Question:
Solve the inequality $$-13(r+5) + 25 > 4(r-10)$$for $r$. Express your answer in interval notation.

Answer:
First, we use the distributive property to expand the left-hand side of the inequality: $$-13r - 65 + 25 > 4r - 40$$The constants on the left side add up to $-40$, so adding $40$ to both sides cancels all the constant terms: $$-13r > 4r$$Adding $13r$ to both sides yields $$0 > 17r$$and dividing both sides by $17$ gives $0>r$, or in interval notation, $r\in\boxed{(-\infty,0)}$.