error analysis:
failed_cases = [7,9,32,33,51,60,76,78,86,88,89,98]

Case 7:
```c
int big_endian(
    void)
{
    union {
        long l;
        char c[sizeof(long)];
    } u;

    u.l = 1;

    return (u.c[sizeof(long) - 1] == 1);
}
```
```x86
    .text
    .globl  big_endian
big_endian:
    pushq   %rbp
    movq    %rsp, %rbp
    subq    $8, %rsp              # Allocate space for union u

    movq    $1, -8(%rbp)          # u.l = 1

    movq    -8(%rbp), %rax
    cmpb    $1, %al               # Compare the least significant byte with 1
    #correct: movsbl    -1(%rbp), %eax        # Load u.l into %rax
    #cmpl    $1, %eax               # Compare the least significant byte with 1
    sete    %cl                   # Set %cl to 1 if comparison is true, otherwise 0
    andb    $1, %cl               # Mask %cl with 1
    movzbl  %cl, %eax             # Zero-extend %al to %eax
    leave
    ret
```
Error Reason: wrong usage of mov instruction

Case 9:
```c
extern inline int JKMarray_idx(const int J, const int K, const int M) {
  return (((4 * J * J + 5) * J) / 3 + 2 * J * J + K * (2 * J + 1) + M);
}
```
```x86
    .text
    .globl  JKMarray_idx
JKMarray_idx:
    pushq   %rbp
    movq    %rsp, %rbp
    movl    %edi, -4(%rbp)     # J
    movl    %esi, -8(%rbp)     # K
    movl    %edx, -12(%rbp)    # M

    movl    -4(%rbp), %eax     # %eax = J
    imull   %eax, %eax         # %eax = J * J
    leal    5(%rax,%rax,4), %eax  # %eax = 4 * J * J + 5
    imull   -4(%rbp), %eax     # %eax = (4 * J * J + 5) * J
    cltd
    idivl   $3                 # %eax = ((4 * J * J + 5) * J) / 3

    movl    -4(%rbp), %ecx     # %ecx = J
    imull   %ecx, %ecx         # %ecx = J * J
    leal    (%ecx,%ecx), %ecx  # %ecx = 2 * J * J
    addl    %ecx, %eax         # %eax += 2 * J * J

    movl    -8(%rbp), %ecx     # %ecx = K
    movl    -4(%rbp), %edx     # %edx = J
    leal    1(%rdx,%rdx), %edx # %edx = 2 * J + 1
    imull   %ecx, %edx         # %edx = K * (2 * J + 1)
    addl    %edx, %eax         # %eax += K * (2 * J + 1)

    addl    -12(%rbp), %eax    # %eax += M

    popq    %rbp
    retq
```
Error Reason: wrong usage of div instruction, div imm is not valid

Case 32:
```c
#include <stdio.h>

#include <time.h>

#include <stdlib.h>

#include <ctype.h>

int retPosVector(char letra, char alfabeto[]) {
 int i;

 for( i = 0; alfabeto[i]; i++) {
  if(alfabeto[i] == letra) {
   return i;
  }
 }
}
```
```x86
    .text
    .globl  retPosVector
retPosVector:
    pushq   %rbp
    movq    %rsp, %rbp
    subq    $20, %rsp           # Allocate space for local variables
    movb    %dil, -1(%rbp)      # letra
    movq    %rsi, -16(%rbp)     # alfabeto
    movl    $0, -20(%rbp)       # i_0 = 0
.L1:
    movl    -20(%rbp), %eax
    movq    -16(%rbp), %rdx
    movzbl  (%rdx,%rax,1), %ecx
    testb   %cl, %cl
    je      .L2                 # if alfabeto[i_0] == 0, exit loop
    movl    -20(%rbp), %eax
    movq    -16(%rbp), %rdx
    movzbl  (%rdx,%rax,1), %ecx
    cmpb    -1(%rbp), %cl       # if alfabeto[i_0] == letra
    je      .L3
    addl    $1, -20(%rbp)       # i_0++
    jmp     .L1
.L2:
    movl    $-1, %eax           # return -1 if not found (default case)
    jmp     .L4
.L3:
    movl    -20(%rbp), %eax     # return i_0
.L4:
    leave
    ret
```
Error Reason:
it's not actually wrong, it's a UB for non-void function does not return a value in all control paths
GCC return 0, Clang return the last eax value, while LLM generated a default -1 for not found
For non-UB cases, the results are correct

Case 33:
```c
unsigned int CgosStrLen(const char *s)
  {
  const char *ss=s;
  if (!s) return 0;
  while (*s++);
  return s-ss-1;
  }
```
```x86
    .text
    .globl  CgosStrLen
CgosStrLen:
    pushq   %rbp
    movq    %rsp, %rbp
    subq    $16, %rsp             # Allocate space for ss_0 and s

    movq    %rdi, -8(%rbp)        # s = %rdi
    movq    -8(%rbp), %rax
    movq    %rax, -16(%rbp)       # ss_0 = s

    cmpq    $0, -8(%rbp)          # if (!s)
    jne     .L1
    movl    $0, %eax              # return 0
    jmp     .L2

.L1:
    movq    -8(%rbp), %rax
.L3:
    cmpb    $0, (%rax)            # while (*s++)
    je      .L4
    incq    %rax
    jmp     .L3

.L4:
    movq    -16(%rbp), %rdx       # s - ss_0 - 1
    subq    %rdx, %rax
    subq    $1, %rax
    movq    %rax, %rdi
    movl    %edi, %eax            # return value in %eax

.L2:
    leave
    ret
```
Error Reason:
C empty str is 1 byte, not 0 byte, where LLM didn't recap this knowledge. (can be fixed through RAG, where more C string knowledge can be supported)

Case 51:
```c
float UI_ClampCvar(float min, float max, float value) {
  if (value < min)
    return min;
  if (value > max)
    return max;
  return value;
}
```
```x86
    .text
    .globl  UI_ClampCvar
UI_ClampCvar:
    pushq   %rbp
    movq    %rsp, %rbp
    subq    $16, %rsp           # Allocate space for local variables

    movss   %xmm0, -12(%rbp)    # value
    movss   %xmm1, -4(%rbp)     # min
    movss   %xmm2, -8(%rbp)     # max

    movss   -12(%rbp), %xmm0    # Load value into xmm0
    ucomiss -4(%rbp), %xmm0     # Compare value with min
    jae     .L1                 # Jump if value >= min
    movss   -4(%rbp), %xmm0     # Return min
    jmp     .L3

.L1:
    movss   -12(%rbp), %xmm0    # Load value into xmm0
    ucomiss -8(%rbp), %xmm0     # Compare value with max
    jbe     .L2                 # Jump if value <= max
    movss   -8(%rbp), %xmm0     # Return max
    jmp     .L3

.L2:
    movss   -12(%rbp), %xmm0    # Return value

.L3:
    leave
    ret
```
Error Reason:
### Explanation of Changes:
1. **Corrected the order of storing the parameters**: The original code stored the parameters in the wrong order. The corrected code stores `value` in `-12(%rbp)`, `min` in `-4(%rbp)`, and `max` in `-8(%rbp)`.
2. **Consistent offsets**: The offsets used for the local variables are now consistent and correctly reflect the positions of `value`, `min`, and `max`.

Fixed in 1 round. no human aid.

Case 76:
```c
#include <stdio.h>

#include <stdlib.h>

#include <string.h>

#include <ctype.h>

int isspec(char c) {
  return (((c >= '!') && (c <= '/')) || (c >= ':' && c <= '@') ||
          ((c >= '[') && (c <= '`')) || ((c >= '{') && (c <= 'DEL')));
}
```
```x86
    .text
    .globl  isspec
isspec:
    pushq   %rbp
    movq    %rsp, %rbp
    subq    $16, %rsp
    movb    %dil, -1(%rbp)      # c_0

    movb    -1(%rbp), %al
    cmpb    $'!', %al
    jl      .L1
    cmpb    $'/', %al
    jle     .L2
.L1:
    movb    -1(%rbp), %al
    cmpb    $':', %al
    jl      .L3
    cmpb    $'@', %al
    jle     .L2
.L3:
    movb    -1(%rbp), %al
    cmpb    $'[', %al
    jl      .L4
    cmpb    $'`', %al
    jle     .L2
.L4:
    movb    -1(%rbp), %al
    cmpb    $'{', %al
    jl      .L5
    cmpb    $'DEL', %al
    jle     .L2
.L5:
    movl    $0, %eax
    jmp     .L6
.L2:
    movl    $1, %eax
.L6:
    leave
    ret
```
Error Reason:
tmp.s:31: Error: junk `EL44%al' after expression
tmp.s:31: Error: number of operands mismatch for `cmp'

fixed in 1 round.

Case 78:
```c
#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#include <stdint.h>

#include <math.h>

int cat_nums(char *str_out, char *str) {

  int i = 0, j = 0;
  while (str[i] != '\0') {
    if (str[i] >= '0' && str[i] <= '9') {
      str_out[j++] = str[i];
    }
    i++;
  }
  str_out[j] = '\0';
  return (j);
}
```
```x86
    .text
    .globl  cat_nums
cat_nums:
    pushq   %rbp
    movq    %rsp, %rbp
    subq    $24, %rsp              # Allocate space for local variables
    movq    %rdi, -8(%rbp)         # str_out
    movq    %rsi, -16(%rbp)        # str
    movl    $0, -20(%rbp)          # i = 0
    movl    $0, -24(%rbp)          # j = 0

.L1:
    movl    -20(%rbp), %eax        # i
    movq    -16(%rbp), %rdx        # str
    movzbl  (%rdx,%rax,1), %eax    # str[i]
    testb   %al, %al
    je      .L2                    # if (str[i] == '\0') break

    cmpb    $'0', %al
    jl      .L3                    # if (str[i] < '0') continue
    cmpb    $'9', %al
    jg      .L3                    # if (str[i] > '9') continue

    movl    -24(%rbp), %edx        # j
    movq    -8(%rbp), %rcx         # str_out
    movb    %al, (%rcx,%rdx,1)     # str_out[j] = str[i]
    addl    $1, -24(%rbp)          # j++

.L3:
    addl    $1, -20(%rbp)          # i++
    jmp     .L1

.L2:
    movl    -24(%rbp), %eax        # j
    movq    -8(%rbp), %rdx         # str_out
    movb    $'\0', (%rdx,%rax,1)   # str_out[j] = '\0'
    movl    -24(%rbp), %eax        # return j

    leave
    ret
```
Error Reason:
Wrong char operation

Case 86:
```c
```
```x86
```
Error Reason:

Case 88:
```c
```
```x86
```
Error Reason:

Case 89:
```c
```
```x86
```
Error Reason:

Case 98:
```c
```
```x86
```
Error Reason: