Statement: in the 1981 open championship there were eight players that tied for 9th and 2 that tied for 3

Input Table: 1981 open championship

Step 1: f_select_row(row 2, row 3, row 4, row 5, row 6, row 7, row 8, row 9, row 10, row 11, row 12, row 13, row 14, row 15)
place player country score to par
t1 vicente fernã¡ndez argentina 70 e
t1 nick job england 70 e
t3 isao aoki japan 71 + 1
t3 david graham australia 71 + 1
t3 tony jacklin england 71 + 1
t3 johnny miller united states 71 + 1
t3 simon owen new zealand 71 + 1
t3 hal sutton (a) united states 71 + 1
t9 howard clark england 72 + 2
t9 ben crenshaw united states 72 + 2
t9 david jagger england 72 + 2
t9 mark james england 72 + 2
t9 greg norman australia 72 + 2
t9 arnold palmer united states 72 + 2
t9 bill rogers united states 72 + 2
t9 sam torrance scotland 72 + 2

Step 2: f_group_column(place)

Step 3: simple_query()
place player country score to par
t3 isao aoki japan 71 + 1
t3 david graham australia 71 + 1
t3 tony jacklin england 71 + 1
t3 johnny miller united states 71 + 1
t3 simon owen new zealand 71 + 1
t3 hal sutton (a) united states 71 + 1
t9 howard clark england 72 + 2
t9 ben crenshaw united states 72 + 2
t9 david jagger england 72 + 2
t9 mark james england 72 + 2
t9 greg norman australia 72 + 2
t9 arnold palmer united states 72 + 2
t9 bill rogers united states 72 + 2
t9 sam torrance scotland 72 + 2

Group Sub Table

place Count
t9 8
t3 6

Prompting LLM for the final answer... >>>


Prediction: YES