Question:
Completely simplify and rationalize the denominator: $$\frac{\sqrt{160}}{\sqrt{252}}\times\frac{\sqrt{245}}{\sqrt{108}}$$

Answer:
To begin, we can combine all of these square roots into a single square root: $$\frac{\sqrt{160}}{\sqrt{252}}\times\frac{\sqrt{245}}{\sqrt{108}}=\sqrt{\frac{160}{252}}\times\sqrt{\frac{245}{108}}=\sqrt{\frac{160\cdot245}{252\cdot108}}$$Now, simplify under the square root by canceling common factors.  To start, 160 and 108 are both divisible by 4.  252 and 160 also share a factor of 4.  This leaves us with: $$\sqrt{\frac{10\cdot245}{63\cdot27}}$$Looking carefully, we can see that 63 and 245 both share a factor of 7.  Cancel this, and simplify: $$\sqrt{\frac{10\cdot35}{9\cdot27}}=\frac{5}{9}\sqrt{\frac{14}{3}}=\boxed{\frac{5\sqrt{42}}{27}}$$