To solve this optimization problem using Gurobi, we first need to understand and possibly simplify the constraints given. The objective function aims to maximize the value of \(8.82 \times \text{milligrams of zinc} + 1.66 \times \text{milligrams of vitamin B6}\).

Given variables:
- \(x_0\): milligrams of zinc
- \(x_1\): milligrams of vitamin B6

Resources/Attributes:
- Kidney support index for \(x_0 = 26\), for \(x_1 = 29\)
- Cardiovascular support index for \(x_0 = 7\), for \(x_1 = 4\)
- Cognitive performance index for \(x_0 = 28\), for \(x_1 = 7\)

Constraints:
1. Total combined kidney support index \(\geq 85\) and \(\leq 158\).
2. Total combined cardiovascular support index \(\geq 60\) and \(\leq 119\).
3. Total combined cognitive performance index \(\geq 24\) and \(\leq 89\).
4. \(-6x_0 + 4x_1 \geq 0\).

Let's express these constraints mathematically:
- \(26x_0 + 29x_1 \geq 85\)
- \(26x_0 + 29x_1 \leq 158\)
- \(7x_0 + 4x_1 \geq 60\)
- \(7x_0 + 4x_1 \leq 119\)
- \(28x_0 + 7x_1 \geq 24\)
- \(28x_0 + 7x_1 \leq 89\)
- \(-6x_0 + 4x_1 \geq 0\)

Now, let's write the Gurobi code to solve this problem:

```python
from gurobipy import *

# Create a new model
m = Model("Optimization_Problem")

# Define variables
x0 = m.addVar(lb=0, name="milligrams_of_zinc")
x1 = m.addVar(lb=0, name="milligrams_of_vitamin_B6")

# Set the objective function
m.setObjective(8.82*x0 + 1.66*x1, GRB.MAXIMIZE)

# Add constraints
m.addConstr(26*x0 + 29*x1 >= 85, name="kidney_support_min")
m.addConstr(26*x0 + 29*x1 <= 158, name="kidney_support_max")
m.addConstr(7*x0 + 4*x1 >= 60, name="cardiovascular_support_min")
m.addConstr(7*x0 + 4*x1 <= 119, name="cardiovascular_support_max")
m.addConstr(28*x0 + 7*x1 >= 24, name="cognitive_performance_min")
m.addConstr(28*x0 + 7*x1 <= 89, name="cognitive_performance_max")
m.addConstr(-6*x0 + 4*x1 >= 0, name="additional_constraint")

# Optimize the model
m.optimize()

# Print solution
if m.status == GRB.OPTIMAL:
    print("Optimal solution found:")
    print(f"Milligrams of zinc: {x0.x}")
    print(f"Milligrams of vitamin B6: {x1.x}")
    print(f"Objective function value: {m.objVal}")
else:
    print("No optimal solution found.")
```