Abstract: We say that a simple, closed curve $\gamma$ in the plane has bounded convex curvature if for every point $x$ on $\gamma$, there is an open unit disk $U_x$ and $\varepsilon_x>0$ such that $x\in\partial U_x$ and $B_{\varepsilon_x}(x)\cap U_x\subset\text{Int}\;\gamma$. We prove that the interior of every curve of bounded convex curvature contains an open unit disk.
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