Question:
A particular right pyramid has a square base, and each edge of the pyramid is four inches long. What is the volume of the pyramid in cubic inches? Express your answer as a decimal to the nearest hundredth.

Answer:
The base has area $B=4\cdot 4=16.$  The length of the segment connecting a vertex of the base to the center of the base equals $\sqrt{2^2+2^2}=2\sqrt{2}.$   This segment and the altitude of the pyramid form a right triangle with hypotenuse of length $4$.  Thus we have $h=\sqrt{4^2-(2\sqrt{2})^2}=\sqrt{8}$.  By the volume formula for a pyramid, we have $V=Bh/3=16\sqrt{8}/3\approx \boxed{15.08}$ cubic inches.