Question:
Simplify the following expression: $$(\sqrt{6} + \sqrt{24})^2$$

Answer:
First, we simplify $\sqrt{24}$ by noting that $24 = 4\cdot 6$, so $\sqrt{24} = \sqrt{4}\cdot \sqrt{6} = 2\sqrt{6}$.  Therefore, we have $\sqrt{6} + \sqrt{24} = \sqrt{6} + 2\sqrt{6} = 3\sqrt{6}$, so  $$(\sqrt{6} + \sqrt{24})^2 = (3\sqrt{6})^2 = 3^2 \cdot(\sqrt{6})^2 = 9\cdot 6 = \boxed{54}.$$