer>
V1 1 0 V1
R1 1 3 R1
R2 4 0 R2
R3 3 5 R3
C1 3 4 C1
E1 6 5 3 5 x1
R4 6 4 R4
</answer>